Answer:
when u stop at great speed in a vechial your body is in still in motion
Explanation:
You're given an unknown acid and told that it will donate one proton per molecule. When 1. 0 g of this acid is dissolved in water, the resulting solution requires 50. 0 ml of a 0. 25 M solution of NaOH for neutralization. What's the molecular mass of the unknown acid? Explain. (Hint: Find the moles of acid present)
The molecular mass of the unknown acid is 100 g/mol.
To find the molecular mass, first determine the moles of acid present. Since 50.0 mL of 0.25 M NaOH is required for neutralization, calculate the moles of NaOH using the formula: moles = Molarity × Volume (in L).
Moles of NaOH = 0.25 mol/L × (50.0 mL × 0.001 L/mL) = 0.0125 mol
Since the acid donates one proton per molecule, the moles of acid present equal the moles of NaOH: 0.0125 mol.
Next, find the mass of one mole of the unknown acid. You have 1.0 g of the acid, so divide the mass by the moles to get the molecular mass:
Molecular mass = Mass / Moles = 1.0 g / 0.0125 mol = 100 g/mol
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Use the electron-transfer method to balance this equation:
solid copper and dilute nitric acid react to produce copper(ii) nitrate, water, and nitrogen monoxide gas (no)
The electron-transfer method is a way to balance chemical reactions by assigning oxidation numbers to each element and then transferring electrons between the two sides of the equation until the number of electrons is equal on both sides.
In this case, the reactants are solid copper and dilute nitric acid, which will produce copper(II) nitrate, water, and nitrogen monoxide gas (NO).
The first step is to assign oxidation numbers to the elements. For copper, the oxidation number is 0, for nitrogen it is +3, for oxygen it is -2, and for hydrogen it is +1.
The next step is to transfer electrons between the two sides of the equation so that the number of electrons on each side is equal. In this case, we can transfer two electrons from the reactant side to the product side. This will result in the equation being balanced, with the copper being reduced to 0 and the nitrogen being oxidized to +5.
The balanced equation would look like this:
Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO
The electron-transfer method is a simple, effective way to balance chemical equations.
By assigning oxidation numbers and transferring electrons between the reactants and products, we can ensure that the equation is balanced and all atoms are conserved.
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13. Lab Analysis: You forgot to label your chemicals and do not know whether your unknown solution is strontium nitrate or magnesium nitrate. You use the solutions potassium carbonate and potassium sulfate in order to determine your mistake. unknown + potassium carbonate & unknown + potassium sulfate . What do you observe when the unknown solution is mixed with potassium sulfate? (Can you see the shape underneath?)
if the unknown solution is mixed with potassium carbonate, the reaction will proceed differently depending on whether the unknown solution is strontium nitrate or magnesium nitrate.
Mixing the unknown solution with potassium sulfate will not provide any useful information to identify whether the unknown solution is strontium nitrate or magnesium nitrate. This is because neither strontium nor magnesium sulfate has distinctive properties that allow them to be easily distinguished from one another.
However, When mixed with strontium nitrate, potassium carbonate will form a white precipitate of strontium carbonate, while no reaction will occur when mixed with magnesium nitrate. Therefore, the presence of a white precipitate after mixing with potassium carbonate indicates that the unknown solution is strontium nitrate.
In summary, to identify whether the unknown solution is strontium nitrate or magnesium nitrate, the solution should be mixed with potassium carbonate. If a white precipitate forms, the solution is strontium nitrate. If no reaction occurs, the solution is magnesium nitrate. Mixing the unknown solution with potassium sulfate will not provide any useful information.
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the process in which an atom or ion experiences a decrease in its oxidation state is _____________.
Answer:
Reduction
Explanation:
when an atom or ion decreases in oxidation state
The process in which an atom or ion experiences a decrease in its oxidation state is called reduction.
Reduction is the opposite of oxidation, which is the process in which an atom or ion experiences an increase in its oxidation state. In a redox (reduction-oxidation) reaction, one species undergoes reduction while the other undergoes oxidation.
In the process of reduction, the species gains electrons, resulting in a decrease in its oxidation state. The reducing agent is the species that donates electrons, while the oxidizing agent is the species that accepts electrons.
Reduction reactions are important in many chemical and biological processes, including metabolism, photosynthesis, and corrosion. The study of redox reactions is important in understanding the behavior of chemicals in natural and industrial processes.
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Draw the major organic product for each reaction. Assume a one to one ratio of starting material to reagent. H3Cl Cl --> AlCl3 ;
The major organic product for the reaction between hydrogen chloride (HCl) and aluminum chloride [tex](AlCl_3)[/tex] is aluminum chloride [tex](AlCl_3)[/tex].
When hydrogen chloride (HCl) reacts with aluminum chloride [tex](AlCl_3)[/tex], the reaction is exothermic and produces aluminum chloride [tex](AlCl_3)[/tex] as the major product. Hydrogen chloride (HCl) is a strong acid that dissociates fully in water, releasing chloride ions (Cl-). Aluminum chloride [tex](AlCl_3)[/tex] is a strong base that reacts with hydrogen chloride (HCl) to form aluminum hydroxide [tex](AlCl_3)[/tex] and hydrochloric acid (HCl). The ratio of starting material to reagent is one to one.
The balanced equation for the reaction between hydrogen chloride (HCl) and aluminum chloride [tex](AlCl_3)[/tex] is:
HCl + [tex](AlCl_3)[/tex] → [tex]Al(OH)_3[/tex] + HCl
Therefore, the major organic product for this reaction is aluminum hydroxide [tex]Al(OH)_3[/tex], which is an inorganic compound.
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Silo measure d 640 grams of sulphur which occupies 540ml of container at 47 degree celsius.find the pressure of the gas.
The pressure of the gas is 76.8 atm.
The pressure of the gas can be calculated using the ideal gas law formula:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
First, we need to calculate the number of moles of sulfur:
molar mass of sulfur = 32 g/mol
number of moles = mass/molar mass
= 640 g/32 g/mol
= 20 mol
Next, we need to convert the volume from milliliters to liters and the temperature from Celsius to Kelvin:
V = 540 ml = 0.54 L
T = 47°C + 273.15 = 320.15 K
Finally, we can plug in the values and solve for pressure
P = nRT/V
= 20 mol x 0.08206 L atm mol⁻¹ K⁻¹ x 320.15 K / 0.54 L
= 76.8 atm
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Naturally occurring potassium consists of potassium-39 and potassium-41. calculate the percentage of each isotope present if theaverage is 39.1.
When the average is 39.1, naturally occurring potassium consists of 50% potassium-39 and 50% potassium-41.
An isotope is a variant of an element that has the same number of protons but a different number of neutrons in its nucleus. Potassium has two naturally occurring isotopes: potassium-39 and potassium-41. To calculate the percentage of each isotope present when the average is 39.1, we can use the following formula:
% of potassium-39 = (39.1 - 41) / (39 - 41) x 100%
% of potassium-41 = 100% - % of potassium-39
Using this formula, we can first calculate the percentage of potassium-39:
% of potassium-39 = (39.1 - 41) / (39 - 41) x 100%
% of potassium-39 = -1 / (-2) x 100%
% of potassium-39 = 50%
This means that potassium-39 makes up 50% of the naturally occurring potassium. To calculate the percentage of potassium-41, we simply subtract the percentage of potassium-39 from 100%:
% of potassium-41 = 100% - 50%
% of potassium-41 = 50%
Therefore, potassium-41 also makes up 50% of the naturally occurring potassium. In summary, when the average is 39.1, naturally occurring potassium consists of 50% potassium-39 and 50% potassium-41.
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what is the major organic product from the addition reaction of hbr to 2-methyl-2-butene? group of answer choices 2-bromopentane 2-bromo-2-methylbutane 1-bromo-2-methylbutane 1-bromo-3-methylbutane 2-bromo-3-methylbutane
The addition of HBr to 2-methyl-2-butene is an example of an electrophilic addition reaction. The correct answer is (2)
The double bond in 2-methyl-2-butene is attacked by the electrophilic H+ ion from HBr, leading to the formation of a carbocation intermediate. The bromide ion (Br-) then attacks the carbocation, leading to the formation of a new carbon-bromine bond. The major organic product obtained from the addition reaction of HBr to 2-methyl-2-butene is 2-bromo-2-methylbutane, which is also known as t-butyl bromide. This is because the addition of HBr occurs at the tertiary carbon, leading to the formation of a tertiary carbocation intermediate, which is relatively stable. Therefore, the correct answer is (2) 2-bromo-2-methylbutane.
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--The complete Question is, what is the major organic product from the addition reaction of hbr to 2-methyl-2-butene? group of answer choices
1. 2-bromopentane 2-bromo-2-methylbutane
2. 1-bromo-2-methylbutane
3. 1-bromo-3-methylbutane
4. 2-bromo-3-methylbutane=--
A 54.2 g sample of Magnesium has an initial temperature of 55°C and a final temperature of 78°C, and the specific heat of Magnesium is 1.023 J/g°C. If the sample absorbs 1300 J of heat energy, what is the change in temperature?
Change in temperature of the Magnesium sample is calculated as 23.7°C.
What is meant by heat energy?Heat energy is a form of energy that is transferred between objects or systems due to temperature difference. It flows from hotter to cooler objects, and its amount is measured in joules.
As we know; Q = m c ΔT
Q is the amount of heat absorbed, m is mass of the object, c is specific heat, and ΔT is change in temperature.
ΔT = Q / (m * c)
ΔT = 1300 J / (54.2 * 1.023 )
ΔT = 23.7°C
Therefore, the change in temperature of the Magnesium sample is 23.7°C.
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A neutral atom of a certain element has 15 electrons. a. what is the ground state electron configuration of the element?b. how should the element be classified ?c. are the atoms of this element diamagnetic or paramagnetic?
A neutral atom of the element with 15 electrons is phosphorus with a ground state electron configuration of 1s2 2s2 2p6 3s2 3p3. It is classified as a nonmetal element in group 15. The atoms of this element are diamagnetic, as all electrons are paired up in their orbitals.
A neutral atom is an atom that has an equal number of protons and electrons. In the case of this certain element with 15 electrons, its ground state electron configuration would be 1s2 2s2 2p6 3s2 3p3.
This means that the first shell (n=1) has 2 electrons, the second shell (n=2) has 8 electrons, and the third shell (n=3) has 5 electrons.
Based on its position in the periodic table and the number of valence electrons it has, the element with this electron configuration is phosphorus. Phosphorus is a nonmetal element that belongs to group 15, also known as the nitrogen group.
To determine whether the atoms of this element are diamagnetic or paramagnetic, we need to look at its electron configuration. In this case, we can see that all the electrons are paired up in their respective orbitals, meaning there are no unpaired electrons.
This makes the element diamagnetic, which means it does not have a magnetic field of its own and will not be attracted to a magnetic field.
In summary, a neutral atom of the element with 15 electrons is phosphorus with a ground state electron configuration of 1s2 2s2 2p6 3s2 3p3. It is classified as a nonmetal element in group 15. The atoms of this element are diamagnetic, as all electrons are paired up in their orbitals.
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G A saturated liquid-vapor mixture of water with a mass of 4. 2 kg is contained in a rigid tank at a pressure of 225 kPa. Initially, 80% of the mass is in the liquid phase. All of the liquid in the tank is then vaporized by an electric resistance heater such that the system now contains a saturated vapor. What is the total entropy change of the steam during this process
The total entropy change of the steam during this process is 24.885 kJ/K.
During this process, the system undergoes a phase change from a saturated liquid-vapor mixture to a saturated vapor. The initial state can be determined using a steam table, which shows that at 225 kPa, the saturation temperature of water is 120.23°C. Therefore, the initial state is a mixture of liquid water and steam at 120.23°C with 80% of the mass in the liquid phase.
When the electric resistance heater vaporizes all of the liquid, the system transitions to a state of saturated vapor at the same pressure of 225 kPa and temperature of 120.23°C. The total entropy change of the steam during this process can be calculated using the formula:
ΔS = m * s_final - m * s_initial
where ΔS is the total entropy change, m is the mass of the steam, s_final is the specific entropy of the final state, and s_initial is the specific entropy of the initial state.
At the initial state, using the steam table, the specific entropy of the saturated liquid-vapor mixture can be found to be 1.5875 kJ/kg-K. At the final state, the specific entropy of the saturated vapor can also be found to be 7.2925 kJ/kg-K.
Therefore, the total entropy change of the steam is:
ΔS = 4.2 kg * (7.2925 kJ/kg-K - 1.5875 kJ/kg-K)
ΔS = 24.885 kJ/K
Therefore, the total entropy change of the steam during this process is 24.885 kJ/K.
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An equilibrium mixture at 425°C is found
to consist of 1.83 × 10-3 mol/L of H2,
3.13 × 10-3 mol/L of I2, and 1.77 × 10-2 mol/L
of HI. Calculate the equilibrium constant, K, for
the reaction H2(g) + I2(g) ⇄ 2HI(g).
The equilibrium constant, K, for the reaction H2(g) + I2(g) ⇄ 2HI(g) can be calculated using the expression K= [HI]2/([H2][I2]). Since the concentrations of H2, I2, and HI are given in the question, we can calculate the equilibrium constant, K, for the reaction.
K = [HI]2/([H2][I2]) = (1.77 × 10-2)2/((1.83 × 10-3)(3.13 × 10-3)) = 4.43 × 104. Therefore, the equilibrium constant, K, for the reaction H2(g) + I2(g) ⇄ 2HI(g) at 425°C is 4.43 × 104.
Using the specified concentrations of H2, I2, and HI, it appears that you have correctly calculated the equilibrium constant, K, for the reaction H2(g) + I2(g) 2HI(g) at 425°C. The ratio of the concentrations of the reactants and products at equilibrium, K, is represented by each concentration being raised to the power of its stoichiometric coefficient.
The concentration of the product, HI, is preferred above the concentrations of the reactants, H2 and I2, at equilibrium, as shown by the value of K = 4.43 104 in this instance. This suggests that at equilibrium, the forward reaction—the creation of HI—is preferred.
It is significant to remember that the equilibrium constant, K, is temperature-dependent, and that temperature changes affect K's value.
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1. Using the "octet rule," write the Lewis structures for the following molecules: (a) CH2Cl2 (b) NCl3 (c) CS2 and (d) CH3CHCHCH3 2. The following questions refer to the bolded carbon atom in the molecule: CH3CHCHCH3 a) How many areas of high electron density (number of bonded atoms plus number of lone pairs) surround the indicated C? b) Give the AXmEn notation for the C in this molecule (Look on page 6 of this experiment) c) What is the molecular geometry for the C in this molecule? d) What are the bond angles surrounding C? 3. While obeying the octet rule, nitric acid HNO3, has two resonance structures. Draw them. (Hint: the hydrogen atom is bonded to one of the oxygen atoms)
1. Using the "octet rule," I will write the Lewis structures for the following molecules:
(a) CH₂Cl₂: H-Cl:C-H
|
Cl
(b) NCl₃: Cl
|
Cl-N-Cl
(c) CS₂: O=C=S=O
(d) CH₃CHCHCH₃: CH₃-CH-CH-CH₃
2. For the bolded carbon atom in the molecule CH₃CHCHCH₃:
a) There are 3 areas of high electron density surrounding the indicated C (3 bonded atoms and 0 lone pairs).
b) The AXmEn notation for the C in this molecule is AX₃E₀, where m=3 and n=0.
c) The molecular geometry for the C in this molecule is trigonal planar.
d) The bond angles surrounding C are approximately 120 degrees.
3. Obeying the octet rule, nitric acid (HNO₃) has two resonance structures. They can be drawn as:
Resonance Structure 1: O=N-O-H
||
O
Resonance Structure 2: O-N=O
||
O-H
Let us learn more in detail.
1.
(a) CH₂Cl₂: Carbon is the central atom with two hydrogen atoms and two chlorine atoms attached. The Lewis structure would be:
Cl H
| |
C-H-C-Cl
| |
H Cl
(b) NCl₃: Nitrogen is the central atom with three chlorine atoms attached. The Lewis structure would be:
Cl
|
Cl-N-Cl
|
Cl
(c) CS₂: Carbon is the central atom with two sulfur atoms attached. The Lewis structure would be:
S=C=S
(d) CH₃CHCHCH₃: Carbon is the central atom with three methyl groups and one hydrogen atom attached. The Lewis structure would be:
H H H
| | |
H-C-C-C-H
| | |
H H CH₃
3. The two resonance structures for nitric acid HNO₃ would be:
O-H O
| |
H-O=N O=N-O
| |
O O-H
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If you have 16 moles of o2 in a balloon what is the volume of oxygen in the balloon
If you have 16 moles of O2 in a balloon at 25°C and 1 atm, the volume of oxygen in the balloon is 390.5 liters.
The volume of oxygen in a balloon containing 16 moles of O2 depends on the temperature and pressure of the gas. To find the volume, we can use the ideal gas law equation PV = nRT, where P is the pressure of the gas, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
Assuming the temperature and pressure are constant, we can rearrange the equation to solve for volume: V = nRT/P. The value of R is 0.0821 L·atm/mol·K.
Let's assume that the temperature is 25°C, or 298 K, and the pressure is 1 atm. Plugging in the values, we get:
V = (16 mol)(0.0821 L·atm/mol·K)(298 K)/(1 atm)
V = 390.5 L
Therefore, if you have 16 moles of O2 in a balloon at 25°C and 1 atm, the volume of oxygen in the balloon is 390.5 liters.
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what do you think determines these traits in the lobsters? How could these traits change?
The traits in lobsters are determined by their genetic makeup and environmental factors.
Natural selection can play a role in changing traits over time.
Which genetic factors are at play?Genetic factors include inherited traits from their parents such as color, size, and shell density. Environmental factors such as water temperature, salinity, and availability of food can also impact these traits.
For example, lobsters in warmer water tend to grow faster and larger than those in cooler water. Changes in habitat or pollution can also impact the availability of food and water quality, leading to changes in growth rates and physical traits.
Lobsters with advantageous traits, such as stronger shells or better camouflage, are more likely to survive and pass on their genes to the next generation. Over time, these beneficial traits may become more common in the population.
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use a sheet of paper to answer the following question. take a picture of your answers and attach to this assignment. treatment of pentanedioic (glutaric) anhydride with ammonia at elevated temperature leads to a compound of molecular formula c5h7no2. what is the structure of this product? [hint: you need to think about the reactivity not only of acid anhydrides but also of amides and carboxylic acids]
The structure of product is shown.
When pentanedioic (glutaric) anhydride reacts with ammonia at high temperature, it undergoes an amide formation reaction to produce a compound with the molecular formula C₅H₇NO₂. The amide formation reaction involves the nucleophilic attack of the ammonia molecule on one of the carbonyl carbon atoms of the anhydride, leading to the formation of an intermediate product called an amide.
This amide then undergoes further reactions to form the final product with the given molecular formula. The presence of both carboxylic acid and amide functional groups in the molecule indicates that it contains both the original anhydride and the product of its reaction with ammonia.
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which nutrients are most responsible for eutrophication?
a. carbon and oxygen
b. carbon and phosphorus
c. nitrogen and oxygen
d. nitrogen and phosphorus
Answer:
C. Nitrogen and Phosphorous.
Explanation:
Review this reaction:
H2SO4+NaOH->?.
What are the products?
Which words would be under the subheading "Ingredients"?
(Heading) Old Hunting Recipe for Rhinoceros Stew
(Subheading) Ingredients:
hair
broth
pepper
rhinoceros
hare
salt
water
onions
The words listed under the subheading "Ingredients" for the recipe "Old Hunting Recipe for Rhinoceros Stew" would be: Rhinoceros, Hare, Onions, Water, Broth, Salt, Pepper, and Hair.
What word would be listed?Under the subheading "Ingredients" for the recipe "Old Hunting Recipe for Rhinoceros Stew," the following words would be listed:
RhinocerosHareOnionsWaterBrothSaltPepperHair (Note: this is an unusual ingredient and may be questioned as to its necessity in the recipe)
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A sample of 0. 0400 mol potassium hydroxide, KOH was dissolved in water to yield 20. 0 mL of solution. What is the molarity of the solution?
0. 4M
250M
2. 0M
2. 00x 10-3M
The molarity of the potassium hydroxide solution is 2.0 M.
We know that, Molarity (M) = moles of solute (mol) / volume of solution (L)
We have 0.0400 mol of KOH dissolved in 20.0 mL of water.
Volume of the solution= 20.0 mL = 20.0 / 1000 = 0.0200 L
Therefore, molarity = (0.0400 mol) / (0.0200 L) = 2.0 M
So, the molarity of the potassium hydroxide solution is 2.0 M.
Thus, option 3 is the correct answer.
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Blackworms were collected from an environment with an acidic pH, and the pulse rates were measured. Predict the outcome of the measurements. [2 pt] The pH of the nevironment would have no effect on pulse rate. The pulse rate would be increased to minimize the effects of acidosis. The pulse rate would be increased to minimize the effects of alkalosis. The pulse rate would be decreased to minimize the effects of acidosis
The pulse rate of blackworms collected from an environment with an acidic pH would be increased to minimize the effects of acidosis.
Acidosis occurs when there is an excess of acid in the body, which can lead to a decrease in blood pH. To compensate for this, the body increases pulse rate to improve blood circulation and oxygen delivery.
Blackworms are no exception to this mechanism and would experience an increase in pulse rate to counteract the acidic environment. It is important to note that the increase in pulse rate would not be enough to completely eliminate the effects of acidosis, but rather to minimize them.
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NEED HELP FAST!!!! Please answer both questions
There is a 0.37 M molarity.
1.71 m molality is present.
Molarity: What is it?The quantity of a solute in a solution is measured in terms of molarity, a unit of concentration. It is described as the quantity of solutes that dissolve in one liter of solution, or mol/L. Molarity, in other words, reveals how many moles of solute there are in a liter of solution.
To determine molarity, use the following formula:
Molarity (M) is calculated as moles of solute divided by the liters of solution.
100g/180 g/mol * 1/1.5 L is the molarity.
= 0.37 M,
Molality = 200g/58.5g/mol * 1/2 Kg
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Classify each type bifunctional molecule as being a material used in the synthesis of polyesters, nylons, both, or neither.
dialcohol
diester
dinitro
diacid
diamine
diether
Dialcohol and diacid are bifunctional molecules that can be used in the synthesis of polyesters. In a polyester, the dialcohol and diacid react to form an ester bond, resulting in a long chain polymer.
Diesters can also be used in the synthesis of polyesters, as they can be hydrolyzed to form two carboxylic acid groups and two alcohol groups, which can then react to form an ester bond. Therefore, diesters are also a material used in the synthesis of polyesters.
Diamines and diacids can react to form nylon, so they are bifunctional molecules used in the synthesis of nylons. The reaction between a diamine and diacid forms an amide bond, which leads to a long-chain polymer.
Dinitro and diether are bifunctional molecules that are neither used in the synthesis of polyesters nor nylons. Dinitro compounds typically have nitro groups attached to each of the functional groups, making them more reactive and often used as explosives.
Diethers, on the other hand, can be used in organic synthesis as protecting groups for alcohols or carbonyl groups, but they do not have a direct role in the synthesis of polyesters or nylons.
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2. write out the balanced chemical equation for the reaction of 2 moles of naoh with 1 mole of h3po4
2NaOH + H₃PO₄ → Na₂HPO₄ + 2H2O is the balanced chemical equation for the reaction between 2 moles of NaOH and 1 mole of H3PO4.
It is clear from the balanced chemical equation that the reaction between 2 moles of NaOH and 1 mole of H₃PO₄ is an acid-base reaction, commonly referred to as a neutralization reaction.
In this reaction, phosphoric acid (H₃PO₄) acts as the acid and sodium hydroxide (NaOH) as the base. Na₂HPO₄ and H2O are created when the base (NaOH) and acid (H₃PO₄) react. Since all the reactants are completely consumed in the reaction and no excess of either reactant is left over, the stoichiometric balance of the number of moles of the acid and base is demonstrated by the balanced chemical equation.
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A solution of lithium carbonate reacts with a solution of potassium iodide to produce solid potassium carbonate and aqueous lithium iodide. You measure 3. 9 moles of potassium carbonate produced by the reaction. How much lithium iodide was produced?
The quantity of lithium iodide produced in the reaction was determined to be 7.8 moles.
The balanced chemical equation for the reaction between lithium carbonate (Li₂CO₃) and potassium iodide (KI) is:
2 Li₂CO₃ + 2 KI → 2 K₂CO₃ + 4 LiI
From the balanced equation, we can see that for every 2 moles of Li₂CO₃ reacted, 4 moles of LiI are produced.
Therefore, if we have 3.9 moles of K₂CO₃, we can calculate the moles of LiI produced as:
3.9 moles K₂CO₃ × (4 moles LiI / 2 moles Li₂CO₃) = 7.8 moles LiI
Therefore, 7.8 moles of lithium iodide were produced in the reaction.
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What is the volume of 0.78 mol of CO₂ gas at STP?
Answer: 17.49L
Explanation:
STP is 1atm and 273.15K
V=nRT/
V=(0.78)(0.0821)(273.15)/1
V= 17.49L
It is the compound that acts to fulfill the function of the said product.
It is the compound that acts to fulfill the function of the said product.
the statement is true.
What is a compound?A chemical compound is described as a chemical substance composed of many identical molecules containing atoms from more than one chemical A
A product may be made up of one or more compounds that work together to fulfill any desired function.
The key difference between a chemical compound and solution is that a compound contains two or more elements that are chemically bound together whereas a solution has few substances that do not chemically bound together as compounds do.
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26. Over time an open soft drink will lose carbonation (dissolved CO2
Which of these allows the CO2 to remain in solution the longest?
O Reduced air pressure
Exposure to direct sunlight
Increased air currents
O Cooler temperatures
Out of the options provided, cooler temperatures allow CO2 to remain in solution the longest.
When a soft drink is opened, CO2 molecules start to escape from the solution and accumulate in the headspace of the container. Higher temperatures increase the kinetic energy of the CO2 molecules, causing them to move faster and escape the solution more quickly. In contrast, cooler temperatures reduce the kinetic energy of the CO2 molecules, slowing down their movement and allowing them to remain in solution for a longer period of time.
Reduced air pressure, exposure to direct sunlight, and increased air currents can all further accelerate the loss of carbonation in an open soft drink. Reduced air pressure lowers the atmospheric pressure, which decreases the solubility of CO2 in the liquid. Exposure to direct sunlight increases the temperature of the drink and causes the CO2 molecules to escape more quickly. Increased air currents can also cause CO2 to escape more quickly by creating turbulence in the liquid.
Therefore, to keep a soft drink fizzy for longer, it is best to store it in a cool place and avoid exposing it to direct sunlight, reducing air pressure or increased air currents.
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2. What factors determine the rate at which a substance dissolves?
Answer:
Temperature
Agitation
Particle size
Explanation:
Use the drop-down menus to rank the boiling points of the following hydrocarbons. Use a "1" to indicate the compound with the lowest boiling point.
The boiling points of the hydrocarbons can be ranked as follows;
1. 4
2. 2
3. 3
4. 1
What controls the boiling points of the hydrocarbons?The size of the molecules and the nature of the intermolecular interactions between the molecules essentially determine the boiling points of hydrocarbons.
Because they have more electrons and a larger surface area available for intermolecular interactions like Van der Waals forces, larger hydrocarbon molecules typically have higher boiling points.
Additionally, polar hydrocarbons and those that can form hydrogen bonds have higher boiling points than non-polar hydrocarbons because of stronger intermolecular forces.
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