Answer:
echosounding
Explanation:
The time taken for the sound to travel through the ocean and back is then used to calculate water depths. The faster the sound waves return, the smaller the water depths and the higher the elevation of the seafloor.
i am giving brainly to however answers first
A student made the table to showing how different objects transform electrical energy. Which statement best explains why the table is incorrect?
Item Transformed Energy
Radio Electrical → Sound
Lamp Electrical → Light
Doorbell Electrical → Motion
Iron Electrical → Heat
The doorbell transforms electrical energy into sound.
The iron transforms electrical energy into light.
The lamp transforms electrical energy into sound.
The radio transforms electrical energy into heat.
Answer:
The doorbell transforms electrical energy into sound.
Explanation:
The doorbell MAY turn electrical energy into motion of a striker which then impacts a resonator creating sound. However all door bells do not have solenoids. Some are electronic playing recordings when activated.
All doorbells do produce sound, though.
You wear lead to protect you from ____.
1. microwaves
2. gamma rays
3.x_rays
4. infrared
Make a rule: If you know the width, length, and mass of a boat, how can you calculate how deep it will sink in water
Answer:
U would need to know the depth of the water
Explanation:
explain why oxygen-16 and 16/8o are not considered isotopes
Answer:
Each oxygen isotope has 8 protons but a different amount of neutrons. The mass of an isotope is represented by its isotope number. As a result, oxygen 16 has eight protons and eight neutrons, oxygen 17 has eight protons and nine neutrons, and oxygen 18 has eight protons and ten neutrons.
Explanation:
A 25kg cannon ball is shot out of a 1600 kg cannon that is initially at rest . When fired the velocity of the cannon ball is 200m/s. What is the recoil velocity of the cannon?
The correct answer is the recoil velocity of the cannon is equal to 90m/s.
The recoil velocity of the cannon is equal to 3.125m/s.
What is law of conservation of linear momentum?According to this law, the sum of the momentum before and after the collision must be equal.
m₁ u₁ + m₂u₂ = m₁v₁ + m₂ v₂
where m₁ and m₂ is the mass of the collided bodies, u₁ and u₂ are initial speed while v₁ & v₂ is final speed.
Conservation of momentum is a characteristic held by an object where the total amount of momentum never changes.
Given the mass of the cannonball, m₁ = 25 Kg
The velocity of the cannonball, v₁ = 200 m/s
The mass of the cannon, m₂ = 1600 Kg
Assume that v₂ is the recoil velocity of the cannon.
From the law of conservation of momentum: P(initial) = P (final)
m₁ v₁ = m₂ v₂
25 × 200 = 1600 × v₂
v₂ = 3.125 m/s
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Sarah and Tom are riding on a merry-go-round revolving at a constant rate. Sarah is sitting on the edge and Tom is half-way in from the edge. What is the relationship between their centripetal accelerations
The centripetal acceleration of Tom sitting half-way from the edge of the merry-go-round is double of the centripetal acceleration of Sarah sitting at the edge of the merry-go-round.
Let the constant rate of their motion, = v
Let the radius of the merry-go-round = R
The centripetal acceleration of Sarah sitting at the edge of the merry-go-round is calculated as;
[tex]a_c_1 = \frac{V^2}{R}[/tex]
The centripetal acceleration of Tom sitting half-way from the edge of the merry-go-round is calculated as;
[tex]a_c_2 = \frac{V^2}{\frac{1}{2} \times R } \\\\a_c_2 = \frac{2V^2}{R} \\\\a_c_2 = 2(\frac{V^2}{R} )\\\\a_c_2 = a_c_1[/tex]
Thus, the centripetal acceleration of Tom sitting half-way from the edge of the merry-go-round is double of the centripetal acceleration of Sarah sitting at the edge of the merry-go-round.
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A 1500-kg car accelerates from 0 to 25 m/s in 7.0 s. What is the average power delivered by the engine (1 hp
A ball is Thrown straight up with a speed of 30 M/S, and air resistance is negligible what is its velocity after 4.2s
Answer:
11.2 m/s
Explanation:
We need to first figure out how long it took to reach the ball's max height:
Vf = 0
Vi = 30 m/s
a = -9.81 m/s^2
t = ?
---------------
Vf = Vi + at
0 = 30 + (-9.81)t ---> -30 = -9.81t ---> 3.058 = t
t = 3.058 s
---------------
We can now solve the problem by subtracting the given time (4.2s) by the max height time (3.058s) and plugging that into a kinematic equation for Vf:
Vi = 0
a = 9.81 m/s^2
t = (4.2s - 3.058s) = 1.142 s
Vf = ?
---------------
Vf = Vi + at
Vf = 0 + (9.81)*(1.142) ---> Vf = 11.203
---------------
The velocity of the ball after 4.2s is 11.2 m/s
Suppose that an object of mass 11.4 g is hung from a vertical spring that is stretched 10 cm as a result. What is the spring constant of this spring, in N/m
A plane traveling 3.1 m/s east encounters wind traveling 4.7 m/s north. The wind current is 18 m wide. Determine the time to cross the wind current.
An arrow is shot straight up in the air from the ground with an initial velocity of 54.0 m/s. If on striking the ground it
embeds itself 15.0 cm into the ground, what is the acceleration required to stop the arrow when it hits the ground?
hindi ko po alam yan sorry po
when 15 newtons of force is applied to the 0.50 kg book, the friction keeps the book from sliding down the wall
The minimum force to keep the book from sliding is 15 N.
The minimum coefficient of friction to keep the book from sliding is 0.33.
The given parameters;
applied force, F = 15 Nmass of the book, m = 0.5 kgThe normal force on the book is calculated as;
[tex]F_n = mg\\\\F_n = 0.5 \times 9.8\\\\F_n = 4.9 \ N[/tex]
The minimum force to keep the book from sliding is calculated as;
[tex]F - F_s = 0\\\\F_s = F\\\\F_s = 15 \ N[/tex]
The minimum coefficient of friction to keep the book from sliding is calculated as;
[tex]\mu_s F = F_n\\\\\mu_s = \frac{F_n}{F} \\\\\mu_s = \frac{4.9}{15} \\\\\mu_s = 0.33[/tex]
"Your question is not complete, it seems to be missing the following information";
When a force of 15 newtons is applied to the 0.50 kg book, the friction keeps the book from sliding down the wall. What is the minimum force and minimum coefficient of friction to keep the book from sliding?
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Please help
Which statement is true in this situation?
Answer:
b
Explanation:
because the of F frick is the same of the size of F app
Identify if the verbs signal past, future, or present tense, and drag them to the appropriate box. I walked home. She will walk home. It will open next week. She studied. He made a list. She walks home. They leave the door open. W Past Present Future
Answer:
Past
I walked home.
She studied.
He made a list.
Present
She walks home.
They leave the door open.
Future
She will walk home.
It will open next week.
Explanation:
Explain one way the pattern of the moon would be affected if the moon took longer time to orbit the earth
Each day the Moon's appearance changes depending on where it is in its earth orbit. The pattern of day and night is followed only due to the rotation of the earth.
What is the rotation of the Earth?The phrases revolution and rotation describe the various movements of the earth. Rotation is the tendency of the planet on its axis.
The movement of the earth around the sun is a definite path or orbit known as revolution. The earth's axis, a fictional line, makes a 6612° angle with its orbital plane.
The rotation of the earth on its axis does not cause night and day. The occurrence of night and day is caused by the rotation of the earth.
The lunar cycle begins when the Sun, Moon, and Earth are aligned (the Moon is between the Earth and the Sun, and the hemisphere of the Moon faces away from the Earth.
As a result, if the moon took longer to orbit the Earth, the pattern would be disrupted.
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sjkdvsndjkvnisdvnuisbvibsdv.
Answer:
hello!
Explanation:
Hello, I want to ask. . anyone knows the answer.
Answer:
1 tablet
Explanation:
The closest rounding of 1.04 that is in the answers is 1.
What power (in horsepower) is developed by a grinding machine whose wheel has a radius of 8.89 in and runs at 7.42 rev/s, when the tool to be sharpened is held against the wheel with a force of 47.3 lb
Answer:
P = W / t definition of power
P = F s / t = F v t / t = F v power expended
v = 2 pi R f f = frequency = rev / sec (S = 2 pi R n = 2 pi R f t)
and v = S / t
P = F 2 pi R f = 47.3 lb * 6.28 * .741 ft * 7.42 / sec = 1630 ft-lb/sec
(1630 ft-lb/sec) / (550 ft-lb/sec / HP) = 2.96 HP
please HELP IM SOO STUCKKK
A 3.75 kg bucket of water attached
to a rope is swung in a 0.555 m
circle. At the bottom, the tension
in the rope is 172 N. What is the
speed of the bucket at that point?
Answer:
look at the photo........................
Answer:
4.46 is the correct answer
Explanation:
help this is urgent ;-;
What is the mass of a person who
weighs 343 N?
m
[?] kg
Answer:
the answer is 343/9.8=35
Explanation:
the answer is 35 because mass=weight/gravity
The mass of a person who weighs 343 N is 35.0 kg.
What are mass and weight?
The most fundamental characteristic of matter is mass, which is one of the fundamental quantities in physics. Mass is a term used to describe how much matter is there in a body. The kilograms is the SI unit of mass (kg).
Weight is a measurement of how much gravity is pulling on a body.
The weight formula is as follows: w = mg
Since weight is a force, it has the same SI unit as a force, which is the Newton (N). It depends on both mass and the acceleration caused by gravity.
The weighs of the person is = 343 N
The mass of the person is = weighs of the person ÷ acceleration due to gravity
= 343 N ÷ 9.80 m/s²
= 35.0 kg.
Hence, the mass of the person is 35.0 kg.
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A strechy material with a spring constant of 42 N/m is stretched 3.6 cm from its equilibrium length. What is the magnitude of the resulting spring force
The force acting on a stretchy material is the product of of the spring constant and the displacement by stretching of the material. Thus, resultant force of the material with a spring constant o 42 N/m with a displacement of 3.6 cm is 1.51 N downwards.
What is force?Force is an external agent acting on a body to change it form the state of rest or motion. There are various kinds of forces such as gravitational force, nuclear force, magnetic force, frictional force etc.
A stretching material such as a string will experience an elastic nature. The force F acting on the spring is directly proportional to the its displacement X. The proportionality constant is called spring constant.
Hence we can write it as ,
F = -kx
Here, the spring constant is given 42 N/m and displacement is 3.6 cm or 0.036 m. Now the force is calculated as follows:
Force = -0.036 m × 42 N/m
=- 1.51 N
The negative sign indicates the direction is downwards.
Thus, the force acting on the material is 1.51 N.
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A jet needs to reach a "lift-off' speed of 120 m/s before it can leave the ground. How quickly must
the jet accelerate if the run way has a length of 322 m?
The jet must accelerate in 5.37 s if it must reach the lift-off speed
From the question given above, the following data were:
Initial velocity (u) = 0 m/s
Final velocity (v) = 120 m/s
Distance (s) = 322 m
Time (t) =?The time needed for the jet to accerate can be obtained as follow:
[tex]s = \frac{(v + u)t}{2} \\ \\ 322 = \frac{(120 + 0)t}{2} \\ \\ 322 = \frac{120t}{2} \\ \\ cross \: multiply \\ \\ 120t = 322 \times 2 \\ \\ 120t = 644 \\ \\ divide \: both \: side \: by \: 120 \\ \\ t = \frac{644}{120} \\ \\ [/tex]
t = 5.37Thus, the jet must accelerate in 5.37 s in order to reach the lift-off speed
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As the jet leaves the ground, it accelerates at a rate of 22.4 ms-2.
We have the following information from the question;
Final velocity = 120 m/s
Initial velocity = 0 m/s
Distance covered = 322 m
Acceleration = ?
Using the equation;
v^2 = u^2 + 2as
v = final velocity
u = initial velocity
a = acceleration
s = distance
(120)^2 = 0^2 + (2 × a × 322)
14400 = 644a
a = 14400/644
a = 22.4 ms-2
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The gravitational force between two objects is represented by the variable F.
If the masses are both doubled and the distance is halved, what is the new gravitational force?
Explanation:
Fgravity = G*(mass1*mass2)/D²
G is the gravitational constant, which has the same value throughout our universe.
D is the distance between both objects.
now, we change these numbers
Fgravitynew = G*(2*mass1*2*mass2)/(1/2 * D)² =
= G*(4*mass1*mass2)/(D²/4) =
= 4* (G*(mass1*mass2)/D²) *4 =
= 16* (G*(mass1*mass2)/D²) = 16*Fgravity
so, the new gravitational force will be 16×F.
A 2kg pumpkin is thrown with a velocity of 15m/s towards a brick wall. The pumpkin comes to a crashing rest (0m/s) in 0.05 seconds. What is the force exerted on the pumpkin by the wall?
The force exerted on the pumpkin by the wall is 600 N
From the question given above, the following data were obtained:
Mass (m) = 2 Kg
Initial velocity (u) = 15 m/s
Final velocity (v) = 0 m/s
Time (t) = 0.05 s
Force (F) =?The force exerted on the pumpkin by the wall can be obtained as follow:
[tex]f = \frac{m(v + u)}{t} \\ \\ f = \frac{2(0 + 15)}{0.05} \\ \\ f = \frac{2 \times 15}{0.05} \\ \\ f = \frac{30}{0.05} \\ \\ [/tex]
F = 600 NTherefore, the force exerted on the pumpkin by the wall is 600 N
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how long in seconds would it take a rock to fall 450 feet and what would be the final velocity of the rock in miles per hour when it hit the ground
Answer:
S = Vy t + 1/2 g t^2 = 1/2 g t^2 vertical speed with zero initial speed
t = (2 S / g)^1/2 with g = 32 ft/sec^2
t = (900 / 32)^1/2 = 5.30 sec time to reach ground
V = a t = 32 ft/s^2 * 5.30 s = 170 ft/sec
170 ft/sec / (88 ft/sec / 60 mph) = 116 mph since 88 ft/sec = 60 mph
Plane-polarized light is incident on a single polarizing disk with the direction of E0 parallel to the direction of the transmission axis. Through what angle should the disk be rotated so that the intensity in the transmitted beam is reduced by a factor of 1.22
Malus's law allows us to find the result for which is the angle of the polarizer for a reduction of the intensity is:
θ = 34.9º
Malus's law establishes a mathematical relationship for the light transmitted by a polarizer is:
I = I₀ cos² θ
where I and I₀ are the transmitted and incident intensities, respectively, θ is the angle between the two polarizers.
They indicate that the incident light is polarized, so we do not need the first polarized to create the polarized light, ask what the polarized angle should be for the intensity to be reduced by a factor.
[tex]\frac{I_o}{I } = 1.22 \\\frac{I}{Io} = 0.81967[/tex]
Let's use Malus's law
i / Io = cos² θ
cos θ = [tex]\sqrt{\frac{I}{I_o} }[/tex]
θ = cos⁻¹1 0.81967
θ = 34.9º
In conclusion, using Malus's law we can find the angle of the polarized for a reduction of the intensity is:
θ = 34.9º
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Please list the following for the Element, HYDROGEN
Number of protons, number of electrons, and number of neutrons
Period number
Group number
Name of group to which it belongs (i.e., alkali metals, alkaline earth metals, halogens,
noble gases, and so on)
PLEASE INCLUDE ALL INFORMATION THANK YOU! WILL MARK BRAINLIEST IF ANSWERED CORRECTLY
Answer:
1 Proton, 1 Electron, No Neutrons
Group 1, Period 1
Gases
One factor that could account for a drop in the water table is:
A. more wind.
B. less porous soil.
C. more clouds.
D. less rain and snow.
Answer:
D. Less rain and snow.
Explanation:
A factor that can be a account for a drop in the water table is, less rain and snow. to topography, water tables is influenced by lot of factors, including the geology, weather, ground cover.
According to Washington, is a strong central government important?
Answer:
According to Washington, the most important factor in sustaining the independence of the United States was protecting the unity of the states. ... Members of the Democratic-Republican Party believed that a strong federal government would not respect the rights of the states and the people.
Explanation:
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