Wave 1 has a wavelength 0.5 m and wave 2 has a wavelength= 0.05m. which wave carries higher energy?

Answers

Answer 1

Answer & Explanation:

The energy of a wave depends upon its amplitude, frequency and wave speed.

Assuming that both these waves are light waves, they have the same speed and amplitude can be assumed to be constant.

Wave 2 has a smaller wavelength and hence a higher frequency as c = λf, where

c is the speed of light,

λ is the wavelength and

f is the frequency of the wave.

Since wave 2 has a higher frequency, it has more energy.


Related Questions

How does the angle of launch affect the kinetic energy of a rubber band?​

Answers

Answer:

The angle of launch of the rubber band affects the initial velocity. The more the rubber band is stretched the more force it applies to return to equilibrium and the more kinetic energy that results in.

A dropped ball gains speed because

its nature is to become closer to Earth,

its velocity changes.

a gravitational force acts on it

Of inertia

Answers

Answer:

3 and 3 and 3

Explanation:

I am sure Hope for brain list

I don’t get my physical science hw it’s about ocean currents

Answers

okay I’ll help you with some

11. Anchorage has the coldest average temperature because its the furthest north

7. The temperatures lower in Albuquerque because it has a higher elevation

10. Miami has the highest average temperature because it’s the closet to the equator

9. San Diego has warmer winter temperatures than Albuquerque because the elevation is lower in San Diego

According to the article, what was the effect of elevation on the experimental group?

Answers

Answer:

Due to the effect of elevation on the experimental group the participants decided to try to help the research assistant who was having opening one of her files to finish the study. Schnall, Roper, and Fessler were able to conclude that happiness associated with a feeling of elevation can lead to more altruism or helping behaviors.

Explanation:

100 percent on edge

The effect of elevation on the experimental group was they show more urge of being altruistic and feeling happiness and satisfaction associated with elevation.

Altruism:

It is a practice in which a person help others without any selfishness, the person just want to help.

Witnessing someone's altruistic behavior, make other to feel good and a urge of being Altruistic, this is known as elevation.

After watching elevating Oprah video, the test group help the research assistant who was having trouble in opening file.

Therefore, the effect of elevation on the experimental group was they show more urge of being altruistic and feeling happiness and satisfaction associated with elevation.

To know more about Altruism:

https://brainly.com/question/25776081

A particle move in the xy plane so that its position vector r=bcosQi +bsinQj+ ctk, where b, Q and c are constants. show that the partial move with constant speed.​

Answers

Answer:

The speed of this particle is constantly [tex]c[/tex].

Explanation:

Position vector of this particle at time [tex]t[/tex]:

[tex]\displaystyle \mathbf{r}(t) = b\, \cos(Q)\, \mathbf{i} + b\, \sin(Q) \, \mathbf{j} + c\, t\, \mathbf{k}[/tex].

Write [tex]\mathbf{r}(t)[/tex] as a column vector to distinguish between the components:

[tex]\mathbf{r}(t) = \begin{bmatrix}b\, \cos(Q) \\ b\, \sin(Q) \\ c\, t\end{bmatrix}[/tex].

Both [tex]b[/tex] and [tex]Q[/tex] are constants. Therefore, [tex]b\, \cos(Q)[/tex] and [tex]b \sin (Q)[/tex] would also be constants with respect to [tex]t[/tex]. Hence, [tex]\displaystyle \frac{d}{dt}[b\, \cos(Q)] = 0[/tex] and [tex]\displaystyle \frac{d}{dt}[b\, \sin(Q)] = 0[/tex].

Differentiate [tex]\mathbf{r}(t)[/tex] (component-wise) with respect to time [tex]t[/tex] to find the velocity vector of this particle at time [tex]t\![/tex]:

[tex]\begin{aligned}\mathbf{v}(t) &= \frac{\rm d}{{\rm d} t} [\mathbf{r}(t)] \\ &=\frac{\rm d}{{\rm d} t} \left(\begin{bmatrix}b\, \cos(Q) \\ b\, \sin(Q) \\ c\, t\end{bmatrix}\right) \\ &= \begin{bmatrix}\displaystyle \frac{d}{dt}[b\, \cos(Q)] \\[0.5em] \displaystyle \frac{d}{dt}[b\, \sin(Q)]\\[0.5em]\displaystyle \frac{d}{dt}[c \cdot t]\end{bmatrix} = \begin{bmatrix}0 \\ 0 \\ c\end{bmatrix}\end{aligned}[/tex].

The speed [tex]v[/tex] (a scalar) of a particle is the magnitude of its velocity :

[tex]\begin{aligned}v(t) &= \| \mathbf{v}(t) \| \\ &= \left\|\begin{bmatrix}0 \\ 0 \\ c\end{bmatrix}\right\| \\ &= \sqrt{0^2 + 0^2 + c^2} = c\end{aligned}[/tex].

Therefore, the speed of this particle is constantly [tex]c[/tex] (a constant.)

What body system,
respiratory system
Circulatory system
Digestive system
Nervous system


Affects ulcer disease and heartburn.


Please do this quick it is due please. I will make brainlest and give out extra points


Affects ulcer disease and heartburn.


Please do this quick it is due please. I will make brainlest and give out extra points!

Answers

Answer:

Digestive system

Explanation:

ulcer affect anywhere in the digestive system

Digestive system.

Since the acids in your food break down with the chemicals in your stomach, it can give you heartburn and also, ulcer disease happens in your stomach so the only correct answer would be Digestive System. I would like to say that the person with the profile name BigPapa who commented on my answer deserves a lot of credit, and thanks if you see this.

-R3TR0 Z3R0

The magnitude obtained when adding vector A (80 N at 20 deg) with vector B (40 N at

70 deg) is:

110.06 N

89.85 N

0 130.32 N

0 141.98 N

Answers

Answer:

110.06N

Explanation:

The magnitude of the force is known as the resultant.

R = √Fx²+Fy²

Fx = 80cos 20 + 40cos70

Fx = 80(0.9397)+40(0.3420)

Fx = 75.176 + 13.68

Fx = 88.856N

Fy = 80sin 20 + 40sin70

Fy = 80(0.3420)+40(0.9397)

Fy = 27.36 + 37.588

Fy = 64.948N

R = √88.586²+64.948²

R = √7,847.48+4,218.24

R = √12,065.72

R = 109.5

R = 110N

Hence the magnitude of the forces is 110N

Light rays travel from one medium into another and refract away from the boundary. What changes about the light to cause this refraction?

A. Its speed increases.
B. Its frequency increases.
C. Its frequency decreases.
D. Its speed decreases.​

Answers

Answer:

a

Explanation:

I think its a its speed increases.....

Two light bulbs are 2.0 m apart. From what distance can these light bulbs be marginally resolved by a small telescope with a 4.50 cm. Assume that the lens is limited only by diffraction and λ = 600 nm

Answers

Answer:

R = 1.2295 10⁵  m

Explanation:

After reading your problem they give us the diameter of the lens d = 4.50 cm = 0.0450 m, therefore if we use the Rayleigh criterion for the resolution in the diffraction phenomenon, we have that the minimum separation occurs in the first minimum of diffraction of one of the bodies m = 1 coincides with the central maximum of the other body

            θ = 1.22 λ / D

where the constant 1.22 leaves the resolution in polar coordinates and D is the lens aperture

             

how angles are measured in radians

          θ = y / R

where y is the separation of the two bodies (bulbs) y = 2 m and R the distance from the bulbs to the lens

            [tex]\frac{y}{R} = 1.22 \frac{ \lambda}{D}[/tex]

            R = [tex]\frac{ y \ D}{1.22 \lambda}[/tex]

let's calculate

            R = [tex]\frac{ 2 \ 0.045}{ 1.22 \ 600 \ 10^{-9}}[/tex]

            R = 1.2295 10⁵  m

unpolarized light of intensity Io is incident on an ideal linear polariser (no absorption) . what is the transmitted intensity?​

Answers

Answer:

A Polarizing sheet transmits only the component of light polarized along a particular direction and absorbs the component perpendicular to that direction.

Consider a light beam in the z direction incident on a Polaroid which has its transmission axis in the y direction. On the average, half of the incident light has its polarization axis in the y direction and half in the x direction. Thus half the intensity is transmitted,and the transmitted light is linearly polarized in the y direction.

DOES ANYONE KNOW HOW TO DO THIS?

Question:

Convert 68 MHz to Hz.

Answers

Answer:

68000

Explanation:

1 MHz = 1000 Hz

just multiply by 1000 :)

If a truck has a mass of 7,692 kg and travels at a speed 51 m/s what is the momentum of the truck

Answers

Answer:

Explanation:

Given the following data;

Velocity = 51 m/s

Mass = 7,692 kg

To find the momentum;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

[tex] Momentum = mass * velocity [/tex]

Substituting into the equation, we have;

Momentum = 7692 × 51

Momentum = 392292 Kgm/s

A bicyclist rides 5.0 km due east, while the resistive forcefrom the air has a magnitude of 3.0 N and points due west. Therider then turns around and rides 5.0 km due west, back to herstarting point. The resistive force from the air on the return triphas a magnitude of 3.0 N and points due east.
a) Find the work done by the resistive force during the roundtrip.
Based on answer in part A.
b) Is the resistive force a conservative force? explain.

Answers

Answer:

a) Find the work done by the resistive force during the roundtrip.

W=-30kJ

b) Is the resistive force a conservative force? explain.

The resistive force is not a conservative force since the work done during the round trip is not zero

Explanation:

The worf done on object y a constant force F is given by:

W= (F  cos ∅)S

Where S is the displacement and ∅ is the angle between the force and the displacement.

The displacement of the bicycle during each part of the trip is s=5000m and teh magnitude of teh resistance force is F=3.0N

∅1=180° he angle between the displacement and the force

W1=W2

W1 = (3.0 cos180) 5000m

W1=-15.O kJ

W=W1+W2

W=-30kJ

The resistive force is not a conservative force since the work done during the round trip is not zero

(a) The work done by the resistive force is 15,000 J

(b) The work done the resistive force is non-conservative since the resultant resistive force in not zero.

Work done

Work is said to be when an applied force displaces an object from its initial position.

Work done by resistive force

The work done by the resistive force is calculated as follows;

W = FΔr

W = 3 x (5,000 - 0)

W = 15,000 J

Thus, the work done the resistive force is non-conservative since the resultant resistive force in not zero.

Learn more about conservative force here: https://brainly.com/question/15357875

A cork dropped into a water filled beaker floats with volume V1 representing the portion of cork above water. When it is dropped in a beaker containing corn syrup, it floats with its volume V2 (again, the portion of cork above syrup). How do these volumes compare?A. V1 = V2.B. V1 > V2.C. V1 < V2.D. V1 ≥ V2.

Answers

Answer:

C. V1 < V2

Explanation:

The computation is shown below:

As we know that

Byoyancy force represent the displaced water weight

[tex]B = V_{in},_{w}P_{w}g[/tex]

[tex]V_{in},_{w}[/tex] denotes cork volume that inside the water

[tex]P_{w}[/tex] denotes water density

And, byoyancy force represent the displaced weight of corn syrup

[tex]B = V_{in},_{syr}P_{syr}g[/tex]

[tex]V_{in},_{syr}[/tex] denotes the cork volume that inside the water

[tex]P_{syr}[/tex] denotes syrup density

Now

[tex]P_{syr}>P_{w}\\\\V_{in},_{syr}<V_{in},_{wat}\\\\V_2>V_1 or V_1 <V_2[/tex]

Hence, the option c is correct

It is necessary to to secure an inflated balloon tightly give reason

Answers

Yea if you want it to be filled up but if not then no

Please answer my head is about to explode.

Answers

Answer:

290

Explanation:

I tried not so certain abt the answer

Answer:

Explanation:

Givens

Mass: 1450 kg

vi = 0

a = 5 m/s^2

vf=?

Formula

KE = 1/2 m v^2

d = vi * t + 1/2 a t^2

a = (vf - vi)/t

Solution

The final KE = 0 because the final velocity = 0 (The concrete wall saw to that).

Second formula

d = vi*t  + 1/2 a t^2

20  = 0 + 1/2 * 5 * t^2

40 = 5*t^2                         Divide by 5

40/5 = t^2

8 = t^2

2√2 = t

Third formula

5 = (vf - 0)/2√2                Multiply by 2√2

5* 2√2 = vf

10√2= vf

First formula

KE = 1/2 m * (10√2)^2

KE = 1/2 1450 * 100*2

KE = 1450 * 100              2 and 1/2 cancel out.

KE = 145000

This means that the change in KE is 145000 Joules or 145 kJ

If the mass of the object doubles then the acceleration is when the force is kept the same

Answers

Answer:

Halved

Explanation:

F=ma

Let case 1 (original) be:

[tex]F_{1}=m_{1} a_{1} \\[/tex]

Case 2 (new) be:

[tex]F_{2}=m_{2} a_{2}[/tex]

Mass is double:

[tex]m_{2}= 2m_{1}[/tex]

Force kept the same:

[tex]F_{1} =F_{2}[/tex]

Combine the equation and gives:

[tex]\frac{F_{1} }{F_{2}} =\frac{m_{1} a_{1} }{m_{2}a_{2} }\\\frac{F_{1} }{F_{1}} =\frac{m_{1} a_{1} }{2m_{1}a_{2} }\\1=\frac{a_{1} }{2a_{2} }\\a_{2}=\frac{1}{2} a_{1}[/tex]

Acceleration is halved

An object is placed in material a at point P, as shown in the diagram. The light is refracted when it strikes the interface with material b. When viewed from material b, at which point will the image appear?

Answers

B because the areas of f can be 7 or higher

The spectral classification of Antares is

Answers

Answer:

M1.5Iab-Ib

Explanation:



Name the nutrients required for the
body.​

Answers

Answer:

1- water

2- fat

3- carbohydrates

4- vitamins

5- minerals

HELP ASAP WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST!!!
A car with a mass of 1,200 kg accelerates at a rate of 3.0 m/s^2 forward. What is the force acting on the car?

Answers

Answer:

the force acting on the car is 3600 N

Explanation:

The computation of the force acting on the car is shown below:

As we know that

Force = mass × acceleration

= 1200 kg × 3.0 ms/^2

= 3600 N

hence, the force acting on the car is 3600 N

A Carnot engine operates between 1350 °F and 125 °F. If it rejects 55 Btu as heat, determine the work output.
a. W =68.54 Btu
b. W=145.19 Btu
c. W = 115.12 Btu
d. W=235.7 Blu

Answers

Answer:

C. [tex]W = 115.12\,Btu[/tex]

Explanation:

Thermodynamically speaking, a Carnot engine represents an entirely reversible thermal process and its energy efficiency represents the maximum theoretical efficiency that thermal machines can reach. The efficiency of the ideal thermal process ([tex]\eta[/tex]), no unit, is:

[tex]\eta = \left(1-\frac{T_{L}}{T_{H}} \right)[/tex] (1)

Where:

[tex]T_{L}[/tex] - Temperature of the cold reservoir, measured in Rankine.

[tex]T_{H}[/tex] - Temperature of the hot reservoir, measured in Rankine.

If we know that [tex]T_{H} = 1809.67\,R[/tex] and [tex]T_{L} = 584.67\,R[/tex], then the energy efficiency of the ideal thermal process is:

[tex]\eta = 0.678[/tex]

By First Law of Thermodynamics, we calculate the work output:

[tex]W = Q_{H}-Q_{L}[/tex]

[tex]W = \frac{W}{\eta} -Q_{L}[/tex] (By definition of efficiency)

[tex]Q_{L} = \frac{W}{\eta}-W[/tex]

[tex]Q_{L} = \left(\frac{1}{\eta}-1 \right)\cdot W[/tex](2)

Where:

[tex]Q_{H}[/tex] - Heat received by the engine, measured in Btu.

[tex]Q_{L}[/tex] - Heat rejected by the engine, measured in Btu.

[tex]W[/tex] - Work output, measured in Btu.

If we know that [tex]\eta = 0.678[/tex] and [tex]Q_{L} = 55\,Btu[/tex], then the work output of the Carnot engine is:

[tex]W = \frac{Q_{L}}{\frac{1}{\eta}-1 }[/tex]

[tex]W = 115.807\,Btu[/tex]

The work output of the Carnot engine is 115.807 Btu. (Answer: C)

If the magnitude of vector A⃗ is less than the magnitude of vectorB⃗ , then the x component of A⃗ is less than the x component ofB⃗ . If the magnitude of vector is less than the magnitude of vector, then the component of is less than the component of.



a. True


b. False

Answers

False ?
I’m not totally sure but I think false

A sled's mass is 9 kg. It is held in place on a frictionless 16-degree slope by a rope attached to a stake at the top of the slope. What is the tension in the rope if it is parallel to the slope?

Answers

Answer:

The tension in the rope if it is parallel to the slope is 24.31 N.

Explanation:

Given;

mass of the sled, m = 9 kg

angle of inclination of the slope, θ = 16⁰

The tension in the rope if it is parallel to the slope is calculated from the parallel component of the tension;

[tex]T_|_| = mgSin \theta\\\\T_|_| = 9 \times 9.8 \times sin(16^0)\\\\T_|_| = 24.31 \ N[/tex]

Therefore, the tension in the rope if it is parallel to the slope is 24.31 N.

A 20 cm radius ball is uniformly charged to 70 nC.
(a) What is the ball's charge density?
(b) How much charge is enclosed by spheres of radii 5, 10 and 20 cm?
(c) What is the electric field strength at points 5, 10 and 20 cm from the center?

Answers

Answer:

Explanation:

A)

Density= charge/total volume .......eqn(1)

But volume= 4/3πr^3

r= radius= 20 cm= 0.20m

If we substitute into the volume equation, we have

volume= 4/3 * 3.142 *( 0.20)^3

= 0.0335 m^3

The volume= 0.0335 m^3

Charge=71 nC= 71×10^-9

If we substitute into eqn(1) we have

Density= (71 *10^-9C )/0.0335

= 2.11µc/m^3

B) charge enclose= Density × volume

spheres of radii are

5cm

10 cm

20 cm

Volume for 5cm

V= 4/3 * 3.142 *( 0.05)^3 = 0.0005237 m^3

charge enclose=2.11µc/m^3×0.0005237

charge enclose= 2.110 nC

Volume for 10cm

V= 4/3 * 3.142 *( 0.10)^3 = 0.004189 m^3

charge enclose= 2.11µc/m^3 ×0.004189

=8.9 nC

Volume for 20cm

V= 4/3 * 3.142 *( 0.20)^3 = 0.0335 m^3

charge enclose= 71nC

A car turns a certain curve of radius 24.98 m with constant linear speed of
15.67 m/s. If the centripetal force experienced by that car is 34.652 kN, what is the
mass of the car?

Answers

Answer:

3525.19 kg

Explanation:

The computation of the mass of the car is shown below:

As we know that

Fc = m × V^2 ÷ R

m = Fc × R ÷ V^2

Provided that:

Fc = 34.652 kN = 34652 N

R = Radius = 24.98 m

V = speed = 15.67 m/s

So,

m = 34652 × 24.98 ÷ 15.67^2

 = 3525.19 kg

A 107 kg boat that is 7 m in length is initially 7.3 m from the pier. A 53 kg child stands at the end of the boat closest to the pier. The child then notices a turtle on a rock at the far end of the boat and proceeds to walk to the far end of the boat to observe the turtle. 7.3 m 7 m How far is the child from the pier when she reaches the far end of the boat

Answers

Answer:

11.98 m

Explanation:

Given that:

mass of the child [tex]m_c[/tex] = 53 kg

mass of the boat [tex]m_b[/tex] = 107 kg

[tex]\text{length of the boat L = 7 m}[/tex]

the distance of the boat from pies l = 7.3 m

initial momentum [tex]P_i = 0[/tex]

Final momentum [tex]P_f = mc \dfrac{L}{f}- (m_c +m_b) \dfrac{x}{l}[/tex]

where;

x = distance moved by boat towards left

t = time taken for the child to travel to the far end of the boat

[tex]P_i =P_f[/tex]

[tex]m_c \dfrac{L}{t}=(m_c +m_b) \dfrac{x}{t}[/tex]

Then;

[tex]x = \dfrac{m_cL}{m_c+m_b}[/tex]

[tex]x = \dfrac{53 \times 7}{53+107}[/tex]

x = 2.32 m

The distance of the child from the pier is:

d = L +(l - x)

d = 7 m + ( 7.3 m - 2.32 m)

d = 7 m + 4.98 m

d = 11.98 m

what was Thomas Edison first major invented? ​

Answers

Answer:

Thomas Edisons most famous invention was the phonograph

Thomas Edison announces his invention of the phonograph, a way to record and play back sound. Edison stumbled on one of his great inventions—the phonograph—while working on a way to record telephone communication at his laboratory in Menlo Park, New Jersey.

Explanation:

Hope I helped

23. Christina wanted to know whether the eating behavior of goldfish is affected by music. She set up a fish

tank. Every day, she played music for the fish and measured how much the fish ate. What is Christina

missing from this experiment?

A. a control group

B. a measurable result

C. a dependent variable

D. different types of fish

Answers

Answer:

a control group

Explanation:

To have a succsessful experiment you need something to compare your variable to.

pers
2. (a) Calculate the virtual depth of a black dot at the
bottom of a cubic block made of transparent glass with each
side 4 cm, while the refractive index of glass is 1.6.​

Answers

Answer:

2.5 cm

Explanation:

Using the relation :

Refractive index = Real Depth / Apparent depth

Refractive index = 1.6

Real depth = 4cm

Virtual depth = apparent depth = x

1.6 = 4cm / x

1.6x = 4

x = 4 / 1.6

x = 2.5

Hence, virtual depth = 2.5cm

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