What is the given function below in vertex form

What Is The Given Function Below In Vertex Form

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Answer 1
The answer is in this picture
What Is The Given Function Below In Vertex Form

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5. An archway has vertical sides 10 feet high. The top of an archway can



be modeled by the quadratic function f(x) = -0. 5x2 + 10 where x is the



horizontal distance, in feet, along the archway. How far apart are the



walls of the archway? Round your answer to the nearest tenth of a foot.



Original content Copyright © by Houghton Mifflin Harcourt. Additions and changes to the original content are the responsibility of the instructor.



293

Answers

The walls of the archway are approximately 8.9 apart.

Find out the distance between the walls of the archway?

To find the distance between the walls of the archway, we need to find the horizontal distance where the function f(x) intersects the x-axis. This is because the archway's walls are vertical, and their distance apart is the same as the horizontal distance between the points where the archway meets them.

To find the x-intercepts of the function f(x) = -0.5x^2 + 10, we need to set f(x) = 0 and solve for x:

0 = -0.5x^2 + 10

0.5x^2 = 10

x^2 = 20

x = ±√20

Since the archway is a physical object, we can discard the negative value for x, which means the archway meets the walls at x = √20 feet.

To find the distance between the walls of the archway, we can double this value:

2√20 ≈ 8.94

Then it's concluded that the walls of the archway are approximately 8.9 feet apart.

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solve the initial value problem. f '(x) = 5 x2 − x2 5 , f(1) = 0

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We can start by integrating both sides of the differential equation to obtain:

∫f '(x) dx = ∫([tex]5x^2 - x^2/5[/tex]) dx

f(x) = (5/3)[tex]x^3[/tex] - (1/15) [tex]x^5[/tex] + C

where C is the constant of integration.

To find the value of C, we can use the initial condition f(1) = 0:

f(1) = (5/3)[tex](1)^3[/tex] - (1/15) [tex](1)^5[/tex] + C = 0

Simplifying this equation gives:

C = (1/15) - (5/3)

C = -2/9

Therefore, the solution to the initial value problem f '(x) = 5[tex]x^2[/tex] − [tex]x^2[/tex]/5 , f(1) = 0 is:

f(x) = (5/3) [tex]x^3[/tex] - (1/15) [tex]x^5[/tex] - (2/9)

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Express tan H as a fraction in simplest terms.
F
H
28
7
G

Answers

Answer:

4 or [tex]\frac{4}{1}[/tex]

Step-by-step explanation:

To solve this we need to remember SOH-CAH-TOA. With SOH being Sine, CAH being Cosine, and TOA being Tangent. In the last term (TOA), the O means opposite and the A is adjacent. This means the segment opposite of angle H you have to divide that by the segment adjacent to H.

In this case, the opposite is 28 and the adjacent is 7. So we have to do [tex]\frac{28}{7}[/tex]. This is tan(H). Now we have to simplify this. Now we get our tangent of H to be [tex]\frac{4}{1}[/tex] or 4. So 4/1 or 4 is our answer

SOMEONE HELP PLS, giving brainlist to anyone who answers!!!

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Answer: $532,000

Step-by-step explanation:

If the company is making $140,000 and they get 20% each year, we just multiply it by 20%, or 0.20, and get $28,000. So, we would multiply that by 14, the years the company operated, and then add it to the original $140,000.

28,000 x 14 = 392,000

392,000 + 140,000 = 532,000

So, over the course of 14 years, the company made a profit of $532,000.

A baker uses 2 lbs of butter to make 7


dozen cookies. How many pounds of


butter would be used to make 132


cookies?

Answers

Approximately 37.71 lbs of butter would be used to make 132 cookies.

we can use a proportion:

[tex]2 lbs of butter / 7 dozen cookies = x lbs of butter / 132 cookies\\[/tex]

To find x, we can cross-multiply and solve for x:

[tex]2 lbs of butter * 132 cookies = 7 dozen cookies * x lbs of butter264 lbs of cookies = 7xx = 264 / 7x = 37.71[/tex]

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This stop sign is a regular octagon. The length of one side is 8 inches and the length of the apothem is 9.65 inches. Find the area of the stop sign.

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The area of the stop sign, given the length of one side and the apothem, would be 308. 8 square inches.

How to find the area ?

To find the area of a regular octagon, we can use the formula:

Area = ( Perimeter × Apothem ) / 2

Initially, we must determine the perimeter of the octagon. Since it is a regular octagon all sides have an identical length. There are 8 sides with length equal to 8 inches; therefore the perimeter is:

= 8 x 8

= 64 inches

The area is;

Area = ( Perimeter × Apothem ) / 2

Area = ( 64 inches × 9.65 inches ) / 2

Area = 617. 6 square inches / 2

Area = 308.8 square inches

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Read and imagine what is happening in this problem. Hannah mixed 6. 83 lb of pretzels with 3. 57 lb of popcorn. After filling up 6 bags that were the same size with the mixture, she had 0. 35 lb left.

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Hannah mixed 6.83 lb of pretzels with 3.57 lb of popcorn to make 10.4 lb of mixture. She then filled up 6 bags with an average of 1.68 lb of mixture per bag, leaving her with 0.35 lb of mixture left over.

In this problem, Hannah mixed 6.83 lb of pretzels with 3.57 lb of popcorn. This means that she had a total of 10.4 lb of mixture. She then filled up 6 bags that were the same size with the mixture, which means that each bag had approximately 1.73 lb of mixture (10.4 lb / 6 bags).

After filling up all 6 bags, Hannah had 0.35 lb of the mixture left over. This means that she used a total of 10.05 lb of mixture for the bags (10.4 lb - 0.35 lb).

To find out how much mixture was used per bag, we can divide the total amount of mixture used (10.05 lb) by the number of bags (6). This gives us an average of approximately 1.68 lb per bag.

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Height of 10th grade boys is normally distributed with a mean of 63. 5 in. And a standard deviation of 2. 9 in. The area greater than the z-score is the probability that a randomly selected 14-year old boy exceeds 70 in. What is the probability that a randomly selected 10th grade boy exceeds 70 in. ?Use your standard normal table.




Heights for 16-year-old boys are normally distributed with a mean of 68. 3 in. And a standard deviation of 2. 9 in. Find the z-score associated with the 96th percentile. Find the height of a 16-year-old boy in the 96th percentile. State your answer to the nearest inch

Answers

The probability that a randomly selected 10th grade boy exceeds 70 in is approximately 0.0127 or 1.27%.

The height of a 16-year-old boy in the 96th percentile is approximately 73 inches.

For the first question, we need to find the z-score for a height of 70 inches using the formula:

z = (x - μ) / σ

where x is the height of 70 inches, μ is the mean of 63.5 inches, and σ is the standard deviation of 2.9 inches.

z = (70 - 63.5) / 2.9 = 2.241

Using a standard normal table, we can find the area to the right of this z-score, which represents the probability that a randomly selected 10th grade boy exceeds 70 inches. The area to the right of 2.24 is 0.0127. Therefore, the probability is approximately 0.0127 or 1.27%.

For the second question, we need to find the z-score associated with the 96th percentile using a standard normal table. The 96th percentile is the point below which 96% of the data falls and above which 4% of the data falls. This corresponds to a z-score of approximately 1.75.

To find the height of a 16-year-old boy in the 96th percentile, we can use the formula:

x = μ + z * σ

where x is the height we want to find, μ is the mean of 68.3 inches, σ is the standard deviation of 2.9 inches, and z is the z-score we just found.

x = 68.3 + 1.75 * 2.9 = 73.28

Therefore, the height of a 16-year-old boy in the 96th percentile is approximately 73 inches.

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4. The cost of purchasing songs from a particular online service can be found by using the following equation: c= 1. 390 + 3. 50 Where c represents the total cost and d represents the number of songs downloaded. If Josh spent a total of $20. 18, how many songs did he download? A 12 B 6 C 11 D 7​

Answers

Josh downloaded 6 songs, which corresponds to option B.

The given equation is:

c = 1.390 + 3.50d

Where c represents the total cost and d represents the number of songs downloaded. You mentioned that Josh spent a total of $20.18. So, we'll set c to 20.18 and solve for d:

20.18 = 1.390 + 3.50d

Step 1: Subtract 1.390 from both sides of the equation:
20.18 - 1.390 = 3.50d
18.79 = 3.50d

Step 2: Divide both sides of the equation by 3.50:
18.79 / 3.50 = d
5.36857 = d

Since d must be a whole number (as you can't download a fraction of a song), we round it down to the nearest whole number:

d = 5

However, 5 is not among the given options. This indicates there may be a typo in the question. If the correct equation is:

c = 0.390 + 3.50d

Then, solving for d with the given total cost of $20.18:

20.18 = 0.390 + 3.50d

Step 1: Subtract 0.390 from both sides:
20.18 - 0.390 = 3.50d
19.79 = 3.50d

Step 2: Divide both sides by 3.50:
19.79 / 3.50 = d
5.65429 = d

Rounding to the nearest whole number:

d = 6

Thus, Josh downloaded 6 songs, which corresponds to option B.

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Kevin can clean a large aquarium tank in about 7 hours. When Kevin and Lara work together, they can


clean the tank in 3 hours. Enter and solve a rational equation to determine how long, to the nearest tenth


of an hour, it would take Lara to clean the tank if she works by herself? Complete the explanation as to


whether the answer is reasonable.


It would take Lara about 7hours to clean the tank by herself. The answer is reasonable because it


is (select) and, when substituted back into the equation, the equation is true.

Answers

The answer is reasonable because it is positive and also the equation is true . it would take Lara about 5.3 hours to clean the tank by herself.

Let's denote the time it takes for Lara to clean the tank alone as "L". We can use the formula for the combined work rate of two people, which is:

(1/7) + (1/L) = (1/3)

Multiplying both sides by the least common denominator, 21L, gives:

3L + 21 = 7L

Subtracting 3L from both sides, we get:

21 = 4L

Dividing both sides by 4, we get:

L = 5.25 hours (to the nearest tenth)

The answer is reasonable because it is positive, and it is also less than 7 hours, which is Kevin's time. When substituted back into the original equation, we get:

(1/7) + (1/5.25) = (1/3)

0.1429 + 0.1905 = 0.3333

0.3334 ≈ 0.3333

The equation is true, so the answer is reasonable. Therefore, it would take Lara about 5.3 hours to clean.

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A function f(x) = 3x^² dominates g(x) = x^2. O True O False

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The given statement "A function f(x) = 3x² dominates g(x) = x²" is True as it grows faster than the other function.

To show that f(x) dominates g(x), we need to prove that there exists a constant c such that f(x) > c * g(x) for all x > 0.

Let's consider c = 3. Then, for all x > 0, we have:

[tex]f(x) = 3x^2 > 3x^2/1 = 3x^2 * 1 > x^2 * 3 = g(x) * 3[/tex]

A function dominates another function when it grows faster than the other function. In this case, f(x) = 3x² and g(x) = x². Since f(x) has a higher coefficient (3) than g(x) (1) for the x² term, it grows faster than g(x) as x increases.

Therefore, we have shown that f(x) > 3g(x) for all x > 0, which means that f(x) dominates g(x).

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Determine the missing length in each right triangle using the Pythagorean theorem. Round the answer to the nearest tenth, if necessary

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The evaluated missing length in right triangle by using the Pythagorean theorem is  9 yards under the condition given the triangle is a right triangle.

The Pythagoras theorem projects that in a right triangle, the square of the hypotenuse is equal to the sum of the square of the other two sides,
It is given to us that in a right triangle,
Hypotenuse = 15 yd
Perpendicular = 12 yd

Therefore, applying Pythagoras theorem;
Base² = 15² - 12²

Base² = 225 - 144

Base² = 81

Base = √81

Base = 9 yards

Hence, The missing length present in the right triangle by applying the Pythagorean theorem is,
9 yards

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The complete question is

Determine the missing length in each right triangle using the Pythagorean theorem. Round the answer to the nearest tenth, if necessary


2. Assume that a cell is a sphere with radius 10 or 0. 001 centimeter, and that a cell's density is 1. 1 grams per cubic centimeter. A. Koalas weigh 6 kilograms on average. How many cells are in the average koala?​

Answers

The number of cells found in an average Koala is 1.30 x 10¹², under the condition that a cell is a sphere with radius 10 or 0. 001 centimeter.

Then the volume of a sphere with radius 10 cm is considered to be 4/3π(10)³ cubic cm that is approximately 4,188.79 cubic cm.
The evaluated volume of a sphere with radius 0.001 cm is 4/3π(0.001)³ cubic cm that is approximately 0.00000419 cubic cm.

Then the evaluated mass of a single cell is  found by applying the formula
mass = density x volume
In case of larger cell, the mass will be
mass = 1.1 g/cm³ x 4,188.79 cubic cm
= 4,607.67 grams

In case of  smaller cell, the mass will be

mass = 1.1 g/cm³ x 0.00000419 cubic cm
= 0.00000461 grams

As koalas measure an average of 6 kilograms or 6,000 grams², we can evaluate the number of cells in an average koala using division of the weight of the koala by the mass of a single cell

In case of larger cells
number of cells = weight of koala / mass of single cell
number of cells = 6,000 grams / 4,607.67 grams
≈ 1.30 x 10⁶ cells

For smaller cells:
number of cells = weight of koala / mass of single cell
number of cells = 6,000 grams / 0.00000461 grams

≈ 1.30 x 10¹² cells
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PLEASE HELP ME THIS IS AN COMPOSITE FIGURES

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The area of the shaded region is 5 sq units and the percentage of the shaded region is 83.33%

Calculating the area of the shaded region

The area of the shaded region is the difference between the area of the rectangle and the area of the clear region

Assuming the following dimensions

Rectangle = 3 by 2Triangles (unshaded) = 1 by 1

So, we have

Shaded = 3 * 2 - 2 * 1/2 * 1 * 1

Evaluate

Shaded = 5

The percentage of the shaded region

This is calculated as

Percentage = Shaded/Rectangle

So, we have

Percentage = 5/(3 * 2)

Evaluate

Percentage = 83.33%

Hence, the percentage of the shaded region is 83.33%

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Rate of Change of Production Costs The daily total cost C(x) incurred by Trappee and Sons for producing x cases of TexaPep hot sauce is given by the following function. C(x) = 0.000002x^3 + 4x + 300 Calculate the following for h = 1, 0.1, 0.01, 0.001, and 0.0001. (Round your answers to four decimal places.)
C(100+h) – C(100)/h

Answers

The instantaneous rate of change of cost with respect to x when x = 100 is 4.

We can begin by calculating C(100+h) and C(100):

C(100+h) = 0.000002(100+h)^3 + 4(100+h) + 300

C(100+h) = 0.000002(1,000,000 + 300h^2 + 30h^2 + h^3) + 400 + 4h + 300

C(100+h) = 0.000002h^3 + 0.0006h^2 + 4h + 700

C(100) = 0.000002(100)^3 + 4(100) + 300

C(100) = 2 + 400 + 300

C(100) = 702

Therefore,

C(100+h) - C(100) = (0.000002h^3 + 0.0006h^2 + 4h + 700) - 702

C(100+h) - C(100) = 0.000002h^3 + 0.0006h^2 + 4h - 2

Now, we can find the rate of change of cost with respect to x by dividing this expression by h and taking the limit as h approaches 0:

(C(100+h) - C(100))/h = (0.000002h^3 + 0.0006h^2 + 4h - 2)/h

(C(100+h) - C(100))/h = 0.000002h^2 + 0.0006h + 4 - (2/h)

As h approaches 0, the term 2/h approaches infinity, which means the rate of change of cost with respect to x is undefined. However, we can calculate the limit of the expression as h approaches 0 from the left and from the right to see if it has a finite value:

limit (h->0+) ((C(100+h) - C(100))/h) = 4

limit (h->0-) ((C(100+h) - C(100))/h) = 4

Since the left and right limits are equal, the overall limit exists and equals 4. Therefore, the instantaneous rate of change of cost with respect to x when x = 100 is 4.

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If P (6, 1), find the image
of P under the following rotation.
180° counterclockwise about the
origin
([?],
Enter the number that belongs in
the green box,

Answers

The image of point P (6, 1) under a 180° counterclockwise rotation about the origin is (-6, -1).

To find the image of point P (6, 1) under a 180° counterclockwise rotation about the origin, we can use the rotation formula for 2D coordinates.

The formula for rotating a point (x, y) counterclockwise by θ degrees about the origin is:

x' = x [tex]\times[/tex] cos(θ) - y [tex]\times[/tex] sin(θ)

y' = x [tex]\times[/tex] sin(θ) + y [tex]\times[/tex] cos(θ)

In this case, θ is 180°.

So, let's substitute the values of x and y from point P into the rotation formula:

x' = 6 [tex]\times[/tex] cos(180°) - 1 [tex]\times[/tex] sin(180°)

y' = 6 [tex]\times[/tex] sin(180°) + 1 [tex]\times[/tex] cos(180°)

Now, let's simplify these equations using the trigonometric values for 180°:

[tex]x' = 6 \times (-1) - 1 \times 0[/tex]

[tex]y' = 6 \times 0 + 1 \times (-1)[/tex]

Simplifying further:

x' = -6

y' = -1

Therefore, the image of point P (6, 1) under a 180° counterclockwise rotation about the origin is (-6, -1).

Please note that the rotation formula assumes angles are measured in radians.

However, for simplicity, we used degrees in this explanation.

The trigonometric functions (cos and sin) can be evaluated in radians using their corresponding values for 180°.

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Shawn wrote down the activities for his day on Saturday. In which situation will his activity result in a final value of zero?
1 point
A. Shawn places four quarters in a jar of quarters which contains four quarters.
B. In the morning, Shawn added six hard candies to a jar which contained four hard candies. By the end of the day he ate ten candies from this jar.
C. Shawn starts out on the ground and then climbs ten feet on a ladder.
D. Shawn travels east ten feet and then travels south ten feet

Answers

The situation in which Shawn's activity will result in a final value of zero is Shawn travels east ten feet and then travels south ten feet. The correct option is D.

This is because when Shawn travels east ten feet, he moves horizontally to the right of his starting point. When he travels south ten feet after that, he moves vertically downwards from his previous position, cancelling out the horizontal movement he made earlier.

The displacement caused by Shawn's movement in the east direction is equal in magnitude but opposite in direction to the displacement caused by his movement in the south direction.

The net displacement of Shawn's movement is zero, and he ends up back at his starting point. Options A, B, and C do not involve any movements that result in a net displacement of zero.

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A velociraptor runs 5m [E] , 10 m [W], 3m [S], & 2m [W] in 10 seconds. Calculate speed & velocity

Answers

The velocity of the velociraptor is 0.4 m/s [E] - 0.8 m/s [W] + 0.3 m/s [S] and  the speed of the velociraptor is 2 m/s.

To calculate the speed of the velociraptor, we need to divide the total distance traveled by the total time taken:

Total distance = 5m + 10m + 3m + 2m = 20m

Total time = 10 seconds

Speed = Total distance / Total time

     = 20m / 10s

     = 2m/s

To calculate the velocity of the velociraptor, we need to consider both the magnitude of its speed and its direction. We can calculate the displacement by subtracting the final position from the initial position:

Displacement = (5m [E] + 10m [W] + 3m [S] + 2m [W])

           = (5m [E] - 8m [W] + 3m [S])

           = 5m [E] - 8m [W] + 3m [S]

Note that we have used negative sign for the distance traveled towards the west.

The time taken is 10 seconds.

Velocity = Displacement / Time taken

        = (5m [E] - 8m [W] + 3m [S]) / 10s

        = 0.4 m/s [E] - 0.8 m/s [W] + 0.3 m/s [S]

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question subtract. write your answer as a fraction in simplest form. 19−(−29)=

Answers

The result of 19 minus a negative 29 is 48. Expressed as a fraction in simplest form, this would be 48/1.

To find the difference between 19 and negative 29, we can use the rule that subtracting a negative number is the same as adding its absolute value. So, 19 - (-29) is the same as 19 + 29, which equals 48.

To write this as a fraction in simplest form, we simply put 48 over 1, since any integer can be expressed as a fraction with a denominator of 1. We don't need to simplify any further, so our final answer is 48/1.

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Suppose you want to represent a triangle with sides of 12 feet, 15 feet, and 18 feet on a drawing where 1 Inch - 3 feet How long should the sides of the triangle be in inches? 12 feet should be inches. 15 feet should be 18 feet should be inches.​

Answers

In linear equation, The sides of the triangle on the drawing should be 6 inches, 8 inches, and 9 inches.

What in mathematics is a linear equation?

An algebraic equation B. y=mx+b (where m is the slope and b is the y-intercept) containing simple constants and first-order (linear) components, such as the following, is called a linear equation.

                           The above is sometimes called a "linear equation in two variables" where x and y are variables. Equations in which the variable is power 1 are called linear equations. axe+b = 0 is a one-variable example where a and b are real numbers and x is a variable. 

A triangle with sides 12 feet, 16 feet, and 18 feet on a drawing where 1 inch = 2 feet.

Then, 1 feet of original triangle = 1/2 inch on drawing.

Now, the sides of the triangle on the drawing are

12 feet = 1/2 * 12 = 6 in

12 feet = 1/2 * 16 = 8 in

12 feet = 1/2 * 18 = 9 in

Hence, the sides of the triangle on the drawing should be 6 inches, 8 inches, and 9 inches..

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Can you find continuous function & so that when an = f(n) we have SIGMA an = ∫ f(x)dx

Answers

[tex]SIGMA an = 1 + 2 + 3 + ... + n = n(n+1)/2 = ∫_1^n f(x)dx = ∫ f(x)dx[/tex]

f(x) = x is indeed a continuous function that satisfies the given condition.

Yes, we can find a continuous function f(x) such that when an = f(n), we have SIGMA an = ∫ f(x)dx.

One such function is f(x) = x.

To see why this works, let's consider a few terms of the series SIGMA an.

When n = 1, we have a1 = f(1) = 1, so the series starts with 1.

When n = 2, we have a2 = f(2) = 2, so the series becomes 1 + 2. When n = 3, we have a3 = f(3) = 3, so the series

becomes 1 + 2 + 3. And so on.

Notice that this series is just the sum of the first n positive integers, which we know is equal to n(n+1)/2.

But if we take the derivative of f(x) = x, we get f'(x) = 1, which means that the integral of f(x) from 1 to n is just n.

So we have:

[tex]∫ f(x)dx = ∫ xdx = 1/2 x^2 + C[/tex]

[tex]∫_1^n f(x)dx = (1/2 n^2 + C) - (1/2 (1)^2 + C) = 1/2 n^2 - 1/2[/tex]

And therefore:

[tex]SIGMA an = 1 + 2 + 3 + ... + n = n(n+1)/2 = ∫_1^n f(x)dx = ∫ f(x)dx[/tex]

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Mara putting together pieces of string for an art project. She has a piece of string that is 30 inches, a piece that is 22 inches, and a piece that is 20 inches. Once she puts together the pieces, what will be the total length in feet?



Step 1 - What will be the total length of the string in inches?





Step 2 - How many feet is this equal to? (Inches -> Feet)





2. A water jug holds 300 ounces of water. The football team has 2 water jugs. How many cups of water will both water jugs hold altogether?



Step 1 - How many ounces do both water jugs hold?




Step 2 - How many cups is this equal to? (Ounces -> Cups



Please help me if you help me and explain all the answer I will give you brainiest!!!

Answers

The total length of the string in feet is 6 feet, and the combined capacity of both water jugs in cups is 75 cups.

What is the total length of the string, and how many cups of water can the two water jugs hold altogether?

Step 1: To find the total length of the string in inches, Mara needs to add the lengths of the three pieces of string:

30 inches + 22 inches + 20 inches = 72 inches

So the total length of the string in inches is 72 inches.

Step 2: To convert inches to feet, we need to divide the number of inches by 12 (since there are 12 inches in a foot):

72 inches ÷ 12 = 6 feet

Therefore, once Mara puts together the three pieces of string, the total length will be 6 feet.

Step 1: To find out how many ounces of water both water jugs hold altogether, we need to add the capacity of the two jugs:

300 ounces + 300 ounces = 600 ounces

So both water jugs together can hold 600 ounces of water.

Step 2: To convert ounces to cups, we need to divide the number of ounces by 8 (since there are 8 ounces in a cup):

600 ounces ÷ 8 = 75 cups

Therefore, both water jugs together can hold 75 cups of water.

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Question 2(Multiple Choice Worth 4 points) (05.03 MC) Solve the system of equations using elimination. 2x + 3y = -8 3x+y=2 O(-4,0) (2,-4) (5.-6) (8-8)​

Answers

Answer:

(2,-4)

Step-by-step explanation:

In order to solve by elimination, coefficients of one of the variables must be the same in both equations so that the variable will cancel out when one equation is subtracted from the other.

2x+3y=−8,3x+y=2

To make 2x and 3x equal, multiply all terms on each side of the first equation by 3 and all terms on each side of the second by 2. Then simplify

6x+9y=−24,6x+2y=4

Add 6x to −6x. Terms 6x and −6x cancel out, leaving an equation with only one variable that can be solved, add 9y to −2y, add −24 to −4, and divide both sides by 7.

y=−4

Substitute −4 for y in 3x+y=2. Because the resulting equation contains only one variable, you can solve for x directly. Add 4 to both sides of the equation and divide both sides by 3.

x=2

the length of a shadow of building is 12m. The distance from the top of the building to the tip of shadow is 20m. Find the height of the building. if necessary, round your answer to the nearest tenth.​

Answers

The height of the building is 16 meters.

What is right triangle?

A right triangle is a type of triangle that has one of its angles measuring 90 degrees (π/2 radians). The side which is opposite to the right angle is the hypotenuse, while the other two sides are called the legs.

We can solve this problem using the Pythagorean theorem, which relates the sides of a right triangle. Let h be the height of the building. Then we can draw a right triangle with one leg of length h and the other leg of length 12m, representing the height and length of the shadow, respectively. The hypotenuse of this triangle is the distance from the top of the building to the tip of the shadow, which is 20m. So we have:

h² + 12² = 20²

Simplifying and solving for h, we get:

h² = 20² - 12²

h² = 256

h = sqrt(256)

h = 16

Therefore, the height of the building is 16 meters.

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Intelligence Quotient (IQ) scores are often reported to be normally distributed with μ=100. 0 and σ=15. 0. A random sample of 45 people is taken. Step 1 of 2 : What is the probability of a random person on the street having an IQ score of less than 96? Round your answer to 4 decimal places, if necessary

Answers

We are given that IQ scores are normally distributed with mean μ = 100 and standard deviation σ = 15. We want to find the probability of a random person on the street having an IQ score of less than 96.

To do this, we need to standardize the IQ score using the z-score formula:

z = (x - μ) / σ

where x is the IQ score we're interested in, μ is the mean IQ score, and σ is the standard deviation of IQ scores.

Plugging in the given values, we get:

z = (96 - 100) / 15 = -0.267

Now, we look up the probability of getting a z-score less than -0.267 in a standard normal distribution table or using a calculator. The probability is approximately 0.3944.

Therefore, the probability of a random person on the street having an IQ score of less than 96 is 0.3944 (rounded to 4 decimal places).

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HELP ON MATH ASAPPP I NEED TO PASS

Answers

I think it might be C

Molly's cafe has regular coffee and decaffeinated coffee. this morning, the cafe served 30 coffees in all, 40% of which were regular. how many regular coffees did the cafe serve?

Answers

The cafe served 12 regular coffees.

Out of the 30 coffees served at Molly's cafe this morning, 40% were regular coffee. To determine the number of regular coffees, we can calculate 40% of 30.

To find the value,

Step 1: Convert the percentage to a decimal by dividing it by 100. So, 40% = 40/100 = 0.4.
Step 2: Multiply the total number of coffees served by the decimal. So, 30 * 0.4 = 12.

Hence, the cafe served 12 regular coffees. The remaining 60% (or 18 coffees) would be decaffeinated. It is important to note that percentages represent proportions or fractions of a whole. In this case, 40% indicates that 40 out of 100 parts (or 40/100) are regular coffees. By applying this proportion to the total number of coffees served (30), we can determine the specific quantity. This method can be used in various scenarios involving percentages to find a portion of a whole. Therefore, Molly's cafe served 12 regular coffees and 18 decaffeinated coffees, making a total of 30 coffees.


Your answer: Molly's cafe served 12 regular coffees this morning.

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In ΔHIJ, j = 72 cm, i = 70 cm and ∠I=72°. Find all possible values of ∠J, to the nearest degree.

Answers

The possible value of <J is 78 degrees

How to determine the value

It is important to note that the different trigonometric identities are;

sinecosinetangentcotangentsecantcosecant

Also, the law of sines in a triangle is expressed as;

sin A/a = sin B/b = sin C/c

Given that the angles are in capitals and the sides are in small letters.

From the information given, we have that;

sinI/i = sin J/j

Substitute the values, we get;

sin 72 /70 = sin J/72

cross multiply the values, we have;

sin J = 68. 476/70

divide the values

sin J = 0. 9782

Find the inverse of sin

<J = 78 degrees

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There is a line through the origin that divides the region bounded by the parabola y = 2x − 7 x^2 and the x-axis into two regions with equal area. What is the slope of that line?

Answers

The slope of the line that divides the region into two equal parts is 8/7.

How to find the slope of that line?

We begin by finding the x-coordinates of the points where the parabola intersects the x-axis. Setting y = 0, we get:

[tex]2x - 7x^2 = 0[/tex]

x(2 − 7x) = 0

x = 0 or x = 2/7

Thus, the parabola intersects the x-axis at x = 0 and x = 2/7.

We want to find the slope of the line through the origin that divides the region bounded by the parabola and the x-axis into two regions with equal area.

Let's call this slope m.

We know that the area under the parabola from x = 0 to x = 2/7 is:

A = ∫[0,2/7] (2x − 7[tex]x^2[/tex]) dx

A = [[tex]x^2[/tex] − (7/3)[tex]x^3[/tex]] from 0 to 2/7

A = (4/21)

Since we want the line to divide this area into two equal parts, the area to the left of the line must be (2/21).

Let's call the x-intercept of the line h. Then the equation of the line is y = mx, and the area to the left of the line is:

(1/2)h(mx) = (1/2)mhx

We want this to be equal to (2/21), so we can solve for h:

(1/2)mhx = (2/21)

h = (4/21m)

The x-coordinate of the point of intersection of the line and the parabola is given by:

2x − 7[tex]x^2[/tex] = mx

Simplifying, we get:

[tex]7x^2 - (2 + m)x = 0[/tex]

Using the quadratic formula, we get:

[tex]x = [(2 + m) \pm \sqrt((2 + m)^2 - 4(7)(0))]/(2(7))[/tex]

x = [(2 + m) ± √(4 + 4m + [tex]m^2[/tex])]/14

x = [(2 + m) ± (2 + m)]/14

x = 1/7 or x = −(2/7)

Since we want the line to pass through the origin, we must choose x = 1/7, and we can solve for m:

[tex]2(1/7) - 7(1/7)^2 = m(1/7)[/tex]

m = 8/7

Therefore, the slope of the line that divides the region into two equal parts is 8/7.

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Jamie jogged x km. Anabel jogged 1/4 less than Jamie. Choose the equation that best represents the situation. A

y = 3/4x

b

x = 4/3y

c

y = 1/4x

d

x = 1/4y

Answers

The equation that best represents the situation is y = 3/4x. The correct answer is A.

The given problem involves two people, Jamie and Anabel, who jogged a certain distance. Let's say Jamie jogged x km. Anabel jogged 1/4 less than Jamie, which means she jogged 3/4 of x km (since 1 - 1/4 = 3/4).

To represent this situation in an equation, we need to find the relationship between the distance jogged by Jamie and the distance jogged by Anabel. Since Anabel jogged 3/4 of the distance jogged by Jamie, we can write:

distance jogged by Anabel = 3/4(distance jogged by Jamie)

Using the given variable x for the distance jogged by Jamie, we can rewrite the equation as:

distance jogged by Anabel = 3/4x

And since the question is asking for an equation that best represents the situation, the correct answer is:

Cy = 3/4x

Therefore, Cy = 3/4x is the equation that best represents the situation where Jamie jogged x km and Anabel jogged 1/4 less than Jamie. The correct answer is A.

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