When estimating a job to bid, a contractor’s estimator first determines the actual cost of labor using the function L(h) = 28.75h, where h is the number of estimated hours it will take to complete the job. Next, the estimator adds the labor burden, which accounts for taxes and insurance, using the function B(L) = 1.78L. Finally, the estimator calculates the selling price, including the markup for overhead and profit, using the function M(B) = 1.43B. Which composite function can be used to find the selling price for the labor portion of a bid based on the estimated number of hours?

Answer:

d. no solution

Explanation:

Step 1 - Subtract nine from both sides of the equation

[tex]|x| + 9 \leqslant 7 \\ |x| + 9 - 9 \leqslant 7 - 9 \\ |x| \leqslant - 2[/tex]

Step 2 - Remove the absolute value

[tex] |x| \leqslant - 2 \\ 2 \leqslant x \leqslant - 2 \\ 2 \leqslant - 2[/tex]

Therefore, since positive two is not less than or equal to negative two, there is no solution.

Answer:

  θ = ±2π/3 +2kπ . . . . . for any integer k

Step-by-step explanation:

  2·cos(θ) +1 = 0

  cos(θ) = -1/2 . . . . . subtract 1, divide by 2

The cosine function has the value -1/2 for θ = ±2π/3 and any integer multiple of 2π added to that.

  θ = ±2π/3 +2kπ . . . . . for any integer k

No figure required.  If M is the midpoint of ST then SM=MT or

3x + 16 = 6x + 4

12 = 3x

x = 4

SM = 3(4)+16=28

Answer: 28

Answer:

[tex] P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b[/tex]

And using this formula we have this:

[tex] P(X<11) = \frac{11-0}{12-0}= 0.917[/tex]

Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917

Step-by-step explanation:

Let X the random variable of interest that a woman must wait for a cab"the amount of time in minutes " and we know that the distribution for this random variable is given by:

[tex] X \sim Unif (a=0, b =12)[/tex]

And we want to find the following probability:

[tex] P(X<11)[/tex]

And for this case we can use the cumulative distribution function given by:

[tex] P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b[/tex]

And using this formula we have this:

[tex] P(X<11) = \frac{11-0}{12-0}= 0.917[/tex]

Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917

Answer:

A right triangle consists of two legs and a hypotenuse.

Step-by-step explanation:

The two legs meet at a 90° angle and the hypotenuse is the longest side of the right triangle and is the side opposite the right angle. There are a couple of special types of right triangles, like the 45°-45° right triangles and the 30°-60° right triangle.

the answer is A: 146 ≤ 9c + 10

Answer: 400

Step-by-step explanation:

25% is equal to one quarter (1/4). If theres 100 red gumballs then there must be 300 more gumballs in the machine because a quarter of a number is always even.

Answer:

Step-by-step explanation:

The bottom (or top) of the U is called the vertex, or the turning point. The vertex of a parabola opening upward is also called the minimum point. The vertex of a parabola opening downward is also called the maximum point.

The x-intercepts are called the roots, or the zeros. To find the x-intercepts, set ax^2 + bx + c = 0.

The parabola is symmetric (a mirror image) about a vertical line drawn through its vertex (turning point). This line is called the axis of symmetry.

If possible, please mark brainliest

The quadratic function can be expressed in the form of vertex form and the parabola is symmetric about the line which is passing through focus.

The quadratic equation is given as ax² + bx + c = 0. Then the degree of the equation will be 2.

The important features for the graph of a quadratic function will be

The parabola is symmetric about the line which is passing through focus.

The quadratic function can be expressed in the form of vertex form.

Let the point (h, k) be the vertex of the parabola and a be the leading coefficient.

Then the equation of the parabola will be given as,

y = a(x - h)² + k

More about the quadratic equation link is given below.

https://brainly.com/question/2263981

#SPJ2

Answer:

55% probability that a randomly selected depth is between 2.25 m and 5.00 m

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X between c and d is given by the following formula.

[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]

While conducting experiments, a marine biologist selects water depths from a uniformly distributed collection that vary between 2.00 m and 7.00 m.

This means that [tex]a = 2, b = 7[/tex]

What is the probability that a randomly selected depth is between 2.25 m and 5.00 m?

[tex]P(2.25 \leq X \leq 5) = \frac{5 - 2.25}{7 - 2} = 0.55[/tex]

55% probability that a randomly selected depth is between 2.25 m and 5.00 m

Answer:

Population = 34.27336

Step-by-step explanation:

Given:

Population function (t) = 34(1.00804)^t

Number of year = 2000

Find:

Number of citizen in year 2000

Computation:

We know that, base year is 2000

So, t = 1

Population function (t) = 34(1.00804)^t

Population function (1) = 34(1.00804)^1

Population = 34(1.00804)

Population = 34.27336

Therefore, Population is 34.273636 million

Answer:

8

Step-by-step explanation:

just do the comparation

Vb : Vs

b for big and s for small

4/3 π rb³ : 4/3 π rs³ (since there are 4/3 and π on both side, we can eliminate them so)

Vb : Vs = rb³ : rs³

Vb : Vs = (2rs)³ : rs³

Vb : Vs = 8rs³ : rs³ (delete the r³ on both side)

Vb : Vs = 8 : 1

so Vb is 8 times larger in volume than the small one

Answer:

A) The probability that a randomly selected medical student who took the test had a total score that was less than 484 = 0.06178

B) The probability that a randomly selected study participant's response was between 504 and 516 = 0.29019

C) The probability that a randomly selected study participant's response was more than 528 = 0.00357

D) Option D is correct.

Only the event in (c) is unusual as its probability is less than 0.05.

Step-by-step explanation:

The b and c parts of the question are not complete.

B) Find the probability that a randomly selected study participant's response was between 504 and 516

C) Find the probability that a randomly selected study participant's response was more than 528.

D) Identify any unusual event amongst the three events in A, B and C. Explain the reasoning.

a) None.

b) Events A and B.

C) Event A

D) Event C

Solution

This is a normal distribution problem with

Mean = μ = 500

Standard deviation = σ = 10.4

A) Probability that a randomly selected medical student who took the test had a total score that was less than 484 = P(x < 484)

We first normalize or standardize 484

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (484 - 500)/10.4 = - 1.54

To determine the required probability

P(x < 484) = P(z < -1.54)

We'll use data from the normal distribution table for these probabilities

P(x < 484) = P(z < -1.54) = 0.06178

B) Probability that a randomly selected study participant's response was between 504 and 516 = P(504 ≤ x ≤ 516)

We normalize or standardize 504 and 516

For 504

z = (x - μ)/σ = (504 - 500)/10.4 = 0.38

For 516

z = (x - μ)/σ = (516 - 500)/10.4 = 1.54

To determine the required probability

P(504 ≤ x ≤ 516) = P(0.38 ≤ z ≤ 1.54)

We'll use data from the normal distribution table for these probabilities

P(504 ≤ x ≤ 516) = P(0.38 ≤ z ≤ 1.54)

= P(z ≤ 1.54) - P(z ≤ 0.38)

= 0.93822 - 0.64803

= 0.29019

C) Probability that a randomly selected study participant's response was more than 528 = P(x > 528)

We first normalize or standardize 528

z = (x - μ)/σ = (528 - 500)/10.4 = 2.69

To determine the required probability

P(x > 528) = P(z > 2.69)

We'll use data from the normal distribution table for these probabilities

PP(x > 528) = P(z > 2.69) = 1 - P(z ≤ 2.69)

= 1 - 0.99643

= 0.00357

D) Only the event in (c) is unusual as its probability is less than 0.05.

Hope this Helps!!!

Answer:

Step-by-step explanation:

Area of a sector = [tex]\frac{\theta}{360} * \pi r^{2}\ where\ \pi r^{2} \ is\ the\ area\ of\ the\ circle[/tex]

theta is the sector's central angle

Area of the sector = [tex]\frac{\theta}{360} * \ area\ of\ a\ circle[/tex]

Given area of a circle = 18πin² and area of a sector = 6πin²

On substituting;

6π = [tex]\theta/360 * 18 \pi[/tex]

Dividing both sides by 18π we have;

1/3 = [tex]\theta/360[/tex]

[tex]3 \theta = 360\\\theta = 360/3\\\theta = 120^{0}[/tex]

The sector's central angle is 120°

Answer:

[tex] (x+11)^2 = (x+3)^2 +16^2[/tex]

And if we solve this equation for x we got:

[tex] x^2 +22x +121 = x^2 +6x +9 +256[/tex]

We can cancel [tex]x^2[/tex] in both sides and we have this:

[tex] 22x -6x= 256+9-121 =144[/tex]

And then we got:

[tex] 16 x= 144[/tex]

[tex] x =\frac{144}{16}= 9[/tex]

And then the length of the sides are 9+11= 20 m for the hypothenuse, 16 for the adjacent side and 9+3 = 12m for the last side.

Lenght of the smaller unknown side: 12m

Lenght of the larger unknown side: 20m

Step-by-step explanation:

For this case we have a right triangle and we can use the Pythagoras Theorem and using the info given by the triangle we can set up the following equation:

[tex] (x+11)^2 = (x+3)^2 +16^2[/tex]

And if we solve this equation for x we got:

[tex] x^2 +22x +121 = x^2 +6x +9 +256[/tex]

We can cancel [tex]x^2[/tex] in both sides and we have this:

[tex] 22x -6x= 256+9-121 =144[/tex]

And then we got:

[tex] 16 x= 144[/tex]

[tex] x =\frac{144}{16}= 9[/tex]

And then the length of the sides are 9+11= 20 m for the hypothenuse, 16 for the adjacent side and 9+3 = 12m for the last side side.

Lenght of the smaller unknown side: 12m

Lenght of the larger unknown side: 20m

Answer:

$3,485.48

Step-by-step explanation:

For computing the money required at the end of the account term we need to apply the Future value formula i.e be to shown in the attachment below:

Given that,  

Present value = $3,000

Rate of interest = 3% ÷ 365 days  = 0.00821917

NPER = 5 years × 365 days  = 1,825

PMT = $0

The formula is shown below:

= FV(Rate;NPER;PMT;PV;type)

So, after applying the above formula

the amount of future value is $3,485.48

Answer:

a) 56.82

b) 64

c) there is no mode

d) 57

e) the jersey numbers are nominal data and they do not measure or count anything, so the resulting statistic are meaningless

Step-by-step explanation:

The first thing is to organize the data from least to greatest:

15 24 29 38 41 64 72 74 76 93 99

a) the mean would be the average of the data, thus:

m = (15 + 24 + 29 + 38 + 41 + 64 + 72 + 74 + 76 + 93 + 99) / 11

m = 56.82

b) the median is the data of half, when the data is organized, in this case the value of half would be the sixth data that is 64.

c) the mode is the value that is most repeated, therefore as none is repeated there is no mode.

d) the midrange is the average between the minimum value and the maximum value:

mr = (15 + 99) / 2

mr = 57

e) the jersey numbers are nominal data and they do not measure or count anything, so the resulting statistic are meaningless

Answer:

  42.67%

Step-by-step explanation:

The annual growth factor for interest at annual rate r compounded quarterly is ...

  (1 +r/4)^4

You want that value to be 1.5:

  1.5 = (1 +r/4)^4

  1.5^(1/4) = 1 +r/4

  (1.5^(1/4) -1) = r/4

  4(1.5^(1/4) -1) = r ≈ 0.426728

The rate r must be about 42.67%.

_____

Comment on the wording

We interpreted the problem to mean the end-of-year amount is 1.5 times the beginning-of-year amount. That is, it is "1.5 times the amount invested."

The word "more" is typically used when addition is involved. For example, "25% more" means 25% of the original is added to the original. We occasionally see "more" where "x times more" is intended to mean "x times", rather than "x times the amount, added to the original amount."

Answer:

2/7

Step-by-step explanation:

Since Rebecca is garunteed to pick a poodle, there are 7 puppies left. There are 2 retrievers so the probability is 2/7

Answer:2/7

Step-by-step explanation:

Answer:  The correct answer is:  

_________________________  

The given "graph" in the bottom right, lowest corner

Step-by-step explanation:

_________________________

Note:  When there is only one (1) equation give for a graph;

          and/or:  only one (1)  "inequality given";  

         we  look for the symbol.

If the symbol is "not" an "equals" symbol (i.e. not an:  =  symbol) ;

 we check for the type of "inequality" symbol.

If there is a:  "less than" (<) ;  or a "greater than" (>) symbol;  the graph of the "inequality" will have "dashed lines" (since there will be a "boundary").

If there is an "inequality" that is a: "less than or equal to" (≤) ;

                                                 or a: "greater than or equal to" (≥) ;

       →   then there will be not be a dashed line when graphed;

          but rather—a "solid line" ;  since "less than or equal to" ;

          or "greater than or equal to" —is similar to:

          "up to AND including"; or: "lesser/fewer than AND including".).

 _________________________  

Note:  We are given the "inequality" :

            →   " y <  x²  + 4x  "  .

_________________________________

Note that we have a "less than" symbol (< ) ; so the graph will have a:

   "solid line" [and not a "dotted line".].

_________________________________

Note that all of the graphs among our 4 answer choices have "dotted lines".

Not that all values (all x and y coordinated) within the "shaded portion" of the corresponding graph are considered part of the graph.  

As such, given any point within the shaded part,  the x and y coordinates must match the inequality (i.e. the given inequality must be true when one puts in the "x-coordinate" and "y-coordinate" into the "given inequality" :

→   " y <  x²  + 4x "  .

_________________________

Likewise, we can take any point within the "white, unshaded" portion of any of the graph, and take the "x-coordinate" and "y-coordinate" of that point, and the inequality: →   " y <  x²  + 4x  "  ;  will not hold true when the "x-coordinate" and "y-coordinate" values of that point— are substituted into the "inequality".  

_________________________

{Note:  Answer is continued on images attached.}.

Wishing you the best!

Answer: C ( yes, both lines have a slope of 2/3. )

Step-by-step explanation:

Answer: C

Step-by-step explanation:

Answer:

a. 6% one is better

b. $12,285.95

Step-by-step explanation:

a. For determining which investment earn more first we have to calculate both the investment which are as follows

a. Based on compound quarterly, the amount is find out by using the following formula

[tex]Amount = {Present\ value\times (1 + interest\ rate)} ^{number\ of\ years}[/tex]

where,

Present value is $50,000

Interest rate is = [tex]\frac{0.06}{4}[/tex] = 0.015

And, the number of years is

= [tex]4\times4[/tex]

= 16

So, the amount is

[tex]= \$50,000 \times (1 + 0.015)^{16}[/tex]

= $63,449.28

And, based on compounded continuously, the amount is determined by using the following formula

[tex]Amount = Present\ value\times e^{rt}[/tex]

[tex]= \$50,000 \times e.^{0575(4)}[/tex]

= $51,163.33

Therefore, The the investment at 6% is better

b. Now the difference in earning is

= $63,449.28 - $51,163.33

= $12,285.95

Answer:

f

Step-by-step explanation:

Complete Question

A box is formed by cutting squares from the four corners of a sheet of paper and folding up the sides. However, the size of the paper is unknown!

Answer:

(a)[tex]f(0.2)=0.2(l-0.4)(w-0.4)[/tex]

(b)[tex]f(1.3)=1.3(l-2.6)(w-2.6)[/tex]

(c)f(1.3)-f(0.2)

(d) f(5.6)-f(5.5)

Step-by-step explanation:

Let the Length of the paper =l  (in inches)

Let the Width of the paper =w  (in inches)

Let the length of the cutout square = x (in inches)

Volume of the box: [tex]f(x)=x(l-2x)(w-2x)[/tex]

(a)When the cutout length is 0.2 inches.

x=0.2

Volume of the box (in cubic inches) ,

[tex]f(0.2)=0.2(l-0.4)(w-0.4)[/tex]

(b)When the cutout length is 01.3 inches.

x=1.3

Volume of the box (in cubic inches) ,

[tex]f(1.3)=1.3(l-2.6)(w-2.6)[/tex]

(c)If the cutout length increases from 0.2 inches to 1.3 inches.

Change In volume (in cubic inches):

[tex]f(1.3)-f(0.2)\\=1.3(l-2.6)(w-2.6)-0.2(l-0.4)(w-0.4)[/tex]

(d)If the cutout length increases from 5.5 inches to 5.6 inches.

Change In volume (in cubic inches):

[tex]f(5.6)-f(5.5)\\=5.6(l-11.2)(w-11.2)-5.5(l-11)(w-11)[/tex]

Answer:

Option (2).

Step-by-step explanation:

In the figure attached,

A, C and B are the points lying on a straight line.

2 lines EC and DC have been drawn by extending the lines from C to E and D respectively.

Ray CE is the angle bisector of ∠ACD.

That means CE divides ∠ACD in two equal parts.

m∠ACE = m∠DCE

Since m∠ACD = m∠ACE + m∠DCE

                        = 2(m∠ACE)

          m∠ACE = [tex]\frac{1}{2}(\angle ACD)[/tex]

Therefore, option (2) will be the answer.

Answer:

b

Step-by-step explanation:

took test

The correct answer is D No, Dan should reduce his discretionary spending

Explanation:

For Dan to stay on the budget he needs to spend the amount budgeted for each expense or less than the amount budgeted. This occurred in the case of the Internet, food, and rent; for example, the amount budgeted for the internet was $35 and Dan spent this money, also, the amount budgeted for food was $100 and Dan spent $95, which means he stood in the budget. However, this did not occur with discretionary spending, which refers to other non-necessary expenses, because in this case, Dan spent $140 even when the budget limit was $100. Also, this exceeds the total income considering 35 + 95 + 500+ 140 = $770, which is above the income ($750). Thus, Dan did not stay in the budget because he spent more money than expected in discretionary spending and should reduce this.

The correct answer is D. No, Dan should reduce his discretionary spending.

Hope this helps

:)

Answer:

The quantity of salt at time t is [tex]m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })[/tex], where t is measured in minutes.

Step-by-step explanation:

The law of mass conservation for control volume indicates that:

[tex]\dot m_{in} - \dot m_{out} = \left(\frac{dm}{dt} \right)_{CV}[/tex]

Where mass flow is the product of salt concentration and water volume flow.

The model of the tank according to the statement is:

[tex](0.5\,\frac{pd}{gal} )\cdot \left(6\,\frac{gal}{min} \right) - c\cdot \left(6\,\frac{gal}{min} \right) = V\cdot \frac{dc}{dt}[/tex]

Where:

[tex]c[/tex] - The salt concentration in the tank, as well at the exit of the tank, measured in [tex]\frac{pd}{gal}[/tex].

[tex]\frac{dc}{dt}[/tex] - Concentration rate of change in the tank, measured in [tex]\frac{pd}{min}[/tex].

[tex]V[/tex] - Volume of the tank, measured in gallons.

The following first-order linear non-homogeneous differential equation is found:

[tex]V \cdot \frac{dc}{dt} + 6\cdot c = 3[/tex]

[tex]60\cdot \frac{dc}{dt} + 6\cdot c = 3[/tex]

[tex]\frac{dc}{dt} + \frac{1}{10}\cdot c = 3[/tex]

This equation is solved as follows:

[tex]e^{\frac{t}{10} }\cdot \left(\frac{dc}{dt} +\frac{1}{10} \cdot c \right) = 3 \cdot e^{\frac{t}{10} }[/tex]

[tex]\frac{d}{dt}\left(e^{\frac{t}{10}}\cdot c\right) = 3\cdot e^{\frac{t}{10} }[/tex]

[tex]e^{\frac{t}{10} }\cdot c = 3 \cdot \int {e^{\frac{t}{10} }} \, dt[/tex]

[tex]e^{\frac{t}{10} }\cdot c = 30\cdot e^{\frac{t}{10} } + C[/tex]

[tex]c = 30 + C\cdot e^{-\frac{t}{10} }[/tex]

The initial concentration in the tank is:

[tex]c_{o} = \frac{10\,pd}{60\,gal}[/tex]

[tex]c_{o} = 0.167\,\frac{pd}{gal}[/tex]

Now, the integration constant is:

[tex]0.167 = 30 + C[/tex]

[tex]C = -29.833[/tex]

The solution of the differential equation is:

[tex]c(t) = 30 - 29.833\cdot e^{-\frac{t}{10} }[/tex]

Now, the quantity of salt at time t is:

[tex]m_{salt} = V_{tank}\cdot c(t)[/tex]

[tex]m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })[/tex]

Where t is measured in minutes.

Answer:

x = 22

x = 4,6

Step-by-step explanation:

3x - 22 = 44

3x = 44 + 22

3x = 66

x = 66/3

x = 22

5/6 = 10/2x - 3

5/6 + 3 = 10/2x

5/6 + 18/6 = 10/2x

23/6 = 10/2x

23/6 * 2 = 10x

46 = 10x

x = 46/10

x = 4,6

Answer:

The volume of the space outside the pyramid but inside the prism is 225 cubic centimeters.

Step-by-step explanation:

To find this, you subtract the volume of the pyramid from the volume of the rectangular prism.

The prism and pyramid's bases is 25 cm²

The pyramid's height is 12÷2 or 6 cm

The volume formula for a prism is l×w×h

The volume formula for a pyramid is [tex]\frac{1}{3}[/tex] ×b×h

The area of the prism is 5×5×12 or 300 cm³

The area of the pyramid is [tex]\frac{1}{3} *25*6[/tex] or 75 cm³

300 cm³-75 cm³=225 cm³

The volume outside the pyramid but inside the prism is 225 cm³.