Suppose an object is traveling in a circle of radius 10 m. if the object has a period of 6 s, what is its orbital speed (in m/s)
The orbital speed of the object moving around the circle is 10.5 m/s
Speed is the ratio of total distance to total time taken. Speed is given by:
Speed = distance / time
Given that the object is traveling in a circle of radius 10 m. The distance along the circle is:
Distance along circle = 2π * radius = 2π * 10 m = 62.83 m
The orbital speed = distance / time = 62.83 m / 6s = 10.5 m/s
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Forces can...
A. Change speed of motion
B. Change shape of objects
C. Change direction of motion
D. All of the above
Answer:
D
Explanation:
Forces can change speed of motion, the more force that's applied when you push a ball for example, the faster the ball will go. Force can also change the shape of objects by applying pressure to them too. The inertia from force can change direction, as when you let's say hit a tennis ball, it won't go perfectly straight. So all of the above are correct
The reaction is at dynamic equilibrium.
N2 + 3H2 = 2NH3
Which statement is correct?
(1 point)
a. The solution has the same concentrations of nitrogen gas and ammonia.
b. Nitrogen and hydrogen combine at the same rate that ammonia breaks down.
c. The solution has the same concentrations of nitrogen and hydrogen gases.
d. Both directions of the reaction have stopped.
Answer:
Nitrogen and hydrogen combine at the same rate that ammonia breaks down.
Explanation:
A monatomic ideal gas is compressed at a constant pressure of 0.293 atm from a volume of 8.26 L to 3.32 L. In the process, heat energy flows out of the gas. What is the work done on the gas?
The work done on the gas as it is compressed from volume 1 to volume 2 is 146.7 J.
Given the data in the question;
Pressure; [tex]P = 0.293 atm = 29688.225pa[/tex]Initial volume; [tex]v_1 = 8.26L = 0.00826m^3[/tex]Final volume; [tex]v_2 = 3.32L = 0.00332m^3[/tex]Work done on the gas; [tex]W = \ ?[/tex]
From the first law of thermodynamic:
[tex]W = -P\delta v[/tex]
Where W is work done, P is pressure and [tex]\delta v[/tex] is change in volume.
We substitute our values into the equation
[tex]W = -29688Pa * ( 0.00332m^3- 0.00826m^3)\\\\W = -29688Pa * -0.00494m^3\\\\W= 146.7 J[/tex]
Therefore, the work done on the gas as it is compressed from volume 1 to volume 2 is 146.7 J.
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Help please its 30 marks thanks for willing to help me
Answer:
Independent variable: Height
Dependent variable: time
Explanation:
Not sure what the experiment was, but assuming that this was the amount of time for a ball to reach the ground, the independent variable would be height since you determine and change the initial height. The dependent variable would be time since it changes with height, and you have to measure it.
Where is a spinal tap usually taken?
This is between L3 and L4 and L4 and L5 of the lumbar Vertebrae of the vertebral column. The medical procedure is also called Lumbar Puncture, vertebral puncture.
The fluid collected is called Cerebrospinal fluid (CSF).It acts as shock absorber for the brain and spinal cord. It also contains some nutrients for these organs.
Procedure.
The patient or subject must lie by his side, and the knees draws up towards the chest. Alternatively, the subject can sit up or bent forward so that the vertebral column is bent and locations above revealed.
Then anesthesia is performed at the lower spine to neutralize the pain of the spine needle.
Finally, the spine needle is inserted between the L3 and L4 or L4 and L5 to draw a clear liquid; mostly water. This is CSF
The procedure may also be used to determine the pressure in the brain.
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What is being transferred as you do work?
A. Energy
B. Power
C. Heat
D. Strength
[tex]\huge\bold{\purple{\bold{⚡A. Energy⚡}}} [/tex]
[tex]\huge\underline\mathtt\colorbox{cyan}{Reason:}[/tex]
When a force causes a body to move, work is done on the object by the force. Work is the measure of the energy transfer when a force 'F' moves an object through a distance 'd'. So we say that energy is transferred from one energy store to another when work is done, and therefore, energy transferred = work done.
Accelerating car is a _______
•Law of inertia
•Law of universal gravitation
•Law of acceleration
•Law of conversation of energy
Acceleration is the rate of change of velocity as a function of time. For example a car traveling at 50 km/hr starts to accelerate, 10 seconds after, its speed changes to 100 km/hr then the acceleration of the car during the time can be calculated as below: initial speed = 50 km/hr.
A bullet (m=20g) shot with a speed of 800 m/s hits an oak tree and sticks 4cm inside it.
What is the average force acting on the bullet from the tree?
Hi there!
We can begin by converting cm to m:
4cm = 0.04 m
Use the following equation:
vf² = vi² + 2ad
The final velocity is 0 m/s, so:
0 = vi² + 2ad
vi² = -2(a)d
Plug in given values to solve for the acceleration:
800²/2(0.04) = -a
a = -8,000,000 m/s²
Find the force using the equation:
F = ma
F = (0.02)(-8,000,000) = -160,000 N
If 8.90 kg of ice at -5.00°C is added to 12.0 kg of water at 15°C, compute the final temperature.
(in deg C)
How much ice remains, if any? (in Kg)
Answer:
6.93 kg
Explanation:
m1 = 8.90 kg
T1 = -5°C
m2 = 12 kg
T2 = 15°C
constant needed:
c (ice) = 2100 J/kg °C
c (water) = 4200 J/kg °C
L (Latent Heat) = 336 000 J/kg
Black Principle
Q (release) = Q (absorbs)
Q (release) max = m2 c(water) ∆T2
Q (release) max = 12 x 4200 x (15-0)
Q (release) max = 756 000 J
Q (absorbs) = m1 c(ice) ∆T1 + m1 L
Q (absorbs) = 8.9 x 2100 x (0-(-5)) + 8.9 x 336 000
Q (absorbs) = 93 450 + 2 990 400 = 3 083 850 J
since Q (absorbs) is much much bigger than Q (release), only a few litlle ice melting. So we need to see how much ice melting and how many left.
Q (release) - Q (absorbs) ice -5°C to ice 0°C = 756000 - 93450 = 662550
mass of melting Ice
Q (absorbs) melting ice = m(melting) L
662 550 = m(melting x 336 000
m (melting) = 662 500/336 000
m (melting) = 1.977 kg
so the ice remains is 8.90 - 1.97 = 6.93 kg
im board lolololololololololol
Answer:
noice me too U n U
Explanation:
Unless otherwise stated, all objects are located near the Earth's surface, where g = 9.80 m/s. A girl pushes a 21 kg lawn mower as shown in the figure
a)If F = 32 N and θ = 45 ∘ what is the acceleration of the mower? Ignore friction.
b)What is the normal force exerted on the mower by the lawn?
Newton's second law allows us to find the result for the acceleration of the mower is:
a = 0.8 m / s²
Newton's second law says that the net force is proportional to the mass and the acceleration of the bodies.
∑ F = m a
where the bold letters indicate vectors, F is the force, m the mass and the acceleration of the bodies.
A free-body diagram is a schematic where the forces are drawn if the details of the bodies, see attached.
Let's write Newton's equation.
x-axis
Fₓ = ma
y-axis
N - F_y - w = 0
Let's use trigonometry to find the components of the force.
Cos 45 = [tex]\frac{F_x}{F}[/tex]
sin 45 = [tex]\frac{F_y}{F}[/tex]
Fₓ = F cos 45
F_y = F sin 45
Let's substitute.
F cos 45 = m a
a = [tex]\frac{F \ cos45}{m}[/tex]
Let's calculate.
a = [tex]\frac{32 \ cos 45}{21}[/tex]
a = 0.8 m / s²
In conclusion using Newton's second law we can find the result for the acceleration of the mower is:
a = 0.8 m / s²
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The acceleration of the mower is 1.1m/s^2. The normal force exerted on the mower by the lawn is 145.5 N.
a) The force that moves the lawn mower in the horizontal direction is Fcosθ.
Where;
F = 32 N
θ = 45∘
Effective force that moves the mower forward = 32 N cos 45∘ = 22.6 N
Now;
F = ma
m = mass of the lawn mower
a = acceleration
a = F/m
a = 22.6 N/21 kg
a = 1.1 m/s^2
b) The normal force = mgcosθ
FN = 21 kg × 9.80 m/s × cos 45 ∘
= 145.5 N
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I need HELP ASAP please!!!
Answer: A
Explanation:i took this one
If an astronaut was on a planet 9*10^10 meters away, how long would it take a radio signal (in seconds) to travel from them to Earth? (Be sure to give your answer to two decimal places)
The time taken a radio signal to travel form the given distance to Earth is [tex]2.65 \times 10^8 \ s[/tex].
The given parameters;
distance between the astronaut and Earth, d = 9 x 10¹⁰ mThe time taken a radio signal to travel form the given distance to Earth is calculated by using Echo formula as shown below;
[tex]2d = v \times t\\\\t = \frac{2d}{v}[/tex]
where;
v is the speed of sound sound in air = 340 m/st is the time taken for the signal to be heard (to and fro)The time taken for the signal to travel in a single forward motion is calculated as;
[tex]t = \frac{1}{2} \times \frac{2d}{v} = \frac{d}{v} \\\\t = \frac{9\times 10^{10}}{340} \\\\t = 2.65 \times 10^8 \ s[/tex]
Thus, the time taken a radio signal to travel form the given distance to Earth is [tex]2.65 \times 10^8 \ s[/tex].
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3. A ferry boat is 4.0 m wide and 6.0 m long. When a truck pulls onto it, the boat sinks 4.00 cm in the water. What is the weight of the truck?
Answer:
Explanation:
The weight of the truck will equal the weight of the displaced water.
Assuming fresh water and that the sides of the ferry are vertical,
The volume of the water displaced is
6.00(4.00)(0.0400) = 0.960 m³
that volume of water weighs
0.960 m³(1000 kg/m³)(9.81 N/kg) = 9,417.6 = 9.42 kN
en que consiste el atletismo de pista y campo?
Answer:
El atletismo es un deporte que incluye competencias atléticas basadas en las habilidades para correr, saltar y lanzar. El nombre se deriva del lugar donde se lleva a cabo el deporte, una pista de atletismo y un campo de hierba para los lanzamientos y algunos de los eventos de salto.
Explanation:
Yo se esto
PLEASE HELPPPPPPPPPP
Answer:
sorry me computer is blocking the picture but i will try to unblock so i can answer
Explanation:
car accelerates at a rate of 4.00 m/s?. How long will it take the car to speed up from 20 m/s to 50 m/s?
The distance that will take the car to speed yup from 20m/s to 50m/s is 262.5 meters
The first step is to write out the parameters given in the question are
acceleration= 4
initial velocity= 20
final velocity= 50
The distance can be calculated as follows
V²= U² + 2as
50²= 20² + 2(4)(s)
2500= 400= 8s
2500-400= 8s
2100= 8s
s= 2100/8
s= 262.5 meters
Hence the distance is 262.5 meters
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From the definition of acceleration, the time it will take the car to speed up is 7.5 seconds
Given that a car accelerates at a rate of 4.00 m/s^2. To calculate how long it will take the car to speed up from 20 m/s to 50 m/s, let us first mark out the needful parameters.
Acceleration a = 4 m/[tex]s^{2}[/tex]
Initial velocity U = 20 m/s
Final Velocity V = 50 m/s
Time t = ?
From the definition of acceleration, acceleration is the rate of change of velocity. That is,
a = (V - U)/ t
Substitute all the parameters into the formula above.
4 = ( 50 - 20) / t
Cross multiply
4t = 30
Make t the subject of formula
t = 30/4
t = 7.5 t
Therefore, the time it will take the car to speed up is 7.5 seconds
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Why did the brain name itself? 100 points
Answer:
In the remote past, people had no notion what function the brain has in the human organism. They saw “mush” and called it accordingly. Since brain was a borrowed word, those who began to use it, must at one time have had a native name for the content of heads.
does this help?
thanks for the points!
F = kx
k = ?
Select one:
a. F/x
b .x/F
c. F + x
d. F − x
Answer:
[tex]F = kx \\ k = \frac{F }{x} [/tex]
so the answer is a
cells science crossword
where's the crossword?
One type of BB gun uses a spring driven plunger to blow the BB from its barrel. Calculate the force constant of its plunger's spring if you must compress it 0.150 m to drive the 0.0500 kg plunger to a top speed of 20.0 m/s.
Answer:
a) 889 N / m
b) 133 N
Compare and contrast the different parts of the Electromagnetic Spectrum. Evaluate the usefulness of each part and decide which part is most useful, or most important, to you and society as a whole. You must provide two reliable sources to back up your opinion. Recall that reliable sources include scientific sites or publications, education sites or publications, and government sites or publications.
Answer:
Think in your Mind
Explanation:
if you do you will have a better understanding of what you're doing
you could study you could ask a parent or guardian
or maybe stop looking up answer and expect other people breaking thier heads doing this
What s the kinetic energy of a 0.100 kg baseball thrown at 20.0 m/s?
1: 40.0 J
2: 1.00 J
3: 2.00 J
4; 20.0 J
5: 4.00 J
Answer:
KE = ½mv² = ½(0.100)20.0² = 20.0 J
Explanation:
The speed of a motorcycle changed from 5m/s to 20m/s the ratio of initial and final kinetic energy is?
Answer:
Explanation:
½m5² / ½m20² = 25/400 = 1/16 = 0.0625
Find the maximum possible coefficient of performance for a heat pump used to heat a house in a northerly climate in winter
Answer:
[tex]COP_{Heating}[/tex][tex]= \frac{T_{H}}{T_{H}-T_{C} }[/tex]
The temperature must be in Kelvin: [tex]degrees Celsius+273.15=K[/tex].
Explanation:
COP is similar to efficiency: [tex]\frac{what you get}{what you pay}[/tex] = [tex]\frac{energy from hot reservoir}{work needed for energy transfer}[/tex]
The maximum possible coefficient of performance (COP) for a heat pump is equal to 7.32.
What is the coefficient of performance of a heat pump?The coefficient of performance can be described as the relationship between the power (kW) that is supplied to the compressor and the power (kW) that is drawn out of the heat pump as cooling or heat.
The coefficient of performance of a heat pump or air conditioning system is a ratio of useful heating or cooling provided to work or energy required. The COP usually exceeds 1, it pumps extra heat from a heat source to where the heat is needed.
Assume that the temperature of the hot reservoir is [tex]T_H[/tex] and the temperature of the cold reservoir is [tex]T_c[/tex].
The temperature of the hot reservoir, T[tex]_H[/tex] = 20° C = 20 + 273 = 293 K
The temperature of cold reservoir, [tex]T_C[/tex] = -20°C = 273 -20 = 253 K
The equation of the maximum possible coefficient of performance for a heat pump is as follows:
[tex]COP_{max}= \frac{T_H}{T_H-T_c}[/tex]
[tex]COP_{max } = \frac{293}{293-253}[/tex]
COP = 7.32
Therefore, the maximum possible coefficient of performance for a heat pump is 7.32.
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Your question is incomplete, most probably the complete question was,
Find the maximum possible coefficient of performance for a heat pump used to heat a house in a northerly climate in winter. The inside is kept at 20°C and the outside is -20°C.
A hooligan throws a stone vertically down with an initial speed of 17 m/s from the roof of a building 51 metres above the
ground. How long in seconds does it take the stone to reach the ground?
Answer:
Explanation:
impact velocity is
√(18² + 2(-9.8)-51) = 36 m/s
average velocity is (17 + 36)/2 = 26.5 m/s
t = d/v = 51 / 26.5 = 1.9 s
or
if ground is origin and UP positive
0 = 51 - 17t - ½(9.8)t²
quadratic formula
t = (17 ±√(17² - 4(-4.9)(51))) / (2(-4.9))
t = (17 ± 36) / -9.8
t = - 5.4 s which we ignore as the stone is not thrown yet
or
t = 19 s
Two workers use 100 N of force to move a sofa 2 meters in 2 seconds. How
much power is required?
A. 200 W
B. 100 W
C. 4 W
D. 400W
Answer:
B.) 100 W
Explanation:
Power = work/time = (Force * Distance)/Time
Force = 100 N
Distance = 2M
Time = 2 sec
Power = (100 * 2)/2 = 100 Watts
Thus the answer is B.) 100 W
An incompressible fluid is flowing through a horizontal pipe with a constriction. The velocity of the fluid in the wide section of the pipe is 5.00 m/s and the velocity of the fluid in the narrow section of pipe is 8.00 m/s. The pressure of the fluid in the wide section is 200 kPa. What is the pressure in the narrow section of the pipe
The Bermoulli's equation allows us to find the pressure in the narrow part of the pipe through which water circulates is:
P = 500 Pa
Bernoulli's equation is the work-energy relationship for fluids that are liquids and gases.
[tex]P_1 + \frac{1}{2} \rho v_1^2 + \rho g y_1 = P2 + \frac{1}{2} \rho v_2^2 + \rho g y_2[/tex]
Where the subscripts 1 and 2 represent points of interest, P is the pressure, ρ the density of the fluid, v the velocity and y the height.
They indicate that the pipe is horizontal, that the pressure in the wide part P₁ = 200 kPa and the velocity is v₁ = 5 m / s and in the narrow part v₂=8.00 m/s, see attached.
Since the pipe is horizontal y₁ = y₂
P₁ + ½ ρ v₁² = P₂ + ½ ρ v₂²
P₂ = P₁ + ½ ρ (v₁² - v₂²)
Let's calculate
P₂ = 200 10² + ½ ρ (5² - 8²)
P₂ = 2 10⁴ - 19.5 ρ
For a specific calculation the value of the density of the fluid is needed, suppose that the fluid is water ρ = 1000 kg / m³
P₂ = 2 10² - 19.5 1000
P₂ = 500 Pa
In conclusion using the Bermoulli equation we can find the pressure in the narrow part of the pipe through which water circulates is:
P = 500 Pa
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If the gas was instead in a cylinder with a floating, massless, frictionless piston, what would the volume of the gas be (in liters) at STP
The volume of the gas at standard temperature and pressure (STP) is 1,239.2 L.
The given parameters;
volume of the gas, V₁ = 9.5 Lpressure of the gas, P₁ = 140 atmtemperature of the gas, T₁ = 20 ⁰C = 273 + 20 = 293 Kpressure of gas at standard condition, P = 1 atmtemperature of gas at standard condition, T = 0⁰C = 273 KThe volume of the gas at standard condition is calculated by applying general gas law as shown below;
[tex]\frac{PV}{T} = \frac{P_1V_1}{T_1} \\\\V = \frac{P_1V_1T}{T_1P} \\\\V = \frac{140 \times 9.5 \times 273}{293 \times 1} \\\\V = 1,239.2 \ L[/tex]
Thus, the volume of the gas at standard temperature and pressure (STP) is 1,239.2 L.
"Your question is not complete, it seems be missing the following information;"
A compressed air tank carried by scuba divers has a volume of 9.5 L and a pressure of 140 atm at 20∘C.
If the gas was instead in a cylinder with a floating, massless, frictionless piston, what would the volume of the gas be (in liters) at STP.
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