Answer:
3-methyl-2-butanone.
Explanation:
Hello there!
In this case, for these types of oxidation of secondary alcohols, due to the 2-butanol, it is possible for us to remember that the product is a ketone exhibiting a carbonyl (C=O) group as the product of the oxidation. In such a way, the reaction would be:
CH3 - CH - CH - CH3 -------> CH3 - C - CH - CH3
| | || |
OH CH3 O CH3
Therefore, the product would be 3-methyl-2-butanone.
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Methane (CH4) undergoes combustion. Which products form? please help will give brainliest if correct
Answer:
B. CO₂ and H₂O.
Explanation:
When any organic substance undergoes complete combustion, it produces carbon dioxide (CO₂) and water (H₂O).
In the case of methane, the balanced reaction is:
CH₄ + 2O₂ → CO₂ + 2H₂OWith the above information in mind the correct answer is option B. CO₂ and H₂O.
When the combustion is incomplete, carbon monoxide (CO) is produced as well.
Answer:
B. CO₂ and H₂O!
4. How many moles of NaOH(s) would be required to react with 1.90 g of Cu(NO3)2 (aq)
according to the balanced equation:
Cu(NO3)2(aq) + 2 NaOH(aq) → Cu(OH)2(s) + 2 NaNO3(aq)
Answer:
2.03 x 10⁻² mol NaOH
Explanation:
First step for these questions is to ensure the reaction is balanced, then use the periodic table to determine the molar mass for the reactant you are given. Use the ratio from the balanced equation and dimensional analysis to solve. See attached image
Based on the picture of the map, why does Buenos Aries have a higher ocean surface temperature than Cape Town even though they have the same latitude?
Which is composed of alkenes?
welding torch fuel
polystyrene cups
gasoline
synthesized dyes
Answer:
a. welding torch fuel
Answer:
welding torch fuel
Explanation:
Acetic acid has the molecular formula CH3COOH. How many atoms of oxygen are there in 60 grams of acetic acid?
Answer:
1.2046x10²⁴ atoms
Explanation:
First we convert 60 grams of acetic acid into moles of acetic acid, using its molar mass:
60 g ÷ 60 g/mol = 1 molThen we double the number of acetic acid moles, as there are two oxygen moles per acetic acid mole.
1 mol CH₃COOH * 2 = 2 mol OFinally we convert moles into number of atoms, using Avogadro's number:
2 mol O * 6.023x10²³ atoms/mol = 1.2046x10²⁴ atomsFamous people who talked about plastic water bottles
Why is it important for scientists to monitor meteors in the sky?
Answer:
Because You never know when a meteor will hit you.
Humans do things that can affect the
environment.
Tap the boxes to place an 'X'on examples
of ways humans can affect water resources.
Growing crops for
food
Building a garden
wall to prevent
erosion
Watering flowers
at night
Help me I’ll give you 10 or 5 points
Answer:
they cause animals home's to be destroyed
Explanation:
In solution, strong acids and bases ionize completely, but weak acids and bases ionize only partially.
Answer:
A weak acid is one that does not dissociate completely in solution; this means that a weak acid does not donate all of its hydrogen ions (H+) in a solution. ... Therefore, the concentration of H+ ions in a weak acid solution is always less than the concentration of the undissociated species, HA.
Explanation:
Hope it helps
FOLLOW MY ACCOUNT PLS PLS
How many moles of Mg(OH)2(aq) would be required to neutralize 6.0 mol HCl(aq)?
Answer:
[tex]3.0molMg(OH)_2[/tex]
Explanation:
Hello there!
In this case, for these types of acid-base neutralizations, it is crucial to firstly set up the chemical reaction taking place between the acid and the base; in this case HCl and Mg(OH)2 respectively, whose products are obtained by switching around the anions and cations as shown below:
[tex]HCl(aq)+Mg(OH)_2(aq)\rightarrow MgCl_2(aq)+H_2O(l)[/tex]
Which must be balanced to accurately predict the mole ratio on the reactants side:
[tex]2HCl(aq)+Mg(OH)_2(aq)\rightarrow MgCl_2(aq)+2H_2O(l)[/tex]
Whereas we can see a 2:1 mole ratio of the acid to the base; thus, the moles of Mg(OH) required for the neutralization of 6.0 moles of HCl turn out to be:
[tex]6.0molHCl*\frac{1molMg(OH)_2}{2molHCl} \\\\=3.0molMg(OH)_2[/tex]
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Complexes containing metals with d10 electron configurations are typically colorless because ________. Complexes containing metals with d10 electron configurations are typically colorless because ________. d electrons must be emitted by the complex in order for it to appear colored there are no d electrons to form bonds to ligands a complex must be charged to be colored there is no d electron that can be promoted via the absorption of visible light the empty d orbitals absorb all of the visible wavelengths
Answer:
there is no d electron that can be promoted via the absorption of visible light
Explanation:
One of the properties of transition elements is the possession of incompletely filled d orbitals. This property accounts for their unique colours.
The colours of transition metal compounds stem from d-d transition of electrons due to the presence of vacant d orbitals of appropriate energy to which electrons could be promoted.
For elements whose atoms have a d10 configuration, such vacant orbitals does not exist hence their compounds are not colored.
Sometimes, the colour of transition metal compounds stem from ligand to metal charge transfer(LMCT) for instance in KMnO4.
When 3.915 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 12.74 grams of CO2 and 3.913 grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 54.09 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon.
Answer: The empirical formula and the molecular formula of the hydrocarbon is [tex]C_2H_3[/tex] and [tex]C_4H_6[/tex] respectivley.
Explanation:
The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:
[tex]C_xH_y+O_2\rightarrow CO_2+H_2O[/tex]
where, 'x', 'y' are the subscripts of Carbon, hydrogen
We are given:
Mass of [tex]CO_2[/tex] = 12.74 g
Mass of [tex]H_2O[/tex]= 3.913 g
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
For calculating the mass of carbon:
In 44g of carbon dioxide, 12 g of carbon is contained.
So, in 12.74 g of carbon dioxide, =[tex]\frac{12}{44}\times 12.74=3.474g[/tex] of carbon will be contained.
For calculating the mass of hydrogen:
In 18g of water, 2 g of hydrogen is contained.
So, in 3.913 g of water, =[tex]\frac{2}{18}\times 3.913=0.435g[/tex] of hydrogen will be contained.
Mass of C = 3.474 g
Mass of H = 0.435 g
Step 1 : convert given masses into moles.
Moles of C =[tex] \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{3.474g}{12g/mole}=0.289moles[/tex]
Moles of H=[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.435g}{1g/mole}=0.435moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =[tex]\frac{0.289}{0.289}=1[/tex]
For H =[tex]\frac{0.435}{0.289}=1.5[/tex]
The ratio of C : H = 1: 1.5
The whole number ratio will be = 2: 3
Hence the empirical formula is [tex]C_2H_3[/tex].
The empirical weight of [tex]C_2H_3[/tex] = 2(12.01)+3(1.008)= 27.04 g.
The molecular weight = 54.09 g/mole
Now we have to calculate the molecular formula.
[tex]n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{54.09}{27.04}=2[/tex]
The molecular formula will be=[tex]2\times C_2H_3=C_4H_6[/tex]
Help I'm stuck
The scientific theory of evolution is accepted by scientists as a way to explain the
diversity of life on Earth. Which best describes the process of evolution?
1.Populations gradually change over time.
2.Populations change rapidly and then go extinct.
3.Populations go extinct and new species take their place.
4.Populations change into new species when the environment changes.
This fossil is of a species that no longer exists on Earth. What is this fossil evidence of?
Captionless Image
1.evolution
2.extinction
3.natural selection
4.overproduction
When gas molecules collide with other gas molecules or the walls of a container, does it affect their speed?
Answer:
Yes it does
Explanation:
an aluminum kettle weighs 1.05 kg how much heat and joules is required to increase the temperature of this kettle from 23° c to 99° c
Answer:
71820 J
Explanation:
From the question given above, the following data were obtained:
Mass (M) = 1.05 Kg
Initial Temperature (T₁) = 23 °C
Final temperature (T₂) = 99 °C
Heat (Q) required =?
Next, we shall determine the change in temperature. This can be obtained as follow:
Initial Temperature (T₁) = 23 °C
Final temperature (T₂) = 99 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 99 – 23
ΔT = 76 °C
Finally, we shall determine the heat required. This can be obtained as follow:
Mass (M) = 1.05 Kg
Change in temperature (ΔT) = 76 °C
Specific heat capacity (C) of aluminum = 900 J/KgºC
Heat (Q) required =?
Q = MCΔT
Q = 1.05 × 900 × 76
Q = 71820 J
Thus, 71820 J heat energy is required.
As NH4Cl dissolves in water, and cools the solution,
a. delta H is negative, and delta S is negative
b. delta H is positive, and delta S is negative
c. delta H is negative, and delta S is positive
d. delta H is positive, and delta S is positive
Answer:
D. delta H is positive, and delta S is positive
went to the creamery and got a malted milkshake. What type of carbohydrate did I eat?
what is the method of seperating inmisible liquid
Which contains more reducing sugars, apple or cheese?
Answer:
An apple.
Explanation:
Hope this helps.
HELP ME PLEASE ITS DUE TODAY
Answer:
Explanation:
S2Si
O2
C2H4
N2
CBr4
S2
I think these are correct
Choose the appropriate electron configuration for an element that has electrons in six orbitals.
Group of answer choices
1s2 2s2 2p6 3s2 3p6
1s2 2s2 2p6 3s2 3p4
1s2 2s2 2p6 3s1
1s2 2s2 2p5
Answer:
pagtoon og imo dotsExplanation:
pagtoon og imo dotsWhat is the Electron Center Geometry of a CH3 carbon.
Answer:
tetrahedral geometry
CHCH2O- CH2CH3Explanation:
There are several centers of interest. Each carbon with all single bonds is the center of a tetrahedral geometry.
If 175.6 joules of energy are applied to a sample of Aluminum and its temperature changed by 35.4 degrees then what was the weight of the Aluminum sample?
Answer:
5.51g
Explanation:
Using the following formula:
Q = m × c × ∆T
Where;
Q = amount of heat in Joules
m = mass/weight of Aluminum
c = specific heat of Aluminum (0.900 J/g°C)
∆T = change in temperature.
Based on the information given in this question, Q = 175.6 joules, ∆T = 35.4°C, c = 0.900 J/g°C.
Using, Q = m × c × ∆T
175.6 = m × 0.900 × 35.4
175.6 = 31.86m
m = 175.6/31.86
m = 5.51g
The weight of the aluminum sample is 5.51g.
Formula for the compound Tetraoxygen nonabromide?
Answer:
O4Br9
Explanation:
Tetra means 4 and nona means 9. Just use these prefixes to decide how many of each element you have.
True or Fase. Every substance has to be classified as either acid or base?
Answer:
False
Explanation:
Some substances don't have to be
Give the systematic (IUPAC) names for these molecules. This molecule has the condensed formula C H 3 C H 2 C O O (C 6 H 5). C 6 H 5 is a benzene ring. IUPAC name: phenyl propanoate This molecule has the condensed formula C H 3 O C O C H 2 C H 2 C H (C H 3) 2. IUPAC name:
Answer:
The IUPAC name of the given compound is - Methyl - 4 - methylpentanoate
Explanation:
IUPAC name of the compound helps to determine the correct structure of the compound which can be used universally in order to avoid any confusion or misinterpretation.
[tex]CH_3CH_2COO(C_6H_5)[/tex]
The IUPAC name of the given compound is - phenyl propanoate.
[tex]CH_3OCOCH_2CH_2CH(CH_3)_2[/tex]
The IUPAC name of the given compound is - Methyl - 4 - methylpentanoate.
with a well labeled diagram explain the stages of meiosis and mitosis
Answer:
hope that helps
A 17.11 gram sample of an organic compound containing only C, H, and O is analyzed by combustion analysis and 21.71 g CO2 and 5.926 g H2O are produced. In a separate experiment, the molar mass is found to be 104.1 g/mol. Determine the empirical formula and the molecular formula of the organic compound. Enter the elements in the order C, H, O empirical formula
Answer: The empirical formula and the molecular formula of the organic compound is [tex]CHO[/tex] and [tex]C_4H_4O_4[/tex] respectively.
Explanation:
The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:
[tex]C_xH_yO_z+O_2\rightarrow CO_2+H_2O[/tex]
where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.
We are given:
Mass of [tex]CO_2[/tex] = 21.71 g
Mass of [tex]H_2O[/tex]= 5.926 g
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
For calculating the mass of carbon:
In 44g of carbon dioxide, 12 g of carbon is contained.
So, in 21.71 g of carbon dioxide, =[tex]\frac{12}{44}\times 21.71=5.921g[/tex] of carbon will be contained.
For calculating the mass of hydrogen:
In 18g of water, 2 g of hydrogen is contained.
So, in 5.926 g of water, =[tex]\frac{2}{18}\times 5.926=0.658g[/tex] of hydrogen will be contained.
Mass of oxygen in the compound = (17.11) - (5.921+0.658) = 10.53 g
Mass of C = 5.921 g
Mass of H = 0.658 g
Mass of O = 10.53 g
Step 1 : convert given masses into moles.
Moles of C =[tex] \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.921g}{12g/mole}=0.493moles[/tex]
Moles of H=[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.658g}{1g/mole}=0.658moles[/tex]
Mass of O=[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{10.53g}{16g/mole}=0.658moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =[tex]\frac{0.493}{0.493}=1[/tex]
For H =[tex]\frac{0.658}{0.493}=1[/tex]
For O=[tex]\frac{0.658}{0.493}=1[/tex]
The ratio of C : H: O = 1: 1: 1
Hence the empirical formula is [tex]CHO[/tex].
empirical mass of CHO = 12(1) + 1(1) + 1 (16) = 29
Molecular mass = 104.1 g/mol
[tex]n=\frac{\text {Molecular mass}}{\text {Equivalent mass}}=\frac{104.1}{29}=4[/tex]
Thus molecular formula = [tex]n\times {\text {Empirical formula}}=4\times CHO=C_4H_4O_4[/tex]
How many grams of magnesium
sulfate (MgSO4) are dissolved in
0.965 L of a 0.0575 M solution?
Molar Mass Mg: 24.30 g/mol
Molar Mass S: 32.06 g/mol
Molar Mass O: 16.00 g/mol
Answer:6.68
Explanation:
In each term equation below a blank line shows one term missing the terms may be an elemental symbol a coefficient or a subscript decide which term would balance the equation write the missing term in the second column the. Determine the reactants third column and products forth column of the reaction some reactions may have only one reactant or product and other reactions may have only one reactant or product and other reactions may have multiple reactants or products write your answers in the spaces in the table the first reaction involves sodium chloride not sodium carbon and iodine
Answer:
1) Cl2 2 is missing
2) H H is missing
Explanation:
