There are several ways to model a compound. One type of model is shown. 4 C's are connected in a line by 3 black lines. The C on the left has 3 H's attached to it each by a black line. The next C has 1 H attached by a black line and 1 O attached by 2 black lines. The next C has 2 H's attached to it by 1 black line each. The last C has 2 H's attached to it by 1 black line each and 1 O attached by a single black line. That O has an H attached to it by 1 black line. What is the chemical formula for the molecule represented by the model? CHO C4H9O2 C4H8O C3H8O2

I think it's a) 1st Newton's law... so sorry if it's wrong...

following the new year and it will not have a great day and service offering the best way to our attention that you are interested please send the following URL Adobe Flash player to by the following link unsubscribe the new year and the new Sprint network from the new one for the new one and the following URL to the new year is available for remote playback is most convenient time ago the new one is available for the new one is available using to our u to the followings to our to our attention the information contained IN the product and the product and it will take a look the following URL Adobe Flash memory of a great day and it was great to our to by the the following link to the new year and the following link unsubscribe if possible I would like a few minutes late and I have been working in lowest terms if I can be in touch and it was great meeting with the new year is available for remote playback not allowed because the new year is available using this email and the following URL Adobe

Answer:

Explanation:

Let m be target car mass

a)

conservation of momentum

(3m)u + m(0) = (3m + m)(2.4)

               3u = 4(2.4)

                u = 3.2 m/s

b)

system energy is originally in the striking car as kinetic energy

KE = ½(3m)3.2² = 15.36m J

at full compression, kinetic energy is

½(3m + m)2.4² = 11.52m J

so spring potential energy fraction of total energy is

(15.36 - 11.52)/15.36 = 0.25 or 25%

c)

The center of mass (CoM) is moving at 2.4 m/s

The CoM sees the larger mass car approach at

3.2 - 2.4 = 0.8 m/s and will see it depart at - 0.8 m/s

so a ground based observer would see it moving at

v₁ = 2.4 + -0.8 = 1.6 m/s in its original direction

The CoM sees the smaller mass car approach at

0 - 2.4 = -2.4 m/s and will see it depart at + 2.4 m/s

so a ground based observer would see it moving at

v₂ = 2.4 + 2.4 = 4.8 m/s in its original direction of the larger car

so the relative velocity of approach at 3.2 - 0 = 3.2 m/s

equals the relative velocity of departure at 4.8 - 1.6 = 3.2 m/s

checks.

Answer:

a lot of the masks are hand made a long time ago its really an art

Explanation:

Because it is a piece of art that is hard to craft  

Helium gas is in a chamber with a moveable piston, whose mass is 8.7 kg and its radius is 0.013 m. The pressure exerted on the piston by the gas is 1.6 × 10⁵ Pa.

Helium is confined in a chamber with a moveable 8.7-kg piston (m). We can calculate the weight of the piston (w) using Newton's second law of motion.

[tex]w = m \times g = 8.7kg \times 9.8 m/s^{2} = 85 N[/tex]

The radius of the piston (r) is 0.013 m. We can calculate the area of the piston (A) using the following expression.

[tex]A = \pi \times r^{2} = \pi \times (0.013)^{2} = 5.3 \times 10^{-4} m^{2}[/tex]

We can calculate the pressure exerted by the piston (P) using the following expression.

[tex]P = \frac{w}{A} = \frac{85N}{5.3 \times 10^{-4}m^{2} } = 1.6 \times 10^{5} Pa[/tex]

Since the system is in equilibrium, the pressure exerted on the piston by the gas is also 1.6 × 10⁵ Pa.

Helium gas is in a chamber with a moveable piston, whose mass is 8.7 kg and its radius is 0.013 m. The pressure exerted on the piston by the gas is 1.6 × 10⁵ Pa.

Learn more: https://brainly.com/question/14672252

Explanation:

using v=u+at

0=32.6 + (a×(2.4/3600))

-32.6=(a×(2.4/3600))

a=-32.6×3600/2.4

a= -48900miles/hr^2

The speed of the block m1 on the frictionless table is 1.34 m/s.

The given parameters;

The net torque on both blocks is calculated as;

[tex]\tau _{net} = I \alpha[/tex]

[tex]T_2R- T_1 R_1 = I \alpha \\\\[/tex]

where;

[tex]T_1 = m_1 g + m_1 a\\\\T_2 = m_2 g - m_2 a[/tex]

The acceleration of both blocks is calculated as follows;

[tex]R(T_ 2- T_1) = MR^2 \times (\frac{a}{R} )\\\\R(T_2 -T_1) = MRa\\\\T_2 - T_1 = Ma\\\\(m_2g - m_2 a) - (m_1 g + m_1 a) = Ma\\\\m_2 g - m_1 g - m_2 a - m_1 a = Ma\\\\g(m_2 - m_1) = Ma + m_2a+ m_1a\\\\g(m_2 - m_1) = a(M+ m_2 + m_1)\\\\where;\\\\M \ is \ mass \ of \ string = 0 \\\\g(m_2 - m_1) = a (0+ m_2 + m_1)\\\\g(m_2 - m_1) = a(m_1 + m_2)\\\\a = \frac{g(m_2 - m_1)}{m_1 + m_2} \\\\a = 1.88 \ m/s^2[/tex]

The speed of the block m1 is calculated as follows;

[tex]a = \frac{v^2}{r} \\\\v^2 = ar\\\\v = \sqrt{a r} \\\\v = \sqrt{1.88 \times 0.95} \\\\v = 1.34 \ m/s[/tex]

Thus, the speed of the block m1 on the frictionless table is 1.34 m/s.

Learn more here:https://brainly.com/question/9060205

Answer:

Attached below! Ignore the name please. Thanks!

Explanation:

[tex]\\ \sf\longmapsto Frequency=\dfrac{1}{Time}=\dfrac{1}{3}=0.33s^{-1}[/tex]

Velocity be v

[tex]\\ \sf\longmapsto v=f\lambda[/tex]

[tex]\\ \sf\longmapsto V=0.33(1.5)[/tex]

[tex]\\ \sf\longmapsto V\approx 0.5ms^{-1}[/tex]

Given,

Wavelength = 1.5 metres

T = 3 seconds OR 3.0 seconds

We know that the formula of Frequency–

1/Time

According to the question we have seen that Time is 3 seconds

[tex] \sf \longmapsto \: Frequency = \frac{1}{3 .0 \: seconds} [/tex]

[tex] \sf \longmapsto \: Frequency = 0.33 seconds^{-1} [/tex]

We Know,

Velocity = Frequency

[tex]\sf \longmapsto Velocity =0.33 \times 1.5 [/tex]

[tex]\sf \longmapsto \: 0.5 \: m/s ^{-1}[/tex]

Explanation:Saturn is the second largest planet of the solar system in mass and size and the sixth nearest planet in distance to the Sun.

In the night sky Saturn is easily visible to the unaided eye as a non twinkling point of light.

Answer:

Explanation:

Complete the following sentence: If the car is 100% efficient, it could travel a distance of 900 meters on a single battery charge.

    W = Fd

1800 = 2d

     d = 900

Assuming 100 % efficient means turning battery power into motion.

A car totally 100% efficient would have zero friction and could travel an infinite distance on a full battery charge.

Newton's second law for rotational motion allows finding the net torque for each body is:

Newton's second law for rotational motion establishes a relationship between the torque, the moment of inertia, and the angular acceleration of the body.

               τ = I α

Where τ is the torque, I the moment of inertia and α the angular acceleration.

They indicate that the rotated angle is θ = 13 rad in a time of 8.0 s, let's use the rotational kinematics relations.

           θ = w₀ t + ½ α t²

The body starts from rest, therefore its inertial velocity is zero.

          θ = ½ α t²

          [tex]\alpha =\frac{2 \theta }{t^2}[/tex]  

Let's calculate

            α = [tex]\frac{2 \ 13^2}{8.0^2 }[/tex]

            α = 0.406 rad / s²

The moments of inertia of symmetrical bodies are tabulated:

Let's look for every torque.

Ring

         τ = m R² α

         τ = 4.0 0.35² 0.406

         τ = 0.199 N m

          τ = ½ m R² α

          τ = ½ 4.0 0.35² 0.406

          τ = 0.0995 N m

In conclusion using Newton's second law for rotational motion we can find the net torque for each body is:

Learn more about Newton's second law for rotation here:  brainly.com/question/15344745

Answer:

Explanation:

Givens

vi = 10 m/s

a = 1.5 m/s^2

d = 600 m

vf = ?

Formula

vf^2 = vi^2 + 2*a*d

Solution

vf^2 = 10^2 + 2*1.5 * 600

vf^2 = 100 + 1800

vf^2 = 1900

sqrt(vf^2) = sqrt(1900)

vf = 43.59 m/s

Newton's second law and the kinematics of rotation allow us to find the angular velocity of the snowball as it rolls across the roof is:

          w = [tex]\frac{2g}{R}[/tex]  

The kinematics of rotational motion studies the rotational motion of bodies.

           w = w₀ + 2 α θ

Where w and w₀ are the current and initial angular velocities, α the angular acceleration and θ the angle traveled.

Newton's second law establishes a relationship between the force, mass, and acceleration of the body.

The linear and rotational moviments are related.

             a = α R

Where a and α are the linear and rotational accelerations, respectively, and R is the radius of the body.

Let's find the linear acceleration of the body, in the attached we see a diagram of the forces, let's use trigonometry to decompose the weight.

            [tex]sin \theta = \frac{W_x}{W}[/tex]

            Wₓ = W sin θ

            Wₓ = m a

            mg sin θ = m a

            a = g sin θ

Now we can find the angular acceleration.

         α = a / R

         α = [tex]\frac{g}{ R \ sin \theta }[/tex]  

The body is released therefore its initial velocity is zero, we substitute in the kinematics expression.

          [tex]w = 2 ( \frac{g}{R \ sin \theta }) \ \theta[/tex]  

in rotational motion the angles are measured in radians  We use trigonometry to find the relationship between the angle and the distance traveled

             [tex]\theta = \frac{h}{D}[/tex]  

Where h is the height of the ceiling and D is the distance traveled.   Let's substitute.

           [tex]w = 2 \frac{g}{R sin \theta } \frac{h}{D}[/tex]

Let's tirgonmetry.

         sin θ = [tex]\frac{h}{D}[/tex]

         w = [tex]\frac{2g}{R}[/tex]

In conclusion, using Newton's second law and the kinematics of rotation, we can find the angular velocity of the snowball when rolling on the roof is:

          w = [tex]\frac{2g}{R}[/tex]

Learn more here:  brainly.com/question/14455108

Answer:

Let, θ be the angle between vector a and vector b.

So, the angle between vector a and vector (-b) must be (180° - θ).

Magnitude of the difference of vectors a and b

= |a - b|

= Magnitude of the resultant of the vector sum of the vectors a and (-b)

= |{√|a|^2 + |b|^2 + 2 * |a| * |b| * cos (180° - θ)}|

= |{√|a|^2 + |b|^2 - 2 * |a| * |b| * (cos θ)}|.

Explanation:

Answer:

Explanation:

Wt = ρVg

Wt = ρ(πD²/4)hg

Wt = 7800(π0.0275²/4)0.94(9.81)

Wt = 42.72152359...

Wt = 42.7 N

Answer:

E-MgO(Magnesium Oxide)

Hãy giải thích các khái niệm sau và lấy ví dụ cụ thể để minh họa:

Answer:

uhmmm

Explanation:

uhmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

Answer:

.

Explanation:

Answer:  lamda max= 16,5m   lamda min=  0,0165m (air)  

lamda  max= 75m, lamda min=0,075m (water)

Explanatin

Answer:

because I dont know

Explanation:

first you add the multiply

The instantaneous velocity at 60 m is zero, at - 40 m is - 1 m / s, at 15 s is zero and at 25 s is 0.8 m / s if Displacement (m) 0 20 40 40 80 80 60 400 Time (s) 10 10 20 30 40 50 60 70 80.

Instantaneous velocity = Position with respect to time / Time

1 ) At d = 60 m, the instantaneous velocity is zero because the car is at rest.

2 ) At d = - 40 m, t = 40 s

Instantaneous velocity = - 40 / 40

Instantaneous velocity = - 1 m / s

3 ) At t = 15 s, d = 60 m

At 60 m, the car is at rest, so the Instantaneous velocity is zero

4 ) At t = 25 s, d = 20 m

Instantaneous velocity = 20 / 25

Instantaneous velocity = 0.8 m / s

Instantaneous velocity of a given curve in a position-time graph can be found by drawing a tangent to the curve and finding the slope of the tangent. Instantaneous velocity = 0

Instantaneous velocity = - 1 m / s

Instantaneous velocity = 0

Instantaneous velocity = 0.8 m / s

Therefore, The instantaneous velocity at 60 m is zero, at - 40 m is - 1 m / s, at 15 s is zero and at 25 s is 0.8 m / s if Displacement (m) 0 20 40 40 80 80 60 400 Time (s) 10 10 20 30 40 50 60 70 80.

Learn more about velocity on:

https://brainly.com/question/18084516

#SPJ2

Answer:

The net force on the desk is zero.

Answer:

No, it cannot. The car needs the friction of the surface to drive because the car pushes the surface backwards, and the surfaces makes a reaction force pushing the car forward, and that works because of the friction. In a frictionless surface the tires would rotate in the same place

Analog signals and storage are used in most modern electronics is a false statement.

Analog signals and storage are not used in most modern electronics because analog signals are used in old instruments and technologies while on the other hand, in modern electronics digital signals and storage system are used that have higher speed, compatibility and space for storage.

Analog signals and storage were used in old electronics and can't be used in modern electronics due to non-compatibility so we can conclude that digital signals and storage are used in modern electronics.

Learn more: https://brainly.com/question/25752598

Answer: 140.625

Explanation: Because energy gained due to damped motion and needs to be absorbed

Answer:Wavelength

Explanation: The wavelength of a wave is the distance between any two corresponding points on adjacent waves.

Answer:

8280J

Explanation:

W = f x d

345 x 24 = 8280J