Answer:
multiples of 12
Step-by-step explanation: when looking at the GCF, the answer is 12
Can anyone help me with the answer please
Answer:
Graph D
Step-by-step explanation:
First, look at the x-intercepts (where the graph touches the x-axis): x= -1 and x= 3
This rules out Graph B and C which have x-intercepts at x= -3 and x= -1
Next, look at the y-intercept (where the graph touches the y-axis): y= -3
This rules out Graph A which has a y-intercept at y= 3
The first term in the sequence 5, 7, −7, ... is 5. Each even-numbered term is 2 more than the previous term and each odd-numbered term, after the first, is (−1) times the previous term. For example, the second term is 5+2 and the third term is (−1)×7. What is the 255th term of the sequence?
Answer:
Step-by-step explanation:
According to the condition, your terms are arranged as
5, 7 , -7 ,-5, 5, 7, -7, 5, -5,...................
So one loop will have 4 terms: 5, 7, -7. -5
Hence after 63 loops, the new loop has only 3 terms. That means the last loop will be 5, 7 ,-7. In other words, the 255th term will be -7
Please help me. I’ll mark you as brainliest if correct
Answer:
b = -18
Step-by-step explanation:
(3 + 4i) (-3-2i)
When we foil:
-9 + -6i + -12i + -8i^2
-8i^2 = +8
Combine like terms:
-1 + -18i
Which of the following statements is NOT true?
YA
The slope of AB is
different than the
slope of BC.
The ratios of the rise to
the run for the triangles
are equivalent.
B
2.
х
-2
AB has the same slope
as AC.
The slope of Ac is
Answer:
The slope of AB is
different than the
slope of BC.
Step-by-step explanation:
A train is traveling at a constant speed and has traveled 67.5 miles in the last 11 hours.
Which equation shows the proportional relationship between the distance, d, and the time, t,
that the train has traveled?
A.d=45t
B.d=50t
C.d = 690
D.d=67.5t
Answer:
A. d= 45t
Step-by-step explanation:
(assuming that you meant 67.5 in the last 1.5 hours)
67.5 miles = distance
1.5 hours = time
therefore:
[tex]\frac{d}{t\\}[/tex] = 67.5/1.5
making your answer 45
leaving a as your correct answer:
d= 45t
The proportion relationship between the distance d, and the time t, that the train has travelled is, d = 45t. So the correct option is A).
What is a proportion relationship?Proportional relationships are relationships between two variables where their ratios are equivalent. Another way to think about them is that, in a proportional relationship, one variable is always a constant value times the other.
Given that, A train travels at a constant speed and has travelled 67.5 miles in the last 1.5 hours. (assuming that you meant 67.5 in the last 1.5 hours)
67.5 miles = distance
1.5 hours = time
We know that, speed = distance / time
s = 67.5/1.5
s = 45 mph
Now, distance = speed × time
d = 45t
Hence, the proportion relationship between the distance d, and the time t, that the train has travelled is, d = 45t. So the correct option is A).
For more references on proportion relationship, click;
https://brainly.com/question/29765554
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Graph the equation below by plotting the
y-intercept and a second point on the
line.
Answer:
Step-by-step explanation:
On the y-axis, graph the point on (0,4). Then from there, go up one, and to the right 4.
Show the frequency distribution for the Gross Profit Margin using the five intervals below:, , , , and Gross Profit MarginFrequencyA. B. C. D. Choose the correct histogram from the above diagrams.e. What is the average price/earnings ratio (to 1 decimal)
Answer:
Step-by-step explanation:
a) Number of variables in the data set : 5
b) A quantitative variable is the one which can be quantitatively measured. i.e. it is a numerical value.
A categorical variable is the one that can take one value from a limited number of fixed values.
Exchange is a Categorical Variable. Price/Earnings Ratio is a Quantitative Variable. Gross Profit Margin (%) is a Quantitative Variable.
c. Out of the 25 stocks, AMEX is the exchange for 5 stocks. So percent frequency is 5/25 = 0.2 = 20%.
NYSE is the exchange for 3 stocks. So percent frequency is 3/25 = 0.12 = 12%.
OTC is the exchange for 17 stocks. So percent frequency is 17/25 = 0.68 = 68%.
These percentages are correctly shown in graph a. So the answer is a.
d) The frequency distribution is
Gross Profit Margin Frequency
0-14.9 2
15-29.9 6
30-44.9 8
45.59.9 6
60.74.9 3
As we come across the Gross Profit Margin values in the table, we add a | next to its respective interval and build the above table. E.g. the first value in the table under Gross Profit Margin is 36.7 which lies in the interval 30–44.9. So we add one | in fromt of that interval and so on until we cover the entire table. The number of | shows the frequency distribution of the values.
The correct histogram is A.
e. The average price/earnings ratio is found by adding all the 25 values in the table and dividing the answer by 25.
= 505.40/25
= 20.2To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the three treatments. You are given the results below. Treatment Observation A 20 30 25 33 B 22 26 20 28 C 40 30 28 22 The test statistic to test the null hypothesis equals _____.
Answer:
The test statistic to test the null hypothesis equals 1.059
Step-by-step explanation:
From the given information; we have:
Treatment Observations
A 20 30 25 33
B 22 26 20 28
C 40 30 28 22
The objective is to find the test statistic to test the null hypothesis; in order to do that;we must first run through a series of some activities.
Let first compute the sum of the square;
Total sum of squares (TSS) = Treatment sum of squares [tex](T_r SS)[/tex] + Error sum of squares (ESS)
where:
(TSS) = [tex]\sum \limits ^v_{i=1} \sum \limits ^{n_i}_{j-1}(yij- \overline {y}oo)^2[/tex] with (n-1) df
[tex](T_r SS)[/tex] [tex]= \sum \limits ^v_{i=1} n_i( \overline yio- \overline {y}oo)^2[/tex] with (v-1) df
[tex](ESS) = \sum \limits ^v_{i=1} \sum \limits ^{n_i}_{j-1}(yij- \overline {y}io)^2[/tex] with (n-v) df
where;
v= 3
[tex]n_i=[/tex]4
i = 1,2,3
n =12
[tex]y_{ij}[/tex] is the [tex]j^{th[/tex] observation for the [tex]i^{th[/tex] treatment
[tex]\overline{y}io[/tex] is the mean of the [tex]i^{th[/tex] treatment i = 1,2,3 ; j = 1,2,3,4
[tex]\overline y oo[/tex] is the overall mean
From the given data
[tex]\overline y oo = \dfrac{1}{12} \sum \limits ^3_{i=1} \sum \limits ^{4}_{j=1}(yij)^2= 27[/tex]
[tex]TSS = \dfrac{1}{12} \sum \limits ^3_{i=1} \sum \limits ^{4}_{j=1}(yij- 27)^2 = 378[/tex]
[tex]T_r SS= \sum \limits^3_{i=1}4 (\overline y io - \overline yoo)^2[/tex]
[tex]=4(27-27)^2+4(24-27)^2+4(30-27)^2 = 72[/tex]
Total sum of squares (TSS) = Treatment sum of squares [tex](T_r SS)[/tex] + Error sum of squares (ESS)
(TSS) = 378 - 72
(TSS) = 306
Now; to the mean square between treatments (MSTR); we use the formula:
MSTR = TrSS/df(TrSS)
MSTR = 72/(3 - 1)
MSTR = 72/2
MSTR = 36
The mean square within treatments (MSE) is:
MSE = ESS/df(ESS)
MSE = 306/(12-3)
MSE = 306/(9)
MSE = 34
The test statistic to test the null hypothesis is :
[tex]T = \dfrac{ \dfrac{TrSS}{\sigma^2}/(v-1) }{ \dfrac{ESS}{\sigma^2}/(n-v) } = \dfrac{MSTR}{MSE} \ \ \ \approx \ \ T(\overline {v-1}, \overline {n-v})[/tex]
[tex]T = \dfrac{36}{34}[/tex]
T = 1.059
If f(x) = 4–1 and g(x) = 8x, which expression is equivalent to (g-1)(3)?
O 8-3-(4 + 3)
08-3-(4-32
813)-4432
O 6(3) 4-32
Answer:
Option (3)
Step-by-step explanation:
Given functions are f(x) = 4 - x² and g(x) = 6x
We gave to find the expression for (g - f)(3).
(g - f)(x) = g(x) - f(x)
= 6x - (4 - x²)
= 6x - 4 + x²
By substituting x = 3 in this expression,
(g - f)(x) = 6(3) - 4 + (3)²
Therefore, option (3) will be the answer.
Each square in the grid is a 1 x 1 unit square. What is the area of the shape
Answer:
So since the formula for a square is w*h
That means that the area is 1*1 or 1 unit^2
I knew it was a joke question.
:))))
Step-by-step explanation:
A gum ball machine has 22 red 18 white 10 blue and 23 green. What chances of pulling out a red
Step-by-step explanation:
Total gum balls = 22 + 18 + 10 + 23 = 73
Probability of red gum = 22/73
What is the approximate value for the modal daily sales?
Answer:
Step-by-step explanation:
Hello!
The table shows the daily sales (in $1000) of shopping mall for some randomly selected days
Sales 1.1-1.5 1.6-2.0 2.1-2.5 2.6-3.0 3.1-3.5 3.6-4.0 4.1-4.5
Days 18 27 31 40 56 55 23
Use it to answer questions 13 and 14.
13. What is the approximate value for the modal daily sales?
To determine the Mode of a data set arranged in a frequency table you have to identify the modal interval first, this is, the class interval in which the Mode is included. Remember, the Mode is the value with most observed frequency, so logically, the modal interval will be the one that has more absolute frequency. (in this example it will be the sales values that were observed for most days)
The modal interval is [3.1-3.5]
Now using the following formula you can calculate the Mode:
[tex]Md= Li + c[\frac{(f_{max}-f_{prev})}{(f_{max}-f_{prev})(f_{max}-f_{post})} ][/tex]
Li= Lower limit of the modal interval.
c= amplitude of modal interval.
fmax: absolute frequency of modal interval.
fprev: absolute frequency of the previous interval to the modal interval.
fpost: absolute frequency of the posterior interval to the modal interval.
[tex]Md= 3,100 + 400[\frac{(56-40)}{(56-40)+(56-55)} ]= 3,476.47[/tex]
A. $3,129.41 B. $2,629.41 C. $3,079.41 D. $3,123.53
Of all options the closest one to the estimated mode is A.
14. The approximate median daily sales is …
To calculate the median you have to identify its position first:
For even samples: PosMe= n/2= 250/2= 125
Now, by looking at the cumulative absolute frequencies of the intervals you identify which one contains the observation 125.
F(1)= 18
F(2)= 18+27= 45
F(3)= 45 + 31= 76
F(4)= 76 + 40= 116
F(5)= 116 + 56= 172 ⇒ The 125th observation is in the fifth interval [3.1-3.5]
[tex]Me= Li + c[\frac{PosMe-F_{i-1}}{f_i} ][/tex]
Li: Lower limit of the median interval.
c: Amplitude of the interval
PosMe: position of the median
F(i-1)= accumulated absolute frequency until the previous interval
fi= simple absolute frequency of the median interval.
[tex]Me= 3,100+400[\frac{125-116}{56} ]= 3164.29[/tex]
A. $3,130.36 B. $2,680.36 C. $3,180.36 D. $2,664
Of all options the closest one to the estimated mode is C.
A random sample of 1141 men and 1212 women aged 25-64 y (response rate 76%) completed a questionnaire and underwent a short examination in a clinic. Intake of beer, wine and spirits during a typical week, frequency of drinking, and a number of other factors were measured by a questionnaire. The present analyses are based on 891 men and 1098 women who were either nondrinkers or 'exclusive' beer drinkers (they did not drink any wine or spirits in a typical week). 500 men are beer drinkers and 325 men from this group have the obesity. 80 non-drinkers men are obese.
Required:
a. What type of study desing?
b. Which parameters can be calculated?
c. Determine it and explain the results.
Answer:
(a) A cross sectional study (b) The parameter can be computed as follows: Non-drinkers who agree exposed to obesity, Drinkers who are exposed or vulnerable to obesity (c) A postie relationship is established from the experiment between drinkers who are exposed to obesity and non drinkers who are exposed to obesity
Step-by-step explanation:
(a) The type of design is refereed to as a cross sectional study
(b) Now, because 50 men are beer drinkers out of 891 men.
Hence we can deduce form this that 500/891 gives us 0.56%.
This suggest that 0.56% men are beer drinkers out of which 325 have obesity, lets take for example 235/500 = 0.65% are exposed to obesity in which 80/ (89-500) = 80/491 = 0.16%
The non drinkers are 0.16% and are not exposed to obesity
Thus,
The parameters to be calculated is stated below:
Non-drinkers who agree exposed to obesityDrinkers who are exposed or vulnerable to obesity(c) The next step is to determine and explain the results.
In this case we can say there is a positive relationship between drinkers and non drinkers, since from the experiment 0.65% are exposed to obesity and 0.16$ non drinkers are exposed to obesity.
4. In the Department of Natural Sciences, 14 faculty members have a PhD, and 30 faculty
members do not have a PhD. In the Department, the number of female faculty who do not
have a PhD is 10 more than the number of females who have a PhD. If a third of the male
faculty in the Department have a PhD, then what is the number of female faculty in the
Answer:
8
Step-by-step explanation:
We can start by making the table below to show the given numbers (red) and to assign a variable (x) to the number we want to find: female PhDs.
By subtracting the female numbers from the totals, we can find the corresponding numbers of male PhDs and non-PhDs.
The number of male non-PhDs is twice the number of male PhDs, so we have ...
2(14 -x) = 20 -x
28 -2x = 20 -x . . . . eliminate parentheses
8 = x . . . . . . . . . . . .add 2x-20
The number of female faculty with PhDs is 8.
find the mean of the following numbers 7,21,2,17,3,13,7,4,9
Answer:
9.222222222
Step-by-step explanation:
7+21+2+17+3+13+7+4+9 = 83
7+21+2+17+3+13+7+4+9 = 83 83÷9 = 9.222222222
_____________________________
Hey!!
Solution,
Given data=7,21,2,17,3,13,7,4,9
summation FX= 83
N(total no. of items)=9
Now,
Mean=summation FX/N
= 83/9
=9.23
So the answer is 9.23
__________________________
which is the equation of a circle with center (-3, -5) and radius of 4
Answer: -8
Step-by-step explanation:
In a certain city district the need for money to buy drugs is stated as the reason for 70% of all thefts. Find the probability that among the next 7 theft cases reported in this district, exactly 3 of them resulted from the need to buy drugs.
Answer:
9.72% probability that among the next 7 theft cases reported in this district, exactly 3 of them resulted from the need to buy drugs.
Step-by-step explanation:
For each theft, there are only two possible outcomes. Either the need to buy drugs is the reason of the theft, or it is not. Each theft is independent of each other. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
In a certain city district the need for money to buy drugs is stated as the reason for 70% of all thefts.
This means that [tex]p = 0.7[/tex]
Find the probability that among the next 7 theft cases reported in this district, exactly 3 of them resulted from the need to buy drugs.
This is P(X = 3) when n = 7. So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 3) = C_{7,3}.(0.7)^{3}.(0.3)^{4} = 0.0972[/tex]
9.72% probability that among the next 7 theft cases reported in this district, exactly 3 of them resulted from the need to buy drugs.
Triangle ABC is a right triangle whose right angle is ZABC.
Find the measure of ZEBF.
ZABC and DBF are vertical angles, so they have the same
measure. Because IZABC is 90°, the sum of m2. DBE and
m2 EBF must also be 90°
Solve for x in this equation.
x + (x - 12) = 90
2x - 12 = 90
2x = 102
X51
m2 EBF = 51°
1.What is m
2.What is m
3.Explain how to find m
Answer: m is 13
m is 6
you find m by calculating!
Step-by-step explanation:
Leroy is 22 years old. His car averages 31 miles
per gallon. His car payments are $165.32 per
month, and he has 36 more payments to
make. How old will he be when he pays off his
car?
Answer:
he will be 25
Step-by-step explanation:
36 monthly payments left/12 payments a year = 3 years. 22 + 3 = 25
It is believed that approximately 12% of the population of the United States is lefthanded. Suppose researchers suspect that the proportion of left-handed people is higher in certain states than the national average. The researchers conduct a sample of 200 randomly selected people in the state of Maine and find that 29 people in the sample are left-handed.
a. Write the null hypothesis and alternative hypothesis and define your parameter.
b. Show that the necessary conditions (Randomization Condition, 10% Condition, Sample Size Condition) are satisfied to perform a hypothesis test. Briefly explain how each condition is satisfied.
c. Perform the hypothesis test and find the P-value. (To show your work: Write down what values you are entering into the hypothesis testing calculator.)
d. Is there strong evidence that the left-handed rate in the state of Maine is higher than the national average? Briefly explain how you know.
Answer:
Step-by-step explanation:
a. Null hypothesis: P = p
Alternatives hypothesis: P =/ p
Where P is the hypothesized population proportion and p is the sample proportion
b. Performing a test of proportions
Randomization: the sample was randomly selected in the study
The population size is at least 20 times as big as the sample size.
The sample includes both successes and failures with 29 success and 171 failures.
c. To perform the hypothesis test: we have to find the standard deviation first
Sd = sqrt[ P * ( 1 - P ) / n ]
where P is the hypothesized value of population proportion, n is the sample size.
Sd = √[0.12*(1-0.12)/200]
Sd = √[0.12*(0.88/200]
Sd = √[0.12*(0.0044)]
Sd = √0.000528
Sd = 0.023
Then we can find the z score
z = (p - P) / σ where p = 29/200 = 0.145
z = (0.145-0.12)/ 0.023
z = 0.025/0.023
z = 1.09
Calculation the p value using 0.05 level of significance and a two waited test (p value calculator),
A p-value of 0.2757 which is greater than 0.05, thus we will fail to reject the null stating that there is not enough strong evidence that the left-handed rate in the state of Maine is higher than the national average.
The point A (-7,5) is reflected over the line x = -5, and then is reflected over the line x= 2. What are the coordinates of
A?
o (7, 19)
O (10,5)
(7,5)
(10, 19)
Answer:
(7, 5) is the final reflection of the point.
Step-by-step explanation:
We are given point A(-7, 5) which is first reflected over the line [tex]x= -5[/tex].
The minimum distance of the point A(-7, 5) from the line [tex]x= -5[/tex] is 2 units across the horizontal path (No change in y coordinate).
Point A lies 2 units on the left side of the line [tex]x= -5[/tex].
So, its reflection will be 2 units on the right side of [tex]x= -5[/tex].
Let its reflection be A' which has coordinates as (-5+2,5) i.e. (-3, 5).
Now A'(-3, 5) is reflected on the line [tex]x=2[/tex].
The minimum distance of the point A'(-3, 5) from the line [tex]x=2[/tex] is 5 units across the horizontal path (No change in y coordinate).
Point A' lies 5 units on the left side of the line [tex]x=2[/tex].
So, its reflection will be 5 units on the right side of [tex]x=2[/tex].
Let its reflection be A'' which has coordinates as (2+5, 5) i.e (7, 5) is the final reflection of the point..
Please find attached image.
(7, 5) is the final reflection of the point.
Los Angeles workers have an average commute of 33 minutes. Suppose the LA commute time is normally distributed with a standard deviation of 15 minutes. Let X represent the commute time for a randomly selected LA worker. Round all answers to 4 decimal places where possible.
a. What is the distribution of X? X N
b. Find the probability that a randomly selected LA worker has a commute that is longer than 38 minutes
c. Find the 80th percentile for the commute time of LA workers. _______ minutes
Answer:
a) N(33,15).
b) 37.33% probability that a randomly selected LA worker has a commute that is longer than 38 minutes
c) 45.6 minutes.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 33, \sigma = 15[/tex]
a. What is the distribution of X?
Normal with mean 33 and standard deviaton 15. So
N(33,15).
b. Find the probability that a randomly selected LA worker has a commute that is longer than 38 minutes
This is 1 subtracted by the pvalue of Z when X = 38. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{38 - 33}{15}[/tex]
[tex]Z = 0.333[/tex]
[tex]Z = 0.333[/tex] has a pvalue of 0.6267.
1 - 0.6267 = 0.3733
37.33% probability that a randomly selected LA worker has a commute that is longer than 38 minutes
c. Find the 80th percentile for the commute time of LA workers.
This is X when Z has a pvalue of 0.8. So it is X when Z = 0.84.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]0.84 = \frac{X - 33}{15}[/tex]
[tex]X - 33 = 0.84*15[/tex]
[tex]X = 45.6[/tex]
45.6 minutes.
Given AB intersects DE at point C. prove: DCB = ECA. What is the missing reason in step 5
Answer: the answer is linear pair
Step-by-step explanation:
Answer:
Linear pair postulate
Step-by-step explanation:
What is the inverse of the given function f(x)=1/4x -12?
Answer:
[tex]f^{-1}(x)=4x+48[/tex]
Step-by-step explanation:
To find the inverse, solve for y:
x = f(y)
x = (1/4)y -12
x +12 = (1/4)y . . . . add 12
4(x +12) = y . . . . . multiply by 4
y = 4x +48 . . . . . . simplify
The inverse function is ...
[tex]\boxed{f^{-1}(x)=4x+48}[/tex]
3km 5hm multiplied by 15 equals what
Answer: 525
Step-by-step explanation:
3 km =30 hm
35hm*15=525
What degree of rotation about the origin will cause the triangle below to map
onto itself?
A. 90 degrees
B. 360 degrees
C. 180 degrees
D. 270 degrees
Answer: 360ᴼ
Step-by-step explanation:
If a figure goes 360ᴼ around the graph, it will be mapped onto itself.
360ᴼ is full circle (number of degrees in a circle), so the figure just went around in a circle, back into the same location before it rotated.
Answer:
360
Step-by-step explanation:
i took the text
Suppose a company's revenue function is given by R(q) = - q^3 + 220q^2 and its cost function is given by C(q) = 500 + 13q, where q is hundreds of units sold/produced, while R(q) and C(q) are in total dollars of revenue and cost, respectively.
A) Find a simplified expression for the marginal profit function. (Be sure to use the proper variable in your answer.)
MP(q) =
B) How many items (in hundreds) need to be sold to maximize profits? (Round your answer to two decimal places.)
Answer:
A) MP(q) = -3q² + 440q - 13
B) 146.64 units.
Step-by-step explanation:
The profit function is given by the revenue minus the cost function:
[tex]P(q) = R(q) - C(q)\\P(q) = -q^3+220q^2-500-13q[/tex]
A) The Marginal profit function is the derivate of the profit function as a function of the quantity sold:
[tex]P(q) = -q^3+220q^2-500-13q\\MP(q) = \frac{dP(q)}{dq} \\MP(q)=-3q^2+440q-13[/tex]
B) The value of "q" for which the marginal profit function is zero is the number of items (in hundreds) that maximizes profit:
[tex]MP(q)=0=-3q^2+440q-13\\q=\frac{-440\pm \sqrt{440^2-(4*(-3)*(-13))} }{-6}\\q'=146.64\\q'' = - 0.03[/tex]
Therefore, the only reasonable answer is that 146.64 hundred units must be sold in order to maximize profit.
An oval shaped walking path at a local park is 3/4 of a mile long. Four walkers recorded the number of laps they walked and the time it took them in them.
laps Minutes
Amber. 3. 40. Bruno. 4. 54. Cady. 5. 75. Drake. 6. 72.
Match each walker to their corresponding unit rate in miles per hour................................................. 3 3/4 mph, 3 mph, 3 1/2mph, 3 1/4 mph, 3 3/8 mph and 3 2/3mph
Answer:
Amber = 3 3/8 mphBruno = 3 1/3 mphCady =3 mphDrake = 3 3/4 mphStep-by-step explanation:
Consider the calculations in the table below with the respective columns being: Name | Laps | Time | Time(in hours) |Total Distance | Unit Rate
[tex]\left|\begin{array}{c|c|c|c|c|c}---&---&---&----&----&---\\Amber&3&40&\frac{40}{60}&3*\frac{3}{4}=2.25&2.25 \div \frac{40}{60}= 3\frac{3}{8} \\\\Bruno&4&54&\frac{54}{60}&4*\frac{3}{4}=3&3 \div \frac{54}{60}= 3\frac{1}{3}\\\\Cady&5&75&\frac{75}{60}&5*\frac{3}{4}=3.75&3.75 \div \frac{75}{60}= 3 \\\\Drake&6&72&\frac{72}{60}&6*\frac{3}{4}=4.5&4.5 \div \frac{72}{60}= 3\frac{3}{4} \end{array}\right|[/tex]
We can then match each walker to their respective unit rates in miles per hour.
Amber = 3 3/8 mphBruno = 3 1/3 mphCady =3 mphDrake = 3 3/4 mphSolve.
3^x+1 = 9^ 5x
a. x=3
b. x = 1/3
c. x=9
d. x= 1/9
Answer:
x = 1/9
Step-by-step explanation:
3^ (x+1) = 9 ^ (5x)
Replace 9 with 3^2
3^ (x+1) = 3^2 ^ (5x)
We know that a^b^c = a ^(b*c)
3^ (x+1) = 3^(2 * (5x))
3^ (x+1) = 3^(10x)
The bases are the same so the exponents are the same
x+1 = 10x
Subtract x from each side
x+1-x = 10x-x
1 = 9x
Divide each side by 9
1/9 = 9x/9
1/9 =x
1. What is the approximate area of a circle with a diameter of 20 inches?
2. What is the volume of a cube with a side length of 3 cm?
3. What is the median of the data set { 35,20, 30,25,20 }?
Answer:
1. 100[tex]\pi[/tex]
2. 27 [tex]cm^{3}[/tex]
3. 30
Step-by-step explanation:
Area = [tex]\pi[/tex][tex]r^{2}[/tex]
= [tex]\pi[/tex] x [tex]10x^{2}[/tex]
= 100[tex]\pi[/tex]
Volume = l x w x h
= 3 x 3 x 3
= 27
