x/2 = -5 solve for x

Answer:

A. (I) v = 46.42 m/s; (ii) v = 47.35 m/s; (III) v = 48.09 m/s; (iv) v = 48.26 m/s; (v) v = 58.28 m/s

B. v = 48.28 m/s

Note: the question is missing some values. The full Question is provided below:

If an arrow is shot upward on Mars with a speed of 52 m/s, its height in meters t seconds later is given by y = 52t − 1.86t2. (Round your answers to two decimal places.)

(a) Find the average speed over the given time intervals. (i) [1, 2] m/s (ii) [1, 1.5] m/s (iii) [1, 1.1] m/s (iv) [1, 1.01] m/s (v) [1, 1.001] m/s

(b) Estimate the speed when t = 1. m/s

Step-by-step explanation:

Height, y = 52t - 1.86t²

Velocity = ∆y/∆t = 52 - 1.86 * 2t = 52- 3.72t

A. Average velocity = (v1 + v2)/2

(i) At t = 1, 2

Average velocity = (52 - 3.72*1 + 52 -3.72*2)/2 = 46.42 m/s

(ii) At t = 1,1.5

Average velocity = (52 - 3.72*1 + 52 - 3.72*1.5)/2 = 47.35 m/s

(iii) At t = 1,1.1

Average velocity = (52 - 3.72*1 + 52 -3.72*1.1)/2 = 48.09m/s

(iv) At to = 1, 1.01

Average velocity = (52 - 3.72*1 + 52 - 3.72*1.01)/2 = 48.26 m/s

(iv) At t = (1, 1.001)s

Average velocity = (52 - 3.72*1 + 52 - 3.72*1.001)/2 = 48.28 m/s

B. Speed at t = 1s

Velocity = 52 - 3.72 * 1 = 48.28 m/s

Answer:

[tex]P(210<X<290)=P(\frac{210-\mu}{\sigma}<\frac{X-\mu}{\sigma}<\frac{290-\mu}{\sigma})=P(\frac{210-202}{70}<Z<\frac{290-202}{70})=P(0.114<z<1.26)[/tex]

And we can find this probability with this difference

[tex]P(0.114<z<1.26)=P(z<1.26)-P(z<0.114)[/tex]

And we can find the difference with the normal standard distirbution or excel:

[tex]P(0.114<z<1.26)=P(z<1.26)-P(z<0.114)=0.896-0.545=0.351[/tex]

Step-by-step explanation:

Let X the random variable that represent the hotel room cost of a population, and for this case we know the distribution for X is given by:

[tex]X \sim N(202,70)[/tex]  

Where [tex]\mu=202[/tex] and [tex]\sigma=70[/tex]

We are interested on this probability

[tex]P(210<X<290)[/tex]

The z score formula is given by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

Using the formula we got:

[tex]P(210<X<290)=P(\frac{210-\mu}{\sigma}<\frac{X-\mu}{\sigma}<\frac{290-\mu}{\sigma})=P(\frac{210-202}{70}<Z<\frac{290-202}{70})=P(0.114<z<1.26)[/tex]

And we can find this probability with this difference

[tex]P(0.114<z<1.26)=P(z<1.26)-P(z<0.114)[/tex]

And we can find the difference with the normal standard distirbution or excel:

[tex]P(0.114<z<1.26)=P(z<1.26)-P(z<0.114)=0.896-0.545=0.351[/tex]

The image of P(-2,1) after it is rotated 90° is (-1,-2).

Answer:

a) The Expectation of the Population  to grow in the next year

                         = 3069

b) The Expectation of the Population decrease in the next year

                         = 12,467

Step-by-step explanation:

Explanation:-

a)

The population of Boom town is currently 3000

Given expected to grow by 2.3 % over the  next year

                  = [tex]3000 X \frac{2.3}{100} = 69[/tex]

                  = 69

The Expectation of the Population growth in the next year

                         = 3000 +69 = 3069

b)

The population of town is currently 13000

Given expected to grow by 4.1 % over the  next year

                  = [tex]13000 X \frac{4.1}{100} = 533[/tex]

The Expectation of the Population decrease  in the next year

                         = 13000 - 533 = 12,467

Answer:

π

Step-by-step explanation:

For a circle, arc length is equal to the radius times the angle.

s = rθ

s = (1) (π − 0)

s = π

Answer:

y = x+15

Step-by-step explanation:

y - 15=x

Add 15 to each side

y - 15+15=x+15

y = x+15

Answer:

[tex]y=x+15[/tex]

Step-by-step explanation:

[tex]y - 15=x[/tex]

Add [tex]15[/tex] on both sides of the equation.

[tex]y - 15+15=x+15[/tex]

The [tex]y[/tex] should be isolated on one side of the equation.

[tex]y=x+15[/tex]

Answer:

[tex]z^{0.5}[/tex]

Step-by-step explanation:

So first simplify inside:

[tex]z^4z^{-1.5}=z^{2.5}[/tex]

Now divide that by 5:

[tex]z^{0.5}[/tex]

Answer:

1: Glide

2: Reflection

3: Reflection

Step-by-step explanation:

1): The first one is glide because you are just moving the triangle and not changing anything to the angle and the size.

2): The second one is a reflection because you are reflecting across an invisable line. Basicly think of it as a mirror. In the picture below, you can see the line of reflection.

3): The third one is also a reflection for the same reason as the second, (view attached image below for line of reflection.

Answer: y= -2/3 + 8/3

Step-by-step explanation:

-2/3  is the slope so you just need the y-intercept to write the equation in general form or slope intercept form

4= -2/3(-2) +b

4 = 4/3  + b

-4/3   -4/3

b=  8/3

general form is   y= -2/3 + 8/3

Answer:

113 feet

Step-by-step explanation:

Use the ratio 1:50 to calculate the height of the tower.

The scale model height is 2.25 feet, so multiply that by 50

2.25 x 50 = 112.5

Round to 113 feet

Answer:

D. 113 feet

Step-by-step explanation:

We know that Josephine made a smaller model that is one-fiftieth the size of the real model. That means the height of the real model is fifty times as big as this model. All we need to do to find the height of the real thing is to multiply 50 and 2.25. (50) 2.25 = 112.5. That will round to 113 feet, which is the height of the new water tower.

Hope this helps ^-^

Answer:

s(t)=8t

Step-by-step explanation:

The length of the sides of a square are initially 0 cm and increase at a constant rate of 8 cm per second.

Let the length of the Square = s

[tex]\dfrac{ds}{dt}=8 $cm/seconds, s_0=0 cm[/tex]

We solve the differential equation above subject to the given initial condition.

[tex]\dfrac{ds}{dt}=8\\ds=8$ dt\\Take the integral of both sides\\\int ds=\int 8$ dt\\s(t)=8t+C, where C is the constant of integration\\When t=0, s=0cm\\s(0)=0=8(0)+C\\C=0\\Therefore, s(t)=8t[/tex]

The formula that expresses the side length of the square, s (in cm), in terms of the number of seconds, t , since the square's side lengths began growing is:

s(t)=8t (in cm)

Answer:

Step-by-step explanation:

Area of rectangle = l × b

= 23 × 6

= 138 feet

hope this helps

plz mark it as brainliest!!!!!!!

Answer:

[tex] p =\frac{7}{51}= 0.1372[/tex]

And then the probability that is NOT from sport temas using the complement rule is given by:

[tex] q = 1-p =1- \frac{7}{51}= 0.8627[/tex]

And if we convert that into % we got:

[tex] 0.8627 *100= 86.27\%[/tex]

Approximately 86.27% of the floats were NOT sports teams

Step-by-step explanation:

For this case we can begin finding the % of floats that were from sport tems using the Laplace definition of probability given by:

[tex]p = \frac{Possible}{Total}[/tex]

And replacing we got:

[tex] p =\frac{7}{51}= 0.1372[/tex]

And then the probability that is NOT from sport temas using the complement rule is given by:

[tex] q = 1-p =1- \frac{7}{51}= 0.8627[/tex]

And if we convert that into % we got:

[tex] 0.8627 *100= 86.27\%[/tex]

Approximately 86.27% of the floats were NOT sports teams

Answer:

19 marbles in each bag 28 left over

Step-by-step explanation:

the first step to this problem is to find out the number of marbles in each bag.

if there were 731 marbles and 37 bags, we need to divide 731 by 37.

731/37 = 19[tex]\frac{28}{37}[/tex]

therefore there are 19 marbles in each bag.

the second part of the question is to determine how many are left out or in other words how many numbers are "left over"

since the fraction is 28/37 there are 28 marbles that are left out of the bag.

feel free to ask questions, hope this helped you!

Answer:

P = 62.5 %

Step-by-step explanation:

Of means multiply and is means equals

P * 48  = 30

Divide each side by 48

P = 30/48

P = .625

Change to percent form

P = 62.5 %

Answer:

62.5%

Step-by-step explanation:

30 is 62.5% of 48 since:

30÷48=0.625

0.625×100=62.5%

Answer:

37.047

Step-by-step explanation:

Sin(39) = 30/hyp

Cos(39) = x/hyp

hyp = 30/Sin(39)

and hyp = x/Cos(39)

hyp = hyp

30/Sin(39) = x/Cos(39)

x = 30(Cos(39))/Sin(39)

x is approximately equal to 37.047

Answer:

2

Step-by-step explanation:

Answer: y = 11 - x / -6

Step-by-step explanation:

X - 6y = 11

Since we are solving for y, we need to isolate the variable.

Move x to the other side of the equation.

- 6y = 11 - x

Now divide bith sides by -6 to cancel out -6y and get the variable y

-6y/ -6 = 11 - x/ -6

y = 11 - x / -6

Im not sure if it was solving for y, or if it was solve for x if y = 11

Mark all of the values that are between 61 and 80. See the diagram below. You should mark exactly 6 values.

Answer:

c

Step-by-step explanation:

Answer:

Step-by-step explanation:

The formula for the area of a triangle is base*height divided by 2. Remember this because itll be important for everything you do in math relating to geometry and calculus. Assuming you go that far

[tex]\frac{base*height}{2} =\frac{14*8}{2} =\frac{112}{2} = 56 units^2[/tex]

Answer:

A =56 units^2

Step-by-step explanation:

The area of a triangle is given by

A =1/2 bh where 14 is the base and 8 is the height

A = 1/2 (14)8

A =56 units^2

Answer:

  24.2

Step-by-step explanation:

You are given the hypotenuse and angle, and you want to find the length of the adjacent side.

The mnemonic SOH CAH TOA reminds you that the relation between angle and sides is ...

  Cos = Adjacent/Hypotenuse

  cos(41°) = x/32

  x = 32·cos(41°)

  x ≈ 24.2

Answer:

4.8

Step-by-step explanation:

simple interest=Principal ×time×rate ÷100

=24×4×5÷100

=4.8

Answer:

Around 57.74 feet

Step-by-step explanation:

The tower and James form a right triangle, where the other two angles are 30 degrees and 60 degrees. The tangent of an angle is equivalent to the length of the opposite side divided by the length of the adjacent side, which means:

[tex]\tan 30=\dfrac{x}{100} \\\\x=\tan 30 \cdot 100 \approx 57.74[/tex]

Hope this helps!

Answer:

It can produce 1590 loaves of bread per day.

Step-by-step explanation:

Given that the bread machine operates only 10 hours per day. So in order to calculate how many loaves can be produce a day, you have to multiply it by 10 :

[tex]1hour = 159loaves[/tex]

[tex]10hours = 159 \times 10[/tex]

[tex]10hours = 1590loaves[/tex]

Answer:

4 pizza's

Step-by-step explanation:

hope this helps :)

Answer:

Step-by-step explanation:

A=πr^2

But A=88/63

88/63=πr^2

88/63π=r^2

√88/63π=r

Answer:

C. Parameter since the data set of all 14 teams is a population.

Explanation:

Find the attachment

Answer:

Options A, B and E are correct

Step-by-step explanation:

From the information given above, we would draw a dilation that produces an image that is the same shape as the original image, but has a different size.

The scale factor is 2

QRS → Q'R'S' = (x,y) → 2(x,y)

The coordinates of ∆QRS

Q (-3, 3)

R (2, 4)

S (-1, 1)

To get the coordinates of Q'R'S', we would multiply each coordinate of the original triangle by the scale factor of 2 since the dilation is from the origin. In order words, each vertex of QRS is multiplied by 2 to get each of the vertex of Q'R'S'.

2 (x,y) = (2x, 2y)

The coordinates of ∆Q'R'S' becomes:

Q' (-6, 6)

R' (4, 8)

S' (-2, 2)

To determine the statements that are true about the image ΔQ'R'S,

we would graph the coordinates of the two triangles.

Starting with ΔABC, we would draw the dilation image of the triangle with a center at the origin and a scale factor of 2.

See attached the diagram for better explanation.

Let's check out each options and compare it with diagram we obtained:

a) DO, 2 (x,y) = (2x, 2y)

A dilation about the origin with a scale factor 2 is described using the above notation.

Q' = 2(-3,3) = [2(-3), 2(3)] = (-6, 6)

R' (4, 8) = 2(2,4) = [2(2), 2(4)] = (4, 8)

S' (-2, 2) = 2(-1,1) = [2(-1), 2(1)] = (-2, 2)

This option is correct

b) Side Q'S' lies on a line with a slope of -1

Q' (-6, 6)

S' (-2, 2)

coordinate (x, y)

Slope = m = (change in y)/(change in x)

m = (6-2)/[-6-(-2)]

= 4/(-6+2) = 4/-4

m = -1

This option is correct

c) QR is longer than Q'R'

Length of QR (-3 to 2) = 5

Length of Q'R' (-6 to 4) = 10

QR is not longer than Q'R'

This option is false

d) The vertices of the image are closer to the origin than those of the pre-image

The scale factor determines how much bigger or smaller the dilation image will be compared to the preimage. In a transformation, the final figure is referred to as the image. The original figure is referred to as the preimage.

From the diagram, the vertices of the preimage (original image) are closer to the origin than those of the dilation image.

This option is false

e) The distance from Q' to the origin is twice the distance from Q to the origin.

The distance from Q' to the origin (6 to 0) = 6

The distance from Q to the origin (3 to 0) = 3

The distance from Q' to the origin = 2(the distance from Q to the origin)

This option is correct

Answer:

A,B and E is correct

Step-by-step explanation: