The horizontal lines (l and m) are parallel. They are crossed by two transversals (lines a and b).

Lines a and b intersect line l at the same point, creating 3 angles to the right of line a. Angle 1 is above line l, angle 2 is below line l and above line b, and angle 3 is below line b. Line a intersects line m, creating angle 5 to the right of line a and above line m. Line b intersects line m, creating angle 4 above line m and to the left of line b.
Transversals a and b intersect to make a triangle. The m∠1 = 75°, and the m∠4 = 50°.

1. What is the m∠5? Explain how you know. (2 points)




2. What is the measure of the sum of the angles in a triangle? (2 points)



3. ∠3 is in a triangle with ∠4 and ∠5. Write and solve an equation to find the m∠3. (2 points)







4. What is the measure of a straight angle? (2 points)



5. ∠2 is in a straight line with ∠1 and ∠3. Write and solve an equation to find the m∠2. (2 points)

To test the reliability of the coefficients obtained from the Fama-French model, you can use a hypothesis test.

Then are the detailed  way to set up a  thesis test   Step 1 Define the null and indispensable  suppositions   The null  thesis( H0) is that the measure of a particular factor is equal to zero, while the indispensable  thesis( Ha) is that the measure isn't equal to zero.   H0 βi =  0  Ha βi ≠ 0   where βi is the measure of the factor in the Fama- French model.  

Step 2 Determine the significance  position   The significance  position is the probability of rejecting the null  thesis when it's actually true. It's  generally set at0.05 or0.01.   Step 3 Calculate the test statistic   The test statistic is a measure of how far the sample estimate of the measure is from the  hypothecated value of zero, relative to the standard error of the estimate. In the case of the Fama- French model, the t- test can be used to calculate the test statistic as follows   t =  βi/ SE( βi)   where SE( βi) is the standard error of the estimate of the ith measure.

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2. Discrete Variable.
3. The probability that a randomly selected package will weigh less than 18 pounds is 0.67.

4. The probability that a randomly selected package will weigh between 16 and 18 pounds is 0.33.

2. The amount of time it takes students to get to school would best be modeled as a Discrete variable because time can be measured in infinitely many decimal values.


3. The probability that a randomly selected package will weigh less than 18 pounds can be found by calculating the area under the probability density curve to the left of 18 pounds. Since the weights are uniformly distributed, the probability density function is a straight line with a slope of 1/(20-14) = 1/6.

The area of a triangle with base 4 (from 14 to 18 pounds) and height 1/6 is (1/2)(4)(1/6) = 1/12.

Therefore, the probability that a randomly selected package will weigh less than 18 pounds is the area under the curve from 14 to 18 pounds, which is 1/12 divided by the total area under the curve from 14 to 20 pounds, which is 1.

This gives us a probability of 1/12 ÷ 1 = 0.0833, which can be rounded to 0.08 or 0.10. The closest answer choice is c. 0.20, but neither a nor b nor d are correct.


4. The probability that a randomly selected package will weigh between 16 and 18 pounds can be found by calculating the area under the probability density curve between 16 and 18 pounds.

Again, since the weights are uniformly distributed, the probability density function is a straight line with a slope of 1/(20-14) = 1/6.

The area of a triangle with base 2 (from 16 to 18 pounds) and height 1/6 is (1/2)(2)(1/6) = 1/12.

Therefore, the probability that a randomly selected package will weigh between 16 and 18 pounds is the area under the curve from 16 to 18 pounds, which is 1/12 divided by the total area under the curve from 14 to 20 pounds, which is 1.

This gives us a probability of 1/12 ÷ 1 = 0.0833, which can be rounded to 0.08 or 0.10. The closest answer choice is not listed, but the correct probability is between 0.07 and 0.09.

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The value of angle E is 88°

a circle is a special kind of ellipse in which the eccentricity is zero and the two foci are coincident.

There is a theorem that states the opposite angles of a cyclic quadrilateral are supplementary i.e they sum up to give 180.

A cyclic quadrilateral is a quadrilateral inscribed in a circle. touching all the circumference of a circle.

This means that, 92 +angle E = 180°

therefore angle E = 180-92

= 88°

Therefore, the value of angle E is 88°

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The approximate area of the larger pin is 62.04 cm².

The area of an equilateral triangle is given by:

A = (√3/4) * a²

Where a is the side length

Let S and L represent the side length of smaller and larger pin respectively

For the smaller pin:

A = (√3/4) * S²

6.9 = (√3/4) * S²

S = 3.99 cm

Since L = 3 * S

L = 3 * 3.99 = 11.97 cm

For the larger pin:

A = (√3/4) * 11.97²

A = (√3/4) * 143.2809

A = 62.04 cm²

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The derivative of F(x) = Sx² x  [tex]e^t[/tex]² dt with respect to x is F'(x) = 2Sx (1 + x²t) [tex]e^t[/tex]² .

In this case, the two functions that we need to multiply are Sx² and  [tex]e^t[/tex]² , and the variable of integration is t. Applying the product rule, we get:

F'(x) = (Sx²)' [tex]e^t[/tex]² + Sx² ([tex]e^t[/tex]²)'

The first term is straightforward, as the derivative of Sx² with respect to x is 2Sx.

Thus, the derivative of  [tex]e^t[/tex]²  with respect to t is 2t [tex]e^t[/tex]² . Multiplying this by the derivative of the exponent of the exponential function (which is 1) gives us (e^t²)' = 2t [tex]e^t[/tex]² .

Substituting these derivatives into the product rule formula, we get:

F'(x) = 2Sx  [tex]e^t[/tex]²  + Sx² 2t [tex]e^t[/tex]²

Simplifying this expression, we can factor out the common factor of  [tex]e^t[/tex]² :

F'(x) = 2Sx  [tex]e^t[/tex]²  + 2Sx²t [tex]e^t[/tex]²

Finally, we can use the distributive property of multiplication to factor out 2Sx from both terms:

F'(x) = 2Sx (1 + x²t) [tex]e^t[/tex]²

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The volume of the stump is approximately 73316.6 cubic inches.

A right cylinder is a three-dimensional solid geometric shape that has a circular base and straight, parallel sides that form a curved surface.

The volume of a cylinder, which is given by:

                                V = πr²h

where V is the volume, r is the radius, and h is the height of the cylinder. Additionally, unit conversion from feet to inches is also used.

Here we have

The volume of a tree stump can be modeled by considering it as a right cylinder. Shaniece measures its height as 1. 5 ft and its radius as 36 in.

First, we need to convert the height and radius to the same units.

Let's convert the height to inches:

1.5 ft × 12 in/ft = 18 in

Hence, height h = 18 in and radius r = 36 in

Using the formula, the volume of a right cylinder (V) = πr²h

V = π(36)²(18) = 73316.57 in³

Rounding to the nearest tenth, we get:

V = 73316.6 in³

Therefore,

The volume of the stump is approximately 73316.6 cubic inches.

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The derivative, implicit differentiation: dhe 8x w+v+wzº+byx = 0 = 8/w - b times y / w. To find the expressions for dy/dx and dz/dx, we'll need additional information or equations relating y, z, and x.

To calculate the derivative using implicit differentiation, we need to differentiate both sides of the equation with respect to the variable we are interested in, which in this case is x.

First, we need to apply the chain rule to each term that contains a function of x. For example, the term 8x becomes 8 times the derivative of x, which is just 8. Similarly, the term byx becomes b times y times the derivative of x, which is just b times y.

Next, we need to apply the product rule to each term that contains two or more variables that are functions of x. For example, the term wzº becomes w times the derivative of zº plus zº times the derivative of w, which simplifies to w times 0 plus zº times the derivative of w.

Putting all of this together, we get:

8 + w + v + w times derivative of zº plus b times y = 0

To solve for the derivative of zº, we just need to isolate it on one side of the equation:

w times derivative of zº = -8 - w - v - b times y

Dividing both sides by w gives us:

derivative of zº = (-8 - w - v - b times y) / w

So the derivative of the original equation with respect to x is:

8 + w + v + (-8 - w - v - b times y) / w

which simplifies to:

8/w - b times y / w.

To calculate the derivative using implicit differentiation for the equation 8x + w + wz + byx = 0, we'll need to differentiate both sides with respect to x:

Derivative of 8x: 8
Derivative of w: 0 (since w is considered a constant with respect to x)
Derivative of wz: w * (dz/dx) (applying product rule)
Derivative of byx: b * (dy/dx) (applying product rule)

Now, differentiate both sides with respect to x:

8 + 0 + w * (dz/dx) + b * (dy/dx) = 0

Now, solve for dy/dx and dz/dx:

b * (dy/dx) = -8 - w * (dz/dx)

(dy/dx) = (-8 - w * (dz/dx)) / b

To find the expressions for dy/dx and dz/dx, we'll need additional information or equations relating y, z, and x.

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The probability that a customer spends less than 46.5 minutes in the supermarket is approximately 0.7389 or 73.89%.

We are given that the amount of time customers spend in the supermarket is approximately normally distributed with a mean of μ = 43.2 minutes and a standard deviation of σ = 5.2 minutes.

We want to find the probability that a customer spends less than 46.5 minutes in the supermarket. We can find this probability by standardizing the variable X representing the time spent in the supermarket to a standard normal distribution Z with mean 0 and standard deviation 1, and then looking up the corresponding probability from the standard normal distribution table.

The standardized variable Z is given by:

Z = (X - μ) / σ

where X is the time spent in the supermarket.

Substituting the given values, we get:

Z = (46.5 - 43.2) / 5.2

Z = 0.6346

Using a standard normal distribution table, we can find that the probability of Z being less than 0.6346 is approximately 0.7389.

Therefore, the probability that a customer spends less than 46.5 minutes in the supermarket is approximately 0.7389 or 73.89%.

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Approximately 28.81% of states had an infant mortality rate between 5.6 and 7.1 per 1,000 live births.

To answer this question, we can use the Z-score formula: Z = (X - μ) / σ where X is the value we're interested in (in this case, 5.6 and 7.1), μ is the mean (6.98), and σ is the standard deviation (1.62).

For 5.6: Z = (5.6 - 6.98) / 1.62 Z = -0.853 For 7.1: Z = (7.1 - 6.98) / 1.62 Z = 0.074

We can use a Z-table to find the percentage of states that fall between these two Z-scores. Using the table, we find that: P(-0.853 < Z < 0.074) = 0.2881

So approximately 28.81% of states had an infant mortality rate between 5.6 and 7.1 per 1,000 live births.

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The equivalent expression to the given expression is x + 5.

The range of the function is [-5,∞).

What is a function?

Each element of X receives exactly one element of Y when a function from one set to the other is used. The sets X and Y are collectively referred to as the function's domain and codomain, respectively. Initially, functions represented the idealized relationship between two changing quantities.

Here, we have

Given: Expression = 3(x+4) - (2x+7)

We have to find the equivalent expression to the given expression.

= 3(x+4) - (2x+7)

= 3x + 12 - 2x - 7

= x + 5

Hence, the equivalent expression to the given expression is x + 5.

The range of the function f(x) = |x+3|-5

Here, we have

Given: Expression = 3(x+4) - (2x+7)

We have to find the equivalent expression to the given expression.

= 3(x+4) - (2x+7)

= 3x + 12 - 2x - 7

= x + 5

Hence, the equivalent expression to the given expression is x + 5.

The range of the function f(x) = |x+3| - 5.

f(x) =  |x+3| - 5, where x∈R

As we know,  |x+3| ≥ 0 ∀ x∈R

So by adding -5 on both sides of the above inequality

=  |x+3| - 5 ≥ -5

f(x) = =  |x+3| - 5 ≥ -5

Hence, the range of the function is [-5,∞).

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The threshold for outputting "H" has been lowered to 0.47, which means that there is a 53% chance of getting heads and a 47% chance of getting tails.

To create a formula that produces an H or a T to simulate a coin toss, you can use the following formula:

`=IF(RAND()>0.5, "H", "T")`

This formula uses the `RAND()` function to generate a random number between 0 and 1. If the number is greater than 0.5, it will output "H" for heads; otherwise, it will output "T" for tails.

To simulate a coin that is not fair and comes up heads 53% of the time, you would need to change the formula slightly:

`=IF(RAND()>0.47, "H", "T")`

The threshold for outputting "H" has been lowered to 0.47, which means that there is a 53% chance of getting heads and a 47% chance of getting tails.

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The median first-name length of a person at the meeting is 6.5

To determine the value of the their median first name, we need to know that;

The median of a given set of data is the described as the middle number when the data is arranged in an order from least to the greatest value, that is, in an ascending order of arrangement.

From the information given, we have that;

The lengths of their first names are;

9, 3, 5, 8, 6, 7, 4, and 5 letters.

arrange in ascending order

3, 4, 5, 5, 6, 7, 8, 9

The middle values are;

= 5 + 6/2

Add the values

= 11/2

= 5. 5

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1. Integrate the slope function to find the original function, f(x):
∫(5x² + 7x - 3) dx = (5/3)x³ + (7/2)x² - 3x + C

2. Use the given point (0, 4) to find the constant C:
f(0) = (5/3)(0)³ + (7/2)(0)² - 3(0) + C = 4
C = 4

3. Write the final equation for f(x) with the found constant:
f(x) = (5/3)x³ + (7/2)x² - 3x + 4

To find an equation of the curve f(x), we need to integrate the given function f(x) = 5x² + 7x - 3. Before we do that, we can find the slope of the tangent line at any point (x, f(x)) on the curve by taking the derivative of f(x) with respect to x:

f'(x) = 10x + 7

So, the slope of the tangent line at the point (0, 4) is:

f'(0) = 10(0) + 7 = 7

Now, we can use the point-slope form of the equation of a line to write the equation of the tangent line at (0,4):

y - 4 = 7(x - 0)

Simplifying, we get:

y = 7x + 4

This tangent line also intersects the curve at (0, 4). So, the point (0,4) must satisfy the equation of the curve f(x). Substituting x = 0 and y = 4 in f(x), we get:

4 = 5(0)² + 7(0) - 3

4 = -3

This is not true, which means that the point (0,4) is not on the curve f(x). Therefore, we cannot find an equation of the curve that passes through this point.

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The true statement is Together, the families spend $409

We have to solve the equation using the substitution method

13a + 17c = 211

14a + 9c = 198

From equation 1:

13a = 211 - 17c

a = (211 - 17c)/13

Now substitute 'a' in equation 2:

14(211 - 17c)/13) + 9c = 198

multiply through by 13

14(211 - 17c) + 9c * 13 = 198 * 13

2942 - 238c + 117c = 2574

Combine like terms:

-121c = -368

c = 368 / 121

c = 3

Put the value of C in a

a = (211 - 17c)/13

a = (211 - 17 * 3) / 13

a = (211 - 51) / 13

a = 160 / 13

a = 12

The true statement is ogether, the families spend $409.

Together, they spend $211 + $198 = $409.

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The derivative f'(4π) of the function f(x) = |cos(x) - sin(x)| is equal to cos(4π) + sin(4π).

To find f'(x) for f(x) = |cos(x) - sin(x)|, we must first differentiate the absolute value function. Since the absolute value of a function is non-differentiable at its "corners," we need to consider the cases when cos(x) - sin(x) is positive and negative separately.

Case 1: cos(x) - sin(x) ≥ 0. Then, f(x) = cos(x) - sin(x) and f'(x) = -sin(x) - cos(x).
Case 2: cos(x) - sin(x) < 0. Then, f(x) = -[cos(x) - sin(x)] and f'(x) = sin(x) + cos(x).

Now, we need to determine which case to use at x = 4π. Since cos(4π) = 1 and sin(4π) = 0, cos(4π) - sin(4π) = 1 - 0 = 1, which is positive. Therefore, we use Case 1:

f'(4π) = -sin(4π) - cos(4π) = -0 - 1 = -1. However, f(x) is the absolute value of cos(x) - sin(x), so the derivative should be positive. Therefore, f'(4π) = cos(4π) + sin(4π) = 1 + 0 = 1.

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The 40th percentile for these test results is 74,  the 40th percentile is a score equal to or greater than the 12th score in the ordered list. Counting from the top of the list, the 12th result is 74.

To discover the 40th percentile of these test scores, we to begin with have to arrange them from least to most elevated. 

44 56 58 62 64 64 70 72 72 72 74 74 75 78 78 79 80 82 82 84 86 87 88 90 92 95 96 96 98 100

This list has 30 items. To find the 40th percentile, we need to find scores that are at least 40% of the scores.

To do this, first, calculate how many scores are below the 40th percentile.

0.40 × 30 = 12

This means that the 40th percentile is a score equal to or greater than the 12th score in the ordered list. Counting from the top of the list, the 12th result is 74.

Therefore, the 40th percentile for these test results is 74. 

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The probability of getting 5 consecutive "Heads" in 5 coin tosses is approximately 0.03.

To find the probability of getting 5 consecutive "Heads" in 5 coin tosses, follow these steps:

Step 1: Determine the probability of a single coin toss resulting in "Heads".
- Since a coin has 2 sides (Heads and Tails), the probability of getting "Heads" in one toss is 1/2 or 0.5.

Step 2: Calculate the probability of getting "Heads" in all 5 tosses.
- Since each toss is an independent event, multiply the probabilities for each toss together: (1/2) x (1/2) x (1/2) x (1/2) x (1/2).

Step 3: Simplify the expression.
- (1/2)^5 = 1/32

Step 4: Express the answer as a proportion rounded to two decimals.
- 1/32 ≈ 0.03 (rounded to two decimals)

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Answer:

Step-by-step explanation:

We can solve this problem by using a system of linear equations. Let's call a and b the two numbers we are looking for. We know that a times b equals 10000 and that a plus b equals some other number x. We can write these two equations as follows:

a * b = 10000

a + b = x

We can solve for a in terms of b by rearranging the first equation:

a = 10000 / b

Substituting this expression for a into the second equation gives:

10000 / b + b = x

Multiplying both sides by b gives:

10000 + b^2 = bx

Rearranging this equation gives:

b^2 - xb + 10000 = 0

This is a quadratic equation in terms of b. We can solve for b using the quadratic formula:

b = (x ± sqrt(x^2 - 4 * 10000)) / 2

Since neither a nor b are divisible by 10, we know that both a and b must be multiples of 5. Therefore, we can assume that x is also divisible by 5.

Let's try an example where x equals 5005:

b = (5005 ± sqrt(5005^2 - 4 * 10000)) / 2

b ≈ (5005 ± sqrt(25000025 - 40000)) / 2

b ≈ (5005 ± sqrt(24960025)) / 2

b ≈ (5005 ± 4996) / 2

So we have two possible values for b:

b ≈ (5005 + 4996) / 2 = 5000.5

b ≈ (5005 - 4996) / 2 = 4.5

Since neither a nor b are divisible by 10, we know that the correct value for b is:

b ≈ (5005 - 4996) / 2 = 4.5

Substituting this value for b into the first equation gives:

a ≈ 2222.22

Therefore, a plus b equals approximately 2226.72.

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It will take 8.15 years for the amount $3725 to double at 8.5% if compounded continuously, the correct option is (a).

We have to find the time it takes for the amount $3725 to double at 8.5% compounded continuously,

So, we use the formula for "Continuous-Compounding",

which is : A = P[tex]e^{r\times t}[/tex],

where A = final amount, P = initial amount, r = annual interest-rate (in decimal), t = time in years,

Since we want to find the time it takes for $3725 to double,

the double of $3725 is $7450,

So, the amount "A" is = $7450, and P is = $3725,

the rate is = 8.5% = 0.085,

Substituting the values,

We get,

⇒ $7450 = $3725[tex]e^{0.085\times t}[/tex],

⇒ 2 = [tex]e^{0.085\times t}[/tex],

⇒ ln(2) = 0.085×t,

⇒ t = 8.1546 ≈ 8.15 years.

Therefore, it will take (a) 8.15 years for the amount to double.

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The given question is incomplete, the complete question is

How long does it take for $3725 to double if it is invested at 8.5% compounded continuously, Round your answer to two decimal places

(a) 8.15 years

(b) 0.32 years

(c) 0.01 years

(d) 0.08 years

The defined the variables that you use to write the system   are 4x+6y=56 and y=4x

Recall that a variable is a quantity that may change within the context of a mathematical problem or experiment.

To determine the number of small cars rented and the number of large cars rented, where x represents number of small cars and y represents number of large cars

We use the variables

4x+6y=56 and y=4x can be used

This is determined thus

Number of people hold by small cars = 4

Number of people hold by large cars = 6

Let,

Number of small cars = x

Number of large cars = y

The students rented 4 times as many large cars as small cars,

y = 4x   .................................. Eqn 1

which altogether can hold 56 people.

4x+6y=56   ..............................Eqn 2

4x+6y=56 and y=4x can be used to determine the number of small cars rented and the number of large cars rented, where x represents number of small cars and y represents number of large cars.

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Answer:

30 students

Step-by-step explanation:

We Know

24 students in Mrs. Evans's class have a dog, and this represents 80% of her class.

How many students are in her class?

We Take

(24 ÷ 80) x 100 = 30 students

So, there are 30 students in her class.

Answer: 10x+8

Step-by-step explanation: 6x+2(4+2x)

Distribute 2 to numbers in parenthesis

2(4) + 2(2x)

8+4x

Don't forget to keep the 6x in the equation

6x+8+4x

Combine like terms (numbers with the same variable (letter))

6x+4x

10x

Keep the 8 because it is a whole solo number

10x+8

Hope this helps!

Since f(5) = 0, we have shown that 5 is one of the zeros of the function f(x).

What is function zero?

A function zero (also known as a root or a solution) is a value of the independent variable in a function that makes the function equal to zero. In other words, a function zero is a value of x for which f(x) = 0.

To prove that 5 is one of the zeros of the function f(x) = x³ - 2x² - 75, we need to show that f(5) = 0.

Substituting x = 5 into the function, we get:

f(5) = 5³ - 2(5)² - 75

= 125 - 50 - 75

= 0

Since f(5) = 0, we have shown that 5 is one of the zeros of the function f(x).

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For the probability density function, [tex]f(x) = \[ \begin{cases} \frac{10}{x²}& x ≥10 \\ 0 & x< 10\end{cases} \] [/tex],

a) The probability that the device will last more than 20 hours is equals to [tex]= \frac{1}{2} [/tex].

b) The cumulative distribution function (CDF) of X is [tex]F(x) = \[ \begin{cases} 1- \frac{10}{x}& x ≥10 \\ 0 & x< 10\end{cases} \][/tex].

c) The probability that of 6 such type of devices at least 3 will function at least 15 hours is equals to 0.31960.

d) The average lifetime of such type of device is infinity.

e) The expected value and variance is 1.25 and 2.066 respectively.

The probability density function is integrated to compute the cumulative distribution function. We have a probability density function (pdf) of X, for lifetime of a certain type of electronic device, [tex]f(x) = \[ \begin{cases} \frac{10}{x²}& x ≥10 \\ 0 & x< 10\end{cases} \][/tex].

We have answer the following questions,

a) The probability that the device will last more than 20 hours, P( X> 20) [tex]= \int_{20}^{\infty } \frac{ 10}{x²} dx[/tex]

[tex]= [ \frac{- 10}{x} ]_{20}^{ \infty } \ [/tex]

[tex]= [\frac{-10}{\infty}-\frac{(-10)}{20}][/tex]

[tex]= \frac{1}{2} [/tex]

b) The cumulative distribution function (CDF) of X, is represented as, [tex]= \int_{10}^{x}\frac{10}{y²}dy[/tex]

[tex]= - 10 [ \frac{ 1}{y} ]_{10}^{ x } [/tex]

[tex]= [ \frac{ -10}{x } + \frac{10}{10} ][/tex]

[tex]= 1- \frac{ 10}{x } [/tex]

[tex]F(x) = \[ \begin{cases} 1- \frac{10}{x}& x ≥10 \\ 0 & x< 10\end{cases} \][/tex].

c) The probability that of 6 such type of devices at least 3 will function at least 15 hours, [tex]P( X>15) = \int_{15}^{\infty} ( \frac{10}{x²}) dx[/tex]

= [tex] \frac{2}{3}[/tex]

Now, [tex]P( X ≥ 3) = P(X= 0) + P( X=1) + P( X = 2) + P( X = 3) \\ [/tex]

[tex] = ⁶C₀( \frac{2}{3})⁰( \frac{2}{3})⁶+ ⁶C₁( \frac{2}{3})¹ (\frac{1}{3} )⁵ + ⁶C₂(\frac{2}{3})²(\frac{1}{3})⁴ +⁶C_3(\frac{2}{3})³(\frac{1}{3})³ \\ [/tex]

= 0.001371 + 0.01646 + 0.08230 + 0.21947

= 0.31960

So, the probability is 0.31960.

d) the average lifetime of such type of device, [tex]E(X) = \int_{10}^{\infty} \frac{10}{x} dx[/tex]

[tex]=10[ln(x) ]_{10}^{\infty}[/tex]

[tex]=\infty[/tex]

e) Let X be a random variable with pdf, f(x) = [tex]f(x) = \[ \begin{cases} \frac{ {x}^{2} }{3}& - 1 < x < 2 \\ 0 &otherwise\end{cases} \][/tex]

The expected value, [tex]E(X) = \int_{-1}^{2}\frac{x³}{3}dx[/tex]

[tex]= [\frac{x⁴}{12}]_{-1}^{2} [/tex]

= 1.25

The variance value of g(X) = 3−4X

[tex] {X^2}= \int\limits_{ - 1}^2 {\dfrac{{{x^4}}}{3}} dx = (\frac{x^5}{15})_{ - 1}^{2} \\ [/tex]

= 2.066

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Complete question :

The probability density function (pdf) of X, the lifetime of a certain type of electronic device (measured in hours), is given by f(x)=10/x2,

x≥10, 0, x <10.

a. Find the probability that the device will last more than 20 hours.

b. What is the cumulative distribution function (CDF) of X?

c. What is the probability that of 6 such type of devices at least 3 will function at least 15 hours?

d. What is the average lifetime of such type of device?

e. Let X be a random variable with pdf

f(x)=x2/3,−1<x<2, 0 otherwise

Find the expected value and variance of g(X)=3−4X

8. The domain of (f/g)(x) should be all real numbers except for x = 0. 9. The value of (f+g)(5) = -5, (f-g)(0) = -46, (fg)(3) = 24, and (f/g)(2) = 1/2.

A function is a mathematical formula that gives each input value a distinct output value. It is a method of consistently and precisely linking one set of values (the inputs) to another set of values (the outputs). It is a relationship between two values in which the output value depends on the input value, or put it another way. In many areas of mathematics and science, functions are frequently used to simulate real-world occurrences or to find solutions to issues. They can be expressed algebraically, visually, or in a table.

8. The domain of (f/g)(x) should be all real numbers except for x = 0, since that would set the denominator g(x) equal to zero, which is incorrect because we cannot divide by zero.

9. The values of (f + g) (f-g) and fg are:

(f+g)(0) = f(0) + g(0) = 18 + 64 = 82

(f+g)(1) = f(1) + g(1) = 13 + 32 = 45

(f+g)(2) = f(2) + g(2) = 8 + 16 = 24

(f+g)(3) = f(3) + g(3) = 3 + 8 = 11

(f+g)(4) = f(4) + g(4) = -2 + 4 = 2

Now, f-g is:

(f-g)(0) = f(0) - g(0) = 18 - 64 = -46

(f-g)(1) = f(1) - g(1) = 13 - 32 = -19

(f-g)(2) = f(2) - g(2) = 8 - 16 = -8

(f-g)(3) = f(3) - g(3) = 3 - 8 = -5

(f-g)(4) = f(4) - g(4) = -2 - 4 = -6

Also the value of fg is:

(fg)(0) = f(0) * g(0) = 18 * 64 = 1152

(fg)(1) = f(1) * g(1) = 13 * 32 = 416

(fg)(2) = f(2) * g(2) = 8 * 16 = 128

(fg)(3) = f(3) * g(3) = 3 * 8 = 24

(fg)(4) = f(4) * g(4) = -2 * 4 = -8

Thus, the value of the required function is:

(f+g)(5) = f(5) + g(5) = -7 + 2 = -5

(f-g)(0) = f(0) - g(0) = 18 - 64 = -46

(fg)(3) = f(3) * g(3) = 3 * 8 = 24

(f/g)(2) = f(2) / g(2) = 8 / 16 = 1/2

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The cost of the reinforced fencing is $25/foot and is used for both the length and width of the rectangle. Therefore, the cost for the reinforced fencing is 2L + 2W. The cost of the cheaper fencing is $15/foot and is used for one division inside, which is equal to W. The total cost is 2L + 2W + W = $2500.

To maximize the overall area while spending $2500, you need to determine the dimensions of the rectangular area. Let's denote the length of the rectangle as L and the width as W. The reinforced fencing is used for the outside perimeter, while the cheaper fencing is used for the inner division.

The cost of the reinforced fencing is $25/foot and is used for both the length and width of the rectangle. Therefore, the cost for the reinforced fencing is 2L + 2W. The cost of the cheaper fencing is $15/foot and is used for one division inside, which is equal to W. The total cost is 2L + 2W + W = $2500.

Now, we can create an equation based on the cost:

25(2L + 2W) + 15W = 2500
50L + 50W + 15W = 2500
50L + 65W = 2500

To maximize the area, we need to find L and W values that satisfy this equation while also considering the area of the rectangle, which is given by L × W. We can use calculus to find the maximum area, but the approach is quite complicated for this format. Alternatively, you can test different L and W values that satisfy the cost equation and compare the resulting areas to find the maximum value.

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Since this value is constant, we can say that the maximum value of f''''(x) over [3phi/4, 3phi/2) is 13/81. Therefore,
L4 = 13/81

To calculate L4 for f(x) = 13 cos(x/3) over [3phi/4, 3phi/2), we first need to find the fourth derivative of f(x).

f(x) = 13 cos(x/3)
f'(x) = -13/3 sin(x/3)
f''(x) = -13/9 cos(x/3)
f'''(x) = 13/27 sin(x/3)
f''''(x) = 13/81 cos(x/3)

Now, to find L4, we use the formula:

L4 = max|f''''(x)| over [3phi/4, 3phi/2)

We can see that cos(x/3) is always between -1 and 1, so the maximum value of f''''(x) occurs when cos(x/3) = 1.

cos(x/3) = 1 when x/3 = 2npi (where n is an integer)
So, x = 6npi

Plugging this value of x into f''''(x), we get:

f''''(6npi) = 13/81 cos(6npi/3) = 13/81 cos(2npi) = 13/81

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The Excel function used when calculating the t critical value is the T.INV function.

The TINV function returns the inverse of the Student's t-distribution, which is a probability distribution that is commonly used in hypothesis testing when the sample size is small and the population standard deviation is unknown. The TINV function requires two arguments: the probability value (alpha) and the degrees of freedom.

The degrees of freedom depend on the sample size and the number of parameters estimated in the model. The TINV function returns the value of the t statistic that corresponds to a given probability and degrees of freedom. This t critical value is compared to the calculated t statistic to determine if the null hypothesis should be rejected or not.

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The variable of interest in the study is A) Whether the show's rating has an effect on the cost of the commercials.

In this scenario, the TV show executives raised the fee for commercials after learning that the show received a "No. 1" rating in a survey of viewers.

To investigate whether the show's rating has an effect on the cost of the commercials, the variable of interest would be the show's rating. Specifically, the study would aim to determine whether there is a relationship between the show's high rating and the increase in commercial fees.

The data collected for the study would likely include information on the show's rating, the fees charged for commercials before and after the rating was released, and potentially other relevant factors that may influence the cost of commercials.

Analyzing this data would allow the researchers to draw conclusions about the relationship between the show's rating and commercial fees. The correct answer is A.

Your question is incomplete but most probably your full question was

Identify the variable of interest in the study. 3) A T.V. show's executives raised the fee for commercials following a report that the show received No. 1" rating in a survey of viewers.

A) Whether the show's rating has an effect on the cost of the commercials

B) Whether raising the fee for commercials has an effect on the show's rating

C) The responses to the survey question

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Answer:

0

Step-by-step explanation: