Answer:
Transitions through geologic time among 3 rock types
Explanation:
A hiker is at the bottom of a canyon facing the canyon wall closest to her. She is 280.5 meters from the wall and the sound of her voice travels at 340 m/s at that location. How long after she shouts will she hear her echo? (Be careful to consider why echoes happen.)
Answer:
4.80 seconds
Explanation:
The velocity of sound is obtained from;
V= 2d/t
Where;
V= velocity of sound = 329.2 ms-1
d= distance from the wall = 790.5 m
t= time = the unknown
t= 2d/V
t= 2 × 790.5/ 329.2
t= 4.80 seconds
The time is taken by the sound to reach the hiker will be t= 4.80 seconds
What is sound velocity?The sound velocity is defined as the distance traveled by the sound wave in a particular direction with respect to time.
The velocity of sound is given by the formula:
[tex]V=\dfrac{2d}{t}[/tex]
Here;
V= velocity of sound = 329.2 [tex]\frac{m}{s^2}[/tex]
d= distance from the wall = 790.5 m
t= time = the unknown
The time will be calculated as:
[tex]t=\dfrac{2d}{V}[/tex]
[tex]t=\dfrac{2\times 790.5}{329.2}[/tex]
[tex]t=4.80\ seconds[/tex]
Hence the time is taken by the sound to reach the hiker will be t= 4.80 seconds
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What is being transferred as you do work?
A. Energy
B. Power
C. Heat
D. Strength
[tex]\huge\bold{\purple{\bold{⚡A. Energy⚡}}} [/tex]
[tex]\huge\underline\mathtt\colorbox{cyan}{Reason:}[/tex]
When a force causes a body to move, work is done on the object by the force. Work is the measure of the energy transfer when a force 'F' moves an object through a distance 'd'. So we say that energy is transferred from one energy store to another when work is done, and therefore, energy transferred = work done.
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Answer:
.
Explanation:
The inclined plane in the figure above has two sections of equal length and different roughness. The dashed line shows where section 1 ends and section 2 begins. A block of M is placed at different locations on the incline. The coefficients of kinetic and static friction between the block and each section are shown in the table below.
If the block is at rest on section 1 of the incline, what is the magnitude of the force of static friction exerted on the block by the incline?
The static friction exerted on the block by the incline is [tex]\mu _ s _1 Mgcos \ \theta[/tex].
The given parameters;
mass of the block, = Mcoefficient of static friction in section 1, = [tex]\mu_s_1[/tex]angle of inclination of the plane, = θThe normal force on the block is calculated as follows;
Fₙ = Mgcosθ
The static friction exerted on the block by the incline is calculated as follows;
[tex]F_s = \mu_s F_n\\\\F_s = \mu _s_1(Mg cos\ \theta)\\\\F_s = \mu _s_1 Mgcos\ \theta[/tex]
Thus, the static friction exerted on the block by the incline is [tex]\mu _ s _1 Mgcos \ \theta[/tex]
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Please explain what the passage mean in your own words.
Remember the Sabbath day, to keep it holy. Six days shalt thou labor, and do all thy work: But the seventh day is the Sabbath of the Lord thy God: in it thou shalt not do any work, thou, nor thy son, nor thy daughter, thy manservant, nor thy maidservant, nor thy cattle, nor thy stranger that is within thy gates: For in six days the Lord made heaven and earth, the sea, and all that in them is, and rested the seventh day: wherefore the Lord blessed the Sabbath day, and hallowed it.
i really need help with this. cant anyone help me?
(A)
Explanation:
The number of atoms for each element on the left side must equal that on the right side. Only (A) satisfies that condition. The other other choices have mismatching number of atoms on either side.
no links never ever in the world give me a link just answer now without links What is the lithosphere? please write a full paragraph
Answer:
The lithosphere is the Earth's stable outer layer. The lithosphere is made from the brittle top mantle and the crust, which are the Earth's outermost layers. The atmosphere above it and the asthenosphere (another issue of the top mantle) underneath it define its limitations. even though the rocks of the lithosphere are nevertheless taken into consideration elastic, they may be not viscous. The asthenosphere is viscous, and the lithosphere-asthenosphere boundary (LAB) is the component in which geologists and rheologists—scientists who study the drift of depend—mark the difference in ductility among the 2 layers of the top mantle. Ductility measures a strong cloth’s ability to deform or stretch under strain. The lithosphere is a long way less ductile than the asthenosphere.
Explanation:
Plagarism checked, 100% unique [I think, if not sorryyyyeeeeee]
Hope this helps!
Byeeee have a nice day
d. The soccer player accelerates from rest at a rate of 3.1 m/s2. How far does he
run in 1.5 seconds? (1 point)
Answer:
= 6.975 m
Explanation:
3.1 m = 1 s2
? = 2.25 s2
(3.1 * 2.25)/1
= 6.975m
please answer ASAP .
a body slides down an inclined plane which makes an angle of 30° with the horizontal, neglecting friction. calculate the velocity of the body after sliding 10 m from rest
Answer:
Explanation:
a = gsinθ
a = 9.8sin30
a = 4.9 m/s²
v² = u² + 2as
v² = 0² + 2(4.9)(10)
v² = 98
v = √98 = 9.8994949...
v = 9.9 m/s
If a car has a suspension system with a force constant of 5.00x104 N/m, how much energy must the car's shocks remove to dampen an oscillation starting with a maximum displacement of 0.0750 m
Answer: 140.625
Explanation: Because energy gained due to damped motion and needs to be absorbed
what makes the morion mask expensive ?
Answer:
a lot of the masks are hand made a long time ago its really an art
Explanation:
Because it is a piece of art that is hard to craft
The speed of a motorcycle changed from 5m/s to 20m/s the ratio of initial and final kinetic energy is?
Answer:
Explanation:
½m5² / ½m20² = 25/400 = 1/16 = 0.0625
Including reaction time, the stopping distance is more than 20 feet at 10 miles per hour, at 20 miles per hour it will be about:
30 feet
63 feet
40 feet
75 feet
Answer:
A. 30 feet
Explanation:
Including reaction time, the stopping distance is more than 20 feet at 10 miles per hour, at 20 miles per hour it will be about 63 feet. Option B is correct.
What is speed?Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity.
Given conditions;
10 miles per hour ⇒ 20 feet
1 mile per hour ⇒ 2 feet
20 miles per hour ⇒ 20 × 2 feet
20 miles per hour ⇒ 20 × 2 feet
20 miles per hour ⇒40 feet
If the stopping distance is more than 20 feet at 10 miles per hour at 20 miles per hour it must be more than 40 feet.So that the correct answer is 63 feet.
Hence option B is correct.
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A car equipped with a massless spring in front collides with a stationary car as shown in the diagram. The mass of the incoming car is three times the mass of the target car. While the spring is being compressed, the cars are moving closer together, and while it is expanding they are moving farther apart, but at the instant that the spring is fully compressed, they have no relative motion, which means they are moving at the same speed. At this instant, the cars are moving with a speed of 2.4 m/s.
(a) Find the speed of the incoming car before the collision.
(b) Find the fraction of the system’s energy that is stored in the spring when
it is fully compressed.
(c) Find the final speed and direfction for both cars after the spring expands and the cars separate.
Answer:
Explanation:
Let m be target car mass
a)
conservation of momentum
(3m)u + m(0) = (3m + m)(2.4)
3u = 4(2.4)
u = 3.2 m/s
b)
system energy is originally in the striking car as kinetic energy
KE = ½(3m)3.2² = 15.36m J
at full compression, kinetic energy is
½(3m + m)2.4² = 11.52m J
so spring potential energy fraction of total energy is
(15.36 - 11.52)/15.36 = 0.25 or 25%
c)
The center of mass (CoM) is moving at 2.4 m/s
The CoM sees the larger mass car approach at
3.2 - 2.4 = 0.8 m/s and will see it depart at - 0.8 m/s
so a ground based observer would see it moving at
v₁ = 2.4 + -0.8 = 1.6 m/s in its original direction
The CoM sees the smaller mass car approach at
0 - 2.4 = -2.4 m/s and will see it depart at + 2.4 m/s
so a ground based observer would see it moving at
v₂ = 2.4 + 2.4 = 4.8 m/s in its original direction of the larger car
so the relative velocity of approach at 3.2 - 0 = 3.2 m/s
equals the relative velocity of departure at 4.8 - 1.6 = 3.2 m/s
checks.
If 8.90 kg of ice at -5.00°C is added to 12.0 kg of water at 15°C, compute the final temperature.
(in deg C)
How much ice remains, if any? (in Kg)
Answer:
6.93 kg
Explanation:
m1 = 8.90 kg
T1 = -5°C
m2 = 12 kg
T2 = 15°C
constant needed:
c (ice) = 2100 J/kg °C
c (water) = 4200 J/kg °C
L (Latent Heat) = 336 000 J/kg
Black Principle
Q (release) = Q (absorbs)
Q (release) max = m2 c(water) ∆T2
Q (release) max = 12 x 4200 x (15-0)
Q (release) max = 756 000 J
Q (absorbs) = m1 c(ice) ∆T1 + m1 L
Q (absorbs) = 8.9 x 2100 x (0-(-5)) + 8.9 x 336 000
Q (absorbs) = 93 450 + 2 990 400 = 3 083 850 J
since Q (absorbs) is much much bigger than Q (release), only a few litlle ice melting. So we need to see how much ice melting and how many left.
Q (release) - Q (absorbs) ice -5°C to ice 0°C = 756000 - 93450 = 662550
mass of melting Ice
Q (absorbs) melting ice = m(melting) L
662 550 = m(melting x 336 000
m (melting) = 662 500/336 000
m (melting) = 1.977 kg
so the ice remains is 8.90 - 1.97 = 6.93 kg
Please help on question e and F
E- what will be the total charge of the compound formed?
F what type of band will form?
Answer:
E-MgO(Magnesium Oxide)
How are the parts of birds and fish similar in structure and function?
Answer:
Birds and fish both have a backbone structure, which makes them structurally and functionally similar.
Explanation:
A 100 Hz sound wave is traveling through the air. If we increase the frequency to 200 Hz, this will _____ the wavelength.
Answer:
reduce
Explanation:
It will reduce the wavelenth
3. How do you record your score in the 3-Minute Step Test? A record the 60-second heart rate before activity B. record the 30-second heart rate after the activity C. record the 60-second heart rate after the activity D. record the 60-second heart rate during7 the activity ?? plss po nid ko ngayon plsss free piont makakasagot neto
Answer:
d
Explanation:
you record it during the test
Why did the physicist conclude that cats can be either liquid or solid?
Answer:
Explanation:
https://www.science.org/content/article/cats-behave-liquids-tampons-play-music-and-other-advances-honored-ig-nobel-prizes
Answer:
Liquid or Both
Explanation:
Cats exist in their own three states of matter: loaf, cinnamon roll, and liquid. The last category is certainly the most confusing because cats should be solids — and of course, they can be.
Kaya is riding her dirt bike eastward on a dirt road. She spots a pothole ahead.
Kaya slows her car from 14.0 m/s to 5.5 m/s in 6.0 s. What is her acceleration?
Answer: The acceleration of Kaya is .
Explanation:
Answer:
Kaya's acceleration is 1.41666667.
Explanation:
To find the acceleration we need to subtract the starting speed to the slowed speed. So 14 - 5.5 = 8.5.
Now we divide 8.5 by the time, 6 seconds.
Our final answer is 1.41666667, or rounded, 1.42.
Hello, I wanted an answer from a mathematician. The number 1.04 is closer to the number 1, 2, 1.25 or 1.5.
Answer:
Explanation:
Of the 4 numbers given, the answer is 1 or A
If you take the absolute value of abs(1 - 1.04) you get 0.04.
(2 - 1.04) = 0.96
1.25 - 1.04 = .21
1.5 - 1.04 = 0.46
The last three are all larger than 0.04
Note: absolute value means the positive difference between 2 numbers (even though it is negative). If it is negative, absolute value makes it positive.
A girl sitting on a beach counts six waves passing a buoy in 3.0 s. She measured the distance between the wave crests to be 1.5 meters. What is the speed of the waves the girl observed?
[tex]\\ \sf\longmapsto Frequency=\dfrac{1}{Time}=\dfrac{1}{3}=0.33s^{-1}[/tex]
Velocity be v
[tex]\\ \sf\longmapsto v=f\lambda[/tex]
[tex]\\ \sf\longmapsto V=0.33(1.5)[/tex]
[tex]\\ \sf\longmapsto V\approx 0.5ms^{-1}[/tex]
Given,
Wavelength = 1.5 metres
T = 3 seconds OR 3.0 seconds
We know that the formula of Frequency–
1/Time
According to the question we have seen that Time is 3 seconds
[tex] \sf \longmapsto \: Frequency = \frac{1}{3 .0 \: seconds} [/tex]
[tex] \sf \longmapsto \: Frequency = 0.33 seconds^{-1} [/tex]
We Know,
Velocity = Frequency
Solving Further[tex]\sf \longmapsto Velocity =0.33 \times 1.5 [/tex]
[tex]\sf \longmapsto \: 0.5 \: m/s ^{-1}[/tex]
Therefore the speed is[tex]\sf \: 0.5 \: m/s ^ {-1}[/tex]A steam pipe is covered with 1.50-cm thick insulating material of thermal conductivity of 0.200 cal/cm · °C · s. How much energy is lost every second when the steam is at 195°C and the surrounding air is at 20.0°C? The pipe has a circumference of 800 cm and a length of 40.0 m. Neglect losses through the ends of the pipe.
This question involves the concepts of Fourier's law of heat conduction and heat loss per unit time.
The heat energy loss per second is "3.12 x 10⁸ W".
Applying Fourier's Law of Heat Conduction here, we get:
[tex]Q = -kA\frac{\Delta T}{\Delta x}[/tex]
where,
Q = heat energy loss per unit time = ?
k = thermal conductivity = 0.2 cal/cm.°C.s [tex](\frac{4.184\ J}{1\ cal})(\frac{100\ cm}{1\ m})[/tex] = 83.68 J/m.°C.s
A = Surface area = (circumference)(length) = (8 m)(40 m) = 320 m²
ΔT = difference in temperature = 20°C - 195°C = -175°C
Δx =thickness of insulation = 1.5 cm = 0.015 m
Therefore,
[tex]Q = -(83.68\ J/m.^oC.s)(320\ m^2)(\frac{-175\ ^oC}{0.015\ m})\\\\[/tex]
Q = 3.12 x 10⁸ W = 312 MW
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What s the kinetic energy of a 0.100 kg baseball thrown at 20.0 m/s?
1: 40.0 J
2: 1.00 J
3: 2.00 J
4; 20.0 J
5: 4.00 J
Answer:
KE = ½mv² = ½(0.100)20.0² = 20.0 J
Explanation:
What is the value of the magnitude of the difference of vectors A and B, |A - B|?
Answer:
Let, θ be the angle between vector a and vector b.
So, the angle between vector a and vector (-b) must be (180° - θ).
Magnitude of the difference of vectors a and b
= |a - b|
= Magnitude of the resultant of the vector sum of the vectors a and (-b)
= |{√|a|^2 + |b|^2 + 2 * |a| * |b| * cos (180° - θ)}|
= |{√|a|^2 + |b|^2 - 2 * |a| * |b| * (cos θ)}|.
Explanation:
A remote-control car has batteries that store 1.8 kJ of energy. When the car is
driven across a sports field there is friction dragging on the car, producing a force
of 2 N.
Complete the following sentence: If the car is 100% efficient, it could travel a
distance of metres on a single battery charge.
Answer:
Explanation:
Complete the following sentence: If the car is 100% efficient, it could travel a distance of 900 meters on a single battery charge.
W = Fd
1800 = 2d
d = 900
Assuming 100 % efficient means turning battery power into motion.
A car totally 100% efficient would have zero friction and could travel an infinite distance on a full battery charge.
The chart shows data for a moving object.
Which conclusion is best supported by the information
in the chart?
Time (s)
Velocity (m/s)
2
4
6
8
8
8
O The object has negative displacement.
O The object has negative acceleration.
O The object does not have displacement
O The object is not accelerating
Mark this and return
Save and Exit
Next
Submit
Answer:
the object is not accelerating
name a suitable thermometer for a winter temperature at noth pole?
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a force is something that ___ an object to ____
Answer:
which can cause an object with mass to change its volocity
