Answer:
The probability that at least one defective card appears in the sample
P(D) = 0.9644 or 96.44%
Step-by-step explanation:
Given;
Total number of cards t = 140
Number of defective cards = 20
Number of non defective cards x = 140-20 = 120
The probability that at least one defective card = 1 - The probability that none none is defective
P(D) = 1 - P(N) ........1
For 20 selections; r = 20
-- 20 cards are selected from the lot without replacement for functional testing
The probability that none none is defective is;
P(N) = (xPr)/(tPr)
P(N) = (120P20)/(140P20)
P(N) = (120!/(120-20)!)/(140!/(140-20)!)
P(N) = (120!/100!)/(140!/120!) = 0.035618370821
P(N) = 0.0356
The probability that at least one defective card appears in the sample is;
P(D) = 1 - P(N) = 1 - 0.0356 = 0.9644
P(D) = 0.9644 or 96.44%
Note: xPr = x permutation r
Solve the inequality.
-3(x-1) > -3x - 2
Answer:
all real x
Step-by-step explanation:
-3(x-1) > -3x - 2
Distribute
-3x +3> -3x -2
Add 3x to each side
-3x +3 +3x > -3x+3x - 2
3 > -2
This is always true so the inequality is true for all x
Sander bought 5 bags of nuts. Each bag costs $5.69.
How much did Sander spend for the nuts?
Enter your answer in the box.
Answer:
28.45.
Step-by-step explanation:
5 x 5.69
What is the measure of angle 7?
Answer: 95 degrees
Step-by-step explanation:
We can infer than angles 1, 4, 5, 8 are all equal and angles 2, 3, 6, 7 are also equal to eachother. These two sets of angles are supplementary(you’d get 180 by adding them)
So 3x+10=4x-15
if you rearrange you'll get
x=25
therefore angle 1 equals
3*25+10=85
angle 1 and 7 are supplementary
thus angle 7 equals
180-85=95
Using propositional logic to prove that each argument is valid.If Jose took the jewelry or Mrs. Krasov lied, then a crime was committed. Mr. Kraso was not in town. If a crime was committed, then Mr. Krasov was in town. Therefore Jose did not take the jewerly. Use letters J, L, C, T.So for this question, I am very confused and would appreciate any help offerd.
Answer:
Step-by-step explanation:
We will first translate the situation to propositional logic. First, some notation is needed: [tex]\lor[/tex] is the or logical operation and [tex]\implies[/tex] is the symbol for logical implication. Define the following events:
J: Jose took the jewelry. L: Mrs Krasov lied, C: a crime was committed. T: Mr Krasov was in town.
We will symbol the propositions in logical symbols. Recall that [tex]\neg[/tex] means negation
If Jose took the jewelry or Mrs. Krasov lied, then a crime was committed: [tex]J\lor L \implies C[/tex]
Mr. Krasov was not in town: [tex]\neg T[/tex]
If a crime was committed, then Mr. Krasov was in town: [tex]C\implies T[/tex]
We want to check if the conclusion Jose did not take the jewerly: [tex]\neg J[/tex] can be deduced from the premises.
First, recall the following:
- if [tex] a\implies b[/tex] and a is true, then b is true.
- [tex] a\implies b[/tex] is logically equivalent to [tex]\neg b \implies a[/tex]
Coming back to the problem, we have the following premises
[tex]J\lor L \implies C, \neg T, \neg T \implies \neg C, \neg C \implies \neg(J\lor L)[/tex]
where the equivalence for the logical implication was applied. REcall that the negation of an or statement is g iven by
[tex] \neg( a \lor b ) = \neg a \land \neg b [/tex] where [tex] \land[/tex] is the and logical operator.
USing this, we get the premises
[tex]J\lor L \implies C, \neg T, \neg T \implies \neg C, \neg C \implies \neg J\land \neg L[/tex]
Since [tex]\neg T[/tex], by having [tex]\neg T \implies \neg C[/tex], then it must be true that [tex]\neg C[/tex]. Since [tex]\neg C \implies \neg J\land \neg L[/tex], then it must be true that [tex] \neg J\land \neg L[/tex]. This final conclusion implies that it is true that [tex]\neg J[/tex] which is the statement that Jose did not take the jewelry.
A DJ charges a booking fee of $100 and an hourly rate. He made $250 in 5 hours. Which equation shows the amount the DJ charges per hour?
We have a bag containing 4 yellow, 5 green and 6 orange candies. We draw two candies without replacement.
Find the probability of getting both candies green
Answer:
9.52% probability of getting both candies green
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
The order in which the candies are selected is not important. They are also selected without replacement. So we use the combinations formula to solve this question.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
Find the probability of getting both candies green
Desired outcomes:
2 green, from a set of 5. So
[tex]D = C_{5,2} = \frac{5!}{2!3!} = 10[/tex]
Total outcomes:
2 from a set of 4+5+6 = 15. So
[tex]T = C_{15,2} = \frac{15!}{2!13!} = 105[/tex]
Probability:
[tex]p = \frac{D}{T} = \frac{10}{105} = 0.0952[/tex]
9.52% probability of getting both candies green
What’s the correct answer for this question?
Answer:
A. Schaid draws a white sock and a green sock. It did not talk about no green sock
Step-by-step explanation:
Brainliest AppreciatEdThe defect length of a corrosion defect in a pressurized steel pipe is normally distributed with mean value 28 mm and standard deviation 7.6 mm.(a)What is the probability that defect length is at most 20 mm
Answer:
14.69% probability that defect length is at most 20 mm
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 28, \sigma = 7.6[/tex]
What is the probability that defect length is at most 20 mm
This is the pvalue of Z when X = 20. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{20 - 28}{7.6}[/tex]
[tex]Z = -1.05[/tex]
[tex]Z = -1.05[/tex] has a pvalue of 0.1469
14.69% probability that defect length is at most 20 mm
Using the following data on the Observations 10, 13, 4, and 20 confirm that the complete linkage distance between the cluster containing 《10, 13) and the cluster containing (4, 20) s 2.577 units as displayed in the dendrogram
Observation
13 20 0.032 0.195 -0510 0.466 0.741 0.8750.207 0.474 0.700 0.748 -0.004 -0.490 -0.892 0.735 0.219 0.655 -0.1731.013 0.943 0.083 -0.693 -0.489-0.702 -0.458 1.620 2.275 1328 1.733 -0.863 1.035 0.724 0.721 10 Income/Debt Return Cost Load Peak Sales TotalFuelCosts
If required, round your answers to three decimal places.Do not round intermediate calculations
1. Distance from Observation 10 and Observation 4:
2. Distance from Observation 10 and Observation 20:
3. Distance from Observation 13 and Observation 4:
4. Distance from Observation 13 and Observation 20:
Answer:
Step-by-step explanation:
The distance between:
10 and 4: 1.492
10 and 20: 2.055
13 and 4: 2.577
13 and 20: 2.226
The R code:
#Convert your datafile into csv and make sure your row names are 10,13,4 and 20
data=read.csv(file.choose())
data
row.names(data)=c(10,13,4,20)
data
d=dist(data,method="euclidean")
d
fit=hclust(d,method="complete")
plot(fit)
groups=cutree(fit,k=2)
rect.hclust(fit,k=2,border="red")
Antonio burns 75 calories for every 15 minutes
Answer is 5 calories/min
75 divided by 15 is 5
Answer:five cal per min.15 in five groups equals ''75''
Which of these levelers will make it easier to lift the object
Answer:
C
Step-by-step explanation:
Because it would have less weight to carry
Ryan remembers numbers using images that look somewhat like each number: 0 is a ball, 1 is a stick, 2 is a hanger, 3 is a comb, 4 is a kite, etc. Ryan remembered a 4-digit phone extension with this story: A person uses a hanger to pop a ball, then flies two kites. What number is Ryan likely remembering? (1) 2044 or (2) 2042 (3) 2004 or (4) 2204
Answer:
2044
Step-by-step explanation:
just follow the story
a person uses a
hanger (2)
to pop a
ball (0)
then flies
two kites (44)
Answer:
1). 2044
Step-by-step explanation:
The story includes: a hanger, a ball, and two kites (in that order)
From the information given, a hanger is 2, a ball is 0, and a kite is 4.
So it would be 2044.
find five rational numbers between ? explain please
Answer:
1.5, 6, 24.7, 384, 404.4, 1,980Step-by-step explanation:
Rational numbers are the result of dividing two integers. Intergers cannot be fractions. So 1.5 is rational but 3/2 is not.
Five rational numbers: 1.5, 6, 24.7, 384, 404.4, 1,980
I'm always happy to help :)
A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance traveled (miles). The fitted regression is Time = −7.126 + .0214 Distance, based on a sample of 20 shipments. The estimated standard error of the slope is 0.0053. Find the critical value for a right-tailed test to see if the slope is positive, using α = .05.
Answer:
Thus; the slope is positive
Step-by-step explanation:
Given that :
the sample size = 20
for the slope; the degree of freedom df = n - 2
= 20 -2
= 18
Using ∝ = 0.05
From t -table , one tailed, at df =18)
[tex]t_{\alpha , df}}= t_{0.05, df = 18} = 1.734[/tex]
Thus the t- critical for the right tailed test is 1.734. This simply refers to the fact that the critical region is test statistics.
Incorporating the Excel Formula [ T.INV (1 - 0.05).18) = 1.734063607
≅ 1.734
1/4x - 2/5 =39 someone please answer this question thx
Answer:
157.6
Step-by-step explanation:
Use PEMDAS! In this rule, it is stated that we should always add/subtract before multiplying/dividing. Also, whatever you do on one side of an equation, you do to another. Therefore, in order to get rid of the -2/5, add 2/5 so we can get rid of it. We also (according to the rule), have to add it to the other side in order to balance out. So add the 2/5 to 39. Then the other side is now 39.4. Now we have to get x by itself. Divide both sides by 1/4 (or multiply by 4 on both sides) in order to get x=157.6
Which is the correct classification of StartFraction 3 Over 8 EndFraction?
Answer:
Classifications would include
Rational; Fraction; Can be turned into Decimal; Positive
Those would be classifications
Answer: rational number, 0.375
Step-by-step explanation:
The HCF of two numbers is 11, and their L.C.M is 368. If one number is 64, then the other
number is ….
FIND P(NOT 6) WHEN YOU ROLL A STANDARD NUMBER CUBE THEN DESCRIBE THE LIKELIHOOD OF THE EVENT WRITE IMPOSSIBLE ,UNLIKELY , EQUALLY LIKELY , LIKLEY OR CERAIN
Answer: LIKLEY
Step-by-step explanation:
Formula : Probability [tex]=\dfrac{\text{Number of favorable outcomes}}{\text{Total outcomes}}[/tex]
A standard cube has six numbers on it (1,2,3,4,5 and 6).
P( NOT 6) =[tex]\dfrac{\text{Numbers that are not 6}}{\text{Total numbers}}[/tex]
[tex]=\dfrac{5}{6}=0.8333[/tex]
We know that when the probability of any event lies between 0.5 and 1then the event is said to be likely to happen.
Since , P(not 6)=0.8333 which lies between 0 and 0.5.
That means, it is likely to happen.
Note :
When probability of having A = 0 , we call A as uncertain event.
When probability of having A = 1 , we call A as certain event.
When probability of having A = 0.5 , we call A as equally likely event.
When probability of having A lies between 0 and 0.5 , we call A as unlikely event.
When probability of having A lies between 0.5 and 1 , we call A as likely event.
What is five + five
A 500.0 g piece of aluminum at 100° C is placed in 300ml of water. While in the water, the
aluminum then cools to 30°C. Calculate the amount of heat lost by the aluminum. The
specific heat of water is 4.18 J/g °C and the specific heat of aluminum is 0.90 J/g °C
Answer:
The amount of heat lost by the aluminum is 31,500 J
Step-by-step explanation:
Given;
mass of aluminum, m = 500 g
initial temperature of the aluminum, θ₁ = 100° C
final temperature of the aluminum, θ₂ = 30°C
specific heat capacity of water, C = 4.18 J/g °C
specific heat capacity of aluminum , C = 0.90 J/g
Heat lost by the aluminum is equal to heat gained by the water.
The amount of heat lost by the aluminum, is calculated as;
Q = MCΔθ
Q = 500 x 0.9 (100 - 30)
Q = 500 x 0.9 x 70
Q = 31,500 J
Therefore, the amount of heat lost by the aluminum is 31,500 J
Suppose you buy a CD for $500 that earns 3% APR and is compounded quarterly. The CD matures in 3 years. Assume that if funds are withdrawn before the CD matures, the early withdrawal fee is 3 months' interest. What is the early withdrawal fee on this account?
Answer:
$3.75
Step-by-step explanation:
I = Prt
I = $500·0.03·(3/12) = $3.75
The early-withdrawal fee is $3.75 for the first quarter.
_____
Each quarter after that, the principal amount will be larger, so the interest penalty will be larger. The fee would be the amount of interest that would be credited at the end of the next quarter, or at the end of the quarter currently in progress.
The strength of paper used in the manufacturing of cardboard boxes (y) is related to percentage of hardwood concentration in the original pulp (x). Under controlled conditions, a pilot plant manufactures 16 samples, each from differential batch of pulp, and measures the tensile strength. Determine if there is significance relationship between x and y.
y = 101, 117, 117, 106, 132, 147, 147, 134, 111, 123, 125, 145, 134, 145, 144, 146.9
x = 1.0, 1.5, 1.5, 1.5, 2.0, 2.0, 2.2, 2.4, 2.5, 2.5, 2.8, 2.8, 3.0, 3.0, 3.2, 3.3
Answer:
At a significance level of 0.05, there is enough evidence to claim that there is a significant relationship between x and y.
P-value = 0.003.
Step-by-step explanation:
If we perform a regression analysis relating x and y, we get the best fitting line with equation:
[tex]y=15.82x+92.9[/tex]
and a correlation coefficient r:
[tex]r=0.693[/tex]
We have to test the hypothesis, where the alternative hypothesis claims that there is a relationship between these two variables, and the null hypothesis claiming there is no relationship (meaning that the correlation is not significantly different from 0).
This can be written as:
[tex]H_0: \rho=0\\\\H_a:\rho\neq0[/tex]
where ρ is the population correlation coefficient for x and y.
The significance level is assumed to be 0.05.
The sample size is n=16.
The degrees of freedom are df=14.
[tex]df=n-2=16-2=14[/tex]
The test statistic can be calculated as:
[tex]t=\dfrac{r\sqrt{n-2}}{\sqrt{1-r^2}}=\dfrac{0.693\sqrt{14}}{\sqrt{1-(0.693)^2}}=\dfrac{2.593}{0.721}=3.597[/tex]
For a test statistic t=2.05 and 14 degrees of freedom, the P-value is calculated as:
[tex]\text{P-value}=2\cdot P(t>3.597)=0.003[/tex]
The P-value (0.003) is smaller than the significance level (0.05), so the effect is significant enough.
The null hypothesis is rejected.
At a significance level of 0.05, there is enough evidence to claim that there is a significant relationship between x and y.
which equation represents a line perpendicular to the line shown on the graph
Answer:
y = 1/4x + (any number)
Step-by-step explanation:
m = -8/2 = -4, the equation shown is y = -4x + 8
perpendicular is y = 1/4x + (any number), you didn't say where the line was perpendicular.
Convert 88 ounces to pounds.
A.0.18 pounds
B.5.5 pounds
C.1408 pounds
Answer: it is b because 2.5 lbs = 40 oz. then i know that 40 is half of 80 then there is not way it is the 1000 pound choice
Step-by-step explanation:
A magazine asks its readers to complete a survey on their favorite music and tv celebrities. Classify this sample
Answer:
All the elements in the sample share a common characteristic. All of them read the magazine, so we may have a biased sample. And we also have the bias of the fact that only the volunteers will respond to this survey, so this is a biased sample.
This type of sample is usually called convenience sampling, where the elements in the sample are the most readily available (and what is most readily available for a magazine than its own readers?)
Then the type of sample is a convenience sample and a biased sample.
Here is rectangle A. Block A. Rectangle B is ¹/₅ longer than A Block B. Rectangle C is ¹/₃ longer than B Block C. The total length of all three rectangles is 133 cm. How much longer is rectangle C than B?
Answer:
Rectangle C is 14 cm longer than B
Step-by-step explanation:
Let x be the length of Rectangle A. Rectangle B is ¹/₅ longer than A Block B,
Therefore the length of rectangle B is:
[tex]x+\frac{1}{5}x[/tex]
Rectangle C is ¹/₃ longer than B, therefore the length of rectangle c is:
[tex]x+\frac{1}{5}x+\frac{1}{3}(x+\frac{1}{5}x) =x+ \frac{1}{5}x+\frac{1}{3}x+\frac{1}{15}x=x+\frac{9}{15}x[/tex]
The total length of all three rectangles is 133 cm.
Length of rectangle A + Length of rectangle B + Length of rectangle C = 133 cm
[tex]x+x+\frac{1}{5}x +x+\frac{9}{15}x=133\\x+x+x+\frac{1}{5}x +\frac{9}{15}x=133\\3x+\frac{12}{15}x=133\\ 45x+12x=1995\\57x=1995\\x=35cm[/tex]
Therefore the length of rectangle A is 35 cm, the length of rectangle B is [tex]35+\frac{1}{5}*35=42\ cm[/tex] and the length of rectangle C is [tex]35+\frac{9}{15}*35=56\ cm[/tex]
Rectangle C is ¹/₃ longer than B, which is 14 cm (42\3) longer than B
Drag each description to the model and equation it matches.
Tell me if it is right
Answer:
213, 123
Step-by-step explanation:
As part of an insurance company’s training program, participants learn how to conduct an analysis of clients’ insurability. The goal is to have participants achieve a time in the range of 30 to 47 minutes. Test results for three participants were: Armand, a mean of 37.0 minutes and a standard deviation of 3.0 minutes; Jerry, a mean of 38.0 minutes and a standard deviation of 2.0 minutes; and Melissa, a mean of 38.5 minutes and a standard deviation of 2.9 minutes.
a.Which of the participants would you judge to be capable? (Do not round intermediate calculations. Round your answers to 2 decimal places.)
Participants :
Armand: Cpk _____ Cp Capable ? No/Yes
Jerry: Cpk _____ Capable ? Yes/No
Melissa Cp ________ No/Yes
b.Can the value of the Cpk exceed the value of Cp for a given participant?
yes or no
Answer:
1) cpk < 1.33, therefore it is not capable
b) cpk = 1.33, therefore it is capable
c) cpk < 1.33, therefore it is not capable
2) Cpk can never be greater than the Cp, but can be equal to it
Step-by-step explanation:
Upper limit (USL) = 47 minutes and Lower limit (LSL) = 30 minutes
1)
a) mean (μ) = 37 minutes, standard deviation (σ) = 3 minutes
[tex]cpk=min(\frac{USL-\mu}{3\sigma}, \frac{\mu - LSL}{3\sigma})=min(\frac{47-37}{3*3},\frac{37-30}{3*3} )=min(1.11,0.78)=0.78[/tex]
[tex]cp=(\frac{USL-LSL}{6\sigma})=\frac{47-30}{6*3}=0.94[/tex]
cpk < 1.33, therefore it is not capable
b) mean (μ) = 38 minutes, standard deviation (σ) = 2 minutes
[tex]cpk=min(\frac{USL-\mu}{3\sigma}, \frac{\mu - LSL}{3\sigma})=min(\frac{47-38}{3*2},\frac{38-30}{3*2} )=min(1.5,1.33)=1.33[/tex]
[tex]cp=(\frac{USL-LSL}{6\sigma})=\frac{47-30}{6*2}=1.42[/tex]
cpk = 1.33, therefore it is capable
c) a) mean (μ) = 38.5 minutes, standard deviation (σ) = 2.9 minutes
[tex]cpk=min(\frac{USL-\mu}{3\sigma}, \frac{\mu - LSL}{3\sigma})=min(\frac{47-38.5}{3*2.9},\frac{38.5-30}{3*2.9} )=min(0.98,0.98)=0.98[/tex]
[tex]cp=(\frac{USL-LSL}{6\sigma})=\frac{47-30}{6*2.9}=0.98[/tex]
cpk < 1.33, therefore it is not capable
2) Cpk can never be greater than the Cp, but can be equal to it
PLEASE HELPPPPPPPPPP <3
Answer:
y = 1/2x + 4
Step-by-step explanation:
Slope intercept form is y = mx + b, where m is the slope and b is the y-intercept.
When we count rise over run, we find that the slope is 1/2
y = 1/2x + b
The line intersects the y-axis at 4, so the y-intercept is 4.
y = 1/2x + 4
I hope this helps :))
describe the slope of the graph from 1 sec to 5.3 sec ( is the slope positive, negative, zero or non existent)
Answer:
[tex] m =\frac{y_2 -y_1}{x_2 -x_1}[/tex]
Where x for this case represent the time and y the height waist off ground.
We have one point that can be extracted from the graph on this case:
[tex] x_1 = 1, y_1= 3[/tex]
Bout for the other point we have:
[tex] x_2 = 5.3 , y_2 = 9.6[/tex]
Is important to notice that 9.6 is an estimation since we don't have the scale to identify the real value. so then if we replace we got:
[tex] m =\frac{9.6-3}{5.3-1}= 1.535[/tex]
And for this case we can conclude that this slope is positive and around 1.5 and 1.6. And that means if we increase the time in one unit then the height off waist off ground would increae about 1.5 to 1.6 ft
Step-by-step explanation:
In order to calculate the slope we need to use the following formula:
[tex] m =\frac{y_2 -y_1}{x_2 -x_1}[/tex]
Where x for this case represent the time and y the height waist off ground.
We have one point that can be extracted from the graph on this case:
[tex] x_1 = 1, y_1= 3[/tex]
Bout for the other point we have:
[tex] x_2 = 5.3 , y_2 = 9.6[/tex]
Is important to notice that 9.6 is an estimation since we don't have the scale to identify the real value. so then if we replace we got:
[tex] m =\frac{9.6-3}{5.3-1}= 1.535[/tex]
And for this case we can conclude that this slope is positive and around 1.5 and 1.6. And that means if we increase the time in one unit then the height off waist off ground would increae about 1.5 to 1.6 ft
