Answer:
Well if you want to kiss them go for it, but if you don't then say sorry but I don't feel comfortable with that.
Hope everything goes well <3
Which of the following is a true statement about the Earths tectonic plates?
Answer:
Pretty sure it's C
Explanation:
GIVING BRAINLIEST AND 20 POINTS
Which number represents precipitation on the hydrologic cycle diagram?
1
2
3
4
Answer:
Number three, because precipitation is rain, which comes from cumulonimbus clouds. Precipitation happens when clouds have accumulated enough evaporated water for the cloud to get heavy and need to get rid of some of the water, which it does through condensing the water and then delivering it as rain.
Hope this helps! Have a wonderful day! (Please give me brainliest and thank you!)
:)
Carbon monoxide is a colorless, odorless gas that binds irreversibly to hemoglobin in our blood, causing suffocation and death. CO is formed during incomplete combustion of carbon. One way to represent this equilibrium is: CO(g)C(s) 1/2 O2(g) We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above.
The question is missing some parts. Here is the complete question.
Carbon monoxide is a colorless, odorless gas that binds irreversibly to hemoglobin in our blood, causing suffocation and death. CO is formed during incomplete combustion of carbon. One way to represent this equilibrium is:
[tex]2CO_{(g)}[/tex] ⇄ [tex]2C_{(s)}+O_{2}_{(g)}[/tex]
we could also write this reaction three other ways listed below. The equilibrium constant for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above.
1) [tex]2C_{(s)}+O_{2}_{(g)}[/tex] ⇄ [tex]2CO_{(g)}[/tex] K₁ =
2) [tex]C_{(s)}+1/2O_{2}_{(g)}[/tex] ⇄ [tex]CO_{(g)}[/tex] K₂ =
3) [tex]CO_{(g)}[/tex] ⇄ [tex]C_{(s)}+1/2O_{2}_{(g)}[/tex] K₃ =
Answer: 1) [tex]K_{1}=\frac{1}{K}[/tex]
2) [tex]K_{2}=\frac{1}{K^{1/2}}[/tex]
3) [tex]K_{3}=K^{1/2}[/tex]
Explanation: A chemical reaction can be reversible, i.e., can proceed in both directions: to the right of the arrow (forward) or towards the left of the arrow (backward).
When the rates of forward and backward reactions are the same, the reaction is in equilibrium. In that state, we can determine the equilibrium constant, [tex]K_{c}[/tex].
For the first way to represent equilibrium of CO formed, the [tex]K_{c}[/tex] is calculated
[tex]2CO_{(g)}[/tex] ⇄ [tex]2C_{(s)}+O_{2}_{(g)}[/tex]
[tex]K=\frac{[O_{2}]}{[CO]^{2}}[/tex]
in which the symbol [ ] is concentration of the compound.
In equilibrium constant, solids are not included.
Equilibrium constants for the other reactions:
1) [tex]2C_{(s)}+O_{2}_{(g)}[/tex] ⇄ [tex]2CO_{(g)}[/tex]
[tex]K_{1}=\frac{[CO]^{2}}{[O_{2}]}[/tex]
Comparing K₁ and K, the first one is the inverse of K, so writing in terms of K
[tex]K_{1}=\frac{1}{K}[/tex]
2) [tex]C_{(s)}+1/2O_{2}_{(g)}[/tex] ⇄ [tex]CO_{(g)}[/tex]
[tex]K_{2}=\frac{[CO]}{[O_{2}]^{1/2}}[/tex]
In terms of K, K₂ is
[tex]K_{2}=\frac{1}{K^{1/2}}[/tex]
3) [tex]CO_{(g)}[/tex] ⇄ [tex]C_{(s)}+1/2O_{2}_{(g)}[/tex]
[tex]K_{3}=\frac{[O_{2}]^{1/2}}{[CO]}[/tex]
This constant in terms of K will be
[tex]K_{3}=K^{1/2}[/tex]
In conclusion, K₁, K₂ and K₃ in terms of K is [tex]\frac{1}{K}[/tex],[tex]\frac{1}{K^{1/2}}[/tex] and [tex]K^{1/2}[/tex], respectively.
need help answering this, Aleks is very picky, and I have been struggling with these questions
Answer:
No
No
Yes 25cm
Explanation:
1) mass can't be divided by distance.
2) the measurements are completely different but under the same category of distance. you can only divide it if meters was cm and squared
3) measurements the same and you can multiply it
Ve. In what layer do weather balloons fly?
Earth layers
Answer:
stratosphere
Explanation:
what organelle acts as a barrier of the cell?
Answer:
cell membrane
Explanation:
it controls what comes and goes out of a cell
Answer:
Cell membrane
Explanation:
It separates the interior of all cells from the outside environment (the extracellular space) which protects the cell from its environment.
What is the volume of 0.05 mol of neon gas at 1.45 atm and 275K?
Answer:
sdasdasddsafsadsfds
Explanation:
A balloon of hydrogen is subjected to vacuum. The initial pressure and volume of hydrogen is 0.95 atm and 0.55 L. Calculate the final pressure if the final volume is 1.22 L?
Answer:
0.43 atm
Explanation:
From the question given above, the following data were obtained:
Initial pressure (P₁) = 0.95 atm
Initial volume (V₁) = 0.55 L
Final volume (V₂) = 1.22 L
Final pressure (P₂) =?
The final pressure of the gas can be obtained by using the Boyle's law equation as follow:
P₁V₁ = P₂V₂
0.95 × 0.55 = P₂ × 1.22
0.5225 = P₂ × 1.22
Divide both side by 1.22
P₂ = 0.5225 / 1.22
P₂ = 0.43 atm
Therefore, the final pressure of the gas is 0.43 atm
The final pressure of the gas is 0.43 atm.
What is pressure?Pressure is the process of force exerted perpendicular to any surface.
Given, the Initial pressure (P₁) is 0.95 atm
The initial volume (V₁) is 0.55 L
The final volume (V₂) is 1.22 L
To find the final pressure (P₂)
By the Boyle's Law
[tex]\rm P_1V_2= P_2V_2[/tex]
[tex]\rm 0.95\times 0.55 = P_2\times1.22\\\\0.5225 = P_2 \times 1.22\\\\Divided\;both \;side\;by\;1.22\\\\P_2=\dfrac{0.5225}{1.22} = 0.43 atm.[/tex]
Thus, the final pressure of the gas is 0.43 atm.
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Am I right????????????????Btw question was “Name four abiotic factors shown in the above prairie ecosystem?
Do you agree / disagree - Light is always the same, even when it is emitted by different light sources (like the sun and a light bulb).
Answer:
She's right that there's a difference, and you are right that it's all just electromagnetic waves!
The key to this is that there is no such thing as "white light" when you really get down to it. Each light emits a range of wavelengths of light. If they have a sufficiently even distribution of wavelengths, we tend to call that light "white," but we can only use that term informally.
Both the sun and the light bulb emit so-called "Blackbody radiation." This is the particular spectrum of light that's associated with the random thermal emissions of a hot object. Cool objects tend to emit more of their energy in the longer wavelengths like reds and IRs, while hotter objects emit more energy in the shorter wavelengths like blues and UV.
Blackbody graphic
(Note, there are other possible emission spectra, but those are associated with different materials doing the emissions and, for the purposes of this discussion, they aren't too important. We can just claim the emissions are all blackbody)
If you notice, as you get hotter, a larger portion of the energy is emitted in the blue, violet, and ultraviolet. That's how you get a sunburn from the sun. It's harder to get a sunburn from an artificial light, not because it's artificial, but because those lights are almost always cooler than the sun. They don't have as much UV content. Instead, they have more red and yellow, which incidentally is why pictures taken indoors look very yellow. If you use a strobe, however, all those yellow hues go away because a strobe light is very warm, with lots of blues.
You can get a sunburn from artificial light, of course. Tanning beds are the obvious example, but there are other interesting ones. When you're a jeweler working in platinum, for instance, you need to wear UV protective gear (like glasses or even sunscreen). Platinum's melting point is so hot that it actually emits quite a lot of UV light and can give you a sunburn!
Other than these spectra, there is nothing different between light from an artificial source and light from the sun. Photons are photons.
Explanation:
PLEASS MARK ME AS BRAINLIEST
#STAY SAFE
Most of the sulfur used in the United States is chemically synthesized from hydrogen sulfide gas recovered from natural gas wells. In the first step of this synthesis, called Claus process, hydrogen sulfide gas is reacted with dioxygen gas to produce gaseous sulfur dioxide and water. Suppose a chemical engineer studying a new catalyst for the Claus reaction finds that 450 liters per second of dioxygen are consumed when the reaction is run at 264 degrees Celsius and 0.48 atm.
Required:
Calculate the rate at which sulfur dioxide is being produced. Give the answer in kg per second.
Answer:
[tex]0.21\ \text{kg/s}[/tex]
Explanation:
P = Pressure = [tex]0.48\ \text{atm}=0.48\times 101325\ \text{Pa}[/tex]
V = Volume = [tex]450\ \text{L/s}=450\times 10^{-3}\ \text{m}^3/\text{s}[/tex]
R = Gas constant = [tex]8.314\ \text{J/mol K}[/tex]
T = Temperature = [tex](264+273.15)\ \text{K}[/tex]
The reaction is
[tex]2H_2S+3O_2\rightarrow 2SO_2+2H_2O[/tex]
From ideal gas equation we have
[tex]PV=nRT\\\Rightarrow n=\dfrac{PV}{RT}\\\Rightarrow n=\dfrac{0.48\times101325\times 450\times 10^{-3}}{8.314\times (264+273.15)}\\\Rightarrow n=4.9\ \text{mol}[/tex]
Moles of [tex]SO_2[/tex] produced is
[tex]\dfrac{2}{3}\times 4.9=3.267\ \text{moles}[/tex]
Molar mass of [tex]SO_2[/tex] = 64.066 g/mol
Production rate is
[tex]3.267\times 64.066=209.3\ \text{g/s}=0.21\ \text{kg/s}[/tex]
The rate at which sulfur dioxide is being produced [tex]0.21\ \text{kg/s}[/tex].
Someone please help me I’m so stuck I cannot find the empty ones that were not filled in :(. I’m really confused
Answer:
Positive charges: 2
Negative charges: 1
Overall charge: +1
Explanation:
In Diagram B we have the chemical element Helium (He). You can see in the Periodic Table that He has an atomic number of 2 and an atomic mass of approximately 4.
The atomic number is equal to the number of protons, so He has 2 protons. The protons are the positive charges in the atom, so the number of positive charges is 2. That is invariable, if the number of protons - or the atomic number - of an atom changes, it changes its identity.
In the drawing, we can see that the nucleus is composed of 2 protons (2 'p' particles) and 2 neutrons (2 'n' particles). The atomic mass is calculated as the number of protons and neutrons, so 2 protons+ 2 neutrons = 4.
The surrounding particle with an 'e' is an electron. So, we have 1 electron. Electrons are negative charges, so the number of negative charges is 1.
Now, we can calculate the overall charge. We add the positive charges (protons) and negative charges (electrons). Each proton has a +1 charge, whereas each electron has a -1 charge. Finally, we perform the addition:
Overall charge= (number of protons x charge) + (number of electrons x charge) = (2 x (+1)) + (1 x (-1)) = (+2) + (-1) = +1
how would you explain to an elementary school student what the periodic table is?
Answer: The periodic table is a chart where different types of elements organized by what they have in common.
Explanation:
It is often possible to change a hydrate into an anhydrous compound by heating it to drive off the water (dehydration). Write an equation that shows the dehydration of manganese(II) sulfate pentahydrate . Use an asterisk to enter the dot.
Answer:
MnSO4.5H2O(s) ---------> MnSO4(s) + 5H2O(g)
Explanation:
The dehydration of a hydrate implies that the water of crystallization is lost. Water of crystallization is included in the crystal structure as it is formed and is incorporated into the structure of the compound.
Now the equation for the dehydration of manganese(II) sulfate pentahydrate is;
MnSO4.5H2O(s) ---------> MnSO4(s) + 5H2O(g)
The MnSO4 is now said to be anhydrous.
a molecure that contains 3 iddentical polar bonds to the central atom will be
ANSWER:
Nonpolar
sorry if I'm wrong
Determine the number of molecules in 0.0500 mole of boron tribromide
(show work)
Answer:
There are 0.5 moles
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.
To calculate the moles, we use the equation:
Thus there are 0.5 moles
Explanation:
Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions:
Mg2+, V5+, Br-, S2-
Answer: [tex]MgS[/tex], [tex]MgBr_2[/tex], [tex]V_2S_5[/tex] and [tex]VBr_5[/tex] are four binary ionic compounds that could be formed.
Explanation:
For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.
Mg is having an oxidation state of +2 called as [tex]Mg^{2+}[/tex] cation and [tex]S^{2-}[/tex] is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral [tex]MgS[/tex]. Also [tex]Mg^{2+}[/tex] cation and [tex]Br^{-}[/tex] can combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral [tex]MgBr_2[/tex].
Also Vanadium is having an oxidation state of +5 called as [tex]V^{5+}[/tex] cation and [tex]S^{2-}[/tex] is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral [tex]V_2S_5[/tex]. Also [tex]V^{5+}[/tex] cation and [tex]Br^{-}[/tex] anion can combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral [tex]VBr_5[/tex].
The mass of a dust particle would be measured in?
An analytical chemist is titrating of a solution of ethylamine with a solution of . The of ethylamine is . Calculate the pH of the base solution after the chemist has added of the solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of solution added. g
Answer:
pH=11.
Explanation:
Hello!
In this case, since the data is not given, it is possible to use a similar problem like:
"An analytical chemist is titrating 185.0 mL of a 0.7500 M solution of ethylamine(C2HNH2) with a 0.4800 M solution of HNO3.ThepK,of ethylamine is 3.19. Calculate the pH of the base solution after the chemist has added 114.4 mL of the HNO3 solution to it"
Thus, for the reaction:
[tex]C_2H_5NH_2+H^+\rightleftharpoons C_2H_5NH_4^+[/tex]
Tt is possible to compute the remaining moles of ethylamine via the following subtraction:
[tex]n_{ethylamine}=0.1850L*0.7500mol/L=0.1365mol\\\\n_{acid}=0.1144L*0.4800mol/L=0.0549mol\\\\n_{ethylamine}^{remaining}=0.1365mol-0.0549mol=0.0816mol[/tex]
Thus, the concentration of ethylamine in solution is:
[tex][ethylamine]=\frac{0.0816mol}{0.1850L+0.1144L}=0.2725M[/tex]
Now, we can also infer that some salt is formed, and has the following concentration:
[tex][salt]=\frac{0.0549mol}{0.1850L+0.1144L}=0.1834M[/tex]
Therefore, we can use the Henderson-Hasselbach equation to compute the resulting pOH first:
[tex]pOH=pKb+log(\frac{[salt]}{[base]} )\\\\pOH=3.19+log(\frac{0.1834M}{0.2725M})\\\\pOH=3.0[/tex]
Finally, the pH turns out to be:
[tex]pH=14-pOH=14-3\\\\pH=11[/tex]
NOTE: keep in mind that if you have different values, you can just change them and follow the very same process here.
Best regards!
chemical formula for calculating pressure
Answer:
First, let's review the ideal gas law, PV = nRT. In this equation, 'P' is the pressure in atmospheres, 'V' is the volumes in liters, 'N' is the number of particles in moles, 'T' is the temperature in Kelvin and 'R' is the ideal gas constant (0.0821 liter atmosphere per moles Kelvin).
Explanation:
I majored in Chemistry
help me plss it’s kinda easy but i’m not sure
Answer:
Sexual Reproduction
Explanation:
In Asexual Reproduction offsprings are know as ramets and many ramets are known as clowns. So, when two parents are involved genetic variations occur in offspring. Pollen possess male gamete (antherozoid/sperm) and ovule possess egg.
A part
Please someone help mee
Answer:
13.9kj/mol
Explanation:
[tex]h = 891 -(393.5 +2*241.8)=1768.1=13.9kj/mol[/tex]
2. How does an atom become an Ion
of nitrogen gas)?
How many grams of H2 are needed to produce 71.1 g of ammonia (NH3) (assuming unlimited availability
3 H2+ N2 + 2NH3
Provide the answer with 3 or more significant figures.
Answer:
[tex]m_{H_2}=12.6gH_2[/tex]
Explanation:
Hello there!
In this case, given the reaction:
[tex]3 H_2+ N_2 \rightarrow 2NH_3[/tex]
It is possible to compute the necessary grams of hydrogen which produce 71.1 g of ammonia, given the 3:2 mole ratio and their molar mass as shown below:
[tex]m_{H_2}=71.1gNH_3*\frac{1molNH_3}{17.04gNH_3}*\frac{3molH_2}{2molNH_3} *\frac{2.02gH_2}{1molH_2}\\\\m_{H_2}=12.6gH_2[/tex]
Best regards!
what is valence electron configuration for group 4A (14)
Answer:
The group 14 elements all have ns2np2 valence electron configurations. All form compounds in which they formally lose either the two np and the two ns valence electrons or just the two np valence electrons, giving a +4 or +2 oxidation state, respectively
Explanation:
Answer:
The group 14 elements all have ns2np2 valence electron configurations. All form compounds in which they formally lose either the two np and the two ns valence electrons or just the two np valence electrons, giving a +4 or +2 oxidation state, respectively.
Explanation:
A metal ion (X) with a charge of 4+ is attracted to non metal ion (Z) with a charge of 3-. Which of these formulas represents the resulting compound? I need answers asap please
Answer: [tex]X_3Z_4[/tex]
Explanation:
For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.
Here metal X is having an oxidation state of +4 called as [tex]X^{4+}[/tex] cation and [tex]Z^{3-}[/tex] is an anion with oxidation state of -3. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral [tex]X_3Z_4[/tex]
[tex]X_3Z_4[/tex] is the formula of the resulting compound.
P4 +502 — P4010
What is the limiting reactant if you are using 25.0 grams of phosphorus and 50.0 grams of oxygen?
A.) O2
B.) P4
C.) P4O10
D.) P4O2
Answer:
B.) P4
Explanation:
Step 1: Convert 25.0 grams of phosphorus into moles of phosphorous:
25 g P4 x 1 mol P4/123.90 g P4 = 0.202 mol P4
Step 2: Convert 0.202 mol P4 into moles of O2 using their stoichiometric ratios:
0.202 mol P4 x 5 mol O2/1 mol P4 = 1.01 mol O2
Step 3: Convert 1.01 mol O2 into grams of O2:
1.01 mol O2 x 31.98 g O2/1 mol O2 = 32.3 g O2
Because 25.0 grams of phosphorous only needs 32.3 grams of oxygen to react, phosphorous will be the limiting reactant, as after the 25.0 grams of phosphorous is used up, there will still be 17.7 grams of oxygen leftover (excess reactant).
Because the reaction cannot occur without more phosphorous to react with the 17.7 grams of oxygen remaining, P4 is the limiting reactant.
Answer: B.) P4
Explanation:
Step 1: Convert 25.0 grams of phosphorus into moles of phosphorous:25 g P4 x 1 mol P4/123.90 g P4 = 0.202 mol P4
Step 2: Convert 0.202 mol P4 into moles of O2 using their stoichiometric ratios:0.202 mol P4 x 5 mol O2/1 mol P4 = 1.01 mol O2
Step 3: Convert 1.01 mol O2 into grams of O2:1.01 mol O2 x 31.98 g O2/1 mol O2 = 32.3 g O2
Because 25.0 grams of phosphorous only needs 32.3 grams of oxygen to react, phosphorous will be the limiting reactant, as after the 25.0 grams of phosphorous is used up, there will still be 17.7 grams of oxygen leftover (excess reactant).
Because the reaction cannot occur without more phosphorous to react with the 17.7 grams of oxygen remaining, P4 is the limiting reactant.
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20 POINTS! NEED HELP!!!
When naming covalent bonds, do all of the following except?
1. use prefixes
2. write the left-most element first
3. add -ide to the end of the 2nd element
4. write the metal first
Answer:
number 2
Explanation:
even though i have never done this i still got it right
Because metals do not form covalent bonds, when naming covalent bonds, all the given rules apply except write the metal first; option 4.
What are covalent bonds?Covalent bonds are bonds formed by the sharing of valence electrons between the atoms involved in the bonding.
In naming covalent bonds, the following rules are applied:
Name the non-metal furthest to the left on the periodic table by its elemental name.Name the other non-metal by its elemental name and an -ide ending.Use the prefixes mono-, di-, tri-, tetra etc. to indicate the number of that element in the molecule.If the first prefix is mono, it is not written add -ide to the end of the second elementFor example, CO₂, is carbon dioxide.
Therefore, when naming covalent bonds, all the given rules apply except write the metal first because metals do not form covalent bonds.
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Can someone help with this one?
Draw the structures of organic compounds A and B. Indicate stereochemistry where applicable The starting material is ethyne, a carbon carbon triple bond where each carbon is bonded to a hydrogen. Step 1 is N a N H 2 followed by 1 equivalent of C H 3 C H 2 C H 2 B r to form compound A. Compound A reacts with hydrogen and lindlar's catalyst to form compound B. COmpound B reacts with H 2 O and H 3 O Plus to form a 5 carbon chain with a hydroxy substituent on carbon 2.
Answer:
See explanation below
Explanation:
In this case we have the starting reactant which is the ethine, In the first step reacts with NaNH₂, a strong base. This base will substract the hydrogen from one of the carbon of the ethine, and form a carbanion. This will react with the propane bromide, displacing the bromine and forming a 5 carbon chain with the triple bond on the carbon 1 and 2.
In the second step, reacts with the lindlar catalyst to do a reduction, and form a double bond between carbon 1 and 2. In essence, compound A is similar to compound B.
Finally B reacts with water in acid and makes a addition reaction, and form an alcohol.
The whole process can be seen in the picture below.
Hope this helps
