1) [tex]\overline{RS} \perp \overline{ST}, \overline{RS} \perp \overline{SQ}, \angle STR \cong \angle SQR[/tex] (given)
2) [tex]\overline{RS} \cong \overline{RS}[/tex] (reflexive property)
3) [tex]\angle RST[/tex] and [tex]\angle RSQ[/tex] are right angles (perpendicular lines form right angles)
4) [tex]\triangle RST \cong \triangle RSQ[/tex] (AAS)
What is the area of this triangle?
1375 ft²
1500 ft²
3300 ft²
4500 ft²
Answer:
Area of a triangle = 1/2 * base * height
here ,
base = 120 ft
height = 25 ft
Area = 1/2* 120*25
= 60 * 25
= 1500 ft²
Answer 2
Answer:
1/2 * base * height
so 1/2 * 25 * 120
= 1500
Homework Progress 46 / 90 Marks Work out the length of AB. Give your answer to 3 significant figures. A (-1, 6) B (5, 3) X + Homework Progress 46 / 90 Marks Work out the length of AB . Give your answer to 3 significant figures . A ( -1 , 6 ) B ( 5 , 3 ) X +
Answer: 6.71
Step-by-step explanation:
[tex]AB=\sqrt{(-1-5)^{2}+(6-3)^{2}} \approx \boxed{6.71}[/tex]
3. Complete the square for the following equations:
a. y = 2x² 12x + 1
b. y = 4x² + 48x - 10
The square for the equation: [tex]y=2x^{2} + 12x +1[/tex] is [tex]y=2(x+3)x^{2} -17[/tex]
The square for the equation: [tex]y=4x^{2} +48x-10[/tex] is [tex]y=4(x+6)x^{2} -154[/tex]
a)
[tex]y=2x^{2} +12x +1[/tex]
[tex]y = 2[(x^{2} + 6x)] + 1[/tex] ( taking common)
[tex]y = 2[(x+3)^{2} - 9] + 1[/tex] ( adding and subtracting 9 to make a square term
[tex]y = 2(x+3)^{2} - 18 + 1[/tex] ( multiplying by 2)
[tex]y=2(x+3)x^{2} -17[/tex]
b)
[tex]y=4x^{2} +48x-10[/tex]
[tex]y = 4[(x^{2} + 12x)] - 10[/tex] (taking 4 common)
[tex]y = 4[(x+6)^{2} - 36)] - 10[/tex] (adding and subtracting 36)
[tex]y = 4(x+6)^{2} - 144 - 10[/tex](multiplying by 4)
[tex]y=4(x+6)x^{2} -154[/tex]
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Calculate the cost of the number of units used
Step-by-step explanation:
calculated the cost of numbers of units usex
Help me solve please with in depth explanation
3. The table shows information about the times for 100 people to complete a task.
Answer:
kuch bhi hai one kutiya kamini sour hii byy7 t-shirts and a hat costs £47.00
5 t-shirts and a hat costs £35.00.
How much does a t-shirt cost?
How much does a hat cost?
Answer:
Shirts are 6
Hats are 5
Step-by-step explanation:
This is a system of equations. Set up the equations first.
7s + h = 47
5s + h = 35
----------------------- Subtract the equations to eliminate the h variable
2s = 12 Divide by 2 to solve
s = 6 Each hat is 6
Plug the 6 in for s in either of the original equations
7(6) + h = 47
42 + h = 47 Subtract 42 from both sides
h = 5
Please someone do this for me
Answer:
A = -12
Step-by-step explanation:
A put in -2 for 'x' in the equation to find value
2(-2) - y = 8 add 4 to both sides
-y = 12
y = -12
I think YOU can now find B and C with this method !
The height of a tank is 3 meter and volume is 12 million centimeters. find the area of the square base of the tank in square meters
Answer:
75
Step-by-step explanation:
Given log subscript 4 baseline 3 almost-equals 0.792 and log subscript 4 baseline 21 almost-equals 2.196, what is log subscript 4 baseline 7?
The value of the logarithmic function log₄7 = 1.404, when the values of the logarithmic functions log₄3 = 0.792 and log₄21 = 2.196.
We are given the logarithmic functions:
log₄3 = 0.792 ,,, (i), and log₄21 = 2.196 ... (ii),
and we are asked to find the value of the logarithmic function log₄7.
On subtracting (i) from (ii), we get:
log₄21 - log₄3 = 2.196 - 0.792.
Using the quotient law of logarithms, according to which:
logₓa - logₓb = logₓ(a/b), we can write the above equation as:
log₄(21/3) = 1.404,
or, log₄7 = 1.404.
Therefore, the value of the logarithmic function log₄7 = 1.404, when the values of the logarithmic functions log₄3 = 0.792 and log₄21 = 2.196.
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Answer:
A.
1.404
Step-by-step explanation:
If u get 2 points every 5 minutes, how long will it take to get 3,600 points?
Answer:
9,000 minutes (150 hours)
Step-by-step explanation:
You have 3,600 points total; you need to divide it by 2 points.
3,600 ÷ 2 = 1,800
So, now you need to multiply the 1,800 points by 5 minutes.
1,800 × 5 = 9,000
Another way:
You can figure out how long it takes to get 1 point. If 2 points takes 5 minutes, divide 5 by 2.
5 ÷ 2 = 2.5
Now you need to figure out how long it would take to get 3,600 points. If each point takes 2.5 minutes, just multiply.
3,600 × 2.5 = 9,000
It would take 9,000 minutes (which is equivalent to 150 hours) to get to 3,600 points.
The terminal side of an angle in standard position passes through p(–3, –4). what is the value of tangent theta?
Answer:
4/3
Step-by-step explanation:
The tangent of any angle (θ) in standard position that has point (x, y) on its terminal ray is ...
tan(θ) = y/x
__
For the given point on the terminal side, the tangent is ...
tan(θ) = (-4)/(-3) = 4/3
_____
Additional comment
There are several ways this can be explained. One of them makes use of the relation between rectangular and polar coordinates:
(x, y) = (r·cos(θ), r·sin(θ))
Then the ratio y/x is ...
y/x = (r·sin(θ))/(r·cos(θ)) = sin(θ)/cos(θ) = tan(θ)
please help i just started summer school online Part F
Several minutes later, Raul decides to measure the water temperature again. He finds that the temperature changed by -0.6°F. What is the temperature of the water now? Show your work.
Answer:
Step-by-step explanation:
basically all you do is
1. Select all the true statements.
A. √-I is an imaginary number.
-1
B. There are no real numbers that satisfy the equation x = √√-1.
C. Because √-I is imaginary, no one does math with it.
D. The equation x² = -1 has real solutions.
E. √-T = -1 because -1 -1 = -1.
Answer:
A , B , D
Step-by-step explanation:
What is the surface area of the cylinder with height 4 yd and radius 5 yd? Round your answer to the nearest thousandth.
Answer:
282.743 yd²
Step-by-step explanation:
Surface Area of the Cylinder: Top Base + Bottom Base + Side
Area of Top Base (Circle): πr² = π(5 yd)² = 25π yd²
Area of Bottom Base (Circle): same as top base = 25π yd²
Area of Side (Rectangle): Circumference*Height = (2πr)*(4 yd) =
2π(5 yd)*(4 yd) = 40π yd²
Total Surface Area = 25π yd² + 25π yd² + 40π yd² = 90π yd² = 282.743 yd²
Please help!!!!!!!
picture below
If the function is vertically stretched by a factor of 3, the resulting function will be g(x) = [tex]3(5^{x-2})[/tex]
Vertical stretch of a functionGiven the parent function f(x) = x, if the function is vertically stretched by k units, the resulting function will be g(x) = kx
Given the parent function
f(x) = [tex]5^{x-2}[/tex]
If the function is vertically stretched by a factor of 3, the resulting function will be g(x) = [tex]3(5^{x-2})[/tex]
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Which statement is true?
O When an altitude is drawn from the right angle in a right triangle it creates two similar triangles.
O When an altitude is drawn from an acute angle in a right triangle it creates three similar triangles.
O When an altitude is drawn from the right angle of a right triangle it creates three similar triangles.
O When an altitude is drawn from an acute angle in a right triangle it creates two similar triangles.
Answer:
C) When an altitude is drawn from the right angle of a right triangle it creates three similar triangles.
Step-by-step explanation:
The Inscribed Similar Triangles Theorem states that if an altitude is drawn from the right angle of any right triangle, then the two triangles formed are similar to the original triangle and all three triangles are similar to each other.
100 points helpppp now
Solve the inequality hurrry show your work
33+6f<33
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \:f < 0 [/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
[tex]\qquad \tt \rightarrow \: 33 + 6f < 33[/tex]
[ subtract 33 on both sides ]
[tex]\qquad \tt \rightarrow \: 33 - 33+ 6f < 33 - 33[/tex]
[tex]\qquad \tt \rightarrow \: 6f < 0[/tex]
[tex]\qquad \tt \rightarrow \: f < 0[/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
8. If a conditional is true and its hypothesis is true, then its_____ is true.
Venn diagram in maths ! !
Answer:
People surveyed: 79
a) p(s) = 46/79
b) p(snv) = 13/79
c) p(suv) = 96/79
hope this helps, and tell me if you get it right! It's prob wrong though, im bad at venn diagrams (×_×)⌒☆
Which is equivalent to 3√8* ?
O x √8^3
O 8 ^3/x
O 8 ^x/3
O 8^3x
Answer:
O 8 ^x/3
Step-by-step explanation:
Remember that :
[tex]\sqrt[n]{x} = x^\frac{1}{n}[/tex]
………………………………
Then
[tex]\sqrt[n]{8^x} = (8^{x})^{\frac{1}{3}}[/tex]
[tex]= 8^{x\times\frac{1}{3}[/tex]
[tex]=8^{\frac{x}{3}[/tex]
HELPP
Simplify the expression 6^3+ 5(4 − 2).
28
36
226
234
Answer:
BODMAS
[tex] {6}^{3 } + 5(4 - 2) = 216 + 5(2) \\ = 216 + 10 \\ = 226[/tex]
Answer: Answer is 226
Step-by-step explanation: Do math
A climber is on a hike. After an hour he is at an altitude of 150 feet. After 2 hours, he is at an altitude of 275 feet. After 4 hours, he is at an altitude of 525 feet and after 6 hours, he is at an altitude of 700 feet. Which table could be used to model his climb?
The table that could be used to model his climb will consist of 125 ft/h for the first two hours and 87.5 ft/h for the next 4 hours.
Equation of motion of the climberThe equation that can be used to model the motion of the climber is calculated as follows;
(1, 150)
(2, 275)
(4, 525)
(6, 700)
Slope for the first two hoursm = (275 - 150)/(2 - 1) = 125 ft per hour
Slope for the next 4 hoursm = (700 - 525)/(4 - 2) = 87.5 ft/hr
Thus, the table that could be used to model his climb will consist of 125 ft/h for the first two hours and 87.5 ft/h for the next 4 hours.
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Find the surface area of the cone in terms of 1.
15 cm
3 cm
In terms of l?
TSA
πr²+πrlπr(l+r)π(3)(3+l)9.42(3+l) cm²LSA
πrl9.42l cm²Answer:
[tex]\sf SA=54\pi\:\:\:cm^2[/tex]
Step-by-step explanation:
Surface Area of a Cone
[tex]\sf SA=\pi r l+\pi r^2[/tex]
where:
r is the radiusl is the slant heightGiven:
r = 3 cml = 15 cmSubstitute the given values into the formula and solve for SA:
[tex]\implies \sf SA=\pi (3)(15)+\pi (3)^2[/tex]
[tex]\implies \sf SA=45\pi+ 9 \pi[/tex]
[tex]\implies \sf SA=54\pi\:\:cm^2[/tex]
Therefore, the surface area of the cone in terms of pi is:
[tex]\sf SA=54 \pi\:\:\:cm^2[/tex]
Calculate the lenth of AC to 1 decimal place in the trapezium below.
Answer:
18.1cm
Step-by-step explanation:
Please refer to the attached photo for a better understanding. Apologies for the terrible drawing.
First we will find the length of BE by using pythagoras' Theorem.
[tex]c^{2} =a^{2} +b^{2} \\AB^{2} =BE^{2} +EA^{2} \\16^{2} =BE^{2} +7^{2} \\256=BE^{2} +49\\BE^{2} =256-49\\BE=\sqrt{207} cm[/tex]
We will leave BE as it is as it is not the final answer.
Since we know CD = BE,
CD = [tex]\sqrt{207} cm[/tex]
Now from the photo, draw a line from C to A or A to C, you will see another triangle.
Now we will use Pythagora's Theorem again to find AC.
[tex]AC^{2} =AD^{2} +DC^{2} \\AC^{2} =11^{2} +(\sqrt{207}) ^{2} \\AC^{2} = 121+207\\AC^{2} =328\\AC=\sqrt{328} \\=18.1cm (1dp)[/tex]
find the length of CB
A. 7
B. 4
C. 14
D. 2
Answer:
7
Step-by-step explanation:
5x-3 = 3x+1
2x=4
x=2
plug in
5(2)-3
10-3
7
answer: 7
area of rectangle = l×b find area of rectangle in sq cm
a) l=7cm,b=4cm
Answer:
[tex]28{cm}^{2} [/tex]
Step-by-step explanation:
we know
area of rectangle=l*b=(7*4)sq cm=28sq cm
40. Se desea distribuir las bancas dentro de un salón de clases cada 1.5 m como
se muestra en la imagen, ¿de qué forma se puede saber el área requerida para
conservar la separación de las bancas?
1.5m
La forma adecuada para saber el área requerida para conservar la separación de las sillas es multiplicar (7.5) (4.5) opción B.
¿Cómo calcular el área requerida para mantener la separación?Para identificar la operación necesaria para calcular el área requerida para ubicar las sillas con su respectiva separación de 1.5 metros es:
7.5 × 4.5 = 33.75Esta expresión nos va a permitir calcular el área necesaria debido a que la separación entre sillas es 1.5 metros y tenemos 6 sillas a lo largo y 4 sillas a lo ancho, es decir:
1.5 × 5 = 7.5 distancia a lo largo1.5 × 3 = 4.5 distancia a lo anchoNota: Esta pregunta está incompleta porque falta la imagen y las opciones. Aquí está la información faltante:
Opciones:
A. Multiplicar (6)(4)
B. Multiplicar (7.5)(4.5)
C. Multiplicar (9)(6)
D. Multiplicar (9.5)(4.5)
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Jerry plans to keep up this saving pattern until he can no longer afford it. At that time he hopes to have enough in his account for his trip. How much will be in the account, after making the down payment, if the most he will be able to contribute in a month is $1,200?
HELP!!!!!
The graph of g(x) is the result of translating the graph of f(x) = 3x six units to the right. What is the equation of g(x)?
g(x) = 3x-6
g(x) = 3x+6
g(x)=3*-6
g(x)=3*+6
The answer is g(x) = 3x - 6
The two dot plots below compare the forearm lengths of two groups of schoolchildren:
Two dot plots are shown one below the other. The title for the top dot plot is Forearm Length, Group A and the title for the bottom plot is Forearm Length, Group B. Below the line for each dot plot is written Length followed by inches in parentheses. There are markings from 9 to 12 on each line at intervals of one. For the top line there are 3 dots above the second mark, 4 dots above the third mark and 3 dots above the fourth mark. For the bottom line there are 3 dots above the first mark, 5 dots above the second mark, and 2 dots above the third mark.
Based on visual inspection of the dot plots, which group appears to have the longer average forearm length?
Group A, because seven children have a forearm length longer than 10 inches
Group B, because two children have a forearm length longer than 10 inches
Group A, because one child in the group has the least forearm length of 9 inches
Group B, because three children in the group have the least forearm length of 9 inches
Answer:
Group A, because seven children have a forearm length longer than 10 inches
Step-by-step explanation:
Create the dot plots based on the given information (please see attached images).
Group A = blue dots
Group B = red dots
From inspection of the attached dot plots, we can see that Group A appears to have the longer average forearm length. This is because 7 children have a forearm length of longer than 10 inches.
To calculate the average forearm length, sum all data values and divide by the total number of data values.
[tex]\textsf{Average of Group A}=\dfrac{ 3 \times 10 + 4 \times 11 + 3 \times 12}{10}=11[/tex]
[tex]\textsf{Average of Group B}=\dfrac{ 3 \times 9 + 5\times 10+ 2\times 11}{10}=9.9[/tex]
Thus proving that Group A has the longer average former length.
According to given text data
Average of both groups
A:-
10(3)+11(4)+12(3)/1030+44+36/1066+44/10110/1011B:-
9(3)+5(10)+11(2)/1027+50+22/1049+50/1099/109.9Group A has bigger average