The table shows the weights of a sample of packages carried by an air freight company last month. Find the mean deviation for the data in the quantity column.
Select one:

8.09

1.52

2.84

6.18

Answer:

1.52

Step-by-step explanation:

[tex]\frac{5 + 9 + 5 + 6 + 8 }{5} = \frac{33}{5} = 6.6[/tex]

distance from 6.6

5,  1.6

9,  2.4

5,  1.6

6,   .6

8,  1.4

[tex]\frac{1.6 + 2.4 + 1.6 + .6 + 1.4}{5} = \frac{7.6}{5} = 1.52[/tex]

The mean deviation of the data set is 1.52. The correct option is B.

Mean is defined as the ratio of the sum of the number of data sets to the total number of data.

First, calculate the mean of the data set and then the deviation of each data set.

The mean is calculated as,

Mean =(5+9+5+6+8)/5

Mean = (33/5)

Mean = 6.6

The deviation is,

5      1.6

9      2.4

5      1.6

6      0.6

8      1.4

The mean deviation is calculated as,

Mean = ( 1.6 + 2.4 + 7.6 + 0.6 + 1.4 ) / 5

Mean = 7.6 / 5

Mean = 1.52

Therefore, the mean deviation of the data set is 1.52. The correct option is B.

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