Answer:
[tex]\left[\begin{array}{cccc}-1\\1\\1\\0\end{array}\right][/tex], [tex]\left[\begin{array}{cccc}0\\2\\0\\1\end{array}\right][/tex] Are two vectors which are basis of null space of A
Step-by-step explanation:
Basis of a null space is a vector matrix which when multiplied by the reduced echelon form of the matrix gives null matrix or 0 matrix
So, to find the reduced echelon form we apply the row operations :
R₁ = R₁/2
[tex]\left[\begin{array}{cccc}1&-2&3&4\\2&-1&3&2\\4&-5&9&10\\0&-1&1&2\end{array}\right][/tex]
R₂ = R₂ - 2R₁
[tex]\left[\begin{array}{cccc}1&-2&3&4\\0&3&-3&-6\\4&-5&9&10\\0&-1&1&2\end{array}\right][/tex]
R₃ = R₃ - 4R₁
[tex]\left[\begin{array}{cccc}1&-2&3&4\\0&3&-3&-6\\0&3&-3&-6\\0&-1&1&2\end{array}\right][/tex]
R₂ = R₂/3
[tex]\left[\begin{array}{cccc}1&-2&3&4\\0&1&-1&-2\\0&3&-3&-6\\0&-1&1&2\end{array}\right][/tex]
R₁ = R₁ + 2R₂
[tex]\left[\begin{array}{cccc}1&0&1&0\\0&1&-1&-2\\0&3&-3&-6\\0&-1&1&2\end{array}\right][/tex]
R₃ = R₃ - 3R₂
[tex]\left[\begin{array}{cccc}1&0&1&0\\0&1&-1&-2\\0&0&0&0\\0&-1&1&2\end{array}\right][/tex]
R₄ = R₄ + R₂
[tex]\left[\begin{array}{cccc}1&0&1&0\\0&1&-1&-2\\0&0&0&0\\0&0&0&0\end{array}\right][/tex]
which is a reduced echelon form of the matrix A
now ,
[tex]\left[\begin{array}{cccc}1&0&1&0\\0&1&-1&-2\\0&0&0&0\\0&0&0&0\end{array}\right][/tex] [tex]\left[\begin{array}{cccc}x1\\x2\\x3\\x4\end{array}\right][/tex] [tex]=\left[\begin{array}{cccc}0\\0\\0\\0\end{array}\right][/tex]
therefore,
x₁ + x₃ = 0
x₁ = -x₃
x₂ - x₃ - 2x₄ = 0
x₂ = x₃ + 2x₄
so now replacing values of x₁ , x₂ in the vector matrix
[tex]\left[\begin{array}{cccc}-x3\\x3 + 2x4\\x3\\x4\end{array}\right][/tex]
we can write the above matrix as,
[tex]x3\left[\begin{array}{cccc}-1\\1\\1\\0\end{array}\right][/tex] [tex]+ x4\left[\begin{array}{cccc}0\\2\\0\\1\end{array}\right][/tex]
therefore we can say that above mentioned vector matrices are the basis of the null space of matrix A
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Can someone help me? I’ll give brainliest to whoever gets it right first
Answer:
72 Degrees
Step-by-step explanation:
We know that its 72 because of VAT, the vertical angle theorem.
Express verbal statement in algebraic form.
The cost to rent a sailing boat at Catalina Island is $370 per day
plus $80 for every hour of use. What is the maximum number of
hours the sail boat can be rented for each day, if the rental cost is
not to exceed $1090 per day?
Answer:
370 + 80x ≤ 1090
Step-by-step explanation:
By using letter variables for the unknown numbers, we can break down the question into mathematical terms:
If the cost is $370 per day and the number of days is unknown, we can substitute the number of days with a placeholder. In this case, it'll be a variable such as x. So the cost can be represented by $370y.
If the cost is $80 per hour and the number of hours is unknown, we can substitute the number of hours with a placeholder. In this case, it'll be a variable such as y. So the cost can be represented by $80x.
The questions asks for the total cost not to exceed $1090 per day. This means that we know that the number of days is 1. We're trying to find the maximum number of hours, so our equation will combine the costs of both day costs and hour costs:
$370 (1 day) + $80 (x hours) ≤ $1090 per day
The symbol is the equal to or less than symbol, meaning the combined total costs is either equal to $1090 or less than it.
To simplify this, we can rewrite it as:
370 + 80x ≤ 1090
Darrel divided 8,675 by 87. His work is shown below
Which answer choice correctly identifies the error Darrel made when dividing?
a b c or d?
p + (-q) - 2 = ? When p = -3 and q = 5
Answer:
= -10
Step-by-step explanation:
p + (-q) - 2 = x
if:
p = -3
q = 5
then:
-3 + (-5) - 2 = x
we know that:
+(-) = -
then:
-3 +(-5) - 2 = -3 - 5 - 2 = x
x = -10
The value of the expression p + (-q) - 2 is -10 if the p = -3 and q = 5 the answer is -10.
What is an expression?It is defined as the combination of constants and variables with mathematical operators.
We have given an expression:
= P + (-q) - 2
Plug p = -3
q = 5
= -3 + (-5) - 2
= -3 - 5 - 2
= -10
Thus, the value of the expression p + (-q) - 2 is -10 if the p = -3 and q = 5 the answer is -10.
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Please state the equation of the line in standard form
Answer:
See below
Step-by-step explanation:
Slope = rise / run
from 0,-1 to 1.5 , 0
this is 1 / 1.5 = 2/3
y xis intercept = -1
y = 2/3 x -1 Slope intercept form
2/3 x - y = 1 another form
2x - 3y = 3 Standard form (I think this is 'standard form' ....yah?)
Which of the following statements are true?
A. Both graphs have exactly one asymptote.
B. Both graphs have been shifted and flipped.
c. Both graphs are logarithmic functions.
D. Both graphs are exponential functions.
PLEASE HELP ME!!!!!!!!!
Answer:
option 4 and option 3 are the answers respectively
Answer:
[tex] \sqrt{ {2}^{3} } \\ \sqrt{3} \\ .............[/tex]
MATH: Inverse function, 10 pts for your help!
The inverse of g(5) and the inverse of h(x) are 2 and [tex]h^{-1}=\frac{-x-13}{4}[/tex] respectively
Inverse of a function
Given the following coordinates and function
g = {(-6, -5), (2, 5), (5,6), (6,9)}
The inverse of "g" is determined by switching the coordinates to have:
g^-1(x) = {(-5, -6), (5, 2), (6, 5), (9,6)}
Since the value of the y-coordinate when x = 5 is 2, hence g^-1(5) = 2
Given the function expressed as:
h(x) = -4x - 13
y = -4x - 13
Replace y with x
x = -4y - 13
4y = -x - 13
y = (-x-13)/4
[tex]h^{-1}=\frac{-x-13}{4}[/tex]
Determine the composite function [tex](hoh^{-1})(-1)[/tex]
h(h(x)) = h(-4x-13)
h(h(x)) =[tex]\frac{-(-4x-13)-13}{4} \\[/tex]
[tex]h(h(x))=\frac{4x}{4} \\h(h(x)) = x\\h(h(-1)) = -1[/tex]
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Which of the following transformations produce congruent figures?
i. Rotation
ii. Reflection
iii. Translation
iv. Dilation
i, ii, and iii
i and ii
iv only
iii and iv
Hi. how can i Find the *number* of terms of a finite geometric sequence?
r= .75
a= 40
sum= 280
We have to use the formula [tex]n = log_{r} (1+\frac{S_{n}(1-r) }{a})[/tex] to find the number of terms of a finite geometric sequence.
If a be the first term of a finite sequence, r be the common ratio between consecutive terms and n be the number of terms.
So, we have to use the formula of sum of sequence and then calculate it to reduce the equation to find the value of number of terms, that is n.
Then, Sum of the sequence (Sn) = [tex]\frac{a(1-r^{n}) }{1-r}[/tex]
Here, in the given problem,
Sum(Sn) = 280, First term of the sequence(a) = 40, Common ratio(r) = 0.75
So, Sn = [tex]\frac{a(1-r^{n}) }{1-r}[/tex]
⇒ [tex]1-r^{n} =\frac{S_{n}(1-r) }{a}[/tex]
⇒ [tex]r^{n} =1+\frac{S_{n}(1-r) }{a}[/tex]
⇒ [tex]n = log_{r} (1+\frac{S_{n}(1-r) }{a})[/tex]
Now you have to put the values and get the number of terms.
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find in factord form -9n+n^2=0
Answer:
n(-9+ n) =0
Step-by-step explanation:
-9n+n^2=0 Kind of use 'reverse distributive' property
n (-9 + n) = 0
In AABC, a = 13, b = 14, and c = 18. Find m/A.
B
A
39.5
с
b
a
Answer:
Step-by-step explanation:
Using the Law of Cosines,
[tex]a^{2}=b^2 + c^2 - 2bc \cos A\\\\13^{2}=14^{2}+18^{2}-2(14)(18) \cos A\\\\-351=-504 \cos A\\\\\cos A=\frac{351}{504}\\\\A=\boxed{\cos^{-1} \left(\frac{351}{504} \right)}[/tex]
Line l has a slope of 2/3 The line through which of the following pair of points is perpendicular to l?
We conclude that the line that passes through (0, 0) and (2, -3) is perpendicular to line l.
The line through which of the following pair of points is perpendicular to l?Remember that two lines are perpendicular only if the slope of one of the lines is equal to the opposite of the inverse of the slope of the other line.
So, if line l has the slope 2/3.
Then the perpendicular lines have a slope equal to -3/2.
Now, remember that if a line goes through two points (x₁, y₁) and (x₂, y₂), then the slope of that line is:
[tex]a = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
So here we just need to find two points (x₁, y₁) and (x₂, y₂) such that the slope is equal to -3/2.
If we define (x₁, y₁) = (0, 0), then the other point must be:
[tex]a = \frac{y_2 - 0}{x_2 - 0} = -3/2\\\\y_2/x_2 = -3/2[/tex]
Then we can write the other point as (2, -3).
So we conclude that the line that passes through (0, 0) and (2, -3) is perpendicular to line l.
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x2y, for x = 3 and y = 6
Answer:
12
Step-by-step explanation:
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\textbf{ASSUMING}[/tex]
[tex]\mathsf{x^{2y}}[/tex]
[tex]\huge\textbf{IF SO, FOLLOW THESE STEPS TO}\\\huge\textbf{SOLVE FOR YOUR RESULT}[/tex]
[tex]\mathsf{x^{2y}}\\\mathsf{= 3^{2(6)}}\\\mathsf{= 3^{2\times6}}\\\mathsf{= 3^{12}}\\\mathsf{= 3\times3\times3\times3\times3\times3\times3\times3\times3\times3\times3\times3}\\\mathsf{= 9\times9\times9\times9\times9\times9}\\\mathsf{= 81\times81\times81}\\\mathsf{= 6,561\times81}\\\mathsf{= 531,441}[/tex]
[tex]\huge\text{Therefore, your answer should be: \boxed{\mathsf{531,441}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\huge\boxed{\frak{Amphitrite1040:)}}[/tex]Dedi had a combination lock.To open the lock he started at 37.He made 3 half turns clockwise and 3 quarter turns anticlockwise
What number did he end up at?
A uniform density curve goes from negative 5 to positive 1.
What would the height need to be for this curve to be a density curve?
Negative one-sixth
One-sixth
One-fifth
1
Picture posted below
Answer: Choice B) One-sixth
In other words, the fraction 1/6
===========================================================
Explanation:
The base, aka horizontal component, is 6 units long. Count out the spaces from -5 to 1 to get a result of 6.
Or you could subtract and use absolute value in either of these two ways
|A - B| = |-5 - 1| = |-6| = 6|B - A| = |1 - (-5)| = |1 + 5| = |6| = 6Where A = -5 and B = 1 are the endpoints mentioned. Absolute value is used to ensure the result of the subtraction isn't negative. Negative distance on a number line doesn't make sense.
----------
However you determine the base, we'll multiply it by the unknown height which we'll call h. This leads to the area of the rectangle. The area is 6h.
Rule: The area under a probability density curve must always be 1.
So the area 6h must be 1 which helps us see that...
6h = 1
h = 1/6
Divide both sides by 6 to isolate h fully.
Answer:
B
Step-by-step explanation:
What is the area of the polygon given below?
Answer:
340 i am pretty sure
Step-by-step explanation:
My friend has $672 to spend on a fence for her rectangular garden. She wants to use cedar fencing which costs $17/yard on one side, and cheaper metal fencing which costs $7/yard for the other three sides.
What are the dimensions of the garden with the largest area she can enclose?
The dimensions of the garden with the largest area she can enclose are given by 24*14 square yards.
The area (A) of the rectangle with length L and Width W is given by,
A=L*W
The maximum of [tex]y=ax^2+bx[/tex] occurs at x = -b/2a
Let the length and width of the garden be L and W respectively.
Now let my friend use cedar fencing for one width and cheaper metal fencing for rest sides.
Rate of cedar fencing is $17/yard
Then she has to pay for cedar fencing = 17W
rate of cheaper metal fencing is $7/yard
Then she has to pay for metal fencing = 7W+7*2L = 7W+14L
Then according to condition,
17W+7W+14L = 672
24W+14L = 672
12W+7L = 336
7L = 336-12W
L = (336-12W)/7
Then the area of the rectangular garden is given by,
A = L*W
[tex]A=\frac{336-12W}{7}\times W\\A=-\frac{12}{7}W^2+48W[/tex]
So here a = -12/7 and b = 48
Then maximum of W occurs at,
W = -48/(2*(-12/7)) = (48*7)/(2*12) = 336/24 = 14
Then maximum width = 14 yards
then length (L) = (336-12*14)/7 = 168/7 = 24 yards
Hence the dimensions with the leargest area she can enclose is given by = 24 * 14 square yards.
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Fig. R24 shows a flower vase whose circular base is parallel to its circular top.
Use the dimensions in the figure to calculate the curved surface area of the flower vase
Answer:
operant conditioning and schedules of reinforcement
I keep putting in the formula but I keep getting the answer wrong
Answer:
314 in² (nearest whole number)
Step-by-step explanation:
Radius of a regular polygon: The distance from the center of the polygon to any vertex. The radius of a hexagon is equal to the length of one side.
Therefore, from inspection of the given diagram:
radius = 11 in ⇒ side length = 11 inTo find the area of a regular polygon, we first need to calculate the apothem. The apothem is the line drawn from the center of the polygon to the midpoint of one of its sides.
[tex]\textsf{Length of apothem (a)}=\dfrac{s}{2 \tan\left(\frac{180^{\circ}}{n}\right)}[/tex]
where:
s = length of one siden = number of sidesGiven:
s = 11 inn = 6Substitute the given values into the formula and solve for a:
[tex]\implies \textsf{a}=\dfrac{11}{2 \tan\left(\frac{180^{\circ}}{6}\right)}=\dfrac{11\sqrt{3}}{2}[/tex]
Area of a Regular Polygon
[tex]\textsf{A}=\dfrac{n\:s\:a}{2}[/tex]
where:
n = number of sidess = length of one sidea = apothemGiven:
n = 6s = 11[tex]\textsf{a}=\dfrac{11\sqrt{3}}{2}[/tex]Substitute the given values into the formula and solve for A:
[tex]\implies \sf A=\dfrac{6 \cdot 11 \cdot \dfrac{11\sqrt{3}}{2}}{2}[/tex]
[tex]\implies \sf A=314.3672216...[/tex]
[tex]\implies \sf A=314\:\:in^2\:\:(nearest\:whole\:number)[/tex]
In(2e^9) in logarithmic expression
I’m having trouble with all of the “In” section and very confused
In logarithmic form, we get In(2e^9)= ln(2)+9.
LogarithmsWe define the logarithm as the power to which any number must be raised to get few other values.Exponentiation is the reverse process of logarithm.We are given,
ln(2[tex]e^{9}[/tex])
We know that, ln(ab) = ln(a) + ln(b)
So we get,
ln(2[tex]e^{9}[/tex]) = ln(2)+ln([tex]e^{9}[/tex])
Since ln(m^n)=n ln(m)
And ln(e)= 1, we will get,
ln(2[tex]e^{9}[/tex]) = ln(2) +9 ln(e)
= ln(2) +9
Hence, the logarithmic form, we get In(2e^9)= ln(2)+9.
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Solve for all values of y
in simplest form.
∣y−12∣=16
Answer:
[tex]y=-4; y=28[/tex]
Step-by-step explanation:
The way I like to think about it, with absolute value meaning the distance is
"find which number are 16 apart from 12". Which means 28 (to the right) or -4 (to the left).
More formally, applying the definition of absolute value,
[tex]|y-12|=16 \leftrightarrow y-12=\pm16\\y-12=-16 \rightarrow y=-4\\y-12=+16 \rightarrow y=28[/tex]
What is the probability if a penny lands on heads 30 times after being tossed 50 times?
The probability will be equal to 60%.
What is probability?Probability is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.
The best thing to do here is to put it into a fraction. as 30 landed heads up, 20 (50-30) must be tails.
You can then put this into a fraction, which becomes 20/50.
To turn this into a decimal, you can then divide 1 by 50
1/50= 0.02
As you've got 22 lots of this, you then need to multiply 0.02 by 20.
0.2x20= 0.40
To find the percentage, you've then got to multiply the decimal by 100.
100x0.40= 40.
Therefore, 40% of the tosses would be tails
As you've found what one percentage is, you simply need to take this number away from 100 to find the other, rather than having to go through the process again.
100-40= 60
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On a walk through the woods, Mr. Finley saw 16 blue jays and 25 purple finches. Write the ratio of finches to blue jays three different ways.
Answer:
25:16
50:32
100:64
Step-by-step explanation:
2. (06.03)
What is the solution to the following system of equations? (2 points)
y = -x2 – 5x − 4
y = -x² + 9x - 18
O (-1,-10)
O (1,-10)
O (-1,10)
(1.10)
Answer: (1, -10)
Step-by-step explanation:
Since both of the equations are set equal to y, we can conclude that:
[tex]-x^2 -5x-4=-x^2 + 9x-18\\\\-5x-4=9x-18\\ \\ -14x-4=-18\\\\-14x=-14\\\\x=1[/tex]
If x=1, then [tex]y=-(1)^{2}+9(1)-18=-10[/tex]
Thus, the solution is (1, -10)
0 1 3 6 10 what goes after 10?
Answer:
15
Step-by-step explanation:
0 + 1 = 1
1 + 2 = 3
3 + 3 = 6
6 + 4 = 10
10 + 5 = 15
25. (01.05)
Given the point (2, 3) and the slope of 4, find y when x = 22. (1 point)
I 78
O83
O88
091
Answer: 83
Step-by-step explanation:
The equation of the line in point-slope form is
[tex]y-3=4(x-2)[/tex]
Substituting in x = 22,
y - 3 = 4(22-2) [substitution]y -3 = 80 [simplify right hand side]y = 83 [add 3 to both sides]I will give BRAINLIEST! ANSWER QUESTION! I NEED IT ASAP
Out of a sample of 500 high school students, 376 said they would prefer to have computers in every classroom. Construct a 95% confidence interval for the population mean of high school students who would prefer to have computers in every classroom.
CI = (71.41%, 78.99%)
CI = (71.98%, 79.45%)
CI = (70.23%, 80.17%)
CI = (72.02%, 78.38%)
The correct answer is CI = (71.415%, 78.915%)
The correct option is (A)
What is Confidence level?A confidence interval is the mean of your estimate plus and minus the variation in that estimate.
Given:
x = 376
Sample = 500 students
CI= [(376/500-1.96 √((376/500)*(124/500)/500) , (376/500-1.96
√((376/500)*(124/500)/500)]
CI = (71.415%, 78.915%)
Hence, CI = (71.415%, 78.915%)
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A rectangle has a length 10 more than its width. If the width is increased by 8 and the length by 4, the resulting rectangle has an area of 135 square units.
Part A Write an equation to model the above scenario. Use the model to find the length of the original rectangle?
Part B What is the perimeter of the expanded rectangle?
The equation to model the above scenario is [tex]x^{2}[/tex] +22x - 23 = 0
The perimeter of the expanded rectangle is 48 units
What is a rectangle?A rectangle is a quadrilateral with its 4 angles 90°
Analysis:
First rectangle:
length = 10 + x
width = x
Second rectangle:
length = x + 14
width = x + 8
Area of expanded rectangle = 135 square unit
(x+8)(x+14) = 135
[tex]x^{2}[/tex] + 8x + 14x + 112 = 135
[tex]x^{2}[/tex] + 8x + 14x -23 = 0
[tex]x^{2}[/tex] + 22x -23 = 0
[tex]x^{2}[/tex] + 23x - x - 23 = 0
(x-1)(x+23) = 0
Therefore x = 1
Expanded length = 1+14 = 15
Expanded width = 1+8 = 9
Perimeter = 2(9+15) = 48 units
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2(x + 2) + 5(x + 5) = 4(x-8) + 2(x - 2)
Step-by-step explanation:
2(x + 2) + 5(x + 5) = 4(x-8) + 2(x - 2)
2x+4+5x+25=4x-32+2x-4
7x+29=6x-36
7x-6X=-36-29
X=-65
Answer:
x = -65
Step-by-step explanation:
2(x + 2) + 5(x + 5) = 4(x-8) + 2(x - 2)
Distribute:
2(x + 2): 2x + 4
5(x + 5): 5x + 25
=
4(x - 8): 4x - 32
2(x - 2): 2x - 4
Combine like terms:
(2x + 4) + (5x + 25) = (4x - 32) + (2x - 4)
5x + 2x: 7x = 4x + 2x: 6x
4 + 25 = 29 = -32 - 4: -36
7x + 29 = 6x - 36
Now we want to separate like terms,
subtract 29 from both sides
subtract 6x from both sides
7x + 29 - 29 - 6x = 6x - 29 - 6x- 36
7x - 6x = - 29 - 36
x = -65