What do you know to be true about the values p and q

Answer:

x=7, y=2

Step-by-step explanation:

Solve2x+3y=20for x:

2x+3y=20

2x+3y+−3y=20+−3y

2x=−3y+20

2x/2=-3y+20/2

x= -3/2 y

Answer:

Step-by-step explanation:

If a sequence c1,c2,c3,...has limit K then the sequence ec1,ec2,ec3,...has limit e^K. Use this fact together with l'Hopital's rule to compute the limit of the sequence given by

bn=(n)^(5.6/n).

a)

[tex]L = \lim_{n \to \infty} b_n \\\\\\L= \lim_{n \to \infty} n^{\frac{5.6}{n} }[/tex]

Log on both sides

[tex]In (L) = \lim_{n \to \infty} In (n)^{\frac{5.6}{n} }\\\\= \lim_{n \to \infty} \frac{5.6}{n} In(n)[/tex]

[tex]=5.6 \lim_{n \to \infty} \frac{d}{dn} In(n)/\frac{d}{dn} (n)\\\\=5.6 \lim_{n \to \infty} \frac{1}{n} /1 \\\\=5.6 \lim_{n \to \infty} \frac{1}{n} \\\\=5.6 \times 0\\\\In(L) =0\\\\L=e^0\\\\L=1[/tex]

[tex]\therefore \lim_{n \to \infty} (n)^{\frac{5.6}{n} =1[/tex]

The limit value of given sequece is 1.

To understand more, check below explanation.

The given sequence is,

                   [tex]b_{n}=n^{5.6/n}[/tex]

We have to find limit of above sequence.

           [tex]L=\lim_{n \to \infty} b_n \\\\L=\lim_{n \to \infty}n^{5.6/n} \\\\ln(L)=\lim_{n \to \infty}\frac{5.6}{n}ln(n) \\\\ln(L)=5.6\lim_{n \to \infty}\frac{ln(n)}{n} \\\\ln(L)=5.6\lim_{n \to \infty}\frac{1/n}{1} \\\\ln(L)=5.6*0=0\\\\L=e^{0}=1[/tex]

Therefore, the limit value of given sequece is 1.

Learn more about the limit of function here:

https://brainly.com/question/2166212

Answer:

The table that illustrates this equation is table A:

1   -6   0   up   (0,0)

Step-by-step explanation:

The values of the parameters a, b, and c have to agree with the values for the general quadratic equation in standard form:

[tex]y = a\,x^2+b\,x+c[/tex]

compared to:

[tex]y=x^2-6\,x[/tex]

So the coefficient "a" of the quadratic term in our case is: "1"

the coefficient "b" of the linear term is : "-6"

the coefficient "c" for the constant term s : "0" (zero)

since the coefficient "a" is a positive number, we know that the parabola's branches must be opening "UP".

The y intercept can be found by evaluating the expression for x = 0:

[tex]y=x^2-6x\\y=(0)^2-6\,(0)\\y=0[/tex]

Therefore the y-intercept is at (0, 0)

These results agree with those of Table "A"

Answer:

Table A.)

Step-by-step explanation:

a 1, b -6, c 0, up, (0, 0), Table A.

Answer:

  A.  G(x) = (x -3)^3 -(x -3)

Step-by-step explanation:

The graph before it was shifted left will be a right-shift of the equation shown. That is accomplished by replacing x with (x-1.5). Then the right-shifted equation is ...

  G(x) = ((x-1.5) -1.5)^3 -((x -1.5) -1.5)

  G(x) = (x -3)^3 -(x -3) . . . . matches choice A

Answer:

The range is {4,5,7}

Step-by-step explanation:

The range of a relation is the output values  The values are 4,7,5  we normally put them in order from smallest to largest

The range is {4,5,7}

Answer:

a. 3

b. 5

c. 4

d. 4

e. 10

Step-by-step explanation:

Answer:

read below

Step-by-step explanation:

a.3

b.5

c.2

d.2

6. 8p

Answer:

The area of a trapezoid is 1/2 (b₁ + b₂) * h where b₁ and b₂ are the bases and h is the height. The answer is 1/2 * (3 + 4) * 1 = 3.5.

Answer:

1) Estimated slope = b₁ = 0.215

2) Estimated y-intercept = b₀ = -4.185

3) Not all the points predicted fall on the same straight line, but the model gives a close to ideal estimate of the line of best fit.

4) The estimated value of y when x=46 is 5.705

5) The value of the dependent variable y^ at x=0 is -4.185

6) The coefficient of determination = 0.951

Step-by-step explanation:

To solve this, we apply regression analysis

y = b₀ + b₁x

Price in Dollars | 23 | 34 | 40 | 46 | 47

Number of Bids | 1 | 3 | 4 | 5 | 7

For this question, we want to predict the number of bids (dependent variable, y), given the list price of the item (independent variable, x)

So, running the analysis on a spreadsheet application, like excel, the table of parameters is obtained and presented in the first attached image to this solution.

Σxᵢ = sum of all the independent variables (sum of all the list prices)

Σyᵢ = sum of all the dependent variables (sum of all the number of bids in the table)

Σxᵢyᵢ = sum of the product of each dependent variable and its corresponding independent variable

Σxᵢ² = sum of the square of each independent variable (list prices)

Σyᵢ² = sum of the square of each dependent variable (number of bids)

n = number of variables = 5

The scatter plot and the line of best fit is presented in the second attached image to this solution

Then the regression analysis is then done

Slope; m = b₁ = [n×Σxᵢyᵢ - (Σxᵢ)×(Σyᵢ)] / [nΣxᵢ² - (∑xi)²]

Intercept b: b₀ = [Σyᵢ - m×(Σxᵢ)] / n

Mean of x = (Σxᵢ)/n

Mean of y = (Σyᵢ) / n

Sample correlation coefficient r: r =

[n*Σxᵢyᵢ - (Σxᵢ)(Σyᵢ)] ÷ {√([n*Σxᵢ² - (Σxᵢ)²][n*Σyᵢ² - (Σyᵢ)²])}

And -1 ≤ r ≤ +1

All of these formulas are properly presented in the third attached image to this answer

The table of results; mean of x, mean of y, intercept, slope, regression equation and sample coefficient is presented in the fourth attached image to this answer.

Hence, the regression equation is

y = -4.185 + 0.215x

y = b₀ + b₁x

Intercept = b₀ = -4.185

Slope = b₁ = 0.215

And the regression coefficient = 0.951 (Which is very close to 1 and indicates statistic significance)

Hence, we can use this answer obtained to answer the questions attached

1) Find the estimated slope.

Estimated slope = b₁ = 0.215

2) Find the estimated y-intercept.

Estimated y-intercept = b₀ = -4.185

3) Determine if the statement "All points predicted by the linear model fall on the same line" is true or false.

Taking a few of sample data

x = 23 when y = 1

y = -4.185 + 0.215x

y = -4.185 + 0.215 (23) = 0.76 ≈ 1

x = 34, y = 3

y = -4.185 + 0.215 (34) = 3.125 ≈ 3

Hence, it is evident that not all the points predicted fall on the same straight line, but the model gives a close to ideal estimate of the line of best fit.

4) Find the estimated value of y when x=46.

The linear model is

y = -4.185 + 0.215x

when x = 46

y = -4.185 + 0.215(46) = 5.705

5) Determine the value of the dependent variable y^ at x=0.

y = -4.185 + 0.215x

when x = 0

y = -4.185 + 0.215(0) = -4.185

6) Find the value of the coefficient of determination.

The coefficient of determination = regression coefficient = 0.951 (as calculated above)

Hope this Helps!!!

Answer:

Rectangle

Step-by-step explanation:

Count the units. For the triangle, A=0.5bh. 0.5(4)(6)=A. A=12

Now, for the rectangle, A=bh. A=(3)(5). A=15. The rectangle is larger

Answer:

5

Step-by-step explanation:

There are two ways you can solve this. First is to just count all the numbers in the list given that are within the range 15-19. This is an inclusive range meaning the numbers 15 and 19 are a part of it. The second method is to count how many numbers are in the list given and count all the numbers that have already been put on the table. There are 19 total numbers, and 14 have already been counted. If you subtract you are left with 5 numbers that are within the range. So the answer is 5.

Explanation:

One method is to count all of the values that are between 15 and 19. Those values are highlighted in the diagram below. There are 5 values marked.

An alternative method is to note there are 19 values total. The items in the given table add to 5+2+1+2+4 = 14, so there must be 19-14 = 5 items missing to completely fill out the table.

Hope this helps!

Stay safe, have a good day :D

Answer:

The IV will run [tex]66.67 \ ml /hr[/tex]

Step-by-step explanation:

From the question we are told that

   The mass of Magnesium sulfate is  [tex]m_g = 30 \ g[/tex]

   The volume of the Magnesium sulfate  [tex]V_R = 500ml[/tex]

   The rate at which the dose of the solution (Magnesium sulfate + Lactated Ringers. ) is infused is  [tex]R = 4g/hr[/tex]

The concentration of Magnesium sulfate in Lactated Ringers  is mathematically evaluated as

         [tex]C_m = \frac{m_g}{V_R}[/tex]

substituting values

          [tex]C_m = \frac{30}{500}[/tex]

          [tex]C_m = 0.06\ g/ ml[/tex]

This implies that

     0.06 g of Magnesium sulfate is in every 1 ml of  Lactated Ringers

So  4 g  of  Magnesium sulfate is in x ml of  Lactated Ringers

So

        [tex]x = \frac{4}{0.06}[/tex]

       [tex]x = 66.67 \ ml[/tex]

So the amount of the solution in ml that is been infused in 1 hour is  

      [tex]66.67 \ ml /hr[/tex]

Write z in exponential form:

[tex]z=1-i=\sqrt2 e^{-i\frac\pi4}[/tex]

Then taking the logarithm, we get

[tex]\mathrm{Ln}(z)=\ln(\sqrt2) + \ln e^{-i\frac\pi4} = \boxed{\ln(\sqrt2)-\dfrac\pi4i}[/tex]

so a is the correct answer.

Answer:

The GCF is going to be 32

Answer:

32x^2

Step-by-step explanation:

B on edge

Answer: you would need 776 yards to make both dresses

Step-by-step explanation:

You would need to find the sum of the amount if yards needed for both dresses.

The first dress needs 418 yards

The seconds dress needs 358 yards

418 + 358 = 776

Therefore you would need 776 yards to be able to make both of the dresses

Answer:

given

3/4×1/7

=3×1/4×7

=3/28

thus the answer is 3/28

[tex]answer = \frac{3}{28} \\ solution \\ \frac{3}{4} \times \frac{1}{7} \\ = \frac{3 \times 1}{4 \times 7} \\ = \frac{3}{28} \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment[/tex]

Answer:

( g − f ) ( 3 ) = 23

Step-by-step explanation:

(g-f)(x)=g(x)-f(x)

=6x-(4-X(2))

=x(2)+6x-4

to evaluate (g-f) (#) substitute x=3 into (g-f)(x)

(g-f)=(9)+(6 x 3) -4=23

Answer:

volume of rectangular prism = 30 ft³

Step-by-step explanation:

The fishing trap he wants to build to house sea houses are mostly rectangular prism. The traps are mostly glass like. The volume of the fishing trap will be the volume of the rectangular prism.

volume of rectangular prism = LWH

where

L = length

W = width

H = height

volume of rectangular prism = LWH

Length = 5 ft

width = 2 ft

Height = 3 ft

volume of rectangular prism = 5 × 2 × 3

volume of rectangular prism = 10 × 3

volume of rectangular prism = 30 ft³

Answer:

6.8

Step-by-step explanation:

27 / 4 = 6.75, which rounded to the nearest tenth, is 6.8.

Answer:

D. Time ( length)

Step-by-step explanation:

The function is measuring the length of the race, and the time it took to complete. So, it would be D.

// have a great day //

Answer:

D. Time(length)

Step-by-step explanation:

→The time is on the outside because, according to the information that has been given/provided, the length of the race depends on the time taken to complete the race.

This means the correct answer is "D. Time(length)."

Answer:

Step 3

Step-by-step explanation:

The mistake was made in Step 3.

Step 1: Subtract the wholes. 4 - 1 = 3

Step 2: Subtract the fractions. 5/6 - 3/6 = 2/6

After Step 2, He should have added them instead of subtracting them:

3 + 2/6 = 3 2/6

So, step 3 was his mistake.

Answer:step 3

Step-by-step explanation: he should have added

Answer:

300/60=5 more words per minute

80+5 = 85 words per minute

or

80 x 60 = 4800 + 300 = 5100

5100 / 60 = 85 words per minute

Hope this helps

Step-by-step explanation:

Answer:

D.

Step-by-step explanation:

In the attached file

Answer:

Yes

Step-by-step explanation:

Yes.  Here's why:  We can obtain the graph of the inverse of the function shown by reflecting the red graph about the line y = x.  The resulting graph is true for all x values and for all y values; it passes the vertical line test.

Answer:

yes. ^^^^^^^^

Step-by-step explanation:

We can obtain the graph of the inverse of the function shown by reflecting the red graph about the line y = x.  The resulting graph is true for all x values and for all y values; it passes the vertical line test.

Answer:

Dear user,

Answer to your query is provided below

Scientific notation = 1.8x10^0

Step-by-step explanation:

This is usually expressed simply as 1.8 (Recall that 10^0 = 1.)

1.8×10^0

Answer:

After 1st year, the age distribution will be

[tex]x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right][/tex]

After 2nd year, the age distribution will be

[tex]x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right][/tex]

Step-by-step explanation:

A population has the following characteristics.

A total of 25% of the population survives the first year. Of that 25%, 75% survives the second year.

The average number of offspring for each member of the population is 3 the first year, 5 the second year, and 3 the third year.

From the above information, we can construct a transition age matrix.

[tex]A = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right][/tex]

The population now consists of 144 members in each of the three age classes.

From the above information, we can construct the current age matrix.

[tex]x = \left[\begin{array}{ccc}144\\144\\144\end{array}\right][/tex]

How many members will there be in each age class in 1 year?

After 1st year, the age distribution will be

[tex]x_1 = A \cdot x[/tex]

[tex]x_1 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}144\\144\\144\end{array}\right][/tex]

The matrix multiplication is possible since the number of columns of first matrix is equal to the number of rows of second matrix.

[tex]x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right][/tex]

After 2nd year, the age distribution will be

[tex]x_2 = A \cdot x_1[/tex]

[tex]x_2 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}1584\\36\\108\end{array}\right][/tex]

[tex]x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right][/tex]

Answer:

Cost of visit = 50 + 100n

Step-by-step explanation:

$50 is the set price of the visit.

$100 is the cost per cavity.

N is the number of cavities.

Since we don't know the number of cavities, 'n' will fill that spot.

100 x n will be the total cavity cost.

Cavity cost + set price of visit will equal the total cost of the visit.

Answer:

[tex]z=\frac{0.276 -0.3}{\sqrt{\frac{0.3(1-0.3)}{735}}}=-1.42[/tex]  

Now we can claculate the p value with this formula:

[tex]p_v =P(z<-1.42)=0.0778[/tex]  

If we use a signifiacn level of 5% we see that the p value is higher than 0.05 so then we have enough evidence to fail to reject the null hypothesis and we can't conclude that the true proportion is significantly higher than 0.3 at 5% of significance.

Step-by-step explanation:

Information to given

n=735 represent the random sample taken

X=203 represent the number of people who have their prostate regularly examined

[tex]\hat p=\frac{203}{735}=0.276[/tex] estimated proportion of people who have their prostate regularly examined  

[tex]p_o=0.3[/tex] is the value to verify

z would represent the statistic

[tex]p_v[/tex] represent the p value

System of hypothesis

We want to test if the true proportion is less than 0.3, the ystem of hypothesis are.:  

Null hypothesis:[tex]p \geq 0.3[/tex]  

Alternative hypothesis:[tex]p < 0.3[/tex]  

The statistic is given by:

[tex]z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}[/tex] (1)  

Replacing the info we got:

[tex]z=\frac{0.276 -0.3}{\sqrt{\frac{0.3(1-0.3)}{735}}}=-1.42[/tex]  

Now we can claculate the p value with this formula:

[tex]p_v =P(z<-1.42)=0.0778[/tex]  

If we use a signifiacn level of 5% we see that the p value is higher than 0.05 so then we have enough evidence to fail to reject the null hypothesis and we can't conclude that the true proportion is significantly higher than 0.3 at 5% of significance.

Answer:

Step-by-step explanation:

a) The first derivative helps considering f decreases or increases. Also, when f'(x) = 0, the function gets local max/min depends on how it acts.

The second derivative helps determining the concave up/down.

At x = -5, f"(-5) = -1 <0 That means the function f have concave down. Also, it shows f increases before -5 and decreases after -5.

Hence f'(-5) = 0 shows f gets maximum at -5.

b) At the point where f" =0, the function has a reflecting point and we need more information to determine if f has a local max/min there.

Using concepts of critical points, it is found that:

a) At x = −5, f has a local maximum.

b) At x = 1, f has neither a maximum nor a minimum.

-----------------------

A critical value of a function f(x) is a value of [tex]x^{\ast}[/tex] for which: [tex]f^{\prime}(x^{\ast}) = 0[/tex].

The second derivative test is also applied:

Item a:

At x = −5, f has a local maximum.

Item b:

At x = 1, f has neither a maximum nor a minimum.

A similar problem is given at https://brainly.com/question/16944025