What is the slope of the lines 2,8 -6,-8

Answer:

4: 4[tex]\pi^2[/tex]

Step-by-step explanation:

2[tex]\pi[/tex] x 5 x [tex]x[/tex] = 10[tex]\pi x[/tex]

10[tex]\pi x[/tex] = 40[tex]\pi ^3}[/tex]

x = 4[tex]\pi^2[/tex]

Answer:

4π units

Step-by-step explanation:

v=lwh

40π^3=2π×5×h

40π^3=10π^2×h

h=40π^3/10π^2

h=4π units

mark brianliest if my answer suit your question please.

Answer:

D

Step-by-step explanation:

Line 1: Since these angles are vertical, they are congruent

Line 2: We have 2 sides and an angle in between them so it is SAS

This means the answer is D.

Answer: The correct answer is this set:

1.) Vertical Angles are congruent

2.) SAS Congruence Postulate

Answer:

  AB = 8

Step-by-step explanation:

Since C is the midpoint, ...

  AC = CB

  5x -6 = 2x

  3x = 6 . . . . . . . add 6-2x

  x = 2

Then the length of AB is ...

  AB = 2(CB) = 2(2x) = 4(2)

  AB = 8

Answer:

D. 1, 1/2, 1/4, 1/8, ...

Step-by-step explanation:

Only one of the listed is a geometric sequence:

Answer:

Step-by-step explanation:

If the profit realized by the company is modelled by the equation

P (x) = −0.5x² + 120x + 2000, marginal profit occurs at dP/dx = 0

dP/dx = -x+120

P'(x) = -x+120

Company's marginal profit at the $100,000 advertising level will be expressed as;

P '(100) = -100+120

P'(100) = 20

Marginal profit at the $100,000 advertising level is $20,000

Company's marginal profit at the $140,000 advertising level will be expressed as;

P '(140) = -140+120

P'(140) = -20

Marginal profit at the $140,000 advertising level is $-20,000

Based on the marginal profit at both advertising level, I will recommend the advertising expenditure when profit between $0 and $119 is made. At any marginal profit from $120 and above, it is not advisable for the company to advertise because they will fall into a negative marginal profit which is invariably a loss.

Answer:

[tex]-\dfrac{1}{26}[/tex]

Step-by-step explanation:

[tex]-\dfrac{12}{13}\div 24=\\\\-\dfrac{12}{13} \times \dfrac{1}{24}=\\\\-\dfrac{12}{13\times 24}=\\\\-\dfrac{1}{26}[/tex]

Hope this helps!

Answer:

2cm

Step-by-step explanation:

h=v/(l)w

h=24/(6)2

h=24/12

h=2cm or 2cm²

Answer:

(4,1)

Step-by-step explanation:

(1+7)/2 = 4

(9+(-7))/2 = 1

Answer:

[tex] 25.5 -3.3= 22.2[/tex]

[tex] 25.5 +3.3= 28.8[/tex]

And the confidence interval would be given by: [tex] 22.2\leq \mu \leq 28.8[/tex]

Step-by-step explanation:

[tex]\bar X=25.5[/tex] represent the sample mean for the sample  

ME= 3.3 represent the margin of error

Confidence interval

The confidence interval for the mean is given by the following formula:

[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex]   (1)

The margin of error is given by;

[tex] ME =t_{\alpha/2}\frac{s}{\sqrt{n}}= 3.3[/tex]

And the confidence interval would be given by:

[tex] 25.5 -3.3= 22.2[/tex]

[tex] 25.5 +3.3= 28.8[/tex]

And the confidence interval would be given by: [tex] 22.2\leq \mu \leq 28.8[/tex]

Answer:

[tex] \sqrt{17}\: units [/tex]

Step-by-step explanation:

[tex]d = \sqrt{ {(2 - 1)}^{2} + {(3 - 7)}^{2} } \\ \\ = \sqrt{ {(1)}^{2} + {( - 4)}^{2} } \\ \\ = \sqrt{ 1 + 16 } \\ \\ d= \sqrt{17} \\ [/tex]

Answer:

d=√17≈4.12310562561766

Step-by-step explanation:

Answer: short answer

Just checked it’s False

Hope this helps :))

Step-by-step explanation:

Answer:

B. False

Step-by-step explanation:

A P E X

Answer:

160 off 20p coins

Step-by-step explanation:

20 p coins= 640 - 640*(3/8+3/8)= 640*(1- 6/8)= 640 * 2/8= 640* 1/4= 160

Answer:

C

Step-by-step explanation:

Hope this helps

Answer:

C

Step-by-step explanation:

Wednesday hope this helps!

Answer:

0.3537 feet per minute.

Step-by-step explanation:

Gravel is being dumped from a conveyor belt at a rate of 10 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.

[tex]\dfrac{dV}{dt}=10$ ft^3/min[/tex]

[tex]\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h[/tex]

If the Base Diameter = Height of the Cone

The radius of the Cone = h/2

Therefore,

[tex]\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}[/tex]

[tex]\text{Rate of Change of the Volume}, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}[/tex]

Therefore: [tex]\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=10[/tex]

We want to determine how fast is the height of the pile is increasing when the pile is 6 feet high.

[tex]When h=6$ feet$\\\dfrac{3\pi *6^2}{12}\dfrac{dh}{dt}=10\\9\pi \dfrac{dh}{dt}=10\\ \dfrac{dh}{dt}= \dfrac{10}{9\pi}\\ \dfrac{dh}{dt}=0.3537$ feet per minute[/tex]

When the pile is 6 feet high, the height of the pile is increasing at a rate of 0.3537 feet per minute.

Answer:

Option c

Step-by-step explanation:

This is an experiment because the researcher wants to test efficiency of the magnetic bracelets in the elimination of motion sickness i.e. whether they experienced motion sickness even after wearing the magnetic bracelets.

Answer: The moving of decimal to the left is a shortcut to the operation of multiplying number by decimal numbers

Step-by-step explanation:

the power of 10 that is involved in converting the measurements of pete is -4, so he needs to multiply the measurement by 10^-4 to convert it.

Answer:

Sample Response: Because he moved the decimal 4 places to the left, Pete is dividing by 10 to the 4th power, or 10,000. Pete moved the decimal place 4 places to the left. Pete is dividing by 10 to the 4th power, or 10,000.

Step-by-step explanation:

it was on edg

                                                      hope it helps :b

Answer: The graph is:

Answer:

Solve for  

w

by simplifying both sides of the equation, then isolating the variable.

Exact Form:

w

=

49

2

Decimal Form:

w

=

24.5

Mixed Number Form:

w

=

24

Answer:

24

Step-by-step explanation:

Answer:

( $74.623, $83.777)

The 90% confidence interval is = ( $74.623, $83.777)

Critical value at 90% confidence = 1.645

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = $79.20

Standard deviation r = $10.41

Number of samples n = 14

Confidence interval = 90%

Using the z table;

The critical value that should be used in constructing the confidence interval.

z(α=0.05) = 1.645

Critical value at 90% confidence z = 1.645

Substituting the values we have;

$79.20+/-1.645($10.42/√14)

$79.20+/-1.645($2.782189528308)

$79.20+/-$4.576701774067

$79.20+/-$4.577

( $74.623, $83.777)

The 90% confidence interval is = ( $74.623, $83.777)

Answer:

y = 2cos5x-9/5sin5x

Step-by-step explanation:

Given the solution to the differential equation y'' + 25y = 0 to be

y = c1 cos(5x) + c2 sin(5x). In order to find the solution to the differential equation given the boundary conditions y(0) = 1, y'(π) = 9, we need to first get the constant c1 and c2 and substitute the values back into the original solution.

According to the boundary condition y(0) = 2, it means when x = 0, y = 2

On substituting;

2 = c1cos(5(0)) + c2sin(5(0))

2 = c1cos0+c2sin0

2 = c1 + 0

c1 = 2

Substituting the other boundary condition y'(π) = 9, to do that we need to first get the first differential of y(x) i.e y'(x). Given

y(x) = c1cos5x + c2sin5x

y'(x) = -5c1sin5x + 5c2cos5x

If y'(π) = 9, this means when x = π, y'(x) = 9

On substituting;

9 = -5c1sin5π + 5c2cos5π

9 = -5c1(0) + 5c2(-1)

9 = 0-5c2

-5c2 = 9

c2 = -9/5

Substituting c1 = 2 and c2 = -9/5 into the solution to the general differential equation

y = c1 cos(5x) + c2 sin(5x) will give

y = 2cos5x-9/5sin5x

The final expression gives the required solution to the differential equation.

Answer:

24 beads

Step-by-step explanation:

beads in 4 sheet=32

beads in 1 sheet=32/4=8

beads in 3 sheet=8*3=24

Answer:

Assuming that you can make the same number of beads with 1 sheet of paper, Tameka can make 24 beads with 3 sheets of paper.

Answer:

A:

Step-by-step explanation:

Using tangent-secant theorem

AE²=(EC)(ED)

12²=(8)(8+x+10)

144=8(x+18)

144=8x+144

8x = 144-144

8x = 0

So

x = 0

Now

ED = 8+x+10

ED = 8+0+10

ED = 18

the correct answer is 59.

Answer:

59

Step-by-step explanation:

Answer:

Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.  

How long will it take for this population to grow to a hundred rodents? To a thousand rodents?

Step-by-step explanation:

Use the initial condition when dp/dt = 1, p = 10 to get k;

[tex]\frac{dp}{dt} =kp^2\\\\1=k(10)^2\\\\k=\frac{1}{100}[/tex]

Seperate the differential equation and solve for the constant C.

[tex]\frac{dp}{p^2}=kdt\\\\-\frac{1}{p}=kt+C\\\\\frac{1}{p}=-kt+C\\\\p=-\frac{1}{kt+C} \\\\2=-\frac{1}{0+C}\\\\-\frac{1}{2}=C\\\\p(t)=-\frac{1}{\frac{t}{100}-\frac{1}{2} }\\\\p(t)=-\frac{1}{\frac{2t-100}{200} }\\\\-\frac{200}{2t-100}[/tex]

You have 100 rodents when:

[tex]100=-\frac{200}{2t-100} \\\\2t-100=-\frac{200}{100} \\\\2t=98\\\\t=49\ months[/tex]

You have 1000 rodents when:

[tex]1000=-\frac{200}{2t-100} \\\\2t-100=-\frac{200}{1000} \\\\2t=99.8\\\\t=49.9\ months[/tex]

Answer:

Step-by-step explanation:

Let s, b, a represent the numbers of servings of steak, baked eggs, and acorn squash, respectively. Then the equations we want to solve are ...

  40s +20b +4a = 64 . . . . grams of protein

  10s +2b +20a = 29 . . . . grams of carbohydrate

  1s +20b +32a = 72.5 . . . milligrams of vitamin A

There are any number of calculators or web sites that will solve this system of equations for you. The solution is ...

  s = 0.5

  b = 2

  a = 1

The dietitian should provide 1/2 serving of steak, 2 servings of baked eggs, and 1 serving of acorn squash.

Answer:

a) [tex]x(t) = 13*e^(^-^\frac{t}{100}^)[/tex]

b) 10.643 kg

Step-by-step explanation:

Solution:-

- We will first denote the amount of salt in the solution as x ( t ) at any time t.

- We are given that the Pure water enters the tank ( contains zero salt ).

- The volumetric rate of flow in and out of tank is V(flow) = 50 L / min  

- The rate of change of salt in the tank at time ( t ) can be expressed as a ODE considering the ( inflow ) and ( outflow ) of salt from the tank.

- The ODE is mathematically expressed as:

                            [tex]\frac{dx}{dt} =[/tex] ( salt flow in ) - ( salt flow out )

- Since the fresh water ( with zero salt ) flows in then ( salt flow in ) = 0

- The concentration of salt within the tank changes with time ( t ). The amount of salt in the tank at time ( t ) is denoted by x ( t ).

- The volume of water in the tank remains constant ( steady state conditions ). I.e 10 L volume leaves and 10 L is added at every second; hence, the total volume of solution in tank remains 5,000 L.

- So any time ( t ) the concentration of salt in the 5,000 L is:

                             [tex]conc = \frac{x(t)}{1000}\frac{kg}{L}[/tex]

- The amount of salt leaving the tank per unit time can be determined from:

                         salt flow-out = conc * V( flow-out )  

                         salt flow-out = [tex]\frac{x(t)}{5000}\frac{kg}{L}*\frac{50 L}{min}\\[/tex]

                         salt flow-out = [tex]\frac{x(t)}{100}\frac{kg}{min}[/tex]

- The ODE becomes:

                               [tex]\frac{dx}{dt} = 0 - \frac{x}{100}[/tex]

- Separate the variables and integrate both sides:

                       [tex]\int {\frac{1}{x} } \, dx = -\int\limits^t_0 {\frac{1}{100} } \, dt + c\\\\Ln( x ) = -\frac{t}{100} + c\\\\x = C*e^(^-^\frac{t}{100}^)[/tex]

- We were given the initial conditions for the amount of salt in tank at time t = 0 as x ( 0 ) = 13 kg. Use the initial conditions to evaluate the constant of integration:

                              [tex]13 = C*e^0 = C[/tex]

- The solution to the ODE becomes:

                           [tex]x(t) = 13*e^(^-^\frac{t}{100}^)[/tex]

- We will use the derived solution of the ODE to determine the amount amount of salt in the tank after t = 20 mins:

                           [tex]x(20) = 13*e^(^-^\frac{20}{100}^)\\\\x(20) = 13*e^(^-^\frac{1}{5}^)\\\\x(20) = 10.643 kg[/tex]

- The amount of salt left in the tank after t = 20 mins is x = 10.643 kg

Answer:

11 y 23

Step-by-step explanation:

Nombrando los números como [tex]x[/tex] y [tex]y[/tex],

Planteamos las siguientes ecuaciones:

[tex]xy=253[/tex] (el producto de los numeros es 253)

[tex]x=2y+1[/tex] (uno de los enteros debe ser uno más que el doble del otro).

Sustituimos la segunda ecuación en la primera:

[tex](2y+1)(y)=253[/tex]

resolvemos para encontrar y:

[tex]2y^2+y=253\\2y^2+y-253=0[/tex]

usando la formula general para resolver la ecuación cuadrática:

[tex]y=\frac{-b+-\sqrt{b^2-4ac} }{2a}[/tex]

donde

[tex]a=2,b=1,c=-253[/tex]

Sustituyendo los valores:

[tex]y=\frac{-1+-\sqrt{1-4(2)(-253)} }{2(2)} \\\\y=\frac{-1+-\sqrt{2025} }{4}\\ \\y=\frac{-1+-45}{4} \\[/tex]

usando el signo mas obtenemos que y es:

[tex]y=\frac{-1+45}{4} \\y=\frac{44}{4}\\ y=11[/tex]

(no usamos el signo menos, debido a que obtendriamos fracciones y buscamos numeros enteros)

con este valor de y, podemos encontrar x usando:

[tex]x=2y+1[/tex]

sustituimos [tex]y=11[/tex]

[tex]x=2(11)+1\\x=22+1\\x=23[/tex]

y comprobamos que el producto sea 253:

[tex]xy=253[/tex]

[tex](23)(11)=253[/tex]

Answer:

24

Step-by-step explanation:

That would be:

(3/8)(30)

---------------

(15/16)(1/2)

This can be reduced in various ways.  First, divide that 30 by 15, obtaining:

   6/8

-----------

   1/32

Now invert the divisor (1/32) and multiply:

(6/8)(32/1)

This reduces to 6*4, or 24.

Answer:

(a)[tex]\dfrac{11}{26}[/tex]

(b)[tex]\dfrac{9}{13}[/tex]

(c)[tex]\dfrac{4}{13}[/tex]

Step-by-step explanation:

Number of cards in a Standard Deck=52

(a)

Number of Diamonds (D)=13

Number of Face Cards(F) = 12

Number of Diamonds that are face cards = 3

[tex]Pr($that the card is a diamond or a face card)=P(D)+P(F)-P(D \cap F)\\=\dfrac{13}{52} +\dfrac{12}{52} -\dfrac{3}{52} \\=\dfrac{22}{52} \\=\dfrac{11}{26}[/tex]

(b)The probability that the card is neither an ace nor a heart.

Number of Aces (A)=4

Number of Hearts(H) = 13

Number of Hearts that are Aces = 1

[tex]Pr($that the card is a Ace or a Heart), P(A \cup H)=P(A)+P(H)-P(A \cap H)\\=\dfrac{4}{52} +\dfrac{13}{52} -\dfrac{1}{52} \\=\dfrac{16}{52} \\$Therefore, probability that the card is neither an ace nor a heart.\\=1-P(A \cup H)\\=1-\dfrac{16}{52}\\=\dfrac{36}{52}\\=\dfrac{9}{13}[/tex]

(c)The probability that the card is a face card or a 3

Number of 3 cards(T)=4

Number of Face Cards(F) = 12

[tex]Pr($that the card is a three or a face card)=P(T)+P(F)\\=\dfrac{4}{52} +\dfrac{12}{52} \\=\dfrac{16}{52} \\=\dfrac{4}{13}[/tex]

Answer:

x = 2

Step-by-step explanation:

Well the diagonals bisect each other.

4x = 8

x = 2

Answer:

x = 2

Step-by-step explanation:

5x = 3x+4

2x = 4

x = 2