Part A: Is it possible to make a triangle that is both equilateral triangle and a right triangle? Explain









Part B: Is it possible to draw a triangle with side lengths of 15, 15 and 20? Explain.

Spinner B is the spinner that has a probability of 1/3 of spinning orange.

a) For one of the spinners, the probability of spinning orange is 1/3. To identify which spinner this is, we need to find the spinner that has exactly one orange sector out of three total sectors.

From the given spinners, Spinner B is the only spinner that has one orange sector out of three, so Spinner B is the spinner that has a probability of 1/3 of spinning orange.

b) For two of the spinners, the probability of spinning orange is more than 40%. To find these spinners, we need to look for the spinners that have at least three orange sectors out of a total of eight sectors (since 3/8 is greater than 40%).

From the given spinners, Spinner A and Spinner C both have three orange sectors out of eight total sectors, so they are the two spinners for which the probability of spinning orange is more than 40%.

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Answer: y = (9/5)x + 5.

Step-by-step explanation:

The slope of the given line is -5/9. The slope of a line perpendicular to it would be the negative reciprocal of -5/9, which is 9/5. Using the point-slope form of a line, we can write the equation of the line as y - (-4) = (9/5)(x - (-5)). Simplifying this equation gives y + 4 = (9/5)x + 9. Solving for y, we get y = (9/5)x + 5. This is the equation of the line in slope-intercept form.

In summary, the equation of a line perpendicular to y = −5/9x + 4 and that passes through point (-5,-4) is y = (9/5)x + 5.

Answer:

P = 4/13 = 0.308

Step-by-step explanation:

3 cards 3

13 spade cards (includes the card 3 of spades)

[tex]P=(3+13)/52= 16/52 = 4/13=0.308[/tex]

Hope this helps.

Note that the limit of the expression as x approaches infinity is 1/2.

start by multiplying both the numerator and denominator by the conjugate  expression

√ (x ² - 9x + 1) + x,

this will eliminates the root in the numerator

lim x->∞ [(√(x ² - 9x + 1) - x)  * (√(x² - 9x + 1) + x)] / (√(x² - 9x + 1) + x)

Expanding the numerator

lim x- >∞ [(x² - 9x + 1) - x^2] / (√(x² - 9x + 1) + x)

Simplifying further:

lim x->∞ [(1 - 9/x + 1/ x²)] / (√(1 - 9/x + 1 /x²) + 1)

we can see that the 1/x ² term approaches zero, and the expression simplifies to

lim x->∞ [(1 - 0)]  / (√(1 - 0) + 1)

= 1/2

So it is correct to state that the limit of the expression as x approaches infinity is 1/2.

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Answer:

2y - 3> 9 it is not y + 6< 10

Answer:

  (x -2)(x -4)

Step-by-step explanation:

You want to factor x² - 4x -2x +8.

We recognize that the product of the coefficients of the two linear terms is equal to the contant, so this is more easily factored by not combining like terms prior to factoring.

Grouping the terms in pairs, we find we can factor each pair:

  (x² -4x) + (-2x +8)

  = x(x -4) -2(x -4) . . . . . these terms have a common factor of (x -4)

  = (x -2)(x -4) . . . . . . . factored form of the expression

Real-estate agent tested the effect of staging on home sale prices. Out of 10 comparable homes, 5 were staged. Staged homes sold for $15k more on average, with no skewness or outliers.

Based on the information given, the real-estate agent conducted an experiment to test the effect of selling a staged home vs. selling an empty home.

The hypothesis is that empty homes sell for lower prices than staged homes. The agent randomly assigned 5 empty homes to be staged and obtained a list of 10 comparable homes.

The mean selling price of the 5 empty homes was $150,000 with a standard deviation of $22,000. The mean selling price of the 5 staged homes was $175,000 with a standard deviation of 35,000. There was no strong skewness or outliers in the dot plots of the two samples.

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The circled portion in the confidence interval formula p ± z represents the Margin of Error, which plays a crucial role in interpreting the range of plausible values for the population parameter.

In the confidence interval formula p ± z, the circled portion represents the Margin of Error.

The Margin of Error is a critical component of a confidence interval and quantifies the level of uncertainty in the estimate.

It indicates the range within which the true population parameter is likely to fall based on the sample data.

The Margin of Error is calculated by multiplying the critical value (z) by the standard deviation of the sampling distribution.

The critical value is determined based on the desired level of confidence, often denoted as (1 - α), where α is the significance level or the probability of making a Type I error.

The Margin of Error accounts for the variability in the sample and provides a measure of the precision of the estimate.

It reflects the trade-off between the desired level of confidence and the width of the interval.

A larger Margin of Error indicates a wider confidence interval, implying less precision and more uncertainty in the estimate.

Conversely, a smaller Margin of Error leads to a narrower confidence interval, indicating higher precision and greater certainty in the estimate.

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The value of the given functions are:

(a) (f + g)(x) = (x -8 + 14) = x + 6

(b) (f-g)(x) = (x -8 - 14) = x - 22

(c) (f • g)(x) = (x - 8 (14)) = 14x - 112

(d) (f/g)(x) = (x - 8)/ 14

An expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

We have the functions are as follows:

f(x)=x - 8,

g(x)=5 + 9

To solve :

a. (f + g)(x),

b. (f-g)(x),

c. (f • g)(x), and

d. (f/g)(x)

Now,

(a) (f + g)(x) = (x -8 + 14) = x + 6

(b) (f-g)(x) = (x -8 - 14) = x - 22

(c) (f • g)(x) = (x - 8 (14)) = 14x - 112

(d) (f/g)(x) = (x - 8)/ 14

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The given question is incomplete, complete question is:

For the functions f and g find a. (f+ g)(x), b. (f-g)(x), c. (f• g)(x), and d. (f/g)(x) f(x)=x - 8, g(x)=5 + 9

The amount that will be in Andy's account in 2 years after the addition of interest is $112.36

Andy has $100 in an account

An interest rate of 6% is compounded annually

The amount that will be present in the account after 2 years can be calculated as follows

= 100(1+ 6/100)²

= 100(1 + 0.06)²

= 100(1.06)²

= 100(1.1236)

= 112.36

Hence the amount that will be present in the account after 2 years with the addition of interest is $112.36

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Answer:

A.

circular: ≈ 795.77 square feet

square: 625

Step-by-step explanation:

the circular pen would have a larger area.

Solving for the radius, we have:

r = 100 / (2 × 3.14) = 15.92 feet (rounded to two decimal places)

Therefore, the area of the circular pen would be:

Area = πr^2 = 3.14 × (15.92 ft)^2 ≈ 795.77 square feet

For a square pen with side length s, the perimeter is given by:

4s = 100

s = 25

The area of a square pen with side length s is given by:

A = s^2 = 25^2 = 625

(a) The domain of f of g is {1, 8}.

(b) The range of f of g is {0, 1}.

The domain of f of g consists of all the inputs in the domain of g that are also in the domain of f.

(a) Domain of f of g:

The inputs in the domain of g that are also in the domain of f are 1, and 8. Therefore, the domain of f of g is {1, 8}.

To find the range of f of g, we need to apply the function composition f(g(x)) to each input in the domain of f of g, and collect all the outputs.

(b) Range of f of g:

The range of f of g consists of all the outputs obtained by applying f(g(x)) to each input in the domain of f of g.

We have:

f(g(1)) = f(8) = 0

f(g(4)) = f(2) = 1

f(g(8)) = f(0) = 1

Therefore, the range of f of g is {0, 1}.

Thus, in set notation, the domain of f of g is {1, 8}, and the range of f of g is {0, 1}.

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Answer:

(-9, 6) This ordered pair is used to find the function value f(-9)=6

or the given function​ value, write a corresponding ordered pair.

Step-by-step explanation:

For the given function​ value, write a corresponding ordered pair.

f(-9) = 6

The ordered pair of each function can be written as (x,y).

For any function, for example, g(x)= 10x, the input is x, and the output y is 10x. So ordered pair is (x,10x)

The given function value is: f(-9) = 6

Here input x=-9 and y value is 6

So, he corresponding ordered pair is (-9, 6)

The vertical shift and vertical shrink of the exponential function are 2 and 1/2 respectively and the graph of the function is attached below

An exponential function is defined by the formula f(x) = ax, where the input variable x occurs as an exponent. The exponential curve depends on the exponential function and it depends on the value of the x.

The vertical shift and vertical shrink of the function f(x) = 1/2(4 - eˣ) are 2 and 1/2

The vertical shift = 2

vertical shrink = 1/2

Kindly find the attached graph below

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After Cami cut 17¹/₂ inches of a rope that was 50 inches long, the length of the remaining rope in inches, written in decimal form, is 32.5 inches.

To determine the remaining length of the rope, we apply subtraction operation.

However, since the cut rope was expressed in fractions, we can convert it to decimals before the subtraction.

The total length of the rope = 50 inches

The cut portion of the rope = 17¹/₂ inches

The remaining portion = 32¹/₂ inches or 32.5 inches (50 - 17¹/₂)

Thus, the remaining portion of the rope after Cami cut 17¹/₂ inches is 32.5 inches.

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The measure of angle subtended by the arc EB is 96 ⁰.

The measure of angle subtended by the arc EB is calculated by applying the following formula.

Based on the angle of intersecting chord theorem, the theory states that, the angle formed by the intersection of two chords at the circumference of a circle is equal to half of the difference between the arc angles of the two chords.

We will have the following equation;

m∠ECB = ¹/₂( 7x + 6 - (4x + 16))

25 x 2 = 7x + 6 - 4x - 16

50 = 3x - 10

60 = 3x

x = 60/3

x = 20

The measure of arc angle EB is calculated as follows;

m∠EB = 4x + 16

m∠EB = 4(20) + 16

m∠EB = 96 ⁰

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a. Using Taylor series d(x³eˣ²)/dx about x = 0 is  x⁴.

b. Using Taylor series d⁷(x³eˣ²)/dx⁷ about x = 0 is  x¹⁰.

A Taylor series is a polynomial expansion of a function about a given point. It is given by f(x - a) = ∑(x - a)ⁿfⁿ(x - a)/n! where

Given that the Taylor series of the function f(x) = x³eˣ² about x = 0 is

f(x) = x³ + x⁵ + x⁷/2! + x⁹/3! + x¹¹/4!, (1) we proceed to find the given variables

a. To find d( x³eˣ²)/dx about x = 0, the Taylor series expansion about x = 0 is given by

f(x - a) = ∑(x - a)ⁿfⁿ(a)/n!

f(x - 0) = ∑(x - 0)ⁿf(0)/n!

f(x) = ∑xⁿf(0)/n!

f(x) = x⁰f(x)/0! + xf(x)/1! + x²f(x)/2! + x³f(x)/3! + ....

f(x) = f(x) + xf¹(x) + x²f²(x)/2! + x³f³(x)/3! + ....(2)

Since fⁿ(x) is the nth derivative of f(x), and we desire f¹(x) which is the first derivative of f(x). Comparing equations (1) and (2), we have that

x⁵ =  xf¹(x)

f¹(x) =  x⁵/x

= x⁴

So, d( x³eˣ²)/dx about x = 0 is  x⁴.

b. To find d⁷( x³eˣ²)/dx⁷ about x = 0, the Taylor series expansion about x = 0 is given by

f(x - a) = ∑(x - a)ⁿfⁿ(a)/n!

f(x - 0) = ∑(x - 0)ⁿf(0)/n!

f(x) = ∑xⁿf(0)/n!

f(x) = x⁰f(x)/0! + xf(x)/1! + x²f(x)/2! + x³f(x)/3! + ....

Expanding it up to the 8 th term, we have that

f(x) = f(x) + xf¹(x) + x²f²(x)/2! + x³f³(x)/3! + x⁴f⁴(x)/4! + x⁵f⁵(x)/5! + x⁶f⁶(x)/6!  + x⁷f⁷(x)/7!.....(3)

Now expanding equation (1) above to the 8th term by following the pattern, we have that

f(x) =   x³ + x⁵ + x⁷/2! + x⁹/3! + x¹¹/4! + x¹³/5! + x¹⁵/6!  + x¹⁷/7!.....(4)

Since fⁿ(x) is the nth derivative of f(x), and we desire f⁷(x) which is the seventh derivative of f(x). Comparing equations (3) and (4), we have that

x⁷f⁷(x)/7! = x¹⁷/7!  

f⁷(x) =  x¹⁷/x⁷

= x¹⁰

So, d⁷( x³eˣ²)/dx⁷ about x = 0 is  x¹⁰.

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The height and radius that minimize the amount of material needed to manufacture the can are both approximately 6.39 cm.

The total surface area of the can is therefore:

A = 2πr² + 2πrh

We know that the volume of the can is 810 cm³, which is given by:

V = πr²h

We can solve this equation for h to get:

h = V/(πr²)

Substituting this expression for height h into the equation for the surface area, we get:

A = 2πr² + 2πr(V/(πr²))

Simplifying, we get:

A = 2πr² + 2V/r

Now we have an equation for the surface area of the can in terms of the radius, r.

To minimize the surface area, we need to take the derivative of this equation with respect to r, set it equal to zero, and solve for r.

dA/dr = 4πr - 2V/r² = 0

Solving for radius r, we get:

[tex]r = (810/\pi)^1^/^3[/tex]

r=∛810/3.14

r=6.35 cm

Now find h:

h = 810/πr²

h=810/3.14×6.35²

h=810/126.6

h=6.39 cm

Hence, the height and radius that minimize the amount of material needed to manufacture the can are both approximately 6.39 cm.

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The answer choice which correctly represents the value of cos B as required is;  Cosine B = StartFraction 40 Over 41 EndFraction.

Therefore Choice B is correct

The law of cosines relates the lengths of the sides of a triangle to the cosine of one of its angles and it states that the square of the length of any side of a given triangle is equal to the sum of the squares of the length of the other sides minus twice the product of the other two sides multiplied by the cosine of angle included between them.

we know that from the trigonometric ratios that the cosine of an angle is the ratio of its opposite and hypothenuse.

Hence, we can say that:

cos B = 80 / 82

cos B = 40 / 41.

Inn conclusion, the cosine of angle B following from trigonometric ratios as requested is; cos B = 40 / 41.

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#complete question:

Evaluate the function requested. Write your answer as a fraction in lowest terms.

Triangle A B C. Angle C is 90 degrees. Hypotenuse A B is 82, adjacent B C is 18, opposite A C is 80.

Find cos B.

a.

Cosine B = StartFraction 9 Over 41 EndFraction

c.

Cosine B = StartFraction 9 Over 40 EndFraction

b.

Cosine B = StartFraction 40 Over 41 EndFraction

d.

Cosine B = StartFraction 41 Over 40 EndFraction

Answer: I did not do the math, I just tell people how to do it

Hope I helped.

Step-by-step explanation:

Multiply the number of triangles you created by 180.

Answer:

  a) 2:15 pm

  b) 240 km

Step-by-step explanation:

You want to know the time and place where a car leaving at 11:15 a.m. at 80 km/h catches up with a van leaving at 10:30 a.m. at 64 km/h.

The van travels for 11:15 -10:30 = :45, or 3/4 hour, before the car starts. This gives it a distance advantage of (3/4 h)(64 km/h) = 48 km.

The speed at which that distance is reduced is the difference between the car speed and the van speed:

  80 km/h -64 km/h = 16 km/h

The time it takes for the head-start distance to be reduced to zero is ...

  time = distance/speed

  time = (48 km)/(16 km/h) = 3 h

Three hours after the car leaves, it will catch up with the van. That time is ...   11:15 +3:00 = 14:15 = 2:15 p.m.

In 3 hours, the car travels (3 h)(80 km/h) = 240 km.

Note that the van has been traveling 3 3/4 hours, so will have also traveled (3 3/4 h)(64 km/h) = 240 km. The two vehicles need to be in the same place at the same time if they are to pass each other.

__

Additional comment

The attached graph shows the two vehicles will have traveled 240 km when they mean at 2:15 pm. The horizontal axis is hours after midnight. The vertical axis is kilometers from town X. The relation graphed is distance = speed × time.

Answer:

5.2 seconds

Step-by-step explanation:

To get one foot, we need to divide by 5.5

Set up a proportion:

[tex]\frac{5.5}{5.5}=\frac{28.6}{5.5}[/tex]

Solve:

[tex]1ft.=5.2secs.[/tex]

The probability that a randomly decided piece of cake maybe chocolate is 1/2 or half of or 0.

The proportion of chocolate cakes to all other cakes can be used to calculate the probability that a person will pick a chocolate cake from the pattern tray.

In this case, there are 3 chocolate cakes out of a total of 6 cakes.

So the probability of selecting a chocolate cake is:

3/6 = 1/2 (Dividing the numerator and denominator by their greatest common factor, in this case, 3 will simplify the fraction 3/6.)

Therefore, the probability of selecting a chocolate cake is 1/2 or 0.5 when expressed as a decimal.

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The solution of the inequality given is b < 64

the graph is attached

In the equation, let us replace b with x

To solve the inequality x/8 < 8 for x, we need to isolate x on one side of the inequality.

We can do this by multiplying both sides of the inequality by 8, which will cancel out the 8 in the denominator on the left side:

Therefore, the solution to the inequality x/8 < 8 is x < 64.

This means that any value of x that is less than 64 will make the inequality true.

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Answer: C {m | m  > 2}

Step-by-step explanation:

write the number in exponential form with the base of 2

2^3m-4 > 2^2

compare the exponents = 3m-4 >2

move the constant to the right and then change the sign

3m> 2+4  add

3m>6 divide

m>2

The equivalent value of the expression is y = + 3/5 and y = -3/5

Given data ,

Let the expression be represented as A

Now , the value of A is

y = ±3/5

On simplifying the equation , we get

y = +3/5

And, y = -3/5

Now , the decimal values of y are

y = ±0.6

Hence , the expression is y = ±0.6

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Note that  the following probability as a simplified fraction and as a decimal is:  0.88617886178 and 109/123

Note that the key phrase here is “given that this person is a man.”

This means that all we are interested in is the row labeled Male.

           Married      Never      Div       Widowed    Total

Male    69                  40       11                   3           123    

We are asked to find the probability that the person was either Married or Never. So the fraction you want is (69 + 40) / 123.

⇒ (69 + 40) / 123.

⇒ 109/123

or 0.886179

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Full Question:

Although part of your question is missing, you might be referring to this full question:

Express the following probability as a simplified fraction and a decimal.

if one person is selected from the population described in the table, find the probability that the person has never been married or is married, given that this person is a man.

  Married  Never Married  Divorced   Widowed   Total

Male    69    40     11     3     123

Female  67    33     20     5     125

Total    136    73     31     8     248

Question 1.Express the probability as a simplified fraction

Check the picture below.

The result of adding -3 (row 1) to row 2 is determined as (0  10) |-14.

The resultant of the row multiplication in the Matrice is calculated by applying the following method;

row 1 in the given matrices = [1  -4] | 8

To multiply row1 by -3, we will multiply each entity by 3 as shown below;

= -3(1  -4) | 8

= (-3  12) | -24

To add the result to 3;

(-3  12) | -24  +  (3   -2)|10

= (0  10) |-14

Thus, the result of the row multiplication is determined by multiplying each entry in row 1, by - 3.

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Hence Option A. 22 is correct.

Of the students in the maths club , 67% are not in the literature club.

So the number of students in Maths club =

[ ( Number of students in maths club but not in the literature club) / 67 ] * 100 % = [ 16 / 67 ] * 100% = 24 (Rounded)

Hence, Number of students in maths club and in the literature club =

x = Total Number of students in Maths club - Number of students in maths club but not in the literature club

x = 24 - 16 = 8

Of the students not in the maths club , 78% are not in the in the literature club.

So, Of the students not in the maths club , 100% - 78% = 22% are in the literature club.

So the number of students not in the Maths club =

[ ( Number of students not in the maths club and in the literature club) / 22 ] * 100 %

= [ 4 / 22 ] * 100% = 18.18 = 18 (Rounded)

Hence, Number of students not in the maths club and not in the literature club =

y = Total Number of students not in the Maths club - Number of students not in the maths club and in the literature club

y = 18 - 4 = 14

So, x + y = 8 + 14 = 22.

Hence Option A. 22 is correct.

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