A certain drug is used to treat asthma. In a clinical trial of the​ drug, 30 of 298 treated subjects experienced headaches​ (based on data from the​ manufacturer). The accompanying calculator display shows results from a test of the claim that less than 9​% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.01 significance level to complete parts​ (a) through​ (e) below.
​1-PropZTest
prop<0.09
z=0.643690407
p=0.7401118941
p=0.1006711409
n=298
Question content area bottom
Part 1
a. Is the test​ two-tailed, left-tailed, or​ right-tailed?

Right tailed test

​Two-tailed test

​Left-tailed test
Part 2
b. What is the test​ statistic?
z=enter your response here
​(Round to two decimal places as​ needed.)
Part 3
c. What is the​ P-value?
​P-value=enter your response here
​(Round to four decimal places as​ needed.)
Part 4
d. What is the null​ hypothesis, and what do you conclude about​ it?
Identify the null hypothesis.
A.Upper H 0 : p greater than 0.09
H0: p>0.09
B.Upper H 0 : p less than 0.09
H0: p<0.09
C.Upper H 0 : p not equals 0.09
H0: p≠0.09
D.Upper H 0 : p equals 0.09
H0: p=0.09
Part 5
Decide whether to reject the null hypothesis. Choose the correct answer below.
A.
Fail to reject the null hypothesis because the​ P-value is greater than the significance​ level, α.
B.
Fail to reject the null hypothesis because the​ P-value is less than or equal to the significance​ level, α.
C.
Reject the null hypothesis because the​ P-value is less than or equal to the significance​ level, α.
D.
Reject the null hypothesis because the​ P-value is greater than the significance​ level, α.
Part 6
e. What is the final​ conclusion?
A.
There is not sufficient evidence to support the claim that less than 9​% of treated subjects experienced headaches.
B.
There is sufficient evidence to warrant rejection of the claim that less than 9​% of treated subjects experienced headaches.
C.
There is sufficient evidence to support the claim that less than 9​% of treated subjects experienced headaches.
D.
There is not sufficient evidence to warrant rejection of the claim that less than 9​% of treated subjects experienced headaches.

Answer:

The correct answer is C, Graph D.

x^2 - 4x + 4 = (x - 2)^2.

For the function "f (x) = 120/x²", the domain of the function "f" is (b) All non zero real numbers.

The "Domain" of a function is the set of all possible "input-values" for which the function is defined. In this case, the function is defined as:

f (x) = 120/x²

The only restriction on the input values is that the denominator cannot be equal to zero, because division by zero is undefined.

So, the domain of the function f is all non-zero real numbers.

Therefore, the correct option is (b): All non-zero real numbers.

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The given question is incomplete, the complete question is

Given that f (x) = 120/x², What is the domain of the function f ?

(a) only positive integers,

(b) All non zero real numbers,

(c) only negative integers,

(d) All real numbers including zero.

The angle measures for this problem are given as follows:

θ = 150º and θ = 330º.

The trigonometric expression for this problem is given as follows:

[tex]\theta = \arctan{\left(-\frac{\sqrt{3}}{3}\right)}[/tex]

The solution to the arctangent function is the angle which has the given tangent value.

The angle on the first quadrant with a tangent value of sqrt(3)/3 is given as follows:

θ = 30º.

The quadrants in which the tangent is negative are given as follows:

2nd and 4th.

Hence the equivalent angles are given as follows:

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[tex]\sf Length\, of\,the\,field=\boxed{\sf 104(m)}}.[/tex]

A conversion factor is just a fraction that contains an equivalence. We make the numerator be the unit we want to have as a result and the denominator is the current unit that we have.

The problem states that 0.5 cm equals 8 m, and we want to convert from cm to m, therefore, a conversion factor for this problem is:

[tex]\sf \dfrac{8(m)}{0.5(cm)}[/tex]

To use the conversion factor, just multiply each measure by the fraction:

[tex]\sf 6.5(cm) \dfrac{8(m)}{0.5(cm)}[/tex]

Here the centimeters (cm) cancel out each other and the ending answer is expressed in meters:

[tex]\sf 6.5(cm) \dfrac{8(m)}{0.5(cm)}=\boxed{\sf 104(m)}.[/tex]

For the other measure:

[tex]\sf 3.25(cm) \dfrac{8(m)}{0.5(cm)}=\boxed{\sf 52(m)}.[/tex]

So a soccer field, as you may already know, is always longer than it is wide, therefore, the greatest measure (104m) should be the length of the field.

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The surface area of the rectangular prism is 210 in²

An equation is an expression that shows the relationship between numbers and variables using mathematical operators.

The surface area of a rectangular prism is the sum of each area for the surface.

Hence:

Surface area = 2(8 in * 5 in) + 2(5 in * 5 in) + 2(8 in * 5 in) = 210 in²

The surface area of the prism is 210 in²

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Answer:

x=38.6

Step-by-step explanation:

x=b/cos(alpha)

x=30/cos(39⁰)

x=38.602

18. C

(m / 2) - 6 = (m / 4) + 2

---Multiply everything by the LCM of the denominators

---LCM = 4

2m - 24 = m + 8

m - 24 = 8

m = 32

19. A

k / 12 = 25 / 100

---We can simplify 25/100

---We want to simplify enough to where the denominator of 25/100 is a multiple or factor of 12

k / 12 = 1 / 4

---4 x 3 = 12, 1 x 3 = 3

k = 3

20. A

9 / 5 = 3x / 100

---Cross multiply and solve algebraically

(5 * 3x) = (9 * 100)

15x = 900

x = 60

Hope this helps!

The value of expression 14a +7+ 5b+ 2a + 10b will be 16a + 15b + 7

Since Expression is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

We are given the expression as;

14a +7+ 5b+ 2a + 10b

Combine like terms;

14a + 2a + 10b +7+ 5b

16a + 15b + 7

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The value of the variable a in the equation is 5 from the calculation here.

We need to square of a number is described as a number that when multiplied by itself give the original number.

Also, index forms are described as those mathematical forms that are used to represent numbers that are too large or small.

From the information given, we have the equation;[tex]a^2[/tex]=25

find the square root of value of 25,

We have;25 = [tex]5^2[/tex]

Substitute the value, we get;[tex]a^2[/tex] =  [tex]5^2[/tex]

Take out the similar factor, this is their exponents.

We then have;

a = 5

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Complete question;

Find the value of a in the equation;a² = 25

Answer:

i think its b sorry if  it's wrong

Step-by-step explanation:

Answer: 34,650 permutations

Answer:

All lines are parallel.

Step-by-step explanation:

Get each equation in Slope-Intercept form:

  1. Divide both sides by 3: [tex]y=-\frac{4}{3}x+\frac{7}{3}[/tex]

  2. No change

  3. Subtract 8x and divide by 6 on both sides: [tex]y=-\frac{4}{3}x-\frac{2}{3}[/tex]

Notice:

a. All slopes are -4/3

b. All y-intercepts are different

The Surface area of the composite figure is calculated as approximately: 234 sq. cm

The surface area of the composite figure is the area surrounding the faces of the solid as a whole. Therefore, we have:

Surface area (SA) = Surface area of the square prism + surface area of the square pyramid - 2(area of base)

Area of base = area of square = 6 * 6 = 36 sq. cm.

Surface area of the square prism = 2a² + 4ah

a = 6 cm

h = 4 cm

Plug in the values:

Surface area of the square prism = 2(6²) + 4*6*4

= 72 + 96

= 168 sq. cm.

Surface area of the square pyramid = 2bs + b²

b = side length = 6 cm

s = slant height = √(8² + 3²) = 8.5 cm

Plug in the values:

Surface area of the square pyramid = 2 * 6 * 8.5 + 6² = 138 sq. cm.

Surface area of the composite figure = 168 + 138 - 2(36) = 234 sq. cm

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Answer:

-----------------------------

AB is vertical with same x-coordinates, and BC is horizontal with same y-coordinates.

Hence this is a right triangle.

Its area is:

The solution of the equation is x = -1.

Given is an equation we need to solve it,

3x/4 + 3 - 2x = -1/4 + x/2 +5

Multiplying the equation by 4 both the sides,

3x + 12 - 8x = -1 + 2x + 20

Combining the like terms,

3x - 8x - 2x = 20 - 1 - 12

3x - 10x = 7

-7x = 7

x = -1

Hence the solution of the equation is x = -1.

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Answer:

51/4 quarters

Step-by-step explanation:

To add fractions with different denominators, we need to find a common denominator. In this case, the common denominator for 4 and 2 is 4x2=8.

So we need to convert both fractions to have a denominator of 8:

31/4 = (31/4) x (2/2) = 62/8

41/2 = (41/2) x (4/4) = 164/8

Now we can add the fractions:

62/8 + x/4 = 164/8

Subtracting 62/8 from both sides:

x/4 = 102/8

Simplifying:

x = 51/4

Therefore, we need to add 51/4 quarters to 31/4 to get 41/2

Answer:

f'(x) = 2x, so f'(-2) = 2(-2) = -4.

Thus, the probability for the outcome of either purple or orange: P(purple or orange) = 57/97.

a choice that is made at random (entirely by chance, with no predictability). Every person in the population under study need to have an equal probability of getting chosen. Every person who is under investigation has an equal probability of being chosen at random for the sample.

Given bag with balls:

probability = favourable outcome / total outcome

P(purple) = 28/97

P(orange) = 29/97

Thus,

P(purple or orange) = 28/97 + 29/97

P(purple or orange) = 57/97

Thus, the probability  for the outcome of either purple or orange ball : P(purple or orange) = 57/97.

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In linear equation, 9 is the constant of variation k.

What in mathematics is a linear equation?

An algebraic equation with simply a constant and a first-order (linear) component, such as y=mx+b, where m is the slope and b is the y-intercept, is known as a linear equation.

                             Sometimes, the aforementioned is referred to as a "linear equation of two variables," where x and y are the variables. Equations with variables of power 1 are referred to be linear equations. axe+b = 0 is a one-variable example in which a and b are real numbers and x is the variable.

given x varies inversely with y then

xy = k ← k is the constant of variation

to find k use the condition x = - 4 when y = - 9, hence

k = -4 × -9 = 36

 x = 36/y

 when x = 4 , then  y = 36/4

                                  x = 9

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The given identity (P+1/P-1 + P+1/P+1)-(P-1/P+2 + P+1/P-2)=-4(2p² + 1)/(p²-4) (p² - 1) is proven below

Given the following equation

(P+1/P-1 + P+1/P+1)-(P-1/P+2 + P+1/P-2)=-4(2p² + 1)/(p²-4) (p² - 1)

We start by simplifying the left-hand side of the equation:

(P+1/P-1 + P+1/P+1)-(P-1/P+2 + P+1/P-2)= [(P²+1)/(P(P-1))] + [(P²+1)/(P(P+1))] - [(P²-1)/((P+2)P)] - [(P²+1)/((P-2)P)]

Next, we have the following steps to simplify the expression

= [(P³ + P² + P + 1)/(P(P²-1))] - [(P³ - 3P)/(P(P²-4))]

= [(P³ + P² + P + 1)(P²-4) - (P³ - 3P)(P²-1)]/[(P(P²-1))(P(P²-4))]

= [(P⁵ - 3P³ + P³ - 3P² + P² - 4P + P² - 4P - 4 + P³ - 3P)/(P⁴ - 5P² + 4)]

= [P⁵ - 2P³ - 6P² - 8P - 4]/[(P²-4)(P²-1)]

= -4(2p² + 1)/(p²-4) (p² - 1)

Hence, the given identity is proven.

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Answer:

$2,631.55

Step-by-step explanation:

To find the total amount in the account after 6 years, we can use the compound interest formula.

[tex]\boxed{\sf A=P\left(1+\dfrac{r}{n}\right)^{nt}}[/tex]

where:

Given values:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=2000\left(1+\dfrac{0.046}{4}\right)^{4 \cdot 6}[/tex]

[tex]\implies \sf A=2000\left(1+0.0115\right)^{24}[/tex]

[tex]\implies \sf A=2000\left(1.0115\right)^{24}[/tex]

[tex]\implies \sf A=2000\left(1.3157739...\right)[/tex]

[tex]\implies \sf A=2631.54794...[/tex]

Therefore, the total amount after 6 years is $2,631.55 rounded to the nearest cent.

The probability of Caleb selecting a 5 on the first selection and then selecting a 5 on the second selection after returning the card to the deck and shuffling is 1/9.

There are a total of 12 cards, out of which 4 are 5s. Since Caleb returns the card to the deck and shuffles it, the selection of the first card does not affect the probability of selecting a 5 on the second selection.

Therefore, the probability of selecting a 5 on the first selection is 4/12 = 1/3, and the probability of selecting a 5 on the second selection is also 4/12 = 1/3.

Since the events are independent, we can multiply the probabilities to find the probability of both events occurring:

P(selecting a 5 on first selection and selecting a 5 on second selection) = P(selecting a 5 on first selection) x P(selecting a 5 on second selection)

= (1/3) x (1/3)

= 1/9

Therefore, the probability that Caleb selects a 5 on the first selection, returns the card to the deck, shuffles the cards, and then draws a 5 on the second selection is 1/9.

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The measure of angle JKM is 26°

The exterior angle theorem states that the exterior angle of a triangle is equal to the sum of the opposite angles in the triangle.

Also the sum of angle in a triangle is 180°

Therefore ;

3x+64 = 5x+4

collecting like terms

5x -3x = 64-4

2x = 60

x = 60/2

x = 30

since x = 30

value of the exterior angle = 5x+4

= 5×30+4

= 150+4 = 154

therefore angle JKM = 180-( 154)

= 26°

Therefore the measure of angle JKM is 26°

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There are 1100 many ways can be done that is when catering service offers 5 appetizers, 11 main courses, and 4 desserts.

Given that,

A catering service offers 5 appetizers, 11 main courses, and 4 desserts. A customer is to select 4 appetizers, 9 main courses, and 3 desserts for a banquet.

We have to find how many ways can this be done.

We know that,

Number of appetizers offered = 5

Number of appetizers customer is to select = 4

Number of main courses offered = 11

Number of main courses customer is to select = 9

Number of desserts offered = 4

Number of desserts the customer is to select = 3

So,

To determine the number of ways this can be selected,

By using the combination formula that is

[tex]^nC_r = \frac{n!}{r!(n-r)!}[/tex]
[tex]^nC_r = ^5C_4\times ^{11}C_9\times^4C_3[/tex]

[tex]^5C_4\times ^{11}C_9\times^4C_3 = \frac{5!}{4!(5-4)!} \times \frac{11!}{9!(11-9)!}\times \frac{4!}{3!(4-3)!}[/tex]

[tex]^5C_4\times ^{11}C_9\times^4C_3 = \frac{5!}{4!1!} \times \frac{11!}{9!2!}\times \frac{4!}{3!1!}[/tex]

[tex]^5C_4\times ^{11}C_9\times^4C_3 = \frac{5!}{4!} \times \frac{11!}{9!(2)}\times \frac{4!}{3!}[/tex]

[tex]^5C_4\times ^{11}C_9\times^4C_3 =[/tex] 5 × 11 × 5 × 4

[tex]^5C_4\times ^{11}C_9\times^4C_3 =[/tex] 1100

Therefore, There are 1100 many ways this can be done.

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The value of the 3 × f( - 4 ) - 3 × g( - 2 ) is 40

Given the following expression 3 × f( - 4 ) - 3 × g( - 2 ), to find the required values, we can assume that;

f( - 4 ) = 15

g( - 2 ) = 5

Substitute the given parameters into the expression to have:

3 × f(- 4 ) - 3 × g(- 2) = 3 × 15 - 3 × 5

= 45 - 5

= 40

Hence the value of the 3 × f( - 4) - 3 × g( - 2) is 40

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Step-by-step explanation:

m ∠WXY = 72°

m ∠ 1 = m ∠ 2 + 6°

m ∠WXY = m ∠ 1 + m ∠ 2

72° = (m ∠ 2 + 6°) + m ∠ 2

72° = 2 × (m ∠ 2) + 6°

2 (m ∠ 2) = 72° - 6°

2 (m ∠ 2) = 66°

(m ∠ 2) = 33°

Answer:

Assuming you meant to write "x^2 - 4x - 12", there are a few equivalent forms that you could use to represent this expression. One common form is:

(x - 6)(x + 2)

Step-by-step explanation:

This is the factored form of the expression, which shows that it can be written as a product of two linear factors. To see why this is true, you can use the distributive property to expand the product:

(x - 6)(x + 2) = x(x + 2) - 6(x + 2) = x^2 + 2x - 6x - 12 = x^2 - 4x - 12

a) The formula relating y to t is: y = 45.1 * e^(-0.693/19 * t) b) there will be approximately 30.1 mg of the substance present after 9 minutes.

(a) The general formula for exponential decay is y = y0 * e^(-kt), where y is the amount at time t, y0 is the initial amount, k is the decay constant, and e is Euler's number.

To find the decay constant, we can use the fact that the half-life is 19 minutes. The formula for half-life is t1/2 = ln(2) / k, where ln(2) is the natural logarithm of 2.

Substituting t1/2 = 19 and ln(2) = 0.693 into the formula gives:

19 = 0.693 / k

k = 0.693 / 19

So the formula relating y to t is:

y = 45.1 * e^(-0.693/19 * t)

(b) To find how much will be present in 9 minutes, we can plug t = 9 into the formula we found in part (a):

y = 45.1 * e^(-0.693/19 * 9) ≈ 30.1 mg

So, there will be approximately 30.1 mg of the substance present after 9 minutes.

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