The histogram to the right represents the weights​ (in pounds) of members of a certain​ high-school math team.
How many team members are included in the​ histogram?

There were 144 students when the contest began

Equation is formed when an algebraic expression is equated by a constant or another algebraic expression.

On the basis of given data :

Let the total number of students are x

50% of the students are eliminated after the first round

the remaining students are 0.5x

After the second round = (1/3) * 0.5 x were remaining

and

(1/3) * 0.5 x = 24

then solving this equation will give the total number of students

0.5x = 24 * 3

x = 24*3 /0.5 = 144

Therefore there were 144 students when the contest began

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When two parallel lines are cut by a transverse. the angles formed on the exterior of the parallel lines, on the opposite sides of the transverse are known as the Alternate Exterior Angle.

When two parallel lines are cut by a transverse. the angles formed on the exterior of the parallel lines, on the opposite sides of the transverse are known as the Alternate Exterior Angle.

Firstly, ∠1 and ∠7 are alternate exterior angles as shown in the image, now to prove if these two angles will be congruent we can use the below proof.

First Method:

∠1  + ∠2 = 180° {Supplementary angles because both lies on the line q}

∠2 = (180° - ∠1)

Similarly, ∠2 = ∠6 = (180° - ∠1), corresponding angles are equal,

∠6 + ∠7 = 180° {Supplementary angles because both lies on the line r}

∠7 = 180° - ∠6

∠7 = 180° - (180° - ∠1)

∠7 = 180° - 180° + ∠1

∠7 = ∠1

OR

Second Method:

∠1 = ∠3 {Vertical angles formed by intersecting lines q and r}

∠3 = ∠5 {Alternate Interior angles}

∠5 = ∠7 {Vertical angles formed by intersecting lines s and r}

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I don't understand your question

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \:\approx 9.2 \:\: units [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex] \textsf{Using distance formula : - } [/tex]

[tex]\qquad \tt \rightarrow \: \sqrt{(x_2 - x_1) {}^{2} + (y_2 - y_1) {}^{2} } [/tex]

[tex]\qquad \tt \rightarrow \: \sqrt{(2 - 0) {}^{2} + (0 - 9) {}^{2} } [/tex]

[tex]\qquad \tt \rightarrow \: \sqrt{(2) {}^{2} + (- 9) {}^{2} } [/tex]

[tex]\qquad \tt \rightarrow \: \sqrt{ 4 + 81} [/tex]

[tex]\qquad \tt \rightarrow \: \sqrt{85} \: \: units[/tex]

[tex]\qquad \tt \rightarrow \: \approx 9.2 \: \: units[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

The distance between points A and B is 9.2 units.

We have,

To find the distance between two points (a, b) and (c, d) in a coordinate plane, you can use the distance formula:

Distance = √[(c - a)² + (d - b)²]

In this case, point A is (2, 0) and point B is (0, 9).

Now, plug the values into the distance formula:

Distance = √[(0 - 2)² + (9 - 0)²]

Distance = √[(-2)² + 9²]

Distance = √[4 + 81]

Distance = √85

Now, round the answer to the nearest tenth:

Distance ≈ √85 ≈ 9.2 (rounded to the nearest tenth)

Thus,

The distance between points A and B is 9.2 units.

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Answer:

8 in

Step-by-step explanation:

Volume of Cube = 512 in³

Formula : -

Volume of cube = side x side x side = side³

512 = 8 x 8 x 8 = 8³

So,

The length of one side of the jewelry box is 8 in.

Answer:

19/54

Step-by-step explanation:

- 7/27 + 11/18

LCM of the 27, 18 is 54

- 7/27 * (2/2) + 11/18 * (3/3)

- 14/54 + 33/54

33 - 14/54

19/54

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An expression is defined as a set of numbers, variables, and mathematical operations. The correct option is C.

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

Juanita’s salary once she completes 10 years, her salary will be increased to 3 times what she makes now plus $2,000. Now, if her salary is represented by s, then the expression that would represent her salary after 10 years is,

Salary after 10 years = 3s + 2000

Hence, the correct option is C.

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Answer:

C

Step-by-step explanation:

Answer:

[tex] 19\% \: of \: 49[/tex]

[tex] \frac{19}{100} \times 49[/tex]

[tex]0.19 \times 49[/tex]

[tex]9.13[/tex]

Answer:

39.69

Step-by-step explanation:

A percentage is on a scale of 100 so we divide 19 by 100

that makes 0.19.

Then multiply 49 with 0.19 that makes 9.31 (this is 19% of 49)

49 - 9.31 = 39.69

Answer:

D.) x = − ½, x = 4

Explanation:

[tex]\rightarrow \sf (10x + 5)(11x - 44) = 0[/tex]

set the factors to zero

[tex]\rightarrow \sf 10x + 5 = 0, \ 11x - 44 = 0[/tex]

exchange the sides

[tex]\rightarrow \sf 10x = -5, \ 11x = 44[/tex]

exchange the sides

[tex]\rightarrow \sf x = -\dfrac{5}{10} , \ x = \dfrac{44}{11}[/tex]

simplify the following

[tex]\rightarrow \sf x = -\dfrac{1}{2} , \ x =4[/tex]

On solving

Let's take this problem step-by-step:

Let's convert the equation back into the standard form:

     ⇒ standard form: (x-h)² +(y-k)² = r²

       [tex]x^2+y^2-8x+10y + 37 = 0\\\rm \hookrightarrow x^2 - 8x + y^2+10y = -37\\\rm \hookrightarrow (x^2 - 8x) + (y^2 + 10y) = -37\\\rm \hookrightarrow (x^2-8x+16) + (y^2+10y+25) = -37 + 16 +25\\\rm \hookrightarrow (x-4)^2 + (y+5)^2 = 4\\\rm \hookrightarrow (x-4)^2 + (y+5)^2 = 2^2[/tex]

Based on the equation found

  ⇒ center: (4, -5)

   ⇒ radius: 2

Answer:

Hope that helps!

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Answer:

42.3cm

Step-by-step explanation:

I think this is right :)

An equation is formed of two equal expressions. Shaquana earns $10 less per hour than Vani.

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The equation y=28.8x represents Vani's earnings in dollars and cents, y, for working x hours.

y = 28.8x

y/x = 28.8

Hence, Vani is paid $28.8 per hour.

The amount that Shaquana earned was $653.40 in 33 hours. Therefore, per hour she was paid

Amount per hour = $653.40/33 = $19.8 per hour

The difference between the two is,

Difference = $28.8 - $19.8 = $10

Hence, Shaquana earns $10 less per hour than Vani.

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Vani - 28.8

y=28.8x

Vani earns $28.80 per hour.

Shaquana -

653.40 / 33 = $19.80 per hour

Shaquana earns $19.80 per hour.

Vani − Shaquana = $28.80

$28.80−$19.80

=$9

Shaquana earns $9 less per hour than Vani.

Answer:

i don't know

Step-by-step explanation:

i

Answer:

B

Step-by-step explanation:

This is quite a trial and error question.

Given from the table

$1 cost of item = $0.08 tax on item

$2 cost of item = ($0.08x2) tax on item = $0.16 tax on item

$3 cost of item = ($0.08x3) tax on item = $0.24 tax on item

$8.50 cost of item = ($0.08x8.50) tax on item =  $0.68 tax on item

$10 cost of item = ($0.08x10) tax on item = $0.80 tax on item

The only one that is different is the incorrect value therefore $0.64 is the incorrect one.

Answer:

Step-by-step explanation:

2.5

4 quarts per gallon

8 quarts per 2 gallons

2 quarts is half a gallon since 4 quarts is a full gallon

answer: 2.5

Answer:

[tex]98 \pi \:\: \sf units^2[/tex]

Step-by-step explanation:

[tex]\textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}[/tex]

From inspection of the given diagram, circle C and circle D both have a radius of 7 cm.

Therefore:

[tex]\implies \textsf{Area of circle C}=\pi (7)^2=49 \pi \:\: \sf cm^2[/tex]

[tex]\implies \textsf{Area of circle D}=\pi (7)^2=49 \pi \:\: \sf cm^2[/tex]

Therefore, the sum of the areas of circle and circle D is:

[tex]\implies \textsf{Area of circle C}+\textsf{Area of circle D}=49 \pi + 49 \pi = 98 \pi \:\: \sf cm^2[/tex]

The sum of the areas of the circles is 98π units².

The correct option is D.

A circle is a closed, two-dimensional object where every point in the plane is equally spaced from a central point. The line of reflection symmetry is formed by all lines that traverse the circle.

And the general formula of the circle,

(x – h)²+ (y - k)² = r²,

where (h, k) is the center and r is the radius of the circle.

The formula for the area of a circle is A=πr², where A is the area and r is the radius.

For circle C, the radius is 7, so its area is A_C = π(7)² = 49π units².

For circle D, the radius is also 7, so its area is A_D = π(7)² = 49π units².

The sum of the areas is therefore:

A_C + A_D = 49π + 49π = 98π units²

Therefore, the answer is (D) 98π units².

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Answer:

Hello auggggh nice to meet you!

Step-by-step explanation:

If 30 is half price, then what is full price?

You can set up this problem like this:

30 = x/2

OR

30 = (1/2)x

where x is the full price.

To solve, simply multiply each half by 2:

2(30) = 2((1/2)x)

x = $60

Answer:

2 angles are 142 degrees

2 angles are 38 degrees

Step-by-step explanation:

In any parallelogram, the opposite angles are congruent.

So,

5x - 8 = 2x + 82

3x - 8 = 82

3x = 90

x = 30

Now lets plug in x into one of the angles:

5 ( 30 ) - 8

150-8

142

So, because that angle is 142, the other angle must also be 142. However, to make sure, we should still check.

2 ( 30 ) + 82

60 +82

142

As we can see, both angles are 142.

Now we have figured out 2 angles, and they are both 142. Now lets figure out the other 2 angles.

Any 4 sided shape has 360 degrees

142 + 142 = 284 degrees

Our 2 angles have 284  degrees in total.

if we subtract 284 from 360, we get 76.

Our remaining 2 angles have a total of 76 degrees. Because these angles are also opposite, we must divide by 2. 76/2 is 38.

So,

2 angles are 142 degrees

2 angles are 38 degrees

The tension in both cables are calculated as; T₁ = 127.63 N and T₂ = 185.48 N

Resolving forces in the y direction gives us;

T₁ sin 29° + T₂ sin 53° = 210  ------(eq 1)

Resolving forces in the horizontal direction gives;

T₁ cos 29° = T₂ cos 53°   ----(eq 2)

T₁ = T₂ cos 53°/cos 29°

Thus;

(T₂ cos 53°/cos 29°)sin 29° + T₂ sin 53° = 210  

0.3336T₂ + 0.7986T₂ = 210

T₂ = 210/1.1322

T₂ = 185.48 N

Thus;

T₁ = 185.48 cos 53°/cos 29°

T₁ = 127.63 N

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Solution:

[tex]\dfrac{\left[\left(\sin ^{2} A+2 \times \sin A \times (1-\cos A)+(1-\cos A)^{2}\right]\right.}{\left[\left(1-\cos ^{2} A\right)-(1-\cos A)^{2}\right]}[/tex]

[tex]\dfrac{\left[\left(1-\cos ^{2} A\right)+2 \times \sin A \times (1-\cos A)+(1-\cos A)^{2}\right]}{\left[(1-\cos A)(1+\cos A)-(1-\cos A)^{2}\right]} [/tex]

[tex]\dfrac{(1-\cos A)[1+\cos A+2 \sin A+1-\cos A]}{[1-\cos A][1+\cos A-1+\cos A]} [/tex]

[tex]\dfrac{[2+2 \sin A]}{[2 \times \cos A]}[/tex]

[tex]\dfrac{2(1+\sin A)}{2 \times \cos A}[/tex]

[tex]\dfrac{1+\cos A}{\sin A} [/tex]

Hence Proved.

Answer:

[tex]-75x^{7}y^{9}[/tex]

Step-by-step explanation:

[tex] {3}^{18n} [/tex]

Answer:

9^10

Step-by-step explanation:

khan

The value of y for the given equation at x=81 is 87.

Equations are mathematical statements containing two algebraic expressions on both sides of an 'equal to (=)' sign.

Here, given equation;

       y = x + 6

     Put x = 81, we get

       y = 81 + 6

      y = 87

Thus, the value of y for the given equation at x=81 is 87.

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Answer:

Look down below and you will know the answer↓:

Step-by-step explanation:

He will have to work as between the range (of 20,0) and (0,20) points to earn more than $125.

So, What is inequality?

Inequality means is the relationship between two expressions that are not equal, so employing a sign such as ≠ “is not equal to,” > “greater than,” or < “less than.”.

Since then: Liam can work at most 20 hours a week, but he also needs to earn at least $125. His dog-walking job pays $7 per hour and his job as a car-wash attendant pays $11 dollars an hour. How can he earn $125.

He Let the Dog walking hours are represented by x and Car wash hours will be represented by y. The inequality will be formed as:

7x + 11y ≥ 125

x+y = 20

When we plot these two equations on the graph, we will get the range for the time from (20,0) and (0,20).

We Suppose that we will take a random point-like (5,15) when we put this value in the inequality, we get the total earning greater than $125.

7x + 11y ≥ 125

7 (5) + 11 ( 15 ) ≥ 125

35  + 165  ≥ 125

200 ≥ 125

Therefore, He has to work between the range (of 20,0) and (0,20) points to earn more than $125.

The substance's half-life is 5.5 days if the 11-gram sample of a substance that’s used to treat thyroid disorders has a k- the value of 0.125

During exponential decay, a quantity falls slowly at first before rapidly decreasing. The exponential decay formula is used to calculate population decline and can also be used to calculate half-life.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have an exponential function:

[tex]\rm N = N_oe^{-kt}[/tex]

Plug N = N⁰/2

[tex]\rm N_o/2 = N_oe^{-kt}[/tex]

[tex]\rm \dfrac{1}{2} = e^{-0.125t}[/tex]

Solving for t:

t = 5.54 ≈ 5.5 days

Thus, the substance's half-life is 5.5 days if the 11-gram sample of a substance that’s used to treat thyroid disorders has a k- the value of 0.125

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Answer: I love the picture example

Step-by-step explanation:

We will first find the heigh of the kite from his hand to a point in the air.

Then, we will add 3 feet to the result.

So, how to find the vertical line of the right triangle?

Well, we have the vertical line = x

We also got the hypothenuse, equal to 100 feet

And also theta, equal to 25 degrees.

We can calculate sine because the sine of 25 degrees = opposite side (the height line) over (divided by) the hypothenuse

sin(25) = x/100 feet

multiply 100 feet on both sides, to cancel to 100 feet on the right side.

100sin(25) = x

100(0.442) = x

x = 42.2  feet

Height = 42.2 + 3 feet (the yoda's hand =) =  45.2 feet (total)

Rounded to the nearest tenth.

I also did the verification, so it is the correct answer.

Easy as that =]]

Height of the kite from 3ft above the ground

[tex]\\ \rm\Rrightarrow sin\Theta=\dfrac{Perpendicular}{Hypotenuse}[/tex]

[tex]\\ \rm\Rrightarrow sin25=\dfrac{P}{100}[/tex]

[tex]\\ \rm\Rrightarrow P=100sin25[/tex]

[tex]\\ \rm\Rrightarrow P=42.26\approx 42ft[/tex]

Height from the ground