How to place 5/3 on a number line

Answer:

439.20

Step-by-step explanation:

to find 549 deceased by 20% percent you need to find what's 20% percent of 549 is.

Answer:

D

Step-by-step explanation:

-1/2m=-18

m=36

answer is D

Answer:

m = 36

Step-by-step explanation:

[tex]\frac{1}{3} m+3-\frac{5}{6}m=-15[/tex]

Combine like terms:

[tex](\frac{1}{3} m+(-\frac{5}{6}m)[/tex]

[tex](\frac{2}{6} m+(-\frac{5}{6}m)[/tex]

[tex]-\frac{3}{6}m = -\frac{1}{2} m[/tex]

[tex]-\frac{1}{2}m+3=-15[/tex]

Subtract 3 from each side:

[tex]-\frac{1}{2}m=-18[/tex]

Multiply each side by -2:

[tex]m = 36[/tex]

Answer:

It's decreasing quickest  between 3:23 and 3:24 (where the steepest drop on the graph is)

Answer:

3:23-3:24

…………………..

Answer:

C. Definition of Supplementary Angles

Step-by-step explanation:

You know this because they are opposites

I hope I could help!!!

Answer:

2

Step-by-step explanation:

Answer:

D.    Graph c

Step-by-step explanation:

I got this answer correct on Gradpoint

Answer:

where is the questions I don't know

Answer:

3 hours and 45 minutes

Step-by-step explanation:

let's assume the tank has a volume of x liters.

let's assume the speed of filling it is x/6 liters per hour for A and x/10 liters per hour for B.

the formula to calculate the time is:

time = volume / speed

If the pumps work together, the total speed is x/6 + x/10, which is 16/60 x

So the time this takes is:

time = x / (16/60 x) = 60/16 hours = 3.75 hours = 3 hours and 45 minutes.

Answer:

Step-by-step explanation:

[tex]x^4+7x^2-144=0\\x^4+16x^{2} -9x^{2} -144=0\\x^{2} (x^{2} +16)-9(x^{2} +16)=0\\(x^{2} +16)(x^{2} -9)=0\\(x^{2} -(-16))(x^{2} -3^2)=0\\(x^{2} -16 \iota^2)(x+3)(x-3)=0\\(x^{2} -(4\iota)^2)(x+3)(x-3)=0\\(x+4\iota)(x-4\iota)(x+3)(x-3)=0\\x=\pm4 \iota,\pm3[/tex]

Answer:

the fraction in simplest form is [tex]\frac{1}{5}[/tex]

Step-by-step explanation:

Hope this helps!

Answer:

you may not find this helpful,

Step-by-step explanation:

0.125 is the answer

Answer:

The 9 is in the ones place.

:)

9.56 m of the wire should be used for the square, to maximize the total area of the wire

Let x be the side length of the square.

So, the perimeter of the square is:

[tex]\mathbf{P_s=4x}[/tex]

Let y represent the side length of the equilateral triangle.

So, the perimeter of the triangle is:

[tex]\mathbf{P_t=3y}[/tex]

The length of the wire is given as:

[tex]\mathbf{P=22}[/tex]

This implies that:

[tex]\mathbf{P_s + P_t=22}[/tex]

Substitute values for Ps and Pt

[tex]\mathbf{4x + 3y=22}[/tex]

Make y the subject

[tex]\mathbf{y=\frac{22 -4x}3}[/tex]

For an equilateral triangle of side length y, the height (h) of the triangle is:

[tex]\mathbf{h =\frac y2\sqrt 3}[/tex]

The area of the triangle is then calculated as:

[tex]\mathbf{A_t = \frac 12 yh}[/tex]

This gives

[tex]\mathbf{A_t = \frac 12 y\times \frac y2\sqrt 3}[/tex]

[tex]\mathbf{A_t = \frac{y^2}{4}\sqrt 3}[/tex]

The area of the square is:

[tex]\mathbf{A_s = x^2}[/tex]

So, the total area is:

[tex]\mathbf{A = A_s + A_t}[/tex]

[tex]\mathbf{A = x^2 + \frac{y^2}{4}\sqrt 3}[/tex]

Substitute [tex]\mathbf{y=\frac{22 -4x}3}[/tex]

[tex]\mathbf{A = x^2 + (\frac{22 - 4x}{3})^2 \times \frac{\sqrt 3}{4}}[/tex]

Differentiate

[tex]\mathbf{A' = 2x + \frac{\sqrt 3}{4} \times \frac 19 \times 2(22 - 4x) \times (-4)}[/tex]

[tex]\mathbf{A' = 2x - \sqrt 3 \times \frac 19 \times 2(22 - 4x) }[/tex]

[tex]\mathbf{A' = 2x - \frac{2\sqrt 3}9 (22 - 4x) }[/tex]

Set to 0

[tex]\mathbf{2x - \frac{2\sqrt 3}9 (22 - 4x) = 0}[/tex]

Rewrite as:

[tex]\mathbf{2x = \frac{2\sqrt 3}9 (22 - 4x) }[/tex]

Divide through by 2

[tex]\mathbf{x = \frac{\sqrt 3}9 (22 - 4x) }[/tex]

Multiply through by 9

[tex]\mathbf{9x = \sqrt 3 (22 - 4x) }[/tex]

Open bracket

[tex]\mathbf{9x = 22\sqrt 3 - 4x\sqrt 3 }[/tex]

Collect like terms

[tex]\mathbf{9x +4x\sqrt 3= 22\sqrt 3 }[/tex]

Factor out x

[tex]\mathbf{x(9 +4\sqrt 3)= 22\sqrt 3 }[/tex]

Solve for x

[tex]\mathbf{x= \frac{22\sqrt 3}{9 +4\sqrt 3} }[/tex]

Simplify

[tex]\mathbf{x= \frac{38.11}{9 +6.93} }[/tex]

[tex]\mathbf{x= \frac{38.11}{15.93} }[/tex]

[tex]\mathbf{x= 2.39 }[/tex]

Recall that, the perimeter of the square is:

[tex]\mathbf{P_s=4x}[/tex]

So, we have:

[tex]\mathbf{P_s=4 \times 2.39}[/tex]

[tex]\mathbf{P_s=9.56}[/tex]

Hence, 9.56 m of the wire should be used for the square

Read more about maximizing lengths at:

https://brainly.com/question/3433355

Answer:

8/3

Step-by-step explanation:

1 foot = 12 inches, so it would be 32/12. After simplifying and dividing 4 on both sides, you would get 8/3.

[tex]\large\underline{\sf{Solution-}}[/tex]

Given that

[tex]\rm \longmapsto\:a > 0 \: \: and \: \: b > 0[/tex]

and

[tex]\rm \longmapsto\: {a}^{6} + {b}^{6} \leqslant 12 {a}^{2} {b}^{2} - 64[/tex]

can be rewritten as

[tex]\rm \longmapsto\: {a}^{6} + {b}^{6} + 64 - 12 {a}^{2} {b}^{2} \leqslant 0[/tex]

[tex]\rm \longmapsto\: {( {a}^{2}) }^{3} + {( {b}^{2} )}^{3} + {(4)}^{3} - 3( {a}^{2})( {b}^{2})(4) \leqslant 0[/tex]

We know

[tex]\mathfrak{ {x}^{3}+{y}^{3}+{z}^{3}-3xyz =(x + y + z)( {x}^{2}+{y}^{2}+{z}^{2}-xy-yz - zx}[/tex]

So, using this identity, we get

[tex] \rm( {a}^{2}+{b}^{2} + 4)( {a}^{4} + {b}^{4} + 16 - {a}^{2} {b}^{2} - 4 {b}^{2} - 4 {a}^{2}) \leqslant 0[/tex]

Let we consider,

[tex]\bf{ \longmapsto\:{a}^{4} + {b}^{4} + 16 - {a}^{2} {b}^{2} - 4 {b}^{2} - 4 {a}^{2}}[/tex]

can be rewritten as

[tex]\bf{ \:  = \dfrac{1}{2}\bigg[2{a}^{4} + 2{b}^{4} + 32 - 2{a}^{2} {b}^{2} - 8 {b}^{2} - 8{a}^{2}\bigg]}[/tex]

[tex]\bf{  = \dfrac{1}{2}\bigg[{a}^{4} + {a}^{4} + {b}^{4} + {b}^{4} + 16 + 16 - 2{a}^{2} {b}^{2} - 8 {b}^{2} - 8{a}^{2}\bigg]}[/tex]

can be re-arranged as

[tex]\bf{ \:  = \dfrac{1}{2}\bigg[({a}^{4} + {b}^{4} - 2{a}^{2} {b}^{2})+({b}^{4} + 16- 8 {b}^{2}) + (16 + {a}^{4} - 8{a}^{2})\bigg]}[/tex]

[tex]\bf{ \:  = \dfrac{1}{2}\bigg[( {a}^{2} - {b}^{2})^{2} + {( {b}^{2} - 4) }^{2} + {( {a}^{2} - 4)}^{2} \bigg]}[/tex]

As sum of squares can never be negative.

[tex]\bf {⇛\:{a}^{4} + {b}^{4} + 16 - {a}^{2} {b}^{2} - 4 {b}^{2} - 4 {a}^{2} \geqslant 0}[/tex]

[ Equality of zero holds when a = b = 2 ]

And if a and b are distinct, then

[tex]\bf{⇛\:{a}^{4} + {b}^{4} + 16 - {a}^{2} {b}^{2} - 4 {b}^{2} - 4 {a}^{2} > 0}[/tex]

and

[tex]\bf{( {a}^{2}+{b}^{2} + 4)( {a}^{4} + {b}^{4} + 16 - {a}^{2} {b}^{2} - 4 {b}^{2} - 4 {a}^{2}) > 0}[/tex]

So,

[tex] \bf{( {a}^{2}+{b}^{2} + 4)( {a}^{4} + {b}^{4} + 16 - {a}^{2} {b}^{2} - 4 {b}^{2} - 4 {a}^{2}) \geqslant 0}[/tex]

So, for the given statement,

[tex]\rm \longmapsto\: {a}^{6} + {b}^{6} \geqslant 12 {a}^{2} {b}^{2} - 64[/tex]

So, we concluded that

If a = b = 2, then

[tex]\rm \longmapsto\: {a}^{6} + {b}^{6} = 12 {a}^{2} {b}^{2} - 64[/tex]

And

If a and b are distinct, then

[tex]\rm \longmapsto\: {a}^{6} + {b}^{6} > 12 {a}^{2} {b}^{2} - 64[/tex]

So, given statement is partially true for a = b = 2 otherwise false.

Answer:

how is traffic to + 54 degree + 42 degree then that 96 degree - by 180 degree you get you will get 84 degree

9514 1404 393

Answer:

  A) (0, 0)

  B) (1, −25)

  D) (−1, 25)

Step-by-step explanation:

For the point to lie on the line, the y-value must be -25 times the x-value. That is the case for points A, B, D.

Answer:

Its is the second one

Step-by-step explanation:

Remember: rise over run

The b of the equation is -2 because that is how far it goes down on the y axis.

The slope is 3x.

Put the slope like this 3/1= rise/run

Sorry for the delayed response!  

Answer:

0.036%

Step-by-step explanation:

Answer:

49.7

Step-by-step explanation:

you just add them. thats perimeter

[tex]\\ \sf\longmapsto px^2+8x+8=0[/tex]

Equal roots means Discriminate=0

[tex]\\ \sf\longmapsto D=0[/tex]

[tex]\\ \sf\longmapsto b^2-4ac=0[/tex]

[tex]\\ \sf\longmapsto 8^2-4(8)(p)=0[/tex]

[tex]\\ \sf\longmapsto 64-32p=0[/tex]

[tex]\\ \sf\longmapsto 32p=64[/tex]

[tex]\\ \sf\longmapsto p=2[/tex]

Answer:

Step-by-step explanation:

Since the roots are equal, the given equation should be a perfect square:

Let p = 2q, since with odd value of p we can't get a perfect square:

The value of q should be 1 to make it a perfect square:

Since q = 1, the value of p is:

Answer:  Choice C

(x, y) → (x – 3, y + 5)

=================================================

Explanation:

The "5 units up" portion means that each y value increases by 5. Therefore, we go from y to y+5. Going from x to x-3 means that we shift each point 3 units to the right.

For example, if the starting point is (1,7), then we have the following steps:

[tex](x,y) \to (x-3,y+5)\\\\(1,7) \to (1-3,7+5)\\\\(1,7) \to (-2,12)\\\\[/tex]

The point (1,7) moves 5 units up and 3 units to the left to arrive at (-2,12).

Note that the order doesn't matter. We could start moving 5 units up, then go 3 units left. Or we could start going 3 units left, then 5 units up. We'll arrive at the same destination.

Answer:

I think you may have written it down wrong because no solution for that is possible.

[tex] \sf \: 70 \times 20[/tex]

[tex]\sf \longmapsto1400[/tex]

OR the question can also be written as

[tex] \sf \: 70 (20)[/tex]

[tex]\sf \longmapsto1400[/tex]

Answer:

1.25

Step-by-step explanation:

Answer:

12/15 > 4/5 equals 80%

Step-by-step explanation:

nani .-. why tho?

why need followers?

must reason why

Answer:

JUPITER SATURN MARS

Step-by-step explanation:

Answer:

el que está debajo del que está marcado con un círculo es correcto

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Answer:

Step-by-step explanation:

eight ten a.m.

Answer:

Do u have a photo??

Step-by-step explanation:

cuzz I do not know