Subtract to find the temperature changes
for the water and the metal.
AT (water) =
AT (metal) =

Answer:

Explanation:

The temperature changes for the water and the metal is

ΔT (water) = 4.7°C

ΔT (metal) = - 72.9°C

The quantity or amount of heat per unit mass required to raise the temperature of a body by one degree Celsius is known as specific heat. The unit of specific heat are joules or calories per gram per degree Celsius. Specific heat is an intensive property.

Relationship between temperature and heat is expressed as:

Q = mcΔT

where,

Q is heat energy in Joules (J)

m is mass (in grams)

c is specific heat in J/g°C

ΔT is change in temperature

Now calculate the temperature changes for the water

ΔT (water) = T(final) - T(initial)

                 = 27.1 - 22.4

                 = 4.7°C

Now calculate the temperature changes for the metal

ΔT(metal) = T(final) - T(initial)

                = 27.1 - 100

                = -72.9°C

Thus, from the above calculation we can see that the temperature changes for the water and the metal is

ΔT (water) = 4.7°C

ΔT (metal) = - 72.9°C

Learn more about the specific heat here: https://brainly.com/question/21406849

#SPJ2                

Balance the combustion reaction between propane and oxygen.
C ₃ H ₈+ O ₂→ CO ₂ + H ₂ O