Why did the physicist conclude that cats can be either liquid or solid?
Answer:
Explanation:
https://www.science.org/content/article/cats-behave-liquids-tampons-play-music-and-other-advances-honored-ig-nobel-prizes
Answer:
Liquid or Both
Explanation:
Cats exist in their own three states of matter: loaf, cinnamon roll, and liquid. The last category is certainly the most confusing because cats should be solids — and of course, they can be.
A girl sitting on a beach counts six waves passing a buoy in 3.0 s. She measured the distance between the wave crests to be 1.5 meters. What is the speed of the waves the girl observed?
[tex]\\ \sf\longmapsto Frequency=\dfrac{1}{Time}=\dfrac{1}{3}=0.33s^{-1}[/tex]
Velocity be v
[tex]\\ \sf\longmapsto v=f\lambda[/tex]
[tex]\\ \sf\longmapsto V=0.33(1.5)[/tex]
[tex]\\ \sf\longmapsto V\approx 0.5ms^{-1}[/tex]
Given,
Wavelength = 1.5 metres
T = 3 seconds OR 3.0 seconds
We know that the formula of Frequency–
1/Time
According to the question we have seen that Time is 3 seconds
[tex] \sf \longmapsto \: Frequency = \frac{1}{3 .0 \: seconds} [/tex]
[tex] \sf \longmapsto \: Frequency = 0.33 seconds^{-1} [/tex]
We Know,
Velocity = Frequency
Solving Further[tex]\sf \longmapsto Velocity =0.33 \times 1.5 [/tex]
[tex]\sf \longmapsto \: 0.5 \: m/s ^{-1}[/tex]
Therefore the speed is[tex]\sf \: 0.5 \: m/s ^ {-1}[/tex]A worker pushes 1500N crate with a horizontal force of 345N a distance of 24m.
How much work is done by the Floor on a crate?
Answer:
8280J
Explanation:
W = f x d
345 x 24 = 8280J
Including reaction time, the stopping distance is more than 20 feet at 10 miles per hour, at 20 miles per hour it will be about:
30 feet
63 feet
40 feet
75 feet
Answer:
A. 30 feet
Explanation:
Including reaction time, the stopping distance is more than 20 feet at 10 miles per hour, at 20 miles per hour it will be about 63 feet. Option B is correct.
What is speed?Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity.
Given conditions;
10 miles per hour ⇒ 20 feet
1 mile per hour ⇒ 2 feet
20 miles per hour ⇒ 20 × 2 feet
20 miles per hour ⇒ 20 × 2 feet
20 miles per hour ⇒40 feet
If the stopping distance is more than 20 feet at 10 miles per hour at 20 miles per hour it must be more than 40 feet.So that the correct answer is 63 feet.
Hence option B is correct.
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Kaya is riding her dirt bike eastward on a dirt road. She spots a pothole ahead.
Kaya slows her car from 14.0 m/s to 5.5 m/s in 6.0 s. What is her acceleration?
Answer: The acceleration of Kaya is .
Explanation:
Answer:
Kaya's acceleration is 1.41666667.
Explanation:
To find the acceleration we need to subtract the starting speed to the slowed speed. So 14 - 5.5 = 8.5.
Now we divide 8.5 by the time, 6 seconds.
Our final answer is 1.41666667, or rounded, 1.42.
The inclined plane in the figure above has two sections of equal length and different roughness. The dashed line shows where section 1 ends and section 2 begins. A block of M is placed at different locations on the incline. The coefficients of kinetic and static friction between the block and each section are shown in the table below.
If the block is at rest on section 1 of the incline, what is the magnitude of the force of static friction exerted on the block by the incline?
The static friction exerted on the block by the incline is [tex]\mu _ s _1 Mgcos \ \theta[/tex].
The given parameters;
mass of the block, = Mcoefficient of static friction in section 1, = [tex]\mu_s_1[/tex]angle of inclination of the plane, = θThe normal force on the block is calculated as follows;
Fₙ = Mgcosθ
The static friction exerted on the block by the incline is calculated as follows;
[tex]F_s = \mu_s F_n\\\\F_s = \mu _s_1(Mg cos\ \theta)\\\\F_s = \mu _s_1 Mgcos\ \theta[/tex]
Thus, the static friction exerted on the block by the incline is [tex]\mu _ s _1 Mgcos \ \theta[/tex]
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How are the parts of birds and fish similar in structure and function?
Answer:
Birds and fish both have a backbone structure, which makes them structurally and functionally similar.
Explanation:
A race car traveling at 10 meters per second accelerates at 1.5 meters per second squared while moving a distance of 600 meters. Which of the following best represents the final speed of the race car?
Answer:
Explanation:
Givens
vi = 10 m/s
a = 1.5 m/s^2
d = 600 m
vf = ?
Formula
vf^2 = vi^2 + 2*a*d
Solution
vf^2 = 10^2 + 2*1.5 * 600
vf^2 = 100 + 1800
vf^2 = 1900
sqrt(vf^2) = sqrt(1900)
vf = 43.59 m/s
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Answer:
.
Explanation:
d. The soccer player accelerates from rest at a rate of 3.1 m/s2. How far does he
run in 1.5 seconds? (1 point)
Answer:
= 6.975 m
Explanation:
3.1 m = 1 s2
? = 2.25 s2
(3.1 * 2.25)/1
= 6.975m
Helium gas is confined within a chamber that has a moveable piston. The mass of the piston is 8.7 kg; and its radius is 0.013 m. If the system is in equilibrium, what is the pressure exerted on the piston by the gas
Helium gas is in a chamber with a moveable piston, whose mass is 8.7 kg and its radius is 0.013 m. The pressure exerted on the piston by the gas is 1.6 × 10⁵ Pa.
Helium is confined in a chamber with a moveable 8.7-kg piston (m). We can calculate the weight of the piston (w) using Newton's second law of motion.
[tex]w = m \times g = 8.7kg \times 9.8 m/s^{2} = 85 N[/tex]
The radius of the piston (r) is 0.013 m. We can calculate the area of the piston (A) using the following expression.
[tex]A = \pi \times r^{2} = \pi \times (0.013)^{2} = 5.3 \times 10^{-4} m^{2}[/tex]
We can calculate the pressure exerted by the piston (P) using the following expression.
[tex]P = \frac{w}{A} = \frac{85N}{5.3 \times 10^{-4}m^{2} } = 1.6 \times 10^{5} Pa[/tex]
Since the system is in equilibrium, the pressure exerted on the piston by the gas is also 1.6 × 10⁵ Pa.
Helium gas is in a chamber with a moveable piston, whose mass is 8.7 kg and its radius is 0.013 m. The pressure exerted on the piston by the gas is 1.6 × 10⁵ Pa.
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If a car has a suspension system with a force constant of 5.00x104 N/m, how much energy must the car's shocks remove to dampen an oscillation starting with a maximum displacement of 0.0750 m
Answer: 140.625
Explanation: Because energy gained due to damped motion and needs to be absorbed
A car equipped with a massless spring in front collides with a stationary car as shown in the diagram. The mass of the incoming car is three times the mass of the target car. While the spring is being compressed, the cars are moving closer together, and while it is expanding they are moving farther apart, but at the instant that the spring is fully compressed, they have no relative motion, which means they are moving at the same speed. At this instant, the cars are moving with a speed of 2.4 m/s.
(a) Find the speed of the incoming car before the collision.
(b) Find the fraction of the system’s energy that is stored in the spring when
it is fully compressed.
(c) Find the final speed and direfction for both cars after the spring expands and the cars separate.
Answer:
Explanation:
Let m be target car mass
a)
conservation of momentum
(3m)u + m(0) = (3m + m)(2.4)
3u = 4(2.4)
u = 3.2 m/s
b)
system energy is originally in the striking car as kinetic energy
KE = ½(3m)3.2² = 15.36m J
at full compression, kinetic energy is
½(3m + m)2.4² = 11.52m J
so spring potential energy fraction of total energy is
(15.36 - 11.52)/15.36 = 0.25 or 25%
c)
The center of mass (CoM) is moving at 2.4 m/s
The CoM sees the larger mass car approach at
3.2 - 2.4 = 0.8 m/s and will see it depart at - 0.8 m/s
so a ground based observer would see it moving at
v₁ = 2.4 + -0.8 = 1.6 m/s in its original direction
The CoM sees the smaller mass car approach at
0 - 2.4 = -2.4 m/s and will see it depart at + 2.4 m/s
so a ground based observer would see it moving at
v₂ = 2.4 + 2.4 = 4.8 m/s in its original direction of the larger car
so the relative velocity of approach at 3.2 - 0 = 3.2 m/s
equals the relative velocity of departure at 4.8 - 1.6 = 3.2 m/s
checks.
Could a car drive on a frictionless surface? Explain using the terms action
force and reaction force. *
Answer:
No, it cannot. The car needs the friction of the surface to drive because the car pushes the surface backwards, and the surfaces makes a reaction force pushing the car forward, and that works because of the friction. In a frictionless surface the tires would rotate in the same place
what is the distance between two corresponding points of adjacent waves?
Answer:Wavelength
Explanation: The wavelength of a wave is the distance between any two corresponding points on adjacent waves.
Imagine you and a friend are trying to rearrange the furniture in your classroom. You push on a desk with a force of 50 N to the right. Your friend pushes on the same desk with a force of 50 N to the left. What is the net force on the desk?
Answer:
The net force on the desk is zero.
i really need help with this. cant anyone help me?
(A)
Explanation:
The number of atoms for each element on the left side must equal that on the right side. Only (A) satisfies that condition. The other other choices have mismatching number of atoms on either side.
g The human ear can perceive sounds with frequencies ranging from 20.0 Hz to 20000 Hz. If the speed of sound is 330 m/s in air and 1500 m/s under water, what is the longest and shortest wavelength that can be heard in air and in water
Answer: lamda max= 16,5m lamda min= 0,0165m (air)
lamda max= 75m, lamda min=0,075m (water)
Explanatin
Draw an energy pie chart above each of the cart’s four positions.
i. Choose your reference point for determining height.
ii. Create a pie chart that accurately represents the ratio of the three forms of energy and label the sections of the pie Eg for gravitational potential energy, Ek for kinetic energy, and Eth for thermal energy.
Answer:
Attached below! Ignore the name please. Thanks!
Explanation:
Displacement (m) 0 20 40 40 80 80 60 400 Time (s) 10 10 20 30 40 50 60 70 80 a) Explain the different sections of the graph in as much detail as you can. b) Use the graph to determine the maximum velocity. c) Find the average velocity after 45 s. d) Find the instantaneous velocity at 45 s.
Answer:
because I dont know
Explanation:
first you add the multiply
The instantaneous velocity at 60 m is zero, at - 40 m is - 1 m / s, at 15 s is zero and at 25 s is 0.8 m / s if Displacement (m) 0 20 40 40 80 80 60 400 Time (s) 10 10 20 30 40 50 60 70 80.
What is Instantaneous velocity?Instantaneous velocity = Position with respect to time / Time
1 ) At d = 60 m, the instantaneous velocity is zero because the car is at rest.
2 ) At d = - 40 m, t = 40 s
Instantaneous velocity = - 40 / 40
Instantaneous velocity = - 1 m / s
3 ) At t = 15 s, d = 60 m
At 60 m, the car is at rest, so the Instantaneous velocity is zero
4 ) At t = 25 s, d = 20 m
Instantaneous velocity = 20 / 25
Instantaneous velocity = 0.8 m / s
Instantaneous velocity of a given curve in a position-time graph can be found by drawing a tangent to the curve and finding the slope of the tangent. Instantaneous velocity = 0
Instantaneous velocity = - 1 m / s
Instantaneous velocity = 0
Instantaneous velocity = 0.8 m / s
Therefore, The instantaneous velocity at 60 m is zero, at - 40 m is - 1 m / s, at 15 s is zero and at 25 s is 0.8 m / s if Displacement (m) 0 20 40 40 80 80 60 400 Time (s) 10 10 20 30 40 50 60 70 80.
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What is the value of the magnitude of the difference of vectors A and B, |A - B|?
Answer:
Let, θ be the angle between vector a and vector b.
So, the angle between vector a and vector (-b) must be (180° - θ).
Magnitude of the difference of vectors a and b
= |a - b|
= Magnitude of the resultant of the vector sum of the vectors a and (-b)
= |{√|a|^2 + |b|^2 + 2 * |a| * |b| * cos (180° - θ)}|
= |{√|a|^2 + |b|^2 - 2 * |a| * |b| * (cos θ)}|.
Explanation:
Please explain what the passage mean in your own words.
Remember the Sabbath day, to keep it holy. Six days shalt thou labor, and do all thy work: But the seventh day is the Sabbath of the Lord thy God: in it thou shalt not do any work, thou, nor thy son, nor thy daughter, thy manservant, nor thy maidservant, nor thy cattle, nor thy stranger that is within thy gates: For in six days the Lord made heaven and earth, the sea, and all that in them is, and rested the seventh day: wherefore the Lord blessed the Sabbath day, and hallowed it.
what makes the morion mask expensive ?
Answer:
a lot of the masks are hand made a long time ago its really an art
Explanation:
Because it is a piece of art that is hard to craft
A remote-control car has batteries that store 1.8 kJ of energy. When the car is
driven across a sports field there is friction dragging on the car, producing a force
of 2 N.
Complete the following sentence: If the car is 100% efficient, it could travel a
distance of metres on a single battery charge.
Answer:
Explanation:
Complete the following sentence: If the car is 100% efficient, it could travel a distance of 900 meters on a single battery charge.
W = Fd
1800 = 2d
d = 900
Assuming 100 % efficient means turning battery power into motion.
A car totally 100% efficient would have zero friction and could travel an infinite distance on a full battery charge.
A car driving at 32.6 miles/hours slowed to a stop in 2.4 seconds
The driver's acceleration was
miles/hour second. Record your answer to two places past the decimal point
Explanation:
using v=u+at
0=32.6 + (a×(2.4/3600))
-32.6=(a×(2.4/3600))
a=-32.6×3600/2.4
a= -48900miles/hr^2
please answer ASAP .
a body slides down an inclined plane which makes an angle of 30° with the horizontal, neglecting friction. calculate the velocity of the body after sliding 10 m from rest
Answer:
Explanation:
a = gsinθ
a = 9.8sin30
a = 4.9 m/s²
v² = u² + 2as
v² = 0² + 2(4.9)(10)
v² = 98
v = √98 = 9.8994949...
v = 9.9 m/s
a force is something that ___ an object to ____
Answer:
which can cause an object with mass to change its volocity
A steam pipe is covered with 1.50-cm thick insulating material of thermal conductivity of 0.200 cal/cm · °C · s. How much energy is lost every second when the steam is at 195°C and the surrounding air is at 20.0°C? The pipe has a circumference of 800 cm and a length of 40.0 m. Neglect losses through the ends of the pipe.
This question involves the concepts of Fourier's law of heat conduction and heat loss per unit time.
The heat energy loss per second is "3.12 x 10⁸ W".
Applying Fourier's Law of Heat Conduction here, we get:
[tex]Q = -kA\frac{\Delta T}{\Delta x}[/tex]
where,
Q = heat energy loss per unit time = ?
k = thermal conductivity = 0.2 cal/cm.°C.s [tex](\frac{4.184\ J}{1\ cal})(\frac{100\ cm}{1\ m})[/tex] = 83.68 J/m.°C.s
A = Surface area = (circumference)(length) = (8 m)(40 m) = 320 m²
ΔT = difference in temperature = 20°C - 195°C = -175°C
Δx =thickness of insulation = 1.5 cm = 0.015 m
Therefore,
[tex]Q = -(83.68\ J/m.^oC.s)(320\ m^2)(\frac{-175\ ^oC}{0.015\ m})\\\\[/tex]
Q = 3.12 x 10⁸ W = 312 MW
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name a suitable thermometer for a winter temperature at noth pole?
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Please help on question e and F
E- what will be the total charge of the compound formed?
F what type of band will form?
Answer:
E-MgO(Magnesium Oxide)
