what mass of potassium chlorate should be required to produce 113 L of oxygen O2. measured at STP g

D is your answer correct.

The circulatory system carries carbon dioxide away from cells and respiratory system removes from the body. The correct option is D.

A group of organs that cooperate to carry out one or more functions is known as an organ system in biology. Each organ in a plant or animal body is composed of certain tissues and serves a specific purpose.

They can aid in gas exchange, waste removal, nutrient acquisition and transportation, illness sensing, and disease protection for the body.

The superior vena cava and the inferior vena cava are two significant veins that carry oxygen-poor, carbon dioxide-rich blood back to the right side of the heart.

The blood is then transported to the lungs via the pulmonary artery, where it absorbs oxygen and exhales carbon dioxide.

Thus, the correct option is D.

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Answer:

thank you for asking question

Answer:

correct the answer below is correct !!

Explanation:

Answer:

the answer is seperate

Explanation:

Stoichiometry is the study of chemical reactions that to calculate the number of mole that are used in the reactant and product of the particles.

Stoichiometry is the system of chemistry which is responsible to keep the data or information about the amount of reactant and the products which are taking part in a chemical reaction.

Balancing of any chemical equation is the main part of it by comparing the atom used as reactant and the number of atom used as a product. basically it signifies the relationship between the reactant and product.

It is only the quantitative analysis of the reaction not the qualitative one.

Therefore, stoichiometry is the study of chemical reactions that to calculate the number of mole that are used in the reactant and product of the particles.

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Answer:    C hope this helps Have a wonderful day :)    

Explanation:

Answer:

Elements in the same period have the same number of valence electrons as each other.

Answer:

12.044  × 10²³ atoms of oxygen

Explanation:

Given data:

Number of atoms of oxygen = ?

Moles of oxygen = 2 mol

Solution:

Avogadro number:

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms of oxygen

2 mole × 6.022 × 10²³ atoms of oxygen / 1 mole

12.044  × 10²³ atoms of oxygen

Answer:

[tex]M_2=3.34x10^{-3}M[/tex]

Explanation:

Hello!

In this case, since a dilution process implies that the moles of the solute remain the same before and after the addition of diluting water, we can write:

[tex]M_1V_1=M_2V_2[/tex]

Thus, since we know the volume and concentration of the initial sample, we compute the resulting concentration as shown below:

[tex]M_2=\frac{M_2V_2}{V_1} =\frac{45.45mL*0.0404M}{550.00mL}\\\\M_2=3.34x10^{-3}M[/tex]

Best regards!

Answer: 38 chlorine atoms are in 3 molecules of HCI

Explanation:

Answer:

2.70 g of glucose.

Explanation:

The following data were obtained from the question:

Molarity of the glucose solution = 0.1 M

Volume of solution = 0.15 L

Molar mass of glucose = 180.16 g/mol

Mass of glucose =.?

Next, we shall determine the number of mole of glucose in the solution. This can be obtained as follow:

Molarity of the glucose solution = 0.1 M

Volume of solution = 0.15 L

Mole glucose =?

Molarity = mole /Volume

0.1 = Mole of glucose /0.15

Cross multiply

Mole of glucose = 0.1 × 0.15

Mole of glucose = 0.015 mole

Finally, we shall determine the mass of glucose in the solution as follow:

Mole of glucose = 0.015 mole

Molar mass of glucose = 180.16 g/mol

Mass of glucose =.?

Mole = mass /molar mass

0.015 = mass of glucose /180.16

Cross multiply

Mass of glucose = 0.015 × 180.16

Mass of glucose = 2.70 g

Therefore, the solution contains 2.70 g of glucose.

The grams that the solution must contain is :

- 2.70 g of glucose.

Given:

Molarity of the glucose solution = 0.1 M

Volume of solution = 0.15 L

Molar mass of glucose = 180.16 g/mole

Molarity of the glucose solution = 0.1 M

Volume of solution = 0.15 L

Molarity = mole /Volume

0.1 = Mole of glucose /0.15

Mole of glucose = 0.1 × 0.15

Mole of glucose = 0.015 mole

Mole of glucose = 0.015 mole

Molar mass of glucose = 180.16 g/mol

Mass of glucose =.?

Mole = mass /molar mass

0.015 = mass of glucose /180.16

Mass of glucose = 0.015 × 180.16

Mass of glucose = 2.70 g

The solution contains 2.70 g of glucose.

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Answer:

d

Explanation:

Answer:

it is 50%

Explanation:

62.9x50=3145

64.9x50=3245

3245+3145=6390

6390/100=63.9

Answer:

its hydroxy and alkoxy

Explanation:

ester is mainly formed by substitution reaction of carboxylic acid and alcohol

The esters are generally produced as a result of the reaction called esterification. They are generally derived from carboxylic acids. The functional group present in ester is OR. The correct option is E.

The chemical compounds which are derived from an acid either organic or inorganic in which at least -OH ( hydroxyl group ) is replaced by an -O- alkyl group ( alkoxy ) group are called esters. Generally an ester can be represented as R - C = O - OR.

The chemical compounds that are formed by the reaction of an acid and alcohol by losing water molecule can be defined as the esters.

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Answer:

24.5872 meters per second

Rouned 24.6 or 25

Answer:

23 Sandwiches

6 slices of bread

0 slices of cheese

Explanation:

brainliest pls:)

Answer:

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Explanation:

Explanation:

I DONT UNDERSTAND WHAT U WANT TO SAY

Answer: 4,000 grams of NaCI

Explanation:

We know that there are 400g of NaCI in one drop.

This bottle has 10 drops of this item.

So, we have to multiply the amount of NaCI in a drop by the amount of drops.

400 x 10 = 4,000.

The answer to the question is 4,000. Hope this helps!

Answer:

-114kJ mol-1

Explanation:

Definition of the enthalpy change of neutralization: the energy released with the formation of 1 mole of water when neutralization takes place between an acid and a base.

Since both reactions yield the same number of moles of water, the answer should be -114kJ mol-1.

The statement for the enthalpy change of reaction 2 is "-114 kJ"

The change in enthalpy (ΔH) is a quantity of heat of a system. The enthalpy change is the amount of heat that enters or exits a system during a reaction.

One equivalent of hydrogen ions is neutralised with one equivalent of hydroxide ions in the reaction 1,

NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)

The change in enthalpy is given as -114 kJ.

Two equivalents of hydrogen ions are neutralised with two equivalents of hydroxide ions in the reaction 2,

Ba(OH)2 + H2SO4 (aq) → BaSO4 (s) + 2H2O (l)

But, that primary ionic reaction is same for both the reaction in which hydrogen ion combines with hydroxide ion to generate a water molecule. So, the enthalpy change of reaction 1 would be exactly same as for reaction 2.

The neutralization enthalpy comes out to be -114 kJ.

Hence the correct answer is -114 kJ.

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Answer:

the median i think it is 6.5

CO₂ produced : 11.92 moles

Reaction

2C₂H₆ (g)+7O₂ (g) ⇒4CO₂ (g)+6H₂O(g)

mol ratio C₂H₆ : CO₂ = 2 : 4

moles of CO₂ :

[tex]\tt \dfrac{4}{2}\times 5.95=11.92~moles[/tex]

Answer:

The answer is 4.31 × 10²³ C atoms

Explanation:

The number of C atoms can be found by using the formula

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 0.716 × 6.02 × 10²³

We have the final answer as

Hope this helps you

Answer:

3.64g

Explanation:

Given parameters:

Mass of NH₃  = 18.1g

Mass of Cu₂O  = 90.4g

Unknown:

Limiting reactant  = ?

Mass of N₂ formed  = ?

Solution:

The reaction equation is given as:

       Cu₂O + 2NH₃ → 6Cu + N₂ + 3H₂O

The limiting reactant is the one in short supply in the reaction. Let us find the number of moles of the given species;

  Number of moles = [tex]\frac{mass}{molar mass}[/tex]  

Molar mass of Cu₂O = 2(63.6) + 16  = 143.2g/mol

Molar mass of NH₃  = 14 + 3(1) = 17g/mol

Number of moles of Cu₂O = [tex]\frac{18.1}{143.2}[/tex]   = 0.13moles

Number of moles of NH₃   = [tex]\frac{90.4}{17}[/tex]   = 5.32moles

  From this reaction;

       1 mole of  Cu₂O combines with 2 mole of NH₃

So   0.13moles of  Cu₂O will combine with 0.13 x 2 mole of NH₃

                                              = 0.26moles of NH₃

Therefore, Cu₂O is the limiting reactant. Ammonia is in excess;

Mass of N₂;

   Mass = number of moles x molar mass

    1 mole of Cu₂O  will produce 1 mole of N₂

    0.13 mole of Cu₂O  will produce 0.13 mole of N₂

    Mass  = 0.13 x (2 x 14) = 3.64g

Answer:

4 moles

Explanation:

The formula of finding moles is

moles = mass / molar mass, therefore

moles = 160 g / 40 g/mol = 4 moles

if you just look up the answer it comes up btw!!

have a great day

Answer:

-306j

Explanation:

For this question we define an equation:

W = -Pext(Vj-Vi)-----> eqn 1

P = 6atm

Vi = 285 ml

We convert it to litre

= 285/1000 mL

= 0.285 L

Vj = 789 mL

When converted to litre

= 789/1000 mL

= 0.789 L

These values are all going to be put values in the eqn 2 above

W = -Pext(Vj-Vi)

W = -6.0x (0.789L - 0.285L)

W = -3.024

W = -3.024 x 101.33 J

This gives us the answer

W = -306 J

Thank you!

Answer: -306 J

Answer:

Mass of CO₂ produced = 20.328 g

Oxygen is limiting reagent.

Explanation:

Given data:

Mass of C₂H₂ = 13.7 g

Mass of O₂ = 18.5 g

Mass of CO₂ produced = ?

What is limiting reagent = ?

Solution:

Chemical equation:

2C₂H₂ + 5O₂      →     4CO₂ + 2H₂O

Number of moles of C₂H₂:

Number of moles = mass /molar mass

Number of moles = 13.7 g/ 26.04 g/mol

Number of moles = 0.526 mol

Number of moles of O₂:

Number of moles = mass /molar mass

Number of moles = 18.5 g/ 32 g/mol

Number of moles = 0.578 mol

Now we will compare the moles of CO₂ with C₂H₂ and O₂

                      C₂H₂              :                CO₂

                           2                :                 4

                       0.526            :              4/2×0.526 = 1.052

                      O₂                  :                   CO₂

                        5                   :                     4

                      0.578             :                4/5×0.578 = 0.462

The number of moles of  CO₂ produced by O₂  are less thus oxygen will be limiting reactant.

Mass of CO₂ produced:

Mass = number of moles × molar mass

Mass = 0.462 mol × 44 g/mol

Mass = 20.328 g

Answer:

no one additions exceed the capacity of the buffer

Explanation:

given

Volume buffer = 500.0 mL = 0.5 L

mol HNO₂ = 0.5 L × 0.100 mol/L = 0.05 mol HNO₂

mol NO₂⁻ = 0.5 L × 0.150 mol/L = 0.075 mol NO₂⁻

solution

we know when any base more than 0.05 (HNO2) than exceed buffer capacity

and when any base more than 0.075 (KNO2) than exceed buffer capacity

when we add 250 mg NaOH (0.250 g)

than molar mass NaOH =40 g/mol

and mol NaOH = 0.250 g ÷ 40g/mol

mol NaOH  = 0.00625 mol

0.00625 mol NaOH will be neutralized by 0.00625 mol HNO₂

so it would not exceed the capacity of the buffer.

and

when we add 350 mg KOH (0.350 g)

than molar mass KOH =56.10 g

and mol KOH = 0.350 g ÷ 56.10 g/mol

mol KOH = 0.0062 mol

here also capacity of the buffer will not be exceeded

and

now we  add 1.25 g HBr

than molar mass HBr = 80.91 g/mol

and mol HBr = 1.25 g  ÷ 80.91 g/mol

mol HBr = 0.015 mol

0.015 mol Hbr will neutralize 0.015 mol NO₂⁻  

so the capacity will not be exceeded.

and

we add 1.35 g HI  

molar mass HI = 127.91 g/mol

so mol HI = 1.35 g ÷ 127.91 g/mol

mol HI = 0.011 mol

capacity of the buffer will not be exceed