What is the output for x = -1

The constant of variation, k, is defined as the ratio between the two variables' values, multiplied by their respective powers:  [tex]k = y/x^a \times z/x^b,[/tex] where a and b are the powers of x in the expressions for y and z, respectively. when   [tex]x = -3[/tex]  and [tex]y = 4[/tex] , z is equal to -81/16.

In this case, we have x = 8, y = 54, and z = 144, so we need to determine the powers of x in the expressions for y and z:

[tex]y = 54 = (8^a) \times k = > a = 3[/tex]

[tex]z = 144 = (8^b) \times k = > b = 2[/tex]

Substituting these values into the formula for k, we get:

[tex]k = y/x^a \times z/x^b = 54/8^3 \times 144/8^2 = 27/64[/tex]

Therefore, the constant of variation is 27/64.

Using the same formula as above, we can solve for z when x = -3 and y = 4:

[tex]k = y/x^a \times z/x^b[/tex]

We need to determine the powers of x in the expressions for y and z:

[tex]y = 4 = (-3)^a * k = > a = -1[/tex]

[tex]z = ? = (-3)^b * k = >[/tex] we don't know b or z yet

Substituting these values into the formula for k, we get:

[tex]k = y/x^a * z/x^b = 4/(-3)^(-1) * z/(-3)^b = -12z/(-3)^2[/tex]

Simplifying this expression, we get:

[tex]k = -12z/9 = -4z/3[/tex]

Now we can solve for z:

[tex]-4z/3 = 27/64[/tex]

Multiplying both sides by 3/(-4), we get:

[tex]z = -81/16[/tex]

Therefore, when  [tex]x = -3[/tex] and   [tex]y = 4, z[/tex] is equal to   [tex]-81/16.[/tex]

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The comparison data is shown below.

Based on the information provided, we can infer that:

Without more information about the specific data and the context of the study, it is difficult to make further comparisons or draw any conclusions about the relationship between completing homework and exam scores. However, it is interesting to note that completing homework did not seem to have an impact on the average exam score or the variability of exam scores.

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Answer: 9

Step-by-step explanation:

Range = maximum number - minimum number (in a data set)

50-41 = 9 minutes

The equation is true based on the model is B) (-3) + 5 = 2.

If we consider the circles on the left as negative units and the circles on the right as positive units.

Then we can see that there are 5 positive units and 3 negative units, so the sum is

= 5 - 3

= 2.

Therefore, the correct equation is: B) (-3) + 5 = 2.

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The linear function is the more appropriate function that has to be used here.

To determine which type of function better models the data, we can analyze the difference in the y values (Estimated Population) as x increases.

Differences between consecutive y values:

77,212 - 66,118 = 11,094

88,340 - 77,212 = 11,128

99,535 - 88,340 = 11,195

The differences between consecutive y values are relatively constant as x increases.

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Answer:

To calculate the amount you would need to deposit in the account now, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

where A is the amount you will have after 15 years, P is the principal amount (the amount you need to deposit now), r is the annual interest rate (7%), n is the number of times the interest is compounded per year (12 for monthly compounding), and t is the time in years (15).

Plugging in the values, we get:

2000 = P(1 + 0.07/12)^(12*15)

Simplifying the right side, we get:

2000 = P(1.00583)^180

Dividing both sides by (1.00583)^180, we get:

P = 2000 / (1.00583)^180

P = $775.80 (rounded to the nearest cent)

Therefore, to have $2000 in the account in 15 years with an annual interest rate of 7% compounded monthly, you would need to deposit $775.80 now.

Answer:

It is 50x or 50*x or 50(x).

Answer:

it is the opposite way around

Step-by-step explanation:

The function that is even is f(x) = 6x² - 8.

option C.

An even function is a function that satisfies the condition f(-x) = f(x) for all values of x in its domain. In other words, an even function is symmetric with respect to the y-axis.

The function that is even is calculated as follows;

f(x) = 5x² - x

f(-x) = 5(-x)² - (-x)

f(-x) = 5x² + x

f(x) ≠ f(-x)

f(x) = 3x³ + x

f(-x) = 3(-x)³ + (-x)

f(-x) = -3x³ - x

f(x) ≠ f(-x)

f(x) = 6x² - 8

f(-x) = 6(-x)² - 8

f(-x) = 6x² - 8

so f(x) = f(-x), this function is even.

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Answer:

the area of the shape is 48m

Step-by-step explanation:

10*4=40

2*4=8

40+8=48

brake it up into two triangles. one is a triangle that is 10m tall and 8m wide at the top. you can solve that by doing 4*10=40. the other triangle is 4m wide at the bottom and 2m tall. you can solve that by doing 2*4=8. and 40+8=48.

The solutions to the rational equations are

The rational equations can be solved as follows

(1)

(x - 2)/(2x + 4) = 1/5

This gives

5x - 10 = 2x + 4

So, we have

3x = 14

x = 14/3

(2)

For equation (2), we have

(x + 3)/2 - x/4 = 4/3

So, we have

[2(x + 3) - x]/4 = 4/3

[x + 6]/4 = 4/3

So, we have

3x + 18 = 16

x = -2/3

(3)

For equation (3), we have

3/(x + 1) - 2/(x - 1) = 1/(x² - 1)

So, we have

3(x - 1) - 2(x + 1) = 1

This gives

3x - 3 - 2x - 2 = 1

x = 4

(4)

For equation (4), we have

18/(x² - 3x) = 2x/(x - 3) - 6/x

So, we have

18 = 2x² - 6(x - 3)

This gives

x = 0 or x = 3

(5)

For equation (5), we have

3x/(x + 2) + 6/x + 4 = 12/(x² + 2x)

Multiiply through by x² + 2x

3x² + 6(x + 2) + 4(x² + 2x) = 12

Evaluate

x = 0 or x = -2

(6)

For equation (6), we have

1/(x - 2) + 4/(x + 9) = 3/(x² + 7x - 18)

Multiiply through by (x² + 7x - 18)

x - 9 + 4x + 8 = 3

So, we have

5x = 4

Evaluate

x = 4/5

(7)

For equation (7), we have

3/5x² - 1/5 = 2/25x²

Multiiply through by 25x²

15 - 5x² = 2

So, we have

5x² = 17

Evaluate

x = √(17/5)

(8)

For equation (8), we have

9/(x + 1) = 2/(x² - 1)

Multiiply through by 25x²

9x - 9 = 2

So, we have

9x = 11

Evaluate

x = 11/9

(9)

For equation (9), we have

3/(x³ - 8) = 1/(x - 2)

Cross multiiply

(x³ - 8) = 3(x - 2)

Evaluate

x = -1 and x = 2

(10)

For equation (10), we have

x²/2 - 3x/2 + 1 = 0

Multiiply through by 2

x² - 3x + 2 = 0

Factoize

(x - 1)(x - 2) = 0

So, we have

x = 1 and x = 2

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A 3:5 scaled version means that the dimensions of the new version are proportional to the original dimensions in a ratio of 3:5.

A scaled version is a version of a shape where every size in the original shape is multiplied by the same number.

In this situation, a 3:5 scaled version means that the dimensions (or sizes) of the new version are proportional to the original dimensions in a ratio of 3:5.

For example, if we have a circle with radius 20 cm, we can create a 3:5 scaled version by multiplying the radius by the ratio 3/5. That is:

scaled version radius = 3/5 * 20 = 12 cm

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Expressing the expansion of the logarithm in terms of log y, we can write: log(8x^2) = log(8) + 2*log(y), where y = x

Using the logarithmic identity that states log(a^b) = b*log(a), we can expand log(8x^2) as:

log(8x^2) = log(8) + log(x^2)

Note that a  logarithmic identity is a mathematical relationship or equation that involves logarithms.

We can further simplify log(x^2) as:

log(x^2) = 2*log(x)

Therefore, we can write:

log(8x^2) = log(8) + 2*log(x)

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The equation is not a quadratic equation. Statement is false.

A second-order polynomial equation with just one variable, x, is referred to as a quadratic equation. with a ≠ 0 . The fundamental theorem of algebra guarantees that it has at least one solution since it is a second-order polynomial equation. The arrangement might be genuine or complex.

This is a linear equation in the form y = mx + b, where m is the slope and b is the y-intercept. In this case, the slope is 5 and the y-intercept is 2. A quadratic equation is an equation in the form y = ax^2 + bx + c, where a, b, and c are constants and x is the variable.

Thus, given equation is not a quadratic equation. Statement is false.

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The height of the triangle is √(115) - 1 inches and the width is (1 + √(115)) / 6 inches.

Let's begin by assigning variables to the height and width of the triangle. We'll use h for height and w for width.

From the problem statement, we know that the area of the triangle is 184 square inches:

Area = (1/2) * base * height

where the base is equal to the width. We can rearrange this formula to solve for the height:

height = 2 * Area / base

Since the area is given as 184 square inches and the base is equal to the width, we can write:

h = 2 * 184 / w

We also know that the height is two less than six times the width. Writing this as an equation, we have:

h = 6w - 2

Now we can substitute the expression for h from the second equation into the first equation:

2 * 184 / w = 6w - 2

Multiplying both sides by w gives:

2 * 184 = w * (6w - 2)

Expanding the right side gives:

2 * 184 = 6w² - 2w

Simplifying further gives:

6w² - 2w - 368 = 0

This is a quadratic equation that we can solve using the quadratic formula:

w = (-b ± √(b² - 4ac)) / 2a

where a = 6, b = -2, and c = -368. Plugging in these values gives:

w = (2 ± √(2² - 4 * 6 * (-368))) / 2(6)

Simplifying further gives:

w = (1 ± √(115)) / 6

Taking the positive value gives:

w = (1 + √(115)) / 6

Plugging this value back into either equation for h gives:

h = 6w - 2 = 6((1 + √(115)) / 6) - 2 = 1 + √(115) - 2 = √(115) - 1

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Answer:

19/20--no

32/4--yes (32/4 = 8)

74--yes

23--yes

5.95--no

Answer:

That number is 230 × 1.08 = 248.4.

To find this number, we calculated 8% of 230, which is 18.4 , and then added it to 230, Hence The number that is 8% larger than 230 is 248.4.

To find a number that is 8% larger than 230, we can calculate the 8% increase of 230 and add it to the original number.

Step 1: Calculate the 8% increase of 230:

8% of 230 = (8/100) * 230 = 0.08 * 230 = 18.4

Step 2: Add the 8% increase to 230:

230 + 18.4 = 248.4

Therefore, a number that is 8% larger than 230 is 248.4.

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if a student scored a 69 on his first test, predict that his score on the second test will be approximately 64.57.

Students’ test scores on the first two tests in an introductory calculus class.

To make a prediction for the student's score on the second test based on their score of 69 on the first test, we need to find the regression equation for the data set.

The regression equation for these data is

y = 0.6443x + 19.943

Where y is the predicted score on the second test and x is the actual score on the first test.

Substituting x = 69 into this equation, we get

y = 0.6443(69) + 19.943 ≈ 64.57

Therefore, if a student scored a 69 on his first test, we predict that his score on the second test will be approximately 64.57.

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If a turtle lives in a garden and a hedgehog lives in the woods. The distance between the garden and the woods is 450m.

Let d represent the distance between the turtle's garden and the hedgehog's wood

Let h represent the  speed of the hedgehog

Let the  turtle's speed = h-10

Le the time it takes for the hedgehog to walk from the woods to the meeting point= t

Set up two equations

d = (h-10)(t+4.5) + ht (Equation 1)

d - 150 = ht (Equation 2)

Solve for d by substituting equation 2 into equation 1:

ht + (h-10)(t+4.5) = ht + 150

(h-10)t + 45h = 150

t = (150 - 45h) / (h-10)

Substitute t into equation 2:

d = ht + 150 - (h-10)(t+4.5)

d = h(150 - 45h)/(h-10) + 150 - (h-10)(45h/(h-10) + 4.5)

d = 2250/(h-10) (distance between the garden and the woods)

Since the turtle and hedgehog meet in 5 hours

Thus,

d = ( h-10 ) (5) + h( 5- 4.5 )

d = 5h - 25

Substitute

5h - 25 = 2250/(h-10)

Multiplying both sides by h-10

5h² - 75h + 250 = 0

Dividing both sides by 5

h²- 15h + 50 = 0

Using the quadratic formula

h = (15 ± sqrt(15^2 - 4(1)(50))) / (2*1)

h = (15 ± 5) / 2

So,

h = 10 or h = 5

Distance between the garden and the woods :

d = 2250/(h-10)

d= 2250/(5-10)

= 450 meters

Therefore the distance is 450m.

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The probability that an eighth-grade girl will have long hair and be wearing a dress is 3/8 or 0.375, which is the same thing expressed as a decimal.

what is probability?

Probability is a measure of the likelihood of an event occurring. It is a number between 0 and 1, where 0 means the event is impossible and 1 means the event is certain to happen.

To solve the problem, we need to find the intersection of the events "having long hair" and "wearing a dress" and calculate the probability of that intersection.

Let L be the event "having long hair" and D be the event "wearing a dress". Then we know:

P(L) = 3/4, since three-fourths of the girls have long hair.

P(D) = 1/2, since half of the girls are wearing dresses.

To find P(L ∩ D), we need to multiply the probabilities of the two events:

P(L ∩ D) = P(L) × P(D) = (3/4) × (1/2) = 3/8

Therefore, the probability that an eighth grade girl will have long hair and be wearing a dress is 3/8 or 0.375, which is the same thing expressed as a decimal.

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Answer:

f(x) = x²-8x+15

g(x) = x -3

h(x) = f(x) ÷ g(x)

= x²-8x+15 ÷ x-3

x-3√x²- 8x +15 | x-5

x² - 3x

-5x + 15

- 5x + 15

-----------

h(x) = x-5

Answer:

Step-by-step explanation:

Answer:

its 112.7

Step-by-step explanation:

x+2x=3x. 3x = 338

divide 3x and 338 by 3 three is cancelled and x equals to 112.7

[tex]\sf x=13.[/tex]

Assuming that the canvas has a standard rectangle shape, the area should be given by: [tex]\sf A= bh[/tex], where "b" is the base length of the rectangle, and "h" its heignt.

We're told that the canvas is "x" inches wide, and that the length of it is "twice as long as the width", thus it is "2x". Now, let's take width as the base, and length as the height.

Since the formula for area is just a product between width and length, and those values are "x" and "2x", respectively, the formula for the area of this canvas is:

[tex]\sf (x)(2x)=338(in^{2} )[/tex]

a) Solve the product.

[tex]\sf (x)(2x)=338(in^{2} )\\ \\\sf 2x^{2} =338(in^{2} )[/tex]

b) Divide by "2" on both sides of the equation.

[tex]\sf \dfrac{2x^{2}}{2} =\dfrac{338(in^{2} )}{2} \\ \\x^{2} =169[/tex]

c) Take the square root of both sides.

[tex]\sf \sqrt{x^{2}} =\sqrt{169} \\ \\x=13[/tex]

[tex]\sf x=13.[/tex]

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Amy's total cost: $697.26

Mackenzie's total cost: $11904.62

Amount = P = 340

Amy's interest rate = ra = 6% = 0.06

Mackenzie's interest rate = rm = 30% = 0.3

Amount is compounded yearly.

Amount at the end of the year is calulated as

Pn= P(1+r)

We will use Excel to fill given table

Person APR 0 1 2 3 6

Amy 6% 340.00 360.40 382.02 404.95 482.30

Mackenzie 30% 340.00 442.00 574.60 746.98 1641.12

Amy has an annual rate of 6%. So Amy has a monthly rate of 6 /12 = 0.5% = 0.005

Mackenzie has an annual rate of 30%. So Mackenzie has a monthly rate of 30/12 = 2.5% = 0.025

Pn= P(1+r)

Here will be replaced by a number of months and r is relaced by monthly interest rate

We can modified this formula as

12n

Pn= P(1+)

Where n and r is same as in first part of question.

We will use excel to fill given table

Person APR 0 1 2 3 6

Amy 6% 340.00 360.97 383.23 406.87 486.90

Mackenzie 30% 340.00 457.26 614.97 827.06 2011.86

From the above two tables, it is clear that it does matter how the company charges interest. When compounded monthly, the amount will more as compared to when compounded yearly. So,

Yes it matters because the more often they calculate the interest the higher the amount goes.

If neither friend made any payments for 12 years, we can add one more column to calculate for n = 12.

Amy's total cost: $697.26

Mackenzie's total cost: $11904.62

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Answer:

The first spinner has a 1/3 chance of not showing an odd number, and the second spinner has a 1/4 chance of showing a 3. The probability of both events happening is:

1/3 x 1/4 = 1/12

Therefore, there is a 1/12 chance of an outcome showing a 3 on the second spinner and not showing an odd number on the first spinner. Since there are a total of 3 x 4 = 12 possible outcomes, the number of outcomes that meet the criteria is:

12 x 1/12 = 1

So there is only one outcome that meets the criteria.

Answer:

C

Step-by-step explanation:

The equation is:

y = [tex]\frac{1}{4}[/tex]x - 8

If you plug in the x and y value from the table, you find they are solutions to the equation.

(36,1)

y = [tex]\frac{1}{4}[/tex]x - 8  Substitute in 36 for x and 1 for y

1 = [tex]\frac{1}{4}[/tex](36) - 8

1 = 9 - 8

1 = 1

You can do the same thing for all of the other points on the table.

Helping in the name of Jesus.

Answer:

congruent to each other cause their measurements are same.

congruent means if 2 shapes have same measurements they are called congruent