Chemistry Middle School


Balance the combustion reaction between propane and oxygen.
C ₃ H ₈+ O ₂→ CO ₂ + H ₂ O

Answers

Answer 1

Answer:

The answer is C3H8 + 5O2 → 3CO2 + 4H2O .

Answer 2

Answer:

[tex]\huge \boxed{\mathrm{C_3 H_8 +5O_2 \Rightarrow 3CO_2 +4 H_2 O}}[/tex]

[tex]\rule[225]{225}{2}[/tex]

Explanation:

[tex]\sf C_3 H_8 +O_2 \Rightarrow CO_2 + H_2 O[/tex]

Balancing Carbon atoms on the right side,

[tex]\sf C_3 H_8 +O_2 \Rightarrow 3CO_2 + H_2 O[/tex]

Balancing Hydrogen atoms on the right side,

[tex]\sf C_3 H_8 +O_2 \Rightarrow 3CO_2 +4 H_2 O[/tex]

Balancing Oxygen atoms on the left side,

[tex]\sf C_3 H_8 +5O_2 \Rightarrow 3CO_2 +4 H_2 O[/tex]

[tex]\rule[225]{225}{2}[/tex]

Related Questions

Subtract to find the temperature changes
for the water and the metal.
AT (water) =
AT (metal) =


Answers

Answer:

Explanation:

The temperature changes for the water and the metal is

ΔT (water) = 4.7°C

ΔT (metal) = - 72.9°C

Specific Heat

The quantity or amount of heat per unit mass required to raise the temperature of a body by one degree Celsius is known as specific heat. The unit of specific heat are joules or calories per gram per degree Celsius. Specific heat is an intensive property.

Calculate the temperature changes

Relationship between temperature and heat is expressed as:

Q = mcΔT

where,

Q is heat energy in Joules (J)

m is mass (in grams)

c is specific heat in J/g°C

ΔT is change in temperature

Now calculate the temperature changes for the water

ΔT (water) = T(final) - T(initial)

                 = 27.1 - 22.4

                 = 4.7°C

Now calculate the temperature changes for the metal

ΔT(metal) = T(final) - T(initial)

                = 27.1 - 100

                = -72.9°C

Thus, from the above calculation we can see that the temperature changes for the water and the metal is

ΔT (water) = 4.7°C

ΔT (metal) = - 72.9°C

Learn more about the specific heat here: https://brainly.com/question/21406849

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