Juan is learning about like terms in his math class. He must check all the combinations below that are like terms which ones should he check

Answer: 2

Step-by-step explanation:

[tex]g(-2)=-2\\\\g(1)=4\\\\\frac{g(-2)-g(1)}{-2-1}=\frac{-2-4}{-3}=\boxed{2}[/tex]

Answer:

a = -9

b = -3

c = 11

d = 19

Step-by-step explanation:

a. x = -2

y= x² + 3x + 1

y= -2²+ 3(-2)+1

y= -4-6+1

y = -9

b. x= -1

y= x² + 3x+ 1

y= -1² + 3(-1) +1

y= -1 -3 + 1

y = -3

c. x =2

y = x² + 3x +1

y= 2²+ 3(2) +1

y= 4 +6 +1

y = 11

d. x= 3

y = x² +3x +1

y = 3² +3(3) +1

y= 9 +9 +1

y = 19

Answer:

8.888(8)

Step-by-step explanation:

(26 +2/3)/ 1/3 =8.8888888889

The Z-score is 2.306 to three decimal places. However, the Z-test statistic value shows that it is greater than the Z-critical value, so we reject the null hypothesis [tex]\mathbf{H_o}[/tex]

A z-score is a measurement of how often standard deviations the score obtained from a z-test is beyond or under the mean population.

From the given data information, let us find the mean and the standard deviation.

[tex]\mathbf{Mean (\bar x) = \dfrac{1154+5998+1007+...3987+4187+887}{10}}[/tex]

[tex]\mathbf{Mean (\bar x) = \dfrac{24256}{10}}[/tex]

Mean (x) = 2425.6

The hypothesis testing can be computed as:

[tex]\mathbf{H_o: \mu = 2425.6}[/tex]

[tex]\mathbf{H_1: \mu \ne 2425.6}[/tex]

The standard deviation (σ) is:

[tex]\mathbf{=\mathbf{ \sqrt{\dfrac{(1154-2425.6)^2+....+(887-2425.6)^2}{10-1}}}}[/tex]

[tex]\mathbf{= \sqrt{3199489}}[/tex]

= 1788.71

Now, the Z-test statistic is determined using the formula:

[tex]\mathbf{|Z| = |\dfrac{\bar x - \mu }{\sigma}| }[/tex]

[tex]\mathbf{|Z| = |\dfrac{2425.6 -6550 }{1788.71}| }[/tex]

[tex]\mathbf{|Z| = |-2.3058| }[/tex]

Z ≅ 2.306  

Therefore, at a 0.05 level of significance, the Z-critical value is 2.306. However, since the Z-test statistic value shows that it is greater than the Z-critical value, so we reject the null hypothesis [tex]\mathbf{H_o}[/tex]

The complete question is given as:

Using a sequencing method called "RNAseq," a researcher determines the level of FOXP2 expression in 10 different samples of lung tissue, and obtains these data:

Scientist has previously determined that FOXP2 is expressed in brain tissue at a level of 6,550. Calculate the Z-score associated with a test to see if the average expression of FOXP in her lung tissue samples is different from the levels she measured from brain tissue.

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Answer:

2025 $

Step-by-step explanation:

275 multiply 3 +1200

Answer:

A.$2,025

Step-by-step explanation:

$275 x 3 years + $1,200

= $2,025

Answer:

[tex]x = \frac{25}{13} [/tex]

Step-by-step explanation:

Given:

[tex] \frac{2}{5} x - \frac{1}{2} = \frac{1}{3} + \frac{5}{6} x[/tex]

Combine like terms:

[tex] \frac{2}{5} x - \frac{5}{6} x = \frac{1}{3} + \frac{1}{2} [/tex]

Find GCF :

[tex] \frac{12}{30} x - \frac{25}{30} = \frac{2}{6} + \frac{3}{6} [/tex]

Subtraction and Addition :

[tex] \frac{13}{30} x = \frac{5}{6} [/tex]

Divide both sides by 13/30 :

[tex] \frac{ \frac{13}{30} }{ \frac{13}{30} } x = \frac{ \frac{5}{6} }{ \frac{13}{30} } [/tex]

Simplify :

Multiplication (Reciprocal) :

[tex]x = \frac{5}{6} \times \frac{30}{13} [/tex]

[tex]x = \frac{150}{78} [/tex]

[tex]x = \frac{25}{13} [/tex]

Answer :

[tex]x = \frac{25}{13} [/tex]

Hope it helps

Answer:slope is 0.4

Step-by-step explanation:

y2-y1 divided by x2-x1

2-4/0-5=0.4

An expression is defined as a set of numbers, variables, and mathematical operations. The solution of (4 x 3)² ÷ 6 is 24.

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

The solution of the expression (4 x 3)² ÷ 6 is,

(4 x 3)² ÷ 6

= (12)² ÷ 6

= 144 ÷ 6

= 24

Hence, the solution of (4 x 3)² ÷ 6 is 24.

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Answer:

A,C,E

(if you find a better answer choose that.)

Step-by-step explanation:

This one has two acute angles and one obtuse.

This one is a scalene.

So, tick A,C,E

Answer:

[tex]\boxed{\sf x=12}[/tex]

Step-by-step explanation:

By applying Similar Triangles Theorem:-

[tex]\sf \cfrac{x}{6} =\cfrac{6}{3}[/tex]

We'll multiply both sides of the equation by 6, the LCM of 6,3.

[tex]\sf x=2 \times 6[/tex]

[tex]\sf x=12[/tex]

The equivalent equation to find the ordered pair will be y=0.3x where x represents the number of days the book is late and y represents the total fine fee.

A linear equation is an equation where the highest degree in the equation is 1.

for example, y=mx,

where y and x is the variable and m, is the constant.

Given, that the librarian charges $0.30 per each day that the book is late to submit

for estimating the relation between the number of days the book is late and the total fine fee

Let's assume the number of days the book is late is x,

and the total fine is y

the librarian charges $0.30 per one day

so for x days, the total charge will be =0.30x

so from above, it is clear that the linear equation will be

y=0.3x

applying all the order pairs in this equation we can decide.

The equivalent equation to find the ordered pair will be y=0.3x

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Answer:

Theres no bag we cant solve it without you showing a picture or describing it

Step-by-step explanation:

Answer:

R ,is the Resultant of two forces,

∠ACB +50°=180°

∠ACB=180° -50°

∠ACB=130°

→Cos(130°)=Cos (180°-50°)= -cos 50°= -0.6427

Magnitude of resultant force =70.70 Newtons(Approx)

Answer:

(u + [tex]\frac{65}{2}[/tex] )²

Step-by-step explanation:

u² + 65u

to complete the square

add ( half the coefficient of the u- term )²

= u² + 2([tex]\frac{65}{2}[/tex] )u + [tex]\frac{4225}{4}[/tex]

= (u + [tex]\frac{65}{2}[/tex] )²

Answer:

4x+2h+5

Step-by-step explanation:

[tex]\frac{(2(x+h)^{2}+5(x+h)) - (2x^{2} +5x) }{h} \\[/tex]

For now I'm just going to ignore the denominator for simplicity

[tex](2(x^{2}+2xh+h^{2})+5x+5h) - (2x^{2} +5x)\\(2x^{2}+4xh+2h^{2}+5x+5h) - (2x^{2} +5x)\\(4xh+2h^{2}+5h)\\\\\frac{(4xh+2h^{2}+5h)}{h}\\ 4x+2h+5[/tex]

Final step just distributes the division

Answer: The graph of g(x) is the graph of f(x) shifted 3 units down.

The number of the units were started into production in a period will be 25,375.

A industry's fully prepared kinds of goods, as well as the primary materials needed to make them, are considered to as inventory.

If there were zero units of beginning work in process inventory, 4,714 units of ending work in process inventory, and 20,661 completed and transferred out units.

Completed and transferred out = 20,661

Ending Inventory = 4,714

Units accounted for = 25,375

Beginning Inventory = 0

Units started into production = [Units accounted for – Beginning work in progress Inventory] = 25,375

Units accounted for = 25,375

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Answer:54

Step-by-step explanation:

There are quicker ways to solve this but a simple and easy way to do this would be by dividing your number by the percent so 288/80 and with this, you would get your number for 1 percent or 3.6. Now you can multiply that number by the percent your need to find so 15. And 15 x 3.6 is = 54.

Answer:

3/4 - 5/12

Step-by-step explanation:

first you make the demoninators the same so 3*4=12

and if you *3 you do it to the numerator

so its 9/12-5/12

the unsimplified fraction is 4/12

if wanted simplified version its 1/3

[tex]\frac{3}{4}-\frac{5}{12}\\[/tex]

First make the denominators equal so you can easily add the numerators

Common Factor of 4 and 12: 12

So multiply [tex]\frac{3}{4}[/tex] with 3 for both numerator and denominator (4*3=12, to make denominator equal)

[tex]\frac{9}{12} - \frac{5}{12} =\frac{4}{12}[/tex]

Simplify further

[tex]\frac{4}{12} =\frac{1}{3}[/tex]

[tex]\frac{1}{3}[/tex] is the answer

Hope it helps!

Answer:

ln(20) = 2.9957

Here given:

ln(4) = 1.3863

ln(5) = 1.6094

Evaluating with that:

[tex]\rm \Rightarrow ln\left(20\right)=ln\left(5\right)+ln\left(4\right)\\[/tex]

[tex]\rm \Rightarrow ln\left(20\right)=1.3863 \ + \ 1.6094[/tex]

[tex]\rm \Rightarrow ln\left(20\right)=2.9957[/tex]

The domain is  {0, 1, 2, 3, 4, 5, 6} and range is {4, 4.5, 5, 5.5, 6, 6.5, 7}.

The domain of a function is the set of values that we are allowed to plug into our function.

The range of a function is the set of values that the function assumes.

The complete question is

Ryan also found that he could model the height of his plan with the equation H = 0.5D + 4 where D is the number of days and H is the height in centimeters. Determine the domain and the range for this relationship.

Given:

h = 0.5d + 4

The Domain of the function is: {0, 1, 2, 3, 4, 5, 6}

and the Range is: {4, 4.5, 5, 5.5, 6, 6.5, 7}

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The correct answer is option C which is the angle LMO is 50°

The branch of mathematics sets up a relationship between the sides and the angles of the right-angle triangle termed trigonometry.

Given that:-

∠O = 70°

∠L = 60°

∠LMO =?

As we know that the sum of the three angles are 180 degree applying this relation:-

∠LOM + ∠OLM  + ∠LMO = 180

70 + 60 +  ∠LMO = 180

∠LMO = 180 - 70 - 60 = 50

Therefore the correct answer is option C which is the angle LMO is 50°

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Answer:

Answer is 6

Step-by-step explanation:

Let the number be ×

Twice a number is 2×

Twice a number increase by 8 is 2×+8

hence the equivalent will be

2×+8=20

2×=12

×6

Answer:

6

Step-by-step explanation:

Let n be the unknown number.

"Twice a number" means to multiply the number by 2:  

⇒ 2n

"Increase by 8" means to add 8:

⇒ 2n + 8

"Is 20" means equals 20:

⇒ 2n + 8 = 20

Therefore, the equation is:  2n + 8 = 20

To solve, subtract 8 from both sides:

⇒ 2n + 8 - 8 = 20 - 8

⇒ 2n = 12

Divide both sides by 2:

⇒ 2n ÷ 2 = 12 ÷ 2

⇒ n = 6

Therefore, the unknown number is 6.

Answer:

P(Event) = N(Favorable Outcomes) / N (Total Outcomes)

P(sum of 10 or 11) = 5/36

Step-by-step explanation:

Probability states how likely an event is about to happen. The probability of an event can exist only between 0 and 1 where 0 indicates that event is not going to happen i.e. Impossibility and 1 indicates that it is going to happen for sure i.e. Certainty.

The higher or lessen the probability of an event, the more likely it is that the event will occur or not respectively. For example – An unbiased coin is tossed once. So the total number of outcomes can be 2 only i.e. either “heads” or “tails”. The probability of both outcomes is equal i.e. 50% or 1/2.

So,

P(Event) = N(Favorable Outcomes) / N (Total Outcomes)

Sample Space:

All the possible outcomes of an event are called Sample spaces.

Examples-

• If two dice are rolled together then total outcomes will be 36 and

Sample space will be

[ (1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)  

  (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

  (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

  (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

  (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

  (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6) ]

Probability of rolling a sum of 10 or 11 with two dice:

When two dice are rolled together then total outcomes are 36 and

Sample space is

[ (1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

  (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

  (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

  (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)  

 (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)  

 (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6) ]

So, pairs with sum 10 or 11 are (4, 6) (5, 5) (6, 4) (5,6) (6,5) i.e. total 5 pairs

Total outcomes = 36

Favorable outcomes = 5

Probability of getting the sum of 10 or 11 = Favorable outcomes / Total outcomes

                                                               = 5 / 36

So, P(sum of 10 or 11) = 5/36

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Answer:

Complemetry angle = 90° - 40°

= 50°

Hii!

___________________________________________________________

Answer:

[tex]\sf 48\textdegree[/tex]

Step-by-step explanation:

The sum of complementary angles is always 90 degrees.

We can find the complement of 90 by setting up an equation; (let x be the unknown angle).

[tex]\implies[/tex] 42+x=90

Subtract 42 from both sides

x=48

--

Hope that this helped! Best wishes.

--

Answer:

Step-by-step explanation:

the numerator goes in side of the radical

Answer: 119°

Step-by-step explanation:

From the positive y-axis, all angles are measured clockwise

PR = PQ + QR = 5[150°] + 3[60°]

X = 5*sin150 + 3*sin60 = 5.1

Y = 5*Cos150 + 3*Cos60 = -2.83

TanA = X/Y

A = -61° = 61° East of South = 119° Clockwise

Therefore, the bearing of R from P is 119°

The length of the AC is x^2  + 4x  - 12.

That quadrilateral in which opposite sides are parallel is called a parallelogram.

Thus, a parallelogram is always a quadrilateral but a quadrilateral can or cannot be a parallelogram.

Given :

In Parallelogram ABCD, diagonals AC and BD intersect at point E.

such that

AE = x^2 - 12,

CE = 4x

We know that the diagonal of a parallelogram bisect each other.

x^2 - 12 = 4x

x^2  - 4x  - 12= 0

(x-6)(x-2) = 0

Hence, the value of x = 6, 2.

AC = AE + CE = x^2  + 4x  - 12.

The length of the AC is x^2  + 4x  - 12.

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