The combustion of octane, C8H18, proceeds according to the reaction shown.

2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l)

If 538 mol of octane combusts, what volume of carbon dioxide is produced at 31.0 ∘C
and 0.995 atm?

Answers

Answer 1

The volume of carbon dioxide is produced at 31.0 ∘C and 0.995 atm is 119,786 L

How do we calculate?

We must ensure that you have a balanced chemical equation

We can multiply 611 * 16 and divide by the 2. We have 4888 moles  CO2.

We determine the  volume by using ideal gas law

(PV=nRT).

P = 0.995 atm

V = x

n = 4888 mol CO2

T = 24.0C + 273 K = 297 K

R = 0.0821 (L*atm)/(mol*K)

PV =

nRT  

V  = (nRT)/P

V = ((4888 mol)(0.0821 L*atm/mol*K)(297K))/(0.995 atm)

V = 119,786 L

Therefore, the volume of carbon dioxide is produced at 31.0 ∘C and 0.995 atm is 119,786 L

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Related Questions

Formula for lead (lll)oxide

Answers

Answer:Pb2O3

Explanation:

lead (III) has a +3 charge

Oxygen has a -2 charge

You need 2 Pb to balance with the 3

show work please energy units conversion​

Answers

The answers to the given questions are; 58 Joules = 13.86 Calories, 230 Calories = 962.32 Joules, 230 Calories = 0.96 kJ, and 3.2 kJ = 0.7648 kCal.

(i) We know that, 4.184 Joules = 1 Calorie

                     ==> 1 Joule = 1 / 4.184 Calories

     Therefore, 58 Joules = [ (1 / 4.184) * 58 ] Calories

                                         = 13.86 Calories (Approx.)

(ii) We know, 1 Calorie = 4.184 Joules

   Then,  230 Calories = 4.184 * 230 Joules

                                     = 962.32 Joules

(iii) We know, 230 Calories = 962.32 kJ(from previous question)

                 and, 1000Joules = 1 kJ

                           ==> 1 Joule = (1 / 1000) kJ

Therefore, 230 Calories i.e., 962.32 Joules = [ (1 / 1000) * 962.32 ] kJ

                                                                        = 0.96kJ (Approx.)

(iii) We know, 4.184 Joules = 1 Calorie

                ==> 1 Joule = (1 / 4.184) Calorie

                ==> 1000Joules i.e, 1 kJ = (1 / 4.184) * 1000 Calories

                Therefore, 3.2 kJ = [ { ( 1 / 4.184 ) * 1000 } * 3.2 ] Calories

                                              = 764.82 Calories(Approx.)

             Since, 1000 Calories = 1 kCal

                      764.81 Calories = [(1 / 1000) * 764.82 ] kCal

                             i.e., 3.2 kJ  = 0.7648 KCal (Approx.)

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What is the percent composition of each element in Prussian Blue?

Answers

The percent composition of iron, carbon, and nitrogen in Prussian Blue is approximately 56.27%, 15.38%, and 28.35%, respectively. The exact percentage of hydrogen depends on the value of x in the formula.

What proportion of each ingredient is there?

When evaluating a chemical complex, knowing the percentage composition of a certain element inside it may be helpful. The formula for percent composition is 100 times the product of the element's mass and its molecular mass.

What proportion of Fe is present in siderite?

It is free of sulphur and phosphorus and contains 48% iron. Siderite-smithsonite, siderite-magnesite, and siderite-rhodochrosite are solid solutions formed when zinc, magnesium, and manganese are substituted for iron.

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Name four types of physical weathering. How are they similar?
for 13 points

Answers

The four types of physical weathering are:

1.) Frost action or freeze-thaw weathering

2.) Exfoliation or unloading

3.) Thermal expansion and contraction

4.) Abrasion

These types of weathering are similar in that they all involve physical processes that break down rocks and other geological materials without the involvement of chemical reactions.

Frost action occurs when water seeps into cracks in rocks and freezes, causing the water to expand and exert pressure on the surrounding rock. This process repeats over time and can cause the rock to fracture and break apart.

Exfoliation occurs when rocks that were once buried deep beneath the earth's surface are exposed to lower pressures as overlying rocks erode away. As the pressure decreases, the rocks expand and crack, causing outer layers of rock to peel away like layers of an onion.

Thermal expansion and contraction occurs when rocks are repeatedly subjected to heating and cooling cycles. This can cause the rock to expand and contract, leading to the development of cracks and fractures.

Abrasion occurs when rocks and other geological materials are subjected to repeated rubbing or grinding by other materials, such as wind-blown sand, water, or other rocks. This process can cause rocks to wear down and break apart over time.

In summary, these four types of physical weathering are similar in that they all involve physical processes that break down rocks and other geological materials, but each type operates under different conditions and results in different forms of weathering.

Answer:

below

Explanation:

The four types of physical weathering are:

1. Freeze-thaw weathering

2. Exfoliation

3. Abrasion

4. Thermal expansion and contraction

These types of physical weathering are similar in that they all involve the breakdown of rocks and other geological features due to physical forces rather than chemical reactions. In each case, the physical stress causes the rock to crack or break apart. Additionally, they all can occur in various types of climates and environmental conditions.

Why is the electromagnetic spectrum important to astronomers when studying stars and other planets?

Answers

The entire spectrum of electromagnetic radiation emitted by celestial bodies, helps astronomers gain complete understanding of stars and planets.

What is Electromagnetic spectrum?

The electromagnetic spectrum encompasses a vast array of electromagnetic radiation, spanning from the elongated wavelength of radio waves to the compact wavelength of gamma rays. This includes an assortment of radiation types, including radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays and gamma rays. With each variation possessing a unique wavelength and frequency, they all traverse at the speed of light.

Why is the electromagnetic spectrum important to astronomers?

Astronomers rely heavily on the electromagnetic spectrum to study celestial bodies like stars and planets. This spectrum enables them to detect and measure various forms of electromagnetic radiation emitted by these objects. The range of frequencies in this radiation spans from radio waves with longer wavelengths to gamma rays with shorter ones.

Different types of electromagnetic radiation provide distinct information about celestial objects, including their temperature, composition, and movement. For instance, visible light allows astronomers to observe the color and brightness of stars and planets, while radio waves can identify magnetic fields or map out gas and dust distribution in galaxies. This knowledge helps answer fundamental questions about the universe's nature such as how galaxies and stars form, evolve over time, and what causes the universe's expansion.

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0.4800 g of a mixture that is 80.0% by mass sodium carbonate and 20.0% by mass sodium hydroxide reacts with 35.00 ml of hydrochloric acid. carbon dioxide is detected as one of the products. a) what is the normality of the hydrochloric acid? b) what is the molarity of the hydrochloric acid?

Answers

a) To find the normality of the hydrochloric acid, we need to know how many moles of HCl were used in the reaction. We can find this by using the balanced chemical equation for the reaction between HCl and Na2CO3:

2 HCl + Na2CO3 → 2 NaCl + CO2 + H2O

From the equation, we can see that 2 moles of HCl react with 1 mole of Na2CO3. Therefore, the number of moles of HCl used in the reaction is:

moles HCl = (35.00 mL HCl) x (1 L / 1000 mL) x (N / 1 L)

where N is the normality of the HCl. We can solve for N:

N = (moles HCl / (35.00 mL)) x (1000 mL / 1 L) x (1 / 2)

N = (0.4800 g / 106 g/mol) x (1 mol Na2CO3 / 0.8) x (2 / 0.03500 L)

N = 0.685 N

Therefore, the normality of the hydrochloric acid is 0.685 N.

b) To find the molarity of the hydrochloric acid, we need to know the volume of the solution used in the reaction. We can assume that the density of the hydrochloric acid solution is 1.00 g/mL, which means that 35.00 mL of solution has a mass of 35.00 g. We can also calculate the number of moles of Na2CO3 used in the reaction:

moles Na2CO3 = 0.4800 g / (106 g/mol x 0.8)

moles Na2CO3 = 0.00567 mol

From the balanced equation, we know that 2 moles of HCl react with 1 mole of Na2CO3. Therefore, the number of moles of HCl used in the reaction is:

moles HCl = 2 x moles Na2CO3

moles HCl = 2 x 0.00567 mol

moles HCl = 0.0113 mol

Finally, we can calculate the molarity of the hydrochloric acid:

Molarity = moles HCl / volume of HCl solution (L)

Molarity = 0.0113 mol / (35.00 g / 1000 g/L) / (1.00 g/mL)

Molarity = 0.323 M

Therefore, the molarity of the hydrochloric acid is 0.323 M.

5.82 x 10^6 atoms of water, H₂O, reacts with Na2O2, how many liters of sodium hydroxide,
NaOH can be formed?

Answers

5.82 x 10⁶ atoms of H₂O can produce 72800 L of NaOH.

What happens when H₂O₂ and NaOH react?

An exothermic mist from the commencement of high temperatures and heat from the breakdown of incompatible combinations can emerge from the reaction of NaOH with H₂O₂, which creates a powerful oxidant known as Na₂O₂ and poses a serious thermal danger.

5.82 x 10⁶ atoms / 3 atoms per mole = 1.94 x 10⁶ moles of H₂O

1.94 x 10⁶ moles of H₂O x (4 moles of NaOH / 2 moles of H₂O) = 3.88 x 10⁶ moles of NaOH

To convert moles of NaOH to liters, we need to use the density of NaOH and its molar mass. The molar mass of NaOH is:

23 g/mol (for Na) + 16 g/mol (for O) + 1 g/mol (for H) = 40 g/mol

The density of NaOH is 2.13 g/mL. Using these values, we can calculate the volume of NaOH produced:

3.88 x 10⁶ moles of NaOH x 40 g/mol = 1.55 x 10⁸ g of NaOH

1.55 x 10⁸ g / 2.13 g/mL = 7.28 x 10⁷ mL

7.28 x 10⁷ mL / 1000 mL/L = 72800 L

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A 7.95 L
container holds a mixture of two gases at 25 °C.
The partial pressures of gas A and gas B, respectively, are 0.352 atm
and 0.715 atm.
If 0.240 mol
of a third gas is added with no change in volume or temperature, what will the total pressure become?

Answers

The total pressure in the container will become 4.02 atm when 0.240 mol of a third gas is added.

How to find the total pressure

In accordance with Dalton's law of partial pressures:

P_total = P_A + P_B = 0.352 atm + 0.715 atm = 1.067 atm

When 0.240 mol of a third gas is further introduced, the overall number of moles of gas in the vessel jumps to:

n_total = n_A + n_B + n_3 = (P_A * V)/(R * T) + (P_B * V)/(R * T) + n_3

for no change in volume

n_total = (P_total * V)/(R * T) + n_3

P_total = (n_total - n_3) * (R * T)/V

Substituting the given value:

P_total = (0.352 + 0.715 + 0.240) * (0.0821 * (25 + 273.15))/7.95

P_total = 1.307 x 3.079

P_total =  4.024 atm

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What pressure, in Torr, will be exerted by 25.0g of CO2 at a temperature of 25.0 °C and a volume of 500.0 mL?

Answers

To find the pressure exerted by 25.0 g of CO2 at a temperature of 25.0°C and a volume of 500.0 mL, we can use the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to convert the given temperature from Celsius to Kelvin by adding 273.15:

T = 25.0°C + 273.15 = 298.15 K

The molar mass of CO2 is 44.01 g/mol. To find the number of moles, we divide the mass by the molar mass:

n = m/M = 25.0 g / 44.01 g/mol ≈ 0.568 mol

Now we can plug in the given values and solve for P:

P = (nRT) / V = (0.568 mol x 0.0821 L atm mol^-1 K^-1 x 298.15 K) / 0.500 L

P = 22.6 atm

Finally, we can convert the pressure from atm to Torr by multiplying by 760:

P = 22.6 atm x 760 Torr/atm ≈ 17176 Torr

Therefore, the pressure exerted by 25.0 g of CO2 at a temperature of 25.0°C and a volume of 500.0 mL is approximately 17176 Torr.

Someone help me do a CER on A lunar eclipse that can be photographed sometimes when Earth is in between the sun and the Moon. 5 sentences

No definitions
No Go*gle

Answers

Answer: A terrestrial phenomenon commonly referred to as lunar eclipse transpires during an astronomical event wherein the Earth traverses its orbit between the Sun and the Moon, resulting in an obstruction and projection of its shade onto the lunar surface. During a lunar eclipse, the moon may exhibit a crimson tint owing to the Earth's atmosphere refracting sunlight towards the moon. This phenomenon is commonly referred to as a "blood moon" in academic discourse. The acquisition of photographic images of lunar eclipses necessitates the utilization of a camera and a tripod. However, it is imperative to exercise care with respect to exposure duration and ISO settings to facilitate the capture of the subdued illumination emitted by the eclipsed moon. An upcoming celestial phenomenon, which is anticipated to be observable from Earth, is the occurrence of a lunar eclipse on May 16, 2022.

Explanation:

Match the label to the correct description.

Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
ball-and-stick model advantage
ball-and-stick model disadvantage
space-filling model advantage
space-filling model disadvantage

Answers

We can see here that matching the label to the correct description, we will have to have a complete part of the description and have a full understanding of what ball-and-stick model is all about.

What is ball-and-stick model?

A specific kind of molecular model called the ball-and-stick model uses balls to represent atoms and sticks to represent the connections connecting them to depict the three-dimensional structure of molecules.

It is a physical model that enables researchers to see the configuration of atoms within a molecule and comprehend their interrelationships.

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The [H3O+] of a solution with pH = 9.7 is

Answers

A solution with a pH of 9.7 contains the hydronium ion. [tex]1x10^-9.7[/tex]M, which is equivalent to approximately [tex]2.01x10^-10 M.[/tex]

Is pH a measure of Hydronium ion?

You must be aware of the hydronium ion concentration expressed in moles per litre (molarity) in order to calculate the pH of an aqueous solution. The pH is then calculated using the equation pH = - log [H3O+].

Why pH is only 1 to 14?

At the far end, there are no more than 1M hydrogen ions, which leads to a pH of no more than 0. The pH value is limited to 14, whereas the other end contains no more than 1M of hydroxide ions.

Question:

[tex]The [H3O+] of a solution with pH = 9.7 is 9.7 M O 1x 109.7M O2 x 10-10 M O 5 x 10-5M 09.7 x 10-1 M The [H3O+] of a solution with pH = 9.7 is 09.7 M O 1x 109.7 M 2 x 10-10 M. 0 5x 10-5m 09.7 10-1 M.[/tex]

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Complete and balance the molecular equation for the reaction of aqueous iron(III) nitrate, Fe(NO3)3 , and aqueous lithium hydroxide, LiOH. Include physical states. molecular equation: Fe(NO3)3(aq)+LiOH(aq)⟶
Enter the balanced net ionic equation for the reaction. Include physical states. net ionic equation:

Answers

The molecular equation for the reaction of aqueous iron(III) nitrate and aqueous lithium hydroxide is :

Fe(NO3)3(aq) + 3LiOH(aq) ⟶ Fe(OH)3(s) + 3LiNO3(aq)

By removing the spectator ions from the molecular equation—ions that appear on both sides of the equation but do not participate in the reaction—we can derive the balanced net ionic equation for the reaction. The spectator ions in this instance are Li+ and NO3-.

The net ionic equation is :

Fe3+(aq) + 3OH-(aq) ⟶ Fe(OH)3(s)

Be aware that solid Fe(OH)3 is created when the ions Fe3+ and OH- mix. Equations with (aq) for aqueous species and (s) for solid species denote the physical states.

What is the average of the following 3 numbers: 22.59, 27.43, 35.642 (provide answer with 4 significant figures)​

Answers

The average of the three numbers is:

(22.59 + 27.43 + 35.642) / 3 = 28.221

Rounding this to four significant figures gives us:

28.22

Therefore, the average of the three numbers is 28.22.

Answer:

The average would be found by:

(22.59 + 27.43 + 35.642) ÷ 3 = 28.554

Rounded to 4 significant figures:

28.55

The volume of a given gas is
Vem? P mm Hg. what is the new volume of the gas if the pressure is reduced to half at constant temperature?

Answers

Answer:  the new volume of the gas is twice the initial volume when the pressure is reduced to half at constant temperature.

Explanation:

If 3.24 mol
of an ideal gas has a pressure of 2.19 atm
and a volume of 76.67 L,
what is the temperature of the sample in degrees Celsius?

Answers

The temperature of the ideal gas sample is approximately 358.4 degrees Celsius

What is the temperature of the sample?

The ideal gas law is expressed as:

PV = nRT

Where P is pressure, V is volume, n is the amount of substance, T is temperature and R is the ideal gas constant ( 0.08206 Latm/molK )

Given that:

Amount of gas n = 3.24 mol

Pressure P = 2.19 atm

Volume of the gas V = 76.67 L

Temperature T = ?

To determine the temperature, substitute the values into the equation above.

PV = nRT

T = PV / nR

T = ( 2.19 atm × 76.67 L ) / ( 3.24 mol × 0.08206 Latm/molK )

T = 167.9073 / 0.2658744

T = 631.5286 K

Convert to degrees Celsius

T = ( 631.529 − 273.15 ) °C

T = 358.4°C

Therefore, the temperature is 358.4 degrees Celsius.

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if 0.80 moles of acetic acid are allowed to react with 0.65 moles of sodium bicarbonate , what is the limiting reactant? how many moles of CO2 can be produced? dimensional analysis

Answers

Sodium bicarbonate is the limiting reactant and just 0.65 moles of CO₂ can be produced.

What is meant by limiting reactant?

Limiting reactant is the reactant that gets consumed completely in a chemical reaction, thereby limiting the amount of product that can be formed.

Acetic acid and sodium bicarbonate react, and the balanced chemical equation for this reaction is:

CH₃COOH + NaHCO₃ -> CH₃COONa + CO₂ + H₂O

Calculating the quantity of product that can be created from each reactant and comparing them to discover which one generates the least will help us identify the limiting reactant. The reactant that produces less product is the limiting reactant.

The provided amounts of each reactant must first be converted to moles:

0.80 moles of acetic acid

0.65 moles of sodium bicarbonate

Then, we may determine how much CO₂ can be created from each reactant using stoichiometry. The balanced equation reveals that 1 mole of acetic acid and 1 mole of sodium bicarbonate combine to create 1 mole of carbon dioxide.

Using acetic acid:

0.80 moles CH₃COOH x (1 mole CO₂ / 1 mole CH₃COOH) = 0.80 moles CO₂

About sodium bicarbonate:

0.65 moles NaHCO₃ x (1 mole CO₂ / 1 mole NaHCO₃) = 0.65 moles CO₂

As 0.65 moles of CO₂ are fewer than 0.80 moles of CO₂, sodium bicarbonate is the limiting reactant. Just 0.65 moles of CO₂ can be produced as a result.

Dimensional analysis:

0.80 moles CH₃COOH x (1 mole CO₂ / 1 mole CH₃COOH) x (44.01 g CO₂ / 1 mole CO₂) = 35.21 g CO₂

0.65 moles NaHCO₃ x (1 mole CO₂ / 1 mole NaHCO₃) x (44.01 g CO₂ / 1 mole CO₂) = 28.61 g CO₂

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Which of the following is true about a compound and its elements?

Answers

The same components always present the same ratios in a compound. Water always has two hydrogen atoms for oxygen, and carbon dioxide always contains two oxygen atoms for every one of carbon.

Which of the following claims regarding an element is untrue?

Considering that each of them is composed of two similar atoms, elements include hydrogen, oxygen, and nitrogen. Water is not an element since it only contains two hydrogen atoms and one oxygen atom.

Do elements and compounds both consist of pure substances?

Pure substances include both elements and compounds. Substances made up of many atom types are known as compounds. The simplest compounds are called elements because they only contain one kind of atom.

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Help pls!!
20 points and I’ll mark brainliest!
Calculate the boiling and freezing points of a 36.0 % by mass Na3PO4 solution.

Answers

Answer:

B P = 100.13 °C

F P = -0.4613 °C

Explanation:

To calculate the boiling and freezing points of a solution, we need to use the formula:

ΔT = K * m * i

where ΔT is the change in boiling or freezing point, K is the cryoscopic or ebullioscopic constant, m is the molality of the solution (moles of solute per kilogram of solvent), and i is the van't Hoff factor.

First, we need to calculate the molality of the solution. We are given that the solution is 36.0% by mass Na3PO4, which means that for every 100 g of solution, there are 36.0 g of Na3PO4 and 64.0 g of solvent. We can assume that the solvent is water, so we can convert the mass of water to moles:

m(H2O) = 64.0 g / 18.015 g/mol = 3.549 mol

Next, we can calculate the number of moles of Na3PO4 in 100 g of solution:

m(Na3PO4) = 36.0 g / (163.94 g/mol) = 0.2197 mol

Now we can calculate the molality of the solution:

molality = 0.2197 mol / 3.549 kg = 0.0619 mol/kg

The van't Hoff factor for Na3PO4 is 4, because it dissociates into four ions in solution:

Na3PO4 → 3 Na+ + PO43-

Now we can use the cryoscopic and ebullioscopic constants for water:

Kf = 1.86 °C/m
Kb = 0.512 °C/m

Boiling point elevation:
ΔTb = Kb * m * i
ΔTb = 0.512 °C/m * 0.0619 mol/kg * 4
ΔTb = 0.1271 °C

Freezing point depression:
ΔTf = Kf * m * i
ΔTf = 1.86 °C/m * 0.0619 mol/kg * 4
ΔTf = 0.4613 °C

The boiling point elevation of the solution is 0.1271 °C, and the boiling point of water at standard pressure is 100.00 °C, so the boiling point of the solution is:

boiling point = 100.00 °C + 0.1271 °C = 100.13 °C

The freezing point depression of the solution is 0.4613 °C, and the freezing point of water at standard pressure is 0.00 °C, so the freezing point of the solution is:

freezing point = 0.00 °C - 0.4613 °C = -0.4613 °C

Therefore, the boiling point of the solution is 100.13 °C and the freezing point of the solution is -0.4613 °C.

Question 12 Consider the following unbalanced chemical equation for the reaction which is used to determine blood alcohol levels: H 1 + 1+ + Cr 2 2 ​ O 7 7 ​ 2 − 2− + C 2 2 ​ H 6 6 ​ O → → Cr 3 + 3+ + CO 2 2 ​ + H 2 2 ​ O Balance the equation using the smallest whole number coefficients. What is the coefficient in front of carbon dioxide in the balanced chemical equation? 1 point 2 1 3 4 none of the other answers is correct

Answers

[tex]16H_{1}[/tex]+ + [tex]2Cr_{2O_{72} }[/tex]- + [tex]3C_{2H_{60} }[/tex] →4 [tex]Cr_{3}[/tex]+ + 3 [tex]CO_{2}[/tex] + 11 [tex]H_{2} O[/tex] is balanced equation. 3 is the coefficient in front of carbon dioxide in the balanced chemical equation

Define an equation with a balanced formula.

A balanced chemical equation, in which the masses of the reactants and products are equal, contains the same amount of atoms of each element on both sides of the equation.

Varied elements' atom counts in the reactants and products of unbalanced chemical equations are varied. Because the coefficients become the powers of the concentrations of the products and reactants, a balanced equation is crucial when utilizing a constant. The constant is wrong if the equation is unbalanced.

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conclusion of solution and filteration of organic compounds method​

Answers

Filtration is the process of passing a liquid containing contaminants through a filter to get a cleaner liquid.

What can you conclude after learning about filtration of solutions of organic compounds?

After filtration impurities are left on the filter when the liquid goes through it, resulting in a cleaner combination. The procedure of separating one ingredient from another in a compound is used in the purification of chemical compounds or any materials. A mixed sample is turned into fresh samples, each of which contains a single ingredient.Separation procedures are then utilised to separate these compounds. These techniques alter the relative proportions of components in a combination.The type of the compounds and the impurities in them influence the purification of organic chemicals and compounds.

Purification of compounds can be done in other methods as well such as distillation, chromatography, sublimation and crystallisation.

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Full question:

What can you conclude after learning about filtration of solutions of organic compounds? Name other methods of purification of compounds.

How many moles of Sb,03 will be formed when you have 20.0 moles of oxygen gases?

Answers

20.0 moles of oxygen react with Antimony to form 13.3 moles of Antimony (III) Oxide. We want to calculate how many moles of Antimony (III) Oxide will be formed from 20.0 moles of oxygen. This is a stoichiometry problem.

What is stoichiometry?

The link between the proportional amounts of components participating in a reaction or generating a compound is known as stoichiometry, and it is often expressed as a ratio of whole integers.

Assuming a balanced chemical equation, the stoichiometric ratio between Antimony (III) Oxide  and oxygen can be used to determine the number of moles of Antimony (III) Oxide  formed.

For example, the balanced equation for the reaction of Antimony with O2 to form Antimony (III) Oxide  is:

4 Antimony + 3 O2 → 2 Antimony (III) Oxide

From this equation, it can be seen that 3 moles of oxygen react with 2 moles of Antimony (III) Oxide . Therefore, if there are 20.0 moles of O2, then the number of moles of Antimony (III) Oxide  formed would be:

20.0 moles oxygen × (2 moles Antimony (III) Oxide  / 3 moles oxygen) = 13.3 moles Antimony (III) Oxide.

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PLEASE HELP ME WITH THIS I DONT KNOW WHERE TO START
1. Calculate the temperature if 5 moles of a gas is compressed into a volume of 50L at a Pressure of 2000 mmHg. R= 0.08206 L•atm/ mole•K and (0°C+273)=K

Answers

Answer:

T = 362.2°C.

Explanation:

We can use the Ideal Gas Law to solve this problem, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to convert the given pressure of 2000 mmHg to atm. We have:

P = 2000 mmHg = 2000/760 atm = 2.63 atm (rounded to two decimal places)

Next, we can plug in the values of the given pressure, volume, gas constant, and number of moles into the Ideal Gas Law and solve for T:

PV = nRT

T = PV / nR

T = (2.63 atm) x (50 L) / [(5 mol) x (0.08206 L•atm/mol•K)]

T = 635.2 K

Finally, we need to convert the temperature from Kelvin to Celsius:

T = 635.2 K - 273 = 362.2°C

Therefore, the temperature is 362.2°C.

James Ensor's Christ's Entry into Brussels (1889) was painted as a sarcastic response to

Seurat's "La Grande Jatte"

Rodin's "Burghers of Calais

OGauguin's "Where Do We Come

O Courbet's "Burial of Calais"

Answers

James Ensor's Christ's Entry into Brussels (1889) was painted as a sarcastic response to Rodin's "Burghers of Calais." Therefore, the correct answer is Rodin's "Burghers of Calais."

"Burghers of Calais" is a sculpture by Auguste Rodin that depicts six burghers of Calais, a city in France, who offered their lives to save their fellow citizens during the Hundred Years' War.

The sculpture is a representation of heroism, sacrifice, and patriotism. James Ensor, however, was critical of this type of heroic representation and sought to challenge it through his own art.

In "Christ's Entry into Brussels," Ensor depicts a grotesque and chaotic scene of Christ's triumphant entry into the city. The painting is a satirical commentary on the hypocrisy of organized religion and the political corruption in Brussels at the time. It can be seen as a direct response to the heroism and idealism of Rodin's "Burghers of Calais."

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Consider the equilibrium of methanol vapor and the liquid.
CH₂OH(1) CH₂OH(g)
What is the vapor pressure of the methanol at -30 °C?
What is the vapor pressure of the methanol at 40 °C?
Thermodynamic Table at 25 °C
Substance AH; (kJ/mol) S (J/mol-K) AG; (kJ/mol)
CH₂OH(1)
126.8
CH₂OH(g)
239.9
Pvap 5
Pap
=
=
-239.2
-201.0
-166.6
-162.3
atm
atm

Answers

The vapor pressure of methanol at 40°C is 0.234 atm.

What distinguishes ethanol from methanol?

Only two types of alcohol are methanol and ethanol. Ethanol, sometimes referred to as ethyl alcohol, has a chemical composition of two carbon atoms. Methanol, sometimes referred to as methyl alcohol, is made up of just one carbon atom.

ln(P2/P1) = (ΔHvap/R) x (1/T1 - 1/T2)

ΔGvap = -RTln(Pvap/P) = ΔHvap - TΔSvap

ΔGvap = -RTln(Pvap/P) = -166.6 kJ/mol

ΔSvap = S(g) - S(l) = 239.9 J/mol-K - 126.8 J/mol-K = 113.1 J/mol-K

ΔHvap = ΔGvap + TΔSvap = -166.6 kJ/mol + (298.15 K)(113.1 J/mol-K) = -134.6 kJ/mol

Now we can use the Clausius-Clapeyron equation to find the vapor pressure of methanol at -30°C and 40°C.

At -30°C, we have:

T1 = 25°C + 273.15 = 298.15 K

T2 = -30°C + 273.15 = 243.15 K

ΔHvap = -134.6 kJ/mol

R = 8.314 J/mol-K

ln(P2/5 atm) = (-134.6 kJ/mol / 8.314 J/mol-K) x (1/298.15 K - 1/243.15 K)

P2 = 0.0038 atm

Therefore, the vapor pressure of methanol at -30°C is 0.0038 atm.

At 40°C, we have:

T1 = 25°C + 273.15 = 298.15 K

T2 = 40°C + 273.15 = 313.15 K

ΔHvap = -134.6 kJ/mol

R = 8.314 J/mol-K

ln(P2/5 atm) = (-134.6 kJ/mol / 8.314 J/mol-K) x (1/298.15 K - 1/313.15 K)

P2 = 0.234 atm

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A balloon originally has 0.100 moles of helium and has a volume of 0.500 L. If 0.510 grams of He are added to the balloon, what will the new volume be, in L? (Assume temperature and pressure do not change.)

Answers

The new volume of the helium gas is 0.39 L.

What is the new volume of the helium gas?

The new volume of the helium gas is calculated by applying the following formula as shown below:

n₁V₁ = n₂V₂

where;

n₁ is the initial number of molesn₂ is the final number of molesV₁ is the initial volumeV₂ is the final volume

the final number of moles is calculated as;

n₂ = 0.51 g/4 g/mol

n₂ = 0.1275 mol

The final volume of the gas;

V₂ =(n₁V₁)/n₂

V₂ = (0.1 x 0.5 L )/ (0.1275)

V₂ = 0.39 L

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If I have 6.5 liters of a gas in a ballon at a pressure, of
1.35 atm and compess the gas until its volume is 4.6,
what will the new pressure inside the ballon be?
Round your answer to 2 decimal places!

Answers

The new pressure inside the balloon will be 1.91 atm after the gas is compressed to a volume of 4.6 L.

What is the formula for the pressure law?

The scientist Robert Boyle discovered this empirical relationship in 1662, which asserts that under constant temperature, the pressure (p) of a given quantity of gas changes inversely with its volume (v). As a result, the equation pv = k, a constant, is produced.

P1 x V1 = P2 x V2

where the starting pressure and volume are P1 and V1, and the ultimate pressure and volume are P2 and V2.

Plugging in the given values, we get:

1.35 atm x 6.5 L = P2 x 4.6 L

Solving for P2, we get:

P2 = (1.35 atm x 6.5 L) / 4.6 L

P2 = 1.91 atm

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In a standard Normal distribution, if the area to the left of a z-score is about 0. 1500, what is the approximate z-score?
Draw a sketch of the Normal curve, showing the area and z-score
Z=
(Round to two decimal places as needed.)

Answers

The value of (approximate) z-score for an area of 0.1500 to the left of the z-score in a standard normal distribution is approximately -1.04.

How do you arrive at the standard normal distribution?

If the area to the left of a z-score is 0.15 this means that 15% of the area under the standard normal distribution curve is to the left of the z-score. To find the approximate z-score, we can use a table of standard normal probabilities or a calculator that has a normal distribution function.

Using a standard normal distribution table, we can look up the closest probability to 0.15 in the table, which is 0.1492. The corresponding z-score is approximately -1.04.

This is how you arrive at the approximate z-score for an area of 0.1500 to the left of the z-score in a standard normal distribution which is approximately -1.04.

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2 Na2O2 + 2 H₂O = 4NaOH+O2

If sodium peroxide, Na2O2, is added to water, elemental oxygen gas, O2, and sodium
hydroxide, NaOH, are generated. Suppose 8.52 g of sodium peroxide, Na2O2, is added to a large
excess of water. What volume, in liters, of oxygen, O2, will be produced?

Answers

The volume of O₂ produced when 8.52 g of Na₂O₂ is added to excess water is approximately 1.17 liters at STP.

What is ideal gas law?

When it comes to the ideal gas law, the underlying assumption is that the gas is in a state of thermodynamic equilibrium. This means that its molecules are not interacting with each other except through perfectly elastic collisions.

Equation:

We can use stoichiometry to determine the volume of oxygen gas produced from the reaction of 8.52 g of Na₂O₂.

First, we need to convert the mass of Na₂O₂ to moles using its molar mass:

8.52 g Na₂O₂ × (1 mol Na₂O₂ / 77.98 g Na₂O₂) = 0.1093 mol Na₂O₂

According to the balanced chemical equation, 1 mole of Na₂O₂ produces 1/2 mole of O₂:

2 Na₂O₂ + 2 H₂O → 4 NaOH + O₂

1 mol Na₂O₂ produces 1/2 mol O₂

So, the number of moles of O₂ produced is:

0.1093 mol Na₂O₂ × (1/2 mol O₂ / 1 mol Na₂O₂) = 0.05465 mol O₂

Finally, we can use the ideal gas law to determine the volume of O₂ produced at standard temperature and pressure (STP), which is defined as 0°C (273 K) and 1 atmosphere (1 atm) of pressure:

PV = nRT

At STP, the pressure and temperature are known, so we can rearrange the equation to solve for V:

V = nRT / P

Plugging the values, we get:

V = (0.05465 mol) × (0.08206 L atm mol⁻¹ K⁻¹) × (273 K) / (1 atm)

V ≈ 1.17 L

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Use the graph to answer the following questions.

a. Describe and provide an explanation for the general period trend in boiling points.

b. Describe and provide an explanation for the general group trend in boiling points.

c. Describe and provide an explanation for exceptions to the general group trend in boiling points.

d. (i) Which of the substances shown are liquids at room temperature? (ii) Which of the substances shown are solids? (iii) Explain why these substances are found in this state at room temperature.

e. Predict an approximate boiling point for lead (IV) hydride. Justify your prediction.

Answers

The general trend in boiling points across the period is that they increase from left to right. This is because as you move from left to right, the number of protons in the nucleus increases, causing the attraction between the electrons and the nucleus to increase.

What increases the boiling point?

In an open system, this is referred to as atmospheric pressure. Pressure rises as boiling points and the amount of energy needed to boil liquids rise.

Why does the boiling point increase when intermolecular interactions increase?

The standard boiling point should rise as intermolecular tensions grow. This is because it takes more energy to separate molecules during the transition from liquid to gas when intermolecular interactions are stronger.

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