What is the value of (Negative one-half)–4?
A) -16
B) Negative StartFraction 1 Over 16 EndFraction
C) StartFraction 1 Over 16 EndFraction
D) 16

Answers

Answer 1

Answer:

It would be 16!!!

Answer 2

The value of the exponent numerical expression (-1/2)⁻⁴ will be 16. Then the correct option is D.

What is the value of the expression?

When the relevant components and basic processes of a numerical method are given values, the expression's result is the result of the computation it depicts.

The definition of simplicity is making something simpler to achieve or grasp while also making it a little less difficult.

The expression is given below.

⇒ (-1/2)⁻⁴

Simplify the equation, then we have

⇒ (-1/2)⁻⁴

⇒ (-2)⁴

⇒ -2⁴

⇒ 16

The value of the exponent numerical expression (-1/2)⁻⁴ will be 16. Then the correct option is D.

More about the value of the expression link is given below.

https://brainly.com/question/23671908

#SPJ6


Related Questions

please help me... I'm confused​

Answers

Answer:

a=5

b=15

Step-by-step explanation:

By following the pattern on the table we can see that the x is increasing by 1 and the y is increasing by 3 each time. Therefore, the next set of numbers would be (5,15).

Savings accounts are a reliable way to store money for the future

Answers

True, this is because it is

Answer:

true

Step-by-step explanation:

just took test

Find the length of Line segment A C . Use that length to find the length of Line segment C D . Triangle A B C is shown. A perpendicular bisector is drawn from point A to point C on side B D. Angle A B C is 30 degrees and angle A D C is 25 degrees. The length of A B is 10 centimeters. What is the length of Line segment C D? Round to the nearest tenth. 2.3 cm 4.0 cm 10.7 cm 18.6 cm

Answers

Answer:

10.7 CM

Step-by-step explanation:

Correct on Edge 2020

Answer:

answer is C  10.7 cm

Step-by-step explanation:

got it right on edg 2020-2021

What's 2|–9| – |–2|?

Answers

Answer:

Step-by-step explanation:    AS YOU KHOW THW ABSOLUTE VALUE OF A QUESTION IS NUMBER ITSELF IF THERE IS MINUS SIGH THEN THE  SIGH OF A NUMBER WILL BECOME PLUS OR IF THERE IS A PLUS SIGH THEN THERE IT WILL REMAIN AS IT IS. IF THERE IS NO NUMBER WITH THE MINUS SIGH THEN THE MINUS SIGH WILL REAMIN AS IT IS.

+2 +9  -   +2

The answer has same sigh, then Plus answer will you get is

+11 - 2 then you will minus the answer will be

+9

HOPE IT HELP YOU

How to find a vertical asymptote

Answers

Answer:

Step-by-step explanation:

Generally's rational functions that have vertical asymptotes, even trig functions (which, like the tangent function, are often rational).

If the given function is the ratio of two functions, polynomial or otherwise, the graph of the given function has an asymptote at any x value for which the denominator is zero.  Example:  y = tan x = (sin x) / (cos x) has vertical asysmptotes at π/2, 3π/2, and so on, because the denominator cos x is zero for those angles.

Susan designed a circular pool with diameter of 25 meters. What is the area of the bottom of the pool?

Answers

Answer: Area = 490.87  meters

Step-by-step explanation:

A=πr2

r = 12.5 (1/2 of diameter)

A = 490.87  meters

Step-by-step explanation:

We know that the formula to find the area of a circle is πr^2 or in other words, pi times the radius squared. We have been given the diamter of 25 inches. We know that the diamater is double the radius. 25 divided by 2 will get us 12.5. If we write this in equation form (or substitute the variables) will be written as: (3.14)12.5^2, 3.14 being pi. Now, we would multiply the radius by radius (because it's squared) or in other words, (12.5*12.5) to equal 156.25. If we write this in equation form, we would get: 3.14(156.25). Now we finally multiply pi (3.14) times 156.25 to equal 490.625 or rounded to the tenth 490.6

The cost of producing x soccer balls in thousands of dollars is represented by h(x) = 5x + 6. The revenue is represented by k(x)
= 9x - 2. Which expression represents the profit, (k-h(x), of producing soccer balls?​

Answers

Answer:

4x - 8

Step-by-step explanation:

k - H(x)

(9x -2) - (5x + 6)

4x -8

If 4/3 * 3/4 = 5k, then k =

Answers

Answer:

1/5

Step-by-step explanation:

switch sides, delete both common factors and your stuck with 5k=1. then you put both in a fraction and it gets you 1/5

Solve 2x - 11 = k for x.

Answers

2x + -11 = k

Reorder the terms:
-11 + 2x = k

Solving
-11 + 2x = k

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 11 + 2x = 11 + k

Combine like terms: -11 + 11 = 0
0 + 2x = 11 + k
2x = 11 + k

Divide each side by '2'.
x = 5.5 + 0.5k

Simplifying

The mean of 6 numbers is 32.If one of the numbers is excluded, the mean reduces by 2.Find the excluded number.

Answers

Answer:

42

Step-by-step explanation:

Mean = Sum of numbers/ Total numbers

Sum of 6 numbers = 32 x 6

= 192

If one number is excluded the mean reduce by 2 . so it becomes 30

Sum of 5 Numbers = 5 x 30

=150

Therefore the excluded number is

= 192 - 150

= 42.

Two number cubes are rolled for two separate events:


Event A is the event that the sum of numbers on both cubes is less than 10.

Event B is the event that the sum of numbers on both cubes is a multiple of 3.

Complete the conditional probability formula for event B given that event A occurs first by writing A and B in the blanks:

P ( _a0 | _a1) = P ( _a2 ∩ _ a3)
___________
P ( _a4)

Answers

Answer:  [tex]\bold{P(B|A)=\dfrac{P(B\cap A)}{P(A)}=\dfrac{11}{30}}[/tex]

Step-by-step explanation:

The probability of Event B given Event A = the intersection of Event A and B divided by the probability of Event A. (see below for the symbols)

[tex]P(B|A)=\dfrac{P(B\cap A)}{P(A)}[/tex]

P(A) = (1, 6), (1, 5), (1, 4), (1, 3), (1, 2), (1, 1)

          (2, 6), (2, 5), (2, 4), (2, 3), (2, 2), (2, 1)

          (3, 6), (3, 5), (3, 4), (3, 3), (3, 2), (3, 1)

                    (4, 5), (4, 4), (4, 3), (4, 2), (4, 1)

                              (5, 4), (5, 3), (5, 2), (5, 1)

                                        (6, 3), (6, 2), (6, 1)

       = 30

P(B) = (1, 2), (2, 1)                                   sum = 3

          (1, 5), (2, 4), (3, 3), (4, 2), (5, 1)    sum = 6

          (3, 6), (4, 5), (5, 4), (5, 4), (6, 3)  sum = 9

          (6, 6)                                           sum = 12

                       

      = 12

P(A ∩ B) =  (1, 2), (2, 1)

                  (1, 5), (2, 4), (3, 3), (4, 2), (5, 1)

                  (3, 6), (4, 5), (5, 4), (5, 4), (6, 3)

             = 11

Brian invests £6300 into his bank account.

He receives 4.9% per year compound interest.

How much will Brian have after 2 years?

Give your answer to the nearest penny where appropriate.

Answers

Answer:

Amount that Brian has after 2 years = £6932.53

Step-by-step explanation:

To find, the amount that Brian will have after 2 years:

Formula for amount where compound interest is applicable:

[tex]A = P \times (1+\dfrac{R}{100})^t[/tex]

Where A is the amount after t years time

P is the principal.

R is the rate of interest.

In the question, we are given the following details:

Principal amount,P = £6300

Rate of interest,R = 4.9%

Time,t = 2 years

Putting the values in formula:

[tex]A = 6300 \times (1+\dfrac{4.9}{100})^2\\\Rightarrow 6300 \times (\dfrac{104.9}{100})^2\\\Rightarrow 6932.53[/tex]

Hence, Amount that Brian has after 2 years = £6932.53

Answer:

THE ANSWER IS ABOVE

Step-by-step explanation:

hahahaha

In a class of 20 students 11 people have a brother 9 people have a sister 6 people have neither fill in the Venn diagram

Answers

Answer:

Draw a Venn diagram with the left circle labeled brother, and the right labeled sister. Label the middle both and fhe outisde neither. Put 5 in brother, 3 in sister, 6 in both and 6 in neithrr.

Step-by-step explanation:

11+9 = 20

20-6 = 14

20-14=6

There are 6 that have both

please very soon I offer the crown !!! + 10 points urgently !!!

Answers

Answer:

a. 2 groups of 2 is 4

b. 3 groups of 2 is 6

c. 4 groups of 2 is 8

d. 5 groups of 2 is 10

e. 6 groups of 2 is 12

Answer:

a - 2

b- 3

c- 4 groups of 2 is 8

d- 5 groups of 2 is 10

e- 6 groups of 2 is 12

One vertex of a triangle is located at (0, 5) on a coordinate grid. After a transformation, the vertex is located at (5, 0). Which transformations could have taken place? Select two options. R0, 90° R0, 180° R0, 270° R0, –90° R0, –180°

Answers

Answer:

The Transformations are R(O , -90°) & R(O , 270)

Step-by-step explanation:

* Lets revise the rotation of a point

- If point (x , y) rotated about the origin by angle 90° anti-clock wise

∴ Its image is (-y , x)

- If point (x , y) rotated about the origin by angle 90° clock wise

 (270° anti-clockwise or -90°)

∴ Its image is (y , -x)

- If point (x , y) rotated about the origin by angle 180°

∴ Its image is (-x , -y)

* There is no difference between rotating 180° clockwise (-180°) or  

anti-clockwise (180°) around the origin

* Lets solve the problem

∵ One vertex of a triangle is located at (0, 5) on a coordinate grid

∵ The image of the point after the transformation is (5 , 0)

- The coordinates are switched with each other

∴ There is no rotation with 180° or -180° because in the rotation with

 180° and -180° around the origin we change only the signs of the

 coordinates without switch them

∴ There is a rotation with 90° are 270° or -90°

- The zero has no sign

- When we rotate the point (0 , 5) by -90° or 270° around the origin

 we will change the sign of x-coordinate and switch the two

 coordinates

∴ The image of the point is (y , -x)

∵ x = 0 and y = 5

- There is no sign for zero, so we switch the coordinates only

∴ The vertex is located at (5, 0)

∴ The Transformations are R(O , -90°) & R(O , 270)

Answer:

R(O , -90°) & R(O , 270)

Step-by-step explanation:

In the past, 35% of the students at ABC University were in the Business College, 35% of the students were in the Liberal Arts College, and 30% of the students were in the Education College. To see whether or not the proportions have changed, a sample of 300 students from the university was taken. Ninety of the sample students are in the Business College, 120 are in the Liberal Arts College, and 90 are in the Education College. This problem is an example of a a. Marascuilo procedure. b. multinomial population. c. z test for proportions. d. test for independence.

Answers

Answer:

The correct answer will be Option B (multinomial population).

Step-by-step explanation:

The population is considered as multinomial whether its information is prescriptive or corresponds to the set of discreet non-overlapping groups. The hypothesis again for fitness test besides multinomial distribution is that even though the approximately normal f I seem to be equivalent to the required number e I across each segment.Here, because we have been testing whether the sampling data matches the hypothesized proportions as mentioned, this is indeed a multinomial population issue (because there have been more least two generations).

Other given options are not connected to the given situation. So that Option B seems to be the perfect solution.

Is the function given by ​f(x)equalsleft brace Start 2 By 2 Matrix 1st Row 1st Column one fourth x plus 1 comma 2nd Column for x less than or equals 4 comma 2nd Row 1st Column 4 x minus 11 comma 2nd Column for x greater than 4 comma EndMatrix continuous at xequals4​? Why or why​ not? Choose the correct answer below. A. The given function is continuous at xequals4 because ModifyingBelow lim With x right arrow 4 f (x )does not exist. B. The given function is not continuous at xequals4 because ​f(4​) does not exist. C. The given function is continuous at xequals4 because the limit is 2. D. The given function is not continuous at xequals4 because ModifyingBelow lim With x right arrow 4 f (x )does not exist.

Answers

Answer:

C. The given function is continuous at x=4 because the limit is 2.

Step-by-step explanation:

Given the function:

[tex]f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right[/tex]

We are to determine if the function is continuous at x=4.

For a function to be continuous  at some value c in its domain:

f(c) must be defined.[tex]Lim_{x \to c}$ f(x)[/tex] must exist. [tex]f(c)=Lim_{x \to c}$ f(x)[/tex]

Now: at x=4

[tex]f(4)=\dfrac{1}{4}*4+1=2[/tex][tex]Lim_{x \to 4}f(x)=2[/tex]

Since the two values are the same, we say that f(x) is continuous at x=4.

The correct option is C.

To inspect manufacturing processes, companies typically examine samples of parts for deficiencies. One company that manufactures ballpoint pens selected samples of pens on each of days. The company recorded, for each sample of , the number of defective pens in the sample. Here are their data:

1, 1, 2, 2, 2, 2, 3, 5, 5, 6, 6, 6, 9, 11, 14, 15, 18

Required:
a. Which measures of central tendency do not exist for this data set?
b. Which measures of central tendency would be affected by the change?
c. Which of the following best describes the distribution of the original data?
d. Suppose that, starting with the original data set, the largest measurement were removed. Which measures of central tendency would be changed from those of the original data set?

Answers

Answer:

a. All measures exist

b. The Mean and the mode

c. Positively skewed

d. The mean and the median

Step-by-step explanation:

a. The frequencies of the data are;

1       2

2      4

3       1

5       2

6       3

9        1

11        1

14        1

15       1

18       1

The formula for mode is given as follows;

The mean = 108/17 = 6.35

The median of 1 1 2 2 2 2 3 5 5 6 6 6 9 11 14 15 18 = (n + 1)/2th term = 9th term  

∴ The median = 5

The mode = 3×Median - 2 × Mean = 15 - 2 × 6.35 = 2.29

Hence all exist

The answer is none theses measures

b. Whereby 18 is replaced by 39 the mean will be then be

(108 + 39 - 18)/17 = 7.59

The median, which is the 9th term remain the same;

Hence only the mean and mode will be affected

c. Since more values are concentrated on the left side of the data distribution, the distribution is positively skewed

d. The largest measurement = 18 the 17th term

Removal will give

Mean = (108 - 18)/16 = 5.625 Mean changes

Median = (16 + 1)/2 th term = 8.5th term = 5 The median remains the same

The mode = 3(Mean - Median) changes

Therefore, the mean and the median will be changed.

If a⊕ b= 1/a + 1/b , for what decimal value of a is a⊕ 0.2=10?

Answers

Answer:

0.2

Step-by-step explanation:

1/0.2 = 5

10-5 = 5

1/a = 5

a = 1/5

a = 0.2

Answer:1/5 or 0.2

Step-by-step explanation:

1/a+1/0.2=10

1/a+1/2/10=10

1/a=10/2=10

1/a+5=10

1/a=10-5

1/a=5

a=1/5 or 0.2

the sum of two rational numbers is 8 if one of the numbers is -5/6 find the other

Answers

Answer:53/6

Step-by-step explanation:

Let X be the other rational number

-5/6+X=8

Add 5/6 to both sides

-5/6+5/6+X=8+5/6

0+X= 53/6 (inverse property)

X=53/6. (Identity property)

how many real solutions does the equation x2 − 9 = 0 have?

Answers

Answer:

Zero

Step-by-step explanation:

Because when you replace x with a number and solve it it doesn't have the same answer as x2 − 9 = 0.

I hope this helped. I am sorry if you get this wrong.

The correct answer is 0

SOMEONE PLEASE HELP ME ASAP PLEASE!!!​

Answers

Answer:

105.12 ft^2

Step-by-step explanation:

Area of a rectangle: bh

In this case 8*10.... so area of the rectangle is 80

Area of a circle: pir^2

Half it for a semicircle.

so 1/2 pi r^2

radius is 4 cuz its half of 8.

so 1/2(3.14)(4^2)=(0.5)(3.14)(16)=25.12

Now add up 80+25.12

Total is 105.12

Hope I helped :)

The accompanying data represent the total travel tax (in dollars) for a 3-day business trip in 8 randomly selected cities A normal probability plot suggests the data could come from a population that is normally distributed. A boxplot indicates there are no outliers. Complete parts through below.
68.87 78.25 70.44 84.67 79.79 86.33 100.24 98.26
Click the icon to view the table of critical t-values.
a. Determine a point estimate for the population mean travel tax A point estimate for the population mean travel tax is $ 83.36. (Round to two decimal places as needed.)
b. Construct and interpret a 95% confidence interval for the mean tax paid for a three-day business trip.
Select the correct choice below and fill in the answer boxes to complete your choice. (Round to two decimal places as needed.)
A. The lower bound is $ and the upper bound is $. One can be % confident that all cities have a travel tax between these values.
B. The lower bound is $ and the upper bound is $ The travel tax is between these values for % of all cities.
C. The lower bound is $ and the upper bound is $ There is a % probability that the mean travel tax for all cities is between these values.
D. The lower bound is $ and the upper bound is One can be [95]% confident that the mean travel tax for all cities is between these values.
c. What would you recommend to a researcher who wants to increase the precision of the interval, but does not have access to additional data?
A. The researcher could decrease the level of confidence.
B. The researcher could decrease the sample standard deviation.
C. The researcher could increase the level of confidence.
D. The researcher could increase the sample mean

Answers

Answer:

Step-by-step explanation:

Given that:

68.87, 78.25, 70.44, 84.67, 79.79, 86.33, 100.24, 98.26

we calculate sample mean and standard deviation from given data

Sample Mean

[tex]\bar x = \frac{\sum (x)}{n} =\frac{666.85}{8} \\\\=83.35625[/tex]

Sample Variance

[tex]s^2= \frac{\sum (x- \bar x )^2}{n-1} \\\\=\frac{933.224787}{7} =133.317827[/tex]

sample standard deviation

[tex]s=\sqrt{s^2} \\=\sqrt{133.317827} \\ =11.546334[/tex]

95% CI for [tex]\mu[/tex] using t - dist

Sample mean = 83.35625

Sample standard deviation = 11.546334

Sample size = n = 8

Significance level = α = 1 - 0.95 = 0.05

Degrees of freedom for t - distribution

d-f = n - 1 = 7

Critical value

[tex]t_{\alpha 12, df}= t_{0.025, df=7}=2.365[/tex] ( from t - table , two tails, d.f =7)

Margin of Error

[tex]E = t_{\alpha 12, df}\times \frac{s_x}{\sqrt{n} } \\\\=2.365 \times \frac{11.546334}{\sqrt{8} } \\\\=2.365 \times 4.082246\\\\E=9.654512[/tex]

Limits of 95% Confidence Interval are given by:

Lower limit

[tex]\bar x - E = 83.35625-9.654512\\\\=73.701738\approx 73.702[/tex]

Upper Limit

[tex]= \bar x + E\\=83.35625+ 9.654512\\=93.010762 \approx 93.011[/tex]

95% Confidence interval is

[tex]\bar x \pm E = 83.35625 \pm 9.654512\\\\=(73.701738,93.010762)[/tex]

95% CI using t - dist (73.70 < μ < 93.01)

D. The lower bound is $ and the upper bound is One can be [95]% confident that the mean travel tax for all cities is between these values.

c.What would you recommend to a researcher who wants to increase the precision of the interval, but does not have access to additional data?

A. The researcher could decrease the level of confidence.

Solve for y
A)16
B)18
C)22
D) 30
Omg help me I need help, please help me I’m so nice and funny, I can make u laugh, help me freaks I’m big baller

Answers

Answer:

30

Step-by-step explanation:

It is an equalateral triangle

Seven students were surveyed on the number of hours of TV they watch each week. The results are shown below.
8, 12, 13, 15, 16, 17, 17
What is the mode of the data set?
7
14
15
17

Answers

the correct answer is 17

need help in b and c. show calculation pls.​

Answers

√(16 - x^2) is defined only for -4 ≤ x ≤ 4, and is continuous over this domain, so

[tex]\displaystyle\lim_{x\to-4^+}\sqrt{16-x^2}=\sqrt{16-(-4)^2}=0[/tex]

From the other side, the limit does not exist, because all x < -4 do not belong to the domain.

Taken together, the two-sided limit also does not exist.

A scale drawing of a rectangular painting has a scale factor of 1:4 which statements are true

Answers

Answer:

object have been reduced by a factor of 4 on paper or the drawing have been increased by a factor of 4 on land .

Step-by-step explanation:

What a scale factor of 1:4 means.

Simply it means that the reals size of the object on land have been reduced in the drawing in the paper.

Now for scale factor of 1:4 in particular it means that the object have been reduced by a factor of 4 on paper or the drawing have been increased by a factor of 4 on land .

Example if the drawing has measurements of 4 inches on paper, then on land it will be 16 inches

The probability that a member of a certain class of homeowners with liability and property coverage will file a liability claim is 0.04, and the probability that a member of this class will file a property claim is 0.10. The probability that a member of this class will file a liability claim but not a property claim is 0.01. Calculate the probability that a randomly selected member of this class of homeowners will not file a claim of either type.

Answers

Answer:

The probability that a randomly selected member of this class of homeowners will not file a claim of either type is 0.89.

Step-by-step explanation:

Denote the events as follows:

X = liability claim will be filled

Y = property claim will be filled

The information provided is:

P (X) = 0.04

P (Y) = 0.10

P (X ∩ Y') = 0.01

The probability that a randomly selected member of the class of homeowners will not file a claim of either type will be given by:

[tex]P[(X\cup Y)']=1-P(X\cup Y)=1-[P(X)+P(Y)-P(X\cap Y)][/tex]

According to the law of total probability:

[tex]P(B)=P(B\cap A)+P(B\cap A')[/tex]

Use the law of total probability to determine the value of P (X ∩ Y) as follows:

[tex]P(X)=P(X\cap Y)+P(X\cap Y')\\\\P(X\cap Y)=P(X)-P(X\cap Y')\\\\=0.04-0.01\\\\=0.03[/tex]

The value of P (X ∩ Y) is 0.03.

Compute the value of P (X ∪ Y) as follows:

[tex]P[(X\cup Y)']=1-P(X\cup Y)[/tex]

                   [tex]=1-[P(X)+P(Y)-P(X\cap Y)]\\\\=1-[0.04+0.10-0.03]\\\\=1-0.11\\\\=0.89[/tex]

Thus, the probability that a randomly selected member of this class of homeowners will not file a claim of either type is 0.89.

Lester worked 12 hours last week at the grocery store and earned $93.00. If he continues to earn the same hourly pay, how many additional hours must he work to earn another $62.00?
A. 9 hours
B. 10 hours
C. 11 hours
D. 8 hours

Answers

Answer:

8 hours

Step-by-step explanation:

We can use a ratio to solve

12 hours    x hours

----------   = ------------

93 dollars    62 dollars

Using cross products

12 * 62 = 93x

Divide each side by 93

12*62/93 = 93x/93

8 = x

8 hours

Barron's reported that the average number of weeks an individual is unemployed is 18.5 weeks. Assume that for the population of all unemployed individuals the population mean length of unemployment is 18.5 weeks and that the population standard deviation is 6 weeks. Suppose you would like to select a sample of 55 unemployed individuals for a follow-up study.
A) show the sampling distribution of x, the sample mean average for a sample of 50 unemployment individuals.B) What is the probability that a simple random sample of 50 unemployment individuals will provide a sample mean within one week of the population mean?C) What is the probability that a simple random sample of 50 unemployed individuals will provide a sample mean within a half week of the population mean?

Answers

Answer:

A) The sampling distribution for a sample size n=50 has a mean of 18.5 weeks and a standard deviation of 0.849.

B) P = 0.7616

C) P = 0.4441

Step-by-step explanation:

We assume that for the population of all unemployed individuals the population mean length of unemployment is 18.5 weeks and that the population standard deviation is 6 weeks.

A) We take a sample of size n=50.

The mean of the sampling distribution is equal to the population mean:

[tex]\mu_s=\mu=18.5[/tex]

The standard deviation of the sampling distribution is:

[tex]\sigma_s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{50}}=0.849[/tex]

B) We have to calculate the probability that the sampling distribution gives a value between one week from the mean. That is between 17.5 and 19.5 weeks.

We can calculate this with the z-scores:

[tex]z_1=\dfrac{X_1-\mu}{\sigma/\sqrt{n}}=\dfrac{17.5-18.5}{6/\sqrt{50}}=\dfrac{-1}{0.8485}=-1.179\\\\\\z_2=\dfrac{X_2-\mu}{\sigma/\sqrt{n}}=\dfrac{19.5-18.5}{6/\sqrt{50}}=\dfrac{1}{0.8485}=1.179[/tex]

The probability it then:

[tex]P(|X_s-\mu_s|<1)=P(|z|<1.179)=0.7616[/tex]

C) For half a week (between 18 and 19 weeks), we recalculate the z-scores and the probabilities:

[tex]z=\dfrac{X-\mu}{\sigma/\sqrt{n}}=\dfrac{18-18.5}{6/\sqrt{50}}=\dfrac{-0.5}{0.8485}=-0.589[/tex]

[tex]P(|X_s-\mu_s|<0.5)=P(|z|<0.589)=0.4441[/tex]

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