Find the ordered pair (s,t) that satisfies the system

s/2+5/t=3

3t-6s=9

From the calculation, you are 100 m away from the plateau.

The angle of elevation is the angle between a horizontal line of sight and a line of sight that is directed upwards, or the angle between the horizontal and the line of sight when an observer is looking upward.

We know that;

Angle of elevation = 35°

Height of the Plateau = 70 m

Thus;

Tan 35 =70/x

x = Your distance from the plateau.

x = 70/Tan 35

x = 100m

In trigonometry and geometry, the angle of elevation—which can be expressed in degrees, radians, or other angular units—is frequently employed to address issues with heights and distances.

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The critical value is approximately 2.681. Since the absolute value of the test statistic (4.114) is greater than the critical value (2.681), we can reject the null hypothesis at the 0.01 significance level and conclude that there is evidence to support the claim that Praxor is effective at lowering cholesterol levels compared to a placebo.

Hypothesis testing is a statistical method used to determine whether there is enough evidence to support a claim about a population.

In this case, the claim being made is that people who take Praxor will experience a greater decrease in cholesterol levels compared to those taking a placebo.

The first step in hypothesis testing is to state the null and alternative hypotheses. The null hypothesis, denoted as H₀, is the assumption that there is no difference between the two populations being compared. The alternative hypothesis, denoted as H₁, is the claim being made, which is that there is a difference between the two populations.

In this case, the null hypothesis would be that there is no difference in the mean cholesterol level decrease between the two groups, while the alternative hypothesis would be that the mean cholesterol level decrease in the treatment group is greater than that in the control group.

Next, a significance level, denoted as α, is chosen. This represents the probability of making a Type I error, which is rejecting the null hypothesis when it is actually true. In this case, a significance level of 0.01 is chosen.

The next step is to calculate the test statistic, which is a value that measures how far the sample data deviates from what is expected under the null hypothesis. The test statistic used in this case is the two-sample t-test. This test assumes that the two populations being compared have normal distributions and that their variances are not equal.

The formula for the two-sample t-test is:

t = (x₁ - x₂) / √√(s₁²/n1 + s₂²/n₂)

Where x₁ and x₂ are the sample means, s₁ and s₂ are the sample standard deviations, and n₁ and n₂ are the sample sizes for the two groups being compared.

Substituting the values in the formula we get,

= (19.9 - 19.3) / √((3.9²/32) + (1.3²/36))

t ≈ 4.114

Finally, we compare the test statistic to a critical value from a t-distribution table with degrees of freedom equal to n₁ + n₂ - 2 and a significance level of 0.01. If the absolute value of the test statistic is greater than the critical value, we reject the null hypothesis in favor of the alternative hypothesis.

In this case, the critical value is approximately 2.681. Since the absolute value of the test statistic (4.114) is greater than the critical value (2.681), we can reject the null hypothesis at the 0.01 significance level and conclude that there is evidence to support the claim that Praxor is effective at lowering cholesterol levels compared to a placebo.

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The area of the circle is approximately 202.03 square feet

If the circumference of a circle is 50.4 ft, we can use the formula for the circumference of a circle to find its radius:

C = 2πr

C = circumference

r = radius

r = C / (2π)

Substituting C = 50.4 ft, we get:

r = 50.4 / (2π)

Using a calculator, we can approximate this value to be:

r =25.2/π ft

A circle's area can be calculated using the following formula:

A = πr²

Substituting r = 25.2/π ft, we get:

A = π(25.2/π)²

= 635.04/3.14

= 202.03

Therefore, the area of the circle is approximately 202.03 square feet.

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Answer:

2π/3 or 120°

Step-by-step explanation:

To find a reference angle, we either subtract 2π or 360°

For this one we do 8π/3 - 2π

Which is equal to 2π/3 which is equivalent to 120° which I assume is what the question is asking for

the value of y is -5/8. So, In part (a), we found that the rational function f(x) = (5x + 20)/(x^2 - 20) had a vertical asymptote at x = -2√5 and x = 2√5, a horizontal asymptote at y = 0, an x-intercept at (-4, 0), a y-intercept at (0, -1), and a hole at (-4, 5/18).

To find the value of y when x = -6, we simply substitute -6 for x in the function:

f(-6) = (5(-6) + 20)/((-6)^2 - 20)

We simplify this expression by first multiplying 5 and -6 to get -30, and then adding 20 to get -10 in the numerator. In the denominator, we evaluate (-6)^2 to get 36, and then subtract 20 to get 16. So, we have:

f(-6) = -10/16

This fraction can be simplified by dividing both the numerator and denominator by 2:

f(-6) = (-10/2)/(16/2) = -5/8

Therefore, when x = -6, the value of y is -5/8.

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The answer is 3√3ln|√3x^2-13|+C, where C is the constant of integration. Evaluating this at the limits of integration (0 and 2), we get 3√3ln(2√3-13)-3√3ln(-13)+C, which simplifies to approximately 1.728. Therefore, the answer in numerical is 1.728.
To evaluate the integral ∫(6x dx)/(√(3x²-13)), first, we need to recognize that this is an integral of the form ∫(f'(x) dx)/f(x). Here, f(x) = √(3x²-13) and f'(x) = 6x. This means we can use the natural logarithm rule to solve the integral.

∫(6x dx)/(√(3x²-13)) = ∫(f'(x) dx)/f(x) = ln|f(x)| + C

Now, substitute f(x) back in:

= ln|√(3x²-13)| + C

Now, we can rewrite the square root as a power of 1/2:

= ln|(3x²-13)^(1/2)| + C

This is the general solution to the integral.

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The remaining piece of board is 8 and 5/12 inches long, and it is long enough to make a 7-inch by 7-inch square.

The total length of the board is 23 and 4/16 inches, which can be simplified to 23 and 1/4 inches.

To replace the shelf, Cindy needs a piece of board that is at least 7 and 15/16 inches long, which is the length of the shelf minus the width of the board (7 and 1/4 inches) and the width of the replacement square (7 inches).

So, the minimum length of the board needed for the shelf and the square is 7 and 15/16 + 7 = 14 and 15/16 inches.

Therefore, the remaining length of the board is 23 and 1/4 - 14 and 15/16 = 8 and 5/12 inches.

To determine if this remaining length is long enough for the 7-inch by 7-inch square, we need to calculate the diagonal of the square, which is √(7^2 + 7^2) = 9.899 inches (rounded to three decimal places).

Since the remaining length of the board is longer than the diagonal of the square, it is long enough to make the square.

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The circumference of a circle with a diameter of 8.7 units is approximately 27.318 units, calculated using the formula Circumference = πd. So, the correct answer is D).

The formula for the circumference of a circle is given by

Circumference = πd

where d is the diameter of the circle.

Substituting the given value of the diameter of circle a, we get:

Circumference = π x 8.7

Using the approximation of π = 3.14, we get

Circumference = 3.14 x 8.7

Circumference = 27.318 units (rounded to three decimal places)

Therefore, the circumference of the circle with a diameter of 8.7 units is approximately 27.318 units. So, the correct option is D).

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--The given question is incomplete, the complete question is given

" The diameter of circle a is 8.7 units. find the circumference of the circle.

a. 17.4 units

b. 75.69 unit

c. 8.7 units

d. 27.318 units "--

If all three conditions are met, then the two-sample t-test can be used to test the hypotheses.

For testing the hypotheses in part A, a two-sample t-test for independent means can be used to compare the mean speed of the baseball line drive using the old technique to the mean speed using the new technique. The conditions for the t-test are:

Independence: The 42 hits using the new technique should be independent of the hits using the old technique.

Normality: The speeds using the new and old techniques should be normally distributed. This can be checked by creating a histogram of the speeds and checking for a roughly bell-shaped curve.

Equal variances: The variance of the speeds using the new technique should be approximately equal to the variance of the speeds using the old technique. This can be checked by using a statistical test for equal variances, such as Levene's test.

If all three conditions are met, then the two-sample t-test can be used to test the hypotheses.

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The function giving the distance between the point (0,-6) and the line y = 8x - 5 is: S = 47 / sqrt(65).

To find the point on the line closest to the point (0,-6), we can find the perpendicular distance from the point (0,-6) to the line y = 8x - 5. The point on the line closest to (0,-6) will be the point on the line that is intersected by the perpendicular line.

The slope of the given line is 8, so the slope of any line perpendicular to it will be -1/8. Let (a,b) be the point on the line y = 8x - 5 that is closest to (0,-6). The equation of the line passing through (0,-6) with slope -1/8 is:

y + 6 = (-1/8)x

Simplifying this equation, we get:

y = (-1/8)x - 6

The point (a,b) will lie on both the given line and the perpendicular line. Therefore, we can substitute y = 8x - 5 in the equation y = (-1/8)x - 6 to obtain:

8x - 5 = (-1/8)x - 6

Solving for x, we get:

x = 37/65

Substituting x = 37/65 in y = 8x - 5, we get:

y = 231/65

Therefore, the point on the line y = 8x - 5 closest to the point (0,-6) is (37/65, 231/65).

The distance S between the point (0,-6) and the line y = 8x - 5 can be found by using the formula:

S = |ax + by + c| / sqrt(a^2 + b^2)

where a, b, and c are the coefficients of the general form of the line equation, which is ax + by + c = 0.

In this case, the equation of the line is y - 8x + 5 = 0. Therefore, a = -8, b = 1, and c = 5. Substituting these values in the formula for S, we get:

S = |(-8)(0) + (1)(-6) + 5| / sqrt((-8)^2 + 1^2)

= 47 / sqrt(65)

Therefore, the function giving the distance between the point (0,-6) and the line y = 8x - 5 is:

S = 47 / sqrt(65)

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Estimated  large sample size need to be selected for the 90%  of confidence level with standard deviation of $900 is equal to 24.

Standard deviation = $900

Confidence level = 90%

Estimate the required sample size,

Use the formula for the margin of error,

Margin of Error = Z × (standard deviation / √(sample size))

where Z is the z-score corresponding to the desired level of confidence.

Using attached z-score table,

For 90% confidence level, Z = 1.645.

Rearrange the formula to solve for the sample size,

Sample size = (Z × standard deviation / margin of error) ^ 2

Substituting the given values, we get,

⇒ Sample size = (1.645 × 900 / 300) ^ 2

⇒ Sample size = 24.35

Round up to the nearest whole number = 24

Therefore, need a sample size of at least 28 to ensure that it is large enough to achieve the desired level of confidence level.

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The statement "if point b is on ac and between points a and c, then mab + mbc = mac" describes the angle addition postulate in geometry.

In geometry, an angle is formed by two rays that share a common endpoint called a vertex. The measure of an angle is the amount of rotation between the two rays, usually measured in degrees or radians. The angle addition postulate states that if point B is on line segment AC and between points A and C, then the sum of the measures of angles MAB and MBC is equal to the measure of angle MAC. This postulate is used in various proofs and constructions in geometry, and it is also useful in real-world applications such as navigation, surveying, and engineering. The postulate is based on the fact that a straight angle measures 180 degrees, so if we know the measures of two angles that share a common ray, we can find the measure of the third angle by subtracting the sum of the first two angles from 180 degrees.

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Answer:

ben earns $9 per hour and $6 for each delivery he makes

Step-by-step explanation:

Each cook made 109 pizzas.

The total number of pizzas ordered is 4 + 97 + 335 = 436.

If the 4 cooks each made an equal number of pizzas, then we can divide the total number of pizzas by the number of cooks to find out how many pizzas each cook made.

436 pizzas / 4 cooks = 109 pizzas per cook.

Therefore, each cook made 109 pizzas.

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Answer

Consider the time taken to completion time (in months) for the construction of a particular model of homes: 4.1 3.2 2.8 2.6 3.7 3.1 9.4 2.5 3.5 3.8 Find the mean, median mode, first quartile and third quartile. Find the outlier?

To find the mean, we add up all the values and divide by the number of values:

Mean = (4.1 + 3.2 + 2.8 + 2.6 + 3.7 + 3.1 + 9.4 + 2.5 + 3.5 + 3.8) / 10

Mean = 36.7 / 10

Mean = 3.67

To find the median, we need to put the values in order:

2.5, 2.6, 2.8, 3.1, 3.2, 3.5, 3.7, 3.8, 4.1, 9.4

The middle number is the median, which is 3.35 in this case.

To find the mode, we look for the value that appears most often. In this case, there is no mode as no value appears more than once.

To find the first quartile (Q1), we need to find the value that separates the bottom 25% of the data from the top 75%. We can do this by finding the median of the lower half of the data:

2.5, 2.6, 2.8, 3.1, 3.2

The median of this lower half is 2.8, so Q1 = 2.8.

To find the third quartile (Q3), we need to find the value that separates the bottom 75% of the data from the top 25%. We can do this by finding the median of the upper half of the data:

3.7, 3.8, 4.1, 9.4

The median of this upper half is 3.95, so Q3 = 3.95.

To find the outlier, we can use the rule that any value more than 1.5 times the interquartile range (IQR) away from the nearest quartile is considered an outlier. The IQR is the difference between Q3 and Q1:

IQR = Q3 - Q1

IQR = 3.95 - 2.8

IQR = 1.15

1.5 times the IQR is 1.5 * 1.15 = 1.725.

The only value that is more than 1.725 away from either Q1 or Q3 is 9.4. Therefore, 9.4 is the outlier in this data set.

Answer

To find the perimeter of a regular polygon with n sides, we can use the formula:

Perimeter = n * s

where s is the length of each side. To find s, we can use trigonometry to find the length of one of the sides and then multiply by the number of sides.

In a regular polygon with n sides, the interior angle at each vertex is given by:

Interior angle = (n - 2) * 180 degrees / n

In a 15-sided polygon, the interior angle at each vertex is:

(15 - 2) * 180 degrees / 15 = 156 degrees

If we draw a line from the center of the polygon to a vertex, we form a right triangle with the side of the polygon as the hypotenuse, the distance from the center to the vertex as one leg, and half of the side length as the other leg. Using trigonometry, we can find the length of half of the side:

sin(78 degrees) = 12 / (1/2 * s)

s = 2 * 12 / sin(78 degrees)

s ≈ 2.17 inches

Finally, we can find the perimeter of the polygon:

Perimeter = 15 * s

Perimeter ≈ 32.55 inches

Rounding this to the nearest whole number, we get that the best approximation for the perimeter is 33 inches. Therefore, the closest option is (1) 68 inches.

From comparing three investment accounts offering different rates, Account A will give Grady at least a 5% annual yield. Therefore, the correct option is option 1.

To determine which investment account will give Grady at least a 5% annual yield, we will need to calculate the Annual Percentage Yield (APY) for each account and compare them. Here are the given terms for each account:

Account A: APR of 4.95%, compounding monthly

Account B: APR of 4.85%, compounding quarterly

Account C: APR of 4.75%, compounding daily

1: Use the APY formula:

APY = (1 + r/n)^(nt) - 1

where r is the annual interest rate (as a decimal), n is the number of compounding periods per year, and t is the number of years.

2: Calculate APY for each account.

Account A:
APY = (1 + 0.0495/12)^(12*1) - 1
APY ≈ 0.0507 or 5.07%

Account B:
APY = (1 + 0.0485/4)^(4*1) - 1
APY ≈ 0.0495 or 4.95%

Account C:
APY = (1 + 0.0475/365)^(365*1) - 1
APY ≈ 0.0493 or 4.93%

3: Compare the APYs to determine which account(s) meet the 5% annual yield requirement.

Based on the calculations, Account A has an APY of 5.07%, which is greater than the 5% annual yield requirement. Therefore, Account A will give Grady at least a 5% annual yield.

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Answer:

m=2

Step-by-step explanation:

Numerator: e^(1 + ln ∞) * (1/∞) = e^(1 + ∞) * 0 = 0, Denominator: 1 + e^∞ = ∞. So, the limit of the expression is: lim (x→∞) [e^(1 + ln x) / ln (1 + e^x)] = 0/∞ = 0

To find the limit of the given function, let's first rewrite the terms using the provided limit notation:

lim (x→∞) [e^(1 + ln x) / ln (1 + e^x)]

To solve this limit, we will apply L'Hôpital's rule, which states that if the limit has the form 0/0 or ∞/∞, we can find the limit by taking the derivative of the numerator and denominator with respect to x:

Numerator: d(e^(1 + ln x))/dx = e^(1 + ln x) * d(1 + ln x)/dx = e^(1 + ln x) * (1/x)
Denominator: d(ln(1 + e^x))/dx = (1/(1 + e^x)) * d(e^x)/dx = (1/(1 + e^x)) * e^x

Now, we will find the limit of the new expression:

lim (x→∞) [(e^(1 + ln x) * (1/x)) / ((1/(1 + e^x)) * e^x)]

Simplify the expression by canceling out the e^x terms:

lim (x→∞) [(e^(1 + ln x) * (1/x)) / (1 + e^x)]

Now, let's substitute x→∞:

Numerator: e^(1 + ln ∞) * (1/∞) = e^(1 + ∞) * 0 = 0
Denominator: 1 + e^∞ = ∞

So, the limit of the expression is:

lim (x→∞) [e^(1 + ln x) / ln (1 + e^x)] = 0/∞ = 0

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Drawing a number line is a useful way to visualize the relationship between tons and pounds and can help make conversions easier to understand.

If we were to draw a number line that shows the relationship between tons and pounds, we would start with the fact that one ton is equivalent to 2000 pounds. We would then draw tick marks on the number line for every whole number from 0 to 10, with each tick mark representing 100 pounds. So, the tick mark at 0 would represent 0 pounds, the tick mark at 1 would represent 100 pounds, the tick mark at 2 would represent 200 pounds, and so on. The tick mark at 20 would represent 2000 pounds, or one ton.

We could then continue the number line past 20 to show larger quantities of tons and pounds, with each additional tick mark representing another ton (2000 pounds). For example, the tick mark at 30 would represent 3000 pounds, or 1.5 tons, the tick mark at 40 would represent 4000 pounds, or 2 tons, and so on.

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The car model that is least likely to have a brake failure is model d, and the probability of brake failure for this model is 0.0029%.

The given table provides the probabilities of brake failure for different car models. We need to identify the car model that has the lowest probability of brake failure and the corresponding probability.

From the table, we can see that the probability of brake failure is the lowest for model d, which is 0.0029%. To find this, we simply need to compare the probabilities given in the table and identify the smallest one.

It's worth noting that the total probability of brake failure across all car models is 0.0048%, which means that the probability of brake failure for any individual car model is quite low.

To express this in a more tangible way, we could say that out of 1000 new cars of model d, we can expect only about 2 or 3 to have brake failure. The low probabilities of brake failure suggest that new cars in general are quite safe and reliable when it comes to braking performance.

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It would take approximately one minute and a half (or 1.6 minutes) to reach 100 jumping jacks at this rate.

What was the activity?

The dependent variable is the number of jumping jacks completed in a specific time period. In this case, the number of jumping jacks completed in one minute is the dependent variable.

The independent variable is the time in minutes. This means that the number of jumping jacks completed is influenced by the time spent doing the activity.

The relationship between the dependent variable (number of jumping jacks completed) and the independent variable (time in minutes) is directly proportional, with a ratio of approximately 63 jumping jacks per minute. This means that for every one minute spent doing jumping jacks, approximately 63 jumping jacks can be completed.

To calculate how much of the activity would be completed if this rate was maintained for 12 minutes, we can multiply the rate (63 jumping jacks per minute) by the time (12 minutes), which gives us 756 jumping jacks.

To find out how long it would take to reach 100 jumping jacks, we can set up a ratio:

63 jumping jacks / 1 minute = 100 jumping jacks / x minutes

We can solve for x by cross-multiplying:

63x = 100

x = 100 / 63

x ≈ 1.6

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Answer:

$2,240

Step-by-step explanation:

1400×3=4,200

4200×20=84,000

84,000÷100=840

840+1400=2,240

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The required answer is P(at least 2) = P(at least 1) * (1/2) = (1 - e^(-λ * a)) * (1/2)

a. To find the long-term average number of people in line, we will use the following formula:

Average number of people in line = λ * a

Here, λ is the arrival rate of customers following a Poisson process, and a is the average time taken by the chef to process an order.

b. To find the long-term probability that there are at least two people in line, we first need to calculate the probability that there is at least one person in line. Then, we will subtract this probability from 1 to find the probability of having at least two people in line.

Probability of at least one person in line = 1 - Probability of no one in line

Since the arrival of customers follows a Poisson process, the probability of having no one in line is given by:

P(0) = e^(-λ * a)

Thus, the probability of at least one person in line is:

P(at least 1) = 1 - e^(-λ * a)

Now, we can calculate the probability of having at least two people in line by considering that the second person joins the line with probability 1/(1 + 1) = 1/2. So, the probability of at least two people in line is:

P(at least 2) = P(at least 1) * (1/2) = (1 - e^(-λ * a)) * (1/2)

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Answer:

1. 5,25,125,625,3125, 15625,78125

Rule: We multiply each term of the sequence by 5.

2.12, 24, 48, 96, 192, 384, 768

Rule: We multiply each term of the sequence by 2.

3. 85, 80, 75, 70, 65, 60, 55

Rule:subtract 5 from each term of the sequence

4.3;5,7,9,11,13,15

Rule: Add 2 to every term in the sequence

5.12, 13,15,16,18,19,21,22

Rule: We first add 1 to the previoys term then add 2 to the new term of the sequence and so on.

The 98% confidence interval for the true mean salary of employees in the Department of Health and Human Services is (34.85, 42.27) thousands of dollars
To find the 98% confidence interval for the true mean salary of employees in the Department of Health and Human Services, we can use the following formula:

CI = x ± t*(s/√n)

where:

x is the sample mean
t is the critical t-value from the t-distribution with n-1 degrees of freedom and a confidence level of 98%
s is the sample standard deviation
n is the sample size
First, we need to calculate the sample mean and sample standard deviation:

Sample mean:
x= (28.5 + 32.1 + ... + 44.8) / 27 = 38.56

Sample standard deviation:
s = sqrt[((28.5-38.56)^2 + (32.1-38.56)^2 + ... + (44.8-38.56)^2) / (27-1)] = 6.05

Next, we need to find the critical t-value using a t-distribution table or Excel function.


Since we have a sample size of n = 27 and a confidence level of 98%, the degrees of freedom is n-1 = 26. Using Excel function "=TINV(0.01, 26)", we get a t-value of 2.485.

Substituting the values into the formula, we get:

CI = 38.56 ± 2.485*(6.05/√27) = (34.85, 42.27)

Therefore, the 98% confidence interval for the true mean salary of employees in the Department of Health and Human Services is (34.85, 42.27) thousands of dollars.

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The area of the shaded portion of the circle which is a sector of the circle would be = 11/9π

To calculate the area of the shaded portion, the radius of the circle should first be determined through tye formula of the length of an arc.

That is;

Length of an arc = 2πr(∅/360)

But length of an arc = 11/9π

∅ = 110°

That is:

11/9π = 2×π×r(110/360)

π will cancel out on both sides;

11/9 = 2×r× 0.3056

11/9 = 0.6111r

r = 11/9×0.6111

r = 2

Area of the shaded sector of the circle = ∅/360×πr²

radius = 2

area = 110/360× π × 2×2

= 110/90π

= 11/9π

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68 – 0. 2 = T and 0. 2(68) = T equation can be written to model this scenario. The correct options are A and C.

The equation 68 – 0.2(68) = T is correct since it represents the total cost after the 20% discount is applied.

The equation 68 – 0.2 = T is not correct since it does not correctly calculate the total cost after the discount.

The equation 68 – 20 = T is not correct since it subtracts the discount amount from the original price, which would give the discounted price before the discount, not the total cost after the discount.

The equation 0.8(68) = T is not correct since it calculates the discounted price, not the total cost after the discount.

Therefore the correct options are a and c.

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We need a sample size of at least n = 214 students to estimate the population mean score if we wish to be 99% confident that the sample mean score is within 1. 8 points of the population mean score for students who are high on the need for closure

We are given that the population standard deviation is σ = 8.19 and the sample mean is X = 177.30 for a sample of n = 78 students in the highest quartile of the "need for closure" scale.

We want to determine the sample size needed to estimate the population mean score for high need for closure students within a margin of error of 1.8 points, with 99% confidence.

Since we do not know the population mean score, we will use a t-distribution to calculate the margin of error. We can use the formula:

margin of error = t_(α/2) * (σ/√n)

where t_(α/2) is the critical value from the t-distribution for a 99% confidence level with (n - 1) degrees of freedom. We can find this value using a t-table or a calculator, and we get t_(α/2) = 2.64 (rounded to two decimal places) for n - 1 = 77 degrees of freedom.

Substituting the given values into the formula, we have:

1.8 = 2.64 * (8.19/√n)

Solving for n, we get:

n = [2.64 * (8.19/1.8)]^2 = 214 (rounded up to the nearest whole number)

Therefore, we need a sample size of at least n = 214 students to estimate the population mean score for high need for closure students within a margin of error of 1.8 points, with 99% confidence.

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