Answer:
Step-by-step explanation:
5
Seventy million pounds of trout are grown in the U.S. every year. Farm-raised trout contain an average of grams of fat per pound, with a standard deviation of grams of fat per pound. A random sample of farm-raised trout is selected. The mean fat content for the sample is grams per pound. Find the probability of observing a sample mean of grams of fat per pound or less in a random sample of farm-raised trout.
Complete question is:
Seventy million pounds of trout are grown in the U.S. every year. Farm-raised trout contain an average of 32 grams of fat per pound, with a standard deviation of 7 grams of fat per pound. A random sample of 34 farm-raised trout is selected. The mean fat content for the sample is 29.7 grams per pound. Find the probability of observing a sample mean of 29.7 grams of fat per pound or less in a random sample of 34 farm-raised trout. Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.
Answer:
Probability = 0.0277
Step-by-step explanation:
We are given;
Mean: μ = 32
Standard deviation;σ = 7
Random sample number; n = 34
To solve this question, we would use the equation z = (x - μ)/(σ/√n) to find the z value that corresponds to 29.7 grams of fat.
Thus;
z = (29.7 - 32)/(7/√34)
Thus, z = -2.3/1.200490096
z = -1.9159
From the standard z table and confirming with z-calculator, the probability is 0.0277
Thus, the probability to select 34 fish whose average grams of fat per pound is less than 29.7 = 0.0277
A hospital needs 0.100 gg of 133 54Xe 54133Xe for a lung-imaging test. If it takes 10 daysdays to receive the shipment, what is the minimal amount mXemXem_Xe of xenon that the hospital should order? Express your answer numerically in grams
Answer:
The correct answer will be "0.400 gm".
Step-by-step explanation:
The give values are:
Needs of hospital, N = 0.100 gm
Time, t = 10 days
Minimum amount of Xenon, N₀ = ?
As we know,
⇒ [tex]N(t)=N_{0} \ e^{-\lambda t}[/tex]
∴ Decay constant, λ = [tex]\frac{ln2}{t_{1/2}}[/tex]
λ = [tex]\frac{ln2}{5}[/tex]
On putting values, we get
⇒ [tex]0.100=N_{0} \ e^{-\frac{ln2}{5}}\times 10[/tex]
⇒ [tex]0.1=N_{0} \ e^{-2ln2} = N_{0} \ e^{-ln4}[/tex]
⇒ [tex]0.1=N_{0} \ e^{ln\frac{1}{4}}[/tex]
⇒ [tex]0.1=\frac{N_{0}}{4}[/tex]
⇒ [tex]N_{0}=0.1\times 4[/tex]
⇒ [tex]MX_{e}=0.400 \ gm[/tex]
subtract 2 16/21 - (-8 5/21). reduce if possible
Answer:
11
Step-by-step explanation:
An accident Investigator measured the skid marks of one of the vehicles involved in an accident. The length of the skid
marks, d, was 117ft. Use the formula s = 24d to find s, the speed of the vehicle before the brakes were applied. Fund
Answer:
2,808
Step-by-step explanation:
since 117 = d then we would just plug that into the equation of s = 24d and get s = 24(117), after that you would just solve.
Answer:
53
Step-by-step explanation:
Solve 23 - Q >-3(2-6)
Answer:
q < 11
Step-by-step explanation:
Distribute the -3
23 - q > 12
Add q and subtract 12
q < 11
Step-by-step explanation:
the answer is
q<11
23-q>12
A rectangular box is 4 cm wide, 4 cm tall, and 10 cm long. What is the diameter of the smallest circular opening through which the box will fit? Round to the nearest tenth of a centimeter.
Answer:
The diameter of the smallest circular opening through which the box will fit is 5.7 cm to the nearest tenth
Step-by-step explanation:
The dimensions of the rectangle are :
height: 4 cm
length: 10 cm
breadth: 4 cm
The diameter of the smallest circular opening through which the box will fit will be equals to the diagonal of a face of the rectangular box.
The face we will try to fit in first will determine the diagonal that we will calculate.
Let us try to fit in the right side of the rectangular box. The face we will have at that side is a square of 4 cm by 4 cm which is formed by the height and the width of the box.
We can calculate the diagonal using Pythagoras Theorem:
diagonal = [tex]\sqrt{height^{2}+ breadth^{2}}= \sqrt{4^{2}+4^{2}}=5.657 \approx 5.7cm[/tex] to the nearest tenth
A voter receives a call in which the caller claims to be conducting a national opinion research poll. The voter is asked if his or her opinion about a congressional candidate would change if he or she knew that the candidate once had a car crash while driving under the influence of alcohol. Identify and explain at least one source of bias in the study described. Then suggest how the bias might have been avoided?
a. The data do not seem to support the claims being made by the study. The researcher should consult an expert to make sure that he or she is correctly interpreting the data.
b. The study does not appear to have a well-defined goal. The researcher should determine his or her goal and precisely define the variables of interest.
c. Since the sample is self-selected, there is a definite participation bias in this study. The researcher should randomly select the subjects of the study.
d. The wording of the question is biased to strengthen opposition against a particular candidate. The question wording should be changed to be more neutral.
Answer:
The correct answer is D. The wording of the question is biased to strengthen opposition against a particular candidate. The question wording should be changed to be more neutral.
Step-by-step explanation:
The phrasing and setup of the poll will produce responses that are biased against the candidate. The setup of the poll should be changed to avoid influencing the opinions of the respondents.
Which ordered pair is the solution of the system of equations? 3x+2y=4, -2+2y=24, I need help Im very confused on how to solve this...
Answer:
x = -7.33 OR x = [tex]\frac{-22}{3}[/tex]
y = 13
Step-by-step explanation:
→You can use the substitution method. First, make y by itself in (-2 + 2y = 24):
-2 + 2y = 24
2y = 26
y = 13
→Then, plug in 13 for y into the other equation:
3x + 2y = 4
3x + 2(13) = 4
3x + 26 = 4
3x = -22
x = -7.33 OR x = [tex]\frac{-22}{3}[/tex]
Please answer this correctly
Answer:
432
Step-by-step explanation:
l x w
4x3
4x19
8x24
8x19
432
Peter has invented a game with paper cups. He lines up 121 cups face down in a straight line from left to right and consecutively labels them from 1 to 121. He then walks from left to right down the line of cups, flipping all of the cups over. He returns to the left end of the line, then makes a second pass from left to right, this time flipping cups 2,4,6,8... On the third pass, he flips cups 3,6,9,12.... He continues like this: On the ith pass, he flips over cups i, 2i, 3i, 4i,.... (By "flip," we mean changing the cup from face down to face up or vice versa.) After 121 passes, how many cups are face up?
Answer:
After 121 passes, there will be 11 cups facing up
Step-by-step explanation:
Given that:
Peter initially lines up 121 cups facing down in a straight line from left to right and consecutively labels them from 1 to 121.
We can have an inequality ; i.e 1 ≤ n ≤ 121; if n represents the divisor including n itself for which n = odd number. Thus at the end of this claim, the cup will be facing up.
On the ith pass, he flips over cups i, 2i, 3i, 4i,.... (By "flip," we mean changing the cup from face down to face up or vice versa.)
For each divisor on the ith pass of n;
[tex]i \ th \ pass \ = \ n \ \to \ p |n[/tex] since we are dealing with possibility of having an odds number:
Thus; [tex]p =i[/tex] and [tex]i^2 = n[/tex] where ; n = perfect square.
Thus ; we will realize that between 1 to 121 ; there exist 11 perfect squares. Therefore; as a result of that ; 11 cups will definitely be facing up after 121 passes
4x and 16y are like terms.
O A. True
O B. False
Kyle is making a frame for a rectangular piece of art. The length of the frame is 3 times the width, as shown below.
TIME REMAINING
54:06
3x
x
If Kyle uses 10 feet of wood to make the frame, what is the length of the frame? Write the answer in decimal form,
0.75
4.60
0.00
Answer:
3.75 feet
Step-by-step explanation:
The length of the frame is 3 times the width.
Let the width be x.
The length will be 3x.
Kyle uses 10 feet of wood to make the frame. This means that the perimeter is 10 feet.
The perimeter of a rectangle is:
P = 2(L + W)
=> 10 = 2(3x + x)
=> 10/2 = 4x
5 = 4x
=> x = 5/4 = 1.25 feet
The width is 1.25 feet. The length is therefore:
1.25 * 3 = 3.75 feet
A researcher classifies firefighters according to whether their gloves fit well or poorly and by gender. They want to know if there is a difference in the proportion of poorly fitted gloves and gender. At alpha = 0.01, use the chi-square test to determine if there is a difference in the population proportion of glove fitness for the two genders.
Observed data Males Females Total
Gloves fit poorly 132 20 152
Gloves fit well 415 19 434
Total 547 39 586
Expected data Males Females Total
Gloves fit poorly
Gloves fit well
Total
Answer:
Step-by-step explanation:
Hello!
The objective is to test if the proportion of "X: gloves fitness, categorized: Fit poorly and Fit well" is the same for two populations of interest, "male firefighters" and "female firefighters"
To do this you have to conduct a Chi-Square test of Homogeneity.
In the null hypothesis you have to state that the proportion of the categories of the variable are the same for all the populations of interest.
Be
M: the firefighter is male
F: the firefighter is female
Y: represents the category that the gloves "fit poorly"
W: represents the category that the gloves "fit well"
The null hypothesis will be:
H₀: P(Y|M)=P(Y|F)=P(Y)
P(W|M)=P(W|F)=P(W)
H₁: At least one of the statements in the null hypothesis is false.
α: 0.01
To calculate the statistic under the null hypothesis you have to calculate the expected frequencies first:
[tex]E_{ij}= O_{.j}*\frac{O_{i.}}{n}[/tex]
O.j= total of the j-column
Oi.= total of the i-row
n= total of observations
[tex]E_{11}= 547*\frac{152}{586} = 141.88[/tex]
[tex]E_{12}=39*\frac{152}{586}= 10.12[/tex]
[tex]E_{21}= 547*\frac{434}{586} = 405.12[/tex]
[tex]E_{22}= 39*\frac{434}{586} = 28.88[/tex]
[tex]X^2= sum \frac{(O_{ij}-E_{ij})^2}{E_{ij}} ~~~X^2_{(r-1)(c-1)}[/tex]
r= number of rows (in this case 2)
c=number of columns (in this case 2)
[tex]X^2_{H_0}= \frac{(132-141.88)^2}{141.88} +\frac{(20-10.12)^2}{10.12} +\frac{(415-405.12)^2}{405.12} +\frac{(19-28.88)^2}{28.88} = 13.95[/tex]
Using the critical value approach, you have to remember that this test is always one-tailed to the right, meaning that you'll have only one critical value from which the rejection region is defined:
[tex]X^2_{(r-1)(c-1);1-\alpha }= X^2_{1;0.99}= 6.635[/tex]
The decision rule is then:
If [tex]X^2_{H_0}[/tex] ≥ 6.635, reject the null hypothesis.
If [tex]X^2_{H_0}[/tex] < 6.635, do not reject the null hypothesis.
The calculated value is greater than the critical value, the decision is to reject the null hypothesis.
So at a 1% level you can conclude that this test is significant. This means that the proportions of gloves fitness, categorized in "Fit poorly" and "Fit well" are different for the male and female firefighters populations.
I hope this helps!
Answer:
The Chi - Square Test Statistics is 13.98
p-value = 0.0002
CONCLUSION: Since the p-value is less than the level of significance ; (i.e p-value < ∝) we reject the null hypothesis and accept the alternative hypothesis.
Thus; there is a difference in the population proportion of glove fitness for the two genders.
Step-by-step explanation:
From the information given ; the structure of the table can be well represented as follows;
Observed data Males Females Total
Gloves fit poorly 132 20 152
Gloves fit well 415 19 434
Total 547 39 586
Expected data Males Females Total
Gloves fit poorly
Gloves fit well
Total
The objective of this question is to use the chi-square test to determine if there is a difference in the population proportion of glove fitness for the two genders.
We call represent the hypothesis as follows:
The null hypothesis: [tex]H_o:[/tex] states that there is no difference in the population proportion of glove fitness for the two genders.
The alternative hypothesis: [tex]H_a[/tex] states that there is difference in the population proportion of glove fitness for the two genders.
The expected frequency of a particular cell can be calculated by multiplying the sum of the rows and columns together, then dividing it by the Total sum
For row 1 column 1 (gloves fit poorly (male) ; we have:
[tex]= \dfrac{547*152}{586} =141.884\\[/tex]
For row 2 column 1 (gloves fit well(male) ; we have:
[tex]= \dfrac{547*434}{586} =405.116[/tex]
For row 1 column 2 (gloves fit poorly (female)) ; we have:
[tex]= \dfrac{39*152}{586} =10.116[/tex]
For row 2 column 2 ( gloves fit well ( female ) ; we have:
[tex]= \dfrac{39*434}{586} =28.884[/tex]
Thus; we can have the complete table to now be:
Observed data Males Females Total
Gloves fit poorly 132 20 152
Gloves fit well 415 19 434
Total 547 39 586
Expected data Males Females Total
Gloves fit poorly 141.884 10.116 152
Gloves fit well 405.116 28.884 434
Total 547 39 586
The Chi - Square Test Statistics can be calculated via the formula:
[tex]X^2 = \dfrac{\sum (f_o-f_e)^2}{f_e}[/tex]
where;
[tex]f_o[/tex] = observed data frequency
[tex]f_e[/tex] = expected data frequency
∴
The Chi - Square Test Statistics is as follows:
[tex]=\dfrac{(131-141.884)^2}{141.884} + \dfrac{(20-10.116)^2}{10.116}+ \dfrac{(415-405.116)^2}{405.116}+ \dfrac{(39-28.884)^2}{28.884}[/tex]
= 0.68+9.6+0.2+3.5
= 13.98
We are given the level of significance ∝ to be = 0.01
numbers of rows = 2; number of column = 2
Thus; the degree of freedom = (2-1)(2-1) = 1×1 = 1
Using the Excel Function : [ = CHISQ.DIST.RT²(X²,df)]
p-value = 0.0002
CONCLUSION: Since the p-value is less than the level of significance ; (i.e p-value < ∝) we reject the null hypothesis and accept the alternative hypothesis.
Thus; there is a difference in the population proportion of glove fitness for the two genders.
the length of a ruler is 170cm,if the ruler broke into four equal parts.what will be the sum of the length of three parts
Answer:
You can do this two ways
1. Divide 170 into 4 parts and multiply by 3.
170/4=42.5
42.5 x 3 = 127.5 so 127.5 is the answer
2. 3/4=0.75
170 x 0.75 = 127.5
or 170/1 x 3/4 = 510/4 = 127 1/2
127 1/2 = 127.5 because 1 divided by 2 is 0.5__127 + 0.5 = 127.5
Hope this helps
Step-by-step explanation:
Solve for x
A) 5
B) 6
C)7
D)8
Answer:
[tex]7x+1+6x+101=180\\13x=78\\x=6[/tex]
A polygraph (lie detector) is an instrument used to determine if the individual is telling the truth. These tests are considered to be 86% reliable. In other words, if an individual lies, there is a 0.86 probability that the test will detect a lie. Let there also be a 0.070 probability that the test erroneously detects a lie even when the individual is actually telling the truth. Consider the null hypothesis, "the individual is telling the truth," to answer the following questions.
a. What is the probability of Type I error? (Round your answer to 3 decimal places.)
Probability
b. What is the probability of Type II error? (Round your answer to 2 decimal places.)
Probability
Answer:
Step-by-step explanation:
a) The probability of a Type I error in a lie detection test would be the probability that the lie detection machine incorrectly detected lie for the truth tellers. This is already given in the problem as 0.07.
Therefore,
[tex]P(Type-I) = 0.07[/tex]
Therefore 0.07 is the required probability here.
b) The probability of a Type II error in a lie detection test would be the probability that the lie detection machine incorrectly detected truth for the the people who are actually liars. This is thus 1 - reliability.
[tex]P(Type-II) = 1 - Reliability = 1- 0.86 = 0.14[/tex]
Therefore 0.14 is the required probability here.
Answer:
a) 0.070
b) 0.14
Step-by-step explanation:
Given that the tests are 86% reliable, i.e a probability of 0.86 a lie would be detected.
Probability of error = 0.070
a) For type I error, we have:
The probability of a type I error in this lie detector is the probability that the test erroneously detects a lie even when the individual is actually telling the truth, i.e
P(type I error) = P(rejecting true null)
= 0.070
b) The probability of a Type II error this lie detectot is the probability that the test erroneously detected truth insteax of lie.
i.e = 1 - reliability
P (Type II error) = P(Failing to reject false Null)
= P(Not detecting a lie)
= 1-0.86
= 0.14
A credit card company monitors cardholder transaction habits to detect any unusual activity. Suppose that the dollar value of unusual activity for a customer in a month follows a normal distribution with mean $250 and variance $2400.
(a) What is the probability of $250 to $294 in unusual activity in a month? Round your answer to four decimal places (e.g. 98.7654) P-0.4861
(b) What is the probability of more than $294 in unusual activity in a month? Round your answer to four decimal places (e.g. 98.7654) P 0.0139
(c) Suppose that 10 customer accounts independently follow the same normal distribution. What is the probability that at least one of these customers exceeds $294 in unusual activity in a month? Round your answer to four decimal places (e.g. 98.7654)
Answer:
Step-by-step explanation:
Let x be the random variable representing the dollar value of unusual activity for a customer in a month. Since it is normally distributed and the population mean and population standard deviation are known, we would apply the formula,
z = (x - µ)/σ
Where
x = sample mean
µ = population mean
σ = standard deviation
From the information given,
µ = 250
σ = √variance = √2400 = 48.99
a) the probability of $250 to $294 in unusual activity in a month is expressed as
P(250 ≤ x ≤ 294)
For x = 250,
z = (250 - 250)/48.99 = 0
Looking at the normal distribution table, the probability corresponding to the z score is 0.5
For x = 294
z = (294 - 250)/48.99 = 0.9
Looking at the normal distribution table, the probability corresponding to the z score is 0.8159
Therefore,
P(250 ≤ x ≤ 294) = 0.8159 - 0.5 = 0.3159
b) the probability of more than $294 in unusual activity in a month is expressed as
P(x > 294) = 1 - P(x < 294)
P(x > 294) = 1 - 0.8159 = 0.1841
c) since n = 10, the formula becomes
z = (x - µ)/(σ/n)
z = (294 - 250)/(48.99/√10) = 2.84
Looking at the normal distribution table, the probability is 0.9977
Therefore, the probability that at least one of these customers exceeds $294 in unusual activity in a month is
1 - 0.9977 = 0.0023
find the slope of the line (-5,2) and (4,2)
Answer:
The answer is 0
Step-by-step explanation:
Select the proper inverse operation to check the answer to 25 - 13 = 12.
A. 12 x 13 = 25
B. 12 x 25 = 13
C. 12 = 25 = 13
O D. 12 + 13 =25
Can someone please help me on this?
Answer:
(0, 3/2)
Step-by-step explanation:
The equation can be put in the form ...
x^2 = 4py
where p = 3/2.
In this form, the focus is distance "p" from the vertex in the direction the parabola opens.
The vertex is at (0, 0); the parabola opens upward. So, the focus is 3/2 units above the vertex, at ...
focus = (0, 3/2) . . . . . matches choice A
How would I start this?
Answer:
(0, ∞)
Step-by-step explanation:
A good place to start is by visualizing what the graph looks like on a number line.
For x > 0, it is an open circle at x=0, and shading to the right extending to infinity.
__
So, the left end of the interval is 0, but 0 is not included in the interval.
The right end of the interval is infinity, but there is no such number, so "infinity" is not included in the interval.
"Not included" means you use round brackets ( ) for the corresponding end of the interval. ("Included" would mean you use square brackets [ ].)
So, the interval 0 < x < ∞ is written in interval notation as ...
(0, ∞)
When planning road development, the road commission estimates the future population using the function represented in the table, where x is the time in years and f(x) is the total population. What is the significance of 160,000 in the function . Graph is x: 0, 1, 2, 3, 4, 5 f(x):160,000, 163,200, 166,464, 169,793, 173,189, 176,653
Answer:C
Step-by-step explanation:
Answer:
The answer is C
Step-by-step explanation:
Source: Dude trust me
Can you help me ? 70 points
Answer:
5
Step-by-step explanation:
Since the diagonals of a parallelogram bisect each other, the two halves must be equal. Therefore:
[tex]15-x=2x \\\\15=3x \\\\x=5[/tex]
Hope this helps!
Answer:
[tex]x=5[/tex]
Step-by-step explanation:
CE = EB since E is the midpoint of CB (proven by AD intersecting it).
If CE=EB, then:
[tex]2x=15-x\\[/tex]
Add [tex]x[/tex] to both sides
[tex]3x=15\\[/tex]
Divide both sides by 3
[tex]x=5[/tex]
The radius of inscribed circle is 10 what is the perimeter of square cabd
Answer:
P=80
Step-by-step explanation:
R= 10
P = R*2 *4
P of a square = 10*2 *4 = 80
Just divide by any fraction of the squares ratio.
ie) if square = 2/3 of the length of the circle then 80 x 2/3 = 53.333...
ie) if square = 3/4 of the length of the diameter of the circle then 80 x 3/4 = 60
As 3/4 pf 10 = 7.5
7.5 * 2 = 15
15* 4 = 60
Howver the square is outside of the circle as described circle inscribed exactly how much if it fits exactly then the length will be same as circles diameter = 10*2 = D;20.
20 *4 = 80. P;80
Etc.
In the transmission of digital information, the probability that a bit has high, moderate, and low distortion is 0.02, 0.07, and 0.91, respectively. Suppose that three bits are transmitted and that the amount of distortion of each bit is assumed to be independent. Let and denote the number of bits with high and moderate distortion out of the three, respectively. Determine the following:
A. fxy(x,y).
B. fx(x).
C. E(X).
D. Are X and Y independent?
Answer:
A. (Table Attached)
B. (See Step 3)
C. 0.06 (See Step 4)
D. NOT independent (See Step 5)
Step-by-step explanation:
STEP 1:Name the probabilities:
p₁ = 0.02, p₂ = 0.07, p₃ = 0.91
q₁ = 1-p₁ = 0.98 , q₂ = 1-p₂ = 0.93 , q₃ = 0.09
Let X and Y be the number of bits with high and moderate distortion out of three.
STEP 2:A.
The function will follow multinomial distribution:
[tex]f_{XY}(x,y) = P(X=x, Y=y) = \frac{3!}{x!y!(3-x-y)!} (p_1^x)(p_2^y)(p_3^{3-x-y})[/tex]
Substitute the values and make a table.
TABLE IN ATTACHMENT
STEP 3:
B.
We calculate marginal distribution by:
[tex]P (X=x)=[/tex] ∑ [tex]P(X=x,Y=y)[/tex]
[tex]fx(x)[/tex] can be found by adding all the probabilities in each row for different value of X
For X=0 , ∑P = 0.94157441
For X=1 , ∑P = 0.057624
For X=2 , ∑P = 0.001176
For X=3 , ∑P =0.000008
STEP 4:C.
The mathematic expectation E is the sum of product of each possibility with its probabiity.
[tex]E(X)=[/tex]∑ [tex]xP(X=x)[/tex]
Find E(X):
[tex]E(X)= (0*0.9415744)+(1*0.057624)+(2*0.001176)+(3*0.000008)[/tex]
[tex]E(X)=0.06[/tex]
STEP 5:
Condition probability states:
[tex]P(A|B)=\frac{P(A,B)}{P(B)}[/tex]
It can also be written as:
[tex]f_{Y|X=1}(y)=\frac{f_{XY}(1,y)}{f_x(1)}[/tex]
Where [tex]f_x(1)\\[/tex] = 0.057624
Calculate the quotient:
[tex]Y|_{x=1}[/tex] = 0 , [tex]f_{Y|_X=1[/tex] = 0.862245
[tex]Y|_{x=1}[/tex] = 1 , [tex]f_{Y|_X=1[/tex] = 0.132653
[tex]Y|_{x=1}[/tex] = 2 , [tex]f_{Y|_X=1[/tex] = 0.000510
[tex]Y|_{x=1}[/tex] = 3 , [tex]f_{Y|_X=1[/tex] = 0
Find the dependency:
[tex]f_{XY}(y)=f_X(x)f_Y(y)[/tex]
We found that
[tex]f_{Y|_X=1[/tex] = 0.862245
Calculate [tex]f_Y(1)[/tex] from summing the column from the table
[tex]f_Y(1)=0.17428341+0.007644+0.000084\\f_Y(1)=0.18201141[/tex]
Which are not equal.
Conclusion:
X and Y are NOT Independent
HELP PLEASE!!!!!!!!
Answer:
3¹²
Step-by-step explanation:
Move 3⁻² to the numerator using the negative exponent rule
1/b-n = bⁿ
(3⁵)² ⋅ 3²
Multiply the exponents
3¹⁰ · 3²
Multiply by adding the exponents
3¹⁰⋅ 3²
3¹²
Area of composed figure. Parallelogram, square and a rectangle
Answer:
126 in²
Dude just trust me
What is the main issue with plugging values into a function and then graphing it?
Too hard to calculate.
Takes too much time.
Never sure of exact data points.
Does not provide accurate results.
Answer:
B: It takes too much time
Step-by-step explanation:
Once the points have been calculated and then graphed, the solutions to y = 0 can be found. Look for y = 0 and the solutions are -5 and -1. But that takes a lot of time. There must be an easier way, and fortunately, there is.
a^3b^2 divided by a^-1b^-3
Answer:
[tex]\frac{a^3 b^2}{\frac{1}{a} \frac{1}{b^3}}[/tex]
And simplifying we got:
[tex] a^3 b^2 a b^3[/tex]
[tex] a^3 a b^2 b^3 = a^{3+1} b^{2+3} = a^4 b^5[/tex]
Step-by-step explanation:
We want to simplify the following expression:
[tex] \frac{a^3 b^2}{a^{-1} b^{-3}}[/tex]
And we can rewrite this expression using this property for any number a:
[tex] a^{-1}= \frac{1}{a}[/tex]
And using this property we have:
[tex]\frac{a^3 b^2}{\frac{1}{a} \frac{1}{b^3}}[/tex]
And simplifying we got:
[tex] a^3 b^2 a b^3[/tex]
[tex] a^3 a b^2 b^3 = a^{3+1} b^{2+3} = a^4 b^5[/tex]
I Need help ASAP!!!
Answer:
x = 15, AOB = 15, BOC = 165
Step-by-step explanation:
Assume that this is a straight line
2x - 15 + 11x = 180
Combine like terms
13x - 15 = 180
Add 15 on both sides
13x = 195
Divide 13 on both sides
x = 15
Substitute x for 15 in both equations
2(15) - 15 = 15
11(15) = 165
(For checking purposes, 165 + 15 = 180)
