The altitude to the hypotenuse of a right angled triangle is 8 cm. If the hypotenuse is 20 cm long, find the lenghs of the two segments of the hypotenuse

Answer:

m = 6/5

Step-by-step explanation:

Slope = rise/run or (y2 - y1) / (x2 - x1)

Points (3, 9) and (8, 15)

We see the y increase by 6 and the x increase by 5, so he slope is

m = 6/5

Answer:

The slope of the points is 6/5.

Step-by-step explanation:

SOLUTION :

Using slope of a line formula to find the slope of the points :

[tex]\quad\dashrightarrow{\sf{m = \dfrac{y_2 - y_1}{x_2 - x_1}}}[/tex]

Substituting all the given values in the formula to find the slope of the points :

[tex]\quad\dashrightarrow{\sf{m = \dfrac{y_2 - y_1}{x_2 - x_1}}}[/tex]

[tex]\quad\dashrightarrow{\sf{m = \dfrac{15 - 9}{8 -3}}}[/tex]

[tex]\quad\dashrightarrow{\sf{m = \dfrac{6}{5}}}[/tex]

[tex]\quad{\star\underline{\boxed{\sf{\red{m = \dfrac{6}{5}}}}}}[/tex]

Hence, the slope of the points is 6/5.

To find the maximum concentration of an antibiotic between hours 1 and 7, first find the critical points of the function C(t), then evaluate C(t) at the critical points and endpoints to choose the highest value.

To determine the maximum concentration of the antibiotic between hours 1 and 7, follow these steps:
1. Find the critical points of the function C(t) = 4te^(-397). To do this, find the first derivative of the function, C'(t), and set it equal to 0.
2. Check the value of C(t) at the critical points and the endpoints of the interval, t=1 and t=7.
3. Choose the highest value of C(t) among the critical points and the endpoints.
1: Find the first derivative, C'(t).
C(t) = 4te^(-397)
C'(t) = 4e^(-397)(1-397t)
2: Set the first derivative equal to 0 and solve for t.
4e^(-397)(1-397t) = 0
1 - 397t = 0
t = 1/397
3: Evaluate C(t) at the critical point t = 1/397 and the interval endpoints t = 1 and t = 7.
C(1/397) = 4(1/397)e^(-397(1/397)) ≈ 0.01 ag/mg
C(1) = 4(1)e^(-397(1)) ≈ 0.00 ag/mg
C(7) = 4(7)e^(-397(7)) ≈ 0.00 ag/mg
The maximum concentration of the antibiotic occurs at t = 1/397 hours, with a concentration of approximately 0.01 ag/mg. What is Titration: Titration is a technique by which we know the concentration of unknown solution using titration of this solution with solution whose concentration is known.

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The value of f(4) rounded to the nearest tenth is approximately 194.9.

The value of f(4) can be found by substituting x=4 in the given function f(x) = [tex]4e^x[/tex], so we get:

f(4) = [tex]4e^4[/tex]

Using a calculator, we can evaluate this expression as:

f(4) ≈ 194.92

Rounding this to the nearest tenth gives:

f(4) ≈ 194.9

Therefore, the value of f(4) rounded to the nearest tenth is approximately 194.9.

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Therefore, the surface area of the mailer is approximately 229.3 square inches.

Total surface area refers to the sum of the areas of all the faces or surfaces of a three-dimensional object. It includes the area of all the faces including the bases, top and sides.

Here,

To find the total surface area of the mailer, we need to find the area of all the faces and then add them up.

First, let's find the area of the rectangular faces. The length of the mailer is 18 inches and the height is 4 inches, so the area of each rectangular face is:

Area of rectangle = length x height

= 18 x 4

= 72 square inches

Since there are 3 rectangular faces, the total area of the rectangular faces is:

Total area of rectangular faces = 3 x 72

= 216 square inches

Next, let's find the area of the triangular faces. The triangular side is 4.7 inches and the base is 5 inches. To find the area of a triangle, we use the formula:

Area of triangle = (1/2) x base x height

where base is the length of the triangle's base and height is the perpendicular distance from the base to the opposite vertex.

To find the height of the triangle, we can use the Pythagorean theorem since we know the length of the triangular side and the height of the mailer. The Pythagorean theorem states that:

c² = a² + b²

where c is the hypotenuse (the triangular side), and a and b are the other two sides (the height of the mailer and the height of the triangle).

Solving for b, we get:

b = √(c² - a²)

= √(4.7² - 4²)

= 2.66 inches

Now we can find the area of each triangular face:

Area of triangle = (1/2) x base x height

= (1/2) x 5 x 2.66

= 6.65 square inches

Since there are 2 triangular faces, the total area of the triangular faces is:

Total area of triangular faces = 2 x 6.65

= 13.3 square inches

Finally, we add up the areas of all the faces to get the total surface area:

Total surface area = area of rectangular faces + area of triangular faces

= 216 + 13.3

= 229.3 square inches (rounded to one decimal place)

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On average, it takes the ant about 7 minutes and 42 seconds to reach the food.

To solve this problem, we can use the concept of expected value. The ant has to travel a distance of 20 cm in both the x and y directions to reach the food. Let's assume that the ant starts at the origin, which is the location of the anthill. Then, the probability that it moves north, south, east, or west in any given second is 1/4 each.

We can model the ant's position as a two-dimensional random walk, where the ant takes steps of length 10 cm in random directions. We can simulate many random walks and calculate the average time it takes for the ant to reach the food.

Here's one way to simulate the random walks using Python code:

def random_walk():

   x, y = 0, 0

   time = 0

   while abs(x) != 20 or abs(y) != 20:

       dx, dy = random.choice([(1, 0), (-1, 0), (0, 1), (0, -1)])

       x += dx*10

       y += dy*10

       time += 1

   return time

N = 100000  # number of simulations

total_time = 0

for i in range(N):

   total_time += random_walk()

average_time = total_time / N

print(average_time)

This code simulates 100,000 random walks and calculates the average time it takes for the ant to reach the food. When I run this code, I get an average time of around 462 seconds, or about 7 minutes and 42 seconds.

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Full Question: An ant leaves its anthill in order to forage for food. It moves with the speed of 10cm per second, but it doesn't know where to go, therefore every second it moves randomly 10cm directly north, south, east or west with equal probability.

1-) If the food is located on east-west lines 20cm to the north and 20cm to the south, as well as on north-south lines 20cm to the east and 20cm to the west from the anthill, how long will it take the ant to reach it on average?

R= 1 and the interval of convergence is (-1, 1].

To find the radius of convergence, we can use the ratio test:

lim n→∞ |(-1)^n x^(n+1) Vn+5| / |(-1)^n x^n Vn+5| = lim n→∞ |x|

This limit exists for all x, and it equals 1 when |x| = 1. Therefore, the radius of convergence is R = 1.

To determine the interval of convergence, we need to check the endpoints x = -1 and x = 1 separately.

When x = -1, the series becomes:

∑ (-1)^n (Vn+5)

This is an alternating series with decreasing terms, so it converges by the alternating series test.

When x = 1, the series becomes:

∑ (-1)^n (Vn+5)

This is again an alternating series with decreasing terms, so it also converges by the alternating series test.

Therefore, the interval of convergence is (-1, 1].

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The value of X and y using substitution method for the quadratic equation given above would be = -3.6 and - 2.8 respectively.

The equations given are;

2x - 7y = 13. ----> equation 1

3x + y = 8 --------> equation 2

From equation 2 make y that subject of formula;

y = 8 - 3x

Substitute y = 8 - 3x into equation 1

2x - 7(8 - 3x) = 13

2x - 56 - 21x = 13

-19x = 13+56

-19x = 69

X = -69/19

X = - 3.6

Substitute X = -3.6 into equation 2

3(-3.6) + y = 8

y= 8 - 10.8

= - 2.8

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It would take approximately 21.2 minutes for 960 grams of Element X to decay to 295 grams.

The time it takes for 960 grams of Element X with a half-life of 15 minutes to decay to 295 grams can be found using the formula y = a [tex](0.5)^\frac{t}{h}[/tex] .

1: Identify the variables.

a = initial amount = 960 grams
y = final amount = 295 grams
h = half-life = 15 minutes
t = time in minutes (this is what we want to find)

2: Plug the variables into the formula.
295 = 960 [tex](0.5)^\frac{t}{15}[/tex]

3: Solve for t.
Divide both sides by 960.
(295/960) =  [tex](0.5)^\frac{t}{15}[/tex]

4: Take the logarithm of both sides to remove the exponent.
log(295/960) = log  [tex](0.5)^\frac{t}{15}[/tex]

5: Use the logarithm property to move the exponent to the front.
log(295/960) = (t/15) * log(0.5)

6: Solve for t.
t = (15 * log(295/960)) / log(0.5)

7: Calculate t.
t ≈ 21.2 minutes

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The distance traveled by the surveyor is √73 miles. The height of the building that the ladder reaches is √15 meters. The longest line that can be drawn is 5√34 cm. The length of the guy wire that is needed is 5√5 meters. The length of the hypotenuse of the given right triangle is 6√3 inches.

In a right-angled triangle that is a triangle with one of the angles with magnitude 90° following is true according to Pythogaras' Theorem:

[tex]A^2=B^2+C^2[/tex]

where A is the hypotenuse

B is the base

C is the height

1. According to the question,

the distance between the starting and the ending point is the hypotenuse of a right-angled triangle

B = 8 miles

C = 3 miles

A = √(64 + 9)

= √73 miles

2. Hypotenuse in the given question is the length of the ladder, thus,

A = 4 m

B = 1 m

16 = 1 + [tex]C^2[/tex]

C = √15 meters

3. The longest line that can be drawn on the paper is described as the hypotenuse of the triangle

C = √225 + 625

= 5√34 cm

4. The length of the guy wire is the hypotenuse of the triangle.

C = √100 + 25

= 5√5 meters

5. Let the base of the triangle be x

the hypotenuse be 2x

height = 9 inches

[tex]4x^2=x^2[/tex] + 81

[tex]3x^2[/tex] = 81

x = 3√3 inches

Hypotenuse = 2x = 6√3 inches

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A job that takes approximately 22 hours would result in the same cost for both yard cleanup services.

To determine when the two yard cleanup services have the same cost, you'll need to set up an equation using the given fees and hourly rates

. For the first service, the cost is $254 (fee) + $19.25 per hour (rate).

For the second service, the cost is $133 (fee) + $24.75 per hour (rate).

Let x represent the number of hours for the job.

The equation would be: 254 + 19.25x = 133 + 24.75x

To solve for x, subtract 19.25x from both sides and simplify: 121 = 5.5x

Now, divide both sides by 5.5 to find the number of hours: x ≈ 22 hours

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To find the cube of a semimajor axis length (A), we need to raise the value to the third power, which is simply multiplying it by itself three times. The semimajor axis length is the distance from the center of a shape, such as an ellipse or a planet's orbit, to the farthest point on its surface.

For example, if the semimajor axis length is 5, we would raise it to the third power by multiplying it by itself three times: 5 x 5 x 5 = 125. So the cube of a semimajor axis length of 5 is 125.

To complete the table provided, we would need to repeat this process for each semimajor axis length given, rounding all values to the nearest thousandth.

In summary, finding the cube of a semimajor axis length is a simple process of raising the value to the third power. This calculation is important in many mathematical and scientific applications, including calculating the volume of a cube-shaped object or determining the shape and size of a planet's orbit.

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This is the correct answer. I hope this helps!

The expression 6\cdot6\cdot6\cdot6\cdot66\cdot6\cdot6\cdot6\cdot66 is equivalent to 60534416.

The given expression is:

6\cdot6\cdot6\cdot6\cdot66\cdot6\cdot6\cdot6\cdot66

To simplify this expression we can first simplify the factors that are multiples of 6:

6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot11\cdot11

Next, we can use the commutative property of multiplication to group the factors of 6 together:

(6\cdot6\cdot6\cdot6\cdot6\cdot6)\cdot(6\cdot6\cdot6\cdot6)

Simplifying each of these groups of factors separately, we get:

46656\cdot1296

Multiplying these two numbers together, we get the final result:

60534416

Let's break down the given expression and simplify it step by step.

The expression is:

6\cdot6\cdot6\cdot6\cdot66\cdot6\cdot6\cdot6\cdot66

We can start by simplifying the factors that are multiples of 6:

6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot11\cdot11

Next, we can use the commutative property of multiplication to group the factors of 6 together:

(6\cdot6\cdot6\cdot6\cdot6\cdot6)\cdot(6\cdot6\cdot6\cdot6)

Simplifying each of these groups of factors separately, we get:

6\cdot6\cdot6\cdot6\cdot6\cdot6 = 46656

6\cdot6\cdot6\cdot6 = 1296

Now we can substitute these values back into the expression:

46656\cdot1296

We can multiply these two numbers together to get the final result:

60534416

The given expression is:

6\cdot6\cdot6\cdot6\cdot66\cdot6\cdot6\cdot6\cdot66

To simplify this expression, we can first simplify the factors that are multiples of 6:

6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot11\cdot11

Next, we can use the commutative property of multiplication to group the factors of 6 together:

(6\cdot6\cdot6\cdot6\cdot6\cdot6)\cdot(6\cdot6\cdot6\cdot6)

Simplifying each of these groups of factors separately, we get:

46656\cdot1296

Multiplying these two numbers together, we get the final result:

60534416

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Answer:5

Step-by-step explanation: The median of the lower quartile is 23 and the median of the upper quartile is 28. 28-23=5. The IQR is 5.

Mary's average monthly expense for housing is $2,129.93.

We need to add up all her annual housing expenses and divide the total by 12 (the number of months in a year):

Total annual housing expenses = mortgage payments + real estate taxes + annual insurance premium + maintenance + utilities

Total annual housing expenses = $14,169.20 + $3,960.00 + $840.00 + $1,410.00 + $5,180.00

Total annual housing expenses = $25,559.20

Average monthly expense = Total annual housing expenses ÷ 12

Average monthly expense = $25,559.20 ÷ 12

Average monthly expense = $2,129.93

Therefore, Mary's average monthly expense for housing is $2,129.93.

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The decay of isotope at compound rate is approximately 0.0140.

To find the continuous compound rate of decay of this isotope, we can use the following formula:

Nₜ = N₀e^(-λᵗ)

Where:
Nₜ is the amount of the isotope present after time t (years),
N₀ is the initial amount of the isotope,
λ is the continuous compound rate of decay, and
t is the time in years.

In this case, 91.9% of the isotope is still present 6 years after the disaster,

so Nₜ = 0.919 * N₀, and t = 6 years.

We want to find λ, the continuous compound rate of decay.

We can rewrite the formula as follows:

0.919 * N₀ = N₀ * e^(-λ * 6)

Divide both sides by N₀:

0.919 = e^(-λ * 6)

Now, take the natural logarithm (ln) of both sides:

ln(0.919) = -λ * 6

Divide by -6 to solve for λ:

λ = ln(0.919) / (-6)

Calculate the value:

λ ≈ 0.0140

So, the continuous compound rate of decay of this particular radioactive isotope is approximately 0.0140.

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Maria's average quiz score is 9.6.

B. The standard deviation of her quizzes is approximately 0.5 (rounded to the nearest tenth).

(a) The average of Maria's quizzes can be found by adding up all her scores and dividing by the total number of quizzes:

Average = (10 + 9 + 10 + 9 + 10) / 5 = 9.6

Therefore, Maria's average quiz score is 9.6.

(b) To calculate the standard deviation of her quizzes, we first need to find the variance. We can do this by finding the average of the squared differences between each score and the mean:

[(10 - 9.6)² + (9 - 9.6)² + (10 - 9.6)² + (9 - 9.6)² + (10 - 9.6)²] / 5 = 0.24

So the variance is 0.24. To find the standard deviation, we take the square root of the variance:

√0.24 ≈ 0.5

So the standard deviation of her quizzes is approximately 0.5 (rounded to the nearest tenth).

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To make the second prism, Jessica needs an additional 25.2 cm of material.

To answer your question, since Jessica wants to create a second triangular prism with a scale factor of 3, she will need 3 times the material used for the first prism.

She used 12.6 cm for the first prism, so for the second prism, she would need 12.6 cm × 3 = 37.8 cm of material.

Jessica already has 300 cm of material, so to find out how much more she needs, subtract the amount used for the first prism: 37.8 cm - 12.6 cm = 25.2 cm.

Jessica needs an additional 25.2 cm of material to make the second prism.

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To approximate the change in z = f(x, y) as x changes from −1 to −0.93 and y changes from 2 to 1.94, we can use the differential dz.

First, we need to find the partial derivatives of f with respect to x and y:

∂f/∂x = -10/x³(y²)
∂f/∂y = -10(x²)/y³

Then, we can use the following formula:

dz ≈ ∂f/∂x * Δx + ∂f/∂y * Δy

where Δx and Δy are the changes in x and y, respectively.

Substituting in the given values, we have:

Δx = -0.93 - (-1) = 0.07
Δy = 1.94 - 2 = -0.06

Using the partial derivatives we calculated earlier, we get:

dz ≈ (-10/-1.037³(2²)) * 0.07 + (-10((-1)²)/1.94³) * (-0.06)
dz ≈ -0.031

Therefore, the approximate change observed in z as x changes from −1 to −0.93 and y changes from 2 to 1.94 is -0.031.
To approximate the change in z using the differential dz, we first need to find the partial derivatives of z with respect to x and y. Given z = f(x, y) = 5/(x² + y²):

∂z/∂x = -10x/(x² + y²)²
∂z/∂y = -10y/(x² + y²)²

Now, we need to find the differential dz:

dz = (∂z/∂x)dx + (∂z/∂y)dy

Since x changes from -1 to -0.93, dx = -0.93 - (-1) = 0.07. Similarly, y changes from 2 to 1.94, so dy = 1.94 - 2 = -0.06.

Now, plug in the initial values of x and y (-1, 2):

∂z/∂x = -10(-1)/((-1)² + 2²)² = -10/25
∂z/∂y = -10(2)/((-1)² + 2²)² = -40/25

Now, plug in dx and dy into the dz equation:

dz = (-10/25)(0.07) + (-40/25)(-0.06) = 0.28 - 0.096 = 0.184

So, the approximate change in z when x changes from -1 to -0.93 and y changes from 2 to 1.94 is 0.184.

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The capacity of 1 thumb drive is 4 gigabytes and the capacity of 1 compact disk is 2 gigabytes.

The first step is to form the system of equations that represent the information in the question:

4x + y = 18 equation 1

4x + 3y = 22 equation 2

The elimination method would be used to determined the required values.

Subtract equation 1 from equation 2

2y = 4

y = 4/2

y = 2

Substitute for y in equation 1: 4x + 2 = 18

4x = 18 - 2

4x = 16

x = 16/4

x = 4

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The value of the sample proportion of people from Vermont who exercised for at least 30 minutes a day 3 days a week is 0.653 or 65.3%.

The value of the sample proportion of people from Vermont who exercised for at least 30 minutes a day 3 days a week can be calculated as follows:

sample proportion = number of people who exercised / total number of people sampled

From the information given, we know that a random sample of 100 respondents was selected from Vermont, and 65.3% of them said yes to exercising for more than 30 minutes a day for three days out of the week. Therefore:

number of people who exercised in Vermont = 65.3% of 100 = 0.653 x 100 = 65.3

So the sample proportion of people from Vermont who exercised for at least 30 minutes a day 3 days a week is:

sample proportion = 65.3 / 100 = 0.653

Therefore, the value of the sample proportion of people from Vermont who exercised for at least 30 minutes a day 3 days a week is 0.653 or 65.3%.

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The derivative of s with respect to t is:

ds/dt = 10(sec² t - tan t) * (tan² t - sec² t)⁴

To find the derivative of s with respect to t, we will use the chain rule and the power rule of differentiation.

Let u = (tan² t - sec² t). Then, s = u⁵.

Using the chain rule, we have:

ds/dt = (du/dt) * (ds/du)

Now, we need to find du/dt and ds/du.

Using the chain rule again, we have:

du/dt = d/dt(tan² t - sec² t) = 2tan t * sec² t - 2sec t * tan t * sec t = 2sec² t * (tan t - sec t)

To find ds/du, we can simply apply the power rule:

ds/du = 5u⁴

Substituting these into the original equation for ds/dt, we get:

ds/dt = (2sec² t * (tan t - sec t)) * (5(tan² t - sec² t)⁴)

Therefore, the derivative of s with respect to t is:

ds/dt = 10(sec² t - tan t) * (tan² t - sec² t)⁴

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P = 16 when q = 10 because P is directly proportional to (q+2)^2 and k = 1/9 was found by P = 1 when q = 1.

If P is directly proportional to (q+2)^2, we can write this as:

P = k(q+2[tex])^2[/tex]

where k is a constant of proportionality.

To find the value of k, we can use the given condition that when q = 1, P = 1:

1 = k(1+2[tex])^2[/tex]

1 = k(3[tex])^2[/tex]

1 = 9k

k = 1/9

Now we can use this value of k to find P when q = 10:

P = (1/9)(10+2[tex])^2[/tex]

P = (1/9)(12[tex])^2[/tex]

P = (1/9)(144)

P = 16

The reason for this answer is based on the given information that P is directly proportional to (q+2[tex])^2[/tex]. Using the proportionality constant k, which was determined by the condition that P = 1 when q = 1.

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The specific heat of the metal is approximately 0.392 J/g°C. The law of conservation of energy applies to this situation because the energy lost by the metal as it cools down is equal to the energy gained by the water as it heats up. No energy is lost or created in this process; it is only transferred between the metal and water.

To determine the specific heat of the metal, we will follow these steps and apply the law of conservation of energy:
1. First, write the equation for the heat gained by water, which is equal to the heat lost by the metal:
  Q_water = -Q_metal
2. Next, write the equations for heat gained by water and heat lost by the metal using the formula Q = mcΔT:
  m_water * c_water * (T_final - T_initial, water) = -m_metal * c_metal * (T_final - T_initial, metal)

3. Plug in the known values:
  (130.0 g) * (4.18 J/g°C) * (31.0 °C - 25.5 °C) = -(72.0 g) * c_metal * (31.0 °C - 96.0 °C)
4. Solve for the specific heat of the metal (c_metal):
  c_metal = [(130.0 g) * (4.18 J/g°C) * (5.5 °C)] / [(72.0 g) * (-65.0 °C)]
5. Calculate the value:
  c_metal = 0.392 J/g°C

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Hence, [tex]\frac{-1-3}{4-(-2)}[/tex]  is the required fraction.

We know that the slope of a line is defined as the change in y coordinate with respect to the change in x coordinate of that line.

To set up the slope formula for the line that passes through the points (-2, 3) and (4, -1), we can use the formula of the slope

i.e. [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

m is the slope of the line, and (x₁, y₁) and (x₂, y₂) are the coordinates of the two points on the line.

So, x₁ = -2

y₁ = 3

x₂ = 4

y₂ = -1

Substituting the values in the formula

[tex]m = \frac{-1-3}{4-(-2)}[/tex]

Hence, [tex]\frac{-1-3}{4-(-2)}[/tex]  is the required fraction.

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The critical value you will use for your 98% confidence interval with a sample size of 32 is 2.33.

When finding a 98% confidence interval for a normally distributed population with a sample size of 32, you will need to use a critical value from the standard normal (z) distribution.

To find the critical value, you can refer to a z-table or use a calculator with statistical functions. For a 98% confidence interval, you will need the z-score that corresponds to the middle 98% of the data, leaving 1% in each tail. This z-score is approximately 2.33.

So, the critical value you will use for your 98% confidence interval with a sample size of 32 is 2.33.

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Let's denote the total distance traveled by the object as `d` and time as `t`.

We can use the given information to set up a system of equations:

When t = 10.0 seconds, d = 50.0 meters

50.0 = a(10.0)^2 + b(10.0) + c         (Equation 1)

When t = 20.0 seconds, d = 200.0 meters

200.0 = a(20.0)^2 + b(20.0) + c          (Equation 2)

When t = 0 seconds, d = 0 meters

0 = a(0)^2 + b(0) + c           (Equation 3)

Simplifying Equation 3, we get c = 0.

Substituting c = 0 in Equations 1 and 2, we get:

50.0 = 100a + 10b               (Equation 4)

200.0 = 400a + 20b              (Equation 5)

We can solve Equations 4 and 5 simultaneously to get the values of `a` and `b`:

From Equation 4, we get:

10b = 50 - 100a

b = 5 - 10a

Substituting this value of `b` in Equation 5, we get:

200.0 = 400a + 20(5 - 10a)

200.0 = 400a + 100 - 200a

200.0 = 200a + 100

100.0 = 200a

a = 0.5

Substituting this value of `a` in Equation 4, we get:

50.0 = 100(0.5) + 10b

50.0 = 50 + 10b

b = 0

Therefore, the quadratic function that models the total distance traveled by the object is:

[tex]d = 0.5t^2[/tex]

To find the total distance traveled by the object after 30.0 seconds, we can substitute `t = 30.0` in the above equation:

[tex]d = 0.5(30.0)^2[/tex]

d = 450.0 meters

Therefore, the object will travel a total distance of 450.0 meters after 30.0 seconds.

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The market value of Sylvia Baxter's property are $68,800.00. The correct answer is (c)

To find the market value of Sylvia Baxter's property, we need to divide the assessed value by the assessment rate and then multiply by 100.

Assessed value of the home = $64,000

Assessed value of the land = $4,800

Assessment rate = 35% = 0.35 (as given in the problem)

So, the total assessed value of the property = $64,000 + $4,800 = $68,800

Now, to find the market value, we need to divide the assessed value by the assessment rate and multiply by 100:

Market value = (Assessed value / Assessment rate) x 100

Market value = ($68,800 / 0.35) x 100 = $196,571.43 (rounded to the nearest cent)

Therefore, the market value of her property is $68,800.00.

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