Answer: D- he’s smart and educated
Explanation:
Arrange the isotopes of oxygen and carbon in order of decreasing number of neutrons.
Rank the isotopes from most o fewest neutrons. To rank items as equivalent, overlap them.
Answer:
C-12 > C-13 > C-14,O-16 > C-16,O-18
Explanation:
Generally, isotopes are described as atoms of the same elements with the same atomic number but different number of neutrons.
Hence,
For O-18, oxygen has an atomic number of 8 and neutron number of 10.
For C-14, carbon has an atomic number of 6 and neutron number of 8.
For C-13, carbon has an atomic number of 6 and neutron number of 7.
For C-16, carbon has an atomic number of 6 and neutron number of 10.
For carbon 12, carbon has an atomic number of 6 and neutron number of 6.
For O-16, oxygen has an atomic number of 8 and neutron number of 8.
Hence the rank from the fewest neutrons would be C-12>C-13>C-14,O-16>C-16,O-18
What is the control center of a cell?
Answer:
Hi there,i hope you are having a wonderful day,
The nucleus
Explanation:
The nucleus is the most centered part of the cell which controls and coordinates activities taking place in the cell
Answer:
the nulsus
Explanation:
Which of these statements are accurate? Hexokinase is a type of transferase that catalyzes the transfer of a phosphoryl group from ATP to a hexose. Hexokinase transfers the terminal phosphate of ATP to carbon 3 of glucose. The conformational shift that occurs when glucose, but not water, enters the active site prevents water from hydrolyzing ATP. Hexokinase consists of two domains, or lobes, that come together when glucose and the MgATP2–MgATP2– complex are bound. Most kinases require the presence of a monovalent metal ion cofactor to prevent ATP hydrolysis. Hexokinase is found in the mitochondrial membrane.
Answer:
A. The conformational shift that occurs when glucose, but not water, enters the active site prevents water from hydrolyzing ATP. True
B. Hexokinase consists of two domains, or lobes, that come together when glucose and the MgATP2–MgATP2– complex are bound. True
C. Hexokinase is a type of transferase that catalyzes the transfer of a phosphoryl group from ATP to a hexose. True
Explanation:
A. Hexokinase suffers and conformational changes by binding glucose in a reaction that prevents ATP hydrolysis.
B. Hexokinase is an enzyme with two domains that function by binding to the substrate (i.e., glucose). The region linking both protein domains is responsible for the catalytic activity.
C. Hexokinase is a type of transferase that catalyzes the transfer of a phosphoryl group from ATP to a hexose. During the first stage of glycolysis, the hexokinase transfers one phosphorous group from magnesium-ATP (Mg-ATP) to one hexose molecule, such as fructose, mannose or glucose.
False statements:
- Most kinases require the presence of a monovalent metal ion cofactor to prevent ATP hydrolysis. False: In canonical kinases, conserved amino acids bind to divalent metal ions before the transference of the phosphate group to their substrates.
- Hexokinase is found in the mitochondrial membrane. False: Hexokinase is found in the cytosol.
- Hexokinase transfers the terminal phosphate of ATP to carbon 3 of glucose. False: Hexokinase catalyzes the transfer of the terminal phosphate ATP to form glucose 6-phosphate.
Explain the link between climate change and population growth
Answer:
when there are changes in climatic condition for example if the sun becomes to harsh ,unbearable and unfavorable this might cause certain population to migrate from their habitat to a more suiting one
Why are scientists concerned about the use of the Bt toxin, which is used to kill insects, in genetic engineering?
It’s because they might not want insects to die.
They might need them for some work
E.g
Bees are used to make honey
Chris talked to his grandma on the phone, and she asked what birthday presents he received. Chris picked up a toy bat
and said, "This is what I got,"fully expecting his grandma on the other end of the phone to see the toy bat, too. What
aspect of development is Chris showing?
concrete operations
egocentrism
abstract thinking
sensory motor skills
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2008 2009 2011 Glynlyon. In
Answer:
I think it's concrete operations
Answer:
1
Explanation:
Which of the following is an example of protein denaturation?
Choose 1 answer:
A) Amino acids fold into repeating patterns due to hydrogen bonding of the peptide backbone.
B) Several amino acids are joined together via peptide bonds.
C) A protein binds with a substrate, lowering the activation energy of a reaction.
D) A protein is exposed to extremely high heat, causing it to lose its secondary structure and be
left with only its primary structure.
Answer:
D
Explanation:
Denaturation occurs when the protein deforms and loses its structure.
According to the question, A protein is exposed to extremely high heat, causing it to lose its secondary structure and be left with only its primary structure.
What is protein denaturation and how does it happen?A protein becomes denatured when its normal shape gets deformed because some of the hydrogen bonds are broken.
Weak hydrogen bonds break when too much heat is applied or when they are exposed to an acid.
Thus, option "D" is correct.
To learn more about the protein click here;
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biology is important in
Answer:
it’s Important reasons for studying biology are to understand how cells and organisms work. It involves the study of life and it is very important as it tells us about the natural world. Biology tells us about our body, helping us to develop cures and treatments for many diseases.
Explanation:
the other ppl said it
A stream or river that runs into another stream or river is called a
Answer:
tributary
Explanation:
A tributary is a river that runs into another river.
There are _______ different amino acids used to make proteins, and different condones code for different amino acids.
Answer: there are only 20 different amino acids but 64 possible codons
Explanation:
2.Black fur(B) in guinea pigs is dominant over white fur(b). Find theprobability of an offspring with the same phenotype as its parents in across between a homozygous black and a heterozygous black guineapig
.A. 0%,
25%B.25%,
25%C.50%,50%
D.75%, 25%
E.100%, 0%
Answer:
Option d: black 75%, white 25%
Explanation:
The cross is between a homozygous black and a heterozygous black guinea pig
Parents gen. BB x Bb
F1 generation BB Bb Bb bb
The probability of an offspring with the same phenotype as its parents is
Genotype: BB - 25% and Bb - 50%, bb-25%
Phenotype: black 75%, white 25%
Based on the objective you should feel comfortable calculating expected genotype frequencies when given observed allele frequencies. You should also be able to compare expected genotype frequencies from HWE to observed frequencies and determine if evolution is occurring. Here's a sample problem. You can do this without a calculator! Let's take the noob gene, a gene with two known alleles that determines feather color in the eastern lark. The two alleles, let's call them delta and gamma, can be sequenced. In fact, looking at a population in southern GA, you discover that 60% of the alleles in the population are the delta allele. So question 1, what is the percentage of the gamma allele in the population
Answer:
40% is the percentage of the gamma allele in the population.
Explanation:
Available data:
Two alleles, delta and gamma60% of the alleles in the southern GA population are the delta alleleWhat is the percentage of the gamma allele in the population?
According to Hardy-Weinberg, the allelic frequencies in a locus are represented as p and q, referring to the allelic dominant or recessive forms. The genotypic frequencies after one generation are p² (Homozygous dominant), 2pq (Heterozygous), q² (Homozygous recessive). Populations in H-W equilibrium will get the same allelic frequencies generation after generation. The sum of these allelic frequencies equals 1, this is p + q = 1.
In the same way, the sum of genotypic frequencies equals 1, this is
p² + 2pq + q² = 1
Being
p the dominant allelic frequency, q the recessive allelic frequency, p² the homozygous dominant genotypic frequency q² the homozygous recessive genotypic frequency 2pq the heterozygous genotypic frequencyIf the percentage of delta allele in a population is 60%, this means that its frequency is 0.6. By clearing the equation p + q = 1, we can calculate the gamma allele frequency. This is:
p + q = 1
0.6 + q = 1
q = 1 - 0.6
q = 0.4
Then the percentage of gamma allele in the population is 40%.
We can also think about it like this:
If the sum of the allelic frequencies equals 1, then 1 is 100% of the allelic frequencies. And if the percentage of delta allele in a population is 60%, then 40% is the percentage of gamma allele.
Which characteristic proves Lactobacillus acidophilus is from the specific kingdom Eubacteria?
Answer: It has peptidoglycan
Explanation:
The kingdom Eubacteria is the domain of prokaryotic bacteria. These are unicellular and prokaryotic organisms. Their cell membrane is made up of lipids. The cell wall is made up of peptiodoglycan which gives rigidity to the cell wall. It gives the structural strength to the bacterial cell wall, gives the strength to the bacteria, and it will counteract the osmotic pressure develop in the cytoplasm.
Lactobacillus acidophilus possess the peptidoglycan in the cell wall this establishes its relationship with kingdom Eubacteria.
Answer these questions based on what you learned from the lesson.
are a relatively small group of bacteria that thrive in extreme conditions.
vare a diverse group of bacteria that sometimes make us sick.
Eubacteria are classified by
are round bacterial cells.
are rod-shaped bacterial cells.
are spiral-shaped bacterial cells.
DONE
Intro
The answers for the question are :
ArchaebacteriaEubacteriaShapeCocciBacilliSpirillaBacteriaBacteria are little single-celled living beings. Microscopic organisms are found nearly all over on Soil and are imperative to the planet's biological systems.
Archaebacteria - are a relatively small group of bacteria that thrive in extreme conditionsEubacteria - are a diverse group of bacteria that sometimes make us sick.Eubacteria are classified by Shape. Cocci -are round bacterial cells. Bacilli - are rod-shaped bacterial cells. Spirilla -are spiral-shaped bacterial cells.Learn more about "Bacteria":
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The answers for the given question should be
Archaebacteria
Eubacteria
Shape
Cocci
Bacilli
Spirilla
What is Bacteria?It is considered as the little single-celled living beings. Microscopic organisms should be found nearly all over on Soil and are considered to be imperative with respect to to the planet's biological systems.
Now
Archaebacteria - should be small group of bacteria
Eubacteria - should be diverse group of bacteria t
Eubacteria should be classified by Shape.
Cocci - should be round bacterial cells.
Bacilli - should be rod-shaped bacterial cells.
Spirilla -should be spiral-shaped bacterial cells.
Learn more about bacteria here: https://brainly.com/question/16568397
in what way do these trees suggest that some of these species of blood flukes have switched hots?
Answer:
Prevention. The basic means of preventing Schistosoma infection is avoiding contact with fresh water infested with Schistosome parasites. Swimming, wading, or any other aquatic activities in these bodies of water exposes the skin to possible penetration by the cercariae.Explanation:
In the lab, metabolic poisons can be used to study ATP synthesis and oxygen consumption. Many of these poisons have – or have had – other uses, from diet aids to animal poisons to antibiotics. Poison Action oligomycin binds to F0F0 and blocks the proton channel cyanide inhibits cytochrome oxidase by reacting with heme a3 trifluorocarbonylcyanide phenylhydrazone (FCCP)(FCCP) increases membrane proton permeability rotenone blocks electron transfer at NADHNADH dehydrogenase (NAD−Q(NAD−Q oxidoreductase) bongkrekic acid binds to inward‑facing site of ATP‑ADP translocase Classify the metabolic poisons as electron transport inhibitors, uncoupling agents, ATP synthase inhibitors, or transport inhibitors.
Answer:
Electron transport inhibitors: Cyanide, Rotenone
Uncoupling agents: trifluorocarbonylcyanide phenylhydrazone (FCCP)(FCCP)
ATP synthase inhibitors: Oligomycin
Transport inhibitors: Bongkrekic acid
Explanation:
Electron transport inhibitors: Cyanide, Rotenone
Cytochrome oxidase also known as complex IV in the electron transport chain, carries electrons from cytochrome c to oxygen. It is a large enzyme having 13 subunits. Subunit 1 contains two heme groups , a and a3. Electrons are tranferred from heme a to oxygen bound to heme a3. The reaction of cyanide with heme a3 blocks this process of eleron transport
.Rotenone blocks electron transfer at NADH dehydrogenase (NAD−Q(NAD−Q oxidoreductase) by preventing electron transfer from Fe-S center to ubiquinone.
Uncoupling agents: trifluorocarbonylcyanide phenylhydrazone (FCCP)(FCCP)
The transfer of electrons from NADH through the respiratory chain to molecularoxygen is coupled to proton pumping from the inner mitochondrial matrix to the intermembrane space. This generates a proton motive force which is utilized in ATP synthesis. Trifluorocarbonylcyanide phenylhydrazone (FCCP)(FCCP) increases membrane proton permeability, causing protons to leak back into the mitochondrial matrix, thereby uncoupling the processs of ATP synthesis and proton flux.
ATP synthase inhibitors: Oligomycin
ATP synthase is the enzyme rensponsible for ATP synthesis. It has two functional domains,: F₁ and F₀. Oligomycin binds to F₀ and blocks the proton channel preventing rotation of the F₁ subuni, thus, preventing ATP synthesis from ADP.
Transport inhibitors: Bongkrekic acid
Adenine nucleotide translocase is a transport protein that transports free ADP from the cytoplasm into the mitochondrial matrix, while ATP produced from oxidative phosphorylation is transported from the mitochondrial matrix to the cytoplasm o the cell.
Bongkrekic acid inhibits Adenine nucleotide translocase, thus preventing ATP from leaving the mitochondria and starving cells of needed energy.
What tipe of cactus is this?
Answer:
Hey!
I think it is the San Pedro Cactus!
Explanation:
i have one at home just like that!
HOPE THIS HELPS!!
Answer:
san pedro
Explanation:
Skin from (a) dorsum left wrist and (b) left forearm, ulnar, near elbow. Clinical Diagnosis: Bowen disease versus basal cell carcinoma versus dermatitis Microscopic Description: (a) There is a mild hyperkeratosis and moderate epidermal hyperplasia with full-thickness atypia of squamous keratinocytes. Squamatization of the basal cell layer exists. A lymphocytic inflammatory infiltrate is present in the papillary dermis. Solar elastosis is present. (b) Nests, strands, and columns of atypical neoplastic basaloid keratinocytes grow down from the epidermis into the underlying dermal. Fibroplasia is present. Solar elastosis is noted.
The given question is incomplete as it lacks the major part of the question, however the correct question is as follows:
MD Specimen: Skin from (a) dorsum left wrist and (b) left forearm, ulnar area, near elbow.
Clinical Diagnosis: Bowen disease versus basal cell carcinoma versus dermatitis.
Microscopic Description: (a) There is mild hyperkeratosis and moderate epidermal hyperplasia with full-thickness atypia of squamous keratinocytes. Squamatization of the basal cell layer exists. A lymphocytic inflammatory infiltrate is present in the papillary dermis. Solar elastosis is present. (b) Nests, strands, and columns of atypical neoplastic basaloid keratinocytes grow down from the epidermis into the underlying dermis. Fibroplasia is present. Solar elastosis is noted. Pathologic Diagnosis: (a) Bowen disease of left wrist; (b) nodular and infiltrating basal cell carcinoma of left forearm, near elbow. Samantha Roberts, MD sr:bg
Answer these Questions:
1. In the specimen section, what does "skin on dorsum left wrist" mean?
2. What types of cells made up the inflammatory infiltrate?
3. What was the pathologist's diagnosis for the left forearm (look at pathologic diagnosis)?
4. Provide a brief description of Bowen disease, the pathologist's diagnosis for the left wrist.
Answer:
1. The skin on the dorsum left wrist implies the outside of the wrist only inverse to the palm.
2. Lymphocytes made up the incendiary penetrate.
3. Nodular and penetrating basal cell carcinoma of left lower arm , close to elbow.
4. Bowen ailment is a skin illness that happens because of development of anomalous cells in the epidermis layer of the skin. Since the irregular cells keep themselves to the epidermis just and don't spread away from it, so it's anything but a sort of cancer. But there are odds of disease being caused later. Red expanding patches are seen on the skin which on occasion bleed. They are caused because of high paces of sun introduction, by Human papillomavirus, or because of immunosupression. Treatment incorporates applying creams, for example, 5-FU to murder strange cells, cryotherapy, laser treatment and radiotherapy too.
Select all that apply. Which of the following are vertebrates? earthworms grasshopper lancelets octopus crab amphibians tunicates starfish
Answer: amphibians
Explanation:
earthworms, grasshopper, lancelets, octopus, crab, tunicates, starfish are all invertebrates.
lancelets(cephalochordata) and tunicates(urochordata) are chordates but do not have a backbone.
Hii!! The correct answer is amphibians. (:
Explain the plasma membrane in easy way.
Answer:
The cell membrane (also known as the plasma membrane (PM) or cytoplasmic membrane, and historically referred to as the plasmalemma) is a biological membrane that separates the interior of all cells from the outside environment (the extracellular space) which protects the cell from its environment.[1][2] The cell membrane consists of a lipid bilayer, including cholesterols (a lipid component) that sit between phospholipids to maintain their fluidity at various temperatures. The membrane also contains membrane proteins, including integral proteins that go across the membrane serving as membrane transporters, and peripheral proteins that loosely attach to the outer (peripheral) side of the cell membrane, acting as enzymes shaping the cell.[3] The cell membrane controls the movement of substances in and out of cells and organelles. In this way, it is selectively permeable to ions and organic molecules.[4] In addition, cell membranes are involved in a variety of cellular processes such as cell adhesion, ion conductivity and cell signalling and serve as the attachment surface for several extracellular structures, including the cell wall, the carbohydrate layer called the glycocalyx, and the intracellular network of protein fibers called the cytoskeleton. In the field of synthetic biology, cell membranes can be artificially reassembled.[
Explanation:
The human body’s nervous system is made up of?
Answer:
The central nervous system is made up of the brain and spinal cord.
Microscope help!
1. which part of the microscope provides concentration of light coming out of a light source?
a. oculars
b. objective
c. condenser
d. light bulbs on/off switch
e. none of the above
2. what is the total magnification of the cells when using the immersion objective of bright field microscope?
a. 40
b. 10
c. 100
d. 400
e. none of the above
3. the role of the immersion oil is to___
a. prevent the loss of light by refraction
b. make objective gentle touching a slide
c. magnify 1000x
d. concentrate light coming from the bulb
e. none of the above
Answer:
1. Condenser
2. None of the above
3. Magnify 1000x
Explanation:
1. Illuminators provides the stable light source in the microscope. It can be reflected using a mirror for a built in microscope. Condenser is made up of two lenses which helps collect and concentrate light. The light beams passes through the centre of the lenses.
Total magnification is objective magnification × Ocular magnification
It makes the object appear bigger than it is. Any of the objective magnification can be uses to achieve the specific size. Objective ranges from 10-100
Oil immersion makes image appears brighter, they increase the refractive index. It is used with 100x objects to achieve a clearer image.
Select the choices that best complete the following sentence: An inherited feature of an organism is a ______ whereas a variant of that feature is called a ______.
A.
homozygote; heterozygote
B.
chromosome; factor
C.
hybrid; gamete
D.
character; trait
E.
allele; gene
Answer:
A
Explanation:
Homozygous means that both copies of a gene or locus match while heterozygous means that the copies do not match. Two dominant alleles (AA) or two recessive alleles (aa) are homozygous. One dominant allele and one recessive allele (Aa) is heterozygous.
Help me ! Please man I need help !!
Which is a lymphocyte?
O A. Amylase
Ο Ο
B. Macrophage
O C. Urethra
D. B cell
Answer:
Lymphocyte is a B cell ans - option D--- is the frame work of the
body of an organism.
(a)flesh (b)tongue (C)skeleton
(d)eye
Answer: C :Skeleton
Explanation: The skeleton is the frame work of the body of an organism. Among other functions the skeleton gives the body shape, support, rigidity and protect the body's delicate organs.
(a) Describe the possible genotypes of the heart cells of an individual if meiosis in this
individual results in two sperm cells carrying the f allele and two sperm cells carrying the
F allele.
Answer:
The possible genotype is Ff
Explanation:
The possible genotype of the heart cells of such individual would be Ff.
Meiosis usually results in the formation of daughter cells with haploid number of chromosomes from parent cells with diploid number of chromosomes. The chromosomes in the parent cells are usually halved in the daughter cells.
The cells of the heart will have diploid number of chromosomes because they are vegetative cells while the sperm cells will usually have haploid number of chromosomes because they are sex cells.
Consequently, the heart cells of an individual will contain twice the chromosome number present in the sperm cells of such individual.
Hence, if meiosis results in the formation of sperm cells with F and f genotypes in an individual, it simply means that any diploid cell in that individual will have the Ff genotype.
The possible genotype is Ff
The following information should be considered:
Meiosis normally arise when the daughter cells are created along with haploid number of chromosomes from parent cells with diploid number of chromosomes. The chromosomes in the parent cells are normally halved in the daughter cells. The heart cells should have diploid number of chromosomes since they are vegetative cells while on the other hand the sperm cells will normally have haploid number of chromosomes. Due to this, the heart cells of an individual will comprise of twice the chromosome number that are present in the sperm cells of such individual.
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In this lecture you learned that due to ___________descent, organisms share many of the same genes and proteins. However, distantly related organisms have _______ DNA differences than closely related organisms.
Answer:
evolutionary
more
Explanation:
In this lecture you learned that due to evolutionary descent, organisms share many of the same genes and proteins. However, distantly related organisms have more DNA differences than closely related organisms.
Organic evolution general refers to the descents, with modification, of organisms from common ancestors. Hence, organisms that share the same ancestors share several similar genes and proteins due to their common lineage. The closer the organisms, the more similar their genes and proteins, and the distant the organisms, the more dissimilar their genes.
Which one ?!!!?!?!?!?!?
Answer:B
Explanation: Mosses are small and usually spreads on the ground like mats thereby avoid direct exposure to sunlight. Palm tree on the other are large and usually grow very tall, hence are expose to maximum sunlight
what is evaporation
Answer:
Evaporation is the process of turning liquid to vapor form.
Given two types of starfish, gold ones and purple ones, that are members of the same species. In your sample area, there are 325 gold starfish and 150 purple starfish (assume purple is dominant)
A. Find the genotype frequencies for "SS", "Ss", & "ss"
B. Find the allele frequencies for "S" (p) & "s" (q)
Answer: I believe I can fly
Explanation:
I believe I can touch the sky.
JK Love you bae
