Terick ran 2 3of a mile in 8 minutes. It took Chad 40 minutes to run 3 1 4miles. a. If Terick runs at that speed, how long will it take him to run one mile?

Answers

Answer 1

The time taken for Terick to run one complete mile is determined as 12 minutes

Speed of Chad

The speed of chad is calculated as follows;

s = distance/time

s = (3.25 miles)/(40)

s = 0.08125 miles/min

Total distance ran by Terick

2/3 of a mile = 8 mins

1/3 of a mile = ?

1/3 of a mile  =  4mins

1 mile = 8 mins + 4 mins = 12 mins

Thus, the time taken for Terick to run one complete mile is determined as 12 minutes.

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Related Questions

Solve, finding all solutions in [0, 2(pi)]

Answers

Answer:

  x = π/12, 5π/12

Step-by-step explanation:

We can work this problem a couple of ways. We can convert it to single trig function, shifted horizontally. Or we can convert it to a double-angle equation.

__

horizontal shift

We recall the sum of angles formula is ...

  sin(x+y) = sin(x)cos(y) +cos(x)sin(y)

Using this, we can rewrite the left side of the equation using some angle offset y, and some scale factor k.

  k·sin(x +y) = k·sin(y)·cos(x) +k·cos(y)·sin(x) = 2cos(x) +2sin(x)

finding the shift

Equating coefficients of cos(x) and sin(x), we can solve for k and y:

  k·sin(y) = 2

  k·cos(y) = 2

The ratio of these equations is ...

  (k·sin(y))/(k·cos(y)) = 2/2

  tan(y) = 1   ⇒   y = π/4

  k = 2/sin(π/4) = 2√2

shifted equation

So, our original equation becomes ...

  2√2·sin(x +π/4) = √6

Dividing by √2 and using the inverse sine function, we have ...

  x +π/4 = arcsin((√3)/2) = π/2 ±π/6

  x = π/4 ±π/6

  x = π/12, 5π/12

__

double-angle equation

If we square both sides of the original equation, we get ...

  (2sin(x) +2cos(x))² = (√6)²

  4sin²(x) +8sin(x)cos(x) +4cos²(x) = 6

  2sin(x)cos(x) = (6 -4)/4 = 1/2 . .  . . use sin² +cos² = 1, subtract 4, divide by 4

Using the trig identity 2sin(x)cos(x) = sin(2x), we can find ...

  2x = arcsin(1/2) = π/2 ±π/3 +2kπ . . . . k = an integer;

  x = π/4 ±π/6 +kπ . . . . for integer k

  x = {π/12, 5π/12, 13π/12, 17π/12}

We know that squaring the equation can introduce extraneous solutions, so we need to try these out. For x in the third quadrant, the sine and cosine values are both negative, so the only useful solutions here are ...

  x = π/12, 5π/12

_____

Additional comment

Based on the above, we now know that any trig expression of the form ...

  a·sin(x) +b·cos(x)

can be rewritten to the form ...

  (√(a² +b²))·sin(x +arctan(b/a)) . . . . . a scaled and shifted sine function

The arctangent will have to take the signs of 'a' and 'b' into account in order to get the angle quadrant right.

Chef Fabio does beginning inventory on Thursday night and finds that he has $1456 in food products in the restaurant. Throughout the week he purchases:

$457 produce,
$632 protein,
$356 dry goods, and
$147 dairy.

The following Thursday he does ending inventory and finds that he has $1643 in food. He looks at his sales and finds that he made $5546 over the same 7 day period. What is his food cost as a percentage of sales (food cost percentage)?

Answers

Using it's concept, it is found that the percentage of his sales that area food costs is of 29.62%.

What is a percentage?

The percentage of an amount a over a total amount b is given by a multiplied by 100% and divided by b, that is:

[tex]P = \frac{a}{b} \times 100\%[/tex]

In this problem, he has $1643 out of $5546 in food, hence the percentage is given by:

[tex]P = \frac{1643}{5546} \times 100\% = 29.62%[/tex]

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Write the equation of the line with a slope of 3/4 and a y'-intercept of -7 in Slope-Intercept and Poin Slope Form.

Answers

Slope intercept form: y = 3/4 x - 7
Point slope form: y + 7 = 3/4 (x+0)

First line joins ordered pairs negative 4, 3 and 2, negative 3. Second line joins negative 4, negative 3 and 2, 3. Part A shaded above first and second line. Part B shaded below first line and above second line. Part C shaded below first and second lines. Part D shaded above first line and below second line. Which part of the graph best represents the solution set to the system of inequalities y ≥ x + 1 and y + x ≤ −1? Part A Part B Part C Part D Question 3(Multiple Choice Worth 5 points) (05.05 MC) Two systems of equations are shown below: System A System B 2x + y = 5 −10x + 19y = −1 −4x + 6y = −2 −4x + 6y = −2 Which of the following statements is correct about the two systems of equations? They will have the same solutions because the first equation of System B is obtained by adding the first equation of System A to 2 times the second equation of System A. They will have the same solution because the first equation of System B is obtained by adding the first equation of System A to 3 times the second equation of System A. The value of x for System B will be −5 times the value of x for System A because the coefficient of x in the first equation of System B is −5 times the coefficient of x in the first equation of System A. The value of x for System A will be equal to the value of y for System B because the first equation of System B is obtained by adding −12 to the first equation of System A and the second equations are identical. Question 4(Multiple Choice Worth 5 points) (05.06 LC) To which graph does the point (−1, −4) belong? y ≤ −x + 4 y ≤ −x − 6 y ≤ 2x − 3 y ≤ 5x − 1 Question 5(Multiple Choice Worth 5 points) (06.04 MC) What is the equation of the graph below? A graph shows a parabola that opens up and crosses the x axis at negative two and negative four. y = − (x − 3)2 + 1 y = − (x + 3)2 + 1 y = (x − 3)2 − 1 y = (x + 3)2 − 1 Question 6 (Fill-In-The-Blank Worth 5 points) (06.04 MC) A ball is thrown upward from the top of a building. The function below

Answers

The part that represents the solution to the inequality will be Part B shaded below first line and above second line.

How to depict the inequality?

From the information given, the equation of the first line will be:

y - 3 = (-3 - 3/2 + 4)(x + 4)

y - 3 = -1(x + 4)

y + x = -4 + 3

x + y = -1

The equation of the second line will be:

y + 3 = -1(x + 4)

y = x + 4 - 3

y = x + 1

This is plotted on the graph attached.

From the systems of equations, the statement that is correct about the two systems of equations is that They will have the same solution because the first equation of System B is obtained by adding the first equation of System A to 3 times the second equation of System A.

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Which expression is equivalent?

Answers

Answer:

Last one/D 9^9/5/5^9/10

Step-by-step explanation:

Enlarge the shape on scale factor 0

Answers

Answer:

Multiply with 2 to the original sides

Which absolute value functions will be narrower than the parent function, f(x) = |x|? Check all that apply.

f(x) = |x|
f(x) = |x – 2|
f(x) = |x| + 3
f(x) = 2.9|x|
f(x) = 1.2|x + 8|
f(x) = 0.7|x| – 3.2

Answers

The correct answer is option 4 which is f(x) = 2.9|x| is narrower than the parent function f(x) = |x|

What is a function?

A function is defined as the expression that set up the relationship between the dependent variable and independent variable.

Given parent function is f(x)=|x|

Now we have to find which function from given choices will be narrower than the parent function.

Notice that adding or subtracting some number from the parent function only shifts the graph up, down, and left of the right side.

But that will not make the function narrower or broader.

So f(x) = |x – 2| and f(x) = |x| + 3, can't be the answer.

Multiplying by some positive real number which is more than 1, makes the function narrower.

Only f(x) = 2.9|x| from remaining choices fits that case.

Hence correct answer is option 4 which is f(x) = 2.9|x| is narrower than the parent function f(x) = |x|

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Answer:

D,E

Step-by-step explanation:

Can y’all help me with ! I need correct anwsers ! Please

Answers

Answer:

-0.875

Step-by-step explanation:

So you have the points -4.25 and 2.50. To find the midpoint you simply add the two and then divide by 2. This results in (-4.25 + 2.50) / 2 = -0.875

I’m pretty sure it’s -0.875

(x^4) (3x^3-2) (4x^2+5x)

Answers

Answer:

12x^7+15x^6

Step-by-step explanation:

Change 3x^3-2 to 3x

(x^4)(3x)(4x^2+5x)

Multiply your single terms

(3x^5)(4x^2+5x)

Then distribute

12x^7+15x^6

2/5 X -3/4
i need help on this

Answers

Answer:

[tex]-\frac{3}{10}[/tex]

Step-by-step explanation:

[tex]\frac{2}{5} *-\frac{3}{4} \\=-\frac{6}{20} \\=-\frac{3}{10}[/tex] (Reduced to simplest form.)

For a fair coin, suppose you toss the coin 100 times.

What is the probability of getting more than 66 heads?

Answers

Using the normal distribution, it is found that there is a 0.0005 = 0.05% probability of getting more than 66 heads.

Normal Probability Distribution

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with [tex]\mu = np, \sigma = \sqrt{np(1-p)}[/tex].

For the binomial distribution, the parameters are given as follows:

n = 100, p = 0.5.

Hence the mean and the standard deviation of the approximation are given as follows:

[tex]\mu = np = 100(0.5) = 50[/tex].[tex]\sigma = \sqrt{np(1-p)} = \sqrt{100(0.5)(0.5)} = 5[/tex]

Using continuity correction, the probability of getting more than 66 heads is P(X > 66 + 0.5) = P(X > 66.5), which is one subtracted by the p-value of Z when X = 66.5.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{66.5 - 50}{5}[/tex]

Z = 3.3

Z = 3.3 has a p-value of 0.9995.

1 - 0.9995 = 0.0005.

0.0005 = 0.05%

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What must be added to -31 to get 12

Answers

Answer:

43

Step-by-step explanation:

31+12=43

Therefore adding 43 to -31 should give the answer 12.

Hii!

____________________________________________________________

Answer:

43

Step-by-step explanation:

We can find an answer to this question by setting up an equation.

-31+x=12

x is the unknown amount we should add to -31 to obtain 12.

Now, to solve it for the variable, x, we need to add 31 to both sides.

Upon doing this we obtain.

x=43

∴, 43 should be added to -31 to get 12

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Hope that this helped! Best wishes.

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A function, h(x), is defined as shown.

h(x) = StartLayout Enlarged left-brace 1st row 1st column one-fourth x minus 4, 2nd column x less-than-or-equal-to 0 2nd row 1st column one-third x minus 3, 2nd column 0 less-than x less-than-or-equal-to 3, 3rd row 1st column one-half x minus 2, 2nd column x greater-than-or-equal-to 4

Which graph represents h(x)?

On a coordinate plane, a piecewise function has 3 lines. The first line starts at (negative 4, 0) and goes up to a closed circle at (0, 1). The second line starts at (0, negative 3) and goes up to a closed circle at (3, negative 2). The third line has a closed circle at (4, negative 2) and goes up to (6, negative 1).

On a coordinate plane, a piecewise function has 3 lines. The first line starts at (negative 4, negative 5) and goes up to a closed circle at (0, negative 4). The second line starts at (0, negative 3) and goes up to a closed circle at (3, negative 2). The third line has a closed circle at (4, 0) and goes up to (6, 1).

On a coordinate plane, a piecewise function has 3 lines. The first line starts at (negative 4, 3) and goes up to a closed circle at (0, 4). The second line starts at (0, 3) and goes up to a closed circle at (3, 4). The third line has a closed circle at (4, 4) and goes up to (6, 5).

On a coordinate plane, a piecewise function has 3 lines. The first line starts at (negative 4, 0) and goes up to a closed circle at (0, 1). The second line starts at (0, negative 1) and goes up to a closed circle at (3, 0). The third line has a closed circle at (4, negative 2) and goes up to (6, negative 1).

Answers

The graph that represents h(x) is option B: On a coordinate plane, a piecewise function has 3 lines. The first line starts at (negative 4, negative 5) and goes up to a closed circle at (0, negative 4). ....

What is the graph about?

Using the piecewise function, one can see that;

In x ≤ 0, the slope of the graph of h(x) = 1/4

In 0 < x ≤ 3, the slope of the graph of h(x) = 1/3

In x ≥ 4, the slope of the graph of h(x) = 1/2

Note that the movement is left to right and the slope of h(x) often increases and the slope of the graph is said to become steeper.

Option B shows the graph of h(x) as it best tells the exact point of various aspect of the function.

Therefore, The graph that represents h(x) is option B: On a coordinate plane, a piecewise function has 3 lines. The first line starts at (negative 4, negative 5) and goes up to a closed circle at (0, negative 4). The second line starts at (0, negative 3) and goes up to a closed circle at (3, negative 2). The third line has a closed circle at (4, 0) and goes up to (6, 1).

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Complete the remainder of the
table for the given function rule:
y = ²x + 4
X-6 -3 03 3 6
y 0 [?] [] [] []

Answers

Answer: 2, 4, 6, 8

Step-by-step explanation:

Just plug x into the equation for each one.

x = -3

[tex]y=\frac{2(-3)}{3} +4\\y=\frac{-6}{3} +4\\y=2[/tex]

With this one, you can see it is a linear equation and for every increase of 3 on x, y in increased by 2.

x   -6   -3   0   3   6

y   0   2    4   6   8

Find the inverse of the function.
y=x+8

Answers

Answer:

y^-1= x +8

Step-by-step explanation:

this may be helpful for you


Drainpipe comes in lengths of 2.5 metres. A man wants to buy drainpipe to fit down
one side of his house from the ground to the gutter.
Estimate how many lengths he will need.
lengths

Answers

The man would need 6 drainpipes with length of 2.5 meters each to fit the side of his house from the ground to the gutter.

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

Let us assume that the distance from the man side of the house to the gutter is 15 m, since the drainpipe comes in lengths of 2.5 m, hence:

Number of drainpipe needed = 15 m / 2.5 m = 6

The man would need 6 drainpipes with length of 2.5 meters each to fit the side of his house from the ground to the gutter.

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The required quantity of drainpipe is mathematically given as six.

L=6

What is the lengths he will need?

Generally, Let's say the distance from the male side of the house to the gutter is 15 meters. Since the length of the drainpipe typically comes in increments of 2.5 meters, we may reason as follows:

In conclusion, The required quantity of drainpipe is equal to 15 meters divided by 2.5 meters, which is equal to six.

L=15/2.5

L=6

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Find the length of the side labeled . Round intermediate values
to the nearest tenth. Use the rounded values to calculate the next
value. Round your final answer to the nearest tenth.

Answers

Step-by-step explanation:

ATTACHED IS THE SOLUTION!!PLEASE DON'T HESITATE TO ASK WHERE YOU DON'T UNDERSTAND.

Evaluate.
-|a+bl
2-c
when a = 1, b = -2, and c = -7
Enter your answer as a simplified fraction in the box.

Answers

Answer:

-9

Step-by-step explanation:

-|1-2|2+7

-|-1|9

-9×1

-9

As a unit price, a half-dozen for
$6.00 is
a. $36.00 each
b. $6.00 each
c. $0.50 each
d. $1.00 each

Answers

d. $1.00 each is the answer
d.$1.00 each
Explanation:
A dozen is 12 half of 12 is 6
6 divided by 6 is 1 therefore u have 1.00 dollar each

find the area for this pls

Answers

Answer:

3,36 in^2

Step-by-step explanation:

The geometric shape shown in image is called a trapezoid

to calculate the area of a trapezoid we use the following formula:

1/2*(a+b)*h (a and b are bases, h: height)

bases are 1.3 and 3.5 and height is 1.4

1/2(1.3 + 3.5)*(1.4) = 3,36 the area is stated in square units so the answer is

3,36 in^2

If the center of a circle is at (5,-7)
and its radius is 6, complete its
equation:

Answers

Answer:

(x-5)²+(y+7)²=36

or

x²+y²-10x+14y+38=0

Below what price level would the firm go out of business in the long run?

Answers

A firm should go out of business in the long run when its price level is less than the average total cost.

When should a firm go out of business in the long run?

The long run is a period where all factors of production are varied. It is known as the planning time of a firm. In the long run, if the if the average total cost is greater than the price, the firm should exit the market.

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pls solve this question ​

Answers

Answer:

[tex] {( \sqrt{ {x}^{ - 3} }) }^{5} = ({( {x}^{ - 3}) }^{ \frac{1}{2} } ) ^{5} \\ \\ = {x}^{ - 3 \times \frac{1}{2} \times 5} = {x}^{ - \frac{15}{2} } = \frac{1}{ {x}^{ \frac{15}{2} } } [/tex]

Or ;

[tex] {( \sqrt{ {x}^{ - 3} } )}^{5} = {( \sqrt{ \frac{1}{ {x}^{3} }} })^{5} = ( { \frac{ \sqrt{1} }{ \sqrt{ {x}^{3} } } })^{5} \\ \\ = ( { \frac{1}{ \sqrt{x} \sqrt{ {x}^{2} } } })^{5} = ({ \frac{1}{ x\sqrt{x} }})^{5} \\ \\ = ( \frac{ {(1)}^{5} }{ {x}^{5} ( \sqrt{x} )^{5} } ) = \frac{1}{ {x}^{5} \times {x}^{ \frac{1}{2} \times 5 } } \\ \\ = \frac{1}{ {x}^{5} \times {x}^{ \frac{5}{2} } } = \frac{1}{ {x}^{5} \sqrt{ {x}^{5} } } \\ \\ = \frac{1}{ {x}^{5} \sqrt{ {x}^{4} {x}^{1} } } = \frac{1}{ {x}^{5} \sqrt{x} \sqrt{( { {x}^{2} })^{2} } } \\ \\ = \frac{1}{ {x}^{5} {x}^{2} \sqrt{x} } = \frac{1}{ {x}^{7} \sqrt{x} } = \frac{ \sqrt{x} }{ {x}^{8} } [/tex]

find the zeros of following quadratic polynomial and verify the relationship between the zeros and the coefficient of the polynomial f(x)=5x-4√3+2√3x²​

Answers

Answer:

[tex]\textsf{Zeros}: \quad x=\dfrac {\sqrt{3}}{2}, \:\:x=-\dfrac {4\sqrt{3}}{3}[/tex]

Step-by-step explanation:

Rewrite the given polynomial in the form ax² + bx + c:

[tex]f(x)=2 \sqrt{3}x^2+5x-4 \sqrt{3}[/tex]

To find the zeros, set the function to zero and solve for x using the quadratic formula.

[tex]\implies 2 \sqrt{3}x^2+5x-4 \sqrt{3}=0[/tex]

Quadratic formula:

[tex]x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0[/tex]

Therefore,

a = 2√3b = 5c = - 4√3

Substituting the values into the quadratic formula:

[tex]\implies x=\dfrac{-5 \pm \sqrt{5^2-4(2\sqrt{3})(-4\sqrt{3})} }{2(2\sqrt{3})}[/tex]

[tex]\implies x=\dfrac {-5 \pm \sqrt {121}}{4\sqrt{3}}[/tex]

[tex]\implies x=\dfrac {-5 \pm 11}{4\sqrt{3}}[/tex]

[tex]\implies x=\dfrac {6}{4\sqrt{3}}, \:\:x=\dfrac {-16}{4\sqrt{3}}[/tex]

[tex]\implies x=\dfrac {3}{2\sqrt{3}}, \:\:x=-\dfrac {4}{\sqrt{3}}[/tex]

[tex]\implies x=\dfrac {\sqrt{3}}{2}, \:\:x=-\dfrac {4\sqrt{3}}{3}[/tex]

The sum of the roots of a polynomial is -b/a:

[tex]\implies -\dfrac{b}{a}=-\dfrac{5}{2 \sqrt{3}}=-\dfrac{5\sqrt{3}}{6}[/tex]

The sum of the found roots is:

[tex]\implies \left(\dfrac {\sqrt{3}}{2}\right)+\left(-\dfrac {4\sqrt{3}}{3}\right)=-\dfrac{5\sqrt{3}}{6}[/tex]

Hence proving the sum of the roots is -b/a

The product of the roots of a polynomial is:  c/a

[tex]\implies \dfrac{c}{a}=\dfrac{-4\sqrt{3}}{2\sqrt{3}}=-2[/tex]

The product of the found roots is:

[tex]\implies \left(\dfrac {\sqrt{3}}{2}\right)\left(-\dfrac {4\sqrt{3}}{3}\right)=-\dfrac{12}{6}=-2[/tex]

Hence proving the product of the roots is c/a

Therefore, the relationship between the roots and the coefficients is verified.

Answer:

Step-by-step explanation:

Rewrite the given polynomial in the form ax² + bx + c:

To find the zeros, set the function to zero and solve for x using the quadratic formula.

Quadratic formula:

Therefore,

a = 2√3

b = 5

c = - 4√3

Substituting the values into the quadratic formula:

The sum of the roots of a polynomial is -b/a:

The sum of the found roots is:

Hence proving the sum of the roots is -b/a

The product of the roots of a polynomial is: c/a

The product of the found roots is:

Hence proving the product of the roots is c/a

Therefore, the relationship between the roots and the coefficients is verified.

Expression Math problem...help and get 15 pts!

Answers

When h = 0 ,  [f(x + h) - f(x)]/h  = 2x +2 for the given expression.

The missing expression is  f(x) = x² + 2x.

What is formula of difference quotient ?

f(x+h)-f(x)/h is called the formula of difference quotient.

When h---> 0 ,

the expression f'(x) = (f(x-h) - f(x)) / h is the equation for tangent to the line

Here the the expression is

f(x) = x² + 2x

Determining f(x + h) by substituting x = x + h on both sides of the given f(x).

Then f(x + h) = (x + h)² + 2(x + h)

= x² + 2xh + h² + 2x + 2h

the difference f(x + h) - f(x).

f(x + h) - f(x) = [x²  + 2xh + h²  + 2x + 2h] - [x² + 2x]

= 2xh + h² + 2h

Divide the difference from h as in the formula of difference coefficient

[f(x + h) - f(x)]/h = (2xh + h² + 2h) / h

= 2x + h + 2

So, when h = 0 ,  [f(x + h) - f(x)]/h  = 2x +2

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(X+p)(x+q) what part of the trinomial will equal the product of p and q?

Answers

The part of the trinomial that will equal the product of p and q is the constant part

How to determine the part?

The expression is given as:

(x + p)(x + q)

From the expression, p and q are both constants.

When a constant is multiplied to another, the result is a constant

This means that:

pq = constant

Hence, the part of the trinomial that will equal the product of p and q is the constant part

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On a coordinate plane, a dashed solid line has an equation of y less-than five-thirds x + 1. It has a positive slope and goes through (negative 3, negative 4) and (0, 1). Everything to the right of the line is shaded.
Which linear inequality will not have a shared solution set with the graphed linear inequality?

y < Five-thirdsx – 2
y < Negative five-thirdsx + 1
y > Five-thirdsx + 2
y > Negative five-thirdsx + 2

Answers

The inequality is represented by y < 5/3(x+1)

Use the information about the straight line and find the equation of the line.

Given coordinates (-3,-4) and (0,1), we can find the slope

Slope,  

Change in y = y2 – y1 = 1-(-4) = 5

Change in x = x2 – x1 = 0-(-3) = 3

Therefore, Slope (m) = Change in y / Change in x = 5/3

Equation of line using m = 5/3 and points (0,1) and (x, y) in form of y = mx + c

Y – 1/ X – 0 =5/3

3(Y-1) = 5(X)

3Y -3 = 5X

3Y = 5X + 3

Y = 5X + 3/3

Y = 5/3(X + 1)

To find the inequality take a point in the shaded region and check it in the above equation.

Given Options

a. y < Five-thirds x – 2

b. y < Negative five-thirds x + 1

c. y > Five-thirds x + 2

d. y > Negative five-thirds x + 2

 Let’s take points (-3,-4) for verification

  Option a: y < 5/3 (x-2)

                     -4 < 5/3(-3-2)

                      --4 < -3.33

-4 is less than -3.33

Thus option a is in the shaded region

 Option b: y < -5/3 (x+1)

                     -4 < -5/3(-3+1)

                      --4 < 3.33

-4 is less than 3.33

Thus option a is in the shaded region

 Option c: y > 5/3 (x+2)

                     -4 > 5/3(-3+2)

                      --4 > -1.67

-4 is NOT GREATER than -1.67

Thus option c is NOT in the shaded region

Option d: y > -5/3 (x+2)

                     -4 > - 5/3(-3+2)

                      --4 > 1.67

-4 is NOT GREATER than 1.67

Thus option d is NOT in the shaded region

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Answer:

y > Five-thirdsx + 2

Step-by-step explanation:

a u.s dollar bill remains in circulation about 1 1/4 years. A u.s coin is in circulation about 22 1/2 times longer. About how long is a coin circulation brainly

Answers

Answer:

28.125

Step-by-step explanation:

22.5×1.25=28.125

Answer:

28 1/8

Step-by-step explanation:

1.25 x 22.5 = 28.125

Each team is required to bring 24 baseballs to each game. If there are 3
baseballs in a pack, how many total packs do the teams bring to each game?

Answers

The total packs the teams bring to each game is 8 packs.

How many packs do the team bring to each game?

Division is the process of dividing a number into equal parts using another number. The sign used to denote division is ÷.

Number of packs = 24 ÷ 3 = 8

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Skylar models the volume of a popcorn box as a right rectangular prism and the box can hold 69 cubic inches of popcorn when it is full. Its width is 33 in and its height is 5 3/4 in. Find the length of the popcorn box in inches. Round your answer to the nearest tenth if necessary.

Answers

Answer:

4/11 of an inch (about .4 of an inch)

Step-by-step explanation:

[tex]l \times 33 \times 5.75 = 69[/tex]

[tex]189.75l = 69[/tex]

[tex]l = \frac{69}{189.75} = \frac{4}{11} = .3636[/tex]

So the length of the popcorn box is 4/11 of an inch, or about .4 of an inch.

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