Tim earns 96pounds for 16 hours. Tim earns 'time and a half' for overtime. he works 4 hours of overtime in addition to his normal 16 hours. how much does he earn altogether​

Answer:

all real numbers

Step-by-step explanation:

the answer is all real numbers.

we know this since if you plug in any value for x we will get a real number.

hope this helps

Answer:

200 Bricks

Step-by-step explanation:

1/3 of the bricks were not used(which was 50 bricks), meaning that 3/3 is 150 bricks of the pile. Since 150 is 3/4 of the original pile, that means that there was 200 bricks at the beginning.

Answer:

B.

Step-by-step explanation:

Question 1

We want to choose a white marble, then a black marble.

Multiplying these probabilities, we get (9/24)(8/24) = 1/8.

Question 2

Thus, the probability is 5/10 = 1/2.

Question 3

Multiplying these probabilities, we get (7/24)(9/23) = 21/184.

Answer:

x = 7/2

Step-by-step explanation:

1/5 (10x+30)-14= - 1/3 (6x-18)

10x + 30/5 - 14 = -6x + 18/3

(2*5)x+2*3*5/5-14 = -(2*3)x-2*3^2/3

x = 7/2

Answer:

-300

Step-by-step explanation:

113-413=-300

Answer:

3

Step-by-step explanation:

Slope of a line between any two points (x1,y1) and (x2,y2) is given by the equation:
[tex]\frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]

let's take (x1,y1) as (4,4) and (x2,y2) as (5,7)

So slope = [tex]\frac{7-4}{5-4}[/tex] = 3

Answer:

y = 3x - 8

Step-by-step explanation:

y = Mx + c

m = 3 / 1

4 = 3(4) + c

4 - 12 = c

Answer:

True

Step-by-step explanation:

-77 is less than -76. Since the symbol refers to less than or equal to, this statement will be true.

In consecuence, the conjugate complex number x₂ = (- 5 + i √3)/2 is one of the three roots of the cubic equation f(x) = x³ + 6 · x² + 12 · x + 7. (Correct choice: D)

In this case we have a cubic equation, that is, a third order polynomial. There are two strategies to determine the roots of cubic equations: (i) Cardano's formula, (ii) Numerical methods.

The quickest though most effective way consists in determining the roots by numerical methods (i.e. Newton-Raphson method). By using numerical methods we conclude that the cubic equation f(x) = x³ + 6 · x² + 12 · x + 7

x₁ = - 1, x₂ = (- 5 + i √3)/2, x₃ = (- 5 - i √3)/2

In consecuence, the conjugate complex number x₂ = (- 5 + i √3)/2 is one of the three roots of the cubic equation f(x) = x³ + 6 · x² + 12 · x + 7. (Correct choice: D)

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The equation of the line with points (2,10) and (0,0) is: y = 5x.

The line given has two points which are stated as:

(2,10) and (0,0).

Find the slope(m):

Slope (m) = change in y / change in x = (10 - 0)/(2 - 0)

Slope (m) = 10/2

Slope (m) = 5

The y-intercept (b) = 0

Substitute m = 5 and b = 0 into y = mx + b

y = 5x + 0

y = 5x

The equation of the line is: y = 5x.

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Answer:

  145 square inches

Step-by-step explanation:

The surface area of a square pyramid can be found using the formula ...

  A = s(s +2h) . . . . . where s is the base side length, and h is the slant height

__

Using this formula with s=5 inches and h=12 inches, we find the area to be ...

  A = (5 in)(5 in +2(12 in)) = (5 in)(29 in) = 145 in²

The area of the pyramid is 145 square inches.

_____

Additional comment

This formula comes from the sum of the areas of the square base (s²) and the four triangular faces (4 × 1/2sh). That sum is ...

  A = s² +2sh = s(s +2h)

If the volume of a cylinder is multiplied by 4/3, it would become the volume of a sphere. Thus, you're a sphere.

Mathematically, the volume of a cone can be calculated by using this formula:

V = 1/3 × πr²h

Where:

Mathematically, the volume of a sphere can be calculated by using this formula:

V = 4/3 × πr³

Similarly, the volume of a cylinder can be calculated by using this formula:

V = πr²h

In this context, we can infer and logically deduce that if the volume of a cylinder is multiplied by 4/3, it would become the volume of a sphere. Also, multiplying the volume of a cylinder by 1/3 would produce the volume of a sphere.

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Answer:

For section A, the average rate of change is 12. For section B, the average rate of change is 300. The average rate of change in Section B is greater than Section A by 25. The rate of change keeps on increasing because the slope of the function is increasing.

Step-by-step explanation:

Concept: For a function f(x), the rate of change is given by [tex]\frac{f(x_{2})-f(x_{1}) }{x_{2}-x_{1} }[/tex]. Given function is h(x) = 3(5∧x).

For x = 0 to x = 1, the value of function would be f(0) = 3 to f(1) = 15.

The rate of change would be (15-3) / (1-0) = 12.

For x = 2 to x = 3, the value of function would be f(2) = 75 to f(3) = 375.

The rate of change would be (375-75) / (3-2) = 300.

The average rate of change in Section B is greater than Section A by

300 / 12 = 25.

Looking at the function, that is h(x) = 3(5∧x), we see that this function is an increasing function. The slope of an increasing function keeps on increasing with the value of x. The rate of increase is also a slope. That is why the rate keeps on increasing.

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Answer:

x=12

Step-by-step explanation:

Given that there is only one expression given in each triangle, if we only use the information in a single triangle, there is no way to set up an equation that we could solve to find the expression.  (For this situation, at best we could use the triangle sum theorem to say that the three angles in one triangle added to 180°, but since we don't know the other two angles, that's 3 unknowns with only 1 equation... that's not solvable)

The only way to solve this problem is to make a relationship of some sort between the two triangles.

Proving a relationship between triangles - option 1

You may have a theorem about the Third angles of two triangles... "Given two arbitrary triangles, [tex]\triangle ABC[/tex] and [tex]\triangle D E F[/tex], if [tex]\angle A \cong \angle D[/tex] and [tex]\angle B \cong \angle E[/tex],  then [tex]\angle C \cong \angle F[/tex] "

If you have this, then the third angles are congruent.

In a more general situation of a similar problem (one in which you don't know two of the angles to begin with), it might be easier to prove triangle congruence, or triangle similarity.

Other Relationships between triangles

There are two main relationships between triangles: similarity and congruence.

Most people learn about congruence first.

In the situation for this problem, the two triangles happen to be congruent (we'll prove it shortly), which implies that all corresponding angles between shapes are congruent (and all corresponding sides between shapes are congruent).

For the purpose of solving for things related to angles, proving that the two triangles are similar is enough to know that angles between triangles are congruent (sides wouldn't necessarily be equal, but would be proportional, and since we're not solving for anything related to side lengths, proving that the triangles are similar would be enough).

Proving a relationship between triangles - option 2 - congruence

Notice that the triangle on top has two angles with markings (a single mark, and a double mark), and one side with a marking (a single tick).  These three pieces are in a configuration of ASA (the side is between the two angles).

Looking at the bottom triangle, it also has angles and sides with corresponding markings, and they are also in an ASA configuration.

Thus, by ASA congruence, these triangles are congruent triangles.

Knowing the triangles are congruent (even though we only used 3 parts), the rest of the corresponding parts (including the third angles) are also congruent.

Proving a relationship between triangles - option 3 - Similarity

For similarity, the process is similar to proving congruence, however the theorems we have for proving similarity are different.

SSS, SAS, or AA similarity.

Since the triangles in our problem do have two angles that are congruent, by AA similarity, the triangles are "similar".

Knowing the triangles are similar (even though we only used 2 parts), the last set of corresponding angles are also congruent.

Building our equation

Since the third angle of each triangle is congruent, by definition of congruent angles, the measures of each of those two angles are equal, and so we can build an equation knowing that the two expressions are equal to each other:

[tex]3x-7=2x+5[/tex]

Solving for x

From there, we need some algebraic properties equality to solve for x.

Subtract 2x from both sides...

[tex](3x-7)-2x=(2x+5)-2x\\x-7=5[/tex]

add 7 to both sides...

[tex](x-7)+7=(5)+7\\x=12[/tex]

Extension

Knowing the value for x, we could solve for the measure of the angles, if that had been requested.  Simply substitute 12 back into the expressions for the angle measure (the results should be the same for both angles, since they were congruent angles)

[tex]3(12)-7\\36-7\\29[/tex]         [tex]2(12)+5\\24+5\\29[/tex]

So, if we had been asked, the measure of the angle is 29°

Answer:

200 sqin.

Step-by-step explanation:

10 x 10 + 10 x 10 = 100 + 100
                          = 200

Answer:

x = +1

x = -1

Step-by-step explanation:

x^4-1=0​

x^4=+1​

fourth root of x^4= fourth root of +1​

x = +1

x = -1

Considering a line of best-fit, the approximate number of hours in 72 days on Saturn is given by 768.

To find the equation, we need to insert the points (x,y) in the calculator.

In this problem, the points are:

(266.67, 25), (373.3, 35), (426.67, 40), (586.67, 55).

Using a calculator, the equation is:

y = 0.09375x + 0.00003455.

For 72 days, we have that y = 72, hence the number of hours is x.

y = 0.09375x + 0.00003455.

72 = 0.09375x + 0.00003455.

x = (72 - 0.00003455)/0.09375

x = 768 hours.

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Answer:

[tex]y=\dfrac{5}{4}x^3+10[/tex]

Step-by-step explanation:

Given information:

Create two equations by substituting the given points into the given equation:

Equation 1:  point (0, 10)

[tex]\implies a(0)^3+d=10[/tex]

[tex]\implies 0+d=10[/tex]

[tex]\implies d=10[/tex]

Equation 2:  point (2, 20)

[tex]\implies a(2)^3+d=20[/tex]

[tex]\implies 8a+d=20[/tex]

Substitute Equation 1 into Equation 2 and solve for a:

[tex]\implies 8a+d=20[/tex]

[tex]\implies 8a+10=20[/tex]

[tex]\implies 8a+10-10=20-10[/tex]

[tex]\implies 8a=10[/tex]

[tex]\implies \dfrac{8a}{8}=\dfrac{10}{8}[/tex]

[tex]\implies a=\dfrac{10}{8}[/tex]

[tex]\implies a=\dfrac{5}{4}[/tex]

Finally, substitute the found values of a and d into the original formula:

[tex]\implies y=\dfrac{5}{4}x^3+10[/tex]

Check by substituting the x-values of the two given points into the found equation:

[tex]x=0 \implies y=\dfrac{5}{4}(0)^3+10=10 \leftarrow \textsf{correct}[/tex]

[tex]x=2 \implies y=\dfrac{5}{4}(2)^3+10=20 \leftarrow \textsf{correct}[/tex]

Put(0,10)

Now

Put again (2,20) this time

Answer: y = -3/2x + 6, y intercept is (0, 6)

Step-by-step explanation: You are dividing 2 from both -3x and 12. -3/2x cannot be simplified any further unless it's a decimal, so we leave it as -3/2x. But, since the equation was y = -3x+12 originally, we divide 12 from 2 as well and not just from 3x, and we get 6.

Hope this helped.

The correct answer is the last choice .

The parent quadratic function is f(x) = x² it's just like the image above .

if you look at the graph horizontal translation has happened two units to right , it means we have -2 inside a bracket next to x , then vertical translation has happened 4 units to up it means we have +4 outside the bracket and after x

there's also a reflection on the graph which means there's a negative before the bracket .

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∠2 and ∠4 are vertical opposite angles and they are congruent.

Vertically opposite angles are congruent.

Therefore, let proof ∠2 and ∠4 are vertical angles

Hence,

m∠2 + m∠3 = 180

∠2 and ∠3  are linear pair.

m∠3 + m∠4 = 180

∠3 and ∠4  are linear pair.

∠2 and ∠4 are vertical angles

m∠2 + m∠3 = m∠3 + m∠4

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Answer: View picture below!

Step-by-step explanation: Just did it!

Part 1

[tex](g\circ h)(x)=g(x-4)=(x-4)^2 + 1=x^2 - 8x+16+1=\boxed{x^2 - 8x+17}[/tex]

Part 2

[tex](-\infty, \infty)[/tex]

The answers in the box are:

Given that the functions are

[tex]g(x)=x^2+1[/tex]

[tex]h(x)=x-4[/tex]

Since clearly g(x) and h(x) exist for all real values of x so the domain of g(x) and h(x) both are all real numbers.

Now the composition of function is given by,

[tex](g\circ h)(x)=g(h(x))[/tex]

               [tex]=g(x-4)[/tex]

               [tex]=(x-4)^2+1[/tex]

               [tex]=x^2-8x+16+1[/tex], since we know that [tex](a-b)^2=a^2-2ab+b^2[/tex]

               [tex]=x^2-8x+17[/tex]

So, [tex](g\circ h)(x)=x^2-8x+17[/tex]

It is a polynomial function so it is defined for all real values of x.

Hence the domain of composition is all real numbers, that is [tex](-\infty,\infty)[/tex]

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The solutions to the quadratic equation 50 - x² = 0 are x = ±5√2.

A quadratic equation is a second-order polynomial equation in a single variable x , ax2+bx+c=0. with a ≠ 0 .

The solution(s) to the quadratic equation 50 - x² = 0 can be found by setting the equation equal to zero and solving for x.

50 - x² = 0

To solve this equation, we can rearrange it as follows:

x² = 50

Taking the square root of both sides, we have:

x = ±√50

Simplifying the square root of 50, we get:

x = ±√(25 × 2)

x = ±√25 × √2

x = ±5√2

Therefore, the solutions to the quadratic equation 50 - x² = 0 are x = ±5√2.

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Answer:

6/x2

Step-by-step explanation:

Answer:

[tex]\mathsf {\frac{6}{x^{2}}}[/tex]

Step-by-step explanation:

[tex]\mathsf {\frac{2}{x^{2}} + \frac{4}{x^{2}} }[/tex]

[tex]\mathsf {\frac{2+4}{x^{2}}}[/tex]

[tex]\mathsf {\frac{6}{x^{2}}}[/tex]