Answer:
If the reaction is going from left to right it would be synthesis, if going right to left it would be decomposition.
Explanation:
Na2O (s) + 2CO2 (g) + H2O (g) = 2 NaHCO3 (s)
Left Side
Na = 2
O = 6
C = 2
H = 2
Right Side
Na = 2
O = 6
C = 2
H = 2
Ok so is balanced already, though initial equation in question had an error in regards to the left hand side the ) should have been an O.
Hmm
Na2O (s) + 2CO2 (g) + H2O (g) = 2 NaHCO3 (s)
If it was going from right to left would be decomposition
But going from left to right it would be synthesis
In a undisturbed layer, how do we know which layer was deposited first ?
Answer:
It's the bottom layer.
Explanation:
Scientists use the Law of Superposition to determine the relative age of a layer of sedimentary rock:
The oldest rock layer is at the bottom of an undisturbed bed.
Thus, Layer A in the figure below was deposited first.
Balance the combustion reaction between propane and oxygen.
C ₃ H ₈+ O ₂→ CO ₂ + H ₂ O
Answer:
The answer is C3H8 + 5O2 → 3CO2 + 4H2O .
Answer:
[tex]\huge \boxed{\mathrm{C_3 H_8 +5O_2 \Rightarrow 3CO_2 +4 H_2 O}}[/tex]
[tex]\rule[225]{225}{2}[/tex]
Explanation:
[tex]\sf C_3 H_8 +O_2 \Rightarrow CO_2 + H_2 O[/tex]
Balancing Carbon atoms on the right side,
[tex]\sf C_3 H_8 +O_2 \Rightarrow 3CO_2 + H_2 O[/tex]
Balancing Hydrogen atoms on the right side,
[tex]\sf C_3 H_8 +O_2 \Rightarrow 3CO_2 +4 H_2 O[/tex]
Balancing Oxygen atoms on the left side,
[tex]\sf C_3 H_8 +5O_2 \Rightarrow 3CO_2 +4 H_2 O[/tex]
[tex]\rule[225]{225}{2}[/tex]
Subtract to find the temperature changes
for the water and the metal.
AT (water) =
AT (metal) =
Answer:
Explanation:
The temperature changes for the water and the metal is
ΔT (water) = 4.7°C
ΔT (metal) = - 72.9°C
Specific HeatThe quantity or amount of heat per unit mass required to raise the temperature of a body by one degree Celsius is known as specific heat. The unit of specific heat are joules or calories per gram per degree Celsius. Specific heat is an intensive property.
Calculate the temperature changesRelationship between temperature and heat is expressed as:
Q = mcΔT
where,
Q is heat energy in Joules (J)
m is mass (in grams)
c is specific heat in J/g°C
ΔT is change in temperature
Now calculate the temperature changes for the water
ΔT (water) = T(final) - T(initial)
= 27.1 - 22.4
= 4.7°C
Now calculate the temperature changes for the metal
ΔT(metal) = T(final) - T(initial)
= 27.1 - 100
= -72.9°C
Thus, from the above calculation we can see that the temperature changes for the water and the metal is
ΔT (water) = 4.7°C
ΔT (metal) = - 72.9°C
Learn more about the specific heat here: https://brainly.com/question/21406849
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