without a calculator find out
√28 ÷ √7

Answer:

y > -1

Step-by-step explanation:

The range is about the y, not the x, so we can eliminate options B & D.

We see the y touch -1 and then go up to ∞, so the answer is y > -1

The sound level of the vocalizations of a blue whale is approximately 140.28 decibels.

The question asks us to find the sound level in decibels (db) of the vocalizations of a blue whale, given its sound intensity of 106.8 watts/meter2.

The formula for sound level in decibels is:

L = 10log(i/I0)

Where L is the sound level in decibels, i is the sound intensity in watts/meter2, and I0 is the smallest sound intensity that can be heard by the human ear (approximately 1x10⁻¹² watts/meter2).

Plugging in the given values, we get:

L = 10log(106.8/1x10⁻¹² )

Simplifying this expression, we get:

L = 10log(1.068x10¹⁴)

L = 10(14.028)

L = 140.28

Therefore, the sound level of the vocalizations of a blue whale is approximately 140.28 decibels.

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1a. The period of the motion is the time it takes for the horse to complete one full cycle of motion, and it is given by:

T = 2π/ω.

See attached graph.

1b. The period of the motion is the time it takes for the carousel to complete one full cycle of motion, and it is also given by:

T = 2π/ω.

1a.
let's assume that the motion of the horse can be modeled by a simple harmonic motion. The equation for simple harmonic motion is:

y = A sin(ωt + φ)

where:

y is the displacement from the equilibrium position

A is the amplitude (maximum displacement)

ω is the angular frequency (2π times the frequency)

t is time

φ is the phase angle

Assuming that the horse's motion is in a vertical direction and that the highest point of its motion corresponds to y = 0, we can write the equation as:

y = A sin(ωt)

where A is the amplitude of the motion and ω is the angular frequency.

We can plot this function as a sine wave on a graph, where the horizontal axis represents time and the vertical axis represents displacement. The period of the motion is the time it takes for the horse to complete one full cycle of motion, and it is given by:

T = 2π/ω

To determine when Ivan will get his next opportunity to take a perfect shot, we need to know the period of the horse's motion. Without additional information, it's difficult to estimate the period accurately.


The graph of the carousel equation θ = A cos(ωt) can be labeled as follows:

1b.
The motion of the carousel can also be modeled as a simple harmonic motion, with the equation:

θ = A cos(ωt + φ)

where:

θ is the angular displacement from the equilibrium position

A is the amplitude (maximum angular displacement)

ω is the angular frequency (2π times the frequency)

t is time

φ is the phase angle


The period of the motion is the time it takes for the carousel to complete one full cycle of motion, and it is given by:

T = 2π/ω

To determine when Ivan will get his next opportunity to take a perfect shot, we need to know the period of the carousel's motion. Without additional information, it's difficult to estimate the period accurately.

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Stevie will need to work at least 150 hours to make at least $1200 after accounting for the initial cost of equipment.

to find the business hours of work, Let's start by defining the variables given in the problem:

The initial cost of equipment is $175.

Stevie charges $12 per hour for cleanup.

Stevie wants to make at least $1200.

The number of hours worked is represented by h.

Now, we can set up an equation to solve for h:

Total earnings - Total cost = Desired profit

We can express the total earnings as the product of the hourly rate and the number of hours worked:

Total earnings = $12h

The total cost includes the initial cost of equipment plus any additional costs incurred during cleanup:

Total cost = $175 + additional costs

Since we don't know the value of the additional costs, we'll leave it as a variable.

Substituting these expressions into the equation, we get:

$12h - ($175 + additional costs) = $1200

Simplifying the equation, we get:

$12h - $175 - additional costs = $1200

$12h - $1375 = additional costs + $1200

$12h - $1375 = additional costs

Now we have an equation that relates the number of hours worked to the additional costs incurred during cleanup. We want to find the minimum value of h that satisfies this equation, since Stevie wants to make at least $1200.

To do this, we need to estimate the additional costs incurred during cleanup. Let's assume that Stevie spends an average of $4 per hour on additional costs (e.g., gasoline, trash bags, etc.). Then, the equation becomes:

$12h - $1375 = $4h + $175

Simplifying further, we get:

$8h = $1200

h = 150

Therefore, Stevie will need to work at least 150 hours to make at least $1200 after accounting for the initial cost of equipment and the estimated additional costs incurred during cleanup.

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The probability that a randomly selected house with 2 bathrooms has 3 is: 0.8.

So, the fourth option is correct.

We have given that,

The two-way table shows the number of houses on the market in the Castillos’ price range.

A 6-column table has 4 rows.

The first column has entries 1 bathroom, 2 bathrooms and 3 bathrooms, in total.

The second column is labeled 1 bedroom with entries 67, 0, 0, 67.

The third column is labeled 2 bedrooms with entries 21, 6, 18, 45.

We are only considering the houses that have 2 bathrooms.

There are a total of 30 of these houses.

Out of these 30, 24 have 3 bedrooms.  

What is the formula for probability?

The probability of an event can only be between 0 and 1 and can also be written as a percentage.

This makes the probability 24/30, which is 0.8.

Therefore, the probability that a randomly selected house with 2 bathrooms has 3 is: 0.8.

So, the fourth option is correct.

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To find the elasticity of demand for the function q = D(x) = 460 - x, we can use the formula:

Elasticity = (% change in quantity demanded) / (% change in price)

a) Since the demand function given does not include a price variable, we can assume that price is constant. Therefore, the elasticity of demand for this function is constant and equal to -1.

b) To find the elasticity at x = 103, we need to calculate the percentage change in quantity demanded when x increases from 103 to 104.

At x = 103, quantity demanded is q = D(103) = 460 - 103 = 357.

At x = 104, quantity demanded is q = D(104) = 460 - 104 = 356.

The percentage change in quantity demanded is:

(% change in quantity demanded) = [(new quantity - old quantity) / old quantity] x 100

= [(356 - 357) / 357] x 100 = -0.28%

Since the elasticity of demand is -1, we can say that demand is inelastic at x = 103.

c) To find the elasticity at x = 205, we need to calculate the percentage change in quantity demanded when x increases from 205 to 206.

At x = 205, quantity demanded is q = D(205) = 460 - 205 = 255.

At x = 206, quantity demanded is q = D(206) = 460 - 206 = 254.

The percentage change in quantity demanded is:

(% change in quantity demanded) = [(new quantity - old quantity) / old quantity] x 100

= [(254 - 255) / 255] x 100 = -0.39%

Since the elasticity of demand is -1, we can say that demand is inelastic at x = 205.
Hi! I'd be happy to help you with your question on elasticity of demand.

a) To find the elasticity, we first need the formula for price elasticity of demand (PED), which is:

PED = (% change in quantity demanded) / (% change in price)

Here, we have the demand function D(x) = 460 - x, where x is the price.

b) To find the elasticity at x = 103, we first need to calculate the quantity demanded, which is:

q = D(103) = 460 - 103 = 357

Now, we'll find the derivative of the demand function with respect to price:

dq/dx = -1

Next, we'll use the formula for PED:

PED = (dq/dx * x) / q = (-1 * 103) / 357 = -103/357 ≈ -0.289

Since the absolute value of PED is less than 1, demand is inelastic at x = 103.

c) To find the elasticity at x = 205, we'll follow the same steps:

q = D(205) = 460 - 205 = 255

PED = (dq/dx * x) / q = (-1 * 205) / 255 ≈ -0.804

Again, the absolute value of PED is less than 1, so demand is inelastic at x = 205.

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The vertex of the function is -6.

The domain of the function is {real numbers}.

The range of the function is y ≥ -6.

The range and domain of the function is calculated as follows;

y = x² - 2x - 5

From the graph of the function, the range of the function includes y values;

range = y ≥ -6

From the graph of the function, the domain of the function includes x values;

domain = real numbers.

The vertex of the graph is -6.

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Answer:

5,005

Step-by-step explanation:

This is a combination problem. The formula for combination is:

nCr = n! / (r!(n-r)!)

Where n is the total number of items, and r is the number of items to be selected.

Using this formula, we can calculate the number of ways to choose 9 varieties from 15:

15C9 = 15! / (9!(15-9)!) = 5005

Therefore, there are 5,005 ways to choose 9 varieties from 15 varieties of pansies.

The  function f(x)=500[tex]x^2[/tex] +10,000  can  be  used  to  model  the  food  vendor's  annual  revenue. The  food  vendor  would expect  to  bring  in  $ 60,000  in  annual  revenue by 10 years from now.

To find out when the mobile food vendor should expect to bring in $60,000 in annual revenue using the function f(x) = 500x^2 + 10,000, follow these steps:

1. Set the function equal to 60,000: 500[tex]x^2[/tex]+ 10,000 = 60,000
2. Subtract 60,000 from both sides of the equation: 500[tex]x^2[/tex]+ 10,000 - 60,000 = 0
3. Simplify the equation: 500[tex]x^2[/tex]- 50,000 = 0
4. Divide both sides by 500:[tex]x^2[/tex] - 100 = 0
5. Add 100 to both sides: [tex]x^2[/tex] = 100
6. Find the square root of both sides: x = ±10

Since it doesn't make sense to have a negative number of years, the food vendor should expect to bring in $60,000 in annual revenue 10 years from now.

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If a number cube is rolled twice, then the probability of getting a six on the first role and then a number less than 5 on the second role is 1/9.

To find the probability of getting a six on the first roll and a number less than 5 on the second roll, we will multiply the individual probabilities of each event.

A number cube has 6 faces, so the probability of rolling a six is 1/6.

For the second roll, there are 4 numbers less than 5 (1, 2, 3, and 4), so the probability of rolling a number less than 5 is 4/6 or 2/3.

To find the combined probability, simply multiply the two probabilities: (1/6) × (2/3) = 2/18 = 1/9.

So, the probability of getting a six on the first roll and a number less than 5 on the second roll is 1/9.

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The absolute value of -8 1/2 is less than the absolute value of -9 1/2.

To compare the absolute values of -8 1/2 and -9 1/2, follow these steps:
1. Convert the mixed numbers to improper fractions:
-8 1/2 = -17/2
-9 1/2 = -19/2

2. Find the absolute values of both numbers:
|-17/2| = 17/2
|-19/2| = 19/2

3. Compare the absolute values and choose the correct symbol:
17/2 < 19/2
So, the statement is: The absolute value of -8 1/2 is less than the absolute value of -9 1/2.

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The power rule for derivatives is  -26/5.

The derivative is a fundamental concept that measures how much a function changes as its input changes. It is a mathematical tool used to find the instantaneous rate of change of a function at a specific point. The derivative of a function f(x) at a point x=a, denoted by f'(a), is the slope of the tangent line to the graph of f(x) at the point (a, f(a)).

a. f(x) = 2x³

Using the power rule for derivatives, we have:

f'(x) = 6x²

So, f'(2) = 6(2)² = 24.

b. g(x) = 13x^(1/2)

Using the power rule for derivatives, we have:

g'(x) = (1/2) * 13x^(-1/2) = (13/2√x)

So, g'(3) = (13/2√3).

c. h(x) = hx

Using the power rule for derivatives, we have:

h'(x) = h

So, h'(4) = h.

d. j(x) = 130x^(-1)

Using the power rule for derivatives, we have:

j'(x) = -130x^(-2)

So, j'(5) = -130(5)^(-2) = -130/25 = -26/5.

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Bristol is the cheapest city and Paul can drop from his plans to stay under budget.

To determine which city Paul can drop and still stay under budget, we need to find the total cost of visiting all four cities and compare it to Paul's budget of £300.

We do not have information about the cost of sightseeing in each city, so we will assume that the cost is the same for each city. In that case, the cost of visiting all four cities is:

Cost of visiting all cities = Cost of visiting one city x 4

Let's call the cost of visiting one city "x". Then:

Cost of visiting all cities = x * 4

To stay under budget, the cost of visiting all cities must be less than or equal to £300. So we can write the following inequality:

Simplifying this inequality, we get:

x ≤ £75

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The answer is (c) Bristol, as it has the highest cost among the remaining cities and dropping it would leave Paul with 224 pounds, which is still within his budget.

A budget is whenever one plans on how to spend an estimated income. All the income should be considered as well as all the expenses. In other words, it is an expending plan.

The total cost of visiting all cities is:

76 + 66 + 91 + 60 + 72 = 365

To stay under budget, Paul must drop at least one city. To determine the cheapest city to drop, we can calculate the cost of the trip to each city if visited individually and compare it to the remaining budget:

- Bristol: 76 pounds

 Remaining budget: 300 - 76 = 224 pounds

- Leicester: 66 pounds

 Remaining budget: 300 - 66 = 234 pounds

- Glasgow: 91 pounds

 Remaining budget: 300 - 91 = 209 pounds

- Leeds: 60 pounds

 Remaining budget: 300 - 60 = 240 pounds

- Belfast: 72 pounds

 Remaining budget: 300 - 72 = 228 pounds

The city that Paul can drop while staying under budget is the one with the lowest cost.

Therefore, the answer is (c) Bristol, as it has the highest cost among the remaining cities and dropping it would leave Paul with 224 pounds, which is still within his budget.

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The 90% confidence interval for the sample is (35.384, 36.616).

We may use the following expression to determine the 90% confidence interval for a sample of 64 participants with a mean of 36 and a standard deviation of 3.

⇄

where: X = sample mean

Z[tex]\alpha[/tex]/2 = critical value for a 90%  level from the ordinary normal distribution, which is roughly 1.645

σ = population standard deviation

n = sample size

Inputting the values provided yields:

CI = 36 ± 1.645 * (3 / √64)

When we condense the equation between the brackets, we obtain:

CI = 36 ± 1.645 * (3 / 8)

Further simplification results in:

CI = 36 ± 0.616

Consequently, the sample's 90% confidence interval is as follows:

(36 - 0.616, 36 + 0.616) = (35.384, 36.616)

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To translate one-step equations, you need to understand the language of algebra.

Algebraic expressions involve variables, numbers, and operations such as addition, subtraction, multiplication, and division. One-step equations require only one operation to isolate the variable, making them easy to solve.

To write an equation to represent the statement "15 is 9 more than j," you can use the equation 15 = j + 9. This equation says that 15 is equal to j plus 9. To solve for j, you need to isolate j on one side of the equation by subtracting 9 from both sides. This gives you the equation j = 6.

To solve the equation j % 3 = c, you need to understand the modulus operator, which gives you the remainder when two numbers are divided. In this case, j % 3 means the remainder when j is divided by 3. To solve for j, you need to multiply both sides of the equation by 3, which gives you the equation j = 3c.

In summary, to translate one-step equations, you need to understand the language of algebra and the operations involved. To solve for variables, you need to isolate them on one side of the equation. And to solve equations involving the modulus operator, you need to understand how it works and how to apply it to solve for variables.

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To answer question a, we use the formula:

time taken = (number of tyres to fit x time taken to fit one tyre) / number of tyres fitted at once

In this case, Liam takes 124 minutes to fit 4 tyres to a lorry. To find out how long it would take him to fit 6 tyres, we plug in the values:

time taken = (6 x 124) / 4
time taken = 186 minutes

So it would take Liam 186 minutes to fit 6 tyres to a lorry.

For question b, we know that Liam takes 124 minutes to fit 4 tyres, so he takes 31 minutes to fit 1 tyre. If he works for 93 minutes, we can find out how many tyres he can fit:

number of tyres = time taken / time taken to fit one tyre
number of tyres = 93 / 31
number of tyres = 3

So Liam can fit 3 tyres in 93 minutes.

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You can fill 4 five liter gas tanks from a full 20 liter gas can.

To determine how many 5-liter gas tanks can be filled from a full 20-liter gas can, you would divide the total capacity of the gas can by the capacity of the individual gas tanks.

Step 1: Identify the total capacity of the gas can (20 liters) and the capacity of each gas tank (5 liters).
Step 2: Divide the total capacity by the individual tank capacity (20 liters / 5 liters).

Your answer: You can fill 4 (20 liters / 5 liters = 4) 5-liter gas tanks from a full 20-liter gas can.

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The radius of gyration of the plate about the x-axis is [tex]6 \sqrt{6} / 5[/tex] units.

To find the radius of gyration of a plate covering the region bounded by [tex]y = x^2[/tex], x = 6, and the x-axis with respect to the x-axis, we need to use the formula:

[tex]k_x = \sqrt{(I_x / A)}[/tex]

where [tex]k_x[/tex] is the radius of gyration, [tex]I_x[/tex] is the moment of inertia of the plate about the x-axis, and A is the area of the plate.

We can calculate the area A of the plate as follows:

[tex]A = \int\limits^6_0 { x^2}\, dx\\= [x^3/3]\ from\ 0\ to\ 6\\= 72[/tex]

To find the moment of inertia [tex]I_x[/tex], we can use the formula:

[tex]I_x = \int\ {y^2} \, dA[/tex]

where y is the perpendicular distance of an element of area [tex]dA[/tex] from the x-axis. We can express y in terms of x as y = x². Therefore, we have:

[tex]dA = y dx = x^2 dx\\I_x = \int\limits^6_0 { x^2 (x^2)} dx\\= \int\limits^6_0 {x^4}\, dx\\= [x^5/5]\ from\ 0\ to\ 6\\= 6^5/5[/tex]

Substituting these values into the formula for [tex]k_x[/tex], we get:

[tex]k_x = \sqrt{(I_x / A)}\\= \sqrt{((6^5/5) / 72)}\\= \sqrt{(6^3 / 5)}\\= 6 \sqrt{6} / 5[/tex]

Therefore, the radius of gyration of the plate about the x-axis is [tex]6 \sqrt{6}/ 5[/tex] units.

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The volume of the prism is 180 cm³.

A prism is a 3D (three-dimensional) solid which has faces that are identical at both ends. The other faces are flats. A prism is named after its base.

The volume of any prism can be calculated using the formula:

V = A[tex]_{B}[/tex] * h

where A[tex]_{B}[/tex] is area of base and h is height of prism

In this case, we have the following information about the prism:

A[tex]_{B}[/tex]  = 20 cm²

h = 9cm

V = 20 * 9

V = 180 cm³

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Complete Question

Check attached image

c = number of chickens

d = number of ducks

c = 4d because there are 4 times as many chickens as ducks

c = d+72 because there are 72 more chickens

4d = d+72 after using substitution

4d-d = 72

3d = 72

d = 72/3

d = 24

c = 4d = 4*24 = 96  ...or...  c = d+72 = 24+72 = 96

P(E1) + P(E2) - P(E1 ∩ E2) is the probability that at least one of the two events occurs in any trial of the experiment.

The correct answer is D. P(E1) + P(E2) - P(E1 ∩ E2).

The probability that at least one of two events occurs can be calculated using the principle of inclusion-exclusion.

The formula for this is:

P(E1 or E2) = P(E1) + P(E2) - P(E1 and E2)

Where:

P(E1) is the probability of event E1 occurring.

P(E2) is the probability of event E2 occurring.

P(E1 and E2) is the probability of both events E1 and E2 occurring simultaneously.

This formula represents the probability that at least one of the two events (E1 or E2) occurs in any trial of the experiment.

It's derived using the principle of inclusion-exclusion.

P(E1) represents the probability of event E1 occurring.

P(E2) represents the probability of event E2 occurring.

P(E1 ∩ E2) represents the probability of both events E1 and E2 occurring simultaneously.

By adding the probabilities of each individual event and then subtracting the probability of their intersection, you're accounting for the possibility of double-counting the intersection when adding the probabilities of the individual events.

So, the formula accurately captures the probability of at least one of the two events occurring.

Hence, P(E1) + P(E2) - P(E1 ∩ E2) is the probability that at least one of the two events occurs in any trial of the experiment.

The correct answer is D. P(E1) + P(E2) - P(E1 ∩ E2).

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complete question:

Two events, E1 and E2, are defined for a random experiment. What is the probability that at least one of the two events occurs in any trial of the experiment?

A.

P(E1) + P(E2) − 2P(E1 ∩ E2)

B.

P(E1) + P(E2) + P(E1 ∩ E2)

C.

P(E1) − P(E2) − P(E1 ∩ E2)

D.

P(E1) + P(E2) − P(E1 ∩ E2)

Answer: $193.42

Step-by-step explanation:

Based on the given designs, the cost to make the triangular and circular street signs would be $68.60 and $124.42 respectively, making the total cost of making both signs $193.02.

To calculate the cost of making the two street signs, we need to first find the area of each sign. The area of a triangle is given by the formula 1/2 x base x height. So, for the triangular street sign, the area would be 1/2 x 3 x 2.6 = 3.9 square feet.

The area of a circle is given by the formula π x radius². So, for the circular street sign, the area would be π x (1.5)² = 7.065 square feet.

Now that we have the areas of both signs, we can calculate the total cost of the material needed. The cost per square foot of material is $17.64, so we need to multiply this by the total area of the signs.

For the triangular sign, the cost would be 3.9 x $17.64 = $68.60.

For the circular sign, the cost would be 7.065 x $17.64 = $124.42.

Therefore, the total cost to make both signs would be $68.60 + $124.42 = $193.02.

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The graph of constant of proportionality of y = 3.75x is attached

The constant of proportionality is a term that indicates a reciprocal relationship between two variables, in which the change of one affects the other similarly.

When x and y are directly linked in this way, the following equation can be used to calculate how they operate together:

y = kx,

where

k serves as the aforementioned constant.

In the problem k = 3.75

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She is incorrect when she said that her rate increased each hour from 8 to 12 to 16 miles per hour. Her jogging rate was actually a steady 5 miles per hour.

You asked if Christy is correct when she said that her rate increased each hour, from 8 to 12 to 16 miles per hour. Let's analyze the data given in the table and see if she's right.

The table shows the distance Christy jogged and the corresponding time:
- 10 miles in 2 hours
- 15 miles in 3 hours
- 20 miles in 4 hours

To find her jogging rate for each time period, we need to divide the distance by the time.

1. For the first 2 hours:
Jogging rate = distance / time = 10 miles / 2 hours = 5 miles per hour

2. For the first 3 hours:
Jogging rate = distance / time = 15 miles / 3 hours = 5 miles per hour

3. For the first 4 hours:
Jogging rate = distance / time = 20 miles / 4 hours = 5 miles per hour

Christy's jogging rate remained constant at 5 miles per hour throughout her run. Therefore, she is incorrect when she said that her rate increased each hour from 8 to 12 to 16 miles per hour. Her jogging rate was actually a steady 5 miles per hour.

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The vertex is the highest or lowest point on the parabola, the line of symmetry is a vertical line passing through the vertex and dividing the parabola into two equal halves, and the number of x-intercepts depends on the discriminant of the quadratic equation.

The vertex is a point on a parabola where the curve changes direction. It is the highest or lowest point on the curve, depending on whether it opens up or down. The vertex is represented as (h, k), where h is the x-coordinate and k is the y-coordinate.

The line of symmetry is a vertical line that divides the parabola into two equal halves. It passes through the vertex and is equidistant from the two arms of the parabola. The equation of the line of symmetry is x = h.

The number of x-intercepts is determined by the equation of the parabola. If the discriminant of the quadratic equation is positive, then the parabola intersects the x-axis at two distinct points, and there are two x-intercepts. If the discriminant is zero, then the parabola touches the x-axis at one point, and there is one x-intercept. If the discriminant is negative, then the parabola does not intersect the x-axis, and there are no x-intercepts.

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Answer:

Step-by-step explanation:

1 - divide

2 - measur

3 - add

answer = 44.78

There are 5 combinations with one flavor, 10 combinations with two flavors, and 10 combinations with three flavors, resulting in 25 possible combinations in total.

a. Only one flavor is there.

b. Buko can be paired with 4 other flavors and Ube can be paired with 3 remaining flavors.

c. 10 combinations of three flavors.

a. There is only one flavor: Since the box contains only one flavor, there are 5 possible combinations (Buko, Ube, Pineapple, Yema, and Mango).

b. There are two flavors:
- Buko can be paired with 4 other flavors (Ube, Pineapple, Yema, Mango).
- Ube can be paired with 3 remaining flavors (Pineapple, Yema, Mango).
- Pineapple can be paired with 2 remaining flavors (Yema, Mango).
- Yema can be paired with 1 remaining flavor (Mango).
In total, there are 10 combinations of two flavors.

c. There are three flavors:
- There are 5 flavors in total, and we want to choose 3. We can use the formula for combinations: C(n, k) = n! / (k!(n-k)!), where n is the total number of flavors and k is the number of flavors to choose.
- C(5, 3) = 5! / (3!(5-3)!) = 10 combinations of three flavors.

So, there are 5 combinations with one flavor, 10 combinations with two flavors, and 10 combinations with three flavors, resulting in 25 possible combinations in total.

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It should be noted that with the equations 6 old printers would produce a batch of comic books in less time.

Using 2 new printers is 27 minutes faster than using 6 old printers.

6 old printers would produce 6*(1/150) = 2/75 of a batch per minute.

2 new printers would produce 2*(1/72) = 1/36 of a batch per minute.

(5/6) * t = 30

(4/2) * t' = 18

Solving for t and t', we get:

t = 36 minutes

t' = 9 minutes

Therefore, using 6 old printers would take 36 minutes to produce a batch of comic books, while using 2 new printers would take only 9 minutes. Using 2 new printers is 27 minutes faster than using 6 old printers.

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The mass of iron III sulfate is  300 g.

If 1 mole of iron III sulfate is produced when 3 moles of hydrogen is produced

x moles of iron III sulfate is produced when 2.25 moles of hydrogen is produced

x = 1 * 2.25/3

= 0.75 moles

Mass of the iron III sulfate = 0.75 moles * 400 g/mol

= 300 g

Number of moles of iron = 85 g/56 g/mol

= 1.5 moles

If 2 moles of iron produces 1 mole of   iron III sulfate

1.5 moles of iron produces 1.5 * 1/2

= 0.75 moles

Mass of the  iron III sulfate = 0.75 moles * 400 g/mol

= 300 g

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