the final answer is 27/125.
To evaluate [tex](3/5)^3[/tex], we simply need to multiply (3/5) by itself three times:
[tex](3/5)^3 = (3/5) * (3/5) * (3/5)[/tex]
To simplify, we can first multiply the numerators together and the denominators together:
[tex](3/5)^3 = 27/125[/tex]
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Triangle A′B′C′ is a dilation of triangle ABC about point P with a scale factor of 1/2. Is the dilation a reduction or an enlargement? reduction enlargement
Triangle A′B′C′ is a dilation of triangle ABC about point P with a scale factor of 1/2. The dilation is a reduction.
A dilation is a transformation that changes the size of a figure, but not its shape. It can be either an enlargement or a reduction depending on the value of the scale factor.
If the scale factor is greater than 1, then the image will be larger than the original figure. This is called an enlargement.
If the scale factor is between 0 and 1, then the image will be smaller than the original figure. This is called a reduction.
In this case, the scale factor is 1/2, which is less than 1. Therefore, the image of triangle ABC is smaller than the original triangle, and the dilation is a reduction.
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N
the accurate scale drawing shows
the positions of port p and a lighthouse l.
n
lindsey sails her boat from port p
on a bearing of 050°
she sails for 12 hours at an average
speed of 5km/h to a port q.
l*
p*
scale: 1 cm represents 3 km.
a) indicate the position of port q on the drawing (use the x tool).
(2)
b) find the distance, in km, of port q from lighthouse l.
(2)
c) find the bearing of port q from lighthouse l.
total marks:
A line segment of length 15 cm at a bearing of 50° from P to locate the position of Q on the drawing. Use the Law of Cosines the distance d between Q and L, which is approximately 71.2 km. Use the Law of Sines the angle x opposite d, which is approximately 29.5°, giving the bearing of Q from L.
Using the given scale of 1 cm represents 3 km, we can draw a line segment of length 15 cm (since 5 km/h x 12 h = 60 km) on a bearing of 50° from P to locate the position of Q. The point Q can be marked on the drawing using the x tool.
We can use the Law of Cosines to find the distance d between Q and L. Let a = 60 km (distance from P to Q), b = 36 km (distance from P to L), and C = 130° (the angle between a and b, which is equal to the sum of the angles at Q and L). Then
d² = a² + b² - 2ab cos(C)
d² = (60)² + (36)² - 2(60)(36)cos(130°)
d ≈ 71.2 km
Therefore, the distance of port Q from lighthouse L is approximately 71.2 km.
We can use the Law of Sines to find the angle x opposite the distance d between Q and L. Let a = 60 km (distance from P to Q), b = 36 km (distance from P to L), and sin(A) = sin(130°)/d. Then
sin(x)/60 = sin(130°)/d
sin(x) = (60/d)sin(130°)
x ≈ 29.5°
Therefore, the bearing of port Q from lighthouse L is approximately 29.5°.
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A survey found that the relationship between the years of education a person has and that person's yearly income in his or her first job after completing schooling can be modeled by the equation y = 1200 x + 7000, where x is the number of years of education and y is the yearly income. According to the model, how much does 1 year of education add to a person's yearly income?
According to the model, each additional year of education adds $1200 to a person's yearly income in their first job after completing schooling.
We're given the equation y = 1200x + 7000, where x represents the number of years of education, and y represents the yearly income.
To find how much 1 year of education adds to a person's yearly income, we need to look at the coefficient of the variable x, which is 1200.
So according to the model, 1 year of education adds $1,200 to a person's yearly income.
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Juanita keeps 25% of the monthly sales from her ice cream shop as a profit. If the shop makes an average of $750 in sales this month, how much money will Juanita keep as profit this month?
Juanita will keep $187.50 as profit from her ice cream shop's sales this month.
Juanita will keep 25% of the monthly sales as profit, which is equivalent to $750 x 0.25 = $187.50. This means that out of the total monthly sales of $750, Juanita will keep $187.50 as her profit, while the remaining $562.50 will go towards the expenses of running the ice cream shop.
Profit is the amount of money that a business earns after deducting all its expenses. It is the excess revenue that remains after all the costs of doing business have been taken into account. Profit is essential for businesses as it helps them to sustain their operations, invest in growth opportunities, and generate returns for their owners or shareholders.
In Juanita's case, her profit is 25% of the monthly sales, which is a significant amount that can help her to keep her ice cream shop running smoothly. By keeping a portion of the sales as profit, Juanita can use the money to pay for her expenses, such as rent, utilities, and supplies, while still having enough left over to reinvest in her business or save for her personal use.
Overall, understanding the concept of profit is crucial for entrepreneurs and business owners to ensure that they can generate enough revenue to cover their expenses and make a profit that will help them to grow and succeed in the long run.
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Mrs. Ross is a librarian at Westside Library. In examining a random sample of the library's book collection, she found the following. 902 books had no damage, 80 books had minor damage, and 43 books had major damage. Based on this sample, how many of the 30,000 books in the collection should Mrs. Ross expect to have no damage? Round your answer to the nearest whole number. Do not round any intermediate calculations. Books 5 ? X
There would be 26,790 books. of the 30,000 books in the collection should Mrs. Ross expect to have no damage
Out of the random sample, 902 books had no damage. To estimate the number of books with no damage in the entire collection of 30,000 books, we can use the proportion of books in the sample that had no damage.
The proportion of books in the sample with no damage is:
902 / (902 + 80 + 43) = 0.893
Therefore, we can expect approximately:
30,000 x 0.893 = 26,790
books in the collection to have no damage. Rounded to the nearest whole number, the answer is:
26,790 books.
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Two weeks ago i bought 20 cupcakes last week I bought 13 help me continue the pattern
Answer:
If the pattern is to continue, the next value would be a decrease of 7 from the previous value because 20-13=7. Therefore, the value for this week would be:
13 - 7 = 6
So, if you were to continue the pattern, you would have bought 6 cupcakes this week.
Describe the clockwise rotation about the origin from the pre-image to the image
The clockwise rotation about the origin from the pre-image to the image include the following: a rotation of 90° clockwise.
What is a rotation?In Mathematics, a rotation is a type of transformation which moves every point of the object through a number of degrees around a given point, which can either be clockwise or counterclockwise (anticlockwise) direction.
Additionally, the rotation of a point 90° about the center (origin) in a clockwise direction would produce a point that has these coordinates (y, -x).
Next, we would apply a rotation of 90° clockwise to the coordinate of triangle ABC as follows;
(x, y) → (y, -x)
Coordinate A = (1, 1) → Coordinate A' = (1, -(1)) = (1, -1)
Coordinate B = (1, 4) → Coordinate B' = (4, -(1)) = (4, -1)
Coordinate C = (5, 1) → Coordinate C' = (1, -(5)) = (1, -5)
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You pick a card at random.
What is P(even or prime)?
Write your answer as a percentage
Probability of picking an even or prime card at random is approximately 88.89%.
To find the probability of picking an even or prime card at random, we first need to identify the possible cards that meet these conditions.
In a standard deck of cards, there are 52 cards, but we only consider the numerical values, which are 2-10 for each of the four suits (hearts, clubs, spades, and diamonds).
Even numbers: 2, 4, 6, 8, 10
Prime numbers: 2, 3, 5, 7
Combining the even and prime numbers, we have: 2, 3, 4, 5, 6, 7, 8, 10. Note that 2 appears only once in the combined list.
Now we find the probability by dividing the number of favorable outcomes (even or prime numbers) by the total number of possible outcomes (cards numbered 2-10).
P(even or prime) = (Number of even or prime cards) / (Total number of cards from 2-10)
P(even or prime) = 8 / 9
To express the probability as a percentage, multiply by 100:
P(even or prime) = (8 / 9) × 100 ≈ 88.89%
So, the probability of picking an even or prime card at random is approximately 88.89%.
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Show your work for multiplying the polynomials below and put your answer in standard form in the box below: (No work loses points)
(x+6)(x2−3x−4)
The polynomials are multiplied to give the expression x³ + 3x² - 22x - 24
How to determine the productWe need to know that algebraic expressions are described as expressions that are composed of terms, variables, their coefficients, factors and constants.
Also, these expressions are made up of mathematical operations. They are listed as;
SubtractionMultiplicationDivisionAddition BracketParenthesesFrom the information given, we have the expression;
(x+6)(x2−3x−4)
expand the bracket, we get;
x³ - 3x² - 4x + 6x² - 18x - 24
add the like terms, we get;
x³ + 3x² - 22x - 24
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Consider a population that grows according to the recursive rule Pn=Pn−1+50
, with initial population P0=30
To find the population at any given term n, continue to apply the recursive rule.
Pₙ = Pₙ₋₁ + 50
Using this recursive rule and the initial population, you can find the population at any given term n.
We are given a population growth model with a recursive rule and an initial population. Let's break down the information and find the population at any given term n.
Recursive rule: Pₙ = Pₙ₋₁ + 50
Initial population: P₀ = 30
Now let's find the population at any term n, using the recursive rule:
Step 1: Determine the base case, which is the initial population.
P₀ = 30
Step 2: Apply the recursive rule to find the next few terms.
P₁ = P₀ + 50 = 30 + 50 = 80
P₂ = P₁ + 50 = 80 + 50 = 130
P₃ = P₂ + 50 = 130 + 50 = 180
Step 3: To find the population at any given term n, continue to apply the recursive rule.
Pₙ = Pₙ₋₁ + 50
Using this recursive rule and the initial population, you can find the population at any given term n.
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In March 2020, a newspaper article reported that houses in Nevada are so expensive that many people are unable to
afford the monthly house payments.
This graph shows the average house price and the average monthly payment for all the different counties in Nevada.
House Prices and Payments
1a. What does the pattern of the data indicate
about the connection between house prices and
monthly payments?
Type Here
1b. Find the monthly payment for a house
costing $450,000.
Type Here
1c. Find a formulate connecting the average
monthly payment with the average house price
in slope-intercept form (y = mx + b).
Type Here
Average monthly payment/dollars
5000
4000-
3000
000
100000
Fosfor
200000 300000 400000
Average house price/dollars
500000
The pattern of the data indicates a linear relationship or strong positive correlation between the average house prices and average monthly payments.
The monthly payment for a house costing $450,000 is $3,600.
A formulate connecting the average monthly payment with the average house price in slope-intercept form is y = 0.008x.
What is a proportional relationship?In Mathematics, a proportional relationship can be represented by this equation:
y = kx
Where:
x represents the average house price.y represents the average monthly payment.k represents the constant of proportionality.Next, we would determine the constant of proportionality (k) as follows:
Constant of proportionality (k) = y/x
Constant of proportionality (k) = 8/1000
Constant of proportionality (k) = 1/125 or 0.008.
Therefore, a formula that connects the two variables is given by;
y = kx
y = 0.008x
When average house price (x) = $450,000, the average monthly payment (y) is given by:
y = 0.008(450,000)
y = $3,600.
In conclusion, we can logically deduce that the pattern of the data shows a linear relationship or strong positive correlation between the average house prices (x) and average monthly payments (y) because as the average house prices (x) increases, the average monthly payments (y) also increases.
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Question 1(Multiple Choice Worth 2 points)
(Circle Graphs MC)
The circle graph describes the distribution of preferred transportation methods from a sample of 400 randomly selected San Francisco residents.
circle graph titled San Francisco Residents' Transportation with five sections labeled walk 40 percent, bicycle 8 percent, streetcar 15 percent, bus 10 percent, and cable car 27 percent
Which of the following conclusions can we draw from the circle graph?
Together, Streetcar and Cable Car are the preferred transportation for 168 residents.
Together, Walk and Streetcar are the preferred transportation for 55 residents.
Bus is the preferred transportation for 45 residents.
Bicycle is the preferred transportation for 50 residents.
Question 2(Multiple Choice Worth 2 points)
(Appropriate Measures MC)
The box plot represents the number of tickets sold for a school dance.
A horizontal line labeled Number of Tickets sold that starts at 8, with tick marks every one unit up to 30. The graph is titled Tickets Sold for A Dance. The box extends from 17 to 21 on the number line. A line in the box is at 19. The lines outside the box end at 10 and 27.
Which of the following is the appropriate measure of center for the data, and what is its value?
The mean is the best measure of center, and it equals 19.
The median is the best measure of center, and it equals 4.
The median is the best measure of center, and it equals 19.
The mean is the best measure of center, and it equals 4.
Question 3(Multiple Choice Worth 2 points)
(Comparing Data LC)
The histograms display the frequency of temperatures in two different locations in a 30-day period.
A graph with the x-axis labeled Temperature in Degrees, with intervals 60 to 69, 70 to 79, 80 to 89, 90 to 99, 100 to 109, 110 to 119. The y-axis is labeled Frequency and begins at 0 with tick marks every one unit up to 14. A shaded bar stops at 10 above 60 to 69, at 9 above 70 to 79, at 5 above 80 to 89, at 4 above 90 to 99, and at 2 above 100 to 109. There is no shaded bar above 110 to 119. The graph is titled Temps in Sunny Town.
A graph with the x-axis labeled Temperature in Degrees, with intervals 60 to 69, 70 to 79, 80 to 89, 90 to 99, 100 to 109, 110 to 119. The y-axis is labeled Frequency and begins at 0 with tick marks every one unit up to 16. A shaded bar stops at 2 above 60 to 69, at 4 above 70 to 79, at 12 above 80 to 89, at 6 above 90 to 99, at 4 above 100 to 109, and at 2 above 110 to 119. The graph is titled Temps in Desert Landing.
When comparing the data, which measure of center should be used to determine which location typically has the cooler temperature?
Median, because Desert Landing is symmetric
Mean, because Sunny Town is skewed
Mean, because Desert Landing is symmetric
Median, because Sunny Town is skewed
Question 4(Multiple Choice Worth 2 points)
(Appropriate Measures MC)
A charity needs to report its typical donations received. The following is a list of the donations from one week. A histogram is provided to display the data.
10, 11, 35, 39, 40, 42, 42, 45, 49, 49, 51, 51, 52, 53, 53, 54, 56, 59
A graph titled Donations to Charity in Dollars. The x-axis is labeled 10 to 19, 20 to 29, 30 to 39, 40 to 49, and 50 to 59. The y-axis is labeled Frequency. There is a shaded bar up to 2 above 10 to 19, up to 2 above 30 to 39, up to 6 above 40 to 49, and up to 8 above 50 to 59. There is no shaded bar above 20 to 29.
Which measure of variability should the charity use to accurately represent the data? Explain your answer.
The range of 13 is the most accurate to use, since the data is skewed.
The IQR of 49 is the most accurate to use to show that they need more money.
The range of 49 is the most accurate to use to show that they have plenty of money.
The IQR of 13 is the most accurate to use, since the data is skewed.
Question 5(Multiple Choice Worth 2 points)
(Making Predictions MC)
A recent conference had 900 people in attendance. In one exhibit room of 80 people, there were 65 teachers and 15 principals. What prediction can you make about the number of principals in attendance at the conference?
There were about 820 principals in attendance.
There were about 731 principals in attendance.
There were about 208 principals in attendance.
There were about 169 principals in attendance.
Question 6(Multiple Choice Worth 2 points)
(Creating Graphical Representations LC)
A teacher was interested in the subject that students preferred in a particular school. He gathered data from a random sample of 100 students in the school and wanted to create an appropriate graphical representation for the data.
Which graphical representation would be best for his data?
Stem-and-leaf plot
Histogram
Circle graph
Box plot
Answer:
Step-by-step explanation:
Car are the preferred transportation for 168 residents.Together, Walk and Streetcar are the preferred transportation for 55 residents.Bus is the preferred transportation for 45 residents.Bicycle is the preferred transportation for 50 residents.Question 2(Multiple Choice Worth 2 points)(Appropriate Measures MC)The box plot represents the number of tickets sold for a school dance.A horizontal line labeled Number of Tickets sold that starts at 8, with tick marks every one unit up to 30. The graph is titled Tickets Sold for A Dance. The box extends from 17 to 21 on the numb
You and a group of friends want to know how many students in your school prefer rap music. There are 440 students in your school. Each person in the group randomly surveys 20 students. The table shows the results.
A. Use each sample to make and estimate for the number of students in your school who prefer rap music
B. Describe the center and variation of the estimates
The survey results show that the estimates for the number of students in the school who prefer rap music range from 110 to 154. The center of the estimates is around 121, with a variation of about 66.
To estimate the number of students who prefer rap music, multiply the proportion who prefer rap in each sample by the total number of students in the school (440)
Sample 1: 0.25 x 440 = 110
Sample 2: 0.20 x 440 = 88
Sample 3: 0.30 x 440 = 132
Sample 4: 0.35 x 440 = 154
The center of the estimates is the average of the four estimates: (110 + 88 + 132 + 154) / 4 = 121. Variability can be described using the range (154 - 88 = 66) or the standard deviation of the estimates, which requires additional calculations.
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Select two trigonometric functions that are equivalent to the ratio x/y.
Sine and cosine are both equivalent to x/y, depending on the angle of the point on the circle.
To find two trigonometric functions equivalent to the ratio x/y, we can use the unit circle. Let's assume that x and y are the coordinates of a point on the circle, where x represents the horizontal displacement, and y represents the vertical displacement.
From this, we can find that the sine of the angle that x and y make with the x-axis is y, and the cosine of that angle is x. Therefore, the two trigonometric functions equivalent to the ratio x/y are sine and cosine.
We can write this as sin(angle) = y/y and cos(angle) = x/y. It's important to note that the value of the angle depends on the position of the point on the unit circle.
So, sine and cosine are both equivalent to x/y, depending on the angle of the point on the circle.
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Will give brainliest if right
aabc ~ def. what sequence of transformations will move aabc onto adef?
d. a dilation by scale factor of 2, centered at the origin, followed by a reflection over the y-axis
AABC is transformed onto ADEF by a dilation by a scale factor of 2, centered at the origin, followed by a reflection over the y-axis.
The sequence of transformations that will move AABC onto ADEF is a dilation by a scale factor of 2, centered at the origin, followed by a reflection over the y-axis.
Firstly, dilation is a transformation that changes the size of an object but not its shape.
The dilation factor is multiplied by each coordinate, so when the dilation is centered at the origin, the new coordinates will be twice the original coordinates.
Therefore, AABC will be enlarged to A'BC', and DEF will be enlarged to D'E'F, both with double the size.
Then, reflection is a transformation that flips an object over a line of reflection. In this case, the line of reflection is the y-axis.
When we reflect A'BC' over the y-axis, we get A''B''C'', and when we reflect D'E'F over the y-axis, we get D''E''F''.
Therefore, AABC is transformed onto ADEF by a dilation by a scale factor of 2, centered at the origin, followed by a reflection over the y-axis.
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EASY POINTS!!
i need someone to write three sentences that explains how i got the answer i have the equation already but dont know how to do it THANKS SO MUCH.
An amusement park has discovered that the brace that provides stability to the Ferris wheel has been damaged and needs work. The arc length of the steel reinforcement that must be replaced is between the two seats shown below. The sector area is 28.25 ft2 and the radius is 12 feet. What is the length of steel that must be replaced (Arc Length)? Describe the steps you used to find your answer and show all work. Round θ to the nearest tenth.
my "work":
Area of Sector = 28.25 ft² & Radius = 12 feet
Area of sector = ∅/360 × π × r²
Put the values,
28.25 = ∅/360 × π × 12²
∅ = (28.25 × 360) / π×12²
∅ = 22.47 ≈ 22.5
length of arc =∅/360 × 2 × π × r
L = 22.5/360 × 2 × π × 12
L = 4.71 Feet
We used the given sector area formula, 28.25 = ∅/360 × π × 12², to find the central angle (∅) by rearranging the equation
The Explanation of your solutionFirst, we used the given sector area formula, 28.25 = ∅/360 × π × 12², to find the central angle (∅) by rearranging the equation and solving for ∅, which resulted in ∅ ≈ 22.5 degrees.
Next, we applied the arc length formula, L = ∅/360 × 2 × π × r, and plugged in the values we had, including the calculated ∅ and the given radius (12 feet).
Finally, we calculated the arc length (L) to be approximately 4.71 feet, which is the length of steel that must be replaced.
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I need to find the 2 answers
Answer:
28 degrees and 62 degrees
Step-by-step explanation:
Set up your equation like this:
x+(x-34)=90
2x-34=90
2x=56
x=28
28+34=62
So the smaller angle is 28 degrees and the larger angle is 62 degrees.
Hope this helps!! :D
If x = -3, then which inequality is true?
The inequailty y < x + 3 would be true when x = -3 and all values of y are less than 1
If x = -3, then which inequality is true?From the question, we have the following parameters that can be used in our computation:
The statement that x = -3
The above value implies that we substitute -3 for x in an inequality and solve for the variable y
Take for instance, we have
y < x + 4
Substitute the known values in the above equation, so, we have the following representation
y < -3 + 4
Evaluate
y < 1
This means that the inequailty y < x + 3 would be true when x = -3 and all values of y are less than 1
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5. A 40-kg ornamental star is suspended by two chains fastened to
horizontal beams at different heights with angles as shown.
Determine the tension in each chain.
The diagram is shown below; I also know we have to split up the triangles to make two right angle triangles but I’m not sure where to go from there
Answer:We can start by resolving the forces acting on the ornamental star in the vertical direction and in the horizontal direction. Since the star is stationary, these forces must balance each other out.
Let's call the tension in the higher chain T1 and the tension in the lower chain T2. We can use trigonometry to find the vertical and horizontal components of each tension force.
For T1:
The vertical component is T1cos(40°) and the horizontal component is T1sin(40°).
For T2:
The vertical component is T2cos(30°) and the horizontal component is T2sin(30°).
Now, resolving the forces in the vertical direction, we have:
T1cos(40°) + T2cos(30°) - mg = 0
where m is the mass of the star and g is the acceleration due to gravity.
Substituting the values:
T1cos(40°) + T2cos(30°) - (40 kg)(9.81 m/s^2) = 0
T1cos(40°) + T2cos(30°) = 392.4 N
Next, resolving the forces in the horizontal direction, we have:
T1sin(40°) = T2sin(30°)
Now we have two equations with two unknowns:
T1cos(40°) + T2cos(30°) = 392.4 N
T1sin(40°) = T2sin(30°)
Solving these equations simultaneously, we get:
T1 = 266.4 N
T2 = 205.1 N
Therefore, the tension in the higher chain (T1) is 266.4 N and the tension in the lower chain (T2) is 205.1 N.
Step-by-step explanation:
Alex can stack exactly 16 cookies, each with a diameter of 5 cm inside a cylindrical container with the same diameter and a volume of 100% cm³. What is
the surface area of the container? Round your answer to the nearest square centimeter.
Answer:
Read
Step-by-step explanation:
If Alex can stack exactly 16 cookies with a diameter of 5 cm inside a cylindrical container with the same diameter, then the height of the cylinder will be equal to the height of 16 cookies stacked on top of each other, which is 16 multiplied by the height of one cookie.
The diameter of each cookie is 5 cm, so the radius is 2.5 cm. The volume of each cookie is πr²h, where r is the radius and h is the height, so the volume of one cookie is:
V1 = π(2.5 cm)²h
The volume of 16 cookies will be:
V16 = 16π(2.5 cm)²h
Since the volume of the cylindrical container is 100% cm³, we have:
V16 = Vcyl
where Vcyl is the volume of the cylindrical container. Therefore:
16π(2.5 cm)²h = Vcyl
The height of 16 cookies stacked on top of each other is 16 times the height of one cookie, so:
h = 16(1 cm) = 16 cm
Substituting this value into the equation above and solving for the radius, we get:
r = √(Vcyl / (16πh)) = √(100 cm³ / (16π(16 cm))) ≈ 1.03 cm
The surface area of the cylindrical container is given by the formula:
A = 2πr² + 2πrh
Substituting the values we found for r and h, we get:
A = 2π(1.03 cm)² + 2π(1.03 cm)(16 cm) ≈ 142 cm²
Therefore, the surface area of the container is approximately 142 square centimeters. Rounded to the nearest square centimeter, the answer is 142 square centimeters.
The surface area of the given cylindrical container is 290 cm².
What is the volume of a cylinder?The volume of a cylinder is given by the formula:
V = πr²h
where r is the radius of the cylinder and h is its height.
We know that the volume of the cylindrical container is 100π cm³ and that it has the same diameter as the cookies, which is 5 cm.
Since the diameter of the container is 5 cm, its radius is 2.5 cm.
We can rearrange the formula for volume to solve for
h = V/πr²
h = 100π/π(2.5)²
h = 16
So, the height of the container is 16 cm.
To find the surface area of the container, we can use the formula:
A = 2πrh + 2πr²
where r is the radius of the container and h is its height.
Substituting the values we have, we get:
A = 2π(2.5)(16)+2π(2.5)²
A = 92.5π
A ≈ 290.45
Rounding to the nearest square centimeter,
A = 290
Thus, the surface area of the container is 290 cm².
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Please help and show work pls
noah and emma are standing on opposite sides of a 43.3 ft tree looking up at noah’s cat, which is perched at the very top. they are separated by a horizontal distance of 100 ft. the distance from emma to the cat is 50 ft and her angle of elevation to see the cat is 60°. the distance from noah to the cat is 86.6 ft and his angle of elevation to see the cat is 30°.
(a) identify three different trigonometric ratios that could have been used to find the distance x between emma and the base of the tree. for each trigonometric ratio, determine the distance. round to the nearest whole number.
(b) use the pythagorean theorem to find the distance x between emma and the base of the tree. round to the nearest whole number.
(a) The three different trigonometric ratios that could have been used to find the distance x between Emma and the base of the tree are sin(60°) = 43.3/50, cos(60°) = x / 50, and tan(60°) = 43.3 / x. The distance is 25 ft.
(b) Using the Pythagorean theorem, the distance x between Emma and the base of the tree is 25 ft.
(a) We can use sine, cosine, and tangent trigonometric ratios to find the distance x between Emma and the base of the tree.
1. Sine:
sin(60°) = opposite/hypotenuse = (tree height) / 50
tree height = 50 * sin(60°) = 43.3 ft (since it's given that the tree is 43.3 ft tall)
2. Cosine:
cos(60°) = adjacent/hypotenuse = x / 50
x = 50 * cos(60°) = 25 ft
3. Tangent:
tan(60°) = opposite/adjacent = (tree height) / x
x = (tree height) / tan(60°) = 43.3 / tan(60°) ≈ 25 ft
(b) To find the distance x between Emma and the base of the tree using the Pythagorean theorem, we can consider the triangle formed by Emma, the base of the tree, and the top of the tree.
Let's call the distance from the base of the tree to the top of the tree (tree height) y.
Emma's distance to the cat (50 ft) is the hypotenuse, the distance x is one leg, and the tree height y (43.3 ft) is the other leg of the right triangle.
Using the Pythagorean theorem: x² + y² = hypotenuse²
x² + 43.3² = 50²
x² + 1874.89 = 2500
x² = 625.11
x ≈ 25 ft
So, the distance between Emma and the base of the tree is approximately 25 ft.
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find the equation of the line that has a gradient of 2 and passes through the point (-3,3)
Answer:
[tex]y = 2x + 9[/tex]
Step-by-step explanation:
It is given that the slope of the line is 2, and it passes through (-3 , 3). The equation of straight lines is y = mx + b, in which:
y = (x , y) = 3
m = slope (gradient) = 2
x = (x , y) = -3
b = y-intercept
~
Plug in the corresponding numbers to the corresponding variables:
y = mx + b
3 = (2)(-3) + b
First, multiply -3 with 2:
[tex]3 = (2)(-3) + b\\3 = (2 * -3) + b\\3 = -6 + b[/tex]
Next, isolate the variable, b. Note the equal sign, what you do to one side, you do to the other. Add 6 to both sides of the equation:
[tex]3 = b - 6\\3 (+6) = b - 6 (+6)\\b = 3 + 6\\b = 9[/tex]
Plug in 2 for slope, and 9 for y-intercept, in the given equation:
[tex]y = mx + b\\m = 2\\b = 9\\[/tex]
[tex]y = 2x + 9[/tex] is your answer.
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Jack, Martina, and Napier are racing their bikes. Each has an equal chance of winning the race
What is the probability that Jack wins the race, and Martina finishes last?
Therefore, the probability that Jack wins the race and Martina finishes last is 1/6 or approximately 0.167.
What is the probability that Jack wins the race, and Martina finishes last?There are 3 people racing, so there are 3! = 6 possible ways the race can end (assuming no ties).
These are:
Jack, Martina, Napier
Jack, Napier, Martina
Martina, Jack, Napier
Martina, Napier, Jack
Napier, Jack, Martina
Napier, Martina, Jack
Of these 6 outcomes, there is only 1 where Jack wins the race and Martina finishes last: outcome 2.
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Unit 11 volume & surface area homework 4 area of regular figures
The area of the regular figure of side length 24 cm is 1496.45 square centimeter.
The given regular figure is a hexagon.
A hexagon is a polygon with six sides and six angles.
It is a two-dimensional shape formed by connecting six straight line segments.
The side length of hexagon is 24 cm..
The formula for the area of a regular hexagon is 3√3/2 a².
Where a is the side length of hexagon.
Area = 3√3/2 a².
Plug in a value as 24:
Area = 3√3/2 ×24²
= 3√3×576/2
=2992.9/2
=1496.45 square centimeter.
Hence, the area of figure is 1496.45 square centimeter.
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Find the area of the regular figure below:
Alguém que entende de curva abc? eu tenho um exercício pra fazer sobre, em que o enunciado diz: "4. construir a curva abc com os seguintes dados da tabela abaixo:" e só me dá a tabela mesmo, ele não me dá nenhuma proporção do tipo: a classe a são os produtos que somam 70% sabe? queria saber como vou fazer a divisão abc se não sei a porcentagem de cada um?
ABC curve: order, calculate percentages, and classify items accordingly.
How to construct ABC curve analysis?A Curva ABC é uma ferramenta de gestão de estoques que classifica os itens de acordo com sua importância em termos de valor monetário. Para construir a curva ABC, é necessário primeiro ordenar os itens por ordem decrescente de valor monetário (ou de outro critério relevante, como o volume de vendas). Em seguida, deve-se calcular a porcentagem acumulada do valor total de todos os itens, começando pelo mais valioso.
Assim, a classe A será composta pelos itens que representam os primeiros 20% a 30% do valor total (ou outro percentual definido pela empresa), a classe B pelos itens seguintes que representam cerca de 30% a 50% do valor total, e a classe C pelos itens restantes que representam cerca de 20% a 50% do valor total.
Se o enunciado do seu exercício não especificou a proporção de cada classe, você pode assumir as proporções padrão que são amplamente utilizadas na prática empresarial. Assim, a classe A é composta pelos itens mais importantes, que representam cerca de 20% a 30% do valor total, a classe B pelos itens seguintes que representam cerca de 30% a 50% do valor total, e a classe C pelos itens menos importantes que representam cerca de 20% a 50% do valor total.
Para construir a curva ABC, você pode seguir os seguintes passos:
1. Ordene os itens da tabela em ordem decrescente de valor monetário (ou do critério relevante) e calcule o valor total de todos os itens.
2. Calcule a porcentagem acumulada do valor total de cada item, começando pelo mais valioso. Por exemplo, se o item mais valioso representa 10% do valor total, e o segundo item mais valioso representa 15% do valor total, então a porcentagem acumulada dos dois primeiros itens seria de 25%
3. Classifique os itens de acordo com as proporções padrão da curva ABC (20-30% para a classe A, 30-50% para a classe B e 20-50% para a classe C).
4. Desenhe a curva ABC, representando no eixo X o percentual acumulado dos itens e no eixo Y o percentual do valor total.
5. Identifique os itens que pertencem a cada classe (A, B ou C) na curva ABC.
Espero que isso ajude! Se você tiver mais alguma dúvida, não hesite em perguntar.
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For a certain company , the cost for producing x items is 50x + 300 and the revenue for selling x items is 90x - 0. 5x^2.
a) set up an expression for the profit from producing and selling x items. We assume that the company sells all of the items that it produces (hint: it is a quadratic polynomial)
b) find two values of x that will create a profit of $300
c) is it possible for the company to make a profit of $15,000
Answer:
Step-by-step explanation:
a) Profit = Revenue - Cost = (90x - 0.5x²) - (50x + 300)
= -0.5x² + 90x - 50x - 300
= -0.5x² + 40x - 300
b) -0.5x² + 40x - 300 = 300
-0.5x² + 40x - 600 = 0
use quadratic equation to find the roots of x (a = -0.5, b = 40, c = -600):
x = 20, 60
c) -0.5x² + 40x - 300 = 15000
-0.5x² + 40x - 15300 = 0
use quadratic equation to find the roots of x (a = -0.5, b = 40, c = -15300):
x = 40±10√290i
Not possible to make a profit of $15,000
A student lifts a 12 n textbook 1. 5 and carries the book 5 m across the room in 7s
The student does 18 J of work on the textbook. Their power output is 0.0228 W. Work is calculated by multiplying force and displacement, while power is the rate at which work is done and is calculated by dividing work by time.
To calculate the work done by the student on the textbook, we use the formula
work = force x distance x cos(theta)
where force is the weight of the textbook, distance is the height it is lifted, and theta is the angle between the force and distance vectors, which is 0 degrees since the force is acting vertically upward and the distance is upward as well. Thus, we have
work = 12 N x 1.5 m x cos(0) = 18 J
To calculate the power output of the student, we use the formula:
power = work / time
where work is the work done by the student on the textbook, and time is the total time it took to lift and carry the book. Thus, we have:
time = 1.5 s + 7 s = 8.5 s
power = 18 J / 8.5 s = 2.12 W
Therefore, the student did 18 J of work on the textbook, and had a power output of 2.12 W.
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--The given question is incomplete, the complete question is given
" a student lifts a 12 N textbook 1.5 m in 1.5 s and carries the books 5 m across the room in 7 s. how much work does the student do on the textbook? and what is the power output of the student."--
Four drivers recorded the distance they drove each day for a week. Which driver's data set has a mode that is greater than the mean or median AND a median with the lowest value of the three measures?
a
Kadisha: 8, 17, 23, 16, 17, 18, 125
b
Cole: 14, 26, 34, 22, 47, 22, 45
c
Fabian: 7, 12, 11, 23, 13, 23, 30
d
Ling: 52, 36, 41, 31, 31, 37, 59
Driver's data set that has a mode that is greater than the mean or median is Fabian and a median with the lowest value of the three measures is Kadisha.
Data of Fabian: 7, 12, 11, 23, 13, 23, 30
Mean = sum of all observation / total no. of observation
Mean = (7+ 12+ 11+ 23+ 13+ 23+ 30) / 7
Mean = 17
Mode = most repeating observation
Mode = 23
For median we have to write observation in ascending order
7,11,12,13,23,23,30
Median = (N+1)/2
Where N = No. of observation
Median = (7+1)/2
Median = 4th observation
Median = 13
Here mode that is greater than the mean or median.
similarly for,
Kadisha: 8, 17, 23, 16, 17, 18, 125
Mean = 32
Median = 17
Mode = 17
Here median with the lowest value of the three measures.
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Here is the information about 30 students in a class
18 of the students do not walk to school
Three quarters of the students who walk to school are boys
There are 6 more girls than boys who do not walk to school
Use the information to fill in the missing numbers in this table
Number who walk to school Number who do not walk to school Total
Number of Boys
Number of Girls
Total 12 18 30
Answer:
Step-by-step explanation:
18 students don't walk to school
6 boys, 12 girls
12 students walk to school (30-18)
3/4 of students who walk to school are boys = 9 boys, 3 girls
Four levels, coded as −3, −1, 1, and 3 were chosen for each of two variables X1 and X2, to provide a total of sixteen experimental conditions when all possible combinations (X1,X2) were taken. It was decided to use the resulting sixteen observations to fit a regression equation including a constant term, all possible first-order, second-order, third-order and fourth-order terms in X1 and X2. The data were fed into a computer routine which ususlly obtains a vector estimate b = (X X) −1X Y The computer refused to obtain the estimates. Why? The experimenter, who had meanwhile examined the data, decided at this stage to ignore the levels of variable X2 and fit a fourth-order model in
"The computer refused to obtain the estimates because of perfect multicollinearity caused by including all possible fourth-order terms in the regression model."
Perfect multicollinearity occurs when there is an exact linear relationship between predictor variables in a regression model. In this case, including all possible fourth-order terms in X1 and X2 resulted in perfect multicollinearity.
When there is perfect multicollinearity, it becomes impossible to calculate the regression estimates using the standard formula, as the matrix (X'X)^-1 does not exist. The presence of perfect multicollinearity creates redundancy and ambiguity in the model, making it impossible for the computer routine to obtain valid estimates.
To address this issue, the experimenter decided to ignore the levels of variable X2 and fit a fourth-order model solely in X1. By focusing on one variable and excluding the other, the problem of perfect multicollinearity was resolved, and the regression model could be estimated successfully.
In conclusion, the computer refused to obtain the estimates due to perfect multicollinearity caused by including all possible fourth-order terms in the regression model. Ignoring one variable helped overcome the issue and allowed the experimenter to fit the desired fourth-order model.
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