1. Janna works at a lab with a huge circular particle accelerator. It has a radius of 4 kilometers. What is the accelerator's diameter?

2. KC wants to know the area of the portion with a lot of cheese. The radius of the pizza is 9 inches and the intercepted arc of the pizza with lot of cheese measures 140°. What will be the area of the shaded sector?

3. From the main entrance of the park, there are two pathways where visitors can walk along going to the circular garden. The pathways are both tangent to the garden whose center is 40m away from the main entrance. If the area of the garden is about 706.5 m2, how long is each pathway?

pakisagot po ty!! ​

Answer:

1. diameter=8 kilometres

2. area=98.96 inches

3. 37m

Step-by-step explanation:

1. diameter= 2*radius

2. area of sector=θ out of 360*π[tex]r^{2}[/tex] where θ is the angle

3. area of garden=π[tex]r^{2}[/tex]

        706.5=π[tex]r^{2}[/tex]

     [tex]r^{2}[/tex]=706.5/π

        = 225(nearest whole)

     r=[tex]\sqrt{225}[/tex]=15m

we now use Pythagoras theorem to find length of each pathway

[tex]40^{2} =15^{2} +x^{2}[/tex]

1600=225+[tex]x^{2}[/tex]

[tex]x^{2}[/tex]=1600-225=1375

x=[tex]\sqrt{1375}[/tex]=37 m (to nearest whole)

The tangent pathways from the entrance form right triangles from which

the length of the pathway which are the sides of the triangle, can be found.

Reasons:

1. The radius of the particle accelerator = 4 kilometers

The diameter of the particle accelerator = 2 × The radius

Therefore;

The diameter = 2 × 4 km = 8 km

The accelerator's diameter is 8 kilometers

2. The area of a sector of a circle is A = [tex]\displaystyle \frac{\theta}{360^{\circ}} \times \pi \cdot r^2[/tex]

The angle subtended by the sector, θ = 140°

The radius of the sector, r = 9 inches

Therefore;

[tex]\displaystyle A = \frac{140^{\circ}}{360^{\circ}} \times \pi \times 9^2 = \mathbf{ 31.5 \cdot \pi}[/tex]

The area of the shaded sector, A = 31.5·π in.² ≈ 98.96 in.²

3. The distance from the center to the main entrance, d = 40 m

Area of the circular garden, A = 706.5 m²

Solution:

The radius of the garden, r = √(A ÷ (π))

Therefore;

r = √(706.5 ÷ (π)) ≈ 15

The tangent pathways are perpendicular to the radius of the circular garden.

Therefore, the pathway from the entrance, the 40 m. distance from the center to the entrance and the radius form a right triangle.

Where;

The 40 m. distance = The hypotenuse side

By Pythagorean theorem, we have;

40² = r² + (Length of the pathway)²

Which gives;

40² = 15² + (Length of the pathway)²

Length of the pathway ≈ √(40² - 15²) ≈ 37.1

The length of each pathway is approximately 37.1 m.

Learn more about Pythagorean theorem here:

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