Which type of reaction is described by the following equation Na2O (s) + 2CO2 (g) + H2) (g) Produces 2 NaHCO3 (s)
Answer:
If the reaction is going from left to right it would be synthesis, if going right to left it would be decomposition.
Explanation:
Na2O (s) + 2CO2 (g) + H2O (g) = 2 NaHCO3 (s)
Left Side
Na = 2
O = 6
C = 2
H = 2
Right Side
Na = 2
O = 6
C = 2
H = 2
Ok so is balanced already, though initial equation in question had an error in regards to the left hand side the ) should have been an O.
Hmm
Na2O (s) + 2CO2 (g) + H2O (g) = 2 NaHCO3 (s)
If it was going from right to left would be decomposition
But going from left to right it would be synthesis
Carbon-14 is a common isotope of the element. How many electrons
does it contain?
O 14
O 12
O 8
O 6
Choose the correct coefficients to balance the following equation: __CaCO3 + __HC; Produces __CaCl2 + __CO2 + __H2O
Answer:
CaCO3 + 2HCl = CaCl2 + CO2 + H2O
Explanation:
CaCO3 + HCl = CaCl2 + CO2 + H2O
Error in equation should be HCl on left hand side not HC
Left Side
Ca = 1
C = 1
O = 3
H = 1
Cl = 1
Right Side
Ca = 1
C = 1
O = 3
H = 2
Cl = 2
So we'll try and balance the Chlorine
CaCO3 + 2HCl = CaCl2 + CO2 + H2O
Left Side
Ca = 1
C = 1
O = 3
H = 2
Cl = 2
Right Side
Ca = 1
C = 1
O = 3
H = 2
Cl = 2
Yay it worked
An ice freezer behind a restaurant has a freon leak, releasing 41.60 g of C2H2F3Cl into the air every week. If the leak is not fixed, how many kilograms of fluorine will be released into the air over 6 months? Assume there are 4 weeks in a month. mass of fluorine leaked over 6 months:
What is the potential energy of the bowling ball as it sits on top of a building?
Answer:
Potential energy is the amount of energy calculated from an object's height off the ground.
Explanation:
Potential energy = Mass x Height x Gravity
Please help me out on this question!!
Answer:
Water H2O
Explanation:
A solvent is defined as being able to dissolve other substances, the fertilizer is being dissolved in the water prior to watering the plants, therefore the water is the solvent in this case.
At what temperature does the solid start meltin
-20°C
0°C
20"
80°C
Answer:
0 C.
Explanation:
I know the correct answer is either a or d. Can anyone explain which one it is and why? CH3C ≡ CCH2CH2Cl is named: a. 1-chloro-3-pentyne b. 5-chloro-2-pentene c. 1-acetylenyl-3-chloropropane d. 5-chloro-2-pentyne
Answer:
D.
Explanation:
CH₃C≡ CCH₂CH₂Cl
Since there are 5 carbons so the suffix used is "pent"
There is a triple bond so its alkyne
So the compound becomes 2-pentyne (2 because the triple bond is with the 2nd carbon)
Then,
The functional group of chlorine is attached with 5th carbon So the compound becomes
5-chloro,2-pentyne
When balanced, which equation would have the coefficient 3 in front of any of the reactants? Zn + HCl ZnCl2 + H2 H2SO4 + B(OH)3 B2(SO4)3 + H2O Fe + AgNO3 Fe(NO3)2 + Ag C2H4O2 + O2 CO2 +H2O
Answer:
b
Explanation:
i got it right on edge
To balance a reaction means to make the number of atoms the same on both the reactants and products side. The steps for balancing is as follows:-
Balance the Metal firstThen balance the HydrogenBalance the oxygen at lastAccording to the question, there are third reactions. the reaction third has the 3 coefficient before the compound.
The balanced reaction is as follows:-
[tex]3H_2So_4 + 2B (OH)_3------->B_2(So_4)_3 + 6H_2O[/tex]
Hence the correct compound is[tex]3H_2SO_4[/tex].
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What is the Log(10^-4)
Answer:
-4
Explanation:
[tex]log 10^{-4} = -4 log 10[/tex]
log 10 = 1
Therefore -4 log 10 = -4 x 1 = -4
mixture of 75 cm3of oxygen and 12.5 cm3 of a gaseous hydrocarbon H were exploded in an eudiometer. After cooling to room temperature, 50 cm3 of gas was left and when this was shaken with KOH solution, 12.5 cm3 of oxygen remained. Given that all the volumes were measured at same temperature and pressure, calculate the molar mass of the hydrocarbon H.
Answer:
molar mass of C₃H ₈ = 44 g/mole
Explanation:
Computation of the amount of oxygen that reacts .
⇒ 75 - 12.5
⇒ 62.5 cm³
Computation of proportion of hydrocarbons
2 mole hydrocarbons 3n+1 oxygen
⇒ 3 n + 1 = [62.5 × 2] / 12.5
⇒ 3 n + 1 = 10
⇒ n = 3
So,
Formula of the hydrocarbon is C₃H ₈
Computation of molar mass of C₃H ₈
⇒ [12×3] + [1×8]
⇒ 44 g/mole
What happens to the motion of the atoms in a spoon after is placed in hot soup?
Answer:
they move faster
Explanation:
Answer:
They move faster.
Help!
A student dissolves 1 gram of sugar in 10 grams of water. She then determines the mass of the solution. What is the mass of the dissolved sugar and water?
a. less than 11 grams
b. more than 11 grams
c. 11 grams
d. It is not possible to tell from the data
Answer:
11 grams
Explanation:
how many moles of hydrogen will react with 40g oxygen
Answer: 2.5 moles
2H2 + O2 = 2H2O
This implies that 2 moles of oxygen is needed to react with one mole of oxygen to form 2 moles of water
It also implies that
2 moles of hydrogen requires 32 grams of oxygen
? moles of hydrogen would require 40 g of oxygen
2 x 40/32 = 2.5 moles
Explain the difference between layers and band.
Answer:
Foliation is developed by stress and fire while layering is developed by the embedding of fine and coarse deposits. Foliation is caused due to an alteration of minerals from pressure and heat while layering is developed by seasonal changes
Explanation:
Banding occurs when two different mineral compositions alternate in thin layers (typically 1 mm to 1 cm). The two types of layers typically contain the same minerals, but in different proportions, giving the rock a striped appearance. A foliation is defined by its banding.
What is foliation rocks?There are two major types of metamorphic rock textures: foliated and nonfoliated. Foliation in rock is caused by the parallel alignment of Platy minerals (such as Muscovite, Biotite, and Chlorite), Needle-like minerals (such as Hornblende), or Tabular minerals (e.g., feldspars). Because of the parallel alignment, the granite easily splits into thin sheets or layers. Foliation can be found in both aphanitic and phaneritic metamorphic rocks. A few foliated rocks also have bands.A banded rock has alternating thin layers of two different mineral compositions, with thicknesses ranging from 1 mm to 1 cm. The same minerals are found in both types of strata, but in varying amounts, giving the rock a striped appearance. A foliation is defined by its banding.To learn more about foliation, refer to:
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The following half-reaction can be balanced in acidic solution:
N2O5 --> NH4+
How many electrons appear in the balanced equation?
A. 13e-
B. 14e-
C. 16e-
D. 18e-
Answer:
None of them, answer seems to be 24 unless I messed up
Explanation:
How many electrons appear in the balanced equation
What the heck do they mean, do they mean transferred?
N2O5 --> NH4+
Left Side
N 5+ Electrons 2 in central shell, 5 in outer
O 2- Electrons 2 in central shell, 6 in outer
Right Side
H 1+ Electrons 1 in central shell
N 3- Electrons 2 in central shell, 5 in outer
Hmm, ok so need to balance the half equation first, this is a redox reaction.
Hmm, so it's going to be something like
H2 + N2O5 → NH + O3
Step 1. Write down the unbalanced equation ('skeleton equation') of the chemical reaction. All reactants and products must be known. For a better result write the reaction in ionic form.
H2 + N2O5 → NH + O3
Step 2. Separate the process into half reactions. A redox reaction is nothing but both oxidation and reduction reactions taking place simultaneously.
a) Assign oxidation numbers for each atom in the equation. Oxidation number (also called oxidation state) is a measure of the degree of oxidation of an atom in a substance (see: Rules for assigning oxidation numbers).
H02 + N+52O-25 → N-1H+1 + O03
b) Identify and write out all redox couples in reaction. Identify which reactants are being oxidized (the oxidation number increases when it reacts) and which are being reduced (the oxidation number goes down). Write down the transfer of electrons. Carefully, insert coefficients, if necessary, to make the numbers of oxidized and reduced atoms equal on the two sides of each redox couples.
When one member of the redox couple is oxygen with an oxidation state of -2 or hydrogen with an oxidation state of +1, it is best to replace it with a water molecule.
O:3H+12O-2 → O03 + 6e-(O)
H02 → H+12O-2 + 2e-(H)
R:N+52O-25 + 12e- → 2N-1H+1(N)
c) Combine these redox couples into two half-reactions: one for the oxidation, and one for the reduction (see: Divide the redox reaction into two half-reactions).
O:3H+12O-2 + H02 → O03 + H+12O-2 + 8e-
R:N+52O-25 + 12e- → 2N-1H+1
Step 3. Balance the atoms in each half reaction. A chemical equation must have the same number of atoms of each element on both sides of the equation. Add appropriate coefficients (stoichiometric coefficients) in front of the chemical formulas to balance the number of atoms. Never change any formulas.
a) Balance all other atoms except hydrogen and oxygen. We can use any of the species that appear in the skeleton equations for this purpose. Keep in mind that reactants should be added only to the left side of the equation and products to the right.
O:3H+12O-2 + H02 → O03 + H+12O-2 + 8e-
R:N+52O-25 + 12e- → 2N-1H+1
b) Balance the charge. For reactions in an acidic solution, balance the charge so that both sides have the same total charge by adding a H+ ion to the side deficient in positive charge.
O:3H+12O-2 + H02 → O03 + H+12O-2 + 8e- + 8H+
R:N+52O-25 + 12e- + 12H+ → 2N-1H+1
c) Balance the oxygen atoms. Check if there are the same numbers of oxygen atoms on the left and right side, if they aren't equilibrate these atoms by adding water molecules.
O:3H+12O-2 + H02 + H2O → O03 + H+12O-2 + 8e- + 8H+
R:N+52O-25 + 12e- + 12H+ → 2N-1H+1 + 5H2O
Balanced half-reactions are well tabulated in handbooks and on the web in a 'Tables of standard electrode potentials'. These tables, by convention, contain the half-cell potentials for reduction. To make the oxidation reaction, simply reverse the reduction reaction and change the sign on the E1/2 value.
Step 4. Make electron gain equivalent to electron lost. The electrons lost in the oxidation half-reaction must be equal the electrons gained in the reduction half-reaction. To make the two equal, multiply the coefficients of all species by integers producing the lowest common multiple between the half-reactions.
O:3H+12O-2 + H02 + H2O → O03 + H+12O-2 + 8e- + 8H+| *3
R:N+52O-25 + 12e- + 12H+ → 2N-1H+1 + 5H2O| *2
O:9H+12O-2 + 3H02 + 3H2O → 3O03 + 3H+12O-2 + 24e- + 24H+
R:2N+52O-25 + 24e- + 24H+ → 4N-1H+1 + 10H2O
Step 5. Add the half-reactions together. The two half-reactions can be combined just like two algebraic equations, with the arrow serving as the equals sign. Recombine the two half-reactions by adding all the reactants together on one side and all of the products together on the other side.
9H+12O-2 + 2N+52O-25 + 3H02 + 24e- + 3H2O + 24H+ → 3O03 + 4N-1H+1 + 13H2O + 24e- + 24H+
Step 6. Simplify the equation. The same species on opposite sides of the arrow can be canceled. Write the equation so that the coefficients are the smallest set of integers possible.
2N+52O-25 + 3H02 → 3O03 + 4N-1H+1 + H2O
Latent heat of vaporization is used to (1 Point) (a) overcome the forces of attraction between molecules in solid-state. (b) increase the kinetic energy of molecules in a liquid state. (c) overcome the forces of attraction between molecules in a liquid state. (d) increase the kinetic energy of molecules in the vapour state.
Answer:
Not sure what the answer is
Explanation:
I did this a while ago and dont remember sorry
Which of these is an example of interactions between the atmosphere and hydrosphere? (3 points) formation of snow cracking of rocks due to heat destruction of houses by wind uprooting of trees during tornadoes
Answer:
A. formation of snow
Explanation:
The formation of snow is an example of interactions between the atmosphere and hydrosphere.
As snow formation takes place when water vapor converted into liquid through condensation in the clouds. As water droplets rises high in clouds, cooler air present in atmosphere allow to lower the temperature and water droplets form ice or snow.
Hence, the correct option is A.
Answer:
A:formation of snow
Explanation:
1. How many acetate ions are in the compound strontium acetate?
Answer: 2 Acetate ions
Explanation:
Strontium Acetate, has the molecular formular to be; C4H6O4Sr ( or in a linear form, Sr(CH3COO)2), contains two acetate ions.
In one molecule of strontium acetate (Sr(CH₃COO)₂), there are two acetate ions (CH₃COO⁻).
We must first comprehend the chemical composition of strontium acetate in order to calculate the quantity of acetate ions present.
Acetate ions (CH₃COO⁻) and strontium ions (Sr²⁺) combine to linear form the ionic compound strontium acetate. Sr(CH₃COO)₂ is the chemical formula for strontium acetate.
(CH₃COO)₂ stands for two acetate ions in the formula. The (CH₃COO⁻) ion, also referred to as the acetate ion, is a polyatomic ion made up of two carbon (C), three hydrogen (H), and two oxygen (O) atoms. It has a -1 charge overall.
Thus, there are two acetate ions (CH₃COO⁻) in a single molecule of strontium acetate (Sr(CH₃COO)₂).
It's crucial to understand that in ionic compounds like strontium acetate, the ratio of positively charged ions (cations) to negatively charged ions (anions) must be balanced in order to produce a neutral compound. In this instance, the two -1 charges of the acetate ions (CH₃COO⁻) counterbalance the two +2 charges of the strontium ions (Sr²⁺), creating a neutral molecule.
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What are the following equations for each:
1. Ratio of product concentrations reactant concentrations at equilibrium.
2. Ratio of partial pressures of products to partial pressures of reactants (for gas phase reactions only) at equilibrium
3. Ratio of products reactants for the reaction of a weak base with water at equilibrium.
4. The thermodynamic equilibrium constant, calculated from thermodynamic data, not concentrations.
5. The autoionization constant for water (= 1.0 x 10-14).
6. Ratio of products reactants for the reaction of a weak acid with water at equilibrium
Answer: thats alot of reading
Explanation:
Which of the following atoms has the largest atomic radius? Provide an explanation
a Hydrogen
b. Sodium
C Lithium
d Rubidium
Answer:
d Rubidium
Explanation:
The atomic radius of an atom is the distance from the center of the nucleus to its outermost electron.
The atomic radius of elements varies in the periodic table, it increases as you go down in a group and decreases along the period from left to right.
All the elements listed: Hydrogen, Sodium, Lithium and Rubidium belong to the same group in the periodic table (group 1), Since atomic radius increases from top to bottom in a group, Rubidium has the largest atomic radius.
I’ve gotten the answer as x=.478 but when plugging back in, .46/.478 ≠ .22. Help please
Answer:
15. 2.66 moles .
16. 2.09L.
Explanation:
Molarity of a solution is simply defined as the mole of solute per unit litre of the solvent. Mathematically, it is represented as:
Molarity = mole /Volume.
With the above formula, let us answer the questions given above
15. Data obtained from the question include the following:
Volume of solution = 1.4L
Molarity = 1.9M
Mole of solute =.?
Molarity = mole /Volume
1.9 = mole / 1.4
Cross multiply
Mole = 1.9 x 1.4
Mole = 2.66 moles
Therefore, the mole of the solute present in the solution is 2.66 moles.
16. Data obtained from the question include the following:
Mole of solute = 0.46 mole
Molarity = 0.22M
Volume of solvent (water) =.?
Molarity = mole /Volume
0.22 = 0.46/Volume
Cross multiply
0.22 x Volume = 0.46
Divide both side 0.22
Volume = 0.46/0.22
Volume = 2.09L
Therefore, 2.09L of water is required.
how can the hemlock woolly upset natural ecosystem?
Answer:
The HWA attacks eastern hemlock trees in forests and ornamental hemlock trees found in our residential landscaping. It feeds on the hemlock trees' young twigs by sucking the sap, causing their buds to die and needles to dry out and drop from the plant prematurely i think
hope i helped!!
Which gas relights a glowing splint? *
C hydrogen
A ammonia
B carbon dioxide
D oxygen
Answer:
Oxygen
Explanation:
A glowing splint applied to a sample of gas "oxygen" will relight.
The compound diborane can be used as a rocket propellant. What is the percent composition of boron in diborane (B2H6)? A. 22% B. 25% C. 39% D. 75% E. 78%
Answer: E. 78%
Explanation:
Diborane (B2H6), a chemical compound made up of approximately 78% Boron and 22% Hydrogen.
Answer:
E
Explanation:
#edmentumgang
What is the energy of an electromagnetic wave with a frequency of 8 x 10^12
Hz?
A. 4.2 x 10-22 J
B. 2.4 x 1021 J
C. 1.59 x 10-12
D. 5.3 x 10-21 J
Answer:
Energy, [tex]E=5.3\times 10^{-21}\ J[/tex]
Explanation:
It is required to find the energy of an electromagnetic wave with a frequency of [tex]8\times 10^{12}\ Hz[/tex]. The energy of a wave in terms of its frequency is given by :
[tex]E=h\nu[/tex]
[tex]\nu[/tex] = frequency of em wave
[tex]E=6.63\times 10^{-34}\times 8\times 10^{12}\\\\E=5.3\times 10^{-21}\ J[/tex]
So, the energy of an electromagnetic wave is [tex]5.3\times 10^{-21}\ J[/tex]
Answer:
D. [tex]5.3 * 10^-21 J[/tex]
A student is trying to dissolve 20 grams of sugar in a beaker containing 250 milliliters of water at room temperature. What can the student do to make the sugar dissolve faster in the water? a. decrease the temperature of the water b.use larger pieces c.stir rapidly d.use less water
Answer:
C. Stir rapidly
Aluminum hydroxide is often present in antacids to neutralize stomach acid (HCl). If 14.0 g aluminum hydroxide is present in an antacid tablet, determine the theoretical yield of aluminum chloride produced when the tablet reacts with stomach acid. If the actual yield of the aluminum chloride from this tablet is 22.0 g, what is the percent yield?
Answer:
Percent Yield = 91.97%
Explanation:
Aluminum hydroxide Formula: Al(OH)3 Molar mass: 78 g/mol
Stomach acid Formula: HCl Molar mass: 36.46 g/mol
Aluminum Chloride Formula: AlCl₃ Molar mass: 133.34 g/mol
14g Al(OH)3
2Al(OH)3 + Cl2 → 2Al(OH)3Cl
Balanced equation
14/156 = 0.0897 Moles of Al(OH)3
Ratio is 2:1:2 so same ratio for Al(OH)3 to AlCl₃
0.0897 x 266.68 = 23.92grams of AlCl₃
Theoretical yield of aluminum chloride
Actual yield aluminum chloride 22.0 g
Percent yield?
Percent Yield = (actual Yield/Theoretical yield) x 100
Percent Yield = (22/23.92) x 100
Percent Yield = 91.97%
The percent yield of aluminum chloride in the neutralization reaction has been 91.97%.
The balanced reaction for neutralization of stomach acid with aluminum hydroxide has been:
[tex]\rm Al(OH)_3\;+\;3\;HC\l\rightarrow\;AlCl_3\;+\;3\;H_2O[/tex]
The reaction has been determined that 1 mole of aluminum hydroxide forms 1 mole of aluminum chloride. The moles of aluminum hydroxide has been given as:
Moles = [tex]\rm \dfrac{Mass}{Molecular\;mass}[/tex]
Moles of Aluminum hydroxide = [tex]\rm \dfrac{14}{156}[/tex]
Moles of Aluminum hydroxide = 0.0897 mol.
Thus, the aluminum chloride formed has been:
1 mole Aluminum hydroxide = 1 mole aluminum chloride
0.0897 mole aluminum hydroxide = 0.0897 mole aluminum chloride
The mass of Aluminum chloride formed has been:
0.0897 mole aluminum chloride = [tex]\rm \dfrac{Mass}{266.68}[/tex]
Mass of Aluminum chloride = 0.0897 mol × 266.68 g/mol
Mass of Aluminum chloride = 23.92 grams
The %yield can be given as:
%Yield = [tex]\rm \dfrac{Actual\;yield}{Theoretical\;yield}\;\times\;100[/tex]
The theoretical yield = 23.92 grams
The actual yield = 22 grams
% Yield = [tex]\rm \dfrac{22}{23.92}\;\times\;100[/tex]
% Yield = 91.97%.
The percent yield of aluminum chloride in the neutralization reaction has been 91.97%.
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Consider the model of the nitrogen atom which electron configuration matches the model
Answer:
1s², 2s², 2p³
Explanation:
The atomic number of Nitrogen is seven. So it contains seven protons and seven electrons in neutral form. Also, the electronic configuration cited above contains seven electrons among which two electrons are present in first shell and five electrons are present in valence shell respectively.
Calculating pH
DETERMINE THE PH OF EACH SOLUTION
» [H] = 1 x 10-9M
pH =
» POH = 3
pH =
» [OH ) = 1 x 10-2 M
pH =
» POH = 7
pH =
Answer:
The answer to your question is given below
Explanation:
1. Data obtained from the question include:
Hydrogen ion concentration, [H+] = 1x10^-9M
pH =..?
pH = - log [H+]
pH = - log 1x10^-9
pH = 9
2. Data obtained from the question include:
pOH = 3
pH =.?
Recall:
pH + pOH = 14
pH + 3 = 14
Collect like terms
pH = 14 - 3
pH = 11
3. Data obtained from the question include:
Hydroxide ion concentration, [OH-] = 1x10^-2M
pH =..?
First, we shall determine the pOH. This is illustrated below
pOH = - Log [OH-]
pOH = - Log 1x10^-2
pOH = 2
Finally, we can obtain the pH as follow:
pH + pOH = 14
pOH = 2
pH + 2 = 14
Collect like terms
pH = 14 - 2
pH = 12
4. Data obtained from the question include:
pOH = 7
pH =.?
Recall:
pH + pOH = 14
pH + 7 = 14
Collect like terms
pH = 14 - 7
pH = 7
