What is 7-12 problems. The image is attached.

The critical point is x = -1/2, the function has a local minimum at x = 1 and an absolute maximum at x = 4, and the absolute minimum is at x = -1/2.

a. The critical point is x = -1/2.

To find the critical point(s), we need to find where the derivative of the function is equal to zero or undefined. In this case, we have:

f(x) = -4x - x^2 + 2

f'(x) = -4 - 2x

Setting f'(x) equal to zero, we get:

-4 - 2x = 0

-2x = 4

x = -2/2

x = -1

However, we need to check if this value is in the given interval (1-4, 4). Since -1 is not in the interval, it is not a critical point.

Next, we check the endpoints of the interval.

When x = 1, f(x) = -4 - 1^2 + 2 = -3.

When x = 4, f(x) = -4 - 4^2 + 2 = -22.

So the function has a local minimum at x = 1, and an absolute maximum at x = 4, and no local maximum.

b. The local maximum is at x = 4, and the local minimum is at x = 1.

We can use the First Derivative Test to locate the local maximum and minimum points. If the derivative changes sign from positive to negative at a point, then it is a local maximum. If the derivative changes sign from negative to positive at a point, then it is a local minimum.

In this case, we have f'(x) = -4 - 2x. It is negative for x < -2 and positive for x > -2. Therefore, the function is decreasing for x < -2 and increasing for x > -2. Since the interval is (1-4, 4), the critical points are -2 and 4.

For x = 4, we have f'(4) = -4 - 2(4) = -12, which is negative, so x = 4 is a local maximum.

For x = 1, we have f'(1) = -4 - 2(1) = -6, which is negative, so x = 1 is a local minimum.

Therefore, the local maximum is at x = 4, and the local minimum is at x = 1.

c. The absolute maximum is at x = 4, and the absolute minimum is at x = -1/2.

To find the absolute maximum and minimum, we need to evaluate the function at the critical points and endpoints of the interval, and choose the largest and smallest values, respectively.

We have already found that the local maximum is at x = 4, and the local minimum is at x = 1. We also found that x = -1/2 is a critical point, but it is not in the given interval, so we can ignore it.

Evaluating the function at the endpoints of the interval, we get:

f(1) = -3

f(4) = -22

Therefore, the absolute maximum is at x = 4, and the absolute minimum is at x = 1/2.

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bro idrk but I think

Answer:  The correct option is

(A) {-1, -5}.

Step-by-step explanation:  We are given to find the zeroes of the quadratic function graphed in the figure shown.

We know that

the zeroes of a quadratic function f(x) are the value of x for which f(x) is equal to zero.

That is, the points on the graph where the curve crosses the X-axis.

From the graph, we note that the curve of the function crosses the X-axis at the points x = 1 and x = -5.

Therefore, the zeroes of the given function are x = -1 an x = -5.

Thus, option (A) is CORRECT.

Martin expects to wait longer than Selena. This can be Mathematically represented as: t > s

To determine who expects to wait longer, we need to compare the values on the number lines for Selena and Martin. Let's say Selena expects to wait for t minutes, and Martin expects to wait for s minutes. Looking at the number lines, we can see that Selena's expected wait time is closer to 10 minutes, while Martin's expected wait time is closer to 5 minutes. Therefore, we can say that Martin expects to wait longer than Selena.

Mathematically, we can represent this as:

t > s

This means that Selena's expected wait time is greater than Martin's expected wait time. Therefore, Martin expects to wait longer than Selena.

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- If the equation is overdamped, b ∈ (-∞, -2√6) ∪ (2√6, ∞).
- If the equation is underdamped, b ∈ (-2√6, 2√6).
- If the equation is critically damped, b ∈ {-2√6, 2√6}.

To determine the behavior of the solution for the given differential equation s′′ + bs′ + 6s = 0, we need to analyze the roots of the characteristic equation:

r^2 + br + 6 = 0

For this quadratic equation, the discriminant Δ is given by:

Δ = b^2 - 4(1)(6) = b^2 - 24

The behavior of the solution depends on the value of Δ:

1. Overdamped: If Δ > 0, the solution will be overdamped.
2. Underdamped: If Δ < 0, the solution will be underdamped.
3. Critically damped: If Δ = 0, the solution will be critically damped.

Now, we find the intervals of b for each case:

1. Overdamped (Δ > 0):
b^2 - 24 > 0
This inequality holds for b ∈ (-∞, -2√6) ∪ (2√6, ∞).

2. Underdamped (Δ < 0):
b^2 - 24 < 0
This inequality holds for b ∈ (-2√6, 2√6).

3. Critically damped (Δ = 0):
b^2 - 24 = 0
This equation holds for b = -2√6 and b = 2√6.

In conclusion:
- If the equation is overdamped, b ∈ (-∞, -2√6) ∪ (2√6, ∞).
- If the equation is underdamped, b ∈ (-2√6, 2√6).
- If the equation is critically damped, b ∈ {-2√6, 2√6}.

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The bicycle mechanic should cut a strip of plastic approximately 82 inches long to place between the tube and tire of the 26-inch diameter bicycle tire.

To calculate the length of the strip of plastic needed, we first need to determine the circumference of the tire. The formula for the circumference of a circle is C=2πr, where C is the circumference, π is approximately 3.14, and r is the radius of the circle.

In this case, the tire diameter is 26 inches, so the radius is 13 inches (half of the diameter). Therefore, the circumference of the tire is: C = 2πr = 2π(13)     = 81.64 inches (rounded to two decimal places)

To ensure that the strip of plastic fits snugly between the tube and tire, it should be the same length as the circumference of the tire. Therefore, the strip of plastic should be 82 inches long (rounded to the nearest inch).

In summary, the bicycle mechanic should cut a strip of plastic that is 82 inches long to fit between the tube and tire of the 26-inch diameter bicycle tire.

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The expression that is equivalent to 3x – (2x + 4) + 5 is x+1 ( optionB)

Equivalent expressions are expressions that work the same even though they look different. If two algebraic expressions are equivalent, then the two expressions have the same value.

For example , 2a+6a is equivalent to 2a( 1+3) and they will surely have the same value when a value is replaced with a

3x – (2x + 4) + 5 = 3x-2x-4+5

= x-4+5

= x +1

therefore the equivalent of 3x – (2x + 4) + 5 is x+1

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The equation of the straight line connecting these points in the form of y = mx + c is given as y = (1/2)x + 1.

The line in the slope-intercept equation is given as,

y = mx + c

where:

m = the slope of the line

c = the y-intercept

The slope m of the line connecting two points (x1, y1) and (x2, y2) is given by the formula

= (y₂ - y₁) / (x₂ - x₁)

Substituting the coordinates values of P and Q into this formula, we get

[tex]m = (3 - 0) / (4 - (-2))[/tex]

= 3/6

= 1/2

Therefore, the value of the m is 1/2

We can find the value of c by substituting the m and x values in the equation. using the point P and  Substituting x and y values in the equation we get

x = - 2

y = 0  

[tex]0 = (1/2) × (-2) + c[/tex]

c = 1

Therefore, the value of c is 1.

By substuting the m and c values in the standard slope-intercept formula we get y = (1/2)x + 1.

Therefore, the equation of the line connecting points P and Q is y = (1/2)x + 1.

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The quotient of the division 3x⁴ + 20x³ + 14x² + 17x + 30 ÷ x + 6 is 3x³ + 2x² + 6x - 19

The quotient expression is given as

3x⁴ + 20x³ + 14x² + 17x + 30 ÷ x + 6

The long division expression is represented as

x + 6 | 3x⁴ + 20x³ + 14x² + 17x + 30

So, we have the following division process

           3x³ + 2x² + 6x - 19

x + 6 | 3x⁴ + 20x³ + 14x² + 17x + 30

          3x⁴ + 18x³

         --------------------------------

                    2x³ + 14x² + 17x + 30

                    2x³ + 12x²

         -------------------------------------

                                 6x² + 17x + 30

                                 6x² + 36x

         -------------------------------------

                                            -19x + 30

                                            -19x - 114

         -------------------------------------

                                                       134

Hence, the quotient of the long division is 3x³ + 2x² + 6x - 19

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The answer should be

2x³ + 14x² + 17x + 30

The probability that a randomly chosen student is a male who enjoys reading P(male and enjoys reading) ≈ 0.261

To calculate the probability that a randomly chosen student is a male who enjoys reading, you need the number of males who enjoy reading divided by the total number of students.

The probability that a randomly chosen student is a male who enjoys reading can be found by dividing the number of males who enjoy reading by the total number of students.

From the table, we see that there are 30 males who enjoy reading and a total of 115 students. Therefore, the probability is:

P(male and enjoys reading) = 30/115

Rounding to the nearest thousandth, we get:

Therefore, The probability that a randomly chosen student is a male who enjoys reading P(male and enjoys reading) ≈ 0.261

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The selling price of the necklace at the store is $32.64.

To calculate the selling price of the necklace, we will first find the markup amount and then add it to the original cost.

Markup = (Original Cost) x (Markup Percentage)
Markup = $24 x 36% = $24 x 0.36 = $8.64

Now, add the markup amount to the original cost to find the selling price:

Selling Price = Original Cost + Markup
Selling Price = $24 + $8.64 = $32.64

So, the selling price of the necklace at the store is $32.64.

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The downhill side of the crane base should be raised by approximately 4.53 inches to level the crane on a 2.5° slope.

We can use trigonometry here. Let x be the length (in inches) that the downhill side of the base should be raised. The slope of the ground is given to be 2.5°,

tan(2.5°) ≈ 0.0436

Now, using the equation,

x / 12 = 9tan(2.5°)

Here, we converted the base's width from feet to inches (by dividing by 12) and calculated the crane's required vertical displacement (inches) using the angle's tangent. When we simplify this equation, we obtain,

x = 9tan(2.5°)12

x ≈ 4.53 inches

Therefore, the downhill side of the base should be raised by about 4.53 inches to level the crane.

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Complete question - A crane is being set up on a slope of 2.5 degrees. If the base of the crane is 9.0 ft​ wide, how many inches should the downhill side of the base be raised in order to level the​ crane?

Answer:

8x - 16 = 40

8x = 56

x = 7

Hope this helps! :D

Step-by-step explanation:

1kL = 100 dal

x = 470 dal .... you will criss cross it

1 kl × 470 dal = x ×100dal

470 dal kl = 100dal x ... then you will divide 100 dal from both side

4.7 kl = x

x = 4.7 kl

so our result is 4.7kl which is equal to 470 dal

Step-by-step explanation:

470 dal = 4.7 kl

because 1 kl = 100 dal

[tex] \frac{1}{x} = \frac{100}{470} \\ \\ 100x = 470 \\ x = \frac{470}{100} \\ x = 4.7[/tex]

Answer:

Step-by-step explanation:

You want the measures of the angles where lines cross if the sum of three of them is 280°.

Angle b and c form a linear pair, so ...

  b + c = 180°

Substituting that into the given equation, we have ...

  b + c + d = 280°

  180° + d = 280°

  d = 100°

Angles in this figure that do not share a side are vertical angles, hence congruent.

  b = d = 100°

  c = 180° -b = 180° -100° = 80° . . . . using the linear pair relation

  a = c = 80°

The approximate volume of the cylinder with a diameter of 14cm and height of 49cm is 10780.78 cubic centimeters, calculated using the formula V=πr²h.

To calculate the volume of a cylinder, we use the formula

Volume = πr²h

where π is pi, r is the radius of the cylinder, h is the height of the cylinder.

We are given the diameter of the cylinder, which is 14 cm. The radius of the cylinder is half of the diameter, so

radius = diameter / 2 = 14 cm / 2 = 7 cm

The height of the cylinder is given as 49 cm.

Now we can use the formula to find the volume of the cylinder

Volume = πr²h = 3.14 x 7² x 49 = 10780.78 cubic centimeters (rounded to two decimal places)

Therefore, the approximate volume of the cylinder is 10780.78 cubic centimeters.

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--The given question is incomplete, the complete question is given

" What is the approximate volume of the cylinder? when diameter is 14cm height is 49cm (Use 3. 14 as an approximation of pi. )"--

We can plot the points (1,8), (2,6), (3,2), and (4,1) on a graph by using a coordinate plane and the x and y-coordinates of each point.

To plot these points, we will use a coordinate plane, which is a two-dimensional graph with an x-axis and a y-axis. The x-axis represents the horizontal position, and the y-axis represents the vertical position. We will use the x-coordinate to determine the horizontal position of the point and the y-coordinate to determine the vertical position of the point.

For the first point, (1,8), we will start at the origin of the graph, which is the point (0,0). We will then move 1 unit to the right along the x-axis and 8 units up along the y-axis to plot the point.

For the second point, (2,6), we will start again at the origin and move 2 units to the right along the x-axis and 6 units up along the y-axis to plot the point.

We will repeat this process for the remaining points, (3,2) and (4,1), to plot all four points on the graph. Once all four points are plotted, we can connect them with a line to visualize the pattern of the ball's bounces.

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Complete Question:

Sara drops a tennis ball and lets it bounce. She records the height of the ball after each of its bounces as an ordered pair, where x represents the number of bounces and y represents the height of the ball in inches.

The ordered pairs she records are (1,8), (2,6), (3,2) and (4,1).

Plot the ordered points on the graph.

Answer:

3

Step-by-step explanation:

2x2=4

4x2=8

8x2=16

The amount in millimeters of lace they have left after finishing the quilts is 400 millimeters.

Determine how much lace is needed for each quilt. Each quilt has a perimeter that we need to cover with lace. The perimeter is the sum of all sides of a rectangle, which is (2 x width) + (2 x length).

Each quilt is 2.2 meters wide and 2.7 meters long. So, the perimeter of one quilt is (2 x 2.2) + (2 x 2.7) = 4.4 + 5.4 = 9.8 meters.

Since there are 2 quilts, the total lace needed for both quilts is 9.8 meters x 2 = 19.6 meters.

They bought a 20-meter roll of lace. To find out how much lace is left, subtract the total lace used from the initial length of the roll: 20 meters - 19.6 meters = 0.4 meters.

To convert this to millimeters, multiply by 1,000: 0.4 meters x 1,000 = 400 millimeters.

So, Franklin and his aunt have 400 millimeters of lace left after finishing the quilts.

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The cost of two oranges is 1.1 dollars.

One Sunday, Cory bought 4 apples and 6 oranges and paid $5.10. Dalia bought 2 apples and 5 oranges and paid $3.65.

Therefore, using equation,

let

x = cost of each apples

y = cost of each oranges

Hence,

4x + 6y = 5.10

2x + 5y = 3.65

Multiply equation(ii) by 2

4x + 6y = 5.10

4x + 10y = 7.3

4y = 2.2

y = 2.2 / 4

y = 0.55 dollars

Therefore,

cost of 2 oranges = 0.55(2) = 1.1 dollars

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The absolute maximum value of the function on the interval (-5, 11) is 670, which occurs at x = -5, and the absolute minimum value is approximately 400.847, which occurs at x ≈ 1.154.

To find the absolute maximum and minimum values of the function f(x) = -2x^3 + 8x + 400 on the interval (-5, 11), we need to consider the critical points and the endpoints of the interval.

First, we find the derivative of the function:

f'(x) = -6x^2 + 8

Setting f'(x) = 0 to find the critical points, we get:

-6x^2 + 8 = 0

x^2 = 4/3

x = ±√(4/3)

Since only √(4/3) is within the interval (-5, 11), this is the only critical point we need to consider.

Next, we evaluate the function at the endpoints of the interval:

f(-5) = -2(-5)^3 + 8(-5) + 400 = 670

f(11) = -2(11)^3 + 8(11) + 400 = -1666

Finally, we evaluate the function at the critical point:

f(√(4/3)) = -2(√(4/3))^3 + 8(√(4/3)) + 400 ≈ 400.847

Therefore, the absolute maximum value of the function on the interval (-5, 11) is 670, which occurs at x = -5, and the absolute minimum value is approximately 400.847, which occurs at x ≈ 1.154.

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Answer:

Step-by-step explanation:

(3√27)^4 = (3^1/3 * 3^3/2)^4 = (3^5/2)^4 = 3^10 = 59049

So the equivalent expression is not listed among the given options.

Answer:148

Step-by-step explanation:

Assuming he only bought milk, fish and chicken.
220+132=352
500-352=148

Therefore, the only value of c that works is 6√5.

(A) To find the average slope of the function f(x) = 1/x on the interval (5, 9), we use the formula:

Average Slope = (f(9) - f(5)) / (9 - 5)

Plugging in the values, we get:

Average Slope = (1/5 - 1/9) / 4 = -1/180

Therefore, the average slope of the function on the interval (5, 9) is -1/180.

(B) By the Mean Value Theorem, we know there exists a c in the open interval (5, 9) such that f'(c) is equal to this mean slope.

The derivative of f(x) = 1/x is f'(x) = -1/x^2.

Setting f'(c) = -1/180, we get:

-1/c^2 = -1/180

Solving for c, we get:

c = ±6√5

Since c must be in the open interval (5, 9), the only value that works is:

c = 6√5

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The coordinates of the images after the translation are K' (-4, 6).

To find the image coordinates of K', we need to translate the coordinates of K 6 units up.

This can be done by adding 6 to the y-coordinate of K.

So, the y-coordinate of K' will be:

y-coordinate of K' = y-coordinate of K + 6

= 0 + 6

= 6

To find the x-coordinate of K', we just need to keep the x-coordinate of K the same, since the translation is only in the vertical direction.

Therefore, the image coordinates of K' are (-4, 6).

So, the correct answer is C. K′(−4, 6).

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The spindle speed for a cut taken with a 4-inch high-speed drill and a cutting speed of 30 feet per minute is approximately 35.1 revolutions per minute.

Speed is a measure of how fast an object is moving. It is usually measured in units of distance per unit time, such as miles per hour or meters per second. Speed is an important concept in physics, engineering, and everyday life

We can use the formula for spindle speed that relates spindle speed to cutting speed and tool diameter:

S = (C × 12) / (π × D)

where S is spindle speed, C is cutting speed in feet per minute, D is tool diameter in inches, and π is the mathematical constant pi.

We know that for a 3-inch high-speed drill with a cutting speed of 70 feet per minute, the spindle speed is 88.2 revolutions per minute. We can use this information to solve for the constant of proportionality k:

88.2 = (70 × 12) / (π × 3)

k = 88.2 × (π × 3) / (70 × 12)

k ≈ 0.0039

Now we can use the value of k to find the spindle speed for a 4-inch high-speed drill with a cutting speed of 30 feet per minute:

S = k × C × 12 / D

S = 0.0039 × 30 × 12 / 4

S = 35.1

Therefore, the spindle speed for a cut taken with a 4-inch high-speed drill and a cutting speed of 30 feet per minute is approximately 35.1 revolutions per minute.

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Deion increased the distance he ran by 20%.

To discover the percentage increase within the distance Deion ran, we need to first calculate the amount of increase.

The increase in distance that Deion ran this week compared to final week is:

6.4 miles

To find the proportion increase, we need to divide the increase by means of the original value (the distance he ran last week),

Then multiply by using a hundred to express the result as a percent.

The original price (last week's distance) is:

32 miles

Therefore, the percentage increase within the distance he ran is:

(6.4 miles / 32 miles) x 100% = 20%

So, Deion increased the distance he ran by 20%.

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The value of s - 85 cannot be determined based on the given information as we do not know the value of s.

Alternating Series Test states that if a series satisfies three conditions, namely the terms alternate in sign, the absolute value of the terms decreases as n increases, and the limit of the terms approaches zero as n approaches infinity, then the series converges.

The given series (-1)^n satisfies the first two conditions as the terms alternate in sign and the absolute value of the terms is decreasing. To check the third condition, we take the limit of the terms as n approaches infinity: lim n→∞ |(-1)^n+1/n+1| = lim n→∞ 1/(n+1) = 0.

Since all three conditions are satisfied, the series converges. We can also see from the given partial sums that the sum s lies between 83 and 85. Therefore, s - 85 is negative or zero.

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The 90% confidence interval for the amount of time that teens spend online each week is (30.761, 32.839) hours

To find the 90% confidence interval for the amount of time that teens spend online each week, we can use the following formula

CI = x ± z*(σ/√n)

where

x is the sample mean

σ is the population standard deviation

n is the sample size

z is the z-score associated with the desired confidence level

In this case, we have

x = 31.8 hours

σ = 5.91 hours

n = 85

z = 1.645 (for a 90% confidence level, using a z-table or calculator)

Plugging in these values, we get

CI = 31.8 ± 1.645*(5.91/√85)

Simplifying, we get

CI = 31.8 ± 1.039

We can interpret this interval as saying that if we were to take many random samples of 85 teens and compute the confidence interval for each sample, about 90% of these intervals would contain the true population mean.

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Out of the students surveyed, 90 played a musical instrument.

To find the total number of students who played a musical instrument, we need to look at the table provided and sum up the number of boys and girls who played an instrument.

From the table, we can see the following:
- Boys who played an instrument: 42
- Girls who played an instrument: 48

To find the total number of students who played a musical instrument, simply add the number of boys and girls together:

Total students who played an instrument = (Number of boys who played an instrument) + (Number of girls who played an instrument)

Total students who played an instrument = 42 (boys) + 48 (girls)

Total students who played an instrument = 90

So, of the students surveyed, 90 played a musical instrument.

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The student could model the chance of it raining on each day by

The experimental probability of having rain on both days expressed as a percentage is 20%.

The experimental probability of having rain on both days can be determined using the probability formula given below as follows:

The number of trials with rain on both days = 2 (Saturday and Sunday)

The total number of trials = 10

Experimental probability = 2 / 10

Experimental probability = 0.2 or 20%

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