The value of amount of R4 670,00 is due to be paid back after 1.47 years.
We have to given that;
A discounted loan of R4 670,00 at a simple discount rate of 14% per year is offered to Mr. Mothapo.
And, The actual amount of money that Mr. Mothapo receives is R3 852,75.
Now, Let n be the loan period.
Hence, We get;
4670,00 = 385275 (1 + 0.14)ⁿ
1.212121 = (1.14)ⁿ
n log 1.14 = log 1.2121
n = 1.47
Thus, The value of amount of R4 670,00 is due to be paid back after 1.47 years.
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40
Selena is training for a race. Last week, she ran 4 miles each day on 3 different
days. Use the symbol X to make an array that represents the total number of miles
Selena ran last week.
Show your work.
The array that represents the total number of miles is X = 12
Given that;
Selena ran 4 miles per day
And she ran for 3 different days
Let the total miles she ran = X
therefore
X = miles of 1st day + miles of 2nd day + miles of 3rd day
⇒ X = 4 + 4 + 4
⇒ X = 12 miles
Thus the symbolic form of miles Selena ran is,
X = 12.
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Please help !!!!!
!!!!!
Answer: 10w + 3 + 4.5w = 90
Step-by-step explanation:
a right angle is 90 degrees, so 10w + 3 and 4.5w have to add up to 90 degrees
(1/2 + 1/3) + [1/4 + (2/3)] ÷ 2/5 -4 x 5/6 ÷ 3/7
Answer:
Step-by-step explanation:
first, take 1/2+1/3 + 1/4+2/3
1/2+1/3=5/6 , 1/4+2/3=11/12
5/6+11/12=22/12
2/5-4=-18/5
-18/5*5/6=-3
22/12/3=22*3/12
=11/2
11/2/3/7=11/2*7/3
=77/6=12.8
Can someone please help me with this
Answer:
cot(65 deg)
Step-by-step explanation:
cot(x) is the complimentary func. of tan(x) with the relation:
tan x = cot (90 - x) and
cot x = tan (90 - x)
A sidewall of a building is shown below. Apply a formula to find the area of the wall.
Answer:1020 ft (squared)
Step-by-step explanation:
Base width 1 (28 ft) x Base width 2 (40 ft) x height (6 ft) = 1020 ft (squared)
A researcher is analyzing bacteria on a door handle after cleaning it with antibacterial disinfectant. Initially there were 15 bacteria, but the researcher noticed that the number of bacteria quadruples every hour,t. Write a function B(t) to represent the number of bacteria t hours after the initial measurement. Write a exponential function
The exponential function representing the number of bacteria t hours after the initial measurement is B(t) = 15 (4[tex])^t[/tex].
The function B(t) can be represented by an exponential function of the form:
B(t) = a[tex]b^t[/tex]
where 'a' is the initial number of bacteria and 'b' is the growth factor or rate at which the number of bacteria quadruples.
Given that the initial number of bacteria is 15 and the number of bacteria quadruples every hour, we can express 'b' as:
b = 4¹ = 4
Substituting the values of 'a' and 'b' in the general form of exponential function, we get:
B(t) = 15 (4[tex])^t[/tex]
Therefore, the exponential function representing the number of bacteria t hours after the initial measurement is B(t) = 15 (4[tex])^t[/tex].
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On January 10, 2022, Cullumber Co. sold merchandise on account to Robertsen Co. for $16,600, n/30. On February 9, Robertsen Co. gave Cullumber Co. a 11% promissory note in settlement of this account.
The preparation of the journal entry to record the sale and the settlement of the account receivable is as follows:
Journal Entry:January 10, 2022:
Debit Accounts Receivable $16,600
Credit Sales Revenue $16,600
(To record the sale of merchandise on account to Robertsen Co, n/30.)
February 9, 2022:
Debit Notes Receivable $16,600
Credit Accounts Receivable $16,600
(To record the receipt of a 11% promissory note in settlement of account receivable.)
What are journal entries?Journal entries refer to the initial records maintained about business transactions.
Journal entries show how the transactions will be posted in the general ledger.
Transaction Analysis:January 10, 2022: Accounts Receivable $16,600 Sales Revenue $16,600
Terms n/30
February 9, 2022: Notes Receivable $16,600 Accounts Receivable $16,600
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Question Completion:Prepare the journal entry to record the sale and the settlement of the account receivable.
What is the relation between the variables in the equation
The equation x⁴/y = 7 represents a relationship of direct proportionality between x and y, where x⁴ and y are inversely proportional to each other.
The equation x⁴/y = 7 represents a relationship between the variables x and y. Specifically, it shows that the fourth power of x divided by y is equal to 7.
This equation can be rewritten as x⁴ = 7y, which means that if we know the value of y, we can determine the corresponding value of x that satisfies the equation. For example, if y = 1, then x⁴ = 7, and taking the fourth root of both sides of the equation gives us x = ± √7.
Conversely, if we know the value of x, we can solve for y by rearranging the equation as y = x⁴/7. This shows that y is directly proportional to x raised to the fourth power, meaning that as x increases, y will also increase, but at a faster rate due to the exponent of 4.
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7 (a) A On the Venn Diagram, shade the region A N B
For A∩B , shade the middle common part in the Venn diagram.
What is Venn diagram?
Using circles to represent relationships between objects or limited groupings of objects, a Venn diagram is one example. Circles that overlap share certain characteristics, whereas circles that do not overlap do not. Venn diagrams are useful for showing how two concepts are related and different visually.
Here the given Venn diagram contains two sets A and B.
The A intersection B or A∩B means , common elements in both A and B.
So we have shade the middle part of Venn Diagram.
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y = 25 - 2x need input x and output y 21 and 19
If we substitute x = 21 into the equation Y = 25 - 2x, we get:
Y = 25 - 2(21)
Y = 25 - 42
Y = -17
Therefore, if x = 21, then Y = -17.
If we substitute x = 19 into the equation Y = 25 - 2x, we get:
Y = 25 - 2(19)
Y = 25 - 38
Y = -13
Therefore, if x = 19, then Y = -13.
Another Statistics question pls help me
Answer:
55
Step-by-step explanation:
0* .4
28*.5
410*.1
Helpppppp pleaseeeee
The resulting matrix from an elementary row operation to get a 1, in row 1 column 1 is:
R₁ = [1 4 -8] and R₂ = [2 4 7]
What is the row of a matrixA rectangular array of numbers or mathematical objects which are arranged in rows and columns is called a matrix. Each row of a matrix is a horizontal sequence of numbers or objects that are separated by commas and enclosed within square brackets, and it represents a vector in the row space of the matrix.
The row operation R₁ - 4 — R₁ will be carried out as follows:
5 - 4 = 1 {row 1 column 1}
9 - 4 = 5 {row column 2}
-4 - 4 = -8 {row column 3}
Therefore, the resulting matrix from an elementary row operation to get a 1, in row 1 column 1 will have:
R₁ = [1 4 -8] and R₂ = [2 4 7]
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Alexia is cutting construction paper into rectangles for a projects. She needs to cut one rectangle that is a 9 inches x 14 1/3 inches. she needs to cut another that is 10 1/4 inches by 10 1/3 inches. How many total square inches of construction paper does Alexia need for her project?
Answer:
234.8525 square inches
Step-by-step explanation:
To find the total area of construction paper needed for the project, we need to find the area of each rectangle and add them together.
For the first rectangle, the dimensions are:
Length = 9 inches
Width = 14 1/3 inches
Area of the first rectangle = Length x Width
Area of the first rectangle = 9 inches x (43/3) inches
Area of the first rectangle = 9 inches x 14.33 inches
Area of the first rectangle = 128.97 square inches (rounded to two decimal places)
For the second rectangle, the dimensions are:
Length = 10 1/4 inches
Width = 10 1/3 inches
Area of the second rectangle = Length x Width
Area of the second rectangle = (41/4) inches x (31/3) inches
Area of the second rectangle = 10.25 inches x 10.33 inches
Area of the second rectangle = 105.8825 square inches (rounded to four decimal places)
Therefore, the total area of construction paper needed for the project is:
Total area = Area of first rectangle + Area of second rectangle
Total area = 128.97 square inches + 105.8825 square inches
Total area = 234.8525 square inches (rounded to four decimal places)
Therefore, Alexia needs a total of approximately 234.8525 square inches of construction paper for her project.
Oscar buys his lunch in the school cafeteria the cost of 15 school lunches is 33.75 which graph has a slope that best represents the average cost of the lunches in dollar per lunch ?
Answer:
The graph should be increasing 2.25 each time
Step-by-step explanation:
Since Oscar buys his lunch in school cafeteria and the cost of 15 school lunches is 33.75
Divide them: 33.75 ÷ 15 =
and will represents the average cost of the lunches in dollar per lunch that is 2.25
A recent study of high school students shows the percentage of females and males who took advanced math courses. A simple random sample of high school students was interviewed. The students were asked whether they had taken an advanced math course. Of the 150 females, 53 answered yes, as did 89 of the 275 males.
Part A: Construct and interpret a 98% confidence interval for the difference in population proportions of females and males who took advanced math courses. Be sure to state the parameter, check conditions, perform calculations, and make conclusion(s). (8 points)
Part B: Does your interval from part A give convincing evidence of a difference between the population proportions? Explain. (2 points)
Construct and interpret a 98% confidence interval for the difference in population proportions of females and males who took advanced math courses.
The parameter of interest is the difference in population proportions of females and males who took advanced math courses. We can denote this parameter by p₁ - p₂, where p₁ is the population proportion of females who took advanced math courses, and p₂ is the population proportion of males who took advanced math courses.
To construct a confidence interval for the difference in population proportions, we need to check the following conditions,
The sample of high school students should be a simple random sample.
The sample of high school students should be independent of each other.
Both groups of females and males who took advanced math courses should have at least 10 successes and 10 failures.
The sample proportions of females and males who took advanced math courses can be calculated as follows,
p₁ = 53/150 = 0.353
p₂ = 89/275 = 0.324
The sample size of females and males can also be calculated as follows,
n₁ = 150
n₂ = 275
The standard error of the difference in sample proportions can be calculated as follows,
SE = √[(p₁(1 - p₁))/n₁ + (p₂(1 - p₂))/n₂]
= √[(0.353(1 - 0.353))/150 + (0.324(1 - 0.324))/275] ≈ 0.048
Using a t-distribution with (n₁ + n₂ - 2) degrees of freedom and a 98% confidence level, we can construct a confidence interval for the difference in population proportions as follows:
(p₁ - p₂) ± t*SE
where t is the t-score corresponding to a 98% confidence level and (n₁ + n₂ - 2) degrees of freedom. Using a t-table, we can find that t ≈ 2.33.
Substituting the values into the formula, we get,
(0.353 - 0.324) ± 2.33*0.048
0.029 ± 0.112
True difference in population proportions of females and males who took advanced math courses lies between 0.029 and 0.147.
Part B: Does your interval from part A give convincing evidence of a difference between the population proportions? Explain.
Yes, our interval from part A gives convincing evidence of a difference between the population proportions because it does not contain zero. The interval (0.029, 0.147) is entirely positive, which means that the proportion of females who took advanced math courses is higher than the proportion of males who took advanced math courses. Additionally, the interval does not contain the value of one, which means that the difference in population proportions is not due to chance. Therefore, we can conclude that there is a significant difference in the population proportions of females and males who took advanced math courses.
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Complete the worksheet below please
Answer:
x= 3 cm
Explanation:
I am bad at it
HELP its a matric or matrix problem I NEED IT SOLVED AS QUICK AS POSSIBLE PLEASE
Using the given matrix, the value of -10(T) is
[tex]-10(T) = \left[\begin{array}{cc}-230&380\\-170&60\end{array}\right][/tex]
Multiplication of matricesFrom the question, we are to carry out the matrix multiplication
From the given information,
The given matrices is:
[tex]T =\left[\begin{array}{cc}23&-38\\17&-6\end{array}\right][/tex]
Now, we are to determine -10(T)
To achieve this, we will multiply each of the element in the given matrix by -10
That is,
-10 ×23 = -230
-10 × -38 = 380
-10 × 17 = -170
-10 × -6 = 60
Thus,
The result of the multiplication will be:
[tex]\left[\begin{array}{cc}-230&380\\-170&60\end{array}\right][/tex]
Hence, the value of -10(T) is
[tex]-10(T) = \left[\begin{array}{cc}-230&380\\-170&60\end{array}\right][/tex]
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1. It is impossible to manufacture any product by mass production methods without some
items being defective. Most production facilities employ quality control specialists to
study the proportion of a product being manufactured that is defective. Suppose a quality control engineer needs to keep defective items at 5% (or less). The engineer collects a
sample of 50 items manufactured and calculates the sample proportion (^ )of defective
items. (P)
a. What is the population proportion of items manufactured that are defective?
The population proportion of items manufactured that are defective is estimated to be between 0.137 and 0.037 with a 95% confidence level.
What is Sample Proportion :The sample proportion, denoted as ^p, is the proportion of a certain characteristic or outcome in a sample. It is calculated by dividing the number of individuals in the sample that exhibit the characteristic or outcome of interest by the total number of individuals in the sample.
It is an estimate of the population proportion, denoted as p, which represents the proportion of the same characteristic or outcome in the entire population.
Here we have
The sample proportion (^) of defective items is not provided in the question.
Hence, let's assume that the sample proportion (^) of defective items is 0.05 (i.e., 5% as specified in the question).
The sample size is 50, and the sample proportion (^) is 0.05.
The question is asking for the population proportion of items manufactured that are defective (P).
Use the sample proportion (^) and the sample size to calculate the margin of error and construct a confidence interval.
Assuming a 95% confidence level, we can use the following formula to calculate the margin of error:
Margin of error = 1.96 × √(^×(1⁻^)/n)
Substituting the values, we get:
Margin of error = 1.96 × √(0.05 × (1 - 0.05)/50) = 0.087
To construct the confidence interval, we add and subtract the margin of error from the sample proportion:
Confidence interval = ^ ± margin of error
Confidence interval = 0.05 ± 0.087
Confidence interval = (0.137, 0.037)
Therefore,
The population proportion of items manufactured that are defective is estimated to be between 0.137 and 0.037 with a 95% confidence level.
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According to the graph, what is the maximum number of passengers he can transport What is the maximum amount he can collect? Use the graph to determine the amount he charges a single passenger.
I can't see the chart...
john want to buy a new bike that costs 337and he already has save 103 estimates to find about how much more john needs to save to buy the bike
To find the estimated amount John needs to save to buy the bike, we can subtract the amount he already has saved from the cost of the bike:
Estimated amount = Cost of bike - Amount already saved
Estimated amount = $337 - $103
Estimated amount = $234
Therefore, John needs to save an estimated $234 more to buy the bike.
Answer:
John needs to save about $234 more to buy the bike. Note that this is an estimate, as we do not know if John will need to pay any taxes or additional fees when purchasing the bike.
Step-by-step explanation:
To find out how much more John needs to save to buy the bike, we can subtract the amount he has already saved from the cost of the bike:
337 - 103 = 234
Therefore, John needs to save about $234 more to buy the bike. Note that this is an estimate, as we do not know if John will need to pay any taxes or additional fees when purchasing the bike.
A regular pentagon has an apothem of
3 cm and a side length of 4.4 cm, find
its area.
The area of the polygon is 33cm²
What is area of polygon?A polygon is any closed curve consisting of a set of line segments (sides) connected such that no two segments cross.
The area of a polygon is expressed as;
A = 1/2 × p × a
where p is the perimeter of the polygon and a is the apothem.A pentagon is a 5 sides polygon.
Therefore;
Perimeter = 5 × 4.4
= 22cm
apothem = 3cm
area = 1/2 × 22 × 3
= 11× 3
= 33 cm²
therefore the area of the Pentagon in is 33cm²
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The length of a rectangle is five times its width.
If the perimeter of the rectangle is 108 cm, find its length and width.
Answer:
Let the width of the rectangle be w. Then the length of the rectangle is 5w.
The perimeter of a rectangle is the sum of all four sides. So, the perimeter of the rectangle is 2w+2(5w)=108 cm.
Simplifying the right side of the equation, we get 12w=108 cm.
Dividing both sides of the equation by 12, we get w=9 cm.
Since the width is 9 cm, the length of the rectangle is 5w=5(9)=45 cm.
Therefore, the length of the rectangle is 45 cm and the width is 9 cm.
A coach left woodlands and travelled towards Muar at an average speed of 50 Km/h.
Half an hour later, a car left Woodlands, travelled along the same route, and reached
Muar at 12.30 p.m. The distance between the two places was 150 km. The coach reached
Muar at 1.00 p.m
a) At what time did the car leave Woodlands?
b) What was the average speed of the car?
Answer:
a) 10:30 a.m.
b) 75 km/h
Step-by-step explanation:
You want to know the leaving time and speed of a car from Woodlands to Muar if it left half an hour later and arrived half an hour earlier than a coach that traveled the 150 km distance at a speed of 50 km/h and arrived at 1 p.m..
Travel timeThe travel time of the coach is found from the relation ...
time = distance/speed
time = (150 km)/(50 km/h) = (150/50) h = 3 h
Then the coach left Woodlands at ...
1 pm -3 h = 10 am
a) Leaving timeThe car left half an hour later than the coach, so left at 10:30 a.m..
b) SpeedThe car arrived at Muar at 12:30 p.m. so had a travel time of ...
12:30 -10:30 = 2 h
The speed over the 150 km distance is given by ...
speed = distance/time
speed = (150 km)/(2 h) = (150/2) km/h = 75 km/h
The average speed of the car was 75 km/h.
__
Additional comment
The car passed the coach at 11:30 a.m., when both had covered half the distance.
solve for x in the diagram
Answer:
15.04 (3.s.f)
Step-by-step explanation:
Cos a = adjacent/ hypotenuse
Cos 43 = 11/ x
so,
x= 11 / cos 43
= 15.04
on the first day of training Zari runs 2 miles north, the 4 miles east and then back home via shortest route. Taye runs 2 miles west then 4 miles south, and then back home again via the shortest route. a. draw their routes on the coordinate plane above, use a straightedge for accuracy. b. create a proof that demonstrates that the two triangles formed by their routes are congruent. proof needs three pairs of congruent properties of the triangles followed by a triangle congruency statement. show if congruent by ASA, SAS, or SSS.
By ASA (Angle-Side-Angle) congruence, triangle ABC is congruent to triangle DEF.
Instructions to draw the routes:
Draw the x-axis and y-axis to create a coordinate plane.
Mark the starting point of Zari's run as (0,0) on the coordinate plane.
From (0,0), move 2 units north to reach (0,2).
From (0,2), move 4 units east to reach (4,2).
From (4,2), move directly back to the starting point (0,0) using the shortest route.
Mark the starting point of Taye's run as (0,0) on the coordinate plane.
From (0,0), move 2 units west to reach (-2,0).
From (-2,0), move 4 units south to reach (-2,-4).
From (-2,-4), move directly back to the starting point (0,0) using the shortest route.
Instructions to prove that the two triangles are congruent using ASA:
Label the vertices of Zari's triangle as A (0,0), B (4,2), and C (0,0).
Label the vertices of Taye's triangle as D (0,0), E (-2,-4), and F (0,0).
Show that angle A and angle D are congruent because they are both right angles (90 degrees).
Show that segment AB and segment DE are congruent because they both have a length of 4 units.
Show that segment AC and segment DF are congruent because they both have a length of 2 units.
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please help! I don't understand this at all
The equation that represents the consecutive odd numbers whose product is 63 is; (x + 9) (x + 7) = 0
What are odd numbers?Odd numbers have special properties and relationships to other numbers, which make them important in mathematics. For instance, the sum of two odd numbers and the difference between two odd numbers both always equal one.
We can see that we can solve the double brackets by equation them to zero so we have that;
(x + 9) (x + 7) = 0
x = -9
x = -7
Thus;
(-9) (-7) = 63
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Set up the integral (or integrals) needed to compute the area between the curves. Use the smallest possible number of integrals. x= -5 x= 3 y= 9x y=x^2-10
The area between the curves is 61.5 square units.
How did we arrive at this value?To compute the area between the curves y = 9x and y = x^2 - 10, find the points of intersection between the curves.
Setting the two equations equal to each other:
x^2 - 10 = 9x
Move all to one side:
x^2 - 9x - 10 = 0
Factor the quadratics:
(x - 10)(x + 1) = 0
So, the points of intersection are x = -1 and x = 10.
Now, determine which curve is above the other in the interval between -5 and 3. Evaluating the y-coordinates of each curve at a point in this interval, say x = 0.
y = 9x, y = 0 at x = 0, so the curve passes across the origin.
y = x^2 - 10, y = -10 at x = 0.
Therefore, the curve y = 9x is above y = x^2 - 10 in the interval [-5, 3].
To compute the area between the curves, take the integral of the top curve minus the integral of the bottom curve over the interval of intersection:
∫(-1 to 3) [9x - (x^2 - 10)] dx
Simplify:
∫(-1 to 3) [ -x^2 + 9x + 10] dx
Then, integrate each term of the polynomial:
[ (-1/3) x^3 + (9/2) x^2 + 10x ] evaluated from x = -1 to x = 3
Plug into the limits of integration and then simplify:
= [ (81/2) - (19/3) ] - [ (-1/3) - (17/2) ]
= 61.5
Therefore, the area between the curves is 61.5 square units.
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1. A sample of 250 high-school students in a city results in an average number of text messages sent per month of 172.6, with a margin of error of + 4.8. If there are 3000 high-school students in the city, what is the estimated number of text messages sent in a month? between______ and____text messages
Answer:
Step-by-step explanation:
1) Find the upper bound of the confidence interval:
Upper bound = sample mean + margin of error
= 172.6 + 4.8
= 177.4
2) Find the lower bound of the confidence interval:
Lower bound = sample mean - margin of error
= 172.6 - 4.8
= 167.8
3) Estimate the total number of text messages sent in a month:
Total number of text messages sent = (number of students in the population / number of students in the sample) x sample mean
= (3000 / 250) x 172.6
= 2071.2
Therefore, the estimated number of text messages sent in a month is 2071.2, with a 95% confidence interval between 167.8 and 177.4 text messages.
Answer:
Between 503400 and 532200 text messages----------------------------
Determine the average number of text messages sent per student within the margin of errorFind lower bound:
172.6 - 4.8 = 167.8 text messagesFind upper bound:
172.6 + 4.8 = 177.4 text messages Estimate the total number of text messages for all 3000 studentsLower bound:
167.8 text messages × 3000 students = 503400 text messagesUpper bound:
177.4 text messages × 3000 students = 532200 text messagesThe estimated number of text messages sent in a month for all 3000 high-school students in the city is:
Between 503400 and 532200 text messagesWould like some help with this question, please.
Answer:
i believe 67 its somewhat hard to tell but the line seems to be in the middle between 150 and 140
Step-by-step explanation:
since it heats up to 212 then the person lets it cool down for 10 mins the temp goes to 145 (Answer is 67)
The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 8.2 mg and a standard deviation of 1.45 mg. The company that produces these cigarettes claims that it has now reduced the amount of nicotine. The supporting evidence consists of a sample of 42 cigarettes with a mean nicotine amount of 7.73 mg.
Assuming that the given mean and standard deviation have NOT changed, find the probability of randomly seleting 42 cigarettes with a mean of 7.73 mg or less.
P(M < 7.73 mg) = ???
The probability of randomly selecting 42 cigarettes with a mean of 7.73 mg or less is: 0.0179
How to find the p-value from z-score?The formula to find the z-score of the given normal distribution is:
z = (x' - μ)/(σ/√n)
where:
x' is sample mean
μ is population mean
σ is standard deviation
n is sample size
We are given:
x' = 7.73 mg
μ = 8.2 mg
σ = 1.45 mg
n = 42
Thus:
z = (7.73 - 8.2)/(1.45/√42))
z = -2.1
From online p-value from z-score calculator, we have:
p = 0.0179
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