79.8L is the volume for 5.00 mol of an ideal gas occupy at 25 C and 153 kPa of pressure.
A measurement of three-dimensional space is volume. It is frequently expressed quantitatively using SI-derived units, like the cubic metre or litre, or different imperial or US-standard units, including the gallon, quart and cubic inch. Volume and length (cubed) have a symbiotic relationship. A container's capacity is typically thought of as being represented by its volume.
P×V = n×R×T
153000×V = 5×0.082×298
V= 79.8L
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I2 + N2H4==> HI + N2 according to the reaction ,How many grams of HI are obtained if 115.7 g of N2H4 reacts with
an excess of iodine?
The mass of the HI that is produced is 1843 g
What is stoichiometry?Stoichiometry is a branch of chemistry that focuses on the quantitative relationships in chemical reactions between reactants and products.
What is the number of moles?
Number of moles of [tex]N_{2} H_{4}[/tex] = 115.7 g/32 g/mol
= 3.6 moles
Now we have that the balanced reaction equation is;
[tex]N_{2} H_{4} + 2I_{2} --- > N_{2} + 4 HI[/tex]
If 1 mole of [tex]N_{2} H_{4}[/tex] produces 4 moles of HI
3.6 moles of [tex]N_{2} H_{4}[/tex] will produce 3.6 * 4/1
= 14.4 moles of HI
Mass of HI produced = 14.4 moles * 128 g/mol
= 1843 g
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You perform a reaction in a coffee cup calorimeter. The calorimeter has 100 mL of water in it, and the temperature of the water increases by 9.3°C. The calorimeter has a heat capacity of 50.2 J/°C. How much heat was produced by the reaction (specific heat capacity of water is 4.184 J/g-°C)?
We can use the equation:
q = m * c * ΔT
where q is the heat absorbed or released by the water, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature of the water.
Since we know that the calorimeter contains 100 mL (or 100 g, since 1 mL of water has a mass of 1 g) of water and that the temperature of the water increased by 9.3°C, we can plug in these values:
q = (100 g) * (4.184 J/g-°C) * (9.3°C)
q = 3896.68 J
However, this is not the total amount of heat produced by the reaction. We need to take into account the heat absorbed by the calorimeter itself, which has a heat capacity of 50.2 J/°C. If we assume that the temperature of the calorimeter did not change during the reaction (i.e., it remained constant), we can calculate the heat absorbed by the calorimeter:
q_calorimeter = (50.2 J/°C) * (9.3°C)
q_calorimeter = 466.86 J
The total heat produced by the reaction is then:
q_reaction = q_water + q_calorimeter
q_reaction = 3896.68 J + 466.86 J
q_reaction = 4363.54 J
Therefore, the heat produced by the reaction is 4363.54 J.
What is the pH of the solution formed when 12.50 mL of 1.05 M KOH is added to 50.0 mL of 0.225 M HBr?
A. 0.65
B. 1.52
C. 12.48
D. 13.35
Answer: D
Explanation:
When 12.50 mL of 1.05 M KOH is added to 50.0 mL of 0.225 M HBr, the resulting solution has a pH of 13.35.
Here’s how to calculate it:
First, we need to determine the number of moles of KOH and HBr in the solution:
moles of KOH = (12.50 mL) * (1.05 mol/L) * (1 L/1000 mL) = 0.013125 mol moles of HBr = (50.0 mL) * (0.225 mol/L) * (1 L/1000 mL) = 0.01125 mol
KOH is a strong base and HBr is a strong acid, so they will react completely to form water and a salt (KBr):
KOH + HBr -> KBr + H2O
The number of moles of KOH is greater than the number of moles of HBr, so there will be an excess of KOH in the solution after the reaction is complete:
moles of excess KOH = moles of KOH - moles of HBr = 0.013125 mol - 0.01125 mol = 0.001875 mol
The total volume of the solution is the sum of the volumes of KOH and HBr:
total volume = 12.50 mL + 50.0 mL = 62.5 mL
The concentration of excess OH- ions in the solution is:
[OH-] = moles of excess KOH / total volume = 0.001875 mol / (62.5 mL * (1 L/1000 mL)) = 0.03 M
The pOH of the solution can be calculated using the formula pOH = -log[OH-]:
pOH = -log(0.03) = 1.52
The pH can be calculated using the formula pH + pOH = 14:
pH = 14 - pOH = 14 - 1.52 = 13.35
So the correct answer is D. 13.35.
How many grams of Al are needed to react with 352 mL of a 1.65 M HCl solution? Given the equation 2Al + 6HCl yields to form 2AlCl3 + 3H2
5.221 grams of Al are required to react with 352 mL of 1.65 M HCl solution.
What is meant by molarity?Molarity (M) is defined as the moles of solute per liter of the solution.
Balanced chemical equation is : 2Al + 6HCl → 2AlCl₃ + 3H₂
From the equation, we can see that 2 moles of Al react with 6 moles of HCl to produce 2 moles of AlCl₃ and 3 moles of H₂.
As moles of HCl = Molarity × Volume
moles of HCl = 1.65 mol/L × 0.352 L
moles of HCl = 0.58128 mol
and moles of Al = (2/6) × moles of HCl
moles of Al = (1/3) × 0.58128 mol
moles of Al = 0.19376 mol
mass of Al = moles of Al × molar mass of Al
mass of Al = 0.19376 mol × 26.98 g/mol
mass of Al = 5.221 g
So, 5.221 grams of Al are required to react with 352 mL of 1.65 M HCl solution.
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Suppose 135 g of NO3- flows into a swamp each day. What volume of N2 would be produced each day at 17.0°C and 1.00 atm if the denitrification process were complete?
____ L of N2
Suppose 135 g of NO3- flows into a swamp each day. What volume of CO2 would be produced each day at 17.0°C and 1.00 atm?
____ L of CO2
Suppose the gas mixture produced by the decomposition reaction is trapped in a container at 17.0°C; what is the density of the mixture assuming Ptotal = 1.00 atm?
____ g/L
The volume of N2 produced each day is approximately 24.56 L.
How to find the volume of N2First, let's find the number of moles of NO3- that flow into the swamp each day:
NO3- molar mass = 14.01 (N) + 3 * 16.00 (O) = 62.01 g/mol
135 g / 62.01 g/mol ≈ 2.177 moles of NO3-
In the denitrification process, NO3- is reduced to N2 gas. The balanced equation for denitrification is:
2NO3- → N2 + 3O2
From the stoichiometry of the reaction, we can see that 2 moles of NO3- produce 1 mole of N2. Therefore, the moles of N2 produced each day can be calculated as follows:
moles of N2 = 2.177 moles of NO3- / 2 ≈ 1.0885 moles of N2
Now we can use the ideal gas law equation to find the volume of N2 produced:
PV = nRT
where:
P = Pressure (1.00 atm)
V = Volume (in Liters)
n = Moles of N2 (1.0885 moles)
R = Ideal gas constant (0.0821 Latm/molK)
T = Temperature (17.0°C or 290.15 K)
Solving for the volume of N2:
V = nRT / P
V = (1.0885 moles) * (0.0821 Latm/molK) * (290.15 K) / (1.00 atm)
V ≈ 24.56 L
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If the initial temperature of an ideal gas at 2.250 atm
is 62.00 ∘C,
what final temperature would cause the pressure to be reduced to 1.700 atm?
determine the solubility of NH and 90° C
The solubility of NH₃ in water at 90°C is approximately 0.03 g per 100 g of water.
What is the solubility of NH₃?The solubility can be determined from a solubility table or by using the appropriate equilibrium constant.
According to a solubility table, the solubility of ammonia in water at 90°C is approximately 88 g per 100 g of water.
Alternatively, the equilibrium constant for the dissolution of ammonia in water at 90°C can be used to calculate the solubility.
The equilibrium constant (K) for the reaction:
NH3 (g) + H2O (l) ⇌ NH4+ (aq) + OH- (aq)
is approximately 1.76 x 10⁻⁵ at 90°C.
Using the equilibrium constant expression:
K = [NH4+][OH-]/[NH3][H2O]
Assuming that the concentration of water remains constant at 100 g per 100 g of solution, and that the concentration of NH4+ and OH- are negligible compared to that of NH3, the solubility of NH3 can be calculated as:
[NH3] = K[H2O] = 1.76 x 10⁻⁵ x 100 = 1.76 x 10⁻³ mol/L
Converting to grams per 100 g of water:
1.76 x 10⁻³ mol/L x 17.03 g/mol = 0.03 g/100 g of water
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The complete question is below:
determine the solubility of NH₃ in water at 90° C
What was the effect of the addition of FeCl3 to the sample solution in the dichromate titration? Explain
[tex]FeCl_3[/tex] is added to ensure all reducing agent is oxidized, indicating endpoint in dichromate titration.
In a dichromate titration, [tex]FeCl_3[/tex] is frequently added to the example arrangement as a sign of the endpoint. The expansion of [tex]FeCl_3[/tex] to the example arrangement assists with guaranteeing that the lessening specialist has been all oxidized by the potassium dichromate ([tex]K_2Cr_2O_7[/tex] ) arrangement.
[tex]FeCl_3[/tex] responds with any overabundance[tex]K_2Cr_2O_7[/tex] in the answer for structure a red-earthy colored encourage of[tex]Fe(OH)_3[/tex] , demonstrating that the lessening specialist has been all oxidized. This response is known as a "back-titration" since overabundance[tex]K_2Cr_2O_7[/tex] is added to the arrangement, trailed by the option of [tex]FeCl_3[/tex] to decide how much unreacted [tex]K_2Cr_2O_7[/tex] .
The response somewhere in the range of [tex]FeCl_3[/tex] and [tex]K_2Cr_2O_7[/tex] can be addressed as:
[tex]6FeCl_3 + K_2Cr_2O_7 + 7H_2SO_4 → 3Fe_2(SO_4)_3 + Cr_2(SO_4)_3 + K_2SO_4 + 7H_2O + 3Cl_2[/tex]
The [tex]FeCl_3[/tex] goes about as a pointer in this response since it responds with the overabundance [tex]K_2Cr_2O_7[/tex] until the decreasing specialist has been all oxidized. As of now, the red-earthy colored encourage of [tex]Fe(OH)_3[/tex] structures, showing that the endpoint has been reached.
Without the expansion of [tex]FeCl_3[/tex], it would be challenging to precisely decide the endpoint of the titration. The expansion of [tex]FeCl_3[/tex] is important to guarantee that the lessening specialist has been all oxidized and that the endpoint has been reached, considering a more exact assurance of the grouping of the diminishing specialist in the example arrangement.
In outline, the expansion of [tex]FeCl_3[/tex] to the example arrangement in a dichromate titration is significant in light of the fact that it assists with guaranteeing that the decreasing specialist has been all oxidized, considering a more precise assurance of its focus.
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The complete question is -
What is the reason for a dichromate titration, and how does [tex]FeCl_3[/tex]support deciding the endpoint of the titration? Might you at any point give the compound condition to the response somewhere in the range of [tex]FeCl_3[/tex] and [tex]K_2Cr_2O_7[/tex] and make sense of why [tex]FeCl_3[/tex] goes about as a marker in this response?
What is the S-P difference (sec)?
What is the amplitude (mm)?
What isthe distance (km)?
What is the magnitude (M)?
The S-P difference (sec) is the time gap between the arrival of the S-wave and the arrival of the P-wave at a seismic station. The S-P discrepancy is depicted in the figure as 20 seconds.
The amplitude (mm) of a seismic wave is the largest displacement from its resting point. The amplitude of the waves is not depicted in the image and cannot be calculated based on the information provided.
Distance (km): Using the S-P time difference and the known velocity of seismic waves, the distance from the seismic station to the earthquake epicenter may be determined. Seismic wave velocity is determined by the type of wave and the features of the Earth's interior. The velocity of P-waves in the Earth's crust, for example, is around 6 km/s. We may compute the distance to the epicenter using this value and the S-P difference of 20 seconds as follows:
Distance = Speed x Time = 6 km/h x 20 seconds = 120 kilometres
As a result, the distance between the seismic station and the earthquake epicenter is about 120 km.
The magnitude of an earthquake (M) is a measurement of the energy generated by the earthquake based on the amplitude of the seismic waves and the distance to the epicenter. Magnitude is commonly measured on a logarithmic scale, with each whole number reflecting a factor of ten increase in energy release.
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Can someone explain the Glyceraldehyde structure for me in detail please. I read that the first carbon atom is the only asymmetric one out of all three carbons and that the other two carbons do have four attachments that just aren’t different. I can’t even see how the atoms have four attachments though.
Answer:
Glyceraldehyde is a simple sugar with three carbon atoms attached to hydroxyl and hydrogen or carbonyl groups. The first carbon atom has four different groups, including an aldehyde group, which makes it asymmetric. This results in two stereoisomers, D-glyceraldehyde and L-glyceraldehyde, that are mirror images of each other and have opposite optical activities.
If 12.5 mol
of an ideal gas occupies 50.5 L
at 69.00 ∘C,
what is the pressure of the gas?
The pressure of a gas that occupies 50.5L at 69.0°C is 6.95 atm.
How to calculate pressure?The pressure of an ideal gas can be calculated using Avogadro's equation as follows;
PV = nRT
Where;
P = pressureV = volume n = no of molesT = temperatureR = gas law constantAccording to this question, 12.5 mol of an ideal gas occupies 50.5 L at 69.00°C. The pressure can be calculated as follows:
P × 50.5 = 12.5 × 0.0821 × 342
50.5P = 350.9775
P = 6.95 atm
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3. Litharge, Pb0, is an ore that can be roasted (heated) in the presence of carbon monoxide, CO, to produce elemental lead. The
reaction that takes place during this roasting process is represented by the balanced equation below.
PbO(s) + CO(g) → Pb(s) + CO₂(g)
In which compound does carbon have the greater oxidation number
Answer:
Explanation:
In the given reaction, carbon has a greater oxidation number in carbon dioxide (CO₂) than in carbon monoxide (CO). In CO₂, the oxidation number of carbon is +4, while in CO it is +2.
2. Using the law of conservation of mass, explain why the following reaction is
wrong: HCI + NaOH → NaCl.
According to the law of conservation of mass, the mass of the reactant must be equal to the mass of the product, hence the reaction is wrong
What is the conservation of mass?The law of conservation of mass states that mass within a closed system remains the same over time.
It states that the mass in an isolated system can neither be created nor be destroyed but can be transformed from one form to another.
Thus, the mass of the reactants must be equal to the mass of the products for a low energy thermodynamic process.
From the information given, we have the reaction written as;
HCI + NaOH → NaCl
The mass of the reactant Hydrogen(H) is not found on the product
The mass of the reactant(Oxygen) is also not found
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The article talks mainly about A. Dr. Dituri's small underwater habitat B. Dr. Dituri's Project Neptune 100 C. Dr. Dituri's talks with other scientists D. Dr. Dituri's 28 years in the U.S. Navy
We see here that the article is actually talking about: B. Dr. Dituri's Project Neptune 100.
What is an article?A piece of writing known as an article is typically printed in a newspaper, magazine, or journal. It may address a variety of subjects, such as news, features, essays, research findings, and reviews.
We can see here that in the article, being referred to in the question is known as "A Chat With the Scientist Living Underwater for 100 Days,".
From the article, it is very clear that it refers to Dr. Dituri's Project Neptune 100. Retired Navy officer, Joseph Dituri is seeking to break the current record for longest period of time spent submerged.
Note: I can't post the article here. But I have provided the title of the article above.
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Pleae answer 2a and 2b
A chemical interaction between an acid and a base is known as an acid-base reaction.
Thus, These are known as acid-base theories, such as the Brnsted-Lowry acid-base theory, and they offer alternative conceptions of the reaction mechanisms and their application in solving related problems.
When examining acid-base reactions for gaseous or liquid species, or when the acid or basic character may be less obvious, their significance becomes clear.
The relative potency of the conjugated acid-base pair in the salt controls the pH of its solutions when weak acids and bases react. The resulting salt or its solution can be basic, neutral, or acidic. A strong acid and a weak base can combine to generate an acid salt.
Thus, A chemical interaction between an acid and a base is known as an acid-base reaction.
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5 moles of a monoatomic ideal gas is compressed reversibly and adiabatically. The initial volume is 6 dm3 and the final volume is 2 dm3. The initial temperature is 27°C.
(i) What would be the final temperature in this process?
(ii) Calculate w, q and ΔE for the process. Given Cv = 20.91 J K−1 mol−1, γ = 1.4
Final temperature: 677.4K. Work done: -7026J.
Heat exchanged: 0J. Change in internal energy: -7026J.
How to solve(i) For an adiabatic process, T1(V1)^γ-1 = T2(V2)^γ-1.
When we substitute the values (γ=1.4, T1=300K, V1=6dm³, V2=2dm³), we get T2 = 677.4K.
(ii) w = -(P1V1 - P2V2)/(γ-1) = -(nRT1 - nRT2)/(γ-1) = -5 * 8.314 * (677.4 - 300) / 0.4 = -7026J.
For adiabatic, q = 0. ΔE = q + w = -7026J (since q=0).
Final temperature: 677.4K. Work done: -7026J.
Heat exchanged: 0J. Change in internal energy: -7026J.
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Question 8 of 21
Which nucleus completes the following equation?
The nucleus completing the following equation is option C: ₂₄⁵⁰Cr.
This reaction is a type of radioactive nuclei decay.
What is radioactive decay?Radioactive decay is the process by which unstable atomic nuclei undergo spontaneous transformations in order to achieve a more stable state. This is accomplished by the emission of particles and/or electromagnetic radiation from the nucleus. The decay may occur by several mechanisms, including alpha decay, beta decay, gamma decay, and electron capture.
In alpha decay, the nucleus emits an alpha particle, which consists of two protons and two neutrons, resulting in a daughter nucleus that has two fewer protons and two fewer neutrons than the original nucleus.
In beta decay, a neutron in the nucleus is converted into a proton and an electron, and the electron is then emitted from the nucleus as a beta particle. This results in the daughter nucleus having one more proton and one fewer neutron than the original nucleus.
In gamma decay, the nucleus emits a gamma ray, which is a high-energy electromagnetic radiation, without changing the number of protons or neutrons in the nucleus.
In electron capture, an electron from the inner shell of the atom is captured by the nucleus, and a proton in the nucleus is converted into a neutron. This results in the daughter nucleus having one fewer proton and one more neutron than the original nucleus.
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All redox reactions form ionic bonds. True or False
Answer:
true
Explanation:
A 250.0-mL flask contains 0.2500 g of a volatile oxide of nitrogen. The pressure in the flask is 760.0 mmHg at 17.00°C. How many moles of gas are in the flask?
Answer:
0.0104 moles of gas in the flask.
Explanation:
To calculate the number of moles of gas in the flask, you can use the ideal gas law equation: PV = nRT. Where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant and T is temperature.
First, you need to convert the pressure from mmHg to atm and the temperature from Celsius to Kelvin. The pressure in atm is 760.0 mmHg / 760 mmHg/atm = 1 atm. The temperature in Kelvin is 17.00°C + 273.15 = 290.15 K.
Next, you need to convert the volume from mL to L. The volume in L is 250.0 mL / 1000 mL/L = 0.2500 L.
Now you can plug all the values into the ideal gas law equation and solve for n: (1 atm)(0.2500 L) = n(0.08206 L·atm/mol·K)(290.15 K). Solving for n gives n = 0.0104 mol.
So there are approximately 0.0104 moles of gas in the flask.
Which of these are part of the
Earth's lithosphere?
O clouds
O glaciers
O mountains
O water vapor
How many grams of zinc would you need to produce 8.45 grams of hydrogen?
Zn + H2SO4 --> ZnSO4 + H2
273.8 grams of zinc (Zn) are needed to produce 8.45 grams of hydrogen gas [tex](H_2).[/tex]
In this chemical reaction, zinc (Zn) reacts with sulfuric acid [tex](H_2SO_4)[/tex] to produce zinc sulfate [tex](ZnSO_4)[/tex] and hydrogen gas [tex](H_2).[/tex]
From the balanced chemical equation, we can see that 1 mole of zinc (Zn) reacts with 1 mole of sulfuric acid [tex](H_2SO_4)[/tex] to produce 1 mole of hydrogen gas [tex](H_2).[/tex]
Hydrogen gas has a molar mass of 2.016 g/mol.
Therefore, 8.45 grams of hydrogen gas is equal to 8.45 g / 2.016 g/mol = 4.19 moles of [tex]H_2[/tex].
Since 1 mole of Zn reacts with 1 mole of [tex]H_2[/tex] , we need 4.19 moles of Zn to produce 4.19 moles of [tex]H_2[/tex].
molar mass of Zinc = 65.38 g/mol.
Therefore, 4.19 moles of Zn has a mass of 4.19 moles x 65.38 g/mol = 273.8 grams.
Therefore, you would need 273.8 grams of zinc (Zn) to produce 8.45 grams of hydrogen gas [tex](H_2).[/tex]
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HELP PLEASE
A 6.50-g sample of copper metal at 25.0 °C is heated by the addition of 145 J of energy. The final temperature of the copper is ________ °C. The specific heat capacity of copper is 0.38 J/g-K.
58.7
33.7
83.7
25.0
33.5
A 6.50-g sample of copper metal at 25.0 °C is heated by the addition of 145 J of energy. The final temperature of the copper is 83.7 °C. The specific heat capacity of copper is 0.38 J/g-K.
The correct answer choice is "83.7"
To solve this problem, we can use the equation:
q = mcΔT
where q is the amount of energy absorbed by the copper, m is the mass of the copper, c is the specific heat capacity of copper, and ΔT is the change in temperature of the copper.
Rearranging this equation to solve for ΔT, we get:
ΔT = q / (mc)
Substituting the given values, we get:
ΔT = 145 J / (6.50 g x 0.38 J/g-K)
ΔT = 58.7 K
Therefore, the final temperature of the copper is:
25.0 °C + 58.7 °C = 83.7 °C
So the correct option is 83.7.
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Compared to chemical reactions, most nuclear reactions result in the
OA. formation of new compounds
OB. formation of new elements
O C. formation of new bonds
OD. loss of valence electrons
Answer:
OB. formation of new elements.
Nuclear reactions involve changes in the nucleus of an atom, such as the splitting of a nucleus or the combining of two nuclei. These reactions can result in the formation of new elements, as the number of protons in the nucleus determines the element. In contrast, chemical reactions involve the rearrangement of electrons between atoms to form new compounds, but do not involve changes to the nucleus.
A silver block, initially at 55.1∘C
, is submerged into 100.0 g
of water at 25.0∘C
in an insulated container. The final temperature of the mixture upon reaching thermal equilibrium is 27.9∘C
. The specific heat capacities for water and silver are Cs,water=4.18J/(g⋅∘C)
and Cs,silver=0.235J/(g⋅∘C)
.
The mass of the silver block, given that it was initially at 55.1 °C and is submerged into 100.0 g of water at 25.0°C is 189.8 g
How do i determine the mass of the silver?We'll begin our calculation by obtaining the heat absorbed by the water. Details below:
Mass of water (M) = 100 gInitial temperature (T₁) = 25 °CFinal temperature (T₂) = 27.9 °CChange in temperature (ΔT) = 27.9 - 25 = 2.9 °CSpecific heat capacity of water (C) = 4.184 J/gºC Heat absorbed by water (Q) =?Q = MCΔT
Q = 100 × 4.184 × 2.9
Q = 1213.36 J
Finally, we shall determine the mass of the silver block. Details below:
Heat absorbed by water (Q) = 6108.64 JHeat released by silver block (Q) = -1213.36 JInitial temperature of silver block (T₁) = 55.1 °CFinal temperature of silver block (T₂) = 27.9 °CChange in temperature (ΔT) = 27.9 - 55.1 = -27.2 °C Specific heat capacity of silver (C) = 0.235 J/gºC Mass of silver block (M) =?Q = MCΔT
-1213.36 = M × 0.235 × -27.2
-1213.36 = M × -6.392
Divide both sides by -6.392
M = -1213.36 / -6.392
M = 189.8 g
Thus, we can conclude that the mass of the silver block is 189.8 g
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Complete question:
A silver block, initially at 55.1∘C, is submerged into 100.0 g of water at 25.0∘C in an insulated container. The final temperature of the mixture upon reaching thermal equilibrium is 27.9∘C. The specific heat capacities for water and silver are Cs,water = 4.18J/(g⋅∘C) and Cs, silver = 0.235J/(g⋅∘C). What is the mass of the silver block?
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5. The head of matches contains an oxidizing agent such as potassium chlorate, KCIO3, together with tetraphosphorus trisulfide, P4S3.
glass, and binder. When struck either by an obect or on the side of a box of matches, the phosphorus sulfide compound is easily
ignited, causing the potassium chlorate to decompose into potassium chloride and oxygen. The oxygen in turn causes the
phosphorus sulfide to burn more vigorously.
Determine the oxidation number of chlorine in potassium chlorate.
The oxidation number of the unknown chlorine in the compound is + 5
What is oxidation number?The oxidation number of an element in a compound is determined by a set of rules based on its position in the periodic table, as well as the charges of other atoms in the compound
We know that the oxidation number of the chlorine which we want to obtain would be designated as x and the total of the oxidation numbers of the elements in the compound is zero.
Thus we have that;
1 + x + 3(-2) = 0
1 + x - 6 = 0
-5 + x = 0
x = 5
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How many g Al must react with iodine to form AlI₃ via the following reaction scheme to release -836.0 kJ of heat? 2 Al(s) + 3 I₂(s) → 2 AlI₃(s)
∆H = -302.9 kJ
The mass (in grams) of aluminum, Al that must react with iodine to form AlI₃, given that -836.0 KJ of heat is relaesd is 149.0 g
How do i determine the mass aluminum required?The mass of aluminum required to react with iodine to produce AlI₃ can be obtain as shown below:
2Al(s) + 3I₂(s) → 2AlI₃(s) ∆H = -302.9 KJ
Molar mass of aluminum, Al = 27 g/molMass of aluminum, Al from the balanced equation = 2 × 27 = 54 gFrom the balanced equation above,
When -302.9 KJ of heat energy is released, 54 g of aluminum, Al reacted.
Therefore,
When -836.0 KJ of heat energy will be release = (-836.0KJ × 54 g) / -302.9 KJ = 149.0 g of aluminum, Al will react.
Thus, from the above calculation, we can conclude that the mass of aluminum, Al required is 149.0 g
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The following equations represent chemical
reactions.
Chemical Reactions
1) 2Na+2H₂O →NaOH + H₂
2) H₂+O₂ H₂O
3) MgCl₂ → MgCl₂
4) NaOH+MgCh→ NaCl + MgOH
Which equation shows that the total mass during a chemical reaction stays the same?
The equation that shows that the total mass during a chemical reaction stays the same is 2) H₂ + O₂ → H₂O.
This is an example of a balanced chemical equation where the number of atoms of each element on both the reactant and product side is equal. In other words, the total number of atoms of each element is conserved, and therefore the total mass is conserved. In the other reactions, either the number of atoms on the product side is different from the reactant side or there is no reaction at all.
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a tank truck carries 34,000 of sulphuric acid. The density of sulfuric acid is 1.84kg/L.
(a) what mass of sulfuric acid is in the truck?
(b) what amount of sulfuric acid is in the truck?
(a) To calculate the mass of sulfuric acid in the truck, we can multiply the volume of sulfuric acid by its density. Given that the truck carries 34,000 liters of sulfuric acid and the density of sulfuric acid is 1.84 kg/L.
we can use the formula:
Mass (m) = Volume (V) × Density (D)
Plugging in the given values:
Volume (V) = 34,000 L Density (D) = 1.84 kg/L
m = 34,000 L × 1.84 kg/L
m ≈ 62,560 kg (rounded to the nearest whole number)
Therefore, the mass of sulfuric acid in the truck is approximately 62,560 kg.
(b) The amount of sulfuric acid in the truck is already given in the question as 34,000 L (volume).
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(a) To find the mass of sulfuric acid in the truck, we need to use the formula:
mass = density x volume
The volume of sulfuric acid in the truck is given as 34,000 L. The density of sulfuric acid is 1.84 kg/L. Therefore, the mass of sulfuric acid in the truck is:
mass = 1.84 kg/L x 34,000 L = 62,560 kg
So there are 62,560 kg of sulfuric acid in the truck.
(b) To find the amount of sulfuric acid in the truck, we need to use the formula:
amount = mass / molar mass
The molar mass of sulfuric acid is 98.08 g/mol. To convert the mass from kg to g, we need to multiply by 1000. Therefore, the amount of sulfuric acid in the truck is:
amount = 62,560,000 g / 98.08 g/mol = 636,816.3 mol
So there are 636,816.3 moles of sulfuric acid in the truck.
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4. A silver bar with a mass of 300 grams is heated from 30 °C to 55 °C. How much heat does the silver ber absorb in joules? In kilojoules? The specific heat of silver is 0.235 g C
A silver bar with the mass of the 300 grams is heated from the 30 °C to 55 °C. The amount heat does the silver bar absorb in the joules is 1762.5 J.
The mass of the silver bar = 300 g
The initial temperature = 30 °C
The final temperature = 55 °C
The heat energy is expressed as :
Q = mc ΔT
Where,
The m is mass of the silver bar = 300 g
The c is the specific heat capacity = 0.235 J/g °C
The ΔT is the change in the temperature = final temperature - initial temperature
The ΔT is the change in the temperature = 55 °C - 30 °C
The ΔT is the change in the temperature = 25 °C
The heat energy, Q = 300 × 0.235 × 25
The heat energy, Q = 1762.5 J
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Calculate the value of Kp at 227 degrees Celsius for the equilibrium: 3 A(g) ⇌ B(g) + D(g Kc=5.15
