a. 273k,373k
This is the answer.
Question 9 of 10
What happens to light as it moves at an angle into a medium that has a higher index of refraction?
A. It slows down, and the angle decreases.
B. It speeds up, and the angle increases.
C. It slows down, and the angle increases.
D. It speeds up, and the angle decreases.
Answer:
v = C / n light slows entering a medium of higher index of refraction
ni sin theta i = nr sin theta r Snell's Law where i refers to incidence and r refers to refraction
sin theta r = (ni / nr) sin theta i
So if the index of refraction is greater than the angle of incidence then the light ray would be refracted towards the normal
Answer:
A. It slows down, and the angle decreases.
Explanation:
got it right, trust
Calculate the work done to push a 200-N object 5-meters
the ice and steam point on a thermometer are found to be 96ml apart. what temperature is recorded when the length of mercury thread is 33.6ml above the ice point
Answer:
33.6 / 96 is the fraction of the temperature between ice and freezing
33.6 / 96 = .35
So C = .35 * 100 = 35 deg C where the ice point would be 0 deg C
You can convert C to F
F = 9 / 5 * C + 32 = 9/5 * 35 + 32 = 95 deg F
In the nitrogen cycle, plants take in nitrates and convert them into
An object has a mass of 50 kg on Earth. What would be the mass of that object in the Moon
It would be 50 kg.
Mass doesn't change.
Weight can.
An iron wire has a length of 1.50 m and a cross sectional area of 0.450 mm2. If the resistivity of iron is 10.0 ✕ 10−8 Ω · m and a potential difference of 0.800 V is maintained across its length, determine the current in the wire (in A)
Answer:
2400A
Explanation:
R=pL/A
R-Resistance
p-Resistivity=10.0 x 10^-8
L-1.5m
A-Cross sectional Area=0.00045
R=10.0 x 10^-8 x 1.5 ÷ 0.00045
and=0.000333333
I-current
V-potential difference
I=V/R
0.800÷0.000333333
Ans=2400A
A student pushes a 12 N book to the
right with a force of 10 N. The book
experiences a frictional force of 3 N.
Answer:
Explanation:
My name is Jeff
Assertion: In electrical circuits the connecting wires are usually made of thick copper wires. Reason: Thicker wires offer higher resistance and the wires are made of copper as the electrical conductivity of copper is low
a)Both A and R are true and R is the correct explanation of A.b)Both A and R are true, and R is not the correct explanation of A.c)A is true, but R is false. d)A is false, but R is true. e)Both A and R are false.
There actually three assertions here: one in A and two more in B.
All three assertions, as well as the reasoning described in this mess, are all False.
The correct choice from the list is e), but that doesn't even describe the complete Falseness of this disaster.
describe the human condition before Science and technology was practice.
Consider the reaction below Na2CO3 (aq) + CaCl2 (aq) CaCO3 (s) + 2NaCl (aq) If the releases 39.4 kJ of energy, how many kilocalories does it release? (1 cal = 4.184 J) (Round off answer to 2 decimal place)
Answer: 9.42
Explanation: yes
How did our Sun form? *
A cloud of stellar dust from part of a Nebula collapsed causing hydrogen atoms to
fuse together.
Many smaller stars became fused together by gravity
It broke off from a larger star in the universe.
Two gas giants from another solar system became fused together by gravity.
Answer: A cloud of stellar dust from part of a Nebula collapsed causing hydrogen atoms to fuse together
Explanation:
A 0.40 kg block can slide up and down a rough a 10-m-high, 30-m-long slope. At the bottom, a stiff spring with spring constant 800 N/m is compressed 0.50 m and used to launch the block up the slope. The friction force on the block from the slope is 1.2 N. What is the speed of the block when it reaches the top of the slope, in m/s
Answer:
[tex]v=11.135m/s[/tex]
Explanation:
From the question we are told that
Mass [tex]m=0.40kg[/tex]
Frictional friction [tex]f=1.2[/tex]
Spring constant [tex]k=800N/m[/tex]
Compressed [tex]x=0.50[/tex]
Generally the energy balance equation is mathematically given as
[tex]1/2kx^2=f*30+m*g*sin \theta*30+1/2m*v^2[/tex]
if [tex](sin=10/30-1/3)[/tex]
[tex]1/2(800)(0.5)^2=(1.2)*30+(0.4)*9.8*1/3*30+1/2(0.4)*v^2[/tex]
[tex]100=36+39.2+0.20v^2[/tex]
[tex]v^2=\frac{24.8}{0.20}[/tex]
[tex]v=\sqrt{124}[/tex]
[tex]v=11.135m/s[/tex]
As an admirer of Thomas Young, you perform a double-slit experiment in his honor. You set your slits 1.01 mm apart and position your screen 3.09 m from the slits. Although Young had to struggle to achieve a monochromatic light beam of sufficient intensity, you simply turn on a laser with a wavelength of 639 nm . How far on the screen are the first bright fringe and the second dark fringe from the central bright fringe
Answer:
[tex]0.00195\ \text{m}[/tex]
[tex]0.00293\ \text{m}[/tex]
Explanation:
m = Order = 1
D = Distance between screen and slit = 3.09 m
d = Slit distance = 1.01 mm
[tex]\lambda[/tex] = Wavelength = 639 nm
Distance from the first bright fringe from the central bright fringe is given by
[tex]y=\dfrac{m\lambda D}{d}\\\Rightarrow y=\dfrac{1\times 639\times 10^{-9}\times 3.09}{1.01\times 10^{-3}}\\\Rightarrow y=0.00195\ \text{m}[/tex]
Distance from the first bright fringe from the central bright fringe is [tex]0.00195\ \text{m}[/tex]
Distance from the second dark fringe from the central bright fringe is given by
[tex]y=(m+\dfrac{1}{2})\dfrac{\lambda D}{d}\\\Rightarrow y=(1+\dfrac{1}{2})\dfrac{639\times 10^{-9}\times 3.09}{1.01\times 10^{-3}}\\\Rightarrow y=0.00293\ \text{m}[/tex]
Distance from the second dark fringe from the central bright fringe is [tex]0.00293\ \text{m}[/tex].
1 kg block slides down a frictionless inclined plane that makes an angle of 300 with respect to the ground. The total length of the plane is 2 m, but midway down it collides with a second block, weighing 0.5 kg. The two blocks stick together and travel as one unit the rest of the way down the ramp. What is the kinetic energy of the combined 1.5 kg block when it reaches the bottom of the plane
Answer:
the kinetic energy of the combined 1.5 kg block when it reaches the bottom of the plane is 10.62 J
Explanation:
Given that the data in the question;
angle of inclination with respect to the ground [tex]\theta[/tex] = 30°
length of plane d = 2m
m₁ = 1 kg
m₂ = 0.5 kg
now, velocity of the first block at midpoint;
[tex]\frac{1}{2}[/tex]mv² = mgsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex]
[tex]\frac{1}{2}[/tex]v² = gsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex]
v² = gsin[tex]\theta[/tex]d
v = √( gsin[tex]\theta[/tex]d)
g is 9.8 m/s
so we substitute
v = √( 9.8 × sin30° × 2)
v = √( 19.6 )
v = 3.13 m/s
Now, velocity just after collision of the blocks will be;
(m₁ + m₂)v₂ = m₁v
v₂ = m₁v / (m₁ + m₂)
we substitute
v₂ = (1 × 3.13) / (1 + 0.5)
v₂ = 3.13 / 1.5
v₂ = 2.0866 m/s
now, final kinetic energy will be;
[tex]KE_f[/tex] = (m₁ + m₂)gsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex] + Initial Kinetic energy
[tex]KE_f[/tex] = (m₁ + m₂)gsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex] + [tex]\frac{1}{2}[/tex]mv₂²
we substitute
[tex]KE_f[/tex] = [(1 + 0.5)9.8 × sin30 × [tex]\frac{2}{2}[/tex]] + [[tex]\frac{1}{2}[/tex] × 1.5 × 2.0866 ]
[tex]KE_f[/tex] = 7.35 + 3.2654
[tex]KE_f[/tex] = 10.62 J
Therefore, the kinetic energy of the combined 1.5 kg block when it reaches the bottom of the plane is 10.62 J
Why are objects that fall near Earth's surface rarely in free fall?
O Gravity does not act on objects near Earth's surface.
O Air exerts forces on falling objects near Earth's surface.
O The objects do not reach terminal velocity.
O The objects can be pushed upward by gravity.
Answer:
Air exerts forces on falling objects near earth's surface
Explanation:
Falling objects are typically subject to air resistance which prevents the force of gravity on the object
A ball is rolling down a hill. Wich action would slow the ball down?
What is meant by the terms critical mass and supercritical?
Answer:
Critical mass is the minimum mass of fissionable material required to sustain a nuclear fission reaction, and a supercritical mass, which will provide more than enough neutrons to sustain a fission reaction at the time of detonation.
Explanation:
determine the total voltage in the circuit below the ammeter is reading 4 A
Answer:
6 V.
Explanation:
We'll begin by calculating the equivalent resistance of the circuit. This can be obtained as follow:
Resistor 1 (R₁) = 3 Ω
Resistor 2 (R₂) = 3 Ω
Equivalent Resistance (R) =?
Since the two resistor are in parallel connection, the equivalent resistance can be obtained as:
R = (R₁ × R₂) / (R₁ + R₂)
R = (3 × 3) / (3 + 3)
R = 9/6
R = 1.5 Ω
Finally, we shall determine the total voltage in the circuit. This can be obtained as follow:
Current (I) = 4 A
Equivalent Resistance (R) = 1.5 Ω
Total voltage (V) =?
V = IR
V = 4 × 1.5
V = 6 V
Thus, the total voltage in the circuit is 6 V
Which of these is an example of tertiary prevention?
A. Getting screened for skin cancer
B. Avoiding smoking and drinking alcohol
C. Dialysis for damaged kidneys
D. Washing hands
Explanation:
because a tertiary prevention is when the person is already infected with the disease
Families attempting to rebound from crises are advised to discontinue family rituals and leisure activities, as they may regenerate negative family stress and threaten resilience.
A. False
B. True
A disk of a radius 50 cm rotates at a constant rate of 100 rpm. What distance in meters will a point on the outside rim travel during 30 seconds of rotation?
Answer:
The point will travel a distance of 15708 centimeters in 30 seconds of rotation.
Explanation:
In this case, we see a disk rotating at constant rate, the travelled distance of a point on the outside rim ([tex]s[/tex]), in centimeters, is determined by using this expression:
[tex]s = \omega \cdot r\cdot t[/tex] (1)
Where:
[tex]\omega[/tex] - Angular speed, in radians per second.
[tex]r[/tex] - Radius of the disk, in centimeters.
[tex]t[/tex] - Time, in seconds.
If we know that [tex]\omega \approx 10.472\,\frac{rad}{s}[/tex], [tex]r = 50\,cm[/tex] and [tex]t = 30\,s[/tex], then the travelled distance of the point is:
[tex]s = \omega \cdot r\cdot t[/tex]
[tex]s = 15708\,cm[/tex]
The point will travel a distance of 15708 centimeters in 30 seconds of rotation.
Proton traveling across a capacitor A proton enters with a velocity v between the plates of a capacitor as shown in the figure. What is the direction of the magnetic field needed so that the proton continues its trajectory, undeflected? Explain each step of your reasoning.
Answer:
Please see the direction of force in the attachment
Explanation:
As the particle enters the capacitor, it experiences electric. In order to move in the same direction as the electron was moving before entering the capacitor, the force due to the electric field of capacitor must be balanced by the magnetic field.
The direction of particle is shown in the attachment.
As we know,
Force = q (v *B)
Give the relationship between the number of valence electrons in an atom's
valence electron shell and the position of the element on the Periodic Table
Answer:
they're reactions
Explanation:
The relationship between the valence electrons and position is: the number of valence electrons determines the position
What is valence electron?This is the number of electrons in the outermost shell of an atom.
NOTE: The outermost shell is called valence shell
Position in Periodic tableThis is where an element is located in the periodic table
Relationship between valence electrons and positionThe position of an element in the periodic table is determined by the number of valence electrons.
For example
Sodium, Na (atomic number of 11) has the following electronic configuration
1st shell = 2 electrons2nd shell = 8 electrons 3rd (valence) shell = 1 electronSince the valence electron is 1, thus, sodium is located in group 1 of the periodic table.
Thus, we can see that the position of an element in the periodic table is related to the valence electron(s) in the atomic shell of the element.
Learn more about valence electron:
https://brainly.com/question/13993867
#SPJ2
What is the mass of a jet that accelerates at 4 m/s2 after a 4,000 N force from the engines?
Answer:
1000kg
Explanation:
F=MA
Rearrange the formula: M=F/A
plug in values for F (force), and A (acceleration).
M=4000/4
M=1000kg
i think.
not sure tho.
The mass of the jet that accelerates at 4 m/s^2 after a 4000 N force from the engines is 1000 kg.
What is Newton's second law of motion?Newton's second law of motion states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Mathematically, the law can be expressed as F = ma, where F is the net force acting on the object, m is its mass, and a is its acceleration. This law is fundamental to the understanding of the motion of objects under the influence of external forces.
Rearranging the formula to solve for mass, we get:
m = F / a
Substituting the given values, we get:
[tex]m = 4000 N / 4 m/s^2[/tex]
m = 1000 kg
Therefore, the mass of the jet that accelerates at 4 m/s^2 after a 4000 N force from the engines is 1000 kg.
Learn more about Newton's second law of motion, here:
https://brainly.com/question/13447525?referrer=searchRes
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Why do astronomers use frequencies other than the visible ones when they are
investigating the universe?
The weight of an object is the force pulling the object:
a. upward
b. to the side.
c. in all directions
d. downward
A 1.50x103-kilogram car is traveling east at 30 meters per second.
The brakes are applied and the car is brought to rest in 9.00 seconds.
A. Calculate the magnitude of the total impulse applied to the car to
bring it to rest. [Show all work, including the equation and
substitution with units.]
B. State the direction of the impulse applied to the car. [East or
West?]
PLEASE HELP!!!!
Answer:
[tex]39000\ \text{kg m/s}[/tex]
West
Explanation:
m = Mass of car = [tex]1.3\times 10^{3}\ \text{kg}[/tex]
t = Time = 9 seconds
u = Initial velocity = 30 m/s
v = Final velocity = 0
Impulse is given by
[tex]J=m(v-u)\\\Rightarrow J=1.3\times 10^3(0-30)\\\Rightarrow J=-39000\ \text{kg m/s}[/tex]
The magnitude of the total impulse applied to the car to bring it to rest is [tex]39000\ \text{kg m/s}[/tex].
The direction is towards west as the sign is negative.
From fastest to slowest, which of the following lists describes the speed at which sound tends to travel in different materials?
A. Gases, solids, liquids
B. Gases, liquids, solids
C. Solids, liquids, gases
D. Solids, gases, liquids
Answer:
C. Solids,Liquids, Gases
How are newtons third law and his law of universal gravitation are connected
Answer:
please give me brainlist and follow
Explanation:
Gravitational force keeps it attracted to the Earth, and centripetal force keeps it moving in a circle. ... Explain how Newton's third law and his law of universal gravitation are connected. His third law states that every force has an equal opposite force attracted to it, and that force is caused by gravity.
if the root mean square speed of a gas particle is 200 m/s at a temperature of 400k, at what approximate temperature will urms when kelvin temperature equals 350 m/s
Answer:
The correct solution is "1230 K".
Explanation:
The given values are:
[tex](V_{rms})_1= 200 \ m/sec[/tex]
[tex](V_{rms})_2= 350 \ m/sec[/tex]
[tex]T_1=400 \ K[/tex]
As we know,
⇒ [tex]V_{rms} \propto \sqrt{T}[/tex]
or,
⇒ [tex]\frac{(V_{rms})_1}{(V_{rms})_2} =\sqrt{\frac{T_1}{T_2} }[/tex]
On substituting the values, we get
⇒ [tex]\frac{200}{350} =\sqrt{\frac{400}{T_2} }[/tex]
⇒ [tex]T_2=1230 \ K[/tex]
