Answers
Answer:
13 N to the left
Explanation:
the right side adds up to 1550 13 less than the other side. the box will then be pushed left with 13 newtons of force.
Related Questions
The total sum of atoms in an object.
Answers
Answer:
Mass
Explanation:
The total sum of atoms in an object is the mass of the object. There are several ways to quantify the number of atoms in a substance.
In chemical calculations, the number of moles is a good representation of the number of atoms contained in a body. Mass is the amount of substances a body has. If we can sum up all the atoms in a substance, one will arrive at the mass of the substanceA force act on a bicycle for 2.4 sec, and changes its momentum from 20 kg m/s in the x positive direction to 40 Kg m/s in the Positive x direction, what is the magnitude of the force?
A. -10 N
B. 137.5 N
C. 8.33 N
D. -137.5 N
Answers
Answer:
Increased momentum =40-20=20
F=P/T=20/2.4=8.33N
Explanation:
F=(force)
P=(momentum)
T=(time)
Explanation
A package is dropped from the height of 100 m and falls freely. How fast will the package be traveling when it hits the ground?
Answers
Answer:
The package will be traveling at 44.3 m/s when it hits the ground
Explanation:
Free Fall Motion
A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. Free-falling objects do not encounter air resistance.
If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is [tex]g = 9.8 m/s^2[/tex].
The final velocity of a free-falling object after a time t is given by:
vf=g.t
The distance traveled by a dropped object is:
[tex]\displaystyle y=\frac{gt^2}{2}[/tex]
If we know the height h from which the object was dropped, we can find the time it takes fo hit the ground:
[tex]\displaystyle t=\sqrt{\frac{2h}{g}}[/tex]
The package was dropped from h=100 m, thus the time taken to reach the ground is:
[tex]\displaystyle t=\sqrt{\frac{2(100)}{9.8}}[/tex]
[tex]t = 4.52~s[/tex]
The final speed is now calculated:
[tex]vf=9.8*4.52[/tex]
[tex]vf=44.3~m/s[/tex]
The package will be traveling at 44.3 m/s when it hits the ground
A balloon is launched straight upward and has a hang time of 14 s. (wow)
A.) What was the launching velocity of the balloon?
B.) How high did the balloon travel?
C.) How far did the balloon travel between t = 3 and t = 4 s?
Answers
Answer:
A) Vo = 137.34 [m/s]
B) Y = 961.38 [m]
C) y = 367.8[m] for t = 3 [s] and y = 470.88[m] for t = 4[s]
Explanation:
To solve this problem we must use the following equation of kinematics. We must keep in mind that the negative sign of the equation means that the acceleration of gravity acts in the opposite direction to the movement of the balloon.
A)
[tex]v_{f} =v_{o} -g*t[/tex]
where:
Vf = final velocity = 0 (the maximum hang time, maximum elevation)
Vo = initial velocity [m/s]
g = gravity acceleration = 9.81 [m/s²]
t = time = 14 [s]
0 = Vo - (9,81*14)
Vo = 137.34 [m/s]
B)
Now we use the following equation.
[tex]y=y_{o}+v_{o} *t -(\frac{1}{2} )*g*t^{2}[/tex]
where:
Yo = initial position = 0
Y = final position [m]
Vo = initial velocity = 137.34 [m/s]
Now replacing
Y = (137.34*14) - (0.5*9.81*14²)
Y = 961.38 [m]
C)
With the above equation, we can calculate the distances between t = 3 and t = 4 [s]
[tex]y=y_{o} +v_{o} *t - (1/2)*g*t^{2}[/tex]
y = (137.34*3) - (0.5*9.81*3²)
y = 367.8[m] for t = 3 [s]
for t = 4[s]
y = (137.34*4) - (0.5*9.81*4²)
y = 470.88[m]
A 10kg mass is moving to the right with a velocity of 15 m/s. A 13kg mass
is moving to the left with a velocity of 6.0 m/s. Assuming that these two
masses have a head on collision and stick together, what would be the
final velocity and to what direction? *
Answers
Answer:
M1u1+(-m2u2) = (m1+m2) V. By using this equation you can find the final velocity of that. It would be 3.13ms-1. And the direction is right side.
The number of degrees of arc that your location is north or south of the Earth's equator is called your:
A. meridian
B. declination
C. latitude
D. longitude
Answers
Explanation: your latitude is the number of degrees of arc you are away from the equator along your meridian. Latitudes are measured either north or south of the equator from 0 degrees to 90 degrees.
Which of the following is true about light with a single wavelength?
1) It can be refracted
II) It cannot be dispersed
III) It can be reflected *
Answers
Answer:
It can be refracted
Explanation:
When a single wavelength wave which is known as a monochromatic light is passed from one transparent medium to the other, it can refract. This refraction can only be seen if the light enter the medium at some angle.
A tough kid on a tricycle has combined mass 32 kg. She starts from rest and travels 3.5 m in 2.5 s. What is the net force used to accelerate. (Hint: d=(1/2)at2)
Answers
Answer:
F = 35.84NExplanation:
Force = mass * acceleration (Newton's second law of motion)
Given
Mass = 32kg
Get the acceleration using the expression d = 1/2at^2
3.5 = 1/2 (a)2.5^2
3.5 = 3.125a
a = 3.5/3.125
a = 1.12m/s^2
Get the net force;
F = 3.2 * 1.12
F = 35.84N
Hence the net force used to accelerate is 35.84N
how much would a person whose mass is 60kg weight on the moon
Answers
Given that gravity on the Moon has approximately 1/6th of the strength of gravity on Earth, a man who weighs 60kg on Earth would weigh approximately 10kg on the Moon.
The unit of the electric resistance is ???
Answers
Answer:
OhmsStep-by-step-explanation :
Electric resistance
Dimension length :
Squared mass per time cubed , that is , electric current squared.
The SI derived unit of electric resistance is the ohm,(volt per ampere).
What effect will the following have on the inertia of a body if
(i) the force acting on it is increased.
(ii) the mass of the body is reduced.
Answers
Explanation:
Inertia is the tendency of a body to remain at rest or to do nothing.
It is the resistance to any change in position of body.
When the force on a body increases, the inertia reduces
When the mass is reduced the inertia reduces
According to newton's first law or the law of inertia "an object will remain in its state of rest or of uniform motion unless if it is acted upon by an external force".
pls help me i need both answers pls help me this is being timed.
Answers
Answer:
it would have to be diagram C OR B
Whenever an action and reaction occur, momentum is what?
Answers
Answer:
I'm not sure what your asking for
reaction and law
Explanation:
the newton third law of motion
runnin reggie ran up a mountain from an elevation of 915 m to 4095 m in 62.25 min. If Reggie has a mass of 70 kg, how much power did Reggie generate during his run?
Answers
Answer:
....................
I need help asap!!!!!!! FVLS CIVICS
Step 2:
Brainstorm an idea for a new amendment to the Constitution. Answer the following questions about your new amendment idea.
What will this amendment do?
Whom will it benefit and how?
Answers
Answer:
Amendment (whatever you call it), but it would be amendment 28 if passed, lol
Explanation:
This amendment will be term limits for all members of House and Senate for Congress
How this amendment would benefit is that it would be more structured in Congress.
Just helping as usual what about you
Answers
Answer:
same i just love helping people out
god bless you have a blessed day
Explanation:
Answer:
I do too
Explanation:
I like to help others especially if it has been filled in by struggling in a certain concept of a subject.
Do u agree?
You have an oxygen atom that is looking to bond. How many atoms of one element from column 1 would need to bond with that oxygen to form an ionic bond? Why?
Answers
unit of power is derived unit why
Answers
Answer:
it was given the name Newton (N). from this, the derived unit of energy (or work) is defined ,as the work produced when the unit of force causes a displacement equal to the unit of length of its point of application along its direction . It was given the name Joule (J).
Explanation:
In a tug of war game, team A is very strong and is pulling team B with a speed of 1 foot per second. In this situation… *
A. Only team A is doing work
B.Only team B is doing work
C. Team A and team B are doing work
D. Neither team A nor team B is doing work
Answers
linear expansivity?
Answers
Linear expansivity, area expansivity and volume or cubic expansivity are
The target heart rate zone is:
a
the level your recovery heart rate should reach.
b
where you want your exercise heart rate.
c
where you want your resting heart rate.
d
your maximum heart rate.
Answers
The target heart rate zone is where you want your exercise heart rate to be. Option B is correct.
The target heart rate zone is a specific range of heart rates that you should aim to achieve during exercise to maximize the benefits of your workout. This range is typically calculated based on a percentage of your maximum heart rate. For example, if your maximum heart rate is 180 beats per minute, your target heart rate zone might be between 120 and 150 beats per minute.
The objective pulse is 50 to 85 percent of your greatest pulse. It is the level at which your heart is pulsating with moderate to extreme focus. To decide your greatest pulse, take 220 and deduct your age. Supporting an exercise at this speed works on cardiorespiratory perseverance.
Know more about target heart zone:
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Why this way of voting could benefit baboons
Answers
Multiple Intelligences :
• are completely innate ( inborn)
•can be developed
•are not proven with scientific theory
•a and c
•all of the above
Which one is the answer?
Answers
Answer:
all of the above
PLS MARK ME AS BRAINLIAST
What is the acceleration of car if it goes from 60 m/s to a stop in 6 seconds?
Answers
Explanation:
Use Fab 5 equation to solve for acceleration. (Use equation without d/distance because it is irrelevant for this particular question)
vi = 60m/s
vf = 0m/s because car comes to a stop
t = 6s
a = ?
d = irrelevant
Use a = vf-vi/t
Step by step solution:
a = vf - vi / t
a = 0 - 60 / 6
a = -60 / 6
a = -10m/s^2
Hope this helps! :)
Answer:
[tex]\boxed {\boxed {\sf a= -10 \ m/s^2}}[/tex]
Explanation:
Acceleration can be found by dividing the change in velocity by the time.
[tex]a=\frac{v_f-v_i}{t}[/tex]
The car came to a stop, so it's final velocity is 0 m/s.
The initial velocity of the car is 60 m/s.
The time is 6 seconds.
[tex]v_f=0 \ m/s\\v_i=60 \ m/s\\t= 6 \ s[/tex]
Substitute the values into the formula.
[tex]a=\frac{0 \ m/s-60 \ m/s}{6 \ s }[/tex]
Solve the numerator.
0 m/s-60 m/s= -60 m/s[tex]a\frac{-60 \ m/s}{ 6 \ s }[/tex]
Divide.
[tex]a= -10 \ m/s^2[/tex]
The acceleration of the car is-10 meters per square second. The negative acceleration indicates it is slowing down/stopping.
Why are recessive traits not seen even though they are present in the alleles?
Answers
Answer:
Explanation:. The vending machine holds 10 bags of pretzels and 8 packs of cheese crackers. Both the pretzels and crackers dispenseat 2 bags per hour. How many hours will elapse when there is the same number of snacks remaining in the vending machine? How many of each item will there be at this point?Equation1______________________________Equation2_______________________________Hours: ___________________________ Items: ____________________________What does each equation have n common? ______________________How does this affect the solution?
Who was the first professor who implemented a scientific approach in order to investigate a problem, and who is referred to the the father of scientific mythology
Answers
Answer:
1. Aristotle
2. Thales of Miletus
Explanation:
1. Answer: The first professor who implemented a scientific approach in order to investigate a problem was Aristotle(384-322 BC)
Aristotle was a student under Plato, he pioneered the scientific method in ancient Greece.
2. Answer: The father of scientific mythology was
Thales of Miletus (c. 624/623-c. 548/545 BC)
Thales was a Greek mathematician, astronomer, and pre-socratic philosopher, Asia minor.
If the density of water is 1000 kg/m², what is the pressure at the bottom of a swimming pool 2m
deep when it is full of water?
Answers
The pressure at the bottom when the given tank is full of water will be 19600 Pa.
Pressure can be calculated by the formula,
[tex]\bold {P = \rho h g}[/tex]
Where,
P- pressure = ?
[tex]\bold {\rho}[/tex] - density of water = 1000 kg/m²
h - height of water = 2 m
g - gravity acceleration = 9.8 m/s
Put the values in the formula
[tex]\bold {P = 2 \times 1000 \times 9.8} \\\\\bold {P = 19600\ Pa}[/tex]
Therefore, the pressure at the bottom when the given tank is full of water will be 19600 Pa.
To know more about pressure,
https://brainly.com/question/23603188
A boy on rollerskates is travelling along at 8 m/s. He has a mass of 60 kg and is carrying his
school bag of mass 10 kg. He throws the bag directly forward at 20 m/s relative to the
ground. Calculate the boy's speed after the 'explosion?
Answers
Answer:
6m/s
Explanation:
the original momentum = mass x velocity = 8x (60+10) = 560
momentum after = mass x velocity of the school bag + mass x velocity of the boy = 10x20 + 60x A
200+60A = 560
A=6
what do you know about healthy relationship true or false
Answers
Answer:
this question doesn't make sense
Explanation:
What force is necessary to pull a 10 kg sled across a horizontal surface at a constant velocity if the coefficient of kinetic friction between the sled and the ground is 0.25?
Answers
Answer:
Any force greater than 24.5 N
Explanation:
To find the frictional force is the 1st step. this can be found by multiplying the coefficient of friction and the normal force. normal force can be found by multiplying gravity (we will say 9.8 m/s/s) and the mass which is 10. You then multiply the result by the coefficient of friction which is 0.25 and it leads us to an answer to 24.5 N. This means that if you pull with exactly 24.5 N, the sled wouldnt move. So you need a force greater than 24.5 N and we have our answer.
I hope I helped correct me if im wrong
A force of 25 N is necessary to pull a 10 kg sled across a horizontal surface at a constant velocity if the coefficient of kinetic friction between the sled and the ground is 0.25.
First, we will calculate the normal force (N), which, in a horizontal surface, has the same magnitude and opposite sense as the weight (W) of the sled.
[tex]|N| = |W| = m \times g = 10 kg \times \frac{9.8m}{s^{2} } = 98 N[/tex]
where,
m: mass of the sledg: Earth's gravityThen, we will calculate the friction force (f) using the following expression.
[tex]f = \mu \times N = 0.25 \times 98 N = 25 N[/tex]
According to Newton's first law of motion, for the sled to move at a constant velocity, the sum of the force exerted (F) on the sled and the friction force (f) must be zero.
[tex]F + f = 0\\F = -f\\F = -25 N\\|F| = 25 N[/tex]
A force of 25 N is necessary to pull a 10 kg sled across a horizontal surface at a constant velocity if the coefficient of kinetic friction between the sled and the ground is 0.25.
You can learn more about friction here: https://brainly.com/question/18754989
