The time it takes Alice to walk to the bus stop from her home is normally distributed with mean 13 minutes and variance 4 minutes squared. The waiting time for the bus to arrive is normally distributed with mean 5 minutes and standard deviation 2 minutes. Her bus journey to the bus loop is a normal variable with mean 24 and standard deviation 5 minutes. The time it take Alice to walk from the bus loop to the lecture theatre to attend stats class is normally distributed with mean 18 minutes and variance 4 minutes. The total time taken for Alice to travel from her home to her STAT 251 lecture is Normally distributed.


Part a) What is the mean travel time (in minutes)?


Part b) What is the standard deviation of Alice's travel time (in minutes, to 2 decimal places)?


Part c) The STAT 251 class starts at 8 am sharp. Alice leaves home at 7 am. What is the probability (to 2 decimal places) that Alice will not be late for her class?

Answer:

The correct system of inequalities that models the constraints is:

6.00b + 7.75s ≥ 250

b + s ≤ 40

Explanation:

The first inequality represents the requirement that Jason needs to earn at least $250 each week. The earnings from babysitting are $6.00 per hour, and the earnings from working at the store are $7.75 per hour.

Therefore, the total earnings from both jobs can be represented by the expression 6.00b + 7.75s. This expression must be greater than or equal to $250, hence the first inequality.

The second inequality represents the constraint that Jason can work no more than 40 hours each week. The variables b and s represent the number of hours worked babysitting and working at the store, respectively.

The sum of these hours must be less than or equal to 40, hence the second inequality.

Therefore, the correct system of inequalities is:

6.00b + 7.75s ≥ 250

b + s ≤ 40

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The rate of return should an investor expect to earn if he or she purchases these bonds is equal to 4.184%.

Annual coupon rate = 6.35%

Maturity time = 20 years

To calculate the rate of return an investor should expect to earn if they purchase the Taussig Corp. S bonds,

Consider the cash flows from the bond and the purchase price.

Determine the cash flows from the bond,

The bond has a 6.35% annual coupon rate,

which means it pays $63.50 per year 6.35% of $1,000 face value.

The bond has a 20-year maturity, so there will be 20 coupon payments of $63.50 each.

If the bond is not called, the investor will receive the face value of $1,000 at maturity.

Calculate the purchase price of the bond,

The bonds are currently selling for $960.

Calculate the yield to maturity (YTM) on the bond,

Assume the yield curve is horizontal, so the yield to maturity will be the same as the coupon rate.

Calculate the rate of return using the following formula,

Rate of Return = [tex](Total Cash Flows / Purchase Price)^{(1 / Holding Period)}[/tex] - 1

Let us calculate the rate of return step by step,

Total Cash Flows,

Coupon payments,

$63.50 × 20 years = $1,270

Face value at maturity = $1,000

Total Cash Flows = $1,270 + $1,000

                            = $2,270

Rate of Return = [tex]($2,270 / $960)^{(1 / 20)}[/tex] - 1

Using a financial calculator , Attached calculation.

solve for the rate of return:

Rate of Return ≈ 4.184%

Therefore, an investor should expect to earn approximately a 4.18% rate of return if they purchase these bonds.

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Answer:Therefore, the total number of players on the team is 21.

Step-by-step explanation:Let's start by using algebra to represent the information given in the problem.

Let p be the total number of players on the team.

The number of players who chose water is given as 14.

This is also equal to 2/3 of the total number of players, so we can write:

14 = (2/3) * p

To solve for p, we can isolate it on one side of the equation by multiplying both sides by the reciprocal of 2/3, which is 3/2:

14 * (3/2) = (2/3) * p * (3/2)

21 = p

Answer: 6cm

Step-by-step explanation: VF=(SF)^3

let x be the height of the larger container

VF1/VF2=(SF1/SF2)^3

54/128=(4.5/X)^3

rearrange to find x

x=cube root of (4.5^3*128)/54

x=6cm

The value of 6x-5y = -31

The given equations are 2x-y=-7 -eq (1)

& 4x=-3y+16 -eq (2)

Multiplying eq (1) with 2 and rearranging to get equation as follows

(2x-y=-7)*2

4x-2y=-14 -eq (3)

Now, subtracting eq (3) from eq (2) to get y.

(4x+3y=16) - (4x-2y=-14)

5y=30

y=5

Substituting y=5 in eq (1) to get x.

2x-5=-7

x=-1

Now to determine 6x-5y substitute obtained values of x & y.

6*(-1)-5(5)=-31

Hence the value of 6x-5y=-31.

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a. The data provided enough evidence at a = 0.05 level that the true mean pH of water from this source differs from 7

b. A 95% confidence interval for the true mean pH level of the water is (6.21, 6.59) means  about 95% of those intervals would contain the true mean pH level.

c. The estimated mean pH level of seven is not included in the interval in section (b). This is consistent with the result of the test in part (a), which also rejects the null hypothesis that the true mean pH level is 7.

(a) To test whether the true mean pH of water from this source differs from 7, we can perform a one-sample t-test. The null hypothesis is that the true mean pH is equal to 7, and the alternative hypothesis is that the true mean pH is not equal to 7.

The test statistic can be calculated as follows:

t = (sample mean - hypothesized mean) / (sample standard deviation / sqrt(sample size))

t = (6.4 - 7) / (0.5 / sqrt(30))

t = -3.07

Using a t-table with 29 degrees of freedom at a significance level of 0.05 (two-tailed test), the critical t-value is ±2.045. Since the calculated t-value (-3.07) is outside of the critical t-value range, we can reject the null hypothesis and conclude that there is enough evidence at a = 0.05 level to suggest that the true mean pH of water from this source differs from 7.

(b) A 95% confidence interval for the true mean pH level of the water is (6.21, 6.59). This means that if we were to take many random samples of size 30 from this water source, and construct a 95% confidence interval for each sample mean pH level, then about 95% of those intervals would contain the true mean pH level.

(c) The interval in part (b) does not include the hypothesized mean pH level of 7. This is consistent with the result of the test in part (a), which also rejects the null hypothesis that the true mean pH level is 7.

The confidence interval provides additional information by giving a range of plausible values for the true mean pH level, and we can see that all of the values in this range are below 7, indicating that the water is indeed slightly acidic.

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To find the length of the entire perimeter of the region inside r = 7 sin Ф but outside r = 2, we first need to determine the boundaries of the region.

The equation r = 7 sin Ф represents a curve that forms a flower-like shape, while the equation r = 2 represents a circle with radius 2.

To find the region inside r = 7 sin Ф but outside r = 2, we need to find the points where these two curves intersect.

Setting the two equations equal to each other, we get:

7 sin Ф = 2

Solving for sin Ф, we get:

sin Ф = 2/7

Using a calculator, we can find the two values of Ф that satisfy this equation to be approximately 0.304 and 2.837 radians.

Thus, the region inside r = 7 sin Ф but outside r = 2 is bounded by the angles 0.304 and 2.837 radians.

To find the length of the entire perimeter of this region, we need to integrate the length element around this curve:

L = ∫(from 0.304 to 2.837) √[r² + (dr/dФ)²] dФ

Using the equation r = 7 sin Ф, we can substitute and simplify the expression under the square root:

L = ∫(from 0.304 to 2.837) √[49sin²(Ф) + 49cos²(Ф)] dФ

L = ∫(from 0.304 to 2.837) 7 dФ

L = 7(2.837 - 0.304)

L = 16.1

Therefore, the length of the entire perimeter of the region inside r = 7 sin Ф but outside r = 2 is approximately 16.1 units.
To find the length of the entire perimeter of the region inside r = 7 sin Ф but outside r = 2, we must first identify the points of intersection between the two curves.

1. Set the equations equal to each other:
7 sin Ф = 2

2. Solve for Ф:
sin Ф = 2/7
Ф = arcsin(2/7)

Now, we must determine the length of the perimeter of each curve in the region of interest:

3. Length of the perimeter of r = 7 sin Ф (half of the curve, since it's within the specified region):
For a polar curve r = f(Ф), the arc length L is calculated using the formula L = ∫√(r² + (dr/dФ)²) dФ.

In this case, f(Ф) = 7 sin Ф, so dr/dФ = 7 cos Ф. Integrating over the range [0, arcsin(2/7)], we can find the half-length of this curve.

4. Length of the perimeter of r = 2 (portion of the circle outside the region):
Since we know the points of intersection from step 2, we can find the central angle of the circular segment using Ф. The central angle is 2 * arcsin(2/7), and the circumference of the circle is 2π * 2. The portion of the perimeter is given by the ratio of the central angle to 2π, multiplied by the circumference.

Finally, add the lengths obtained in steps 3 and 4 to get the total length of the entire perimeter of the region.

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We know that they cannot exceed 30 minutes, they should not waste any time and must move quickly during each crossing.

To ensure that Leo's family crosses the bridge before the flashlight runs out, they should follow these steps:
1. Dad and Mom should cross the bridge together, which will take 3 minutes (because the slowest person is Mom, who takes 3 minutes).
2. Dad should return to the starting point, which will take 1 minute.
3. Leo and Brother should then cross the bridge together, which will take 8 minutes (because the slowest person is Brother, who takes 8 minutes).
4. Mom should return to the starting point, which will take 3 minutes.
5. Dad and Grandpa should then cross the bridge together, which will take 12 minutes (because the slowest person is Grandpa, who takes 12 minutes).
6. Dad should return to the starting point, which will take 1 minute.
7. Finally, Dad and Mom should cross the bridge together, which will take 3 minutes (because the slowest person is Mom, who takes 3 minutes).

Adding up all the minutes taken, it will be: 3+1+8+3+12+1+3=31 minutes. However, since they cannot exceed 30 minutes, they should not waste any time and must move quickly during each crossing.

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The total distance of Jorge for the week is 8.4 miles.

Let's assume that Jorge walks x miles in a week. According to the problem, he walks 1.4 miles on Monday, which is 1/6 of his total for the week. We can use this information to set up the following equation:

1/6 x = 1.4

To solve for x, we can multiply both sides by 6:

x = 1.4 x 6

x = 8.4

Therefore, Jorge walks a total distance of 8.4 miles in a week.

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The parts of this equilateral triangle ABC are as follows:

The length of side x of the equilateral triangle is determined as follows:

AD = x

AB = 6

DB = 6/2 or 3

AB² = AD² + DB²

6² = x² + 3²

x² = 6² - 3²

x = 27

x = 3√3

Therefore, the length of the perpendicular bisector AD is 3√³ units

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Answer:

the length is 3√³ units

a. The equation to solve for x is given as follows: 2x + 8 = 42.

b. The solution for x is given as follows: x = 17.

The value of x is obtained applying the angle bisection theorem, which divides an angle into two angles of equal measure, hence the opposite segments also have equal length.

The segments for this problem, along with their lengths, are given as follows:

Hence the equation is given as follows:

2x + 8 = 42.

The value of x is given as follows:

2x = 34

x = 17.

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The constant 1.2 in the function represents the rate of change of the quantity per year.

Specifically, it represents the factor by which the quantity grows or decays over a year.

Since 1.2 is greater than 1, the function describes an exponential growth, where the quantity is multiplied by 1.2 each year.

For example, after one year, the quantity is multiplied by 1.2, after two years it is multiplied by 1.2 squared, and so on.

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The sum of the first 8 terms of the sequence is 5100. Rounded to the nearest hundredth, this is 5100.00

To find the sum of the first 8 terms of the sequence 20, 40, 80,..., we need to use the geometric series formula:

S = a(1 - r^{n}) / (1 - r)

where S is the sum of the first n terms, a is the first term, r is the common ratio, and n is the number of terms.

In this case, a = 20 (the first term), r = 2 (the common ratio, since each term is twice the previous one), and n = 8 (since we want to find the sum of the first 8 terms).

So plugging these values into the formula, we get:

S = 20(1 - 2^8) / (1 - 2)
S = 20(1 - 256) / (-1)
S = 20(255)
S = 5100

Therefore, the sum of the first 8 terms of the sequence is 5100. Rounded to the nearest hundredth, this is 5100.00.

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The probability of a randomly selected tire from this sample having a lifespan greater than 45,000 miles is approximately 0.0639 or 6.39%.

We can use the central limit theorem to approximate the distribution of the sample mean.

In this case, the population mean is 44,000 miles and the population standard deviation is 7,650 miles. We are taking a sample of 120 tires, so the standard deviation of the sample mean is:

σ/√n = 7,650/√120 = 698.68

To find the probability that the sample mean will be longer than 45,000 miles, we need to standardize the sample mean using the formula:

z = (x - μ) / (σ / √n)

where x is the sample mean, μ is the population mean, σ is the population standard deviation, and n is the sample size.

Plugging in the values, we get:

z = (45,000 - 44,000) / (7,650 / √120) = 1.527

We can then look up the probability corresponding to a z-score of 1.527 in a standard normal distribution table or using a calculator. The probability of a randomly selected tire from this sample having a lifespan greater than 45,000 miles is approximately 0.0639 or 6.39%.

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the series converges for all x in the interval (-1/6, 1/6) in interval notation.

The given series is a geometric series with first term a=1 and common ratio r=6x. The series converges if and only if |r|<1.

So, |6x|<1

Solving this inequality, we get:

-1/6 < x < 1/6

To find all values of x for which the series converges, we need to analyze the given series:
∑(6x)^n

This is a geometric series with a common ratio of 6x. For a geometric series to converge, the absolute value of the common ratio must be less than 1:

|6x| < 1

Now, we can solve for the interval of x:

|-1/6| < |x| < |1/6|

Using interval notation, the range of values for which the series converges is:

(-1/6, 1/6)

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The monthly payment for a new car priced at $24,530 with the given terms is $630.15.

Calculating the down payment:

20% of $24,530

= 0.20 × 24,530

= $4,906.

Subtracting the down payment from the car price:

= $24,530 - $4,906

= $19,624 (amount to finance).

Adding the 8% TT&L (tax, title, and license) to the amount to finance:

  8% of $24,530

= 0.08 × 24,530

= $1,962.40.

So, the total amount to finance

= $19,624 + $1,962.40

= $21,586.40.

Converting the annual interest rate of 3.16% to a decimal:

  3.16% / 100

= 0.0316.

Calculating the monthly interest rate:

 0.0316 / 12

= 0.002633.

Calculating the total number of payments: 36 months.

Using the monthly payment formula:

P = (PV * r * (1 + r)^n) / ((1 + r)^n - 1),

where P is the monthly payment,

           PV is the present value or amount to finance,

          r is the monthly interest rate, and

          n is the total number of payments.
Now, pluggin  in the values:

P = ($21,586.40 × 0.002633 × (1 + 0.002633)³⁶) / ((1 + 0.002633)³⁶ - 1)

= $630.15.

The monthly payment for the new car will be approximately $630.15.

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So, to the nearest hundredth, the value of f(26.5) is approximately 59.81.

To find the value of f(26.5) for the given exponential function f(x), we will first determine the base and initial value of the function using the given points f(4.5) = 22 and f(14) = 40.
An exponential function has the form f(x) = ab^x, where a is the initial value and b is the base.
1. Write the two equations using the given points:
22 = ab^(4.5)
40 = ab^(14)
2. Divide the second equation by the first to eliminate the initial value, a:
(40/22) = (ab^(14))/(ab^(4.5))
3. Simplify and solve for the base, b:
1.81818 = b^(9.5)
b ≈ 1.05459
4. Now, plug b back into one of the original equations to solve for the initial value, a:
22 = a(1.05459)^4.5
a ≈ 16.08364
5. With a and b found, we can now find the value of f(26.5):
f(26.5) = 16.08364 * (1.05459)^26.5
f(26.5) ≈ 59.81
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The value of exponential function f(26. 5), to the nearest hundredth is 144.42.

To find the value of f(26.5) for the exponential function, we can use the given data points and apply the exponential function formula.

Let's assume the exponential function is of the form: f(x) = a * b^x, where a and b are constants.

Using the given data points:

f(4.5) = 22

f(14) = 40

Substituting these values into the exponential function equation:

22 = a * b^4.5 ---(1)

40 = a * b^14 ---(2)

Dividing equation (2) by equation (1), we can eliminate the constant 'a':

40/22 = (a * b^14) / (a * b^4.5)

1.8182 = b^(14 - 4.5)

1.8182 = b^9.5

To find the value of b, we take the 9.5th root of 1.8182:

b ≈ 1.109

Now we can substitute the value of b into equation (1) to solve for 'a':

22 = a * (1.109)^4.5

a ≈ 4.95

Therefore, the exponential function can be approximated as: f(x) ≈ 4.95 * (1.109)^x

Now we can find the value of f(26.5):

f(26.5) ≈ 4.95 * (1.109)^26.5 ≈ 144.42

Hence, the value of f(26.5), to the nearest hundredth, is approximately 144.42.

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The probability is approximately 45.4% (rounded to the nearest tenth of a percent).

To find the probability that a randomly selected point within the circle falls in the white area, we need to find the area of the white region and divide it by the total area of the circle.

The total area of the circle is:

A = πr² = π(4 cm)² = 16π cm²

The area of the white region can be found by subtracting the area of the two semicircles from the area of the circle:

White area = A - 2(1/2π(2.5 cm)²) = 16π - 2(4.375π) = 7.25π cm²

So, the probability that a randomly selected point within the circle falls in the white area is:

P(white area) = (white area)/(total area) = (7.25π)/(16π) ≈ 45.4%

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The volume of the cylinder is approximately 1570.8 cubic centimeters, rounded to the nearest tenth.

A cylinder is a three-dimensional object with two congruent circular bases that are parallel to each other. The volume of a cylinder can be calculated using the formula V = πr²h, where V is the volume, r is the radius of the base, and h is the height of the cylinder.

In this problem, we are given that the height of the cylinder is 5 centimeters and the radius of the base is 10 centimeters. By substituting these values into the formula, we get:

V = π x 10² x 5

V = 500π

To calculate the volume of the cylinder, we can use an approximation for the value of pi. Taking pi to be approximately 3.14, we can calculate the volume as follows:

V ≈ 500 x 3.14

V ≈ 1570.8

Therefore, the volume of the cylinder to the nearest tenths place is approximately 1570.8 cubic centimeters.

It is important to note that the answer is an approximation since pi is an irrational number with an infinite number of decimal places. However, rounding to the nearest tenths place provides a reasonable level of precision for this calculation.

In summary, the volume of the cylinder is 1570.8 cubic centimeters, and the calculation is based on the given values and the formula for the volume of a cylinder.

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We can assign each participant the real drink or placebo by assigning a drink based on the next random digit.

One method for assigning participants their drink is to utilize a basic rule predicated on the oddness or evenness of specific digits. In this scenario, you may reserve “odd” numbers strictly for real drinks and “even” numbers exclusively for placebos.

To execute this procedure, we will begin at the left-hand side of our precomputed list of randomized digits and work to identify the subsequent digit in order to assign each participant with their corresponding drink:

Assign numbers to each of the houses in every subdivision, ranging from 1 through to 100. Utilize an online random number generator or a table containing random numbers within the range of 1 and 100 to construct a list of such randomly generated figures.

Choose the initial 20 unique figures from said list for both subdivisions selectively. Proceed with visiting those particular homes denoted by these chosen numbers, then examine and test their water sources accordingly.

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The soccer ball will land approximately 1 seconds after it was kicked upward. This is found by setting the height equation to 0 and solving for t using the quadratic formula.

To solve for the time the soccer ball lands, we need to find the time when h = 0. We can use the given equation

h = -4.9t² + vt + s

where v = 4.9 m/s (since it's kicked upward) and s = 0 (since it starts at ground level).

Substituting those values, we get

0 = -4.9t² + 4.9t

Factoring out 4.9t, we get

0 = 4.9t(-t + 1)

So, either t = 0 or -t + 1 = 0

Since time cannot be negative, we discard the second solution and solve for t

-t + 1 = 0

t = 1

Therefore, the soccer ball lands after approximately 1 second.

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The ratio table shows the costs for different amounts of birdseed. So, the unit rate is $2 per pound in this example.

To find the unit rate in dollars per pound, follow these steps:
1. Look at the given ratio table, which shows the costs for different amounts of bird seed.
2. Identify the cost and the corresponding amount (in pounds) of bird seed for any one row in the table.
3. Divide the cost (in dollars) by the amount (in pounds) to calculate the unit rate.

For example, if the table shows that the cost is $6 for 3 pounds of bird seed, the unit rate would be calculated as follows:

Unit rate = Cost / Amount
Unit rate = $6 / 3 pounds
Unit rate = $2 per pound
So, the unit rate is $2 per pound in this example

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The value of the missing side lengths a and b of the right angles triangle are 2 and √2 respectively.

A right-angled triangle's other angle must be 45 degrees because the base angle is that number. The third angle in a triangle must be 90 degrees since the sum of the triangle's three angles is 180 degrees.

Using trigonometric ratios, we know that,

sin(45) = 2√2/a and,

cos(45) = b/a.

Simplifying, we get,

a = 2√2/sin(45)

= 2√2/√2

= 2 and,

b = a cos(45)

= 2 cos(45)

= √2.

Therefore, the value of a is 2 and the value of b is √2.

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Answer: C

Step-by-step explanation:

The percent of the phosphorus-32 decays each day is 0.56%.

The formula for the amount of radioactive isotope remaining after t days is given as:

y = a(0.5)^(t/14)

To find the percent of phosphorus-32 that decays each day, we need to find the fraction of the initial amount that decays each day. This can be found by subtracting the amount remaining after one day from the initial amount, and then dividing by the initial amount:

fraction decayed in one day = (a - a(0.5)^(1/14)) / a

Simplifying this expression gives:

fraction decayed in one day = 1 - (0.5)^(1/14)

To find the percent decayed in one day, we multiply by 100:

percent decayed in one day = 100(1 - (0.5)^(1/14))

Using a calculator, we get:

percent decayed in one day ≈ 0.56%

Therefore, the percent of phosphorus-32 that decays each day is approximately 0.56%.

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If kawan paints the visible outside faces of her shed, she paints two rectangle faces and two triangle faces then the total surface area that she paints is 88ft².

The area of a triangle of altitude h and base b is given by;

A = 0.5bh

Therefore the area of one triangle face ;

At = 0.5 × 8 × 5

At = 20ft²

Area of a rectangle of length l and breadth b is;

A = lb

Therefore the area of a rectangle face;

Ar = 8 × 3

Ar = 24ft²

We have 2 triangle faces and 2 rectangle face, therefore total surface area as;

A = 2At + 2Ar

A  = 2×20 + 2×24

A = 40 + 48

A = 88ft²

Therefore the answer is; 88ft².

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The answer of the given question based on the graph could be used to determine the variance levels that would result in a package of vegetables is histogram.

To determine the variance levels that would result in a package of vegetables being rejected because of its weight, X, consider the following:

1. The company has a tolerance level of less than or equal to y grams for a 250-gram package. This means that the graph must represent a relationship between the weight of the package (X) and the tolerance level (y).
2. Since the package is rejected if it weighs more than the allowed tolerance, the graph should show that as the weight (X) increases, the acceptance range decreases (y decreases).
3. The graph should ideally have a boundary line that represents the maximum tolerance level (y). Any points above this line would represent rejected packages.

Based on these criteria, you should select the graph that best represents this relationship between the weight of the package (X) and the tolerance level (y), where packages with a weight exceeding the tolerance level are rejected.

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The surface area of the triangular prism is 3152 square cm if the  base of the prism is an isosceles triangle.

What exactly is a triangular prism?

When a prism has three rectangular sides and two triangular bases, the prism is said to be triangular. It's a pentahedron. A right triangular prism has two faces and three rectangular sides. Bases refers to the triangle faces, whereas laterals refers to the rectangular sides.

We have a triangular prism, is showing in the picture:

Here  a = 25

b = 25

c = 14

h = 44

The surface area of the triangular prism is given by

  A = ah + bh + ch + 1/2√-a⁴ + 2(ab)² + 2(ac)² + -b⁴ + 2(bc)² - c⁴

  Plug all the values in the formula we get:

A = 3152 square cm

Thus, the surface area of the triangular prism is 3152 square cm if the  base of the prism is an isosceles triangle.

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Answer:

KM = 34

Step-by-step explanation:

Since L is the midpoint of KM that makes KL and LM equal. If LM and KL are congruent that means that the measure of KL is also 17. Therefore KM is just double 17 therefore being 34.