Answer: 29.17m/s^2
Explanation:
Given the following :
Velocity = 525 m/s
Time = 18 seconds
Acceleration = change in Velocity with time
Using the motion equation:
v = u + at
Where v = final Velocity
u = Initial Velocity and t = time
Plugging our values
525 = 0 + a × 18
525 = 18(a)
a = 525 / 18
a = 29.166666
a = 29.17 m/s^2
A tuning fork is vibrating the air around it. What best describes the waves produced by the tuning fork?
Answer:
The water particles move in the same direction as the vibrating source of the sound wave. ... What best describes the waves produced by the tuning fork? mechanical, because the vibrating tuning fork makes air molecules around it vibrate. A wave is produced in a Slinky as shown.
Explanation:
Answer:
mechanical, because the vibrating tuning fork makes air molecules around it vibrate
Explanation:
the components and functionality of the event horizon telescope.
Answer:
The Event Horizon Telescope comprises of a an interconnection of radio observatories. These radio observatories work in unison and helps in efficient observation of radio sources associated with black holes with angular resolution in comparison to their event horizons. This equipment functions by ensuring that anything or light which goes through the event horizon cannot escape from the black hole. Instead there will be a continual falling towards the center of the black hole.
A box that has a mass of 80 kg slides down a ramp with a 30 degree angle. The free-body diagram shows the forces acting on the box. A block is shown on a 30-degree incline with a free body diagram drawn on the block with 2 force vectors. The first vector is pointing away from the surface of the incline and perpendicular to the surface, labeled F Subscript N Baseline. The second vector is pointing straight down to the center of the earth, labeled F Subscript g Baseline. Ignoring friction and air resistance, what is the acceleration of the box, to the nearest tenth? 0.5 m/s2 4.9 m/s2 8.5 m/s2 9.8 m/s2
HOW TO DO IT
Answer:
B. 4.9 m/[tex]s^{2}[/tex]
Explanation:
The parallel vector, [tex]F_{g}[/tex], make the box to accelerate down the plane due to the presence of an unbalanced force.
The perpendicular component of the force will balance the normal force because the box can not accelerate perpendicularly to the plane.
i.e [tex]F_{N}[/tex] = [tex]F_{g}[/tex]
Since the box slides down the ramp, neglecting friction and air resistance;
[tex]F_{g}[/tex] = ma
mg Sinθ = ma
But; m = 80 kg, θ = [tex]30^{0}[/tex], g = 9.8 m/[tex]s^{2}[/tex]
80 × 9.8 × Sin [tex]30^{0}[/tex] = 80 × a
784 × 0.5 = 80 a
392 = 80 a
a = [tex]\frac{392}{80}[/tex]
= 4.9
Thus, the box accelerates down the ramp at 4.9 m/[tex]s^{2}[/tex].
Answer:
b
Explanation:
b
Se realiza un trabajo mecanico de 3500 J para levantar una cubeta con area cuyo peso tiene una determinada magnitud. Determina la altura a la que se elevo la cubeta
Answer:
10 m
Explanation:
Trabajo (W) = 3500 J, peso de la cuchara (F) = 350 N.
El trabajo es el producto de la fuerza que actúa sobre un objeto y la distancia o desplazamiento. La unidad de trabajo estándar son los joules (J).
Trabajo (W) = fuerza (F) × distancia (d)
W = F × d
[tex]d=\frac{W}{F} =\frac{3500J}{350}=10m[/tex]
el cubo se elevó a 10 m
The height (distance) to which the bucket was raised is equal to 10 meters.
Given the following data:
Work done = 3500 JoulesWeight of bucket = 350 NewtonTo determine the height (distance) to which the bucket was raised:
Mathematically, work done is given by the formula:
[tex]Work\;done = Force \times distance[/tex]
Substituting the given parameters into the formula, we have;
Note: Force = weight.
[tex]3500 = 350 \times distance\\\\Distance = \frac{3500}{350}[/tex]
Distance = 10 meters.
Read more: https://brainly.com/question/22599382
when scientists publish experimental results their results are often criticized by other scientists how is this process a source of strength of Science? It encourages scientists to give convincing evidence for the results
it allows scientists to keep their data secret
a scientific model is not used full unless everyone thinks it's true
or if forces scientists to publish results that are in line with current theories
Answer: It encourages scientists to give convincing evidence for the results
Answer:
A.) would be the right answer
Explanation:
I took the test :)
which of the following terms describes a machine that converts heat into work?
A. Entropy pump
B. Heat engine
C. Heat pump
D. Entropy engine
Answer: A
Heat engine
Explanation: just took the test
What is a resistor? A. a light bulb B.a switch C. a battery
Answer:
A resistor is a battery
Answer:
The answer is A
Explanation:
A resistor is a light bulb because it is the flow of an electric current in an electric circuit.
what are two things that are infinite?
Answer:
Infinity = Never ending
Explanation:
The universe could be infinite, both in terms of space and time, but there is currently no way to test whether it goes on forever or is just very big. The part of the universe we are able to observe is finite, measuring about 46 billion light years in diameter.
The set of natural numbers is an infinite set. This kind of infinity is, by definition, called countable infinity. All sets that can be put into a bijective relation to the natural numbers are said to have this kind of infinity. This is also expressed by saying that the cardinal number of the set is aleph-naught (ℵ0).
Hope this helps. Mark as brainliest!
STARS ARE INFINITE , NUMBERS ARE INFINITE
Explanation:
4. ____________ occurs when one object slides over another.
a. Sliding friction
b. Static friction
c. Rolling friction
d. Net force
Answer:
A. Sliding friction
Explanation:
Sliding friction is weaker than static friction
Answer:
Rolling Friction
Explanation:
I know this because the definition of rolling friction is : type of friction that happens when one body rolls over another
How does charging by conduction work?
Answer:
During charging by conduction, both objects acquire the same type of charge. If a negative object is used to charge a neutral object, then both objects become charged negatively. ... In this case, electrons are transferred from the neutral object to the positively charged rod and the sphere becomes charged positively.
Assume that a machine puts out 8000 joules of work when the user puts in 10,000 joules of work. What is the efficiency of the machine?
Answer:
80 Percent
Explanation:
E=energy output/energy input×100
E=8000/10000×100
E=0.8×100
E=80 percent.
Mark brianliest if my answer suit your question
If the machine put, in 8000 J, and the user puts 10,000 J of work then the efficiency of the machine will be equal to 80%.
What is Work?Work is a physics term used to describe the transfer of energy that takes place when an object changes above a distance because of an external force, at least some of which is given in the vector of the dislocation. The element of the force acting all along the path multiplied by the length of the path can be used to calculate work if the force is constant.
Mathematically, this idea is expressed as W = fd, where W is the effort and f is the force multiplied by d, the distance. Work is completed whenever the force is applied at an angle with about the displacement.
As per the data provided in the question,
Total input energy = 10,000 J
Total output energy = 8,000 J
Then, the efficiency (η) of the machine will be,
η = (output energy/input energy) × 100
η = 8000/10000 × 100
η = 80%.
To know more about Work:
https://brainly.com/question/13662169
#SPJ2
Technological design leads to the development and innovation of new technologies.
Which statement represents innovation?
O Solar panels have increased in efficiency over the past 20 years.
O The Sun is the primary source of energy for the solar system
O Previous models of a type of car have fewer engine problems.
O Natural selection ensures that only the fittest survive.
Answer:
Solar panels have increased in efficiency over the past 20 years
Explanation:
Because if efficiency have increased other technologies will be discovered
Answer:
Solar panels have increased in efficiency over the past 20 years
Explanation:
Suggest what would happen to the pressure of a gas at constant temperature if the volume of the gas is halved.
Answer:
8.31 m3-Pa/mol-K
Explanation:
find the period of a simple pendulum of 1m length placed on earth and on moon g on moon =1.67m/s² g on earth=10m/s²
Answer:
[tex]T_{m }[/tex] = 4.86 s
[tex]T_{e}[/tex] = 1.98 s
Explanation:
Given:
Length = l = 1 m
Acceleration due to gravity of moon = [tex]g_{m}[/tex] = 1.67 m/s²
Acceleration due to gravity of Earth = [tex]g_{e}[/tex] = 10 m/s²
Required:
Time period = T = ?
Formula:
T = 2π [tex]\sqrt{\frac{l}{g} }[/tex]
Solution:
For moon
Putting the givens,
T = 2(3.14) [tex]\sqrt{\frac{1}{1.67} }[/tex]
T = 6.3 [tex]\sqrt{0.6}[/tex]
T = 6.3 × 0.77
T = 4.86 sec
For Earth,
Putting the givens
T = 2π [tex]\sqrt{\frac{1}{10} }[/tex]
T = 2(3.14) [tex]\sqrt{0.1}[/tex]
T = 6.3 × 0.32
T = 1.98 sec
10) Um viajante, ao desembarcar no aeroporto de Londres, observou que o valor da temperatura do ambiente na escala Fahrenheit é o quíntuplo do valor da temperatura na escala Celsius. Calcule essa temperatura
Answer:
The observed temperature was 10º Celsius or 50º Fahrenheit.
Explanation:
The traveler observed that the temperature in Fahrenheit is five times the value of the temperature in Celsius, therefore:
[tex]F = 5*C[/tex]
A Fahrenheit temperature relates to a Celsius one by the following expression:
[tex]F = \frac{9}{5}*C + 32[/tex]
Using the second expression on the first, we can solve for the temperature in Celsius, this is done below:
[tex]\frac{9}{5}*C + 32 = 5*C\\\frac{9}{5}*C - 5*C = -32\\\frac{9*C - 25*C}{5} = -32\\\frac{-16*C}{5} = -32\\-16*C = -32*5\\-16*C = -160\\C = \frac{-160}{-16} = 10\º\text{C}\\F = 5*C = 5*10 = 50\º\text{F}[/tex]
The observed temperature was 10º Celsius or 50º Fahrenheit.
A rocket is launched from atop a 101 foot cliff with an initial velocity of 116 ft/s.
\a. Substitute the values into the vertical motion formula h(t) = -16t2 + vt + h0 . Let h(t) = 0
b. How long will the rocket take to hit the ground after it is launched? Round to the nearest tenth of a second.
Answer:
A. 16t2 -116t -101=0 B. 8.0s
Explanation:
Known parameters from the question:
Height of Cliff,h0 = 101ft
Velocity of rocket ,v= 116ft/s.
1.Substituting the above to the above formula we have;
h(t) = -16t2 + vt + h0
Since h(t) =0, it means the rocket is falling towards the ground, when it gets to the ground when it's at rest the height h(t) = 0m
{Note the rocket is launched from the height of the Cliff so that would be the initial height of the rocket,h0}
2.Substituting into h(t) = -16t2 + vt + h0
We have;
0 = -16t2 + 116t + 101=> 16t2 -116t -101=0
Using formula method for solving quadratic equation we have;
t = -(-116)+_√[(-116)^2 -( 4× 16 ×-101]/ (2× 16)
t = [116 +_(141.1382)]/32
t = (116 -141.1382)/32 or (116 +141.1382)/32
-0.786s or 8.036s
-0.8s or 8.0s to the nearest tenth.
Now time cannot be negative in real life situation hence the time is 8.0s
Note : the general equation of a quadratic equation with variable t is given below;
at2 + bt + c=0
Formula method for quadratic equation is :
t =( -b+_√[(b^2 -( 4× a×c)] ) / (2× a)
what is the wavelength of the radio waves transmitted by an FM station at 90MHz where 1M=10^6 AND THE SPEED OF RADIOWAVE IS 3*10^8m/s
Answer: 0.3m
Explanation:
Given the following :
Speed of radio wave(V) = 3 × 10^8 m/s
If 1M = 10^6
Frequency(F) = 90MHz = 90 × 10^6
Wavelength (λ) =?
Speed of wave (V) = frequency(F) × wavelength(λ)
V = fλ
(3 × 10^8) = (90 × 10^6) × λ
λ = (90 × 10^6) / (3 × 10^8)
λ = 30 × 10^(6 - 8)
λ = 30 × 10^-2
λ = 0.3m
100 joule of heat produced each 1 secomd on 4ohm find the potential difference
Answer:
20 V
Explanation:
Power is 100 J/s or 100 W.
We know that P = IV = [tex]\frac{V^{2} }{R}[/tex] .
Isolate the potential difference. V = [tex]\sqrt{RP}[/tex] = [tex]\sqrt{100 * 4}[/tex] = 20 V
What is the symbol for Pressure ? Help
Answer:
The answer is Pascal or Pa.
Answer:
Pa or small p
Explanation:
Force over Area. The SI unit is Pascal
Use the worked example above to help you solve this problem. An Alaskan rescue plane drops a package of emergency rations to stranded hikers, as shown in the figure. The plane is traveling horizontally at 39.0 m/s at a height of 1.50 102 m above the ground. (a) Where does the package strike the ground relative to the point at which it was released? (b) What are the horizontal and vertical components of the velocity of the package just before it hits the ground? horizontal and vertical (c) Find the angle of the impact.
Answer:
(a) The package lands 682 meters horizontally ahead from the point the package was dropped from the plane
(b) The horizontal component = 39.0 m/s
The vertical component = 171.55 m/s
(c) The angle of impact is 77.19°
Explanation:
The parameters given are;
Velocity of the plane, vₓ = 39.0 m/s
Height of the plane above the ground, h = 1.50 × 10² m = 1,500 m
(a) The time, t, before the package hits the ground when dropped from the plane is given by the relation;
h = u·t + 1/2×g×t²
Where:
g = Acceleration due to gravity = 9.81 m/s²
u = Initial vertical velocity = 0 m/s
Hence;
1500 = 0×t + 1/2 × 9.81 × t² = 4.905·t²
∴ t = √(1500/4.905) = 17.49 s
The horizontal distance the package travels before landing = 17.49 × 39 ≈ 682 m
The package lands 682 meters horizontally ahead from the point the package was dropped from the plane
(b) The vertical velocity, [tex]v_y[/tex], of the package just before landing is given by the relation;
[tex]v_y[/tex]² = u² + 2·g·h
u = 0 m/s
∴ [tex]v_y[/tex]² = 0 + 2×9.81×1500 = 29430 m²/s²
[tex]v_y[/tex] = √29430 = 171.55 m/s
Hence the horizontal component = 39.0 m/s
The vertical component = 171.55 m/s
(c) The angle of impact, θ, is given as follows;
[tex]tan \theta = \dfrac{v_y}{v_x} = \dfrac{171.55}{39.0 } = 4.4[/tex]
∴ θ = tan⁻¹(4.4) = 77.19°.
What happens when a sound wave passes from water into air
Answer:
Explanation:
Sounds travel faster in object having high density proportion or matter. This is because particles vibrates and causing the other particle near to as well vibrate. Hence, when sound is moving from a higher dense medium like Water, the rate of traveling is high compare to it moving in air with less dense.
Two people try to lift a heavy box. Jack pulls upward with a 100-newton
force. Jill pulls upward with a 50-newton force, but neither person moves the
box.
Compare the amount of work done on the box by Jack and Jill.
OA) Jack did twice as much work as Jill.
OB) Jack did fifty times more work than Jill.
OC) Jack and Jill did the same amount of work.
Answer:
A ( Jack did twice as much work as Jill
Explanation:
1a. Assuming 100% efficient energy conversion, how much water stored behind a 50cm high hydroelectric dam would be required to charge a 50 ampere-minute 12 volt battery with 600j of energy stored in it
Answer:
7.22 m³ of water should be stored behind the hydroelectric dam.
Explanation:
First we find the total energy that can be stored in the battery. For that purpose we use the formula:
P = VI
where,
P = Power delivered by battery
V = Voltage of Battery = 12 volts
I = Current in Battery
Multiplying both sides by time interval (t), we get:
Pt = VIt
where,
Pt = (Power)(Time) = Total Energy Stored in Battery = E = ?
It = Current Rating of Battery = (50 A.min)(60 s/min) = 3000 A.s
Therefore,
E = (12 volt)(3000 A.s)
E = 36000 J
Now, we have to find the energy required to fully charge the battery:
Energy Required = ΔE = Total Energy Capacity(E) - Already Stored Energy
ΔE = 36000 J - 600 J
ΔE = 35400 J
Now, this energy must be equal to the potential energy of water stored behind hydroelectric dam to fully charge the battery, provided that the conversion efficiency is 100 %.
Therefore,
ΔE = mgh
where,
m = mass of water behind hydroelectric dam
g = 9.8 m/s²
h = height of dam = 50 cm = 0.5 m
Therefore,
35400 J = m(9.8 m/s²)(0.5 m)
m = (35400 J)/(4.9 m²/s²)
m = 7224.5 kg
Now, to find the volume of stored water, we use:
ρ = m/V
V = m/ρ
where,
ρ = density of water = 1000 kg/m³
V = Volume of water behind dam = ?
V = (7224.5 kg)/(1000 kg/m³)
V = 7.22 m³
The object will feel minimum force of gravity at the
Answer:
space , small amount of gravity is found in the space ,infact we can say that there is no gravity in the space
Answer:
Poles
Explanation:
The gravitational force is maximum at the equator and minimum at the poles.
Describe The energy conversions that occur when coal is formed, and then burned to produce thermal energy.
Answer:
When energy contained in coal is turned into heat, and then into electrical energy. As boiling water heated by the burning coal is cooled, steam forges from these cone-shaped cooling towers.
Talia is on a trip with some friends. In the first 2 hours , they travel 100 miles. Then they hit traffic and go only 30 miles in the next hour. The last hour of their trip , they drive 75 miles
Answer:
51 miles/hour
Explanation:
Talia is on a road trip with some friends. in the first 2 hours, they travel 100 miles. then they hit traffic and go only 30 miles in the next hour. the last hour of their trip, they drive 75 miles. calculate the average speed of talia’s car during the trip. give your answer to the nearest whole number.
The average speed would be 51 miles/hour.
The average speed of a moving object is defined as the total distance traveled relative to the total time taken fro the journey. Mathematically, it is given as:
total distance traveled/total time taken.
In this case;
Total distance traveled = 100 + 30 + 75 = 205 miles
Total time taken = 2 + 1 + 1 = 4 hours
Therefore;
Average speed = 205/4 = 51.25 miles/hour
To the nearest whole number = 51 miles/hour
If mass = 30kg, gravity = 10 N/kg and height is 2m of a car. Calculate the gravitational potential energy.
Answer:
P.E.=600Nm
Explanation:
m=30kg
g=10m/s²
h=2m
P.E.=?
as we know that
P.E.=mgh
P.E.=30kg×10m/s²×2m
P.E.=600Nm
A sphere of radius 0.03m has a point charge of q= 7.6 micro C located at it’s centre. Find the electric flux through it?
Answer:
The electric flux through the sphere is [tex]8.58 *10^{5} \frac{Nm^2}{C}[/tex]
Explanation:
Given
[tex]Radius,\ r = 0.03m\\Charge,\ q =7.6\µC[/tex]
Required
Find the electric flux
Electric flux is calculated using the following formula;
Ф = q/ε
Where ε is the electric constant permitivitty
ε [tex]= 8.8542 * 10^{-12}[/tex]
Substitute ε [tex]= 8.8542 * 10^{-12}[/tex] and [tex]q =7.6\µC[/tex]; The formula becomes
Ф = [tex]\frac{7.6\µC}{8.8542 * 10^{-12}}[/tex]
Ф = [tex]\frac{7.6 * 10^{-6}}{8.8542 * 10^{-12}}[/tex]
Ф = [tex]\frac{7.6}{8.8542} *\frac{10^{-6}}{10^{-12}}[/tex]
Ф = [tex]\frac{7.6}{8.8542} *10^{12-6}}[/tex]
Ф = [tex]0.85834970974 *10^{12-6}}[/tex]
Ф = [tex]0.85834970974 *10^{6}}[/tex]
Ф = [tex]8.5834970974 *10^{5}}[/tex]
Ф = [tex]8.58 *10^{5} \frac{Nm^2}{C}[/tex]
Hence, the electric flux through the sphere is [tex]8.58 *10^{5} \frac{Nm^2}{C}[/tex]
A non-uniform rod 60cm long and weighs 32N is balanced at the 45cm mark. A load of 2N is hung on the zinc rod at the 25cm mark. Where must a second knife-edge be placed to balance the zinc rod horizontally
Answer:
The second knife-edge must be placed 46.2 cm from the zero mark of the rod.
Explanation:
From the law of equilibrium, ΣF = 0 and ΣM = 0.
Let R be the reaction at the knife edge. Since the weight of the rod and zinc load act downward, and we take downward position as negative
-32 N - 2 N + R = 0
-34 N = -R
R = 34 N
Also, let us assume the knife-edge is x cm from the zero mark. Taking moments about the weight and assuming the knife-edge is right of the weight of the rod. Taking clockwise moments as positive and anti-clockwise moments as negative,
-(45 - 25)2 + (x - 45)R = 0
-(20)2 + (x - 45)34 = 0
-40 = -(x - 45)34
x - 45 = 40/34
x - 45 = 1.18
x = 45 + 1.18
x = 46.18 cm
x ≅ 46.2 cm
The second knife-edge must be placed 46.2 cm from the zero mark of the rod.
A metal rod has a moves with a constant velocity of 40 cm/s along two parallel metal rails through a magnetic field of 0.575 T. If the rails are separated by 20 cm, what is the power generated by the rod? O 341 x 1ow O 6.98 x 103 w O 9.00x 10sw O 8.10 x 105w
Answer:
2.12/R mW
Explanation:
The electrical power, P generated by the rod is
P = B²L²v²/R where B = magnetic field = 0.575 T, L = length of metal rod = separation of metal rails = 20 cm = 0.2 m, v = velocity of metal rod = 40 cm/s = 0.4 m/s and R = resistance of rod = ?
So, the induced emf on the conductor is
E = BLv
= 0.575 T × 0.2 m × 0.4 m/s
= 0.046 V
= 46 mV
The electrical power, P generated by the rod is
P = B²L²v²/R
= B²L²v²/R
So, P = (0.575 T)² × (0.2 m)² × (0.4 m/s)²
= 0.002116/R W
= 2.12/R mW
