what odd 3 digit number has digits that are all the same and that add up to 9?​

The time spent by the repairman there will be 3 hours so the correct answer is option D.

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Given that:-

A roof repairman charges a $60 consult fee, and then $45 per hour to complete repairs. if the homeowner pays a total of $195.

The time will be calculated as:-

Total amount =  $195

Now the fixed consulting cost will be $60 and will be deducted from the

total amount.

Variable cost = 195 - 60 = 135

The $45 per hour charge so for $145 the time will be:-

Time = 135 / 45

Time =  3 Hours

Therefore the time spent by the repairman there will be 3 hours so the correct answer is option D.

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Answer:

Dimensions = 8 CM and 12 CM

length = 12 CM

width = 8 cm

perimeter = 2 ( length + width)

= 2( 12 + 8)

= 2 ( 20)

= 40 CM

ratio = 12/40

= 6/20

= 3/10

Answer:

  (a)  x = 12

Step-by-step explanation:

The radicals in this equation can be eliminated simply by squaring both sides. Then the resulting linear equation is solved in two steps.

__

  [tex]\left(\sqrt{2x-8}\right)^2=\left(\sqrt{x+4}\right)^2\\\\2x-8=x+4\qquad\text{simplify}\\\\x-8=4\qquad\text{subtract $x$}\\\\\boxed{x=12}\qquad\text{add 8}[/tex]

_____

Additional comment

You know the contents of each radical must not be negative. That means 2x-8 ≥ 0, or x≥4. We know x=4 doesn't work in the equation (0≠√8), so we only need to check the answers x=12 and x=7. Of those, only x=12 satisfies the equation.

Answer:

The answer is (-2,6)

Step-by-step explanation:

Answer: (-2, 6)

Step-by-step explanation:

An easy way to solve this is to plug in each answer into the system of inequalities to figure out with ordered pair adheres to the rules of both equation.

Let's use the first ordered pair as an example: (-3,4)

Is this true?:

4 > (-3)² +1

4 < (-3)² - (-3) + 1

No, it is not:

4 < 10

4 < 13

Let's try the second answer:

Is this true?:

6 > (-2)² + 1

6 < (-2)² -(-2) + 1

YES, it is!

6 > 5

6 < 7

(-2, 6) is your answer. To check, verify that the last two answer choices are wrong.

The image was formed by a reflection of the letter M would be image A in the second quadrant b the reflection on X-axis. The correct option is A.

When a graph is reflected along an axis, say x axis, then that leads the graph to go just in the opposite side of the axis as if we're seeing it in a mirror.

If you study it more, you will find that it's symmetric, thus each point is equidistant from the axis of reflection as that of the image of that point.

Thus, if you're reflecting a point (x,y) along the x-axis, then its x abscissa will stay the same but y coordinates will negate.

Thus (x,y) turns to (x, -y)

Similarly, if you're reflecting a point (x,y) along the y -axis, the resultant image of the point will be (-x,y).

The image was formed by a reflection of the letter M would be image A in the second quadrant b the reflection on X-axis. The correct option is A.

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The reflection of letter M is (A)

A figure is said to be a reflection of the other figure, then every point in a figure is at equidistant from each corresponding point in another figure.

According to the graph the reflection of Of letter M is with same coordinates but with x as positive and y as negative.

Hence the reflection is (A).

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A comparison of the actual number of people who violate the speed limit to the total number of drivers is an example of a rate

A rate is known as the quantity measured with respect to another measured quantity. It refers to the comparison of a part to a whole.

It is also the measure of a part with respect to a whole or a proportion.

Therefore, a comparison of the actual number of people who violate the speed limit to the total number of drivers is an example of a rate

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Answer: 48

Step-by-step explanation:

We need to find the least common multiple of 12 and 16.

Finding the prime factorizations of 12 and 16,

[tex]12=2^{2} \times 3\\\\16=2^{4}[/tex]

Thus, the least common multiple is [tex]2^{4} \times 3=\boxed{48}[/tex]

5[tex]\sqrt{3}[/tex]

Special right triangles, such as the one shown, have unique equations that can be used to find missing sides.

30-60-90 Triangles

The angle measurements show us that this is a 30-60-90 triangle. This name refers to the 3 angle measurement. There are 2 types of special right triangles, 45-45-90 and 30-60-90. For most triangles, it would take the law of sine or cosine to find a missing side with only 1 side given. But, with special right triangles, we can use shortcuts to find a.

Formulas

For all 30-60-90 triangles, there are 3 sides: the hypotenuse (c), the long leg (a), and the short leg (b). The shortcuts for 30-60-90 triangles are based on the length of the short leg.

The formulas are as follows (the variables match the variable given in the figure):

Solving for a

So, to find a, we must first find b. Since b is equal to half of c, we can divide the value of c by 2.

Thus, b = 5

Next, plug this value into the formula for b

Answer:

Last option

Step-by-step explanation:

cos30° = a/10  

a = 10cos30°

     [tex]cos30=0.8660=\frac{\sqrt{3} }{2}[/tex]

[tex]a=10(\frac{\sqrt{3} }{2} )=5\sqrt{3}[/tex]

Hope this helps

Answer: The first graph

Step-by-step explanation: A graph’s inverse will have all of their roots inverted as well. If you put the graph f(x)= 3x+3 into a graphing calculator, you’ll be able to see all the roots. From there, just invert (switch) the roots. Since on the original graph the most prominent roots are {(0,3), (-1,0),(-2,-3)}, you just need to invert those roots and find them ALL on one of the graphs, then you have your answer. So, the inverted roots will be {(3,0),(0,-1),(-3,-2)}.

Still, I find the simplest thing is to put them into a graphing calc like GeoGebra.

Answer:

1,3 is the answer... if you look down here↓:

Step-by-step explanation:

The length of AD is 5 units. so, option A is the correct answer.

The Pythagoras theorem states that the square of the longest side must be equal to the sum of the square of the other two sides in a right-angle triangle.

The length of DC is given as 13 units.

The length of AC is given as 12  units. We can see that angle D is a right angle, so the triangle will be a right-angle triangle.

by Pythagoras theorem;

[tex]DC ^2 = AD^2 + AC^2\\\\13^2 = AD^2 + 12^2\\\\AD^2 = 169 - 144\\\\AD^2 = 25\\\\AD = 5[/tex]

Hence, the length of AD is 5 units. so, option A is the correct answer.

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Answer:

ggggjgfdvhgffgutddfgj

The zeros of the quadratic function f(x) = 2x² + 16x - 9 are given as follows:

[tex]x = -4 + \sqrt{\frac{41}{2}}, x = -4 - \sqrt{\frac{41}{2}}[/tex]

A quadratic function is given according to the following rule:

[tex]y = ax^2 + bx + c[/tex]

The solutions are:

[tex]x_1 = \frac{-b + \sqrt{\Delta}}{2a}[/tex]

[tex]x_2 = \frac{-b - \sqrt{\Delta}}{2a}[/tex]

In which:

[tex]\Delta = b^2 - 4ac[/tex]

In this problem, the equation is given by:

f(x) = 2x² + 16x - 9.

The coefficients are a = 2, b = 16, c = -9, hence:

[tex]\Delta = 16^2 - 4(2)(-9) = 328[/tex]

Then:

[tex]x_1 = \frac{-16 + \sqrt{328}}{2(2)} = -4 + \sqrt{\frac{41}{2}}[/tex]

[tex]x_2 = \frac{-16 - \sqrt{328}}{2(2)} = -4 - \sqrt{\frac{41}{2}}[/tex]

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Answer:

the interest for 100 in 5 years us 12.5

The area of the water well is [tex]4\pi r^2[/tex]

The radius is given as:

Radius, R = 2r

The area of the water well is calculated using:

[tex]A = \pi R^2[/tex]

This gives

[tex]A = \pi (2r)^2\\\\\\[/tex]

Evaluate the expression

[tex]A = 4\pi r^2[/tex]

Hence, the area of the water well is [tex]4\pi r^2[/tex]

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Answer:

120°

Step-by-step explanation:

x = angle       supplement = 180-x

x = 4(180-x) -120

x = 720 -  4x - 120

5x = 600°

x =120°

it is a bracket used in maths

Answer:

They are kind of like outer brackets, so if you have some expression like this:

5 + (4 × 6 + (7 - 8)),

it's better to write it like this:

5 + [4 × 6 + (7 - 8)],

so you can read it more easily.

Answer:

A.) 132.3 mm Hg

B.) 49 years old

Step-by-step explanation:

[tex]P= 0.006y^{2} -0.01y+119[/tex]

P = blood pressure

y = age in years

A.) Solution

To find: P

Given: y = 48

[tex]P= 0.006y^{2} -0.01y+119[/tex]

P = 0.006 x 48 x 48 - 0.01 x 48 + 119

P = 0.006 x 2,304 - 0.48 + 119

P = 13.824 - 0.48 + 119

P = 132.344 ⇒ 132.3

B.) Solution

To find: y

Given: P = 132.92

[tex]P= 0.006y^{2} -0.01y+119[/tex]

[tex]132.92= 0.006y^{2} -0.01y+119[/tex]

[tex]0.006y^{2} -0.01y-13.92[/tex]

.......................................................

Answer: 49 years old

The number of cows and ducks in the garden are 3 and 4 respectively.

Let the numbers of cows be x and the number of ducks is y.

Total number of legs=20

Total number of eyes=14

Linear equation for the total number of legs in the garden,

4x+2y=20 -(1)

Linear equation for the total number of eyes in the garden,

2x+2y=14 -(2)

Solve the system of the two linear equations to find the values of x and y.

Subtract equation (1) from equation (2), and we get,

2x=6

[tex]x=\frac{6}{2}\\[/tex]

x=3

Substitute the value of x in equation (1), and we get,

4(3)+2y=20

12+2y=20

2y=20-12

2y=8

[tex]y=\frac{8}{2}\\[/tex]

y=4

Number of cows=3

Number of ducks=4

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Answer:

hes a titan

Step-by-step explanation:

Answer:

Common difference:  30

General term formula:   [tex]a_n=30n-9[/tex]

52nd term:  1551

Step-by-step explanation:

Given sequence:

21, 51, 81, 111

Calculate the difference in terms:

[tex]21 \underset{+30}{\longrightarrow} 51 \underset{+30}{\longrightarrow} 81 \underset{+30}{\longrightarrow} 111[/tex]

The sequence is increasing by 30 each time, so as there is a common difference, this is an arithmetic sequence with a common difference of 30.

General form of an arithmetic sequence

[tex]a_n=a+(n-1)d[/tex]

where:

Given:

Substitute the given values into the formula to find the general term formula:

[tex]\implies a_n=21+(n-1)30[/tex]

[tex]\implies a_n=21+30n-30[/tex]

[tex]\implies a_n=30n-9[/tex]

To find the 52nd term, simply substitute n = 52 into the found general term formula:

[tex]\implies a_{52}=30(52)-9[/tex]

[tex]\implies a_{52}=1560-9[/tex]

[tex]\implies a_{52}=1551[/tex]

Using translation concepts, it is found that the type of transformation that triangle X′Y′Z′ undergoes is a reflection over the x-axis.

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

From triangle X′Y′Z′ to triangle X′′Y′′Z′′, the rule is given by:

(x,y) -> (x, -y)

Hence the type of transformation that triangle X′Y′Z′ undergoes is a reflection over the x-axis.

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[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{d}{dx} ( {x}^{ \frac{3}{2} } )= \dfrac{3}{2} \sqrt{x} [/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{d}{dx} \bigg( \cfrac{1}{ {x}^{3} } \bigg)= \cfrac{- 3}{ {x}^{4} } [/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{d}{dx} \bigg( \cfrac{1}{ \sqrt{x}^{} } \bigg)= \cfrac{ - 1}{ 2\sqrt{{x}^{ { 3}{} } }} [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

properties to be used here :

[tex]\qquad \tt \rightarrow \:\cfrac{d}{dx}( {x}^{ n } ) = n \sdot{x}^{n - 1} [/tex]

[tex]\large \textsf{Question : 1} [/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{d}{dx} ( {x}^{ \frac{3}{2} } )[/tex]

[tex]\qquad \tt \rightarrow \:y = \dfrac{3}{2} x { }^{ \frac{3}{2} - 1 } [/tex]

[tex]\qquad \tt \rightarrow \:y = \dfrac{3}{2} x { }^{ \frac{3 - 2}{2} } [/tex]

[tex]\qquad \tt \rightarrow \:y = \dfrac{3}{2} x { }^{ \frac{1}{2} } [/tex]

[tex]\qquad \tt \rightarrow \:y = \dfrac{3}{2} \sqrt{x} [/tex]

[tex]\large \textsf{Question : 2} [/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{d}{dx} \bigg( \cfrac{1}{ {x}^{3} } \bigg)[/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{d}{dx} ({ {x}^{ - 3} } )[/tex]

[tex]\qquad \tt \rightarrow \:y = - 3 { {x}^{ - 3 - 1} } [/tex]

[tex]\qquad \tt \rightarrow \:y = - 3 { {x}^{ - 4} } [/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{- 3}{ {x}^{4} } [/tex]

[tex]\large \textsf{Question : 3} [/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{d}{dx} \bigg( \cfrac{1}{ \sqrt{x}^{} } \bigg)[/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{d}{dx} \bigg( \cfrac{1}{{x}^{ \frac{1}{2} } } \bigg)[/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{d}{dx} ({ {x}^{ - \frac{1}{2} } } )[/tex]

[tex]\qquad \tt \rightarrow \:y = -\cfrac{1}{2} { {x}^{ - \frac{1}{2} - 1} } [/tex]

[tex]\qquad \tt \rightarrow \:y = -\cfrac{1}{2} { {x}^{ \frac{ - 1 - 2}{2} } } [/tex]

[tex]\qquad \tt \rightarrow \:y = -\cfrac{1}{2} { {x}^{ \frac{ - 3}{2} } } [/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{ - 1}{ 2{x}^{ \frac{ 3}{2} } } [/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{ - 1}{ 2\sqrt{{x}^{ { 3}{} } }} [/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

It has a period of 2pi

the equation to find the period of a sin/cos function is

[tex]period = \frac{2\pi}{b} [/tex]

y = -2 sin(x) has a normal period of 2pi because the b value in this equation isn't stated, making it equal to 1

the basic equation for a sin function is

[tex]y = a \: \sin(b(x - c) ) + d[/tex]

Answer:

x = 2, y = 1 or (2, 1)

Step-by-step explanation:

Solving by elimination method :

The solution is : x = 2, y = 1 or (2, 1)